Answer:
I think its C and D
Explanation:
Why is it important to keep a fitness journal?
Answer:
To see how well you are doing.
Explanation:
Maintaining an exercise journal helps a person keep track of progress and see firsthand if he or she is sticking to a steady exercise routine.
A fitness journal is a valuable tool that provides structure, accountability, and motivation while allowing you to track progress and make informed decisions to optimize your workouts and well-being.
Monitoring Progress: Keeping a fitness journal enables you to monitor and assess your advancement over time. You may track your progress in terms of fitness by keeping track of the exercises you do, their time, and their intensity. This keeps you motivated and reveals any areas where you might need to change your workouts to efficiently attain your goals. Setting Goals: Putting your fitness objectives in writing in a journal will help you clarify your objectives. You can plan and monitor your progress towards reaching your goals if they are clear and explicit. This helps you maintain your commitment to your fitness journey by keeping you focused and giving you a feeling of direction.
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For Horizontal Distance formula is,
[tex]R = \frac{V_{o} ^2}{g} Sin2[/tex] θ
where,
R is range or horizontal distance
[tex]V_{o}[/tex] is initial velocity
g is acceleration due to gravity
θ is the angel it makes
so,
by putting the initial velocity and EACH ANGEL that is given in the data,
we will get range respectively,
for 31 degree = 565m
for 89 degrees= 22m
for 17 degrees = 357.88m
for 49 degrees = 633.77m
for 40 degrees = 630.27m
for 78 degrees = 260.3 m
SO FROM SHORTEST TO LONGEST IS,
89 degrees i.e. 22m , 78 degrees i.e. 260.3 m, 17 degrees i.e. 357.88m, 40 degrees i.e. 630.27m, 49 degrees i.e. 633.77m
I HOPE IT HELPS YOU :)
How long was Michael Jordan in the air when he jumped straight up with a speed of 4.5 m/s? I know the answer is 0.918 seconds, but I don't know how to get there.
Answer:
Explanation:
Using the equation of motion
v = u+gt
v is the final velocity
u si the initial velocity
g is the acceleration due to gravity
t is the time
Substitute
0 = 4.5-(9.8)t
-4.5 = -9.8t
t = 4.5/9.8
t = 0.459s
Why does lighting usually
lighting usually strike build
buildings and electric poles ?
GREETINGS!
lightening usually strikes the metal pole and cables above the building because they provide a safe low resistance pathway to the lightening to move from building from the concrete steel to the ground below, thats how building doesnt get any damage and high electric charge passes through it
HOPE IT HELPS YOU!
The elements least likely to form bonds are found in which group?
15
ООО
16
O 18
Answer:
It would be O 18
A 2455 kg car was pushed by 77 kg student with a force of 720 N. What force does the car apply on the student?
a.0 N
b.-797 N
c.- 720 N
d.-3175 N
Answer:
C
Explanation:
Given that a 2455 kg car was pushed by 77 kg student with a force of 720 N.
According to Newton's third law of motion which state that in every action, there will be equal and opposite reaction.
The action on the car = 720 N
The reaction from the car = - 720 N
Therefore, the force the car will apply on the student will be -720N.
The correct answer is C
Distance between the centres of charged body is inevrsley proportional to the magnitude of electric force.
TRUE or FALSE
Answer:
TRUE
Explanation:
A ball is thrown eastward into the air from the origin (in the direction of the positive x-axis). The initial velocity is 40 i + 32 k, with speed measured in feet per second. The spin of the ball results in a southward acceleration of 6 ft/s2, so the acceleration vector is a = −6 j − 32 k. Where does the ball land? (Round your answers to one decimal place.) ft from the origin at an angle of ° from the eastern direction toward the south. With what speed does the ball hit the ground? (Round your answer to one decimal place.) ft/s
Answer:
The answer is "52.61 ft/s"
Explanation:
Taking the motion in the z-direction is [tex]u_z = 32 , \ \ a_z = - 32[/tex]
[tex]t = 2 \frac{u_z}{( - a_z )}\\\\[/tex]
[tex]= 2 \times \frac{32}{32}\\\\ = 2 \ sec\\\\[/tex]
z-axis change is zero z and the x-path the same way:
[tex]= u_x t + \frac{1}{2} a_x t^2 \\\\= 40 \times 2 + 0.5 \times 0 \times 2^2 \\\\ = 40 \times 2 + 0.5 \times 0 \times 4 \\\\ = 80 +0\\\\= 80 \ ft \ \ i[/tex]
In y-direction:
[tex]= 0 \times t - \frac{1}{2} \times (6) \times 2^2\\\\ = - \frac{1}{2} \times (6) \times 4\\\\ = - (6) \times 2\\\\= - 12 ft \ \ j[/tex]
the ball lands at:[tex]( 80 i - 12 j + 0 k ) ft[/tex]
Magnitude:
[tex]\to ( 80^2 + (-12)^2 )^{\frac{1}{2}}\\\\\to ( 6400 + 144 )^{\frac{1}{2}}\\\\\to ( 6544 )^{\frac{1}{2}}\\\\\to 80.89 \ ft[/tex]from the origin.
