Quadrilateral ABCD is inscribed in this circle. What is the measure of angle C?

Eric spend 60 minutes for basketball and 35 minutes for volleyball.

An equation that has the highest degree of 1 is known as a linear equation. This means that no variable in a linear equation has an exponent more than 1. The graph of a linear equation always forms a straight line.

Here, let Eric plays basketball for x minutes.

          and volleyball for y minutes.

Total time spend on playing basketball and volleyball everyday = 95 minutes.

Duration of Basketball 25 minutes more than volleyball

Now, according to question,

          x + y = 95        ..........(i)

          x - 25 = y          ...........(ii)

On solving equation (i) and (ii), we get

        x + x - 25 = 95

           2x = 95 + 25

           2x = 120

            x = 120 / 2

            x = 60

put value of x in equation (ii), we get

        60 - 25 = y

          y = 35

Yes, it is possible and clearly described in above calculation.

Thus, Eric spend 60 minutes for basketball and 35 minutes for volleyball.

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Answer:

side ≈ 4.24= [tex]\frac{6}{\sqrt{2} }[/tex]

Step-by-step explanation:

sides a = b

[tex]6^{2} =a^{2} +a^{2}[/tex]

[tex]6^{2} =2a^{2}[/tex]

[tex]a^{2}= \frac{6^{2} }{2} =\frac{36}{2} =18[/tex]

[tex]a=\sqrt{18} =4.24=\sqrt{(9)(2)} =\frac{6}{\sqrt{2} }[/tex]

Hope this helps

Answer: Beans cause Nia to Fart!

Step-by-step explanation:

Mexican food usually contains beans, which beans are a known catalyst of flatulence. Beans induce farts and Nia does so! Farts usually stink, so an air freshener is needed.

Answer:

Answer:

48 cm²

Explanation:

The figure can be cut into 1 rectangle and 1 triangle.

Area of the figure:

⇒ area of rectangle + area of triangle

⇒ Length × Width  +  1/2 × Base × Height

⇒ 6 × 4  +  1/2 × 6 × 8

⇒ 24  +  24

⇒ 48

Therefore, area of figure is 48 cm².

Answer:

48 cm squared

Step-by-step explanation:

The given figure is composed of a rectangle (L=6 cm and W = 4 cm) and a right angled triangle { Base = (12- 4) = 8 cm, height = 6 cm. }

Area of the two figures is to be calculated separately and then added to get the required result.

Area of the rectangle = l × w

= 6 × 4

= 24 cm²

Area of the right triangle = ½ × base × height

= ½ × 8 × 6

= 24 cm²

Hence, area of the given figure = 24 + 24

= 48 cm squared.

Answer:

BEC = C. 50

BCD = A. 120

Step-by-step explanation:

BEC

65 + 65 = 130

180 - 130 = 50

BCD = 180 - 60 = 120

BEC is 50

Answer:

[tex]x = 172.75[/tex]

Hope this help!!!

Have a good day♡

Answer:

When x = 10, they will both be y = 60

(10, 60)

Step-by-step explanation:

2(10) + 40 = 60

4(10) + 20 = 60

Answer:

x = 10

Step-by-step explanation:

2 (10) +40 = 60

4(10) +20 = 60

The values that are part of the solution are x = -5 and x = -4.5

Number lines are lines that are used to represent the solution to inequalities.

From the given number line with he solution x > -4, this shows that all the solutions must be values that are greater than -4.

The values that are part of the solution are x = -5 and x = -4.5

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Answer:

28 feet

Step-by-step explanation:

Area of a rectangle is :

A = L × W

We are given A and a expression for L, so let's substitute :

448 = (2W-4) × W

Now we expand the left side :

2W²-4w = 448

Subtract 448 from both sides :

2W²-4W-448 = 0

Divide everything by 2 :

W²-2W-224 = 0

Now we factorise :

Find 2 numbers that multiply to give -224 and add to give -2 :

-16 and 14

Rewrite -2W with -16W and +14W :

W² - 16W + 14W -224 = 0

W(W-16)  +14(W-16) = 0

(W+14)(W-16) = 0

W = -14 ,  W = 16

Only take positive value since this is lengths :

W = 16

Now we substitute W into the expression to find L :

L = (2W -4)

L = 2(16) - 4

L = 32 - 4

L = 28

Units will be feet since it is a length

Hope this helped and have a good day

Answer:

[tex]7 469.8.56[/tex]

nossa nem sei como é bom saber se fala com a mãe e o pai do mundo e vc não tem mais nada pra comer e não tem como fazer a gente vai ficar muito tempo sem fazer a mãe dela não e vc como tá o trabalho rede de nada em casa e é só pra mim né não é fácil de fazer a mãe dela e a mãe dele tá bem né não é fácil de fazer o que vc quer que Deus quiser vai dar pra mim né e não tem como fazer d id da x não vou poder é o que eu te abençoe e ilumine e ilumine todos os dias entre?01029)

Answer:

Maybe    9     and 12   ?

