Which multiplication expression does the model show?

Answer: 5

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

positive, the longer she run, the longer she jump

Answer:

c is the answer

Step-by-step explanation:

your welcome

Let's solve this problem step-by-step:

   [tex]7 * 9 = (7*10)-(7*x)[/tex]

We know (7*10) - (7*x) is equivalent to the 7*(10-x)

 ⇒ based on the Distributive Properties

                           [tex]a*(b+c) = ab + ac[/tex]  

          [tex]7*(10+(-x))=(7*10)+(7*(-x)=(7*10)-(7*x)[/tex]

 So:

   [tex]7*9=7(10-x)\\9=10-x\\x=10-9\\x= 1[/tex]

Thus delta (the little triangle in this problem) in this case is 1

Answer: 1

Hope that helps!

Answer:

Step-by-step explanation:

congruent slices means all slices with same shape and angle

a circle has 360 (angle)

For 2, 180

For 3, 120

For 4, 90

For 5, 72

For 6, 60

For 8, 45

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

#1. Number of small cubes in the large solid ~

[tex]\qquad \sf  \dashrightarrow \: 3 \times 3 \times 2[/tex]

[tex]\qquad \sf  \dashrightarrow \: 18 \: \: small \: \: cubes[/tex]

#2. Volume of each small cube ~

[tex]\qquad \sf  \dashrightarrow \: v = { \bigg(\dfrac{1}{3} \bigg) }^{3} [/tex]

[tex]\qquad \sf  \dashrightarrow \: v = { \dfrac{1}{3 {}^{3} }}^{} [/tex]

[tex]\qquad \sf  \dashrightarrow \: v = { \dfrac{1}{27{}^{} }}^{} \: \: m {}^{3} [/tex]

#3. Volume of large solid is :

[tex] \dashrightarrow \sf vol \: (small \: cube)\times\: no. \: of \: small \: cubes[/tex]

[tex]\qquad \sf  \dashrightarrow \: \dfrac{1}{27} \times 18 [/tex]

[tex]\qquad \sf  \dashrightarrow \: \dfrac{2}{3} \: \: {m}^{3} [/tex]

Answer:

hello!

Step-by-step explanation:

Answer:

24

Step-by-step explanation:

k = t - 5k

→ Substitute in k

4 = t - 20

→ Add 20 to both sides

24 = t

Rationalizing the denominator of the expression, it is found that the simplified expression is given by:

[tex]\frac{\sqrt{6}(12x + 20x^2) + 3\sqrt{x} + 5\sqrt{x^3}}{x(96x - x)}[/tex]

It is given by:

[tex]\frac{3 + 5\sqrt{x^2}}{4\sqrt{6x^2} - \sqrt{x}}[/tex]

We rationalize the denominator, using the subtraction of perfect squares, hence:

[tex]\frac{3 + 5\sqrt{x^2}}{4\sqrt{6x^2} - \sqrt{x}} \times \frac{4\sqrt{6x^2} + \sqrt{x}}{4\sqrt{6x^2} + \sqrt{x}}[/tex]

Then, solving the expression:

[tex]\frac{(3 + 5\sqrt{x^2})(4\sqrt{6x^2} + \sqrt{x})}{16(6x^2) - x}[/tex]

[tex]\frac{12\sqrt{6x^2} + 3\sqrt{x} + 20x^2\sqrt{6} + 5\sqrt{x^3}}{96x^2 - x}[/tex]

[tex]\frac{\sqrt{6}(12x + 20x^2) + 3\sqrt{x} + 5\sqrt{x^3}}{x(96x - x)}[/tex]

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Answer:

should be 5.05

Step-by-step explanation:

rounded to nearest hundredth

Answer:

5.02

Step-by-step explanation:

Formula for area= π x r^2

(π is 3.14)

Formula for diameter= 2 x r

So all you basically have to do is go backwords with the first equation

20/π=6.36

Now you have 6.36, though you need to go even further back because of the ^2

√6.36=2.51

Now we have the radius, so stick that into the diameter formula

2 x 2.51

5.02 is the diameter :)

[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$6700\\ P=\textit{original amount deposited}\dotfill & \$3600\\ r=rate\to 4.42\%\to \frac{4.42}{100}\dotfill &0.0442\\ t=years \end{cases} \\\\\\ 6700=3600[1+(0.0442)(t)]\implies \cfrac{6700}{3600}=1+0.0442t\implies \cfrac{67}{36}=1+0.0442t \\\\\\ \cfrac{67}{36}-1=0.0442t\implies \cfrac{31}{36}=0.0442t\implies \cfrac{\frac{31}{36}}{0.0442}=t\implies 19.5\approx t[/tex]

Answer:

She is incorrect

Step-by-step explanation:

[tex]\begin{aligned}\dfrac{1}{3}(9x+48)-12x & =\dfrac{9}{3}x+\dfrac{48}{3}-12x\\ & = 3x+16-12x\\& = 16-9x\end{aligned}[/tex]

[tex]\begin{aligned}-4(2x+4) & =(-4)2x+(-4)4\\& = -8x-16\end{aligned}[/tex]

As  [tex]16-9x\neq -8x-16[/tex]  then she is incorrect.

She is incorrect

Answer:

Range at the start of the school year = 12 - 7 = 5

Range at the end of the school year = 12 - 8 = 4

Step-by-step explanation:

Hope this helps!

Answer:

12 - 7 = 5

12 - 8 = 4

If the equation 2(g - h) = b + 4 is solved for g. Then the value of g will be b/2 + h + 2.

A combination of equations solution is a collection of values x, y, z, etc. that enable all of the calculations to true at the same time.

The equation is given below.

2(g - h) = b + 4

Then solve the equation for the value of g. Then we have

2(g - h) = b + 4

   g - h = b/2 + 2

        g = h + b/2 + 2

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Answer:

esf

Step-by-step explanation:

Answer: b and d

Step-by-step explanation: right on edge

The correct answers are 1008 hours are 6 weeks and 5 weeks are 840 hours.

The ratio indicates how many times one number is to the other number.For example, if you have 4 chocolates and 2 cakes the ratio of the chocolates and the cake will be 2:1 which means that chocolate is 2 times then the cake.

It is given that 168 hours is equal to 1 week. we need to find 1008 hours has how many weeks and 5 weeks has how many hours.

1.) 1008 hours has how many weeks

168 hours = 1 week

1 hour  =  1 / 168 weeks

1008 hours  = 1008 / 168  =  6 weeks

So 1008 hours has 6 weeks

2.) 5 weeks has how many hours.

1 week = 168 hours

5 weeks = 5 x 168 hours

5 weeks = 840 hours

So 5 weeks will have 840 hours.

Therefore correct answers are 1008 hours are 6 weeks and 5 weeks are 840 hours.

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Answer:

hours    weeks

168          1

1008        6

840         5

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

They too are congruent because they both have equal measure.

well, we know that θ is in the III Quadrant, where the sine is negative and the cosine is negative as well, or if you wish, where "x" as well as "y" are both negative, now, the hypotenuse or radius of the circle is just a distance amount, so is never negative, so in the equation of cos(θ) = - (2/5), the negative must be the adjacent side, thus

[tex]cos(\theta)=\cfrac{\stackrel{adjacent}{-2}}{\underset{hypotenuse}{5}}\qquad \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{5^2 - (-2)^2}=b\implies \pm\sqrt{25-4}\implies \pm\sqrt{21}=b\implies \stackrel{III~Quadrant}{-\sqrt{21}=b}[/tex]

[tex]\dotfill\\\\ csc(\theta)\implies \cfrac{\stackrel{hypotenuse}{5}}{\underset{opposite}{-\sqrt{21}}}\implies \stackrel{\textit{rationalizing the denominator}}{-\cfrac{5}{\sqrt{21}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies -\cfrac{5\sqrt{21}}{21}} \\\\\\ tan(\theta)=\cfrac{\stackrel{opposite}{-\sqrt{21}}}{\underset{adjacent}{-2}}\implies tan(\theta)=\cfrac{\sqrt{21}}{2}[/tex]

Total marbles = 13

Number of yellow = 2

probability of getting yellow = 2/13

Answer:

hamster heaven

y=20+2.5x

hamster fun world

y=35+x

Step-by-step explanation:

by solving we get

x=10

y=45

by comparing the graph hamster fun world 8s cheaper on the long run

Mark Me Brainliest

Answer:

19/117

Step-by-step explanation:

Because the dice did land on 5, 19 times out of 117

Answer:

9.4 cm

Step-by-step explanation:

33.37x2=66.74÷7.1=9.4

Answer:

210

Step-by-step explanation:

V = B h

B = 8 1/3 * 4 1/5 = 35

V = 35*h

h= 6

35*6 = 210

Answer:

30 - 12x or 6(5 - 2x)

Step-by-step explanation:

Given expression:

First, let us simplify the expression inside the parentheses;

Then, let us open the parentheses by simplifying the distributive property;

Finally, let us simplify the expression by adding 10 to 20.

[Optional] Factor the expression by putting the expression in parentheses.

Since 6 is divisible to all the terms in the expression, we can divide 6 to all the terms in the expression and take "6" outside the parentheses.

Therefore, the simplified expression is 30 - 12x or 6(5 - 2x).

The expression equivalent to the given expression is [tex]\frac{4}{x-9}[/tex]

This are expressions written as a ratio of two expressions. Given the rational expression

[tex]f(x) = \frac{4(x-2)}{(x-2)(x-9)}[/tex]

Since (x-2) is common in both numerator and denominator, they wil cancel out to have the function below;

[tex]f(x) = \frac{4(x-2)}{(x-2)(x-9)}=\frac{4}{x-9}[/tex]

Hence the expression equivalent to the given expression is [tex]\frac{4}{x-9}[/tex]

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Step-by-step explanation:

Properties used

See the steps below