The correct value according to Ruler A is 2.2cm, whereas the correct value according to Ruler B is 2.27 cm.Perform the mathematical operations indicated by the title of each bin using these two values. Round the correct answers to the appropriate number of significant figures or decimal places. Compare the rounded correct answers with the values given and drag the rounded correct answers to the bin that represents the mathematical operation performed. There are also answers that are not rounded to the correct number of significant figures or decimal places. Drag these answers to the bin named �Incorrect rounding.�For example, multiply the number 2.2 by 2.27. Round the answer to the appropriate number of significant figures. Drag the correctly rounded answer to the bin labeled "2.2 x 2.27"Drag the incorrect answers from the multiplication operation to the bin named "Incorrect rounding."Drag the appropriate items to their respective bins.Item: 5.0 cm^2, 4.994 cm^2, 4.5cm, 0.0cm, 4.47cm, 0.07cm, 0.1cm, 1.0, 1, 1, 10.3, 4.99cm^21. 2.27x2.2 =?2. 2.27/2.2 =?3. 2.27 +2.2 = ?4. 2.27-2.2 = ?5. Incorrect rounding?

Answers

Answer 1

Answer:

1) 5.0 cm² ( to two significant figures or one decimal place)

2) 1.0 (to two significant figures or to one decimal place)

3) 4.5 cm ( to  two significant figures or one decimal place)

4) 0.1 cm ( to  two significant figures or one decimal place)

5) The remaining answers due to incorrect rounding are 4.994 cm², 0.0 cm, 4.47 cm, 0.07 cm, 1, 1.03 cm, 4.99 cm²

Explanation:

The answers given are rounded to  two significant figures or one decimal places:

1) 2.27*2.2 =  5.0 cm² ( to one decimal place)

2) 2.27/2.2=  1.0 ( to one decimal place)

3)  2.27+2.2  = 4.5 cm ( to one decimal place)

4) 2.27-2.2  =  0.1 cm ( to one decimal place)

5) The remaining answers due to incorrect rounding are 4.994 cm², 0.0 cm, 4.47 cm, 0.07 cm, 1, 1.03 cm, 4.99 cm²

The Correct Value According To Ruler A Is 2.2cm, Whereas The Correct Value According To Ruler B Is 2.27

Related Questions

Match the term to its description.

Gravitational energy
Answer 1

Mechanical energy
Answer 2

Nuclear energy
Answer 3

Thermal energy
Answer 4


Internal energy caused by vibrations of atoms and molecules
The potential energy of position
The energy of an object due to its movement
Energy stored in the nucleus of an atom

Answers

Answer:

Gravitational Energy: The energy of an object due to its movement

Mechanical Energy: The potential energy of position

Nuclear Energy: internal energy caused by vibrations of atoms and molecules

Thermal Energy: Energy stored in the nucleus of an atom

Answer:

radiant

nuclear

thermal

potential

Explanation:

If you can help answer the question if you can't then don't
a candle burning can be considered both chemical and physical change explain how is that possible ????​

Answers

Answer:

Yes its both a physical and chemical change heres why.

When heated , the wax melts to form a liquid wax . The liquid wax then becomes a solid wax upon cooling ( Physical change )

When the candle is lit, the wax near the tip of the candle will melt . The wick then absorbs the liquid wax . The liquid wax then vapourizes due to the heat emitting from the flame . The wax vapour then burns to give off a black substance ( what we will to as CO₂ , soot ) , heat and water vapour

(Chemical change )

Brainliest ? Hope I answered your question

Be sure to answer all parts. Give the name and the formula of the compound formed from the following elements: (a) bromine and rubidium Name: (select) (select) Formula: (b) strontium and sulfur Name: (select) (select) Formula: (c) barium and chlorine Name: (select) (select) Formula

Answers

Answer:

These are the chemical names and molecular formula of the compounds formed from these elements:

Rubidium + Bromine = Rubidium bromide, RbBrStrontium + Sulphur = Strontium sulfide, SrSBarium and Chlorine = Barium chloride, [tex]BaCl_{2}[/tex]

Need help with these 7 problems

Answers

Answer:

