Solve the following:
a) 4x 3= 2x + 7

b) 2x+6= 7x14

Answer:

A fraction equivalent to [tex]\frac{1}{2}[/tex] on the number line is [tex]\frac{3}{6}[/tex].

Drag the dot to [tex]\frac{3}{6}[/tex] on the number line.

Step-by-step explanation:

3 is half of 6. To check if this is correct multiply [tex]\frac{1}{2}[/tex] and 3.

[tex]\frac{1}{2}*3=\frac{3}{6}[/tex]

Hope this helps!

If not, I am sorry.

Answer:

Step-by-step explanation:

Solution

Total growth (2 weeks) = x + 8

Explanation

During the second week, the plant is already 8 inches tall. It adds x to its total growth. 8x is not the same thing.

Meaning of 8x

For plants, 8x could mean the amount of growth that took place in 8 weeks. x is the amount of growth that takes place in 1 week. You have to think that the growth (x)  for each week is the same

Answer:

11 .21 add the number together

Notice that the given sum is equivalent to

[tex]10 + 1 + \dfrac1{10} + \dfrac1{10^2} + \dfrac1{10^3} + \cdots \\\\ ~~~~~~~~~~~~ = 10 \left(1 + \dfrac1{10} + \dfrac1{10^2} + \dfrac1{10^3} + \dfrac1{10^4} + \cdots\right)[/tex]

or 10 times the infinite geometric series with ratio 1/10.

To compute the infinite sum, consider the [tex]n[/tex]-th partial sum

[tex]S_n = 1 + \dfrac1{10} + \dfrac1{10^2} + \cdots + \dfrac1{10^{n-1}}[/tex]

Multiply both sides by the ratio.

[tex]\dfrac1{10} S_n = \dfrac1{10} + \dfrac1{10^2} + \dfrac1{10^3} + \cdots + \dfrac1{10^n}[/tex]

Subtract this from [tex]S_n[/tex] to eliminate all but the outermost terms,

[tex]S_n - \dfrac1{10} S_n = 1 - \dfrac1{10^n} \implies S_n = \dfrac{10}9 \left(1 - \dfrac1{10^n}\right)[/tex]

As [tex]n\to\infty[/tex], the exponential term will decay to 0, leaving us with

[tex]1 + \dfrac1{10} + \dfrac1{10^2} + \cdots = \dfrac{10}9[/tex]

Then the value of the sum we want is

[tex]10\times\dfrac{10}9 = \boxed{\dfrac{100}9}[/tex]

Answer:

800

Step-by-step explanation:

I did it on the test

Answer:

800

Step-by-step explanation:

I just fifnished test

Step-by-step explanation:

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Answer:

y = 5x - 6

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = 5 and c = - 6 , then

y = 5x - 6 ← equation of line

The equation represents a linear function with a slope of 5 and a y-intercept of -6 is y = 5x - 6.

The equation of a linear function is typically written in the form "y = mx + b," where "m" represents the slope and "b" represents the y-intercept.

Given that the slope is 5 and the y-intercept is -6, the equation becomes:

y = 5x - 6

Here's the calculation:

The slope (m) is 5, and the y-intercept (b) is -6. Therefore, the equation becomes:

y = 5x - 6

This equation represents a linear function with a slope of 5 and a y-intercept of -6.

Hence the equation represents a linear function with a slope of 5 and a y-intercept of -6 is y = 5x - 6.

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Answer:

Step-by-step explanation:

When matching graph to inequality, the first things to look for are the nature of the boundary line (solid or dashed), and the direction of shading relative to the boundary line (above or below, left or right).

The boundary line of the solution set of an inequality will be solid if the line is included in the solution. That is, the inequality will include the "or equal to" case. The corresponding inequality symbols are ≤ or ≥.

The boundary line of the solution set will be dashed if the line is not included in the solution. The corresponding inequality symbols are < or >.

The shading will be above the boundary line if the solution set includes larger y-values than those on the boundary. This will be the case when the inequality is of the form y > ( ) or y ≥ ( ).

For inequalities of the form y < ( ) or y ≤ ( ), the shading will be below the boundary line.

Similarly, the shading for an inequality of the form x > ( ) will be right of the boundary line, where x-values are greater. For inequalities of the form x < ( ), the shading will be to the left of the boundary line.

In the given graph, both boundary lines are solid, so both inequalities will include the "or equal to" case. This eliminates choices A, B, D.

The shading is above the quadratic boundary line, and below the linear boundary line, so the inequalities can be expected to be of the forms ...

These forms match choice C:

Answer:

Graph A is correct.

Step-by-step explanation:

Graph A is the graph with the open circle and the arrow pointing to the right.

The true statement is h(2)=16.

The domain of a function is the set of values that we are allowed to plug into our function. The range of a function is the set of values that the function assumes.

Given:

domain of -3 ≤ x ≤ 11 and a range of 1 ≤ h(x) ≤ 25,

Also, h(8) = 19 and h(-2) = 2,

Now,

2=h(-2)< h(2)<h(8) =19

h(8)=19≠21

h(13)> h(8) =19

h(-3)< h(-2) =2  [1 ≤ h(x) ≤ 25]

Hence, h(2)=16

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[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: Temp = 77° F[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: f = \bigg (c \sdot \cfrac{9}{5} \bigg) + 32[/tex]

[ convert 25° C to °F ]

[tex]\qquad \tt \rightarrow \: \bigg (25 \sdot \cfrac{9}{5} \bigg) + 32[/tex]

[tex]\qquad \tt \rightarrow \: (5 \sdot9) + 32[/tex]

[tex]\qquad \tt \rightarrow \: 45 + 32[/tex]

[tex]\qquad \tt \rightarrow \: 77 \degree \: \: f[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

77

Step-by-step explanation:

took the quiz

Answer:

A - [tex]\sqrt{5}[/tex]

Step-by-step explanation:

[tex]\sqrt{15} = \sqrt{5} *\sqrt{3} \\\frac{\sqrt{5} *\sqrt{3}}{3*\sqrt{3}} = \frac{\sqrt{5}}{3}[/tex]

Answer: √5/3

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

[tex]\text{First I'd recommend using this little equation:}\\\text{m}=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{Substitute the values::}\\\text{m}=\dfrac{5-1}{3-1} \\\text{m}=\dfrac{4}{3}[/tex]

[tex]\rule{300}{1.7}[/tex]

[tex]\text{The gradient is:: }\dfrac{4}{3}[/tex]

Answer:

21

Step-by-step explanation:

a,a+2,..

4(a+2)=29+3a

4a+8=29+3a

4a-3a=29-8

a=21

Answer: (4)

Step-by-step explanation:

The first part has a closed hole at x=0 and an open hole at x=4, so it should be [tex]0 \leq x < 4[/tex].

This eliminates all the options except for (4).

The piecewise function that represents the graph will be f(x) = x + 2, 0 ≤ x < 4 and f(x) = x - 3, 4 ≤ x < 8. Then the correct option is D.

A function is an assertion, concept, or principle that establishes an association between two variables. Functions may be found throughout mathematics and are essential for the development of significant links.

A function that is based on a series of intervals is known as a specific goal. The absolute value serves as a frequent illustration. Other piecewise functions include the Boolean stepping, rectangle, and triangle functions.

The slope of the line is one. And the y-intercept is 2 and -3. Then the equation of the line is given as,

f(x) = x + 2, 0 ≤ x < 4

f(x) = x - 3, 4 ≤ x < 8

The piecewise function that represents the graph will be f(x) = x + 2, 0 ≤ x < 4 and f(x) = x - 3, 4 ≤ x < 8. Then the correct option is D.

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Answer:

3 months

Step-by-step explanation:

If two towns that are 32 km apart are 8 cm on a map. Then the scale factor will be 1 cm = 4 km.

Dilation is the process of increasing the size of an item without affecting its form. Depending on the scale factor, the object's size can be raised or lowered.

Two towns that are 32 km apart are 8 cm on a map.

Then the scale factor will be

8 cm = 32 km

1 cm = 4 km

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When using ANOVA procedures, the research hypothesis is: there is no significance difference within the mean values of the groups.

ANOVA procedure compares the mean values of different groups that are administered with treatments. The research hypothesis, such as the null hypothesis would be stated as: no significance difference in the mean values within the groups.

Thus, we can conclude that the research hypothesis when using the ANOVA procedures can be stated as a null hypothesis, which states that: there is no significance difference within the mean values of the groups.

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Answer:

quadratic with a common second difference of 4

Step-by-step explanation:

quadratic equations: Quadratic equations are the polynomial equations of degree 2 example - a[tex]x^2\\[/tex]+ b[tex]x[/tex] + c = 0.

                               [tex]\begin{array}{cc}x&y\\-2&8\\-1&2\\0&0\\1&2\\2&8\end{array}\right][/tex]

from the table it is clear that,

function is y = 2[tex]x^2\\[/tex]

so the function is not linear as the equation specifies.

formula to find second difference of a quadratic equation:

f(x + 2) - 2f(x + 1) + f(x)

therefore;

[tex]2(x+2)^2[/tex] - [tex]4(x+1)^2[/tex] + [tex]2x^2[/tex]

[tex]2(x^2 + 4x + 4) - 4(x^2 + 2x+ 1 ) + 2x^2[/tex]

[tex]2x^2 + 8x + 8 - 4x^2 - 8x - 4 + 2x^2[/tex]

[tex]4x^2 - 4x^2 + 8x - 8x +8 - 4[/tex]

4

therefore, the answer is quadratic with a common second difference of 4

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Answer:

Your answer is 68. Hope you got a big score!

