Answer:
0.12 M
Explanation:
To find the new concentration, you need to (1) find the moles of Solution A (via the molarity equation), then (2) find the moles of Solution B, then (3) combine all of the moles and volumes, and then (4) calculate the new molarity. The final answer should have 2 sig figs to reflect the lowest amount of sig figs in the given values.
Solution A:
7.7 mL / 1,000 = 0.0077 L
Molarity = moles / volume
0.10 M = moles / 0.0077 L
0.00077 = moles
Solution B:
18.3 mL / 1,000 = 0.0183 L
Molarity = moles / volume
0.20 M = moles / 0.0183 L
0.00366 = moles
New Solution:
11.7 mL / 1,000 = 0.0117 L
New Volume = 0.0077 L + 0.0183 L + 0.0117 L
New Volume = 0.0377 L
New Moles = 0.00077 moles + 0.00366 moles
New Moles = 0.00443 moles
Molarity = moles / volume
Molarity = 0.0043 moles / 0.0377 L
Molarity = 0.1175 M = 0.12 M
What mass in grams of iron metal can be formed by the reaction of 2.14 gAI metal with excess Fe₂O₃, according to the thermite reaction: 2Al(s) + Fe₂O₃ → 2Fe(s) + Al₂O₃(s)
Answer:
4.43 g Fe
Explanation:
To find the mass of iron, you need to (1) convert grams Al to moles Al (via molar mass), then (2) convert moles Al to moles Fe (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Fe to grams Fe (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs because the given value (2.14) has 3 sig figs.
Molar Mass (Al): 26.982 g/mol
2 Al(s) + Fe₂O₃ ---> 2 Fe(s) + Al₂O₃(s)
Molar Mass (Fe): 55.845 g/mol
2.14 g Al 1 mole 2 moles Fe 55.845 g
---------------- x ----------------- x -------------------- x ------------------ = 4.43 g Fe
26.982 g 2 moles Al 1 mole
Aluminum reacts with ferric oxide to produce iron by the thermite reaction. The mass of the iron metal that will be formed by the chemical reaction is 4.43 g Fe.
What is a limiting reagent?Limiting reagent has been described as reactions that are present in lesser amounts than the other reactant in the reaction that determines the amount of formation of the products and are never left in a reaction.
The balanced thermite reaction is given as:
2 Al(s) + Fe₂O₃ → 2 Fe(s) + Al₂O₃(s)
Molar mass of aluminium = 26.982 g/mol
Molar Mass of iron= 55.845 g/mol
Mass of aluminium (Al) = 2.14 grams
Here, according to the reaction 2 moles of Aluminum are needed to produce 2 moles of iron (Fe).
Moles of aluminum is calculated as:
Moles = mass ÷ molar mass
n = 2.14 ÷ 26.982
= 0.079 mol
As aluminum is the limiting reagent, it determines the formation of iron as:
2 mol Al = 2 mol Fe
0.079 mol Al = 0.079 mol Fe
Mass of iron is calculated as:
Mass = moles × molar mass
mass = 0.079 × 55.845 g/mol
= 4.411 grams
Therefore, 4.43 g Fe will be produced from 2.14 gm Al.
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among these properties of acids basses or both which property is specific to acids only? A. accepts protons B. bitter taste C. electricity conductive D. slippery feel
Answer:
C. electricity conductive
a specialist that study substance obtained by attained mining is called a what
Answer:
Explanation:
Mining:
Mining is when certain substances are removed from the Earth, usually in large quantities. Mining can occur below the surface of the Earth via tunnels and caves. It can also occur at surface level through methods such as strip mining, which removes huge amounts of soil in the process
why is it important to record all accidents and breakages that occur in the laboratory
It is important to record all accidents and breakages that occur in the laboratory to prevent them from happening again.
What is laboratory accident?Laboratory accident is defined as the type of accident that occurs in the laboratory leading to harm.
Example of laboratory accidents include the following:
chemical burns, cuts from broken glass, inhalation of toxic fumes, absorption of chemicals through the skin, and ingestion of toxic chemicals.A record of these type of laboratory accidents would hel prevent it's reoccurrence.
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Which of the following is a covalent compound?
