Which equation does not have infinitely many solutions?
o =
6x + 4 = 2(3x + 2)
+
2x + 5 - 5x + 2 + 3x = 7
-
3x + 13 + 4x – 5 = 7x + 8
-
0 4x - 8 = 2(2x + 3)
-

If the only marks that remain are at 1 inch and 2 inches, 9 inches and one mark, the missing mark corresponds to the number 6.

This is a classic problem in recreational mathematics, also known as the "burnt ruler problem". To solve it, we need to think creatively and use rational expressions and equations.

First, we note that the distance between the two marks is 9-2=7 inches. We can imagine the ruler as a number line from 0 to 9, where the two marks correspond to the numbers 1 and 2. We want to find the other mark, which corresponds to some number x between 2 and 9.

Next, we observe that we can use the ruler to construct line segments of length 1, 2, 3, 4, 5, 6, 7, 8, and 9 by adding or subtracting these lengths using the two marks as reference points. For example, we can construct a line segment of length 3 by starting at the mark at 2, moving 1 inch to the right, and then moving 2 more inches to the right.

Now, we notice that any line segment of length n can be expressed as a difference of two line segments of smaller lengths. For example, a line segment of length 7 can be expressed as the difference between a line segment of length 2 and a line segment of length 5. More generally, we can write:

n = a - b

where a and b are integers between 1 and n-1.

Using this observation, we can try to find a way to express the length of the missing segment x as a difference of two integers between 1 and 7. We can start by listing all possible values of a and b:

a=2, b=1: 2-1=1

a=3, b=1: 3-1=2

a=4, b=1: 4-1=3

a=5, b=1: 5-1=4

a=6, b=1: 6-1=5

a=7, b=1: 7-1=6

a=3, b=2: 3-2=1

a=4, b=2: 4-2=2

a=5, b=2: 5-2=3

a=6, b=2: 6-2=4

a=4, b=3: 4-3=1

a=5, b=3: 5-3=2

a=6, b=3: 6-3=3

a=5, b=4: 5-4=1

a=6, b=4: 6-4=2

a=6, b=5: 6-5=1

We notice that the only values of a and b that work are 6 and 1, respectively, since 6-1=5, which is the length of the line segment between the two marks that was not given.

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The range of the number of bottled waters that approximately 68. 2% of the students drink is between 131 and 175 bottled waters per day.

The range of the number of bottled waters that approximately 68.2% of the students drink can be calculated using the empirical rule, also known as the 68-95-99.7 rule.

According to this rule, for a normal distribution:

Approximately 68.2% of the data falls within one standard deviation of the mean

Approximately 95.4% of the data falls within two standard deviations of the mean

Approximately 99.7% of the data falls within three standard deviations of the mean

falls within a certain number of standard deviations from the mean

Since we are interested in the range of values that approximately 68.2% of the students drink, we can start by calculating one standard deviation from the mean:

One standard deviation = mean ± standard deviation

= 153 ± 22

= 131 to 175

This answer is based on the empirical rule, which is a useful tool for understanding the spread of data in a normal distribution. It tells us that for a normal distribution, a certain percentage of the data

Therefore, approximately 68.2% of the students drink between 131 and 175 bottled waters per day.

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Modise is correct, as the input of 5 is mapped to the outputs of 2 and 9, hence the relation does not represent a function.

A relation represents a function if each value of the input is mapped to only one value of the output, that is, one input cannot be mapped to multiple outputs.

For a point in the standard format (x,y), we have that:

For this problem, there are two arrows departing the input of 5, meaning that the input of 5 is mapped to the outputs of 2 and 9, hence the relation is not a function.

The diagram is given by the image presented at the end of the answer.

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There are now 260 cows on the farm.

Let's start through calculating the amount of milk produced with the aid of the original cows before any modifications were made.

If every of the unique cows was producing 12.8 liters of milk in keeping with day, and there had been "x" cows, then the entire amount of milk produced by means of the original cows could be:

12.8x liters per day

After the adjustments, the farmer has 60 more cows and all cows produce 15 liters of milk per day. So, the full amount of milk produced with the aid of all cows after the modifications would be:

15(x + 60) liters per day

we're told that the new milk production is 1340 liters more according to day than before the changes. So, we can set up an linear equation:

15(x + 60) = 12.8x + 1340

Simplifying the equation, we get:

15x + 900 = 12.8x + 1340

2.2x = 440

x = 200

therefore, there were at first 200 cows on the farm. After the changes, the full number of cows would be:

x + 60 = 200 + 60 = 260 cows

So, there are now 260 cows on the farm.

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We can use the formula for the area of a sector to find the area of sector $LMN$

The area of a sector with central angle $\theta$ in a circle with radius $r$ is given by:

$A = \frac{\theta}{360^\circ} \pi r^2$

In this case, we know that $m\angle LMN = 66^\circ$ and $LM = 19$ units, so the radius of circle M is half of the diagonal of the rectangle formed by $LM$ and $MN$. Using the Pythagorean theorem, we can find the length of $MN$:

$MN^2 = LM^2 + LN^2 = LM^2 + LM^2 = 2LM^2$

$MN = \sqrt{2} LM = \sqrt{2} \cdot 19$

So the radius of circle M is $r = \frac{1}{2}MN = \frac{1}{2}\sqrt{2} \cdot 19$

Now we can use the formula for the area of a sector to find the area of sector $LMN$:

$A = \frac{m\angle LMN}{360^\circ} \pi r^2 = \frac{66^\circ}{360^\circ} \pi \left(\frac{1}{2}\sqrt{2} \cdot 19\right)^2 \approx \boxed{90.89}$ square units (rounded to the nearest hundredth).

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Based on the first survey results, we can predict that around 47 people in the second survey of 60 people will prefer cat food A over cat food B.

Based on the results of the first survey, 188 out of 240 people preferred cat food A over cat food B. To predict the preference for cat food A in the second survey, we can calculate the proportion of people who preferred cat food A in the first survey and apply it to the sample size of the second survey.

First, find the proportion of people preferring cat food A in the first survey:

Proportion = (Number of people preferring cat food A) / (Total number of people surveyed)
Proportion = 188 / 240
Proportion ≈ 0.7833

Now, apply this proportion to the second survey's sample size of 60 people:

Predicted preference = Proportion × (Sample size of the second survey)
Predicted preference = 0.7833 × 60
Predicted preference ≈ 47

Therefore, based on the first survey results, we can predict that around 47 people in the second survey of 60 people will prefer cat food A over cat food B.

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The shooter was located approximately 36.15 feet off the ground.

We can use trigonometry to solve for the height of the shooter.

First, we need to find the horizontal distance from the shooter to the man on the park bench. We can use the angle of 26° and the distance of 92 feet to calculate this distance:

horizontal distance = 92 feet * cos(26°)

horizontal distance = 82.33 feet

Next, we can use the height of 3.7 feet and the horizontal distance of 82.33 feet to find the height of the shooter:

tan(26°) = height difference / horizontal distance

height difference = horizontal distance * tan(26°)

height difference = 82.33 feet * tan(26°)

height difference = 36.15 feet

Therefore, the shooter was located approximately 36.15 feet off the ground.

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(a) The function rule for Big Wave Waterpark, f(x) = 2.5x + 5. where f(x) is total cost and x is number of slides ridden.

b) The function rule for Coaster City is, f(x) = 5x + 7.50, where x is the number of roller coaster ridden and f(x) is total cost.

c) The function rule for Virtual Reality Lan is, f(x) = 3x + 10, where f(x) is total cost and x is the number reality rides ridden.

(a) Let f(x) = ax +b be the function which represents the total cost of Big Wave Park where x represents the number of taken ride.

We can see that f(2) = 10; f(4) = 15 and f(6) = 20.

Therefore, 2a + b = 10 and 4a + b = 15

So, 2(2a + b) - (4a + b) = 2*10 - 15

4a + 2b - 4a - b = 20 - 15

b = 5

Now, f(6) = 20

6a + b = 20

6a + 5 = 20 [putting the value of 'b']

6a = 20 - 5 = 15

a = 15/6 = 5/2 = 2.5

Hence, the function rule for Big Wave Waterpark is, f(x) = 2.5x + 5.

(b) The function rule for Coaster city is, f(x) = 5x + 7.50, where x is the number of roller coaster ridden.

(c) Let the total cost for Virtual Reality Lan is, f(x) = cx + d, where x is the number reality rides ridden.

From the given graph we can see that, f(10) = 40; f(20) = 70; f(30) = 100.

So, 10c + d= 40 ........... (i)

20c + d = 70 ............... (ii)

Solving (i) and (ii) we get,

2(10c + d) - (20c + d) = 2*40 - 70

20c + 2d - 20c - d = 80 - 70

d = 10

So putting the value d = 10 in f(30) = 100 we get,

30c + 10 = 100

30c = 100 - 10 = 90

c = 90/30 = 3

So the function rule is, f(x) = 3x + 10.

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To find the area of the floor needed for 6 squirrel monkeys, first calculate the additional area needed for 4 monkeys 4 x 9 = 36 square feet. Add this to the initial area of 36 square feet, to get a total area of 72 square feet. Thus, the floor area for all six monkeys should be 72 square feet.

Let's first find the area of the floor required for the additional 4 monkeys

4 additional monkeys * 9 sq ft per monkey = 36 sq ft

So, to accommodate all 6 monkeys, the total floor area required would be

36 sq ft (original area) + 36 sq ft (additional area) = 72 sq ft

Therefore, the area of the floor for all six monkeys must be 72 square feet.

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Answer:

Sure, I can help you with that! The volume of a cone with a radius of 2.5 and a height of 4 is (1/3)*pi*(2.5^2)*4. This equals approximately 26.18 cubic units.

The width of the first design is -2.5 feet and the width of the second design is 0.5 feet.

For the first design, where the length is 4x, the total area is:

2(4x)² + 7(4x) + 3 = 32x² + 28x + 3

To find the width, we can divide the total area by the length:

width = (32x² + 28x + 3) / 4x

width = 8x + 7 + 3/4x

For the second design, where the length is 2x + 1, the total area is:

2(2x + 1)² + 7(2x + 1) + 3 = 8x² + 23x + 5

width = (8x² + 23x + 5) / (2x + 1)

width = 4x + 2 + 1/(2x + 1)

For the first design:

width = 8(-1/2) + 7 + 3/4(-1/2) = -2.5 feet

For the second design:

width = 4(-1/2) + 2 + 1/(2(-1/2) + 1) = 0.5 feet

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Part A: The given definition states that an angle is two collinear rays with a common endpoint. Part B : A point is an example of an undefined term.In relation to angles, a point is crucial as it serves as the common endpoint of the two rays that form the angle.

Part A :  The given definition states that an angle is two collinear rays with a common endpoint. However, this definition is incorrect as it contradicts the correct definition of an angle. In the correct definition, an angle is formed by two non-collinear rays with a common endpoint.

An example that contradicts the given definition is when you have two rays, AB and BC, with B being the common endpoint. If they were collinear, they would lie along the same straight line, and thus, no angle would be formed between them. To make the definition accurate, you would need to change it to: "An angle is formed by two non-collinear rays with a common endpoint."

Part B: An undefined term in geometry is a term that cannot be defined using other known geometric terms, but its meaning is generally understood. One example of an undefined term is a point. A point is a basic element in geometry, and it has no size, shape, or dimensions. It is merely a location in space. For instance, when discussing angle ABC, point B is the common endpoint of rays AB and BC.

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The relative frequency for the event of spin a 2 is P = 0.16

Given data ,

Let the total number of times the event occurs = 50

Now , the number of times the spin of 2 occurs = 8 times

So , the relative frequency is given by

Relative Frequency = Subgroup frequency / Total frequency

P = 8 / 50

P = 0.16

Hence , the relative frequency is 0.16

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The complete question is attached below :

If the table shows the results for spinning the spinner 50 times. What is the relative frequency for the event "spin a 2"

Howler monkeys are heavier on average than spider monkeys (17.75 lbs vs. 11.25 lbs).

Calculate the mean:

Some of the weights divided by the number of monkeys

Calculate the MAD:

Find the absolute deviation (difference) of each weight from the mean

Calculate the average of these deviations

Mean Howler Monkey = (16+17+18+18+18+20+22+23)/8 = 142/8 = 17.75 lbs

Mean Spider Monkey = (8+10+10+11+11+12+14+14)/8 = 90/8 = 11.25 lbs

Now, we calculate the MAD for each type of monkey:

MAD Howler Monkey=  1.875 lbs

MAD Spider Monkey=  1.5625 lbs

we calculate the means-to-MAD ratio for both types of monkeys:

Howler Monkey: Mean/MAD = 17.75/1.875 = 9.466

Spider Monkey: Mean/MAD = 11.25/1.5625 = 7.2

Inference:

Howler monkeys are heavier on average than spider monkeys (17.75 lbs vs. 11.25 lbs).

The means-to-MAD ratio shows that howler monkeys have more consistent weights (9.466) compared to spider monkeys (7.2), as a higher ratio indicates less variability in weights.

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David's net worth: 86,329.95

To calculate David's new net worth, we need to add the increase in assets and subtract the decrease in liabilities from his current net worth.

New assets value = 62,784.24 + 2,784.89 = 65,569.13

New liabilities value = David's current net worth - his current assets value

New liabilities value = 45,765.78 - 62,784.24 = -17,018.46

Since his liabilities have decreased by 3,742.36, we need to subtract this value from the new liabilities value:

New liabilities value = -17,018.46 - 3,742.36 = -20,760.82

Now we can calculate his new net worth by subtracting his new liabilities value from his new assets value:

New net worth = 65,569.13 - (-20,760.82) = 86,329.95

Therefore, David's new net worth is 86,329.95.

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The percentage of the games that Natasha scores between 93 and 142 is given as follows:

96.9%.

The z-score of a measure X of a normally distributed variable that has mean represented by [tex]\mu[/tex] and standard deviation represented by [tex]\sigma[/tex] is obtained by the equation presented as follows:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The mean and the standard deviation are given as follows:

[tex]\mu = 115, \sigma = 11[/tex]

The proportion of games with scores between 93 and 142 is the p-value of Z when X = 142 subtracted by the p-value of Z when X = 93, hence:

Z = (142 - 115)/11

Z = 2.45

Z = 2.45 has a p-value of 0.992.

Z = (93 - 115)/11

Z = -2

Z = -2 has a p-value of 0.023.

0.992 - 0.023 = 0.969, hence the percentage is of 96.9%.

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If a researcher collected the number of letters in each of 200 first names, approximately 79.4% of first names have seven letters or less. Therefore, the correct answer is 79.4%.

To find the percentage of first names with seven letters or less, we will use the mean (5.82) and standard deviation (1.43) of the normally distributed data. We will calculate the z-score for a name with seven letters:

z = (7 - 5.82) / 1.43
z ≈ 0.83

Now, using a z-table or a calculator that can compute the cumulative distribution function (CDF) of a standard normal distribution, we find the probability associated with the z-score:

P(z ≤ 0.83) ≈ 79.4%

So, approximately 79.4% of first names have seven letters or less. The correct answer is 79.4%.

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A. The missing value for P(X = 1) is 0.20.

B.  The value of P(X ≤ 2) is 0.85.

C.  The value of P(X > 2) is 0.15.

D. The probability of "At least 2" is equivalent to P(X >= 2), which is 0.75.

In probability theory, a probability distribution is a function that assigns probabilities to each possible value of a random variable.

In this Problem, we have a probability distribution for the score on a quiz, with X being the random variable and the table providing the probability of each possible score. In this answer, we will use the given probability distribution to answer the questions posed.

A) Find the missing value for P(X = 1) in the probability distribution.

To find the missing value for P(X = 1), we need to use the fact that the sum of the probabilities for all possible values of X must be equal to 1. Therefore, we can set up an equation:

P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 1

Substituting in the given probabilities, we get:

0.05 + P(X = 1) + 0.60 + 0.15 = 1

Simplifying, we get:

P(X = 1) = 0.20

Therefore, the missing value for P(X = 1) is 0.20.

B) P(X ≤ 2) =

To find P(X ≤ 2), we need to add up the probabilities of X being less than or equal to 2. This is equivalent to:

P(X ≤ 2) = P(X = 0) + P(X = 1) + P(X = 2)

Substituting in the given probabilities, we get:

P(X ≤ 2) = 0.05 + 0.20 + 0.60 = 0.85

Therefore, P(X ≤ 2) is 0.85.

C) P(X > 2) =

To find P(X > 2), we need to add up the probabilities of X being greater than 2. This is equivalent to:

P(X > 2) = P(X = 3)

Substituting in the given probabilities, we get:

P(X > 2) = 0.15

Therefore, P(X > 2) is 0.15.

D) The probability of "At least 2" is equivalent to P(X >= 2)

To find the probability of "At least 2," we need to add up the probabilities of X being greater than or equal to 2. This is equivalent to:

P(X ≥ 2) = P(X = 2) + P(X = 3)

Substituting in the given probabilities, we get:

P(X ≥ 2) = 0.60 + 0.15 = 0.75

Therefore, the probability of "At least 2" is equivalent to P(X ≥ 2), which is 0.75.

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Answer: 141

Step-by-step explanation: 188 x 75% = 141

Answer:

141

Step-by-step explanation:

I looked it up.

The slant height of the given cone is 16.36 cm.

The length from the base to the peak along the "center" of a lateral face of an object (like a frustum or pyramid) is its slant height.

It is, in other words, the height of the triangle that a lateral face is a part of (Kern and Bland 1948, p.

So, calculate the slant height as follows:

614π = πr√h²+r²

614 = 16.2√h²+16.2²

614 = 262.44√h²

614/262.44 = h

2.33

Height = 2.33 cm

Then, slant height formula:

s=√(r² + h²)

s=√(16.2² + 2.33²)

s=√267.8689

s=16.36 cm

Therefore, the slant height of the given cone is 16.36 cm.

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Answer:

274.78

Step-by-step explanation:

Let's call the original price "x".

We know that the price decreased by 31%, so the new price is

100% - 31% = 69% of the original price:

0.69x = 189.6

To solve for x, we can divide both sides by 0.69:

x = 189.6 / 0.69

Simplifying this expression, we get:

x ≈ 274.78

Therefore, the original price was approximately $274.78.

We are not given the distance between the spheres, so we cannot calculate the force without that information.

To calculate the electrostatic force between the two charged spheres, we can use Coulomb's law, which states that the magnitude of the electrostatic force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Mathematically, we can express this as:

F = k * (q1 * q2) / r^2

Where F is the electrostatic force, k is Coulomb's constant (9 x 10^9 N m^2/C^2), q1 and q2 are the charges of the spheres, and r is the distance between their centers.

We are given the charges of the two spheres: sphere A has a charge of +1.0 x 10^-6 C, and sphere B has a charge of -1.6 x 10^-6 C.

However, we are not given the distance between the spheres, so we cannot calculate the force without that information.

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The total amount of carbon dioxide emitted over the 14-year period is 879,594.08 kilotons.

The small country emits 103,000 kilotons of carbon dioxide per year and agreed to cut its emissions by 5% per year for the next 14 years, starting with 103,000 kilotons in the first year.

To find the total amount of carbon dioxide emitted over the 14-year period, follow these steps:

1. Determine the initial amount of emissions: 103,000 kilotons in the first year.

2. Calculate the reduction rate per year: 5% or 0.05.

3. Calculate the total emissions for each year using the formula:

Emissions = Initial Emissions * (1 - Reduction Rate)^Year

4. Sum up the emissions for all 14 years.

Hence,

Year 1: 103,000 * (1 - 0.05)^0 = 103,000 kilotons
Year 2: 103,000 * (1 - 0.05)^1 = 97,850 kilotons
Year 3: 103,000 * (1 - 0.05)^2 = 93,057.50 kilotons
...
Year 14: 103,000 * (1 - 0.05)^13 = 56,516.87 kilotons

Now, add up the emissions for all 14 years:

Total Emissions = 103,000 + 97,850 + 93,057.50 + ... + 56,516.87 = 879,594.08 kilotons.

Therefore, the total amount of carbon dioxide emitted over the 14-year period is approximately 879,594.08 kilotons.

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Therefore, the distance from both Xavier and David's tents to the ranch is: 151 meters and 159.6 meters.

An equation is a mathematical statement that shows the equality of two expressions, often separated by an equal sign (=). The expressions on either side of the equal sign can contain variables, constants, and mathematical operations. Equations are used to solve problems, find unknown values, and represent relationships between quantities in various fields such as mathematics, physics, engineering, and economics.

Here,

The distance from Xavier's tent to the ranch is XR = (10.5z + 34) meters.

The distance from David's tent to the ranch is DR = (12.3z + 12.4) meters.

Since David and Xavier want to place their tents at equal distances from the ranch, we can set these two expressions equal to each other and solve for z:

(10.5z + 34) = (12.3z + 12.4)

Simplifying this equation, we get:

1.8z = 21.6

z = 12

Therefore, the distance from both Xavier and David's tents to the ranch is:

XR = (10.5z + 34)

= (10.5 x 12 + 34)

= 151 meters

DR = (12.3z + 12.4)

= (12.3 x 12 + 12.4)

= 159.6 meters

So both tents are 151 meters away from the ranch.

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The percent error is 4.76%.

To find the percent error, we first need to calculate the actual error, which is the absolute difference between the estimated points and the actual points:

Actual error = |252 - 240| = 12

Next, we need to calculate the percent error, which is the ratio of the actual error to the estimated value, expressed as a percentage:

Percent error = (actual error / estimated value) x 100%

Percent error = (12 / 252) x 100%

Percent error = 4.76%

Therefore, the percent error is 4.76%.

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The formula that models the ratio y is:

y = 6 / (6 + x)

Let y be the ratio of the number of gallons of acid in the container compared to the total volume of liquid in the container, and let x be the number of gallons of water added to the container.

Initially, the container has 6 gallons of acid and 0 gallons of water, for a total volume of 6 gallons. When x gallons of water is added, the total volume of liquid becomes 6 + x gallons, and the amount of acid remains at 6 gallons.

Therefore, the formula that models the ratio y is:

y = 6 / (6 + x)

This formula gives the ratio of the number of gallons of acid in the container compared to the total volume of liquid in the container when x gallons of water is added.

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(a) The critical numbers are x = 0 and x = 6.

(b) The function is increasing on the interval (0, 6) and decreasing on the intervals (-∞, 0) and (6, ∞).

(a) To find the critical numbers of f(x), we need to find the values of x where f'(x) = 0 or f'(x) does not exist.

f'(x) = 12x² - 72x

Setting f'(x) = 0, we get:

12x² - 72x = 0

12x(x - 6) = 0

So, the critical numbers are x = 0 and x = 6.

(b) To determine where the function is increasing or decreasing, we need to examine the sign of f'(x) on different intervals.

For x < 0, f'(x) = 12x² - 72x < 0, which means the function is decreasing on (-∞, 0).

For 0 < x < 6, f'(x) = 12x² - 72x > 0, which means the function is increasing on (0, 6).

For x > 6, f'(x) = 12x² - 72x < 0, which means the function is decreasing on (6, ∞).

So, the function is increasing on the interval (0, 6) and decreasing on the intervals (-∞, 0) and (6, ∞).

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The given expression x²y − 7xy + xyz is a 3rd degree polynomial.

To classify it by degree and term, let's first determine the degree of each term:

1. x²y: The degree is the sum of the exponents of the variables (x and y). Here, the degree is 2 (from x²) + 1 (from y) = 3.
2. 7xy: The degree is 1 (from x) + 1 (from y) = 2.
3. xyz: The degree is 1 (from x) + 1 (from y) + 1 (from z) = 3.

Now, we can classify the expression:

- Degree: Since the highest degree among the terms is 3, the expression is a 3rd-degree polynomial.
- Term: There are three terms in the expression, so it is a trinomial.

In summary, the given expression, x²y − 7xy + xyz, is a 3rd-degree trinomial.

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To find the derivative of y = cot(sen x/X + 14), we need to use the chain rule and the derivative of cot(x) which is -csc^2(x).

First, we let u = sen x/X + 14.
Then, we can rewrite y as y = cot(u).
Using the chain rule, the derivative of y with respect to x is:

dy/dx = dy/du * du/dx

To find dy/du, we need to use the derivative of cot(u) which is -csc^2(u).
So,

dy/du = -csc^2(u)

To find du/dx, we need to use the quotient rule.
Let v = X, so u = sen x/v + 14.
Then,

du/dx = (v*cos x - sen x * 0)/(v^2)
du/dx = cos x/v

Now we can substitute the values of dy/du and du/dx:

dy/dx = dy/du * du/dx
dy/dx = (-csc^2(u)) * (cos x/v)

But u = sen x/X + 14, so we substitute this in:

dy/dx = (-csc^2(sen x/X + 14)) * (cos x/X)

Therefore, the derivative of y = cot(sen x/X + 14) is

dy/dx = (-csc^2(sen x/X + 14)) * (cos x/X).
To find the derivative of y = cot(sen(x)/(x + 14)), we will use the quotient rule and the chain rule.

Let u = sen(x) and v = x + 14, then y = cot(u/v).

First, find the derivatives of u and v:
du/dx = cos(x) (since the derivative of sen(x) is cos(x))
dv/dx = 1 (since the derivative of x is 1, and the derivative of a constant is 0)

Now, apply the quotient rule for cotangent:
d(cot(u/v))/dx = -1/(sin^2(u/v)) * (du/dv - u*dv/dx) / (v^2)

Substitute the expressions for u, v, du/dx, and dv/dx:
dy/dx = -1/(sin^2(sen(x)/(x + 14))) * ((cos(x)*(x + 14) - sen(x)*1) / (x + 14)^2)

This is the derivative of y with respect to x.

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