angle:
[tex]\to \tan^{-1} ( \frac{12}{80} )\\\\\to 8.53^{\circ}[/tex]
velocity:
[tex]\to 40 i + ( 0 - 6 \times 2 ) j + ( 32- 32 \times 2 ) k\\\\\to 40 i + ( - 12 ) j + ( 32- 64 ) k\\\\\to 40 i - 12 j - 32 k\\\\\to ( 40^2 + 12^2 + 32^2 )^{\frac{1}{2}}\\\\\to (1600+144+1024)^{\frac{1}{2}}\\\\\to 2768^{\frac{1}{2}}\\\\\to 52.61\ \ \frac{ft}{s}[/tex]
A bus travel 400 m between 2 stops. It starts from rest and accelerates at 1.5 m / s ^ 2 until it reaches a speed of 5m / s. The bus continuous at this speed and then decelerates at 2 m / s ^ 2 until it comes to a stop. Find the total time required for the journey.
Answer:
Explanation:
Time during which there was acceleration = (v - u) / a = 5 / 1.5 = 3.33 s
Time during which there was deceleration = (v - u) / a = 5 / 2 = 2.5 s
Distance travelled during acceleration = 1 /2 a x t² = 1/2 x 1.5 x 3.33²
= 8.32 m
Distance travelled during deceleration = 1 /2 a x t² = 1/2 x 2 x 2.5²
= 6.25 m
Total distance travelled = 400 m
distance travelled when the velocity was uniform = 400 - ( 6.25 + 8.32 )
= 385.43 m
uniform velocity = 5 m /s
time during uniform velocity existed
= 385.43 / 5 = 77.1 s
Total time required in the journey = 77.1 + 3.33 + 2.5
= 82.93 s
Rita's bike starts from rest and accelerates at 2.0m/s2. Where will she be relative to her starting point after 7 seconds? What
is her velocity after 2s and 7s?
Answer:
She will be at 49m from her starting point in 7s
Explanation:
V = AT 2s V = 2*2 = 4m/s 7s V = = 2*7 = 14 m/s
D = 1/2AT^2 for 7 sec = 1/2*2 m/s^2 * 7s^2
= 1/2*2*49
= 49m
a 1200 kg car travels at a constant velocity of 15 m/s. what is the net force on the car?
Answer:
The answer is 18,000 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × accelerationFrom the question we have
force = 1200 × 15
We have the final answer as
18,000 NHope this helps you
Find the acceleration of an object when the force is 850 N and the mass is 85 kg.
Answer:
ok sooooo,
F=MA
you are looking for a
you have F= 850 N and M= 85 kg
you divide the force with the mass
you get A= 10 m/s²
As you move from a gas to the solid state forces of attraction do what?
Answer:
Gas – In a gas, particles are in continual straight-line motion. The kinetic energy of the molecule is greater than the attractive force between them, thus they are much farther apart and move freely of each other. In most cases, there are essentially no attractive forces between particles.
Explanation:
Answer:
The molecules of a gas move apart when they collide. The average kinetic energy of the particles in a liquid (or solid) is small enough that the forces of attraction between them is sufficient to hold the particles close together. The molecules in a liquid (or solid) do not move apart.
Explanation:
Gas – In a gas, particles are in continual straight-line motion. The kinetic energy of the molecule is greater than the attractive force between them, thus they are much farther apart and move freely of each other. In most cases, there are essentially no attractive forces between particles.
23) A ball was thrown straight up into the air at 50. m/s, how fast was it going 2.2 seconds later? (acceleration = g = -9.8 m/s2)
Answer:
-9.8m/s^2 x 2.2 = -21.56m/s^2 50m/s - 21.56m/s^2 = 28.44m/s
If you threw a rock somewhere with no gravity or friction the rock would..
A.) Continue at the same speed in the same direction.
B.) Stop.
C.) Move forward quickly then slowly.
D.) Move forward slowly then fall.