NF3
KBr
CuO
FeCI3
Pb + 02 - Pb304 help
Answer:
6PbO +O2 --> 2Pb3O4
Explanation:
The question is incomplete I assume it is
PbO + 02 - Pb304
Determine the mass of SO₂ that contains 6.075 × 10^26 S atoms.
Answer:
= 64584.7176 g
or
= 64.5847 kg
Explanation:
From our question, we have been asked to find the mass of SO₂ containing 6.075 × 10^26 S atoms.
We know that from Avogadro's constant,
1 mole of a substance contains 6.02 x 10²³ ions/atoms/units
Thus,
1 mole => 6.02 x 10²³ atoms
x moles=> 6.075 × 10²⁶ atoms
We cross multiply;
x moles = (6.075 × 10²⁶ x 1)/(6.02 x 10²³)
= 1009.1362 moles
1 mole of SO2 = 64 g
1009.1362 moles = ?
=>
[tex] \frac{1009.1362 \times 64}{1} [/tex]
= 64584.7176 g
= 64.5847 kg
2. A solution is made by dissolving 3.88 g of NaCl in enough water to make 67.8 mL of solution. What is the concentration of sodium chloride in units of weight/volume percent?
The concentration of sodium chloride in the solution is 5.72% (weight/volume percent).
How to calculate the weight/volume percent concentration?Weight/volume percent concentration (w/v) expresses the amount of solute (in grams) dissolved in a given volume of solution (in milliliters). Specifically, it is defined as the weight of the solute divided by the volume of the solution, multiplied by 100.
To calculate the weight/volume percent concentration, we need to determine the mass of NaCl per volume of the solution.
First, we need to convert the volume of the solution from milliliters (mL) to liters (L):
67.8 mL = 0.0678 L
Next, we calculate the concentration of NaCl in grams per liter (g/L):
Concentration = Mass of solute ÷ Volume of solution
Concentration = 3.88 g ÷ 0.0678 L
Concentration = 57.2 g/L
Finally, we convert the concentration to weight/volume percent by multiplying by 100:
Weight/volume percent = Concentration x 100
Weight/volume percent = 57.2 g/L x 100
Weight/volume percent = 5.72%
Therefore, the concentration of NaCl in the solution is 5.72% (weight/volume percent).
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Please help me make analysis scheme flow chart for the detection of cation present in my unknown salt mixture of Ag+, Pb2+, or Ca2+ cations based on their solubility in the given reagents.
I can only use these reagents: Na2CO3, NaCl, & Na2SO4
The suspected cations in the unknown cation mixture are: Ag+, Pb2+, or Ca2+.
I used 0.5 M solution of all these reagents.
My test results are:
Na2CO3: 20 drops of sodium carbonate were used and silver blue precipitate was produced.
NaCl: 20 drops of sodium chloride were used and no precipitate was formed.
Na2SO4: 20 drops of sodium sulfate were used yellow precipitate was produced.
Please please help me make analysis flow chart based on this information and also tell me in what sequence these reagents will be added to unknown salt mixture.
I suspect that the cation may be Ca2+ based on solubility rules. But I'm not sure.
The possible action your solution might contain is amongst [tex]Ag^+[/tex], [tex]Pb^{2+}[/tex], or [tex]Ca^{2+}[/tex].
What are the solutions?A solution is a homogeneous mixture of one or more solutes dissolved in a solvent.
NaCl: 20 drops of NaCl were used and no precipitate was formed.
No precipitation formed means the [tex]Cl^-[/tex] cation is soluble in water. From your chart, you might see the halide of [tex]Ag^+[/tex] and [tex]Pb^{2+}[/tex] is insoluble in water, which means they should have formed precipitation but you didn't. This means there's less possibility it contains [tex]Ag^+[/tex] or [tex]Pb^{2+}[/tex], so we are left with only [tex]Ca^{2+}[/tex]. Let's confirm it with the rest.
[tex]Na_2SO_4[/tex] : 20 drops of [tex]Na_2SO_4[/tex] were used yellow precipitate was produced.
Even though all other sulfates form precipitation ( Insoluble in water)
[tex]Na_2CO_3[/tex] : 20 drops of sodium carbonate were used and the silver-blue precipitate was produced.
