Answer:
CSP
Explanation:
CSP systems store energy through Thermal Energy Storage technologies (TES), so power can be used when there isn't enough sunlight. PV systems, however, can't store thermal energy because they use direct sunlight, rather than heat. For this reason, CSP systems are better for energy storage and efficiency.
It just so happens that regardless of the material, when objects are heated up they will start to glow and change colors at near identical temperatures. The plot that you see is called a blackbody spectrum. This plot tells us the intensity or the “amount” of light that an object will emit at different wavelengths (or “colors”). The visible wavelengths are marked by their colors on the plot. To the right of the visible band is lower energy infrared light. To the left of this band is higher energy ultraviolet (UV) light.
Click the + button that is to the left of the intensity scale (far left side of the screen) such that the top of the scale is at 1x10-3 (in the picture above, the top of the scale says 100).
Now use the temperature slider to the right, and take the temperature all the way down to 300 Kelvin (80 Fahrenheit).
Now slowly begin to raise the temperature. At approximately what temperature would a heated material (metal, wood, etc.) begin to give off visible light at a deep red color?
Answer: the plot that you see is called a blackbody spectrum. This plot tells us the intensity or the amount of light that an object will emit at different wavelenths.
Explanation: i hope that this helps
A hollow cast-iron cylinder 4m long, 300mm outer diameter, and thickness of metal 50mm is subjected to a central load on the top when standing straight. The stress produced is 75000kN/m2. Assume Young's modulus for cast iron as 1.5x 108 kN/m^2 and find (i) magnitude of the load, (ii) longitudinal strain produced, and (iii) total decrease in length.
Here, the calculated Magnitude of the load P is 2945.2 kN, the Longitudinal strain produced is 0.0005 and the decrease in length is 2 mm.
Given,
Length, L = 4 m
Outer diameter, D = 300mm, D= 0.3 m
Thickness, t = 50 mm, t = 0.05 m
Stress produced, σ = 75000 kN/m²
Young's modulus for cast iron, E = 1.5 x 10⁸ kN/m²
Calculating the diameter of the cylinder,
Diameter of cylinder, d = (D) – (2t) = 0.3 –( 2 × 0.05)
d= 0.2 m
(i) Magnitude of the load P:
Using the relation, σ =P/A
P = σ × A = 75000 × π /4 (D² – d² )
P= 75000 × π/4 (0.3² – 0.2²)
P= 75000 × π/4 (0.09 – 0.04)
P = 2945.2 kN
Hence, Magnitude of the load P is 2945.2 kN.
(ii) Longitudinal strain produced, e :
Using the relation, Strain, (e) = stress/E
e= 75000/(1.5 x 10⁸)= 0.0005
Hence, the Longitudinal strain produced is 0.0005.
(iii)Total decrease in length, dL:
The total decrease in length can be calculated using the strain as the ratio of change in length to the original length is known as Strain.
Strain = change in length/original length
e= dL/L
0.0005 = dL/4
dL = 0.0005 × 4m = 0.002m=2mm
Hence,the decrease in length is 2 mm.
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identity the sentence that uses quotas and interviews.
A. let us all learn from the history of our country.
B. the guests arrived on time.
C. "My dream is to build my own mansion, "Adrian answered.
D. Teacher Cellyn Kyre ensures that her classroom is always ready for the face to face classes
Teacher Cellyn Kyre ensures that her classroom is always ready for the face to face classes is the sentence used in quotas and interviews.
What is interview?Interview is the examination of the candidate from which a person identifies the candidate is fit for the organization o r not. Maximum interview happened between the interviewer and the candidate. or sometime more people can also be present.
Thus, option D is correct.
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Water flows through a pipe of diameter 8.0 cm with a speed of 10.0 m/s. It then enters a smaller pipe of diameter 3.0 cm. What is the speed of the water as it flows through the smaller pipe? (4) Water flows through a pipe of diameter 8.0 cm with a speed of 10.0 m / s . It then enters a smaller pipe of diameter 3.0 cm . What is the speed of the water as it flows through the smaller pipe ? ( 4 )
Answer:
71m/s
Explanation:
when you convert it you get 158.822 miles per hour
When a cold alcohol thermometer is placed in a hot liquid, the column of alcohol goes down slightly before going up. Explain why.
Answer:
See below
Explanation:
When a cold alcohol thermometer is placed in a hot liquid, the following takes place.The glass of thermometer expands because of the heat so the column of alcohol goes down.After some time, the heat travels to alcohol and then alcohol expands.So, Reason why alcohol goes down first:Alcohol first goes slightly down because of the expansion of the glass of thermometer before doing up.
