The basic equation for calculating compound interest is A = P(1 + nt.
If $1,200 is invested at an interest rate of 8% per year, compounded quarterly, how much will the
investment be worth at the end of 10 years?
Show your work!

The Basic Equation For Calculating Compound Interest Is A = P(1 + Nt.If $1,200 Is Invested At An Interest

Answers

Answer 1

The amount of the investment at the end of the 10 years period if compounded quarterly is $2,649.6.

Compound interest

Principal, P = $1200Interest rate, r = 8% = 0.08Time, t = 10Number of period, n = 4

A = P(1 + r/n)^nt

= 1200(1 + 0.08/4)^(4×10)

= 1200(1 + 0.02)^40

= 1200(1.02)^40

= 1200(2.208)

= $2,649.6

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Related Questions

Thankyou guys for all your help….I need help with one more plsss

Round to the nearest tenth

Answers

I don't understand your question

I got the answer some where I just got to find it

Can someone please help me

Answers

The triangles largest area is c I hope it helps

What is the height of a triangle whose
base is 8.2 centimeters and whose area
is 173.43 square centimeters?

Answers

Answer:

42.3cm

Step-by-step explanation:

I think this is right :)

Please help!!!!!
The equation of a circle is x² + y² – 8x + 10y + 37 = 0. What is the center and the radius of the circle? Show all your work.

Answers

Let's take this problem step-by-step:

 

Let's convert the equation back into the standard form:

     ⇒ standard form: (x-h)² +(y-k)² = r²

(h, k): center's coordinater: radius

       [tex]x^2+y^2-8x+10y + 37 = 0\\\rm \hookrightarrow x^2 - 8x + y^2+10y = -37\\\rm \hookrightarrow (x^2 - 8x) + (y^2 + 10y) = -37\\\rm \hookrightarrow (x^2-8x+16) + (y^2+10y+25) = -37 + 16 +25\\\rm \hookrightarrow (x-4)^2 + (y+5)^2 = 4\\\rm \hookrightarrow (x-4)^2 + (y+5)^2 = 2^2[/tex]

Based on the equation found

  ⇒ center: (4, -5)

   ⇒ radius: 2

Answer:

center: (4, -5)radius: 2

Hope that helps!

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What are the solutions to the quadratic equation below in factored form?
(10x + 5)(11x - 44) = 0
= ½, x = 4
0x=
0 x = 2, x = -4
0x = 2, x = 4
○ x = − ½, x = 4

Answers

Answer:

D.) x = − ½, x = 4

Explanation:

[tex]\rightarrow \sf (10x + 5)(11x - 44) = 0[/tex]

set the factors to zero

[tex]\rightarrow \sf 10x + 5 = 0, \ 11x - 44 = 0[/tex]

exchange the sides

[tex]\rightarrow \sf 10x = -5, \ 11x = 44[/tex]

exchange the sides

[tex]\rightarrow \sf x = -\dfrac{5}{10} , \ x = \dfrac{44}{11}[/tex]

simplify the following

[tex]\rightarrow \sf x = -\dfrac{1}{2} , \ x =4[/tex]

(10x+5)(11x-44)=010x(11x-44)+5(11x-44)=0110x²-440x+55x-220=0110x²-385x-220=0

On solving

x=-1/2 or x=4

add the following rational number7/-27 and 11/18

Answers

Answer:

19/54

Step-by-step explanation:

- 7/27 + 11/18

LCM of the 27, 18 is 54

- 7/27 * (2/2) + 11/18 * (3/3)

- 14/54 + 33/54

33 - 14/54

19/54

please mark me brainlist

C
7 cm
D
What is the sum of the areas of circle C and circle D?
O 7π units²
O 14π units²
O49π units²
O 98π units²

Answers

Answer:

[tex]98 \pi \:\: \sf units^2[/tex]

Step-by-step explanation:

[tex]\textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}[/tex]

From inspection of the given diagram, circle C and circle D both have a radius of 7 cm.

Therefore:

[tex]\implies \textsf{Area of circle C}=\pi (7)^2=49 \pi \:\: \sf cm^2[/tex]

[tex]\implies \textsf{Area of circle D}=\pi (7)^2=49 \pi \:\: \sf cm^2[/tex]

Therefore, the sum of the areas of circle and circle D is:

[tex]\implies \textsf{Area of circle C}+\textsf{Area of circle D}=49 \pi + 49 \pi = 98 \pi \:\: \sf cm^2[/tex]

The sum of the areas of the circles is 98π units².

