1. a. Describe the type of energy that is observed when a musician's finger plucks a guitar string. does it give your ear kenetic or potential energy .​

Answer:

The average acceleration of the car is 5.2778 [tex]\frac{m}{s^{2} }[/tex]

Explanation:

The acceleration of an object is a magnitude that indicates how the speed of the object changes in a unit of time. That is, acceleration relates changes in velocity with the time in which they occur.

The expression for the calculation of the acceleration is:

[tex]acceleration=\frac{change of velocity}{time}[/tex]

In this case:

First, it is convenient to express the change in velocity in units of m/s, where 1 h = 3,600 s and 1 km = 1,000 m.

[tex]change of velocity= 95 \frac{km}{h} =95\frac{1,000 m}{3,600 s} =26.3889 \frac{m}{s}[/tex]

So, replacing in the definition of acceleration:

[tex]acceleration=\frac{26.3889\frac{m}{s} }{5 s}[/tex]

acceleration= 5.2778 [tex]\frac{m}{s^{2} }[/tex]

The average acceleration of the car is 5.2778 [tex]\frac{m}{s^{2} }[/tex]

Answer:

age of the cluster is 3.125 × 10⁸ years

Explanation:

Given that;

stars at the turnoff point in a star cluster have masses of about 4 solar masses

Age of the cluster?

we know that the main sequence lifetime of a star in solar lifetime(t) is related to the mass of the star in solar masses(M). expressed as

ζ = M^(-5/2)

our M is 4, so we substitute

ζ = 4^(-5/2)

ζ =  0.03125 solar lifetime

now convert the lifetime of star cluster into years

ζ = 0.03125 solar lifetime × (10¹⁰ years / 1 solar lifetime)

ζ = 312,500,000 ≈3.124 × 10⁸ years

therefore age of the cluster is 3.125 × 10⁸ years

Answer:

-19rad/s

Explanation:

Given

Initial angular velocity w0 = 57rad/s

Time = 3s

Final angular velocity wf = 0rad/s (car comes to stop)

Required

angular acceleration (α)

Using the equation of motion

wf = w0 + αt

Substitute the given value and get α;

0 = 57 + 3α

-57 = 3α

α = -57/3

α = -19rad/s (the negative sign shows that the car decelerated over time)

Answer:

945 m

Explanation:

First of all let's find the first acceleration before the first stop. We will use Newton's 3rd equation of motion;

v² = u² + 2as

a = (v² - u²)/2s

In this first motion, the initial velocity is given as u = 67 m/s, while the final velocity which is the stop is v = 0 m/s and the distance is s = 250 m

Thus;

a = (0² - 67²)/(2 × 250)

a = -4489/500

a = -8.978 m/s²

Now, to get the time spent for this 250 m distance, we will use Newton's 2nd law of motion;

s = ut + ½at²

Plugging in the relevant values;

250 = 67t + ½(-8.978)t²

250 = 67t - 4.489t²

4.489t² - 67t + 250 = 0

Using quadratic formula, we will arrive at;

t = 7.463 s

Now, we are told that she accelerates out, reaching her previous speed of 67.0 m/s after a distance of 360 m. Thus, let's calculate the time it took to accelerate after a distance of 360 m.

Since she stayed from rest in this phase, then initial velocity (u) = 0 m/s.

Like in the first phase, we can find the acceleration from;

a = (v² - u²)/2s

a = (67² - 0²)/(2 × 360)

a = 4489/720

a = 6.235 m/s²

Thus, we can find the time for this 360 m phase by using; s = ut + ½at², we have;

360 = 0 + ½(6.235)t²

Multiply through by 2 to get;

6.235t² = 720

t² = 720/6.235

t² = 115.477145

t = √115.477145

t = 10.746 s

We are told that she spends 5 s in the pit. Thus;

Total time is;

t_total = 7.463 + 5 + 10.746

t_total = 23.209 s

Distance covered by the Mercedes Benz = 67 × 23.209 = 1555 m

Total distance covered by Thunderbird = 250 + 360 = 610 m

Thus, distance of Thunderbird behind Mercedes Benz is = 1555 - 610 = 945 m

Answer:

W=k[tex]x^{2}[/tex]/2 = 576 j

Explanation:

Answer:

309.02g

Explanation:

According to the information given in this question, the cylinder has the following:

Mass = ?