[tex]\rule[225]{225}{2}[/tex]
2. Height at point A is 30.0 meters with a cart mass of 200.0 kg initially at rest. Point B is at a height of 25.0 meters. Find the KE and PE at points A and B along with the velocity at point B assuming no friction. Show Your Work
At maximum height, velocity is zero and kinetic energy will be zero.
K.E(A) = 0
P.E(A) = mgh = 200 x 9.8 x 30 = 58,800 J
K.E(B) = P.E(A) - P.E(B)
K.E(B) = 58,800 J - (200 x 9.8 x 25)
K.E(B) = 58,800 J - 49,000 J
K.E(B) = 9,800 J
Velocity at point BK.E = ¹/₂mv²
v² = 2K.E/m
v² = (2 x 9800)/(200)
v² = 98
v = √98
v = 9.9 m/s
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question is below............
The total distance traveled by the gardener is 8 meters. the magnitude of total displacement is approximately 7 meters.
Total distance covered by gardener = 2 + 1 +2 + 3= 8 meters
For the magnitude of displacement, we will take the shortest path for the gardener movement.
for displacement-
[tex]=\sqrt{( 0-4^{2}) +( 6-0^{2} )}\\=\sqrt{52} \\=7[/tex](approximately)
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suppose the velocity of a particle is given by the equation, V=m+nt2, where m=10cms and n=2cm/s3.
A, find the change in velocity of the particle in the initial time interval b/n t₁=2sec and t₂=5sec
B, find the average acceleration in this time interval
C, find the instantaneous acceleration at time t₁=2sec
Hello!
Begin by plugging in the values for m and n. We get the equation for the velocity of the particle to be:
[tex]v(t) = 10 + 2t^2[/tex]
A.
To find the change in velocity over the interval (2s ≤ t ≤ 5s), we can simply find the difference in the velocities at these times.
[tex]\Delta v= v_f - v_i[/tex]
For this situation:
[tex]\Delta v = v(5) - v(2)[/tex]
Substitute these times for 't' into the equation and solve.
[tex]v(5) = 10 + 2(5^2) = 60 \frac{cm}{s}\\\\v(2) = 10 + 2(2^2) = 18 \frac{cm}{s}\\\\\Delta v = 60 - 18 = \boxed{42 \frac{cm}{s}}[/tex]
B.
To find the average acceleration, we must take the SLOPE of the velocity function over this interval using the slope formula:
[tex]a_{avg} = \frac{v_f - v_i}{\Delta t}[/tex]
Plug in the values for the particle's velocity at t = 2 s and 5 s that we solved for above.
[tex]a_{avg} = \frac{60- 18}{5 - 2}\\\\a_{avg} = \frac{42}{3} = \boxed{ 14 \frac{cm}{s^2}}[/tex]
C.
The instantaneous acceleration can be found by taking the derivative of the v(t) function using the power rule. Recall:
[tex]\frac{dy}{dx} x^n = nx^{n-1}[/tex]
Using this rule:
[tex]a(t) = v'(t) = 2(2t) = 4t[/tex]
Substituting in t = 2 s:
[tex]a(2) = 4(2) = \boxed{8 \frac{cm}{s^2}}[/tex]
Water moves through a constricted pipe in steady, ideal flow. At the lower point shown in Figure 1, the pressure is and the pipe diameter is 6.0 cm. At another point higher, the pressure is and the pipe diameter is 3.0 cm. Find the speed of flow (a) in the lower section and (b) in the upper section. (c) Find the volume flow rate through the pipe
Answer:
full explanation and answer is on the picture
Honey bees beat their wings, making a buzzing sound at a frequency of 2.3 × 102 hertz. What is the period of a bee's wing beat?
the primary coil of a transformer has 480 turns, and the secondary has 112 turns. when an ac voltage of 28.0 v is applied to the primary, what is the output voltage in the secondary?
The voltage of the secondary will be 36 V.From the given conditions primary transformer has 3 times as many turns in the secondary coil.
What is induced voltage?Electromagnetic induction is what causes the induced voltage. Electromagnetic induction is the process of generating emf (induced voltage) by subjecting a conductor to a magnetic field.
Given data;
No turns in the primary coil,[tex]\rm N_p = 480 turns[/tex]
No turns in the secondary coil,[tex]\rm N_s = 112 turns[/tex]
The voltage of the primary coil,[tex]\rm V_p = 28 v[/tex]
The voltage of the secondary coil,[tex]\rm V_s = ?[/tex]
For a transformer,
[tex]\rm \frac{V_p}{V_s}= \frac{N_p}{N_s} \\\\ \rm \frac{28}{V_s}= \frac{480}{112} \\\\ V_s = 6.53 \ v[/tex]
Hence the voltage of the secondary will be 36 V.