Answer:
A
Explanation:
Once the stone is thrown, with direction vectors and initial velocity will keep on traveling for infinite period unless there is another force to stop it.
For example, Newton's 1st law of Motion: ''Every inanimate body will continue its state of rest/motion unless acted upon by an external unbalanced force''
Since there is no friction, drag or any viscous force, our stone will travel for infinite period of time.
I hope this helps :)
what do you mean by quantization of energy?
Answer:
The quantization of energy refers to the fact that at subatomic levels, energy is best thought of as occuring in discreet "packets" called photons. The red and blue photons are therefore "quantized" just as dollar bill denominations are "quantized". Each photon contains a unique amount of discreet energy.
a 24 N force is being applied to the right, while a 345 N force is being applied to the left of a 18 kg crate.
What is the acceleration of the crate?
Answer:
a = 17.83 m/s²
Explanation:
Given:
Fnet = 345N - 24N
m = 18kg
Unknown:
a or Acceleration of the crate
Formula and solution:
Fnet = F1 + F2
Fnet = 345N - 24N
Fnet = 321N
a = Fnet/m
a = 321 kg m/s² ÷ 18 kg
Final Answer:
a = 17.83 m/s²
Electromagnetic induction is the process of producing an electric current by moving a loop of wire ____.
Answer:
through a magnetic field.
Explanation:
Which atom is most likely to accept electrons to form an ionic bond?
A. a mercury ion with a negative 2 charge
B. a potassium ion with a negative 1 charge
C. radon, a noble gas with 8 valence electrons
D. sulfur, a nonmetal with 6 valence electrons
Answer:
D.
Explanation:
Why are copies of stored digital data better than copies of stored analog
data?
A. The quality of the copies is the same, but digital data can be
copied more quickly.
B. Digital data contain only two different values, so it is easy to
distinguish between them.
c. Digital data contain many continuous values, so it is easy to
distinguish among them.
D. When many copies are made, the quality of digital copies
decreases, but not as much as that of analog copies.
Answer:
letter D.
Explanation:
When many copies are made, the quality of digital copies
decreases, but not as much as that of analog copies.
When many copies are made, the quality of digital copies decreases, but not as much as that of analog copies. Option D is correct.
What is digital data?Digital data is information represented as a string of discrete symbols, each of which can take only one of a finite number of values from some alphabet
The primary aim of digital memory is to enable the storage and retrieval of binary data.
The benefits of digital storage of information over analog procedures are similar to the advantages of digital communication of information over analog communication.
Copies of stored digital data are better than copies of stored analog data. When many copies are made, the quality of digital copies decreases, but not as much as that of analog copies.
Hence option D is correct.
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How does science help us understand Earth’s complex systems?
A. By focusing only on humans, it helps us understand how people are affected by Earth’s systems.
B. By viewing the Earth as a single integrated system, it helps us understand how humanity and Earth are related, and how the systems work
C. By viewing the Earth as many separate systems, it helps us understand how each system functions alone.
D. By looking at other planets, it helps us understand their complex systems and how they are similar to ours.
Answer:
C
Explanation:
By viewing the earth as many separate systems, it helps us understand how each system functions alone
If F = G(m1, x xm2)/r2
m2 = ?
I need help!
A 1200 kg car accelerates at a rate of 3.97 m/s^2. What is the net force acting on the car?
Answer:
The answer is 4764 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × accelerationFrom the question we have
force = 1200 × 3.97
We have the final answer as
4764 NHope this helps you
2. What is the net force exerted on a 80.0 kg race-car driver while the race
car is accelerating from 0 to 50.0 m/s in 5.50 s?*
Answer:
The net force exerted on the race-car driver is 727.3 N
Explanation:
Acceleration
According to Newton's second law of motion, the acceleration of an object a is directly proportional to the net force F and inversely proportional to the object's mass m:
[tex]F=m.a[/tex]
Since we don't have the value of the acceleration, we must use the kinematic equations to calculate it.
The main formula for accelerated motion is:
[tex]v_f=v_o+a.t[/tex]
Where vf is the final speed of the object, vo is its initial speed, a is the acceleration, and t is the time.
The race-car driver accelerates from vo=0 to 50 m/s in t=5.5 s. We can calculate the acceleration, solving the above equation for a:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
[tex]\displaystyle a=\frac{50-0}{5.5}[/tex]
[tex]a=9.09\ m/s^2[/tex]
Now we calculate the net force:
[tex]F=80\ Kg\cdot 9.09\ m/s^2[/tex]
[tex]\boxed{F=727.3\ N}[/tex]
The net force exerted on the race-car driver is 727.3 N
A car in front of the school goes from rest to 27 m/s in 3.0 seconds. What is its acceleration?
Answer:
9m/s^2
Explanation:
v= v0+at
27= 0 + (a* 3.0)
= 9
A test rocket is launched by accelerating it along a 200.0 m, 35 degree incline at 1.25 m/s/s starting
from rest. The instant the rocket leaves the incline, its engines turn off, it is subject only to gravity,
and air resistance can be ignored. Find
a) the maximum height above the ground the rocket reaches
Answer:
The maximum height above the ground the rocket reaches is 123.1 m.
Explanation:
Let's find the final velocity at a distance of 200 m:
[tex] v_{f}^{2} = v_{0}^{2} + 2ad [/tex]
Where:
[tex]v_{f}[/tex] is the final speed =?
v₀ is the initial speed =0
a is the acceleration = 1.25 m/s²
d is the distance = 200 m
[tex]v_{f} = \sqrt{2ad} = \sqrt{2*1.25 m/s{2}*200 m/s} = 22.4 m/s[/tex]
Now, when the engines of the rocket turn off and it is subject only to gravity, the height reached is:
[tex] v_{fy}^{2} = v_{0y}^{2} - 2gh [/tex]
Where:
[tex]v_{f}[/tex] = 0
[tex]h = -\frac{v_{fy}^{2} - v_{0y}^{2}*sin(\theta)}{2g} = \frac{(22.4*sin(35))^{2}}{2*9.81 m/s^{2}} = 8.4 m[/tex]
Finally, the maximum height above the ground is:
[tex] h_{max} = h + H [/tex]
Where H is the vertical component of the 200.0 meters.
[tex]h_{max} = h + H = 8.4 m + 200.0 m*sin(35) = 123.1 m[/tex]
Therefore, the maximum height above the ground the rocket reaches is 123.1 m.
I hope it helps you!
When one resistor in a series is shorted, explain what would happen to the circuit's current, resistance, the voltage across the shorted component, and voltage across the other components
Answer:
A. The circuit's current drops. b. The circuit's resistance drops c. The voltage across it is zero d. The voltage remains the same.
Explanation:
a. What would happen to the circuit's current
Since the circuit is in series and one resistor is shorted, the current in the circuit would drop since it is a series circuit and one resistor has been shorted.
b. What would happen to the circuit's resistance
The resistance of the circuit drops by the value of the resistance shorted since it is a series circuit and the shorting cuts off this resistor from the circuit.
c. What would happen to the voltage across the shorted component
The voltage across the shorted component is zero because, since no current flows through it and we know that voltage V = IR and if I = 0, V = 0 × R = 0 V. So, the voltage across it is zero.
d. What would happen to the voltage across the other components
The voltage across the other components remains the same as the initial voltage because, the short transfers the current across the shorted component and makes the shorted component disappear from the circuit. The short thus makes it seem like the source voltage is directly connected to the other components across the shorted resistor. So, the new voltage across the other components is the initial voltage in the circuit before the short.
A cross-country skier moves 36 meters eastward, then 44
meters westward, and finally 22 meters eastward.
For this motion, what is the distance moved?
Tap button at left to enter
Distance = 102
answer using our built-in
number pad.
What is the magnitude and direction of the
displacement?
Magnitude =
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answer using our built-in
number pad
Dir'n =
(Tap field to change.)
Check Answers
Answer:
a) 102 meters
b) 14 meters
c) The direction is eastward.
Explanation:
Distance is said to be the length between two points. It is a scalar quantity.
a) The distance moved = 36 + 44 + 22
= 102 meters
b) Displacement is the distance moved in a specified direction.
Representing the distance moved with specific direction as a directed number, 36 meters eastward = +36, 44 meters westward = -44, and 22 meters eastward = +22
/Displacement/ = +36 -44 +22
= +58-44
= 14
The magnitude of the displacement is 14 meters.
c) The direction is eastward.
So that the magnitude of displacement and his direction is 14 meters eastward.
Identify the possible source of Earth's magnetic field.
Answer:
The magnetic field is generated by electric currents due to the motion of convection currents of a mixture of molten iron and nickel in the Earth's outer core: these convection currents are caused by heat escaping from the core, a natural process called a geodynamo.Explanation:
[tex]hii[/tex]
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The atomic particles given off as a result of nuclear fission are _____ and _____.
beta
alpha
omega
gamma
Answer:
The atomic particles given off as a result of nuclear fission are alpha and beta.
Explanation: