Since we assume the accelerations are constant, the instantaneous acceleration is the same as the average acceleration, so in the first 6.80 seconds we have
[tex]\alpha_1 = \alpha_{\rm ave} = \dfrac{\Delta \omega}{\Delta t} = \dfrac{8.70\frac{\rm rev}{\rm s}}{6.80\,\rm s} \approx 1.28 \dfrac{\rm rev}{\mathrm s^2}[/tex]
In this time, the tub undergoes an angular displacement of
[tex]\theta_1 = \dfrac12 \alpha_1 (6.80\,\mathrm s)^2 \approx 29.6\,\mathrm{rev}[/tex]
In the next 19.0 seconds the tub has acceleration
[tex]\alpha_2 = \dfrac{-8.70\frac{\rm rev}{\rm s}}{19.0\,\rm s} \approx -0.458 \dfrac{\rm rev}{\mathrm s^2}[/tex]
and in this time, the tube undergoes an additional displacement of
[tex]\theta_2 = \left(8.70\dfrac{\rm m}{\rm s}\right)(19.0\,\mathrm s) + \dfrac12 \alpha_2 (19.0\,\mathrm s)^2 \approx 82.7\,\mathrm{rev}[/tex]
So the tub completes [tex]\theta_1+\theta_2 \approx \boxed{112\,\mathrm{rev}}[/tex].
Question 16 of 25
Which of the following best describes an alternating current?
A. A circuit that has both series and parallel components
B. Charge that moves in a single direction
C. Charge that jiggles back and forth very quickly
D. A circuit that has only series or only parallel components
SUBMIT
Answer:
it is c
Explanation: i just did it
A car is moving at a rate of 72km/hr . How far does the car move when it stops after 4 seconds?
step by step asap pls
Answer:
The car will stop after 4 seconds after moving the distance of 0.08km.
Explanation:
The reading above it clearly states that a car is moving at a speed of 72Km/hr. And it asking for the distance the car move when it stops after 4 seconds.
Looking at speed formula , speed=distance÷time.
But in this problem we I finding distance, so in speed formula make distance the subject.
Therefore distance = speed × timeBefore going ahead you should have this in mind the unit for distance is Km and m . Our speed is in Km/hr but our time is in second. In this case change 4 seconds to hour which is 0.00111 hr .you change second to hour because hr will cancel hr when solving for distance giving distance unit Km
Distance = speed × time
Distance= 72km/hr × 0.00111 hr
hour cancel hour
Distance= 72km × 0.00111
Distance = 0.08km
Therefore the car will stop after 4 seconds after moving the distance of 0.08km.
Please mark brainliest.
conversion :
72 km/h = 72 × (1000/3600) = 20 m/s
so, in 4 seconds it travel
4 × 20 = 80 meters = 0.08 kmRefer to the attached image!!!
The time of motion of the track star is determined as 0.837 s.
Time of motion of the track star
The time of motion of the track star is calculated as follows;
T = (2u sinθ)/g
where;
T is time of motiong is acceleration due to gravityθ is angle of projectionT = (2 x 12 x sin20)/9.8
T = 0.837 s
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2) A ball is thrown forward horizontally from the top of a cliff
with a velocity of 10m/s as shown in the figure below. The
height of the cliff above the ground is 4.5m. Calculate
0218
R
i for position coordinates p(x, y), prove that the path of
horizontal projectile is parabolic.
[3]
ii. the time to reach the ground
[1]
iii. the distance from the cliff of the ball on hitting the ground [1]
iv. the velocity with which the ball hits the ground
[2]
v. the direction of the ball to the horizontal just before it hits the
ground.
[1]
(i) For position coordinates p(x, y), the path of horizontal projectile is parabolic.
(ii) The time to reach the ground is 0.96 s.
(iii) The distance from the cliff of the ball on hitting the ground is 9.6 m.
(iv) The velocity with which the ball hits the ground is 9.4 m/s.
(v) The direction of the ball to the horizontal just before it hits the
ground is 90 degrees.
What is projectile?When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion.
