After taking into consideration the advantages in tax management, it will not be beneficial for Raphael and Martina to get married and avail tax benefits.
What are tax benefits?The individual taxable incomes of Raphael and Martina after availing the standard deductions will be $33,000 and $3,400 respectively. Now the computation of taxation liabilities will be computed as,
For Raphael, 10% of $33,000= $3,300;
For Martina, 10% of $3,400 = $340.
However, the joint income will be $61,200 and taxation liabilities of Raphael and Martina will be,
[tex]\rm Taxable\ Income = Total\ Income - Standard\ Deduction\\\\\rm Taxable\ Income =61200-24800\\\\\rm Taxable\ Income =\$36400[/tex]
Solving further,
[tex]\rm Joint\ Taxation = (\frac{10}{100}\ x\ 19750) + (\frac{12}{100}\ x\ 16650)\\\\\rm Joint\ Taxation = 1975+1998\\\\\rm Joint\ Taxation = \$3973[/tex]
Now, it can be compared that the joint taxation is higher than the summation of individual taxation of Raphael and Martina, and thus, tax benefits are not enough for Raphael and Martina to get married.
Hence, the tax benefits of Raphael and Martina after getting married are given as above.
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A chain weighs 12 pounds per foot. How many ounces will 7 inches weigh?
Answer:
The chain of the length 7 inches weighs 112 ounces.
Step-by-step explanation:
As we know there are 12 inches in a foot and 16 ounces in a pound
That is 1 foot = 12 inches.
and 1 pound = 16 ounces.
Given that the weight of the chain that is 1 foot long = 12 pounds
So weight of the chain per inch is = 12/12
which is equal to 1 pound
and according to the formula 1 pound = 16 ounces
So weight of the chain per inch is = 16 ounces
therefore weight of the chain that is 7 inch long = 7 × 16
that is 112 ounces.
The chain of the length 7 inches weighs 112 ounces.
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Which of the following are true statements?
Sum to n terms of each of following series. (a) 1 - 7a + 13a ^ 2 - 19a ^ 3+...
Notice that the difference in the absolute values of consecutive coefficients is constant:
|-7| - 1 = 6
13 - |-7| = 6
|-19| - 13 = 6
and so on. This means the coefficients in the given series
[tex]\displaystyle \sum_{i=1}^\infty c_i a^{i-1} = \sum_{i=1}^\infty |c_i| (-a)^{i-1} = 1 - 7a + 13a^2 - 19a^3 + \cdots[/tex]
occur in arithmetic progression; in particular, we have first value [tex]c_1 = 1[/tex] and for [tex]n>1[/tex], [tex]|c_i|=|c_{i-1}|+6[/tex]. Solving this recurrence, we end up with
[tex]|c_i| = |c_1| + 6(i-1) \implies |c_i| = 6i - 5[/tex]
So, the sum to [tex]n[/tex] terms of this series is
[tex]\displaystyle \sum_{i=1}^n (6i-5) (-a)^{i-1} = 6 \underbrace{\sum_{i=1}^n i (-a)^{i-1}}_{S'} - 5 \underbrace{\sum_{i=1}^n (-a)^{i-1}}_S[/tex]
The second sum [tex]S[/tex] is a standard geometric series, which is easy to compute:
[tex]S = 1 - a + a^2 - a^3 + \cdots + (-a)^{n-1}[/tex]
Multiply both sides by [tex]-a[/tex] :
[tex]-aS = -a + a^2 - a^3 + a^4 - \cdots + (-a)^n[/tex]
Subtract this from [tex]S[/tex] to eliminate the intermediate terms to end up with
[tex]S - (-aS) = 1 - (-a)^n \implies (1-(-a)) S = 1 - (-a)^n \implies S = \dfrac{1 - (-a)^n}{1 + a}[/tex]
The first sum [tex]S'[/tex] can be handled with simple algebraic manipulation.
[tex]S' = \displaystyle \sum_{i=1}^n i (-a)^{i-1}[/tex]
[tex]\displaystyle S' = \sum_{i=0}^{n-1} (i+1) (-a)^i[/tex]
[tex]\displaystyle S' = \sum_{i=0}^{n-1} i (-a)^i + \sum_{i=0}^{n-1} (-a)^i[/tex]
[tex]\displaystyle S' = \sum_{i=1}^{n-1} i (-a)^i + \sum_{i=1}^n (-a)^{i-1}[/tex]
[tex]\displaystyle S' = \sum_{i=1}^n i (-a)^i - n (-a)^n + S[/tex]
[tex]\displaystyle S' = -a \sum_{i=1}^n i (-a)^{i-1} - n (-a)^n + S[/tex]
[tex]\displaystyle S' = -a S' - n (-a)^n + \dfrac{1 - (-a)^n}{1 + a}[/tex]
[tex]\displaystyle (1 + a) S' = \dfrac{1 - (-a)^n - n (1 + a) (-a)^n}{1 + a}[/tex]
[tex]\displaystyle S' = \dfrac{1 - (n+1)(-a)^n + n (-a)^{n+1}}{(1+a)^2}[/tex]
Putting everything together, we have
[tex]\displaystyle \sum_{i=1}^n (6i-5) (-a)^{i-1} = 6 S' - 5 S[/tex]
[tex]\displaystyle \sum_{i=1}^n (6i-5) (-a)^{i-1} = 6 \dfrac{1 - (n+1)(-a)^n + n (-a)^{n+1}}{(1+a)^2} - 5 \dfrac{1 - (-a)^n}{1 + a}[/tex]
[tex]\displaystyle \sum_{i=1}^n (6i-5) (-a)^{i-1} =\boxed{\dfrac{1 - 5a - (6n+1) (-a)^n + (6n-5) (-a)^{n+1}}{(1+a)^2}}[/tex]
Eric recorded the number of automobiles that a used car dealer in his town sold in different price ranges. From the Histogram given, what is the number of cars sold for the price range of $4000 to $4999? A. 15 B. 20 C. 30 D. 50
The correct answer is option A which is the number of cars sold for the price range of $4000 to $4999 will be 15.
What is a histogram?
A histogram is a graph for the representation of the data on the plot of the rectangular boxes. It has the data sets on the horizontal and the vertical axes.
As we can see from the histogram data we will conclude that the price range of $4000 to $4999 is shown by the third block and this third block reaches the height of 15.
Therefore the correct answer is option A which is the number of cars sold in the price range of $4000 to $4999 will be 15.
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hi can you please help me with this question.
I need explanation too.
I'll like and rate your answer if your answer is right.
0 like and 1 rate for nonsense answer.
0 like and 2 rate if it's incorrect.
0 like and 3 rate if it is un-answer
1 like and 4 rate if it's correct a bit
1 like and 5 rate if it's very good answer.
Answer:
It appears to already be solved. What do you need help with?
Step-by-step explanation:
(a) 3.1563x106
(b) 5.65x10-4 convert to usual form
Answer:
[tex](a) \: 3.1563 \times {10}^{6} = 31563 \times {10}^{6} \times {10}^{ - 4} = 31563 \times {10}^{6 - 4} = 31563 \times {10}^{2} = 3156300[/tex]
__o__o__
[tex](b) \: 5.65 \times {10}^{ - 4} = 565 \times {10}^{ - 4} \times {10}^{ - 2} = 565 \times {10}^{ - 4 - 2} = 565 \times {10}^{ - 6} = 0.000565[/tex]
A chopstick model of a catapult launches a marshmallow in a classroom. The path of the marshmallow can be modeled by the quadratic y=−0.07x2+x+2.2,
where y represents the height of the marshmallow, in feet,
and x represents the horizontal distance from the point it is launched, in feet.
When the marshmallow hits the ground, what is its horizontal distance from the point where it was launched?
The horizontal distance from the point where it was launched is 7.143.
We have given that,
The path of the marshmallow can be modeled by the quadratic y=−0.07x^2+x+2.2,
x represents the horizontal distance from the point it is launched, in feet.
What is the horizontal distance?Horizontal distance means the distance between two points measured at a zero percent slope.
(1) Put x = 7.143 in given equation
y= -0.07(7.143)^2+7.143+2.2
y= 2.2
y= 5.771
We have to determine the what is its horizontal distance from the point where it was launched.
The value of x is called horizontal distance.
Therefore the horizontal distance from the point where it was launched is 7.143.
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Determine whether or not each of the following is a partition of set N of natural numbers. (With reason)
(a) {{n | n > 5}, {n | n < 5}]
(b) [{n | n > 6}, {1, 3,5} , {2, 4}]
(c) {{n | n^2 > 11}, {n | n^2 < 11}
Only Set B is a partition of set N of natural numbers .
What are Natural Numbers ?Numbers starting from 1 to infinity comes under Natural Numbers.
It is asked in the question that to determine whether or not each of the following is a partition of set N of natural numbers
A ) {{n | n > 5}, {n | n < 5}]
It is not a set of natural numbers as it does not include 5.
B ) [{n | n ≥ 6}, {1, 3,5} , {2, 4}]
{1,3,5} {2,4}and {n|n≥6} include all the natural numbers
Therefore , it forms a partition of N.
C ) {{n | n^2 > 11}, {n | n^2 < 11}
Every natural number n must satisfy either n^2 > 11 or n^2 < 11
This cannot be possible , therefore it is not the partition of Natural Numbers.
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Choose the equation that satisfies the data in the table.
[xy−100−41−8]
A. y=−4x−4
B. y=−14x+4
C. y=4x−4
D. y=14x+4
The linear equation that satisfy the data in the table is: A. y = −4x − 4.
How to Find the Linear Equation for a Data in a Table?Given the table attached below, find the slope (m) = change in y / change in x using two pairs of values, say, (-1, 0) and (0, -4):
Slope (m) = (-4 - 0)/(0 - (-1)) = -4/1 = -4
Find the y-intercept (b), which is the value of y when x = 0. From the table, when x = 0, y = -4.
b = -4.
Substitute m = -4 and b = -4 into y = mx + b
y = -4x + (-4)
y = -4x - 4
The equation that satisfy the data is: A. y = −4x − 4.
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A scientist studying insects start with a population of 10. the population triples every hour. how many insects wil there be after 20 minutes
The question is asking you to understand that a population which is raised by a common ratio over a certain time period follows an exponential pattern. See:
After 1 hour, the population is 3*10
After 2 hours, the population is 3*3*10
After 3 hours, the population is 3*3*3*10
.....
This can be generalised as a function of t, the time in hours:
f(t) = (3^t) * 10
Since the function determines the population at a given time, it is more prudent to replace f(t) with P, the population after time t:
P = (3^t) * 10
Since 20 minutes is equal to (1/3) hours, t can be substituted for (1/3) in order to calculate the population size after 20 minutes:
P = (3^(1/3)) * 10 = 14.4224957031 ≈ 14
Therefore the population after 20 minutes is 14.
which ordered pair is a solution to the following system of inequalities
Answer:
it's 1,1 is the correct ans
Step-by-step explanation:
Because my teacher told its absolutely correct answer I got the same question in exam
Answer:
the answer should be the 2 one
Step-by-step explanation:
I got it right just had it.
a) Construct a 95% confidence interval for the average test score for Delhi students. (1 Mark)
(b) Is there statistically significant evidence that Delhi students per form differently than other students in India? (1 Mark)
(c) Another 503 students are selected at random from Delhi. They are given a 3-hour preparation course before the test is administered. Their average test score is 1019, with a standard deviation of 95. Construct a 95% confidence interval for the change in average test score associated with the preparation course. (2 Marks)
(d) Is there statistically significant evidence that the preparation course helped? (1 Mark)
The solution to all the answers are given below.
The complete question includes
Grades on a standardized test are known to have a mean of 1,000 for students in the Delhi. 453
randomly selected Delhi students take the test, yielding sample mean of 1,013 and sample standard
deviation (s) of 108.
What is Confidence Interval ?It is given by
Confidence Interval for 95% confidence Interval is given by
[tex]\rm Z = X \pm 1.96 \dfrac{\sigma}{\sqrt{n}}[/tex]
(a) Construct a 95% confidence interval for the mean test score for Delhi students.
The confidence interval is given by
[tex]\rm 1,013 \pm 1.96 \dfrac{\sigma}{\sqrt{n}}[/tex]
[tex]\rm 1,013 \pm 1.96 \dfrac{108}{\sqrt{453}}[/tex]
1013 ± 5.07
so the interval is [1003.06,1022.94]
(b)Yes, since the null of no difference is rejected at the 5% significance level (interval excludes Delhi sample mean of 1,013)
(c) Another 503 Delhi students are randomly selected to take a 3-hour prep course and then give the test. Their average score is 1,019 with a standard deviation of 95.
The standard deviation now is
[tex]\rm \sqrt{\dfrac{95^2}{453} + \dfrac{108^2}{503}}[/tex]
= 6.61
The interval is given by
[tex](1,019-1,013) \pm 1.96 \dfrac{\sigma}{\sqrt{n}}[/tex]
= [-7,+19]
(d) No, the interval includes 0, the null difference between the two populations
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Which values of x and y would make the following expression represent a real number?
(4 +51)(x + yı)
O x = 4, y =
O x=-4, y = 0
Ox = 4, y = -5
O x = 0, y = 5
The values of x and y would make the following expression represent a real number is 4 and -5 respectively
Complex and real numberThe standard form of writing a complex number is given asl
z= x + iy
where
x is the real part
y is the imaginary part
Given the expression below;
(4 +5i)(x + yi)
Expand
4x + 4yi + 5ix + 5y(-1)
4x + 4yi + 5ix - 5y
Hence the values of x and y would make the following expression represent a real number is 4 and -5 respectively
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Need answers asap please
The inverse of a function is n(a) = (a+30)/3 option (A) is correct by using the concept of the inverse of a function.
What is a function?It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have a function:
a(n) = 3n - 30
To find make subject n and solve
a(n) + 30 = 3n
[tex]\rm n = \dfrac{a(n) + 30}{3}[/tex]
Plug n = n(a) and a(n) = a
[tex]\rm n(a) = \dfrac{a + 30}{3}[/tex]
Thus, the inverse of a function is n(a) = (a+30)/3 option (A) is correct by using the concept of the inverse of a function.
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Which of the following best describes the set of complex numbers?
OA. The set of all numbers of the form a+bi, where a and bare any
real numbers and i equals -1
B. The set of all numbers of the form abi, where a and bare any real
numbers and i equals 1
C. The set of all numbers of the form a+bi, where a and b are any
real numbers and i equals √-1
OD. The set of all numbers of the form abi, where a and b are any real
numbers and / equals -1
Answer:
C
Step-by-step explanation:
The correct statement is option C.
What is complex number?A real number and an imaginary number are effectively combined to create a complex number. The complex number is written as a+ib, where a and ib are real and imaginary numbers, respectively. Additionally, i = √-1 and both a and b are real numbers.
Since we know that
Complex number is of the form a+ib
Where,
a is real number belongs to real axis
And b is also a real number belongs to imaginary axis.
And the value of i = √-1
Thus,
The set of all numbers of the form a+bi, where a and b are any
real numbers and i equals √-1 is the correct statement.
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Acontinous random variable X has a pdf given by p(x) = (5x4 0≤x≤1 0, otherwise) Let Y=X3. Find the probability distribution function
I'll use the method of transformations.
If [tex]f_X(x)[/tex] denotes the PDF of [tex]X[/tex], and [tex]y=g(x)=x^3 \iff x=g^{-1}(y) = y^{1/3}[/tex], we have
[tex]f_Y(y) = f_X\left(g^{-1}(y)\right) \left|\dfrac{dg^{-1}}{dy}\right|[/tex]
[tex]\dfrac{dg^{-1}}{dy} = \dfrac13 y^{-2/3}[/tex]
[tex]\implies f_Y(y) = f_X\left(y^{1/3}\right) \left|\dfrac13 y^{-2/3}\right| = \boxed{\begin{cases} \dfrac53 y^{2/3} & \text{if } 0 \le y \le 1 \\ 0 & \text{otherwise} \end{cases}}[/tex]
Please help !! I will give 20 points for correct answer !!!!
i need help with this geometry question
Answer:
radius ≈ 15.5
Step-by-step explanation:
the radius is RS
the angle between a tangent and the radius at the point of contact is 90°
then Δ RST is a right triangle
using Pythagoras' identity in the right triangle.
the square on the hypotenuse is equal to the sum of the squares on the other 2 sides , then
RS² + ST² = RT² ( substitute values )
RS² + 7² = 17²
RS² + 49 = 289 ( subtract 49 from both sides )
RS² = 240 ( take square root of both sides )
RS = [tex]\sqrt{240}[/tex] ≈ 15.5 ( to 1 dec. place )
How many square decimeters are in 687.1 cm²?
Answer:
6.871 decimeters
Step-by-step explanation:
687.1 square centimeters = 6.871 square decimeters
1 dm² = 100 cm²
Answer:
6.871
Step-by-step explanation:
calculator
cho hàm số f(x) liên tục trên đoạn [a;b] và có nguyên hàm F(x) thỏa F(a)=10;F(b)=2022 Khi đó \int _a^b\: f(x) dx bằng
The result follows from the fundamental theorem of calculus.
[tex]\displaystyle \int_a^b f(x) \, dx = F(b) - F(a) = 2022 - 10 = \boxed{2012}[/tex]
The perimeter of a rectangle is 286 meters. Find the length and width if the length is an integer and the width is 5 times the next consecutive integer.
Answer:
See below
Step-by-step explanation:
I need help please……
Answer:
f=- 6, x=-1
f = - 6, x=-3
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Help me please help help
[tex]\angle P = \angle S \Rightarrow \angle S = 42 &^\circ\\\angle Q = \angle T \Rightarrow \angle S = 86 &^\circ\\\angle R = \angle U\\[/tex]
Sum of all angles in a triangle equals 180:
[tex]\angle R = 180 - (86 + 42) = 180 - 128 = 52[/tex]
Answer:
[tex]U = 52 &^ \circ[/tex]
BRAIN WARM UP MATHS?
We can make 64 different equations using the power of ten.
What is the power of a number?The power of a number identifies how many times that particular number is multiplied by itself.
Here, let us assume that the different equations = x
Using a power of 10, we have 10x making a total of 640.
10x = 640Divide both sides by 10
10x/10 = 640/10
x = 64
Therefore, we can conclude that we can make 64 different equations using the power of ten.
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Need help with algebra homework
Answer:
the answer for this problem is A, big
MATH PERCENTAGE QUESTION HELP!
1. 27400 spectators in a 40000 seat stadium percentage?
2. an archer scores 95 points out of a possible 125 points percentage?
Answer:
68.5% seats filled
76% points earned
Step-by-step explanation:
General outlineIdentify the whole and the partChange ratio into a percentageRatiosPercentages are formed when one finds a ratio of two related quantities, usually comparing the first partial quantity to the amount that "should" be there.
[tex]\text{ratio}=\dfrac {\text{the "part"}}{\text{the whole}}[/tex]
For instance, if you have a pie, and you eat half of the pie, you're in effect imagining the original pie (the whole pie) cut into two equal pieces, and you ate one of them (the "part" of a pie that you ate). To find the ratio of pie that you ate compared to the whole pie, we compare the part and the whole:
[tex]\text{ratio}=\dfrac {\text{the number of "parts" eaten}}{\text{the number of parts of the whole pie}}[/tex]
[tex]\text{ratio}=\dfrac {1}{2}[/tex]
If you had instead eaten three-quarters of the pie, you're in effect imagining the original pie cut into 4 equal pieces, and you ate 3 of them.
[tex]\text{ratio}=\dfrac {\text{the number of "parts" eaten}}{\text{the number of parts of the whole pie}}[/tex]
[tex]\text{ratio}=\dfrac {3}{4}[/tex]
There can be cases where the "part" is bigger than the whole. Suppose that you are baking pies and we want to find the ratio of the pies baked to the number that were needed, the number of pies you baked is the "part", and the number of pies needed is the whole. This could be thought of as the ratio of project completion.