1. 2.3

2. 4.5

3. 10.5

4. 5.6

5. 3.5

6. 3.9

7. 1.6

Explanation:

pH = - log [H+]

1. Lemon juice

[H+] = 0.005

pH = - log [H+]

pH = - log 0.005

pH = 2.3

2. Beer

[H+] = 3.16x10^-5

pH = - log [H+]

pH = - log 3.16x10^-5

pH = 4.5

3. Milk of Magnesia

[H+] = 3.16x10^-11

pH = - log [H+]

pH = - log 3.16x10^-11

pH = 10.5

4. Rain water

[H+] = 2.51x10^-6

pH = - log [H+]

pH = - log 2.51x10^-6

pH = 5.6

5. Soda

[H+] = 3.16x10^-4

pH = - log [H+]

pH = - log 3.16x10^-4

pH = 3.5

6. Tomatoes

[H+] = 1.23x10^-4M

pH = - log [H+]

pH = - log 1.23x10^-4

pH = 3.9

7. Bleach

[OH-] = 2.3x10^-2M

pOH = - log [OH-]

pOH = - log 2.3x10^-2

pOH = 1.6

Since density depends on the mass and volume of an object, we need both of these values combined in the correct way to solve for density. Keep in mind that we may not be given the mass and volume directly, or the values may not be given in the units we want and we need to convert to the correct units before solving for density.When converting between metric units, use the prefixes to help you determine the magnitude of a value. The prefix k indicates kilo, 1000. Therefore 1000 g = 1 kg.A 11.0 kg iron weightlifting plate has a volume of 1400 cm3 . What is the density of the iron plate in g/cm3?Express your answer in grams per cubic centimeter to three significant figures.

Answers

Answer:

  7.86 g/cm³

Explanation:

  11.0 kg = 11,000 g

The density in g/cm³ is ...

  (11,000 g)/(1,400 cm³) = 7.86 g/cm³

The electron in a hydrogen atom, originally in level n = 8, undergoes a transition to a lower level by emitting a photon of wavelength 3745 nm. What is the final level of the electron? (c = 3.00 x 108m/s, h = 6.63 x 10−34 J • s, RH = 2.179 x 10−18 J)
a. 5
b. 6
c. 8
d. 9
e. 1

Answers

Answer:

The level is  [tex]n_1 = 5[/tex]

Explanation:

From the question we are told that

  The level of the hydrogen atom is   [tex]n_2 = 8[/tex]

  The wavelength of the photon is  [tex]\lambda = 3745 nm = 3745 *10^{-9} \ m[/tex]

Generally the wave number is mathematically represented as

        [tex]k = \frac{1}{\lambda }[/tex]

Now this wave number can also be mathematically represented as

       [tex]k = R_{\infty} [\frac{1}{n_1^2} + \frac{1}{n_2^2} ][/tex]  

This implies that

     

 So  

   Here [tex]R_{\infty}[/tex] is the Rydberg constant, with a value  [tex]1.097 * 10^7[/tex]

and  [tex]n_1 \ and \ n_2[/tex]  are the principal quantum levels

 substituting values

               [tex]0.0243= [\frac{1}{n_1^2} - \frac{1}{8^2} ][/tex]  

               [tex]0.0243= \frac{1}{n_1^2} - 0.015625[/tex]  

              [tex]0.0243 + 0.015625= \frac{1}{n_1^2}[/tex]

              [tex]n_1 = 5[/tex]  

Using the relationship given in part 1, calculate Ecell if [Cu2+] = 1.453 M and [Cr3+] = 0.00176 M, assuming that the temperature remains at 25°C. Give your answer to two places after the decimal.

