What is the shape of the cross-section formed when a cone intersects a
plane as shown in the drawing?
A. square
B. oval
c. triangl
d.circle

Answer:

The second one where line go through more points

Step-by-step explanation:

Answer:

With what?

Step-by-step explanation:

Answer: 55,000,000

this might not be right but hear

Answer:

25%

Step-by-step explanation:

16 x 100 ÷ 64.

you simply take the minutes that he exercised and thereafter divide it by the recommended exercise that was prescribed by his coach.

Answer:

150

Step-by-step explanation:

Area of A:

A = bh

A = 10(10)

A = 100

Area of B:

A = 1/2bh

A = 1/2(10)(10)

A = 5(10)

A = 50

Combined:

100 + 50

150

Answer:

150

Step-by-step explanation:

My math genius friend told meh the answer bc I'm not smart at math.

Answer:

Probability Distributions

A listing of all the values the random variable can assume with their corresponding probabilities make a probability distribution.

A note about random variables. A random variable does not mean that the values can be anything (a random number). Random variables have a well defined set of outcomes and well defined probabilities for the occurrence of each outcome. The random refers to the fact that the outcomes happen by chance -- that is, you don't know which outcome will occur next.

Answer:

B

Step-by-step explanation:

Answer:

B. 45

Step-by-step explanation:

we know the sum of both angles is 90 because of the small sqaure in the corner.

90 = 2x+20

70 = 2x

45 = x

Answer:

35

Step-by-step explanation:

Because of the box in the graph, you can tell that this is a 90-degree angle

2x means the next angle will be twice of the answer choice number

because the end product must be 70 the answer must be 35

35 x 2 = 70

Answer:

3

December. total change in December is greater than change in January. 3 is greater than 2

August. the total change in hair growth is 4.

Step-by-step explanation:

total change in hair length = 2 - 1 + 3 - 4 + 3 = 3

My hair is longer in January .

total change in hair length in February = 2 -1 =  1

total change in hair length in August  = 1 + 3 = 4

total change in hair length in September = 4  - 4 = 0

total change in hair length in December = 0 + 3 = 3

My hair is the longest in August because that is the month that has the highest change in hair length

Answer:

180 mm³

Step-by-step explanation:

The polyhedron is an oblique rectangular prism

Area of the oblique rectangular prism = base area * height

height = z = 4 mm

Base area = L*W

L = y = 9 mm

W = x = 5 mm

Base area = 9*5 = 45 mm²

Area of the oblique rectangular prism = 45*4 = 180 mm³

Answer:

A) Replace L with the length of the skid mark:

Speed = √(20(208))

Speed= √(4160)

Speed = 64.5 miles per hour

B) set the equation to the speed and solve for L:

47 = sqrt(20L)

Square both sides:

2209 = 20L

Divide both sides by 20:

L = 110.5 feet

Answer:

Ewan di ko alam e sorry I didn't understand e

Answer:

3 + 8 times 3 +27 times 3 + 64 times 3+ 125 times 3  + 216 times 3+ 343 times 3

2352 cubic units^3

Step-by-step explanation:

Answer:

answer is -6

Step-by-step explanation:

hope it helped!!!

Answer:

Angles 1 & 2 = supplementary

Angles 1 & 3 = supplementary

Angles 1 & 4 = congruent

Angles 1 & 5 = congruent

Angles 1 & 6 = supplementary

Angles 1 & 7 = supplementary

Angles 1 & 8 = congruent

Answer:

the probability of winning & not winning the contest is 2 ÷ 9 and 7 ÷ 9 respectively

Step-by-step explanation:

The computation is shown below

a. The probability of Frank win the contest is

= 2 ÷ 2 + 7

= 2 ÷ 9

b. The probability of Frank that not win the contest is  

= 1  - 2 ÷ 9

= 7 ÷ 9

hence, the probability of winning & not winning the contest is 2 ÷ 9 and 7 ÷ 9 respectively

The same would be relevant

Answer:

3yds by 3yds

Step-by-step explanation:

3×3=9

9514 1404 393

Answer:

Step-by-step explanation:

The inverse variation described can be either of ...

  c = k/d

or

  d = k/c

Either way, the equation can also be written as ...

  cd = k

For the given values of c and d, the value of k is ...

  (5)(5/3) = k = 25/3

So, the model can be written as ...

  cd = 25/3

or

  d = (25/3)/c

__

For c=10, the value of d is ...

  d = (25/3)/10 = 25/30

  d = 5/6

(a) Extend the definition of f(x) to make it an even function f*(x),

[tex]f^*(x)=\begin{cases}0&\text{if }-2\le x<-1\\1&\text{if }0\le x\le1\\0&\text{if }1<x\le2\end{cases}[/tex]

and we take f* to be periodic over an interval of length P = 4. We compute the coefficients of the cosine series:

[tex]a_n = \displaystyle\frac2P \int_{-2}^2 f^*(x)\cos\left(\frac{2n\pi}Px\right)\,\mathrm dx = \frac{2\sin\left(\frac{n\pi}2\right)}{n\pi}[/tex]

Note that a₀ = 1 (you can compute the integral again without the cosine, or just take the limit as n -> 0). For all other even integers n, the numerator vanishes, so we split off the odd case for n = 2k - 1 :

[tex]a_{2k-1} = \dfrac{2\sin\left(\frac{(2k-1)\pi}2\right)}{(2k-1)\pi}[/tex]

Then the cosine series of f(x) is

[tex]\displaystyle \frac{a_0}2 + \sum_{k=1}^\infty a_{2k-1}\cos\left(\frac{(2k-1)\pi}2x\right)[/tex]

(b) For the sine series, you instead extend f(x) to an odd function f*(x),

[tex]f^*(x)=\begin{cases}-1&\text{if }-2\le x\le-1\\x&\text{if }-1<x<1\\1&\text{if }1\le x\le2\end{cases}[/tex]

Again, P = 4, and the coefficient of the sine series are given by

[tex]b_n = \displaystyle\frac2P\int_{-2}^2f^*(x)\sin\left(\frac{2n\pi}Px\right)\,\mathrm dx[/tex]

which we can again split into the even/odd cases,

[tex]b_{2k} = -\dfrac1{k\pi}[/tex]

[tex]b_{2k-1} = \dfrac{4(-1)^{k+1}+2(2k-1)\pi}{(2k-1)^2\pi^2}[/tex]

So the sine series is

[tex]\displaystyle \sum_{k=1}^\infty\left(b_{2k}\sin\left(k\pi x\right) + b_{2k-1}\sin\left(\frac{(2k-1)\pi}2x\right)\right)[/tex]

I've attached plots of the extended versions of f(x) along with the corresponding series up to degree 4.

It goes in the order 3,1,2,4

Answer:

After 3 min

Step-by-step explanation:

So becuase Tim is walking and Tim gave Alex a 50 meter head start so after 3 min they will tie each other.

Answer:

An acute angle is an angle that measures less than 90 degrees. A triangle formed by all angles measuring less than 90˚ is also known as an acute triangle. For example, in an equilateral triangle, all three angles measure 60˚, making it an acute triangle.

hope this answer helps you.....

Answer: There is no choice available for the answer.

Step-by-step explanation:

The question is asking for the value of m in terms of n, so we need to isolate m to one side.

Given

mn=12

Divide n on both sides

mn/n=12/n

m=12/n

Hope this helps!! :)

Please let me know if you have any questions

Answer:

d. 12√37 / 37

Step-by-step explanation:

standard formula for the distance between a point (x₀,y₀) and a line ax+by+c=0 is |a*x₀ + b*y₀ + c| / √a²+b²

(x₀,y₀) : (-2 , 3)

ax+by+c=0 : 6x - y +3 = 0

x₀ = -2      y₀ = 3     a = 6       b = -1        c = 3

d = | 6*(-2) + (-1)*3 + 3 | / √6²+(-1)²

d = 12 / √37 = 12√37 / 37

Answer:

A. has a right angle

thats one

Answer:

I think it is A and D. Not 100% sure tho.

Answer:

434

Step-by-step explanation:

hello :

note :    the n th term of an arithmetic sequence is :

An =A1+(n-1)d   ....a common difference is : d  and A1 the first term

in this exercice :   d = 33-29 =29-25= 4        A1 =  25

when : n =97 you have the  97rd term  A97

so : A97 =25 +(97-1)(4)

A97 = 434

Answer:

11) c = 16.1

12) c = 11.4

Step-by-step explanation:

11)

a² + b² = c²

8² + 14² = c²

64 + 196 = c²

c² = 260

[tex]\sqrt{c^2} =\sqrt{260}[/tex]

c = 16.1

12)

a² + b² = c²

7² + 9² = c²

49 + 81 = c²

c² = 130

[tex]\sqrt{c^2} =\sqrt{130}[/tex]

c = 11.4

• Question 1 :-

We see that in a right angled triangle two sides are 8cm and 14cm . We can find the third side using Pythagoras Theorem .

[tex]\tt \to Hypotenuse^2 = Perpendicular^2+Base^2\\\\\tt \to h^2 = (8)^2+(14) \\\\\to \tt h^2 = 64 + 196 \\\\\tt \to h^2 = 260 \\\\\tt \to h=\sqrt{260} \\\\\tt \to \boxed{\orange{\tt h = 16.12 }}[/tex]

____________________________

• Question 2 :-

[tex]\tt \to Hypotenuse^2 = Perpendicular^2+Base^2\\\\\tt \to h^2 = (9)^2+(7)^2 \\\\\to\tt h^2 = 81 + 49 \\\\\tt \to h^2 = 130 \\\\\tt \to h=\sqrt{130} \\\\\tt \to \boxed{\orange{\tt h = 11.40}}[/tex]

Answer:

graph the curve that models the expression is the first on, I don’t know the rest

Step-by-step explanation: