The ratio of the number of picture books encyclopedias, and fairy tale books Annette had is 3:4:5 She have half of her encyclopedias to her brother and he gave her 5 books of fairytales Now she has 14 more books of fairy tales than encyclopedias How many picture books does she have

Answer:

B: 25 and 35

Step-by-step explanation:

25 product 35 875

Answer:

Using the rational root theorem, we know to divide the function by (x - 1).

(7x³ + 9x² - 12x - 4) / (x - 1) = 7x^2 + 16x + 4

Now we can further factorize 7x^2 + 16x + 4 into (7x + 2) and (x + 2).

Therefore, the original function can be rewritten as (x - 1) (7x + 2) (x + 2).

Using the factorized form above, the zeros of the function are 1, -2/7, and -2.

The equation of the circle, ellipse, and hyperbola will be x² + y² = 3², x² + y² / 3² = 1, and x² / 2² - y² / 3² = 1, respectively.

The curve that is derived from the section of the cone is known as conic section.

The following equations are given below.

x² + y² = 3², this is the equation of the circle.

x² + y² / 3² = 1, this is the equation of the ellipse.

x² / 2² - y² / 3² = 1, this is the equation of the hyperbola.

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Answer:

3 + a/2

Step-by-step explanation:

3 + a/2

The required work done is 62400 J.

work done to lift a 1500 N object from the ground to the top of a 40 m building if the cable weighs 3 N per m

work done, is define as the product of force and displacement.

since,
work done to lift 1500N to height of 40 m is:
W= FS
   =  1500 x 40 = 60000J
now work done for rope
  is given by
w = mgΔx(40-x)
w= [tex]\int _0^{40}\left mg(40-x\right)dx[/tex]
w=[tex]3\int _0^{40}\left(40-x\right)dx[/tex]
w= 3[tex][40x-x^2/2]\left \{ {{40} \atop {0}} \right.[/tex]
w= 3[1600-800]
w = 2400
Total work done for lifting 1500N to 40m height
= 6000+2400=62400J

Thus the required work done to lift 1500N weight to 40m is 62400J.

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Answer:

{x | x = -6, -1, 0, 3}

(first option listed)

Step-by-step explanation:

The domain of a function is all possible x-values for that function

So, we can see (from the x-value portion of our table) that the possible x-values are:

-6 , -1, 0, and 3

We write domain and range in lowest - highest number value order, so we write our domain as such:

{x | x = -6, -1, 0, 3}

{range is all possible y-values, and this would include -7 , 1, 9, and -2}

hope this helps!!

When reflected over ry-axis (x, y) (-x, y) , rx-axis (x, y) (x,-y) , Option A and D is the correct answer.

The rule for reflection is when an object or a coordinate point is reflected over x axis then the coordinate of the x axis remains the same while the y coordinate changes to be additive inverse.

Vice Versa happens when reflected over y axis.

So,

rx-axis (x, y) - (-x, y) --> (x,-y)

ry-axis (x, y) (-x, y)

Therefore Option A and D is the correct answer.

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Answer: its A not A & D

Step-by-step explanation:

The average queue length is greater than 10 students, the introduction of an extra checkpoint is justifiable.

Since the arrival rate and service rate follow a Poisson distribution, we can use the Poisson arrival rate formula to calculate the average queue length.

Average queue length = (arrival rate * service time) / (1 - arrival rate * service time)

For the given problem, the average queue length is:

Average queue length = (50 * 35) / (1 - 50 * 35)

= 175

Since the average queue length is greater than 10 students, the introduction of an extra checkpoint is justifiable.

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The fraction of the journey Sapna traveled by car and train is 3/8 and 5/8 respectively.

We know that fraction is an expression in mathematics used to denote the division of two whole numbers.

Given that the total distance = 48 km.

The distance Sapna traveled by car = 18 km.

So, the fraction is = distance traveled by car/total distance = 18/48 = 3/8

The distance Sapna traveled by train = 48 - 18 km = 30 km.

So, the fraction is = distance traveled by train/total distance = 30/48 = 5/8

Therefore the fraction of the journey Sapna traveled by car and train is 3/8 and 5/8 respectively.

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Answer: the +2

Step-by-step explanation: PEMDAS. Exponents are before addition in the sequence. I hope this helps!

(The E standing for exponents and the A standing for addition)

Answer:

400.9 m

Step-by-step explanation:

The subtraction of the expression will be 238 cubic feet, 551 cubic inches.

It simply implies subtracting something from an entity, group, location, etc. Subtracting from a collection or a list of ways is known as subtraction.

The expressions are given below.

9 cubic yd 113 cubic in and 4 cubic ft 129 cubic in

1 cubic yard = 27 cubic feet

1 cubic feet = 1728 cubic inches

Then the subtraction will be

    242 cu ft 1841 cu in

   −   4 cu ft 1290 cu in

   238 cu ft 551 cu in

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The word problem for given equation is : When 3 is multiplied with x and subtracted by 2 multiplied by y , the number obtained is 13. Solve the equation for x =1 .