It seems all of their Carbonate is insoluble in nature. ( which is our case too ).
From the above result, only the reaction with NaCl was deemed to be decisive and it indeed contains [tex]Ca^{2+}[/tex] ions. Means you are correct.
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How many grams of KCl 03 are needed to produce 6.75 Liters of O2 gas measured at 1.3 atm pressure and 298 K?
11.48-gram of [tex]KCl0_3[/tex] are needed to produce 6.75 Liters of [tex]O_2[/tex] gas measured at 1.3 atm pressure and 298 K
What is an ideal gas equation?The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
First, calculate the moles of the gas using the gas law,
PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.
Given data:
P= 1.3 atm
V= 6.75 Liters
n=?
R= [tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]
T=298 K
Putting value in the given equation:
[tex]\frac{PV}{RT}=n[/tex]
[tex]n= \frac{1.3 \;atm\; X \;6.75 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}[/tex]
Moles = 0.3588 moles
Now,
[tex]Moles = \frac{mass}{molar \;mass}[/tex]
[tex]0.3588 moles = \frac{mass}{32}[/tex]
Mass= 11.48 gram
Hence, 11.48-gram of [tex]KCl0_3[/tex] are needed to produce 6.75 Liters of [tex]O_2[/tex] gas measured at 1.3 atm pressure and 298 K
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Assume that a normal curve is a good model for this data set. If 10,000 more observations were collected, what percentage of the observations would be greater than 98.02? In other words, what percentage of the area under the normal distribution curve would lie above 98.02 on the x-axis?
A) 5.9%
B) 2.96%
C) 2.5%
D) 0.0%
The percentage of the area under the normal distribution curve would lie above 98.02 on the x-axis is 2.5 % , option C is the answer.
What is Normal Distribution ?Normal Distribution is a probability distribution which is symmetric about the mean , The frequency is more near the mean and less far from the mean.
It is given in the data that
10,000 more observations were collected
the percentage of the observations would be greater than 98.02 = ?
According to the 68-95-99.7 rule,
It states that approximately
68% of the observations lie within σ of µ
95% of the observations lie within 2σ of µ.
99.7% of the observations lie within 3σ of µ.
The percentage of the observation between various intervals is attached in the image in the answer.
2.1 percent of the population is distributed in the intervals between two and three standard deviations , which is the zone above 2SD and below 3SD.
As 2.1 % is approximate , Therefore from the given option , 2.5%
The percentage of the area under the normal distribution curve would lie above 98.02 on the x-axis is 2.5 % , option C is the answer.
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A metal object with mass of 22.7 g is heated to 97.0 ∘C and then transferred to an insulated container containing 84.7 g of water at 20.5 ∘C. The water temperature rises and the temperature of the metal object falls until they both reach the same final temperature of 24.3 ∘C. What is the specific heat of this metal object? Assume that all the heat lost by the metal object is absorbed by the water.
The specific heat of the metal object with a mass of 22.7g heated to to temperature of 97.0°C and then transferred to an insulated container containing 84.7 g of water at 20.5 ∘C is 0.815J/g°C
How to calculate specific heat?
The specific heat capacity of a metal can be calculated using the calorimetry equation as follows:
Q = mc∆T
Where;
Q = quantity of heat absorbed
m = mass of substance
c = specific heat capacity
∆T = change in temperature
mc∆T (water) = -mc∆T (metal)
84.7 × 4.18 × 3.8 = - (22.7 × c × -72.7)
1345.375 = 1650.29c
c = 0.815J/g°C
Therefore, the specific heat of the metal object with a mass of 22.7g heated to to temperature of 97.0°C and then transferred to an insulated container containing 84.7 g of water at 20.5 ∘C is 0.815J/g°C.
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A sample of zinc is heated to a temperature of 77.4ºC, then placed in a calorimeter containing 65.0 g of water. Temperature of water increases from 20.00ºC. The specific heat of zinc is 0.390 j/g°C. What was the mass of the zinc sample?
180.189 g was the mass of the zinc sample with a specific heat of zinc is 0.390 j/g°C.
What is specific heat capacity?The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).