Answers

Answer:

1.05 V

Explanation:

Now recall Nernst equation;

Ecell= E°cell - 0.0592/n log [Red]/[Ox]

Now we look at the values of E°cathode and E°anode

E°cathode= 0.34 V

E°anode = -0.74 V

E°cell= 0.34-(-0.74)

E°cell= 1.08 V

[Red] = 1.453 M

[Ox] = 0.00176 M

n= 6

Ecell= E°cell - 0.0592/n log [Red]/[Ox]

Ecell= 1.08 - 0.0592/6 × log[1.453]/[0.00176]

Ecell= 1.08 - 0.0592/6 × 2.917

Ecell= 1.08 - 0.02878

Ecell= 1.05 V

H3C-CH2-OH
What is the name of this

Answers

Answer:

H3C is the chemical name for the methyl group, and it can also be written as CH3

CH2 is a carbene

OH is hydroxide

Under certain conditions the rate of this reaction is zero order in ammonia with a rate constant of 0.0089 M.s^-1:
2NH3(g) → N2(g)+ 3H2(g)
Suppose a 5.0 L flask is charged under these conditions with 400. mmol of ammonia. How much is left 2.0 s later? You may assume no other reaction is important.
Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.

Answers

Answer:

Explanation:

The rate of reaction will not depend upon concentration of reactant . It will be always constant and equal to .0089M s⁻¹.

Initial moles of reactant = 400 x 10⁻³ mole in 5 L

molarity = 400 x 10⁻³ /5 M

= 80 x 10⁻³ M .

= .08M

no of moles reacted in 2 s  = .0089 x 2

= .0178 M

concentration left = .08 - .0178 M

= .0622 M .

No of moles left in 5 L

= 5 x .0622 = .31 moles .

An equilibrium mixture of the three gases in a 7.40 L container at 535 K contains 0.313 M PCl5, 0.119 M PCl3 and 0.119 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if the volume of the container is increased to 16.6 L?

Answers

Answer:

PCl₅: 0.1192M

PCl₃: 0.0734M

Cl₂: 0.0734M

Explanation:

Based on the reaction:

PCl₅ ⇄ PCl₃ + Cl₂

K of reaction is defined as:

K = [PCl₃] [Cl₂] / [PCl₅]

Replacing with concentrations of gases in equilibrium:

K = [0.119] [0.119] / [0.313]

K = 0.0452

Moles of each gas is:

PCl₅: 7.40L × (0.313mol / L) = 2.3162 moles

PCl₃: 7.40L × (0.119mol / L) = 0.8806 moles

Cl₂: 7.40L × (0.119mol / L) = 0.8806 moles

When the volume of the container is increased the system will produce more moles, (That is, produce more products) in order to keep constant the pressure of the container -Le Chatelier's principle-. In equilibrium, molarity of each gas is:

PCl₅: 2.3162 moles - x / 16.6L

PCl₃: 0.8806 moles + x / 16.6L

Cl₂: 0.8806 moles + x / 16.6L

Where X is reaction coordinate.

Replacing in K formula:

0.0452 = [0.05305 + X/16.6] [0.05305 + X/16.6] / [0.13953 - X/16.6]

6.3068x10⁻³ - 2.723x10⁻³ X = 0.0028143 + 0.00639157 X + 0.00362897 X²

0 = -0.0034925 + 0.00911457X + 0.00362897 X²

Solving for X:

X = -2.8 → False answer. There is no negative concentrations

X = 0.3378 moles

Replacing:

PCl₅: 2.3162 moles - 0.3378 / 16.6L = 0.1192M

PCl₃: 0.8806 moles + 0.3378 / 16.6L = 0.0734M

Cl₂: 0.8806 moles + 0.3378 / 16.6L = 0.0734M

Beeing these concentrations the concentrations in equilibrium of the three gases

Citric acid is one component of some soft drinks. Suppose that 8 L of solution are made from 0.24 g of citric acid, C6H8O7. What is the molarity of citric acid in the solution?

Answers

Answer:

The correct answer is 0.15 × 10⁻³ M.

Explanation:

C₆H₈O₇ is the molecular formula of citric acid. The mass of the one mole of the substance that comprise Avogadro's no of molecules is termed as the molar mass of the substance.  

The molar mass of the citric acid (C₆H₈O₇) will be,  

6 × atomic mass of carbon + 8 × atomic mass of hydrogen + 7 × atomic mass of oxygen = 6×12 + 8×1 + 7×16 = 192. Thus, the molar mass of citric acid is 192 g/mol.  