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Answer: 6.53
Explanation: I had the same question and here's what I got:
Values:
Vp (Primary Voltage) = 28.0
Ns (Secondary Number of Turns) = 112
Np (Primary Number of Turns) = 480
Vs = Vp Ns/Np
= (28)(112)/(480)
Vs = 6.53 (FINAL ANSWER)
what type of forces that created at shaping machine
Answer:
a magnetic force
Explanation:
A car headed north at 15.0 m/s experiences an acceleration of 2.50 m/s2 for 3.00 s. What is the final velocity of the car?
Answer:
i dond no can you put another question
Q3, A ball of mass 5.0 kg moving with a Velocity of 10.0 ms collides
with a 15.0 kg ball moves with a Velocity of 4 ms! If both balls
Stick together after Collision, Calculate their Common Velocity after Impact if they initially moves in The Same direction, and Opposite direction.
Answer:
Their common velocity after the collision will be 5.5m/s
Explanation:
look at the attachment above ☝️
Select the correct answer.
What is the average velocity of the particle from rest to 9 seconds?
The average velocity of the particle from rest to 9 seconds would be 2 meters/sec.
How to find the average velocity?This average velocity can be calculated with the following equation:
v = dx / dt
where:
dx = displacement = 18 meters
dt = interval of time = 9 seconds
Substitute;
v = dx / dt
v = 18 / 9
v = 2 meters/sec
Hence, the average velocity of the particle from rest to 9 seconds would be 2 meters/sec.
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the 3kg object in figure is released from rest at height of 5m on curved frictionless ramp.at the foot of the ramp is a spring of force constant 400N/m.the object slide down the ramp and into the spring, compressing it a distance x before coming momentarily to rest. a) find x
b)describe the motion of the object (if any) after the block momentarily comes to rest?
The value of x given the data from the question is 0.86 m
How to determine the energyFrom the data given above, we can s determine the energy as follow:
Mass (m) = 3 KgHeight (h) = 5 mAcceleration due to gravity (g) = 9.8 m/s² Energy (E) = ?E = mgh
E = 3 × 9.8 × 5
E = 147 J
How to determine the value of xSpring constant (K) = 400 N/mEnergy (E) = 147 JExtention (e) = x = ?E = ½Ke²
147 = ½ × 400 × x²
147 = 200 × x²
Divide both side by 200
x² = 147 / 200
Take the square root of both sides
x = √( 147 / 200)
x = 0.86 m
Since the block came to rest, there is no motion
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A hollow conducting sphere has an inside radius of r1 = 0.17 m and an outside radius of r2 = 0.28 m. The sphere has a net charge of Q = 4.8E-06 C. What is the magnitude of the field, in newtons per coulomb, at a distance of 0.05 m from the center of the sphere?
Explanation:
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velocity and distance of free falling object dropped from rest
The diagram shows the speed and distance of a free-falling item dropped from rest. In the attachment, there is a graph.
What is velocity?The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The velocity and the time at the different points are;
A(0 sec ,0 m/sec)
B(1,9.8)
C(2,19.6)
D(3,29.4)
E(4,39.2)
F(5,49.0)
The point is plotted on the graph and get the graph.
The graph is attached in the attachment.
The complete question is;
Velocity and distance of free-falling object dropped from rest are given in the digrame. Draw the velocity-time graph for the given conditions.
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On Earth, a scale shows that you weigh 490 N. What is your mass?
A 50 kg
B 100 kg
c) 75 kg
D 22 kg
Answer:
a
Explanation:
Two charged particles are near each other – the charge magnitudes are +3 uC and +7 uC, respectively. The electrostatic force between these charges is 25 N. A charged particle of -1 uC is added to both of the original two charges. What is the electrostatic force between the two charged particles after the -1 uC charge is added?
Answer:
Approximately [tex]14\; {\rm N}[/tex].
Explanation:
By Coulomb's Law, the magnitude of the electrostatic force between two charges is proportional to the product of the magnitudes of the two charges.
For example, consider charges of magnitude [tex]q_{1}[/tex] and [tex]q_{2}[/tex] that are apart from one another by a distance of [tex]r[/tex] in between. Let [tex]k[/tex] denote Coulomb's constant. By Coulomb's Law, the magnitude of electrostatic force between the two charges would be:
[tex]\displaystyle F = \frac{k\, q_{1}\, q_{2}}{r^{2}}[/tex].