The complete equation will be 3x - 2y =13

When an algebraic expression is equated by an equal sign to a constant or any other algebraic expression , then an equation is formed .

The equation given in the question is

3x-2y =13

When 3 is multiplied with x and subtracted by 2 multiplied by y , the number obtained is 13. Solve the equation for x =1 .

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39 hours;  she works per week if the paramedic maintains a time card for hours she works on the rescue squad.

Fraction number consists of two parts, one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have:

A paramedic maintains a time card for the hours she works on the rescue squad shown in the table:

We can write a mixed fraction in a fraction:

6 1/2 = 13/2

8 1/2  = 33/2

7 3/4 = 31/4

8 1/12 = 97/12

8 5/12 = 101/12

Adding all the fractions:

[tex]=\rm \dfrac{13}{2}+\dfrac{33}{4}+\dfrac{31}{4}+\dfrac{97}{12}+\dfrac{101}{12}[/tex]

[tex]=\dfrac{13}{2}+\dfrac{64}{4}+\dfrac{97}{12}+\dfrac{101}{12}[/tex]

[tex]=\dfrac{13}{2}+\dfrac{64}{4}+\dfrac{198}{12}[/tex]

[tex]=\dfrac{13}{2}+\dfrac{64}{4}+\dfrac{33}{2}[/tex]

[tex]=23+\dfrac{64}{4}[/tex]

= 39 hours

Thus, 39 hours;  she works per week if the paramedic maintains a time card for hours she works on the rescue squad.

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Answer:

5 units

Step-by-step explanation:

to find out the answer for this you must first find the distance between 7 and 4 and then 6 and 10

then you would square them and then add them

lastly you would take the square root of that and youd have your answer

so

7 - 4 = 3

6 - 10 = -4 (just use 4)

3^2 + 4^2 = 9  + 16 = 25

then you take the square root of this

sqrt(25) = 5

that is your answer

To solve this problem, you will use the Distance Formula to find the distance between two coordinate points.

The Distance Formula is defined as follows:

[tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]

We must title our points by the standard coordinate naming system:

[tex](x_1, y_1) \ \text{and} \ (x_2, y_2)[/tex]

Therefore, our points can be labeled:

Now, substitute the known values as the variables in the Distance Formula:

[tex]d=\sqrt{(4 - 7)^2 + (10 - 6)^2}[/tex]

You must know the BPEMDAS acronym, which stands for:

Brackets

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

Simplify the expression using BPEMDAS:

[tex]d=\sqrt{(-3)^2 + (4)^2}[/tex]

Remember that when a number is raised to the 2nd power, it is the same thing as multiplying the number by itself:

[tex]-3\times-3 = 9[/tex]

[tex]4\times4=16[/tex]

Simplify further by removing the parentheses:

[tex]d=\sqrt{9+16}[/tex]

Compute the additive operation:

[tex]d=\sqrt{25}[/tex]

The number that is placed inside of a square root symbol (or a radical symbol) is referred to as the radicand.

In this situation, the radicand is 25.

To simplify the radicand, you may either use a calculator to compute the result, or you can determine which number raised to the 2nd power will result in a final answer of 25.

In this case, we can determine that 5² will result in a final answer of 25.

[tex]5^{2} = 25[/tex]

The final answer is 5 units.

The annual interest would be $5 if you have loaned a friend $100 and will charge him 5% annually and the total amount would be $105.

It is defined as the interest based on the principal amount, it does not include the compounded amount. The interest calculates on the initial amount of borrowed amount.

We have:

You have loaned a friend $100 and will charge him 5% annually.

As we know:

A = P(1 + rt)

P = $100

r = 5% = 0.05

t = 1 years

A = 100(1 + 0.05×1)

A = $105

I = A - P = 105 - 100 = $5

Thus, the annual interest would be $5 if you have loaned a friend $100 and will charge him 5% annually and the total amount would be $105.

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[tex]4x + 7 - (x + 6) = 68 \\ \\ 4x + 7 - x - 6 = 68 \\ \\ 3x + 1 = 68 \\ \\ 3x = 68 - 1 \\ \\ 3x = 67 \\ \\ x = \frac{67}{3} \\ \\ x = 22.3[/tex]

The value of x is 67/3 or 22.3 .

Hi!

__________________________________________________________

[tex]\rightsquigarrow\circ\boldsymbol{Answer}\circ\leftharpoonup[/tex]

x=

[tex]\rightsquigarrow\circ\boldsymbol{Explanation}\circ\leftharpoonup[/tex]

First let's distribute the minus sign.