The value of the solution given in the question is 8 L.  

The mass of citric acid given is 0.24 g or 240 mg, which can also be written as 240/1000 g or 240 × 10⁻³ g.  

The number of moles can be calculated by using the formula = mass / molar mass. Thus, by putting the values we get,  

= 240 × 10⁻³ g / 192 g/mol

= 1.25 × 10⁻³ mol

The number of moles of the solute present in the 1 liter of the solution is termed as the molarity of the solution. The formula of molarity or M is,  

= no of moles of solute / volume of solution in L

Now putting the values we get,  

= 1.25 × 10⁻³ mol / 8 L

= 0.156 × 10⁻³ M

Hence, the molarity of citric acid in the given solution is 0.15 × 10⁻³ M

How many moles of water form when one mole of NH3 reacts according to this reaction 4 NH3+ 5 O2= 4NO+ 6 H20

Answers

moles ratio of NH3 to H2O is 4:6

if 4=6

1. ?

1 * 6 /4 = 1.5

1.5 moles of water

The volume measuring system for a gasoline pump at the service station is calibrated at 20.0°C. If the temperature of the gasoline drops to 10.0°C, what percentage extra amount of mass of gasoline do you receive when making a purchase? The coefficient of volume expansion for gasoline is 9.5 × 10-4/K.

Answers

Answer:

answer = -0.95

Explanation:

A technician prepared a solution by heating 100 milliliters of distilled water while adding KCl crystals until no more KCl would dissolve. She then capped the clear solution and set it aside on the lab bench. After several hours she noticed the solution had become cloudy and some solid had settled to the bottom of the flask. Which statement best describes what happened?
A. As the solution cooled, evaporation of water increased the KCl concentration beyond its solubility
B. Water molecules, trapped with the KCl crystals, were released after heating
C. At lower temperatures the solubility of the KCl decreased and recrystallization occurred
D. At increased temperatures the solubility of KCl increased and remained too high after cooling

Answers

Answer:

At lower temperatures the solubility of the KCl decreased and recrystallization occurred

Explanation:

Solubility refers to the amount of solute that dissolves in one litre of water at a particular temperature. Solubility is a property referring to the ability for a given substance, the solute, to dissolve in a solvent. It is measured in terms of the maximum amount of solute dissolved in a solvent at equilibrium. The resulting solution is called a saturated solution.

Solubility is dependent on temperature. This is the reason why we must state the particular temperature at which a given solubility data was collected. Above or below the quoted temperature, the solubility data may no longer be accurate.

Let's return to the question, at elevated temperatures, we can see that the KCl is very soluble in water as evidenced by the clear solution obtained at high temperature. However, as the temperature decreases, the solubility of KCl also decreases accordingly and recrystallization of the solute occurred hence the formation of a cloudy solution and the settling of some solid at the bottom of the flask.

Answer:

C. At lower temperatures the solubility of the KCl decreased and recrystallization occurred

Explanation:

In an ionic compound, the size of the ions affects the internuclear distance (the distance between the centers of adjacent ions), which affects lattice energy (a measure of the attractive force holding those ions together). Based on ion sizes, arrange these compounds by their expected lattice energy. Note that many sources define lattice energies as negative values. Please arrange by magnitude and ignore the sign.


Compunds: RbCl ,RbBr ,Rbl ,RbF

Answers

Answer:

The correct answer will be " RbF > RbCl > RbBr > Rbl".

Explanation:

The size of the given ions will be:

RbCl:

⇒  689kJ/mol

RbBr:

⇒  660kJ/mol

Rbl:

⇒  630kJ/mol

RbF:

⇒  785kJ/mol

Now according to the size, the arrangement will be:

⇒  (785kJ/mol) > (689kJ/mol) > (660kJ/mol) >(630kJ/mol)

⇒  RbF > RbCl > RbBr > Rbl

The bond among all opposite charging ions seems to be strongest whenever the ions were indeed small.