Given is a ball is thrown forward horizontally from the top of a cliff
with a velocity of 10m/s. The height of the cliff above the ground is 4.5m.
(i) The equation formed by the ball is at point (x,y) given by
y =yo + Voy x t - 1/2gx²
The equation is in the form of parabola.
Thus, the ball follows parabolic path.
(ii) The time to reach the ground is
t = √2h/g
t = √(2x 4.5)/9.81
t= 0.96 s
iii) Horizontal distance traveled
R = u x t
R = 10 x 0.96
R = 9.6 m
Thus, the distance from the cliff of the ball on hitting the ground is 9.6 m.
(iv) The velocity with which the ball hits the ground.
v = √2gh
Plug the values, we get
v = √(2 x 9.81 x 4.5)
v = 9.4 m/s
(v) The direction of the ball to the horizontal will be 90 degrees just before it hits the ground.
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it is easier to drag a stone than to kick it for the same distance. why
Answer:
it is easier to kick a stone than to drag a stone.
Explanation:
the science behind the question is fairly simple.
when you kick and object for say a (rock) you have inertia which is made from you clocking your leg back and swinging it full force forward. when you kick with inertia, you will have a much further travel distance of the object rather than dragging it which is almost set at a certain rate of how fast you are moving (m) and how much inertia you are using by pulling (p)
so m+p=i for inertia. hope this helped
Question 1 of 10
What is the magnitude of the vector described below?
"13 m/s to the east"
A. Meters per second
B. Meters
C. East
D. 13 m/s
Answer:
D
Explanation:
The magnitude is 13 m/s
the direction is east the units are m/s
If you separate vector B into its components. How many components will it have? Those components will be called?
The vector B will have two components and those components will be called resultant vectors.
What is a component vector?
A component vector is a unit vector that represents a given vector in a particular direction.
A vector can be represented in x - direction and y - direction.
x - component of the vector = Bcosθy - component of the vector = BsinθThus, the vector B will have two components and those components will be called resultant vectors.
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Find the momentum of a body of mass 5kg moving with velocity of 4.5m/s
Momentum= mass × velocity
momentum= P
P= m×v
P= 5×4.5
P=22.5
I hope this helps.
Even though it's not very popular these days, I like our system . Getting together to talk about who the best candidate might be makes me feel like we're really part of democracy. After the debate, we vote. In my state, any voter can participate. It's all pretty informal. What system for selecting party nominees does the passage describe? . Mixed primary B. Caucus C. Open primary . Closed primary
Answer:
I think it would be C: open primary
Explanation:
What is the crosswind component for a landing on runway 18 if the tower reports the wind as 220° at 30 knots?
From the head wind component charts, the crosswind component for a landing on runway 18 is 19 knots.
What is crosswind component?
When winds are not parallel to or directly with the line of travel, the wind is said to have a crosswind component.
From the head wind component charts, at 220° at 30 knots, the corresponding crosswind component is 19 knots.
Thus, from the head wind component charts, the crosswind component for a landing on runway 18 is 19 knots.
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The amount of kinetic energy an object has depends on which feature of the object?
A) its motion
B) its position
C) its gravity
D) its height
Against the park ranger's advice, a visitor at a national park throws a stone horizontally off the edge of a 83 m high cliff and it lands a distance of 93 m from the edge of the cliff, narrowly missing a visitor below.
What was the initial horizontal velocity of the rock, in m/s? You can round your answer to the hundredths place and use g ≈ 10 m/s2.
Answer:
20.37m/s
Explanation:
For this problem, we'll need a basic kinematic equation for both directions
Vertical direction:
[tex]y(t)=\frac{1}{2}a_{y}t^{2}+v_{o_y}t+y_{o}[/tex]
Knowing that the acceleration in the y-direction is due to gravity, and is constant near the surface of the Earth, where the rock is being thrown, we get [tex]a_{y}=g=-10m/s^{2}[/tex]. We're also given that the initial vertical height is 83m, so [tex]y_o=83m[/tex]. Additionally, we're given that the stone is thrown horizontally, and thus initially, it has no vertical velocity. Only velocity in the x-direction. Thus, [tex]v_{o_y}=0m/s[/tex]. Substituting known values into our equation:
[tex]y(t)=\frac{1}{2}(-10)t^{2}+(0)t+(83)[/tex]
[tex]y(t)=-5t^{2}+83[/tex]
This equation is true for all times until the acceleration changes (isn't constant... i.e. when it hits the ground).
