What is the mechanical advantage of a wheel barrel that is 4cm long with 0.75m between the wheel and the center of the load?

Answer:

The mechanical advantage = 4/75

Explanation:

A wheel barrel is a second class as the effort is placed further from the point of fulcrum than the point of action of the load

The parameters given are;

Length of wheel barrel = 4 cm

Distance between wheel and center of load = 0.75 m

Therefore, we have the mechanical advantage, MA given as follows;

[tex]MA = \dfrac{F_{o}}{F_{i}} = \dfrac{L_{i}}{L_{o}}[/tex]

[tex]{F_{o}}[/tex] = Output force

[tex]{F_{i}}[/tex] = Input force

[tex]{L_{o}}[/tex] = Distance from output force =  0.75 m

[tex]{L_{i}}[/tex] = Distance from input force = 4 cm = 0.04 m

Therefore;

[tex]MA = \dfrac{0.04}{0.75} = \dfrac{4}{75}[/tex]

The mechanical advantage MA = 4/75 = 0.0533

Therefore, more force (75/4 × the load) will be required to lift a given load.

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establishes general guidelines concerning licensing and vehicle
10. The
registration.
A. National Highway Safety Act
B. National Traffic and Motor Vehicle Safety Act
C. Uniform Traffic Control Devices Act