[tex]\twoheadrightarrow\sf 4x+7-x-6=68[/tex]

[tex]\bullet[/tex] Add 6 to both sides

[tex]\twoheadrightarrow\sf 4x+7-x=74[/tex]

[tex]\bullet[/tex] Subtract the x's

[tex]\twoheadrightarrow\sf 3x+7=74[/tex]

[tex]\bullet[/tex] Subtract 7 from both sides

[tex]\twoheadrightarrow\sf3x=67[/tex]

[tex]\bullet[/tex] Divide both sides by 3

[tex]\twoheadrightarrow\sf x=\cfrac{67}{3}[/tex]

[tex]\bullet[/tex] Great job! We solved for the variable

--

Hope that this helped! Best wishes.

[tex]\textsl{Reach far. Aim high. Dream big.}\\\boldsymbol{-Greetings!-}[/tex]

--

15-(5)/5-10=10/-5=-2 hope it helps!

Applying the negative exponent, it is found that the equivalent expression to [tex]3^{-3}[/tex] is [tex]\frac{1}{27}[/tex].

When we have a negative exponent, we use a fraction, with the term with the exponent going to the denominator, as follows:

[tex]a^{-b} = \frac{1}{a^b}[/tex]

Hence, in this problem, the equivalent expression is:

[tex]3^{-3} = \frac{1}{3^3} = \frac{1}{27}[/tex]

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Answer:

20

Step-by-step explanation:

Plug in -4 for n:

(-4)^2 - (-4) = 16 + 4 = 20

Answer:

$324

Step-by-step explanation:

let x be the amount of money she had at first , then

[tex]\frac{1}{3}[/tex] x + [tex]\frac{1}{9}[/tex] x = 144 ( multiply through by 9 to clear the fractions )

3x + x = 1296

4x = 1296 ( divide both sides by 4 )

x = 324

she had $324 at first

Answer:

1/27

Step-by-step explanation:

We can substitute x=0 into the function to get:

Answer:

simple interest is $281(nearest whole number)

Step-by-step explanation:

S. I=PXTXR

100

P=$6609

T=5

R=8.5 or 85/10

S. I=6609X5X85

100X10

=280.8825

=281

[tex]{\huge \underline{{ \fbox \color{red}{A}}{\fbox \color{green}{n}}{\fbox \color{purple}{s}}{\fbox \color{brown}{w}}{\fbox \color{yellow}{e}}{\fbox \color{gray}{r } }}}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf \red{ \dfrac{1}{2} + \dfrac{1}{4} = \dfrac{3}{4} }[/tex]

Step by step explanation :-

The only thing you have to do is add the numerator to the denominator, in this case you have to add the first ones from the front, which can be these 2+1/4, which would result in 3/4, and this is called the Commutative Property.

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \bf \gray{ \dfrac{1}{2} + \dfrac{1}{4} = \dfrac{1}{4} + \dfrac{1}{2} }}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \bf \green{\dfrac{2 + 1}{4} = \dfrac{1 + 2}{4} }}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed {\bf \blue{\dfrac{3}{4} = \dfrac{3}{4}} }[/tex]

Answer :- The answer is 3/4

¿What is commutative property?

It is to change different ways in order of the addends the result would be the same.

Example :-

[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed {\bf \blue{\dfrac{a}{b} + \dfrac{c}{d}} = {\dfrac{c}{d} + \dfrac{a}{b}} }[/tex]

I hope I've helped : )

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: Final \:\: value = \cfrac{3}{4}[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: \cfrac{1}{2} + \cfrac{1}{4} [/tex]

[ take LCM ]

[tex]\qquad \tt \rightarrow \: \cfrac{2}{4} + \cfrac{1}{4} [/tex]

[tex]\qquad \tt \rightarrow \: \cfrac{2 + 1}{4} [/tex]

[tex]\qquad \tt \rightarrow \: \cfrac{3}{4} [/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

10

Step-by-step explanation:

3+2-1+6=5-1+6=4+6=10

Option D is the correct answer.

All real numbers greater than or equal to 0 and less than 4.

The domain of a function is the set of its possible inputs, i.e., the set of input values where for which the function is defined.

Here, The function of the car value is given as:

V(x) = 20000 X (0.84)ˣ

When the car reaches half its value, we have:

V(x) = 10000

Substitute V(x) = 10000 in V(x) = 20000 * (0.84)ˣ

10000 = 20000 X (0.84)ˣ

Divide both sides by 20000

0.84ˣ = 0.5

Take the logarithm of both sides

x log(0.84) = log(0.5)

Divide both sides by log(0.84)

           x = 4

This means that the maximum value of x is 4.

Thus, all real numbers greater than or equal to 0 and less than 4.

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Answer:

3qr - 6q²

Step-by-step explanation:

3q(r - 2q) ← multiply each term inside the parenthesis by 3q

= 3qr - 6q²

Answer:

3qr – 6q²

Step-by-step explanation:

3q(r – 2q)

E X P A N D I N G :-

3qr – 6q²