The correct option is D.

What is a circle?

A circle is a closed, two-dimensional object where every point in the plane is equally spaced from a central point. The line of reflection symmetry is formed by all lines that traverse the circle.

And the general formula of the circle,

(x – h)²+ (y - k)² = r²,

where (h, k) is the center and r is the radius of the circle.

The formula for the area of a circle is A=πr², where A is the area and r is the radius.

For circle C, the radius is 7, so its area is A_C = π(7)² = 49π units².

For circle D, the radius is also 7, so its area is A_D = π(7)² = 49π units².

The sum of the areas is therefore:

A_C + A_D = 49π + 49π = 98π units²

Therefore, the answer is (D) 98π units².

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True OR False
------------------------
x - 62 = 44, x = 106​

Answers

Answer:

True

Step-by-step explanation:

Step 1: We can plug 106 into x in the equation x - 62 = 44.

Step 2: Check if 106 - 62 = 44. It’s correct, so the answer is TRUE!!

Please mark me as Brainliest. Thanks

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:True [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: x - 62 = 44[/tex]

[ add 62 on both sides ]

[tex]\qquad \tt \rightarrow \: x - 62 + 62 = 44 + 62[/tex]

[tex]\qquad \tt \rightarrow \: x = 106[/tex]

The proved value is same as that of statement, hence the statement is correct.

Fully simply 15x^4y^4(−5x^3y^5)

Answers

Answer:

[tex]-75x^{7}y^{9}[/tex]

Step-by-step explanation:


Find the equation of the parabola with its focus at (6,2) and its directrix y = 0.

Answers

The standard form is y = x 2 4 − 3 x + 10 y= 4 x 2 ​ −3x+10.

The general form is x 2 − 12 x − 4 y + 40 = 0 x 2 −12x−4y+40=0.

The vertex form is y = ( x − 6 ) 2 4 + 1 y= 4 (x−6) 2 ​ +1.

A 210-N mass is suspended from a horizontal beam by two cables that make angles of 29 degrees and 53 degrees with the beam. Find, using vectors, the tension in the cables.

Answers

The tension in both cables are calculated as; T₁ = 127.63 N and T₂ = 185.48 N

How to find the Tension in Suspended Cables?

Resolving forces in the y direction gives us;

T₁ sin 29° + T₂ sin 53° = 210  ------(eq 1)

Resolving forces in the horizontal direction gives;

T₁ cos 29° = T₂ cos 53°   ----(eq 2)

T₁ = T₂ cos 53°/cos 29°

Thus;

(T₂ cos 53°/cos 29°)sin 29° + T₂ sin 53° = 210  

0.3336T₂ + 0.7986T₂ = 210

T₂ = 210/1.1322

T₂ = 185.48 N

Thus;

T₁ = 185.48 cos 53°/cos 29°

T₁ = 127.63 N

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Juanita’s boss told her that once she has worked with the company for 10 years, her salary will be increased to 3 times what she makes now plus $2,000. If s represents her original salary, which expression represents what her salary will be after 10 years at the company?
One-third s + 2,000
StartFraction 3 Over s EndFraction + 2,000
3 s + 2,000
2,000 minus 3 s

Answers

An expression is defined as a set of numbers, variables, and mathematical operations. The correct option is C.

What is an Expression?

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

Juanita’s salary once she completes 10 years, her salary will be increased to 3 times what she makes now plus $2,000. Now, if her salary is represented by s, then the expression that would represent her salary after 10 years is,

Salary after 10 years = 3s + 2000

Hence, the correct option is C.

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Answer:

C

Step-by-step explanation:

Select the correct answer.
Sammile pays $30 for a bag that she buys at a discount of 50% What is the price of the bag without the discount?
O A $30
O B. $45
O C. $60
O D. $80

Answers

If 30 is half price, then what is full price?

You can set up this problem like this:

30 = x/2

OR

30 = (1/2)x

where x is the full price.