In this question, the product of the magnitude of the two charges was originally [tex]3\; {\rm \mu C} \times 7\; {\rm \mu C} = 21\; {\rm (\mu C)^{2}}[/tex]. After [tex](-1\; {\rm \mu C})[/tex] is added to each charge, product of the magnitude of the two charges would become [tex](3 - 1)\; {\rm \mu C} \times (7 - 1)\; {\rm \mu C} = 12\; {\rm (\mu C)^{2}}[/tex].
Thus, the product of the magnitude of the two charges has been scaled to [tex]12\; {\rm \mu C}[/tex] from [tex]21\; {\rm \mu C}[/tex] . The magnitude of the electrostatic force between the two charges would be scaled from [tex]25\; {\rm N}[/tex] to [tex]25\; {\rm N} \times (12 / 21) \approx 14\; {\rm N}[/tex].
Across:
5. The term used for describing the
bending of an arm or a leg
6.
9.
Down:
1. This is one popular brand of exercise
machine
2.
They are made of two types of fibers
You can achieve your target pulse rate
by varying the number of these
flexes the arms at
10. The arm
the elbows
11. These muscle fibers do not require as
much oxygen
13. He wrote a book on aerobics
14. This type of training works primarily
with the white muscle fibers
15.
extends the legs at the
The leg
knees
16. Aerobic exercises help the body's
ability to use this element
18.
The term used to describe the straight-
ening of your arm or leg
3.
4.
5.
6.
7.
8.
This was the most popular form of aerobic
exercise in the early years of aerobics
This organ is one part of the cardiovascu-
lar system
This exercise conditions the cardiovascu-
lar system
Aerobic exercise became part of this
movement in the 1970s
12.
17.
This accompanies aerobic dance
A specific exercise produces this type of
result
This type of training involves moving
from one exercise machine to another with
little rest
If you just train for strength, you will not
improve this
These muscle fibers contract more slowly
Answer:hight
Explanation:
The flux through the coils of a solenoid changes from 2.57.10-5 Wb to 9.44.10-5 Wb in 0.0154 s. If 4.08 V of EMF is generated, how many loops does the solenoid have? (No unit)
Hello!
We can use Faraday's Law of Electromagnetic Induction to solve.
[tex]\epsilon = -N \frac{d\Phi_B}{dt}[/tex]
ε = Induced emf (4.08 V)
N = Number of loops (?)
[tex]\Phi_B[/tex] = Magnetic Flux (Wb)
t = time (s)
**Note: The negative sign can be disregarded for this situation. The sign simply shows how the induced emf OPPOSES the current.
Now, we know that [tex]\frac{d\Phi_B}{dt}[/tex] is analogous to the change in magnetic flux over change in time, or [tex]\frac{\Delta \Phi_B}{\Delta t}[/tex], so:
[tex]\epsilon = N \frac{\Delta \Phi_B}{\Delta t}\\\\\epsilon = N \frac{\Phi_{Bf} - \Phi_{Bi}}{\Delta t}[/tex]
Rearrange the equation to solve for 'N'.
[tex]N = \frac{\epsilon}{ \frac{\Phi_{Bf} - \Phi_{Bi}}{\Delta t}}[/tex]
Plug in the given values to solve.
[tex]N = \frac{4.08}{ \frac{9.44*10^{-5} - 2.57*10^{-5}}{0.0154}} = 914.585 = \boxed{915 \text{ coils}}[/tex]
**Rounding up because we cannot have a part of a loop.
What is the acceleration of the object?
m/s²
Answer:
-2.5m/s^2
Explanation:
10-40/12-0=-2.5
Find the magnitude of this
vector:
The magnitude of the vector is 34.092 N
What is resultant?The resultant is the square root of sum of square of the vector component of x and y direction.
R =√ [(Nx)² +(Ny)²]
Given is the vector with horizontal length of the vector = -28.7 m and the vertical length of the vector = 18.4 m
The resultant will be
R =√ [(-28.7)² +(18.4)²]
R = 34.092 N
Thus, the magnitude of the vector is 34.092 N.
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Two students have fitted their scooters with the same engine. Student A and his
scooter have a combined mass of 127.5 kg and a maximum acceleration of
2.40 m/s². Student B has a maximum acceleration of 1.70 m/s on her scooter.
Show that the combined mass of student B and her scooter is 120 kg
You may assume that the frictional forces acting on each scooter are negligible.
The force exerted by student A with his scooter is 306 N and that of student B is 204 N.