If we need to bake 100 pies, and so far you have only baked 75, then our ratio is:
[tex]\text{ratio}=\dfrac {\text{the number of "parts" made}}{\text{the number of parts of the whole order}}[/tex]
[tex]\text{ratio}=\dfrac {75}{100}[/tex]
But, suppose you keep baking pies and later you have accidentally made more than the 100 total pies.... you've actually made 125 pies. Even though it's the bigger number, the number of pies you baked is still the "part" (even though it's bigger), and the number of pies needed is the whole.
[tex]\text{ratio}=\dfrac {\text{the number of "parts" made}}{\text{the number of parts of the whole order}}[/tex]
[tex]\text{ratio}=\dfrac {125}{100}[/tex]
PercentagesTo find a percentage from a ratio, there are two small steps:
Divide the two numbersMultiply that result by 100 to convert to a percentageGoing back to the pies:
When you ate half of the pie, your ratio of pie eaten was [tex]\frac{1}{2}[/tex]
Dividing the two numbers, the result is [tex]0.5[/tex]
Multiplying by 100 gives 50. So, the percentage of pie that you ate (if you ate half of the pie) is 50%
When you ate three-quarters of the pie, the ratio was [tex]\frac{3}{4}[/tex]
Dividing the two numbers, the result is 0.75
Multiplying by 100 gives 75. So, the percentage of pie that you ate (if you ate three-quarters of the pie) is 75%.
When you were making pies, and 100 pies were needed, but so far you'd only baked 75 pies, the ratio was [tex]\frac{75}{100}[/tex]
Dividing the two numbers, the result is 0.75
Multiplying by 100 gives 75. So, the percentage of the project that you've completed at that point is 75%.
Later, when you had made 125 pies, but only 100 pies were needed, the ratio was [tex]\frac{125}{100}[/tex]
Dividing the two numbers, the result is 1.25
Multiplying by 100 gives 125%. So, the percentage of pies you've made to complete the project at that point is 125%.... the number of pies that you've made is more than what you needed, so the baking project is more than 100% complete.
The questions1. 27400 spectators n a 40000 seat stadium percentage.
Here, it seems that the question is asking what percentage of the stadium is full, so the whole is the 40000 seats available, and the "part" is the 27400 spectators that have come to fill those seats.
[tex]\text{ratio}=\dfrac {\text{the number of spectators filling seats}}{\text{the total number of seats in the stadium}}[/tex]
[tex]\text{ratio}=\dfrac {27400}{40000}[/tex]
Dividing gives 0.685. Multiplying by 100 gives 68.5. So, 68.5% of the seats have been filled.
2. an archer scores 95 points out of a possible 125 points percentage
Here, it seems that the question is asking what percentage of the points possible were earned, so the whole is the 125 points possible, and the "part" is the 95 points that were earned.
[tex]\text{ratio}=\dfrac {\text{the number of points earned}}{\text{the total number of points possible}}[/tex]
[tex]\text{ratio}=\dfrac {95}{125}[/tex]
Dividing gives 0.76. Multiplying by 100 gives 76. So, 76% of points possible were earned.
Which is not a solution of sin 20 = 1?
A = 90
B = 45
C = 225
D = - 135
Out of 220 racers who started the marathon, 203 completed the race, 12 gave up, and 5 were disqualified. What percentage did not complete the marathon?
What is the vertex of the parabola defined by the equation
(x-2)² =-12(y-2)?
A (-12, 2)
B.
(2, 2)
C. (6,2)
D. (2,-2)
Answer: B. (2,2)
Step-by-step explanation:
The vertex of the parabola in the form [tex](x-h)^2 = 4p(y-k)[/tex] is (h, k).
Unas deportivas cuestan $600 he visto que hay una rebaja del 20% cuánto dinero rebajado las reporteras
Answer:
600/100*20=6*20=120
600-120=480$