To solve, simply multiply each half by 2:

2(30) = 2((1/2)x)

x = $60

C. $60. If 50% is 30, the other 50% is also 30. This would make 100% 60.

Simplify. Rewrite the expression in the form 9^n9
n
9, start superscript, n, end superscript.
(9^{-3})(9^{12})=(9
−3
)(9
12
)

Answers

[tex] {3}^{18n} [/tex]

Answer:

9^10

Step-by-step explanation:

khan

2. Liam can work at most 20 hours a week but he needs to earn at least $125. His dog-walking job pays.
$7 per hour and his job as a car-wash attendant pays $11 dollars an hour. How can he earn $125? I
Write a system of inequalities to represent this situation.

Answers

Answer:

Look down below and you will know the answer↓:

Step-by-step explanation:

He will have to work as between the range (of 20,0) and (0,20) points to earn more than $125.

So, What is inequality?

Inequality means is the relationship between two expressions that are not equal, so employing a sign such as ≠ “is not equal to,” > “greater than,” or < “less than.”.

Since then: Liam can work at most 20 hours a week, but he also needs to earn at least $125. His dog-walking job pays $7 per hour and his job as a car-wash attendant pays $11 dollars an hour. How can he earn $125.

He Let the Dog walking hours are represented by x and Car wash hours will be represented by y. The inequality will be formed as:

7x + 11y ≥ 125

x+y = 20

When we plot these two equations on the graph, we will get the range for the time from (20,0) and (0,20).

We Suppose that we will take a random point-like (5,15) when we put this value in the inequality, we get the total earning greater than $125.

7x + 11y ≥ 125

7 (5) + 11 ( 15 ) ≥ 125

35  + 165  ≥ 125

200 ≥ 125

Therefore, He has to work between the range (of 20,0) and (0,20) points to earn more than $125.

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A 11 gram sample of a substance that’s used to treat thyroid disorders has a k- value of 0.125

Answers

The substance's half-life is 5.5 days if the 11-gram sample of a substance that’s used to treat thyroid disorders has a k- the value of 0.125

What is exponential decay?

During exponential decay, a quantity falls slowly at first before rapidly decreasing. The exponential decay formula is used to calculate population decline and can also be used to calculate half-life.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have an exponential function:

[tex]\rm N = N_oe^{-kt}[/tex]

Plug N = N⁰/2

[tex]\rm N_o/2 = N_oe^{-kt}[/tex]

[tex]\rm \dfrac{1}{2} = e^{-0.125t}[/tex]

Solving for t:

t = 5.54 ≈ 5.5 days

Thus, the substance's half-life is 5.5 days if the 11-gram sample of a substance that’s used to treat thyroid disorders has a k- the value of 0.125

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19% of 49 in a decimal

Answers

Answer:

[tex] 19\% \: of \: 49[/tex]

[tex] \frac{19}{100} \times 49[/tex]

[tex]0.19 \times 49[/tex]

[tex]9.13[/tex]

Answer:

39.69

Step-by-step explanation:

A percentage is on a scale of 100 so we divide 19 by 100

that makes 0.19.

Then multiply 49 with 0.19 that makes 9.31 (this is 19% of 49)

49 - 9.31 = 39.69

here is an illustration of a bedroom. the striped wall and the floor intersect at a

Answers

Really don’t know WTH u saying lol

Two friends, Vani and Shaquana, took summer jobs. The equation y=28.8xy=28.8x represents Vani's earnings in dollars and cents, yy, for working xx hours. Shaquana earned $653.40 in 33 hours.
How much less per hour does Shaquana earn than Vani?

Answers

An equation is formed of two equal expressions. Shaquana earns $10 less per hour than Vani.

What is an equation?

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The equation y=28.8x represents Vani's earnings in dollars and cents, y, for working x hours.

y = 28.8x

y/x = 28.8

Hence, Vani is paid $28.8 per hour.

The amount that Shaquana earned was $653.40 in 33 hours. Therefore, per hour she was paid

Amount per hour = $653.40/33 = $19.8 per hour

The difference between the two is,

Difference = $28.8 - $19.8 = $10

Hence, Shaquana earns $10 less per hour than Vani.

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Vani - 28.8

y=28.8x

Vani earns $28.80 per hour.

Shaquana -

653.40 / 33 = $19.80 per hour

Shaquana earns $19.80 per hour.

