Answer:
In conclusion, acetone was determined to be the unknown used in the simple distillation and acetone- water was separated successfully by fractional distillation. Introduction Distillation is the chief technique used to separate and purify liquids.
True or Fase. Every substance has to be classified as either acid or base?
Answer:
False
Explanation:
Some substances don't have to be
went to the creamery and got a malted milkshake. What type of carbohydrate did I eat?
HELP ME PLEASE ITS DUE TODAY
Answer:
Explanation:
S2Si
O2
C2H4
N2
CBr4
S2
I think these are correct
How many moles of Mg(OH)2(aq) would be required to neutralize 6.0 mol HCl(aq)?
Answer:
[tex]3.0molMg(OH)_2[/tex]
Explanation:
Hello there!
In this case, for these types of acid-base neutralizations, it is crucial to firstly set up the chemical reaction taking place between the acid and the base; in this case HCl and Mg(OH)2 respectively, whose products are obtained by switching around the anions and cations as shown below:
[tex]HCl(aq)+Mg(OH)_2(aq)\rightarrow MgCl_2(aq)+H_2O(l)[/tex]
Which must be balanced to accurately predict the mole ratio on the reactants side:
[tex]2HCl(aq)+Mg(OH)_2(aq)\rightarrow MgCl_2(aq)+2H_2O(l)[/tex]
Whereas we can see a 2:1 mole ratio of the acid to the base; thus, the moles of Mg(OH) required for the neutralization of 6.0 moles of HCl turn out to be:
[tex]6.0molHCl*\frac{1molMg(OH)_2}{2molHCl} \\\\=3.0molMg(OH)_2[/tex]
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If 175.6 joules of energy are applied to a sample of Aluminum and its temperature changed by 35.4 degrees then what was the weight of the Aluminum sample?
Answer:
5.51g
Explanation:
Using the following formula:
Q = m × c × ∆T
Where;
Q = amount of heat in Joules
m = mass/weight of Aluminum
c = specific heat of Aluminum (0.900 J/g°C)
∆T = change in temperature.
Based on the information given in this question, Q = 175.6 joules, ∆T = 35.4°C, c = 0.900 J/g°C.
Using, Q = m × c × ∆T
175.6 = m × 0.900 × 35.4
175.6 = 31.86m
m = 175.6/31.86
m = 5.51g
The weight of the aluminum sample is 5.51g.
Choose the appropriate electron configuration for an element that has electrons in six orbitals.
Group of answer choices
1s2 2s2 2p6 3s2 3p6
1s2 2s2 2p6 3s2 3p4
1s2 2s2 2p6 3s1
1s2 2s2 2p5
Answer:
pagtoon og imo dotsExplanation:
pagtoon og imo dots4. How many moles of NaOH(s) would be required to react with 1.90 g of Cu(NO3)2 (aq)
according to the balanced equation:
Cu(NO3)2(aq) + 2 NaOH(aq) → Cu(OH)2(s) + 2 NaNO3(aq)
Answer:
2.03 x 10⁻² mol NaOH
Explanation:
First step for these questions is to ensure the reaction is balanced, then use the periodic table to determine the molar mass for the reactant you are given. Use the ratio from the balanced equation and dimensional analysis to solve. See attached image
How many grams of magnesium
sulfate (MgSO4) are dissolved in
0.965 L of a 0.0575 M solution?
Molar Mass Mg: 24.30 g/mol
Molar Mass S: 32.06 g/mol
Molar Mass O: 16.00 g/mol
Answer:6.68
Explanation:
with a well labeled diagram explain the stages of meiosis and mitosis
Answer:
hope that helps
An alpha particle is an ionized helium nucleus, consisting of 2 protons and 2 neutrons bound together. When alpha particles are beamed toward a thin metal foil, most of them pass through, undergoing a small deflection, while a small fraction of them bounce back at much larger angles in excess of 90 degrees relative to their incoming direction. The reason this happens is that Group of answer choices
Answer:
Due presence of empty as well as heavy particles.
Explanation:
The main reason for this is the presence of empty spaces as well as heavy particles in the nucleus of Helium atom. Most of the beam pass through the helium atom due to the presence of empty spaces in the atom whereas some beams deflect from the helium atom because both repel each other due to same charge i.e. positive charge. Few beams of light bounce back with an angle of 90 degree due hitting with the nucleus where heavy particles such as neutron and proton are present.
Famous people who talked about plastic water bottles
A 17.11 gram sample of an organic compound containing only C, H, and O is analyzed by combustion analysis and 21.71 g CO2 and 5.926 g H2O are produced. In a separate experiment, the molar mass is found to be 104.1 g/mol. Determine the empirical formula and the molecular formula of the organic compound. Enter the elements in the order C, H, O empirical formula
Answer: The empirical formula and the molecular formula of the organic compound is [tex]CHO[/tex] and [tex]C_4H_4O_4[/tex] respectively.
Explanation:
The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:
[tex]C_xH_yO_z+O_2\rightarrow CO_2+H_2O[/tex]
where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.