Answer:

[tex] \frac{p}{38} [/tex]

The required quotient of a number p and 38 is 38/p, as of the given condition

In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication, and division,

here,
In the quesiton, we have to determine the quotient of a number p and 38.
So, divide 38 by p to determine the quotient.

= 38/p

Thus, the required quotient of a number p and 38 is 38/p.

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Answer:

-63

Step-by-step explanation:

3 - 6(12 - 1) = 3 - 6(11) = 3 - 66 = -63

Answer:

25 minutes

Step-by-step explanation:

they started at a quarter past 11, which is 11:15

they then played for 45 minutes, which would be until 12:00

you also know that they stopped playing at 10 minutes past 1, at 1:10.

before 1:10, they had been playing for 45 minutes, which means they started playing for the second time at 12:25.

all that's left is the time between 12:00 and 12:25, which is 25 minutes, so they spent 25 minutes stopping for a drink and a cookie.

Answer:

y=−1/2x−1

Step-by-step explanation:

I put it in slope intercept form as I assume that is what the question is asking.

Answer:

x-4y = 8

Step-by-step explanation:

The standard form for the equation of a line is Ax+By=C  where A is a positive integer and B and C are integers

First we need to find the slope

m = ( y2-y1)/(x2-x1)

m = (-3-1) / (-4-12)

     =-4/-16

    = 1/4

The point slope form is

y-1 = 1/4(x-12)

Multiply each side by 4

4(y-1 )= 4*1/4(x-12)

4(y-1) = x-12

4y -4 = x-12

Subtract 4y from each side

4y-4-4y = x-4y -12

-4 = x-4y -12

Add 12 to each side

-4+12 = x-4y -12+12

8 = x-4y

x-4y = 8

The standard form is x-4y = 8

A function assigns the values. The half life of the substance is 6.25 days.

A function assigns the value of each element of one set to the other specific element of another set.

Given the function for the substance as [tex]N= N_o e^{-kt}[/tex], therefore, the half life of the substance can be written as,

[tex]N= N_o e^{-kt}\\\\\dfrac{N}{N_o}= e^{-kt}[/tex]

Since we need to find the half life, therefore, the ratio of the initial mass and the mass after half-life will be 1/2.

[tex]\dfrac12= e^{-kt}\\\\\ln (0.5) = -kt[/tex]

Given the value of k is 0.1109, therefore,

[tex]\ln (0.5) = -kt\\\\\ln (0.5) = -(0.1109)t\\\\t = 6.25[/tex]

Hence, the half life of the substance is 6.25 days.

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The values of a and b are :

[tex]a = \sqrt{3} \\ \\ •\sqrt{3} b = - 1 \\ \\ b = \frac{ - 1}{ \sqrt{3} }. [/tex]

Answer:

Then the new point is (-6,-5)

Step-by-step explanation:

Answer:

[tex]\dfrac 5{13}[/tex]

Step-by-step explanation:

[tex]\sin \theta =\dfrac{\text{Perpendicular}}{\text{Hypotenuse}} = \dfrac{5}{\sqrt{5^2 +12^2}} = \dfrac 5{\sqrt{169}} = \dfrac 5{13}[/tex]

Answer: (x+z+y)(y+z)

Step-by-step explanation:

y(x+z)+z(x+y)+y^2+z^2

Factor out y and z from the expression

= y(x+z+y)+z(x+y+z)

Factor out x + z + y from the expression

= (x+z+y)(y+z)

Answer:

8t - 15

Explanation:

⇒ 3(t+5)+5(t−6)

distribute inside parenthesis

⇒ 3(t) + 3(5) + 5(t) + 5(-6)

multiply the variables

⇒ 3t + 15 + 5t - 30

collect like terms

⇒ 3t + 5t + 15 - 30

add/ subtract like terms

⇒ 8t - 15

Solution: 8t-15

Detailed explanation:

First the problem asks us to expand

[tex]\tt 3(t+5)=3\cdot t +3\cdot5=3t+15[/tex]

Similarly

[tex]\tt 5(t-6)=5\cdot t -5\cdot 6=5t-30[/tex]

Therefore

[tex]\tt 3t+15+5t-30[/tex]

Upon combining like terms

[tex]\tt 8t+15-30[/tex]

Upon doing this further

[tex]\tt 8t-15[/tex]