Vani − Shaquana = $28.80

$28.80−$19.80

=$9

Shaquana earns $9 less per hour than Vani.

Hi my name is aughhhhhhhhhhh

Answers

Answer:

Hello auggggh nice to meet you!

Step-by-step explanation:

MisterBrainly (also known as Enstine) lets out 100 feet of string on a kite from a hand height of 3 feet. The angle between horizontal hand height and the kite is 25º. Find the height of the kite above the ground, to the nearest foot.

Answers

Answer: I love the picture example

Step-by-step explanation:

We will first find the heigh of the kite from his hand to a point in the air.

Then, we will add 3 feet to the result.

So, how to find the vertical line of the right triangle?

Well, we have the vertical line = x

We also got the hypothenuse, equal to 100 feet

And also theta, equal to 25 degrees.

We can calculate sine because the sine of 25 degrees = opposite side (the height line) over (divided by) the hypothenuse

sin(25) = x/100 feet

multiply 100 feet on both sides, to cancel to 100 feet on the right side.

100sin(25) = x

100(0.442) = x

x = 42.2  feet

Height = 42.2 + 3 feet (the yoda's hand =) =  45.2 feet (total)

Rounded to the nearest tenth.

I also did the verification, so it is the correct answer.

Easy as that =]]

Height of the kite from 3ft above the ground

[tex]\\ \rm\Rrightarrow sin\Theta=\dfrac{Perpendicular}{Hypotenuse}[/tex]

[tex]\\ \rm\Rrightarrow sin25=\dfrac{P}{100}[/tex]

[tex]\\ \rm\Rrightarrow P=100sin25[/tex]

[tex]\\ \rm\Rrightarrow P=42.26\approx 42ft[/tex]

Height from the ground

42+345ft(Rounded)

A contractor is purchasing some stone tiles for a new patio, each tile costs $3 and he wants to spend less than $1000 the size of each tile is 1 square foot, write and inequality that represents the number of tiles he can purchase with a $1000 limit, and the figure out how large the stone patio can be

Answers

Answer:

333.333 Tiles and 333.333 Square Foot

Step-by-step explanation:

3X <= 1000

X <= 1000/3

X <= 333.333 Tiles

Then

333.333* 1sqt2 = 333.333 Square Foot

6. Find the distance between points A = (2, 0) and B = (0, 9). Round your answer to the nearest
tenth.

Answers

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:\approx 9.2 \:\: units [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex] \textsf{Using distance formula : - } [/tex]

[tex]\qquad \tt \rightarrow \: \sqrt{(x_2 - x_1) {}^{2} + (y_2 - y_1) {}^{2} } [/tex]

[tex]\qquad \tt \rightarrow \: \sqrt{(2 - 0) {}^{2} + (0 - 9) {}^{2} } [/tex]

[tex]\qquad \tt \rightarrow \: \sqrt{(2) {}^{2} + (- 9) {}^{2} } [/tex]

[tex]\qquad \tt \rightarrow \: \sqrt{ 4 + 81} [/tex]

[tex]\qquad \tt \rightarrow \: \sqrt{85} \: \: units[/tex]

[tex]\qquad \tt \rightarrow \: \approx 9.2 \: \: units[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

The distance between points A and B is 9.2 units.

We have,

To find the distance between two points (a, b) and (c, d) in a coordinate plane, you can use the distance formula:

Distance = √[(c - a)² + (d - b)²]

In this case, point A is (2, 0) and point B is (0, 9).

Now, plug the values into the distance formula:

Distance = √[(0 - 2)² + (9 - 0)²]

Distance = √[(-2)² + 9²]

Distance = √[4 + 81]

Distance = √85

Now, round the answer to the nearest tenth:

Distance ≈ √85 ≈ 9.2 (rounded to the nearest tenth)

Thus,

The distance between points A and B is 9.2 units.

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need help with work would give more points but poor​

Answers

Answer:

Step-by-step explanation:

2.5

4 quarts per gallon

8 quarts per 2 gallons

2 quarts is half a gallon since 4 quarts is a full gallon

answer: 2.5

A carpenter started with a board that was 31 inches long. he cut 2 pieces that were each 3 inches long. he then cut 3 pieces that were each

Answers

Answer:

i don't know

Step-by-step explanation:

i

Determine the value of y, if x is 81.
Y=/x+6

Answers

The value of y for the given equation at x=81 is 87.