Length/height = 10.55cm

Diameter = 4.00cm

Volume of a cylinder = πr²h

Where; π = pie (3.142 or 22/7)

r = radius (cm)

h = height

Note that, radius = diameter/2

Hence, radius (r) = 4.00/2

r = 2.00cm.

V = πr²h

V = 22/7 × 2² × 10.55

V = 22/7 × 42.2

V = 928.4/7

V = 132.628cm³

Density = mass/volume

Hence, mass = density × volume

Where density of silicon is 2.33g/cm³

Mass = 2.33g/cm³ × 132.628cm³

Mass = 309.02g

Answer:

40.2 N

Explanation:

I'm an Acellus student who got it correct.

The magnitude of  y-component of the total force on the skier is 40.18 N.

Force is an influence which tends to set a stationary body in motion or stop a moving body, or which tends to change the speed and direction of a moving body, or which tends to change the shape and size of body.

Given parameters:

Mass of the water: M = 73.8 kg.

Magnitude of force acting at 22.5° angle is: F₁ = 105 N.

Magnitude of force acting at directly backwards is: F₂ = 74.8 N.

We have to find: the y-component of the total force on the skier = ?

As F₂ acting directly backwards, this force has no y-component.

Hence, resultant y-component of the total force on the skier

= F₁ sin22.5°

= 105 ×sin22.5° N.

= 40.18 N.

Hence, magnitude of  y-component of the total force on the skier is 40.18 N.

Learn more about force here:

https://brainly.com/question/13191643

#SPJ2

Answer:

D. They are all heat insulators.

Explanation:

Those things mentioned above are examples of heat insulators. As a heat insulator, it helps to prevent the heat from leaving the body thereby keeping the body warm and risk free.Feathers in birds and overcoat in humans helps to keep the bodies of the wearer safe and warm during the cold season.

Answer:

Answer

b) Coasting does not dedcribe acceleration

Answer:

The calculated value of the specific heat capacity of the metal will be larger than the actual value

Explanation:

If some of the hot water is transferred to the Calorimeter along with the metal object whose specific heat is to calculated the effect will be that the calculated value of the specific heat of the metal will be larger than normal

this can  be explained with the equation below

= heat transferred to liquid in which metal was / Δ T metal

where ΔTmetal < heat transferred to liquid

Answer:

Explanation:

If e be the charge on the electron and v be its drift speed after undergoing voltage drop of 118.8 V

eV = 1/2 m v²

1.6 x 10⁻¹⁹ x 118.8 = 1/2 x 9.1 x 10⁻³¹ v²

v² = 41.775 x 10¹²

v = 6.46 x 10⁶ m /s

drift speed of electron = 6.46 x 10⁶ m /s

Answer:

B and D

Explanation:

Answer:

It is B. inherits all the traits from its parent

And D. is identical to the parent's structure

Explanation:

Hope this helped have an amazing day!

Answer:

[tex]a_c=0.016 \ m/s^2[/tex]

Explanation:

Centripetal acceleration: Is the acceleration experienced by an object while in a uniform circular motion. It points toward the center of rotation and is perpendicular to the linear velocity v and has the magnitude:

[tex]\displaystyle a_c=\frac{v^2}{r}[/tex]

Where v is the linear velocity and r is the radius of the circle.

It's given a hurricane with a radius r=70 Km = 70,000 m has a tangential wind velocity of v=33 m/s. The acceleration of a particle lying on the edge of the hurricane is:

[tex]\displaystyle a_c=\frac{33^2}{70,000}[/tex]

[tex]\boxed{a_c=0.016 \ m/s^2}[/tex]

Answer:

35 meters

20+15=35

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

From the question we have

force = 8.5 × 9.8

We have the final answer as

Hope this helps you

Answer:

There are [tex]9.053\times 10^{14}[/tex] charge carriers.

Explanation:

Given that,

Current density (current per unit time), [tex]\dfrac{I}{A}=1.55\ A/cm^2=0.000155\ A/m^2[/tex]

The drift velocity of the electron, [tex]v_d=107\ cm/s=1.07\ m/s[/tex]

We need to find the no charge carriers present. The formula for drift velocity is given by :

[tex]v_d=\dfrac{I}{neA}\\\\\text{n is no of charge carriers}\\\\n=\dfrac{I}{eAv_d}\\\\n=\dfrac{0.000155}{1.6\times 10^{-19}\times 1.07}\\\\n=9.053\times 10^{14}[/tex]

So, there are [tex]9.053\times 10^{14}[/tex] charge carriers.

Answer:

400 seconds

Explanation:

Divide the total distance by the unit rate

200/0.5 = 400

400 seconds

Answer:

400 seconds

Explanation:

Answer:

Moles

Explanation:

Moles can be used to measure the quantity of any substance. A mole of water is a small mouthful; a mole of elephants is about the size of the planet Saturn.

Answer:

2 m/s

Explanation:

We will apply the law of conservation of energy to solve this.

The initial spring potential energy = final spring potential energy + kinetic energy of cork, this means that

1/2kx² = 1/2kx'² + 1/2mv², and this is

kx² = kx'² + mv²

From the question, we are given that

k = 10N/m

x = 5cm = 0.05 m

x' = 1cm = 0.01 m

m = 6g = 0.006 kg

Substituting these values to the formula, and we get,

10(0.05)² = 10(0.01)² + 0.006v²

10 * 0.0025 = 10 * 0.0001 + 0.006 v²

0.025 = 0.001 + 0.006v², multiplying all sides by 1000, we have

25 = 1 + 6v²

6v² = 25 - 1

6v² = 24

v² = 24 / 6

v² = 4

v = √4

v = 2 m/s

⇒25 - 1 = 6v²

⇒v² = 24/6 = 4

⇒v = 2 m/s

Answer:

Explained below.

Explanation:

A flyback diode is simply defined as a diode that is connected across an inductor in order to eliminate the sudden spike in voltage that's seen across an inductive load when its supply current is unexpectedly reduced or interrupted. This sudden spike in voltage is known as flyback.

It's very important to place this flyback diode in parallel with the coil in a relay circuit because it allows current to pass through with minimal resistance thereby preventing flyback voltage from building up when power is disconnected.

Complete question is;

A 13g bullet traveling 230 m/s penetrates a 2.0 kg block of wood and emerges going 170 m/s. If the block is stationary on a frictionless surface when hit, how fast does it move after the bullet emerges?

Answer:

0.39 m/s

Explanation:

From the question, we can deduce that there is no external force acting on the

system in the horizontal direction. This means that momentum will be conserved for the system of the 2 kg block & the bullet.

Thus;

Initial momentum(p_i) = final momentum(p_f)

Mass of bullet; = 13g = 0.013 kg

Mass of Block = 2 kg

Speed of bullet = 230 m/s

Speed of Block = 170 m/s

We know that formula for momentum is; p = mv.

Thus, the initial momentum of the (bullet + block) is given as;

p_i = 0.013 × 230

Final momentum is;

p_f = (0.013 × 170) + (2 × v_f)

Where v_f is the speed at which the bullet emerges.

Since p_i = p_f from conservation of momentum, then;

(0.013 × 230) = (0.013 × 170) + (2 × v_f)

2.99 = 2.21 + 2v_f

2.99 - 2.21 = 2v_f

0.78 = 2v_f

v_f = 0.78/2

v_f = 0.39 m/s

Answer:

humans

Explanation:

mhm

Answer:

0.5 pounds per square inches (ibs/in²)

Explanation:

The pressure of an object refers to the force it exerts per unit area i.e. F/a. In this question, the force, F, is created by the weight, W, of the snowshoe. Hence, pressure is calculated thus:

P = W/A

Where; P = Pressure (ibs/in²)

W = Weight of object (ibs)

A = surface area (in²)

In this question, weight = 200 pounds, Area = 400 square inches

Hence, pressure = 200/400

Pressure (P) = 2/4

Pressure (P) = 0.5 ibs/in²

Answer:

A.) 37.8 m/s

B.) No

C.) 172 m

Explanation:

Given that  car accelerates in the +x direction from rest with a constant acceleration of a1 = 1.89 m/s^2 for t1 = 20 s. At that point the driver notices a tree limb that has fallen on the road and brakes hard for t2 s until it comes to a stop. Required:

a.) Write an expression for the car's speed just before the driver begins braking, v1.

Since the car accelerate from rest, initial velocity U = 0

Using first equation of motion

V1 = U + at

V1 = 1.89 × 20

V1 = 37.8 m/s

b.) If the limb is on the road at a distance of 550 meters from where the car began its initial acceleration, will the car hit the limb?

Using third equation of motion

V^2 = U^2 + 2as

37.8^2 = 0 + 2 × 1.89 × S

1428.84 = 3.78S

S = 1428.84 / 3.78

S = 378m

Since the limb is on the road at a distance of 550 meters from where the car began its initial acceleration, we can therefore conclude that the car will not hit the limb.

c. How far, in meters, from the original location of the limb will the car be when it stops?

550 - 378 = 172 m

The car will be 172 metres from the limb.

Answer:

[tex]f = \frac{v}{2\pi r }[/tex]

Explanation:

A cyclist riding a bike whose wheels have a radius of r, moving with constant speed v along a flat straight road.

The frequency of the vibrations is the same as the frequency of the rotation of the wheel and this can be represented as below

V = R(w )     where ; w = [tex]2\pi f[/tex]

[tex]f = \frac{v}{2\pi r }[/tex]

Answer:

Explanation:

Since both loads at connected in parallel, the voltage across them will be the same.

The voltage across parallel connected loads are the same.

Let the loads be R1 and R2

Power = IV

I is the current

V is the voltage

P= V²/R

R = V²/P

Get the first load R1

R1 = V²/P1

R1 = 120²/40

R1 = 360ohms

Get the second load R2

R2 = V²/P2

R2 = 120²/75

R2 = 192ohms

Current in R1 will be;

P1 = I1²R1

I1² = P/R1

I1² = 40/360

I1² = 1/9

I1 = √1/9

I1 = 1/3

I = 0.33A

Current in R2(second load) will be;

P2 = I2²R2

I2² = P/R2

I2² = 75/192

I2² = 0.390625

I2 = √0.390625

I2 = 0.625A

The video showing the movement of the cart during the time interval is gotten from the link;

https://mediaplayer.pearsoncmg.com/assets/_frames.true/frames.true_white_ruler

Answer:

V_avg = 1.8 m/s

Explanation:

From the video, the distance moved by the cart during the 24 frames is 18 cm or 0.18 m.

Now, the speed is at the rate of 240 frames per seconds.

Now, average velocity is given as;

V_avg = distance/time

Time = 24 frames/240 frames/s

Time = 0.1 s

Thus;

V_avg = 0.18/0.1

V_avg = 1.8 m/s

Answer:

[tex] \huge{ \boxed {\bold{ \tt{160 \: N}}}}[/tex]

Explanation:

[tex] \boxed{ \sf{Force = Mass \: \times \: Acceleration}}[/tex]

[tex] \sf{➛ force \: = 10\: \times 16}[/tex]

[tex] \sf{➛ force = 160 \: Newton}[/tex]

The amount of force is 160 N

Hope I helped!

Best regards! :D

~TheAnimeGirl

Answer:

hello your question is incomplete attached below is the missing circuit diagram

answer : 3 unique currents

Explanation:

From the circuit attached below it can be seen that there will be Three(3) unique currents flowing through this circuit and the Branches where this currents could differ is at the Three(3) resistors