Force applied by each studentThe force exerted by each student is calculated from Newton's second law of motion.
F = ma
where;
m is mass a is accelerationF(A) = 127.5 x 2.4
F(A) = 306 N
F(B) = 120 x 1.7
F(B) = 204 N
Thus, the force exerted by student A with his scooter is 306 N and that of student B is 204 N.
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Places rich in limestone and gypsum have hard water . why ??
Answer:
Hard water is formed when water percolates through deposits of limestone, chalk or gypsum which are largely made up of calcium and magnesium carbonates, bicarbonates and sulfates.
Explanation:
Hard water is formed when water percolates through deposits of limestone, chalk or gypsum which are largely made up of calcium and magnesium carbonates, bicarbonates and sulfates.
Answer:
Hard water indicates a high amount of minerals.
Explanation:
This most often occurs when natural water sources pass through mineral deposits such as limestone or chalk. The process leads to a relatively high level of calcium, iron, and magnesium.
A star near the visible edge of a galaxy travels in a uniform circular orbit. It is 41,200 ly (light-years) from the galactic center and has a speed of 275 km/s. Estimate the total mass of the galaxy based on the motion of the star.
Gravitational constant is 6.674×10−11 m3/(kg·s2) and mass of the Sun Ms=1.99 × 1030 kg.
*Answer in billion solar mass
The total mass of the galaxy is 443.4 Solar mass
Orbital velocity ([tex]v[/tex]) = [tex]\sqrt{\frac{MG}{R} }[/tex]
where M= weight of galaxy
G= gravitational constatnt = [tex]6.674*10^-^1^1[/tex] (given)
R = distance from centre = [tex]41200[/tex] Light years (given)= [tex]4.12*9.5*10^1^6[/tex] km (1 ly= [tex]9.5*10^3[/tex] billion km)
v= orbital velocity = [tex]275[/tex] [tex]km/s[/tex] (given)
∴ According to the formula
[tex](2.75*10^2)^2[/tex] = [tex]\frac{M*6.674*10^-^1^1}{4.12*9.5*10^1^6}[/tex]
⇒ [tex]7.56*10^4*4.12*9.5*10^1^6=M*6.674*10^-^1^1[/tex] (cross multiplying and expanding)
⇒ [tex]29.59*10^2^1=M*6.674*10^-^1^1[/tex]
⇒ [tex]\frac{29.59*10^2^1*10^1^1}{6.674}=M[/tex]
⇒ [tex]4.434*10^3^2=M[/tex]
1 solar mass = [tex]1.989*10^3^0 kg[/tex]
⇒ Mass in solar mass =443.4 Solar mass
⇒ M = 443.4 Solar mass
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How is volume flow related to cross sectional area? How is it related to fluid pressure?
Answer:
A venturi meter is used to measure the flow speed of a fluid in a pipe. The meter is connected between two sections of the pipe (the figure); the cross-sectional area A of the entrance and exit of the meter matches the pipe's cross-sectional area. Between the entrance and exit, the fluid flows from the pipe with speed V and then through a narrow ''throat'' of cross-sectional area a with speed v. A manometer connects the wider portion of the meter to the narrower portion. The change in the fluid's speed is accompanied by a change Δp in the fluid's pressure, which causes a height difference h of the liquid in the two arms of the manometer. (Here Δp means pressure in the throat minus pressure in the pipe.) Let A equal 5·a. Suppose the pressure p1 at A is 2.1 atm.
Compute the values of (a) the speed V at A and (b) the speed v at a that make the pressure p2 at a equal to zero.
(c) Compute the corresponding volume flow rate if the diameter at A is 4.0 cm.The phenomenon that occurs at a when p2 falls to nearly zero is known as cavitation. Please assume that the fluid is water. The water vaporizes into small bubbles.
One support of the behavioral perspective is how B. F. Skinner’s ideas have brought to light how the __________ and __________ influence personality.
One support of the behavioral perspective is how B. F. skinner’s ideas have brought to light how the environment and learning influence personality.
What is the behavioral perspective?The behavioral perspective on personality and individual variations places an emphasis on quantifiable behaviors influenced by the environment and the results that follow.
The theoretical aim of behaviorism is the prediction and control of behavior given its natural science methodology.
Skinner's theories have made it clear how learning and the environment affect personality, which is one argument in favor of the behavioral approach.
One support of the behavioral perspective is how B. F. skinner’s ideas have brought to light how the environment and learning influence personality.
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Radioactive decay can involve electrons
True or False
Answer:
i believe the answer is true