What now?
We want to find the specific time when it does hit the ground. Why? Because this is the point in time where we know some extra information about what is happening in the x direction, and that will help us deal with the x-direction equation.
When the stone does hit the ground, the output of this function (measuring the height of the stone) is zero, which leaves only one unknown value, t... the time associated with that y: the time that it takes to hit the ground:
[tex]0=-5(t_{ground})^{2}+83\\-83=-5(t_{ground})^{2}\\\frac{-83}{-5}=(t_{ground})^{2}\\16.6=(t_{ground})^{2}\\\sqrt{16.6}=\sqrt{(t_{ground})^2}\\4.074309757seconds=t_{ground}[/tex]
Again, this is the time that the stone hits the ground. Knowing how special this time is, one might give it a special subscript to keep track of it.
[tex]t_{ground}=4.074309757seconds[/tex]
Horizontal direction
Reusing the basic kinematic equation for the horizontal direction:
[tex]x(t)=\frac{1}{2}a_{x}t^{2}+v_{o_x}t+x_{o}[/tex]
Note that in the horizontal direction, there is no acceleration (after the rock is released), so [tex]a_{x}=0[/tex]. Also, if we define the base of the cliff as our origin, then at the top of the cliff where the rock is released, the initial x-position is still zero, aka, [tex]x_{o}=0[/tex]
[tex]x(t)=\frac{1}{2}(0)t^{2}+v_{o_x}t+(0)\\x(t)=v_{o_x}t[/tex]
While we don't know the initial horizontal velocity, we do know an output of the function for one specific input... we know that when the stone hits the ground, that the stone's horizontal distance is 93m from the cliff. So, if we input [tex]t_{ground}[/tex] into this function, it will give an output of 93. The only remaining unknown is the initial velocity in the x direction. One equation, one unknown, we can solve this:
[tex]x(t_{ground})=v_{o_x}t_{ground}\\83=v_{o_x}(4.074309757)\\\frac{83}{4.074309757} =v_{o_x}\\20.37154879m/s =v_{o_x}\\[/tex]
If there were a component of initial velocity in the y direction, we would need to use the Pythagorean theorem to combine them. However, as the initial y component of velocity is zero, the initial velocity is simply the initial x velocity.
Paying attention to directions, round to the answer to the nearest hundredth:
[tex]20.37m/s =v_{o}\\[/tex]
define density and give its SI unit
Answer:
Density is defined as mass per unit volume. its SI unit is: kg/m³
Explanation:
Answer:
Density is defined as mass per unit volume. its SI unit is: kg/m³
Explanation:
from answer above
which group on the periodic table wants to gain 2 electrons?
Answer:
Periodic
Explanation:
The groups in the periodic table that want to gain electrons are groups; 15, 16 and 17. The members of these groups are mostly nonmetals.
1) Two students are making their way to school. One has a bike and the other
is on foot. If the student on foot is going at a speed of 3 m/s and they make
it to school in 30 s, how far away was the school?
To find how far away the school is:
3m/s * 30 s = 90m
Hope it helps!
Al 26.98 and S 32.06 calculate the number of formula units in 62.2 g sample of aluminum sulfide
The number of formula units would be 2.5 x [tex]10^2^3[/tex]
Formular unitThis is mathematically given as: mole x Avogadro number
Molar mass of the aluminum sulfide (Al2S3) sample = 26.98 x 2 + 32.06 x 3
= 53.96 + 96.18 = 150.14 g/mole
Mole of 62.2 g aluminum sulfide = 62.2/150.14 = 0.4143 moles
Formular unit = 0.4143 x 6.023 x [tex]10^2^3[/tex] = 2.5 x [tex]10^2^3[/tex]
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A car is moving with constant velocity of 30m/s what is it's acceleration in 10s
Answer:
0 m/s²
Explanation:
Acceleration is defined as the rate of change of velocity:
[tex]acceleration = \frac{change \space\ in \space\ velocity}{time taken}[/tex] .
As the velocity is constant, change in velocity = 0.
∴ acceleration = 0/ 10
= 0 m/s²
Type the correct answer in each box. Round your answers to the nearest hundredth.
An illustration depicts a ball tied with a rope and hanged at a position labeled A. The ball is then pulled to a position labeled B with a height of 0 point 5 meters.
A ball with a mass of 1.5 kilograms is tied to the end of a rope. The ball is pulled to a height of 0.5 meters above the ground and released.
The ball has
joules of potential energy at position B. At position A, all of the energy changes to kinetic energy. The velocity of the ball at position A is
meters/second. Assume there’s no air resistance. Use g = 9.8 m/s2 , PE = m × g × h, and .
The velocity of the ball at position A is 3.13 m/s.Since all energy is converted to KE.
What is potential energy?The potential energy is due to the virtue of the position and the height. The unit for the potential energy is the joule.
A person has the most potential energy due to her position. when he is sitting on the highest point.
Given data;
Mass,m = .5 kg
Height,H = 0.5 m
Acceleration due to gravity,g = 9.8 m/s²
H is the height
The potential energy is found as;
The potential energy is mainly dependent upon the height of the object.
Potential energy = mgh
The potential energy at point B;
PE = mgh
PE = ( 1.5 kg) ( 9.8 m/s2) (0.5 m)
PE = 7.35 J
Since all energy is converted to KE, the kinetic energy at point B;
KE = 0.5mv^2
KE = PE
7.35 = 0.53(1.5) v^2
V = 3.13 m/s
Hence, the velocity of the ball at position A is 3.13 m/s.
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A downward force of magnitude 5 n is exerted on the book by the force of.
Answer:
A downward force of magnitude 5 N is exerted on the book by the force of ... Do the downward force in Part A (gravity) and the upward force in Part B ...
the mechanical advantage of a simple machine is 3 and its velocity ratio is 4 find its efficiency
Answer:
75%
Explanation:
Efficiency=MA/VR*100
=3/4*100
=0.75*100
=75%
A 25-kg piece of equipment can be hung by steel wires of length 1.00 m, 2.00 m, or 3.00 m. If all the wires have the same diameter, which one will stretch the greatest distance
If all the wires have the same diameter, they will all stretch by the same percent. The elasticity does not depend upon the length.
What is the distance?Distance is a numerical representation of the distance between two locations. The distance can refer to a physical length or an estimate based on other factors in physics or common use.
|AB| is a symbol for the distance between two points A and B.
A physiological method for identifying far-off or unseen items using sound waves that the objects reflect back to the source, such as a bat. Each one will enlarge by the same percentage.
Hence, they will all stretch by the same percentage.
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What is a characteristic of a catamaran hull? tends to pitch in waves only recommended on calm inland waters planes at low speed a stable ride
A Stable Ride is the main characteristic of a catamaran hull.
What is catamaran hull?
Catamaran Hull is a multi-hulled watercraft, which have two parallel hulls of equal size.
The characteristic of a catamaran hull are as follows:
A catamaran hull has less volume than an equal size monohull.Catamaran hulls are distinguished by lighter displacement and shallower draft when compared to monohulls of the same length. Catamarans can be used in shallow waters as well. This feature makes catamarans quite flexible and versatile.Catamaran has multiple hulls, usually two parallel hulls of equal size. This geometric feature gives the craft an increased stability.Catamarans derives extra stability from its wide beam, in the place of a ballasted keel employed in a regular monohull sailboat.Therefore, Catamarans has a stable ride, according to their characteristic.
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Trivia Time!! At what velocity does light move?
Explanation:
Light Light from a moving source travels at 300,000 km/sec (186,000 miles/sec).
Note:
The Speed of Light Is Constant.
Explanation:
LIGHT TRAVELS AT A CONSTANT VELOCITY OF 300,000 km/sec.
one of the rare galaxies that is isolated in space is likely to be a(n) ____.