What is Equation?

Equations are mathematical statements containing two algebraic expressions on both sides of an 'equal to (=)' sign.

Here, given equation;

       y = x + 6

     Put x = 81, we get

       y = 81 + 6

      y = 87

Thus, the value of y for the given equation at x=81 is 87.

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Consider parallel lines cut by a transversal.
Parallel lines q and s are cut by transversal r. On line q where it intersects line r, 4 angles are created. Labeled clockwise, from uppercase left: angle 1, angle 2, angle 4, angle 3. On line s where it intersects line r, 4 angles are created. Labeled clockwise, from uppercase left: angle 5, angle 6, angle 8, angle 7.

Explain which theorems, definitions, or combinations of both can be used to prove that alternate exterior angles are congruent.

Answers

When two parallel lines are cut by a transverse. the angles formed on the exterior of the parallel lines, on the opposite sides of the transverse are known as the Alternate Exterior Angle.

What are Alternate exterior angles?

When two parallel lines are cut by a transverse. the angles formed on the exterior of the parallel lines, on the opposite sides of the transverse are known as the Alternate Exterior Angle.

Firstly, ∠1 and ∠7 are alternate exterior angles as shown in the image, now to prove if these two angles will be congruent we can use the below proof.

First Method:

∠1  + ∠2 = 180° {Supplementary angles because both lies on the line q}

∠2 = (180° - ∠1)

Similarly, ∠2 = ∠6 = (180° - ∠1), corresponding angles are equal,

∠6 + ∠7 = 180° {Supplementary angles because both lies on the line r}

∠7 = 180° - ∠6

∠7 = 180° - (180° - ∠1)

∠7 = 180° - 180° + ∠1

∠7 = ∠1

OR

Second Method:

∠1 = ∠3 {Vertical angles formed by intersecting lines q and r}

∠3 = ∠5 {Alternate Interior angles}

∠5 = ∠7 {Vertical angles formed by intersecting lines s and r}

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Which output in this table is incorrect

Answers

Answer:

B

Step-by-step explanation:

This is quite a trial and error question.

Given from the table

$1 cost of item = $0.08 tax on item

$2 cost of item = ($0.08x2) tax on item = $0.16 tax on item

$3 cost of item = ($0.08x3) tax on item = $0.24 tax on item

$8.50 cost of item = ($0.08x8.50) tax on item =  $0.68 tax on item

$10 cost of item = ($0.08x10) tax on item = $0.80 tax on item

The only one that is different is the incorrect value therefore $0.64 is the incorrect one.

Bryan is making a wooden cube to hold his little sister's jewelry. The volumes the cube is
3
512 in ³. What is the length of one side of the jewelry box?

Answers

Answer:

8 in

Step-by-step explanation:

Volume of Cube = 512 in³

Formula : -

Volume of cube = side x side x side = side³

512 = 8 x 8 x 8 = 8³

So,

The length of one side of the jewelry box is 8 in.

1-sinA+cosA / sinA+cosA-1 = 1+cosA/sinA​

Answers

Solution:

[tex]\dfrac{\left[\left(\sin ^{2} A+2 \times \sin A \times (1-\cos A)+(1-\cos A)^{2}\right]\right.}{\left[\left(1-\cos ^{2} A\right)-(1-\cos A)^{2}\right]}[/tex]

[tex]\dfrac{\left[\left(1-\cos ^{2} A\right)+2 \times \sin A \times (1-\cos A)+(1-\cos A)^{2}\right]}{\left[(1-\cos A)(1+\cos A)-(1-\cos A)^{2}\right]} [/tex]

[tex]\dfrac{(1-\cos A)[1+\cos A+2 \sin A+1-\cos A]}{[1-\cos A][1+\cos A-1+\cos A]} [/tex]

[tex]\dfrac{[2+2 \sin A]}{[2 \times \cos A]}[/tex]

[tex]\dfrac{2(1+\sin A)}{2 \times \cos A}[/tex]

[tex]\dfrac{1+\cos A}{\sin A} [/tex]

Hence Proved.

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