Step-by-step explanation:

-6 + 9 = 3  

    then   3 + 9 = 12

           then 12 + 3 = 15      

                 each term is the sum of the two that are before it

Answer:

Step-by-step explanation:

we are essentially calculating:

4(1/4)^0 + 4(1/4)^1 + 4(1/4)^2 + ... + 4(1/4)^9

Formula: [tex]\frac{a(1-r^n)}{1-r}[/tex]

4(1-(1/4)^10)/ (1-1/4) approximates to 5.33

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: f(0) = -2[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: 2 {x}^{2} - 3y = 6[/tex]

[tex]\qquad \tt \rightarrow \: 3y + 6 = 2 {x}^{2} [/tex]

[tex]\qquad \tt \rightarrow \: 3y = 2 {x}^{2} - 6[/tex]

[tex]\qquad \tt \rightarrow \: y = \cfrac{2 {x}^{2} - 6 }{3} [/tex]

[tex]\qquad \tt \rightarrow \: y = \cfrac{2 {}^{} }{3} {x}^{2} - 2[/tex]

[ here, y can be replaced with f(x) because y is a function of x ]

[tex]\qquad \tt \rightarrow \: f(x) = \cfrac{2 {}^{} }{3} {x}^{2} - 2[/tex]

[tex] \large\textsf{Find f(0):} [/tex]

[tex]\qquad \tt \rightarrow \: f(0) = \cfrac{2 {}^{} }{3} {(0)}^{2} - 2[/tex]

[tex]\qquad \tt \rightarrow \: f(0) = 0 - 2[/tex]

[tex]\qquad \tt \rightarrow \: f(0) = - 2[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

We have y+2 = 0 and x - 2 = 0. The provided function has an x and y-intercept of -2 and +2, respectively. There is no vertical asymptote. Two is the horizontal asymptote.

A diagram depicting the relationship between two or more variables, each measured along with one of a pair of axes at right angles.

The y-intercept of a function is determined by the intersection of its graph with the y-axis. The value of y on the y-axis at which the considered function crosses it is called the y-intercept.

Assume the following equation: y = f (x)

We have x   =0- 2 and y+2 = 0,The x and y intercept of the given function is -2 and +2.

The vertical asymptote is none. The horizontal asymptote is 2.

Hence,we have y+2 = 0 and x - 2 = 0. The provided function has an x and y-intercept of -2 and +2, respectively. There is no vertical asymptote. Two is the horizontal asymptote.

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Answer:

2:45

Step-by-step explanation:

1 1/2 hour is 1 hour and 30 minutes.

If we add 30 minutes to 1:15, we get 1:45

if we add 1 hour to 1:45, we get 2:45, which is our answer.

Question 1

B. Set of whole numbers

Question 2

A. Set of real numbers

If the perimeter of the square is 4x then the domain of the function will be set of rational numbers and the domain of the function y=3x+8(3-x) is set of real numbers.

Given The perimeter of the square is f(x)=4x and the function is y=3x+8(3-x)

We will first solve the first part in which we have been given that the perimeter of the square is 4x and we have to find the domain of the function.

First option is set of rational numbers which is right for the function.

Second option is set of whole numbers which is not right as whole number involves 0 also and the side of the square is not equal to 0.

Third option is set of integers which is not right as integers involve negative number also and side of square cannot be negative.

Hence the domain is set of rational numbers.

Now we will solve the second part of the question

f(x)=3x+8(3-x)

we have not told about the range of the function so we can put any value  in the function and most appropriate option will be set of real numbers as real number involve positive , negative and decimal values also.

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Answer:

33 elements

Step-by-step explanation:

Set A has 59 elements. Set A and Set B share 26 elements.

This means that 26 out of the 59 elements in Set A are also in set B.

Therefore, to find the number of elements not in Set B, you need to subtract the common elements from the total amount of elements in Set A.

59 (total in Set A) - 26 (common in Set A) = 33 (unshared elements).

The statement about both functions that is true is:

The domain of a function is the set of values of input for which the function is valid.

The range is the dependent variable of a set of values for which the function is defined.

Given that:

f(x) = 4 - x

For function g(x) = -1 ×[tex]\mathbf{\sqrt{x-4}}[/tex]

Therefore, from the given options, the statement about both functions that is true is:

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Answer:

Both f(x) and g(x) include domain values of [4, ∞), and both functions decrease over the interval (4, ∞).