Using specific heat capacity formula here:
[tex]C_{Zn}[/tex] × [tex]m_{Zn}[/tex]× Δ[tex]T_{Zn}[/tex] = [tex]C_{H_2O}[/tex]× [tex]m_{H_2O}[/tex] × Δ[tex]T_{H_2O}[/tex]
0.390J/g°C × [tex]m_{Zn}[/tex] ×77.4ºC = 4.184J/g°C× 65.0g × 20.00ºC.
[tex]m_{Zn}[/tex] = 180.189 g
Hence, 180.189 g was the mass of the zinc sample.
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Is CaO a molecular compound?
Answer:
It's a Ionic compound
Explanation:
To tell if CaO (Calcium oxide) is ionic or covalent (also called molecular) we look at the Periodic Table that and see that Ca is a metal and O is a non-metal. When we have a metal and a non-metal the compound is usually considered ionic.
Because we have a metal and non-metal in CaO there will be a difference in electronegativity between the metal and non-metal. This difference results in an electron(s) being transferred from the metal (lower electronegativity) to the non-metal (higher electronegativity). The results in the metal becoming a postitive ion and the non-metal a negative ion. The two opposite charges are attracted and form the ionic bond between atoms in Calcium oxide.
If the earth were the size of an apple, which piece would best represent the amount of mass of the
atmosphere?
O the skin
O the meat
O the stem
O Oops..... I am sorry. I just ate the Pacific Ocean by mistake.
O a seed
If aluminum has a density of 2.7 g/cm³, what is the volume of 2.7 grams of aluminum?
Answer:
Solution Density of aluminium = 2.7 g/Cm 3 In kg/ m 3 = 27 × 1000 10 =2700 kg/ m 3
Explanation:
Not much of one
5. A group decided to use 250.0 mL of vinegar and 24.0 grams of baking soda. What is the limiting
reactant?
Hence, If the concentration of Acetic acid in vinegar is more than 7%, the limiting reactant is baking soda. If the concentration of Acetic acid in vinegar is less than 7%, the limiting reactant is vinegar.
What is a limiting reactant?The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.
To solve this problem, it is necessary to know the exact concentration of acetic acid in vinegar, because manufacturers produce many types of vinegar the with different concentrations. Most often, concentration of acetic acid in vinegar ranges from 4% to 8%. In this case, it is possible
to calculate the concentration of vinegar making the assumption that 250 ml of vinegar reacts completely with 24 grams of baking soda.
Acetic acid [tex]CH_3CO_2H[/tex] reacts with baking soda [tex]NaHCO_3[/tex] according to the equation:
[tex]CH_3CO_2H + NaHCO_3[/tex] → [tex]CH_3CO_2Na + CO_2 + H_2O[/tex]
1. Molar mass of [tex]NaHCO_3[/tex] is 23+1+12+16×3 = 84 g/mol
= [tex]\frac{1 mol \;NaHCO_3}{84 g \;NaHCO_3}[/tex]
= [tex]\frac{24 g \;NaHCO_3 X 1 mol \;NaHCO_3}{84 g \;NaHCO_3}[/tex]
=0.29 mol [tex]NaHCO_3[/tex]
2. From the balanced equation we see that 1 mole of [tex]NaHCO_3[/tex] reacts with 1 mole of [tex]CH_3CO_2H[/tex] , then 0.29 moles of [tex]NaHCO_3[/tex] react with 0.29 moles of [tex]CH_3CO_2H[/tex].
3. Mass of 1 mole of [tex]CH_3CO_2H[/tex] is 12+ 1×3+12+16×2=60 g/mol
= [tex]\frac{0.29 mol \;CH_3CO_2H X \;60 g \;CH_3CO_2H }{1 mol \;CH_3CO_2H}[/tex]
[tex]=17.4 g CH_3CO_2H[/tex]
4. In this step density of vinegar is needed.
Making the assumption that concentration of acetic acid is 7%, we can calculate the mass of acetic acid in 250 ml of vinegar:
Mass of vinegar=Volume × density
= 250 ml ×1.0084 g/ml
=252 g
Mass of acetic acid = mass of vinegar × concentration ÷ 100%
= 252 g × 7% ÷ 100%
= 17.6 g.