The rarest type of galaxies is the elliptical double-ringed galaxy.
What is the rarest type of galaxy?elliptical double-ringed galaxy is considered as the rarest type of galaxy because of its small number. The example of such type of galaxy is PGC 1000714. Scientists suggest that about 0.1% of galaxies are of this type.
So we can conclude that the rarest type of galaxies is the elliptical double-ringed galaxy.
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two examples of hydraulic brake
Answer:
1). Brake pedal or lever
2). A pushrod also called an actuating rod
Tatenda is making tea and
toast. He uses an 800W
toaster for 2.5 minutes and
a 2kW kettle for 5 minutes.
What is the total cost for
the energy used if
electricity costs 10p per
unit?
The total cost for the energy used if electricity costs 10p per unit is determined as 2p.
Total energy consumedThe total energy consumed during the process is calculated as follows;
E = Pt
where;
P is power (kW)t is time (hr)E = (800 W/1000) x (2.5 /60) + (2 kW) x (5/60)
E = 0.8 kW x 0.042 hr + 2kW x 0.083 hr
E = 0.0336 kW-hr + 0.166 kW-hr
E = 0.1996 kW-hr
Cost of the energy consumptionC = E x 10p
C = 0.1996 kW-hr x 10p
C = 1.996p
C ≈ 2p
Thus, the total cost for the energy used if electricity costs 10p per unit is determined as 2p.
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Use wave equation calculate the speed of sound in the air if frequency of 110 hz has a wave length of 3 m
If m = 2,000, p = 2. 25, and y= 6,000, what is velocity?
The velocity is 6.75
The velocity in the equation stated above can be calculated as follows
m= 2,000
p= 2.25
y= 6000
velocity= 2.25 × 6000/ 2000
= 13500/2000
= 6.75
Hence the velocity is 6.75
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The speed of sound in wood is 3300 m s−1 and the speed of sound in air is 330 m s−1. A hammer hits one end of a 33 m long plank of wood. Find the difference in time between the sound waves being detected at the other end of the plank and the sound being heard through the air.
The difference in time between the sound waves being detected at the other end of the plank and the sound being heard through the air will be 0.09 sec.
What is a sound wave?A sound wave is produced when a medium begins to vibrate. When an entity vibrates, a pressure wave is formed, which causes sound.
Given data;
The speed of sound in wood,u= 3300 m/s
The speed of sound in air,v=330 m/sec
long plank of wood, L=33 m
The time period in the air was found as;
T₁ = 33 m / 330 m/sec
T₁= 0.1 sec
The time period in wood ;
T₂= 33 m / 3300 m/sec
T₂=0.01 sec
T = T₁ - T₂
T=0.1-0.01
T=0.09 sec
Hence, the difference in time between the sound waves being detected at the other end of the plank and the sound being heard through the air will be 0.09 sec.
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what is projectile motion?Give 3 applications of it in our daily life.
Answer:
Motion of an object that travels in a curved path under the influence of Earth's gravitational field. Examples include throwing a ball, javelin throw, and golf ball.
Explanation:
Answer:
1. In sports.
2. In programming or Animation.
3. In home appliances.
4. In military.
Explanation:
1. In sports. Being common in sports, projectile motion is applied in motion of a projectile which is usually a ball. This is because we are able to calculate the angle of the flight developed by a ball to maximize its distance or velocity. For example in baseball and basketball.
2. In programming or Animation. Considering that there is a challenge for animators and programmers in modern world, physics is applied in televisions or video games. For example a baseball being hit by a player in video game or TV, it should look real. Hence the application of projectile motion.
3. In home appliances. Appliances for example hose or water gun uses an application of projectile motion. As the water exits the hose or water gun, the angle over which the water travels depends on the distance moved and force that is being applied.
4. In military. Bullets being shot from the barrel of the gun is a projectile in air. The speed of the bullet is higher than that of the water exiting the hose therefore it will travel a longer distance. The manufacturers of weapons such as a gun tries to maximize the speed while minimizing gun's recoil.