What are the differences between HDL and LDL?​

Answers

Answer:

LDL is

low density lipid

HDL is

high density lipid

Explanation:

HDL helps rid your body is excess cholesterol so so it won't end up in your arteries

LDL is also called "bad cholesterol" because it takes cholesterol to your arteries

in what type of reaction or process does heat flow into the system

Answers

Answer:  The correct answer is:  " endothermic . "

______________________________________

Note:  Heat flows into  [heat may be absorbed within] an "endothermic" reaction or system

          To the contrary, heat flows out  [heat   may exit from or may be released from] an "exothermic" reaction or process.

Hint:  Think of the "prefixes" of:  "endothermic"  and "exothermic" :

_____________________________________

  1)  endo- = "within" (as in "endothermic" —heat tends to be absorbed/"within"/"released within"/released within"/into" ;

  2) exo-   = " outwards"/"exit" (as in "exothermic") —heat tends to '"exit"/leave/escape from/"be released out of/form".

_____________________________________

Hope this is helpful to you!

Best wishes to you in your academic pursuits

     —and within the "Brainly" community"!

_____________________________________

50 mL of CH3CH2Br (bromoethane) and 50 mL of water are poured into a separatory funnel. Bromoethane is a water‑insoluble compound with a density of 1.460gmL . The funnel is stoppered and the mixture is shaken vigorously. After standing, two layers separate. Which substance is in which layer? Explain. Bromoethane is more dense than water. Water is added second. The top layer is bromoethane and the bottom layer is water. The top layer is water and the bottom layer is bromoethane. Bromoethane has a higher molar mass than does water. b) Into the same funnel is poured carefully 50 mL of hexane (density = 0.660 g/mL) so that the other two layers are not disturbed. The hexane forms a third layer. The funnel is stoppered, and the mixture is shaken vigorously. After standing, two layers separate. Which compound(s) are in which layer? The top layer contains: The bottom layer contains:

Answers

Answer:

See explanation below

Explanation:

In this case, we can explain this in a very basic way.

We know that heavier objects will go always at the bottom when we are carrying two objects, one heavier than the other right?

In the same manner works the density of two liquids. In this case, we have a mix of water and bromoethane. Bromoethane is an organic compound and it's less polar than water which is extremely polar. When we mix these two liquids, we can see that both of them are insoluble, so no matter how much we shake the funnel, the liquids will not mix to form a solution.

Instead of that, both of them will be in the funnel, and they'll be gradually separating into two layers. The bromoethane has a higher density than water, this means that in the bottom layer we will have the bromoethane and in the top layer we will have the water.

In case you are wondering what happens if we added water first and then, the bromoethane?, it will happen the same, it does not matter the order you add the liquid, because density here is a very important factor, so when the water is added no matter which position, it will go to the top layer after the bromoethane is added.

Now when the hexane is added, it will form now three layers, and again, density plays an important factor. The higher density will go to the bottom, and the lowest to the top.

In this case, the order of layer will be:

Top layer: hexane (d = 0.66 g/mL)

Middle layer: water (d = 1 g/mL)

Bottom layer: bromoethane (d = 1.46 g/mL)

Hope this helps

Compare a 3s orbital to a 3p orbital. Which of the following are true? I. The orbitals have the same shape. II. The orbitals have different shapes. III. The orbitals have the same energy. IV. The orbitals have different energies.

Answers

Answer:

II. The orbitals have different shapes.  

IV. The orbitals have different energies.  

Explanation:

1. Shapes

Below are pictures of a 3s and a 3p orbital.

The 3s orbital has a spherical shape, and the 3p orbital has a dumbbell shape.

2. Energies

For every element except H, the order of energies is

3s < 3p

For a hydrogen atom,

3s = 3p

Give 2 examples of a strong electrolyte

Answers

Answer:

Sodium Chloride, Potassium Chloride

Explanation:

Sodium Chloride, Potassium Chloride, are the most common example of a strong electrolyte. Most salts are strong electrolytes, such as hydrochloric acid, nitric acid, perchloric acid and sulphuric acid. Strong bases, such as sodium hydroxide and calcium hydroxide, are also potent electrolytes.

hope this helped!

A sample of 0.3220 g of an ionic compound containing the iodide ion (I-) is dissolved in water and treated with an excess of AgHCO3. If the mass of the AgI precipitate that forms is 0.235 g, what is the percent by mass of I in the original compound? The molar mass of AgI is 234.8 g.

Answers

Answer:

39.44 %

Explanation:

Step 1: Write the balanced equation

I⁻(aq) + AgHCO₃(aq) = AgI(s) + HCO₃⁻(aq)

Step 2: Calculate the moles corresponding to 0.235 g of AgI

The molar mass of AgI is 234.8 g/mol.

[tex]0.235g \times \frac{1mol}{234.8g} = 1.001 \times 10^{-3} mol[/tex]

Step 3: Calculate the moles of I⁻ that form 1.001 × 10⁻³ mol of AgI

The molar ratio of I⁻ to AgI is 1:1. The reacting moles of I⁻ are 1/1 × 1.001 × 10⁻³ mol = 1.001 × 10⁻³ mol

Step 4: Calculate the mass corresponding to 1.001 × 10⁻³ mol of I⁻

The molar mass of I⁻ is 126.90 g/mol.

[tex]1.001 \times 10^{-3} mol \times \frac{126.90g}{mol} = 0.1270 g[/tex]

Step 5: Calculate the percent by mass of I⁻ in the original compound

[tex]\frac{0.1270g}{0.3220g} \times 100 \% = 39.44 \%[/tex]

If an experiment produces 5 g but should have made 500 g, what is the percent
yield?

Answers

Answer:

Percentage of yield = 1%

Explanation:

Given:

Amount of yield = 5g

Total amount of product = 500 gram

Find:

Percentage of yield = ?

Computation:

⇒ Percentage of yield = [Amount of yield / Total amount of product]100

⇒ Percentage of yield = [5g / 500g]100

⇒ Percentage of yield = [0.01]100

Percentage of yield = 1%

Write a chemical formula for each molecular model. (Blue ball represents nitrogen atom, red ball represents oxygen atom, white ball represents hydrogen atom, black ball represents carbon atom, yellow ball represents sulphur atom.)

Answers

Answer:

See answer below

Explanation:

In this case, you are missing the picture. Luckily I found one on another site, so I hope is the one you are asking for. If not, please post again with the picture.

According to the picture below, you need to write a chemical formula for each molecular model.

To do this, is just simple. Let's see each model per separate.

In the first model, we have a blue ball and three white balls. According to the nomenclature of the question a blue ball represents nitrogen atoms and white ball represents hydrogen, therefore, we have an atom of nitrogen bonded to three atoms of hydrogens, so, the chemical formula should be:

NH₃: This molecule corresponds to the Ammonia molecule.

The second picture, shows 4 black balls (representing an atom of carbon each) and each black ball holds a determinated number of white balls. The two of the middle have two white balls each, and the terminals have 3 white balls, therefore, the molecule should be the following:

CH₃ - CH₂ - CH₂ - CH₃: this corresponds to the butane

Finally, the last picture shows a yellow ball (which represents sulphur) and three red balls (representing oxygen each), so, the molecule that represents this would be:

SO₃: this is the sulfite ion.

express your answer to three significant figures and include appropriate units

Answers

Answer:

58.702

Explanation:

Data obtained from the question include:

Mass number of isotope 1 (M1) = 57.93

Abundance of isotope 1 (M1%) = 67.76%

Mass number of isotope 2 (M2) = 59.93

Abundance of isotope 2 (M2%) = 26.16%

Mass number of isotope 3 (M3) = 60.93

Abundance of isotope 3 (M3%) = 1.25%

Mass number of isotope 4 (M4) = 61.93

Abundance of isotope 4 (M4%) = 3.66%

Mass number of isotope 5 (M5) = 63.93

Abundance of isotope 5 (M5%) = 1.16%

Relative atomic mass =...?