We are given:
Mass of [tex]CO_2[/tex] = 21.71 g
Mass of [tex]H_2O[/tex]= 5.926 g
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44g of carbon dioxide, 12 g of carbon is contained.
So, in 21.71 g of carbon dioxide, =[tex]\frac{12}{44}\times 21.71=5.921g[/tex] of carbon will be contained.
For calculating the mass of hydrogen:
In 18g of water, 2 g of hydrogen is contained.
So, in 5.926 g of water, =[tex]\frac{2}{18}\times 5.926=0.658g[/tex] of hydrogen will be contained.
Mass of oxygen in the compound = (17.11) - (5.921+0.658) = 10.53 g
Mass of C = 5.921 g
Mass of H = 0.658 g
Mass of O = 10.53 g
Step 1 : convert given masses into moles.
Moles of C =[tex] \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.921g}{12g/mole}=0.493moles[/tex]
Moles of H=[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.658g}{1g/mole}=0.658moles[/tex]
Mass of O=[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{10.53g}{16g/mole}=0.658moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =[tex]\frac{0.493}{0.493}=1[/tex]
For H =[tex]\frac{0.658}{0.493}=1[/tex]
For O=[tex]\frac{0.658}{0.493}=1[/tex]
The ratio of C : H: O = 1: 1: 1
Hence the empirical formula is [tex]CHO[/tex].
empirical mass of CHO = 12(1) + 1(1) + 1 (16) = 29
Molecular mass = 104.1 g/mol
[tex]n=\frac{\text {Molecular mass}}{\text {Equivalent mass}}=\frac{104.1}{29}=4[/tex]
Thus molecular formula = [tex]n\times {\text {Empirical formula}}=4\times CHO=C_4H_4O_4[/tex]
How many moles of iron will be produced from 6.20 moles of carbon monoxide reacting with excess iron oxide
Explanation:
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Methane (CH4) undergoes combustion. Which products form? please help will give brainliest if correct
Answer:
B. CO₂ and H₂O.
Explanation:
When any organic substance undergoes complete combustion, it produces carbon dioxide (CO₂) and water (H₂O).
In the case of methane, the balanced reaction is:
CH₄ + 2O₂ → CO₂ + 2H₂OWith the above information in mind the correct answer is option B. CO₂ and H₂O.
When the combustion is incomplete, carbon monoxide (CO) is produced as well.
Answer:
B. CO₂ and H₂O!
The Moon shines white light on Earth. Is the Moon a good blackbody
radiator? Why?
O A. Yes, because the light from the Moon comes from the Sun, which
is a blackbody radiator
B. No, because white light is only one wavelength of light, not a range
of wavelengths
O C. No, because the Moon reflects most of the Sun's light rather than
absorbing it
O D. Yes, because each night the Moon warms up enough to emit
visible light at a range of wavelengths
Answer:
C.) No, because the Moon reflects most of the Sun's light rather than
absorbing it
Explanation:
:p
Which statement describes the appearance of a
temperature-vs.-time graph?
A horizontal line shows that the temperature
increases at a constant rate over time.
O. A vertical line shows that the temperature
decreases at a constant rate over time.
Horizontal lines where the temperature is
constant during phase changes connect
upward-sloping lines where the temperature
increases.
Horizontal lines where the temperature
increases are connected by upward-sloping
lines where the temperature is constant for
each phase.
Answer: C. Horizontal lines where the temperature is constant during phase changes connect upward-sloping lines where the temperature increase.
Explanation:
Answer:
C
Explanation:
Which contains more reducing sugars, apple or cheese?
Answer:
An apple.
Explanation:
Hope this helps.
When 3.915 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 12.74 grams of CO2 and 3.913 grams of H2O were produced. In a separate experiment, the molar mass of the compound was found to be 54.09 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon.
Answer: The empirical formula and the molecular formula of the hydrocarbon is [tex]C_2H_3[/tex] and [tex]C_4H_6[/tex] respectivley.
Explanation:
The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:
[tex]C_xH_y+O_2\rightarrow CO_2+H_2O[/tex]
where, 'x', 'y' are the subscripts of Carbon, hydrogen
We are given:
Mass of [tex]CO_2[/tex] = 12.74 g
Mass of [tex]H_2O[/tex]= 3.913 g
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44g of carbon dioxide, 12 g of carbon is contained.
So, in 12.74 g of carbon dioxide, =[tex]\frac{12}{44}\times 12.74=3.474g[/tex] of carbon will be contained.
For calculating the mass of hydrogen:
In 18g of water, 2 g of hydrogen is contained.
So, in 3.913 g of water, =[tex]\frac{2}{18}\times 3.913=0.435g[/tex] of hydrogen will be contained.
Mass of C = 3.474 g
Mass of H = 0.435 g
Step 1 : convert given masses into moles.
Moles of C =[tex] \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{3.474g}{12g/mole}=0.289moles[/tex]
Moles of H=[tex]\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.435g}{1g/mole}=0.435moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =[tex]\frac{0.289}{0.289}=1[/tex]
For H =[tex]\frac{0.435}{0.289}=1.5[/tex]
The ratio of C : H = 1: 1.5
The whole number ratio will be = 2: 3
Hence the empirical formula is [tex]C_2H_3[/tex].
The empirical weight of [tex]C_2H_3[/tex] = 2(12.01)+3(1.008)= 27.04 g.
The molecular weight = 54.09 g/mole
Now we have to calculate the molecular formula.
[tex]n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{54.09}{27.04}=2[/tex]
The molecular formula will be=[tex]2\times C_2H_3=C_4H_6[/tex]
Which of the following is not among the elements to include on your note cards?
I. a number to identify the card and link it to a bibliography card
II. the subject (if you know what it is)
III. publishing information about the work in question
IV. your notes
A. II
B. I
C. IV
D. III
Answer:
c
Explanation:
Answer:
The answer is C
Explanation:
The map shows the movement pattern for major ocean currents. What ideas do you have about what might make ocean
currents move?
Please help
Answer:
Currents are physical occurrences or factors that put motion into oceans, making them move back and forth.
Such factors include but may exceed the following:
WindVariation in water mass densities (this is caused by alterations in temperature and salinity levels)GravityEarthquakes or stormsWhen there is movement in ocean currents, heat, nutrients, water oxygen levels are also affected.
Cheers
As NH4Cl dissolves in water, and cools the solution,
a. delta H is negative, and delta S is negative
b. delta H is positive, and delta S is negative
c. delta H is negative, and delta S is positive
d. delta H is positive, and delta S is positive
Answer:
D. delta H is positive, and delta S is positive
Which of the following describes the role of water in supporting the chemical reactions that occur within various life forms?
It is a non-polar molecule with weak hydrogen boding.
It is critical in the process of cellular respiration.
It has a huge electronegativity difference between its atoms.
It allows sunlight to pass through it.
Answer:
It's critical in the process of cellular respiration
It is critical in the process of cellular respiration; is the correct answer; as water plays a very important role in transportation of oxygen and maintaining cell structure.
What is cellular Respiration ?The process by which organisms combine food molecules with oxygen to form energy , which is used for life sustaining activities is called Cellular Respiration.
Carbon Di-Oxide and Water are produced as by products.
Water acts as a solvent in facilitating the transport of oxygen in respiration.
At the molecular level, water permits everything inside the cell to have the proper structure which is very important for biological processes.
Hence option B , i.e. It is critical in the process of cellular respiration; is the correct answer.
To know more about Cellular Respiration
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Why is it important for scientists to monitor meteors in the sky?
Answer:
Because You never know when a meteor will hit you.
In solution, strong acids and bases ionize completely, but weak acids and bases ionize only partially.
Answer:
A weak acid is one that does not dissociate completely in solution; this means that a weak acid does not donate all of its hydrogen ions (H+) in a solution. ... Therefore, the concentration of H+ ions in a weak acid solution is always less than the concentration of the undissociated species, HA.
Explanation:
Hope it helps
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What is the Electron Center Geometry of a CH3 carbon.
Answer:
tetrahedral geometry
CHCH2O- CH2CH3Explanation:
There are several centers of interest. Each carbon with all single bonds is the center of a tetrahedral geometry.
Based on the picture of the map, why does Buenos Aries have a higher ocean surface temperature than Cape Town even though they have the same latitude?
Acetic acid has the molecular formula CH3COOH. How many atoms of oxygen are there in 60 grams of acetic acid?
Answer:
1.2046x10²⁴ atoms
Explanation:
First we convert 60 grams of acetic acid into moles of acetic acid, using its molar mass:
60 g ÷ 60 g/mol = 1 molThen we double the number of acetic acid moles, as there are two oxygen moles per acetic acid mole.
1 mol CH₃COOH * 2 = 2 mol OFinally we convert moles into number of atoms, using Avogadro's number:
2 mol O * 6.023x10²³ atoms/mol = 1.2046x10²⁴ atomswhat is the method of seperating inmisible liquid
What is the kinetic energy of a bicycle with a mass of 11 kg traveling 8 m/s?
What is the kinetic energy of a bicycle with a mass of 11 kg traveling 8 m/s ?
Answer:-Mass (m) of a bicycle is = 11 kg
Speed (v) of a bicycle is = 8 m/s
Kinetic energy (K.E) of a bicycle is = ?
Since, we know,
[tex] { \boxed{\rm \red {K.E \: = \frac{1}{2} mv²}}} [/tex][tex] \bf K.E \: = \frac{1}{2} \: × \: 11 \: kg \: × \: (8 \: m/s)² [/tex]
[tex] \bf K.E \: = \frac{1}{2} \: × \: 11 \: kg \: × \: 64 \: m²/s²[/tex]
[tex] \bf K.E \: = \frac{704}{2} \: kg \: m²/s² [/tex]
[tex] \bf K.E \: = \: 352 \: kg \: m²/s² [/tex]
The kinetic energy (K.E) of a bicycle is 352 kg m²/s². [Answer]hellooooooooooooooooooooo
Answer:
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