17.6 g [tex]CH_3CO_2H[/tex] is very close to 17.4 g [tex]CH_3CO_2H[/tex]. It means, that 250 ml of vinegar with a concentration of acetic acid equal to 7% reacts completely with 24 g of baking soda.
Hence, If the concentration of Acetic acid in vinegar is more than 7%, the limiting reactant is baking soda. If the concentration of Acetic acid in vinegar is less than 7%, the limiting reactant is vinegar.
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Aqueous Copper (II) nitrate reacts with aqueous potassium iodide to form Copper (II) iodide solid and potassium nitrate
Answer:
Cu(NO₃)₂ (aq) + 2 KI (aq) ---> CuI₂ (s) + 2 KNO₃
Explanation:
When writing the reaction with the symbols, you need to take into account the charges of the ions. If he charges on the ions do not balance out in a molecule, they need to be made up for in the form of subscripts. For example, copper (+2) and iodine (-1) have charges which do not balance. Thus, to make the molecule neutral, you need to have two iodine atoms (CuI₂).
The unbalanced equation:
Cu(NO₃)₂ (aq) + KI (aq) ---> CuI₂ (s) + KNO₃
Reactants: 1 copper, 2 nitrate, 1 potassium, 1 iodine
Products: 1 copper, 1 nitrate, 1 potassium, 2 iodine
The balanced equation:
1 Cu(NO₃)₂ (aq) + 2 KI (aq) ---> 1 CuI₂ (s) + 2 KNO₃
Reactants: 1 copper, 2 nitrate, 2 potassium, 2 iodine
Products: 1 copper, 2 nitrate, 2 potassium, 2 iodine
How many mol of C7H16 would you have if you have 76.36 grams? Give your answer to 2 decimal spaces.
0.761 mol of [tex]C_7H_{16}[/tex] would you have if you have 76.36 grams.
What is a mole?A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
Given data:
Mass=76.36 grams
[tex]Moles = \frac{mass}{molar \;mass}[/tex]
[tex]Moles = \frac{76.36 grams}{100.21 g/mol}[/tex]
Moles = 0.761
Hence, 0.761 mol of [tex]C_7H_{16}[/tex] would you have if you have 76.36 grams.
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Assume that you measured exactly 2.0 mL of the sodium chloride solution into a small test tube. How many moles of
sodium chloride are in the tube?
Lisa made observations of stars at different times of the year. She noticed a lot of patterns in the fall, while she couldn't find any patterns in the summer. Why might this be?
This is because fall has more weather patterns which are repetitive than summer.
What is Weather?This is defined as the atmospheric condition of a particular place at a given period of time.
The repetitive weather patterns have various effects on the stars which is why they were studied.
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If a snail crawls at a rate of 228.16cm/s, what is its speed in miles per hour?
If a snail crawls at a rate of 228.16cm/s, Its speed in miles per hour will 5.10 miles/hour
What is speed ?
The rate at which someone or something moves or operates or is able to move or operate.
Snail covers distance in 1 seconds = 228.16 cm
It covers in 60 seconds (1 min) = 228.16 cm x 60 = 6mtrs
It covers in 60 minutes (1 hour) = 228.16 cm x 60 x 60 = 821376 cm
Now, lets convert cm to miles :
As, 1 cm = 6.21371 x 10⁻⁶ miles
Thus, 821376 cm = 5.10 miles
hence, If a snail crawls at a rate of 228.16cm/s, Its speed in miles per hour will 5.10 miles/hour
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Convert the scientific notation to a decimal number.
To convert Scientific Notation to a decimal number, Prescribed steps are to be taken given below.
What is Scientific Notation ?Scientific notation is a way of writing very large or very small numbers.
A number is written in scientific notation when a number between 1 and 10 is multiplied by a power of 10.
Steps to Calculate Scientific Notation ;Determine the exponent, n , on the factor 10 .Move the decimal n places, adding zeros if needed. If the exponent is positive, move the decimal point n places to the right. If the exponent is negative, move the decimal point |n places to the left.Check.Learn more about Scientific Notation here ;
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What is the volume occupied by 14.3 g of argon gas at a pressure of 1.35 atm and a temperature of 436 K?
Answer:
9.487 L
Explanation:
argon mole wt = 39.948 gm/mole
14.3 gm / 39.948 gm/mole = .357965 moles of argon
Use Ideal Gas Law:
PV = n RT where R = .082057 L-atm / K-mol
V = .357965 * .082057 * 436 / 1.35 = 9.487 L
A laser emits light at a wavelength of 678 nm. How many photons are required to emit 1 joule of energy?
0.342 x [tex]10^(^1^6^)[/tex]) photons are required to emit 1 joule of energy.
What is a photon?A photon is a particle of light defined as a discrete bundle (or quantum) of electromagnetic (or light) energy.
We need to find the number of photons emitted per second.
So we have E = hc ÷ λ
= (6.6 x [tex]10^-(^3^4^)[/tex]x 3 x [tex]10^8[/tex] m/s) ÷ 6.78 x [tex]10^(^-^7^)[/tex]nm
= 2.92 x [tex]10^(^-^1^9^)[/tex]Joules
Now number of photons per second = I / E (I = intensity)
= 1 x [tex]10^(^-^3^)[/tex] joule / sec ÷ 2.92 x [tex]10^(^-^1^9^)[/tex]joule
= 0.342 x[tex]10^(^1^6^)[/tex]
Hence, 0.342 x [tex]10^(^1^6^)[/tex]) photons are required to emit 1 joule of energy.
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A boy throws a stone vertically up into the air. What are the energy changes that take place as the stone falls to the ground?
Answer/Explanation:
The boy's muscle energy changes into potential energy due to the height. it then converts into kinetic energy as it goes further upwards into the air.
11C. Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions. It has the unwieldy formula of KHC8H4O4. This is often written in shorthand notation as KHP .If 3.41 grams of KHC are needed to exactly neutralize 31.2 mL of a potassium hydroxide solution, what is the concentration of the base solution?
13B.
H3AsO4 + H2C2O4—--------2CO2 + H3AsO3+ H2O
In the above redox reaction, use oxidation numbers to identify the element oxidized, the element reduced, the oxidizing agent and the reducing agent.
name of the element oxidized:
name of the element reduced:
formula of the oxidizing agent:
formula of the reducing agent:
For the reactants,
The oxidation number of hydrogen = +1The oxidation number of oxygen = -2The oxidation number of arsenic = +5The oxidation number of carbon = +3For the products,
The oxidation number of hydrogen = +1The oxidation number of oxygen = -2The oxidation number of arsenic = +3The oxidation number of carbon = +4Here, arsenic (+5 to +3) and carbon (+3 to +4) are the only oxidation numbers changing.
Note that an increase in oxidation number means electrons are lost. Thus oxidation is occurring, and a decrease in oxidation number means electrons are being gained, and thus reduction is occurring.
Also, the compound that contains the element being oxidized is the reducing agent, and the compound that contains the element being reduced is the oxidizing agent.
So, the answers are:
name of the element oxidized: Carbon
name of the element reduced: Arsenic
formula of the oxidizing agent: [tex]\text{H}_{3}\text{AsO}_{4}[/tex]
formula of the reducing agent: [tex]\text{H}_{2}\text{C}_{2}\text{O}_{4}[/tex]
What hazard symbol does alcohol have? Why?
Answer:
Alcohol has considerable toxic effects on the digestive- and cardiovascular systems. Alcoholic beverages are classified as carcinogenic by the International Agency for Research on Cancer and increase the risk of several cancer types.
Explanation:
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Alcohol has a fire hazard symbol because it is extremely flammable and can create fires. Too be specific, ethanol alcohol is the flammable substance.
How many moles are in 24 g of carbon
Answer:
[tex]\fbox {2 moles}[/tex]
Explanation:
Relation between grams of Carbon and moles :
[tex]\fbox {12 g Carbon = 1 mole}[/tex]
Multiply both sides by 2 :
⇒ 1 x 2 moles = 12 x 2 g
⇒ 2 moles = 24 g
Engineers are starting on a new project to develop technology. Which of these
statements does not describe something they might do at the very beginning
of the process?
OA. Look at the problems society is facing.
OB. Make a decision about how to best apply the technology.
C. Look at the benefits and challenges of using specific materials.
OD. Decide whether they have designed the best possible product.
Answer: Decide whether they have designed the best possible product.