The relative atomic mass(RAM) of the element can be obtained by doing the following:

RAM = [(M1×M1%) /100] +[(M2×M2%) /100] + [(M3×M3%) /100] + [(M4×M4%) /100] + [(M5×M5%) /100]

RAM = [(57.93×67.76)/100] + [(59.93×26.16)/100] + [(60.93×1.25) /100] + [(61.93×3.66)/100] + [(63.93×1.16)/100]

RAM = 39.253 + 15.678 + 0.762 + 2.267 + 0.742

RAM = 58.702

Therefore, the relative atomic mass (RAM) of the element is 58.702

Determine the value of the equilibrium constant, Kgoal, for the reaction N2(g)+H2O(g)⇌NO(g)+12N2H4(g), Kgoal=? by making use of the following information: 1. N2(g)+O2(g)⇌2NO(g), K1 = 4.10×10−31 2. N2(g)+2H2(g)⇌N2H4(g), K2 = 7.40×10−26 3. 2H2O(g)⇌2H2(g)+O2(g), K3 = 1.06×10−10 Express your answer numerically.

Answers

Answer:

K = 1.79x10⁻³³

Explanation:

Using Hess's law, it is possible to fin K of a reaction by the algebraic sum of another related reactions.

In the reactions:

1. N2(g)+O2(g) ⇌ 2NO(g), K1 = 4.10×10−31 2.

2. N2(g)+2H2(g) ⇌ N2H4(g), K2 = 7.40×10−26

3. 2H2O(g)⇌2H2(g)+O2(g), K3 = 1.06×10−10

The sum of 1/2 (1) + 1/2 (2) produce:

N2(g) + 1/2O2(g) + H2(g) ⇌ 1/2N2H4(g) + NO(g)

And K' = √4.1x10⁻³¹×√7.4x10⁻²⁶ = 1.74x10⁻²⁸

Now, this reaction + 1/2 (3):

N2(g) + H2O(g) ⇌ NO(g) + 1/2N2H4(g)

And K of reaction is:

1.74x10⁻²⁸×√1.06x10⁻¹⁰ = 1.79x10⁻³³

Write an equation that shows the formation of a magnesium ion from a neutral magnesium atom

Answers

Answer:

Mg ---> Mg^2+ + 2e^

Explanation:

hope it helps : )

Magnesium is a neutral atom that can lose two electrons two achieve stability and forms a cation. The magnesium ion is produced as, Mg ⇒ Mg²⁺ + 2e⁻.

What is a magnesium ion?

Magnesium ion is a charged species that is produced as the result of the neutral magnesium donating its electron so as to achieve its stable and complete electronic configuration.

When an atom donates an electron to another atom then they themselves become positively charged whereas the other species that accepts the electron becomes negatively charged. The positive charge is called a cation.

The reaction of the neutral magnesium donating electrons to become ions is shown as,

Mg ⇒ Mg²⁺ + 2e⁻

Therefore, magnesium loses two electrons to become positively charged.

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A sample tube consisted of atomic hydrogen in their ground state. A student illuminated the atoms with monochromatic light, that is, light of a single wavelength. If only two separate emission lines in the visible region are observed, what is the wavelength (or wavelengths) of the incident radiation?

Answers

Answer:

The wavelength is [tex]\lambda =97.3 nm[/tex]

Explanation:

Generally the series whose emission  line show on the visible spectrum is the

Balmar series so this two emission line seen on the visible spectrum  could either be due to the move of electron from

[tex]n=3 \to \ n=2[/tex]

OR

[tex]n=4 \to n=2[/tex]

This implies that the first excitement is from [tex]n_i=1 \to \ n_f=4[/tex]

So the energy change due to the excitement is mathematically represented as

     [tex]\Delta E = R_H [\frac{1}{n_i^2} -\frac{1}{n_f^2} ][/tex]

substituting values

       [tex]\Delta E= R_H [\frac{1}{1^2} -\frac{1}{4^2} ][/tex]

       [tex]\Delta E= \frac{15}{16} R_H[/tex]

This energy change can also be represented as

       [tex]\Delta E = \frac{hc}{\lambda}[/tex]      

So   [tex]\frac{15}{16} R_H = \frac{hc}{\lambda}[/tex]

=>    [tex]\lambda = \frac{16hc}{15 R_H}[/tex]

Where  [tex]R_H[/tex] is the Rydberg constant with a value of  [tex]R_H = 2.18 * 10^{-18} J.[/tex]

              h is the Planck's constant with values   [tex]h = 6.626 * 10^{-34} m^2 kg / s[/tex]

                c is the speed of light with value  [tex]c = 3.0*10^{8} \ m/s[/tex]

So

       [tex]\lambda = \frac{16(6.626 *10^{-34})(3*10^{8})}{15 * (2.18*10^{-18})}[/tex]

        [tex]\lambda = 9.73 *10^{-8} \ m[/tex]

       [tex]\lambda =97.3 nm[/tex]

Next, a chemical reaction of interest was conducted in the same constant volume calorimeter. The neutralization reaction of HCl(aq) with NaOH(aq) caused the temperature of the calorimeter to rise by 2.46 °C. What is the change in internal energy ΔU of the neutralization reaction in kJ?

Answers

Answer:

A constant volume calorimeter (bomb calorimeter) was calibrated by performing in it a reaction in which 5.23 kJ of heat energy was released, causing the calorimeter to rise by 7.33 °C. What is the heat capacity Cy of the calorimeter

Explanation:

the heat capacity of the calorimeter is

[tex]C_v = \frac{q}{\Delta T} \\\\=\frac{5.23}{7.33} \\\\=0.714kJ /^\circ C[/tex]

Now that our  heat capacity of the calorimeter is 0.714kJ/°C

we can easily calculate  the change in internal energy ΔU of the neutralization reaction

[tex]\Delta U = C_v \ dt[/tex]

or

[tex]\Delta U = C_V \Delta T[/tex]

Δ T = 2.46 °C

[tex]C_v = 0.714 kJ/ ^\circ C[/tex]

[tex]\Delta U = 0.714*2.46\\\\=1.7564kJ[/tex]

Draw the structure of the bromohydrin formed when (Z)-3-hexene reacts with Br2/H2O. Use the wedge/hash bond tools to indicate stereochemistry where it exists. If the reaction produces a racemic mixture, draw both stereoisomers. Separate multiple products using the sign from the drop-down menu.

Answers

Answer:

(3R,4R)-4-bromohexan-3-ol

Explanation:

In this case, we have  reaction called halohydrin formation. This is a markovnikov reaction with anti configuration. Therefore the halogen in this case "Br" and the "OH" must have different configurations. Additionally, in this molecule both carbons have the same substitution, so the "OH" can go in any carbon.

Finally, in the product we will have chiral carbons, so we have to find the absolute configuration for each carbon. On carbon 3 we will have an "R" configuration on carbon 4 we will have also an "R" configuration. (See figure 1)

I hope it helps!

Polymers are large molecules composed of simple units repeated many times. Thus, they often have relatively simple empirical formulas. Calculate the empirical formulas of the polyethylene: 86% C, 14% H. You must show all work for credit. Polymers are large molecules composed of simple units repeated many times. Thus, they often have relatively simple empirical formulas. Calculate the empirical formulas of the polystyrene: 92.3% C, 7.7% H. You must show all work for credit.

Answers

Answer:

A. CH2.

B. CH.

Explanation:

A. Determination of the empirical formula of polyethylene.

Data obtained from the question include:

Carbon (C) = 86%

Hydrogen (H) = 14%

The empirical formula of the polyethylene can be obtained as follow:

C = 86%

H = 14%

Divide by their molar mass

C = 86/12 = 7.17

H = 14/1 = 14

Divide by the smallest

C = 7.17/7.17 = 1

H = 14/7.17 = 2

Therefore, the empirical formula of the polyethylene is CH2.

B. Determination of the empirical formula of polystyrene

Data obtained from the question include:

Carbon (C) = 92.3%

Hydrogen (H) = 7.7%

The empirical formula of the polystyrene can be obtained as follow:

C = 92.3%

H = 7.7%

Divide by their molar mass

C = 92.3/12 = 7.69

H = 7.7/1 = 7.7

Divide by the smallest

C = 7.69/7.69 = 1

H = 7.7/7.69 =

Therefore, the empirical formula of the polystyrene is CH.

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