Step-by-step explanation:

I got it right on the test.

Answer:

11/200

Step-by-step explanation:

Convert the percentage to a fraction by placing the expression over

100

Percentage means 'out of 100

5.5

100

Convert the decimal number to a fraction by shifting the decimal point in both the numerator and denominator. Since there is

1

number to the right of the decimal point, move the decimal point

1

place to the right.

55

1000

Cancel the common factor of

55

and

1000

11/200

first one b 315, second d

Step-by-step explanation:

18*=3*+315

7*+4*=a*

Answer:

                                  [tex]f^{\prime}\left(x\right)\ =\ -\frac{65}{2}x^{\frac{11}{2}}\ +\frac{49}{2}x^{-\frac{9}{2}}[/tex]

or

                                  [tex]f^{\prime}\left(x\right)\ =\ -32.5x^{5.5}\ +\ 24.5x^{-4.5}[/tex]

Step-by-step explanation:

Rather than solving this question in a more complex method by directly using the product rule and quotient rule, it can first be considered to perform some algebraic manipulation (index laws) to simplify the expression before taking the derivative.

                                       [tex]\begin{large}\begin{array}{l}f\left(x\right)\ =\ -5x^6\ \sqrt{x}\ +\ \frac{-7}{x^3\ \sqrt{x}}\\\\f\left(x\right)\ =\ -5x^6\cdot x^{\frac{1}{2}}\ +\ \frac{-7}{x^3\cdot x^{\frac{1}{2}}}\\\\f\left(x\right)\ =\ -5x^{6\ +\ \frac{1}{2}}\ +\ \frac{-7}{x^{3\ +\ \frac{1}{2}}}\\\\f\left(x\right)\ =\ -5x^{\frac{13}{2}}\ +\ \frac{-7}{x^{\frac{7}{2}}}\\\\f\left(x\right)\ =\ -5x^{\frac{13}{2}}\ -7x^{-\frac{7}{2}}\end{array}[/tex]

Now, the derivative of the function can be calculated simply by only using the power rule, which yields

                   [tex]\begin{large}\begin{array}{l}f\left(x\right)\ =\ -5x^{\frac{13}{2}}\ -7x^{-\frac{7}{2}}\\\\f^{\prime}\left(x\right)\ =\ \left(-5\right)\left(\frac{13}{2}\right)\left(x^{\frac{13}{2}\ -\ 1}\right)\ -\ \left(7\right)\left(-\frac{7}{2}\right)\left(x^{-\frac{7}{2}\ -\ 1}\right)\\\\f^{\prime}\left(x\right)\ =\ -\frac{65}{2}x^{\frac{11}{2}}\ +\frac{49}{2}x^{-\frac{9}{2}}\\\\f^{\prime}\left(x\right)\ =\ -32.5x^{5.5}\ +\ 24.5x^{-4.5}\end{array}\\\end{large}[/tex]

Answer:

Using the formula multiplicity, we find that the equation of the function will be [tex]f(x)=-(x+6)^{3} (x-2)^{4}[/tex]. The graph is in the attachment.

Step-by-step explanation:

Concept: Given that for -6, multiplicity is 3 and for 2 multiplicity is 4.

So, the equation of multiplicity is represented as:

[tex]f(x)=a(x-root)^{mutliplicity}[/tex]

This gives the following function

[tex]f(x)=a(x+6)^{3} (x-2)^{4}[/tex]

The equation has a negative leading coefficient.

This means that, the value of a is less than 0 i.e. a < 0

Assume any value of a (say a = -1), the equation becomes

[tex]f(x)=-(x+6)^{3} (x-2)^{4}[/tex]

The graph is in the attachment.

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Answer:

C

Step-by-step explanation:

trust bro

The final answer of the Inventory is $3540.

The term inventory refers to the raw materials used in production as well as the goods produced that are available for sale.

FIFO means first in, first out. It means that it is the first purchased inventory that is the first to be sold

Ending inventory comprises of goods bought in May, September and November

cost of the ending inventory :

(4 x $130) + (12 x $135) + (10 x$140) = $3540

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The clock was skipping 3 seconds every 30 minutes from Friday noon to Monday 6 pm.

The clock was still accurate by Friday noon. The clock was late by 468 seconds by Monday, 6 pm.

To solve the problem, we must:

Know how many 30-minutes have passed during the time period.

1 day = 24 hours

1 hour = 60 minutes = 2 × (30 minutes)

1 day = 24 hours × 2 × (30 minutes)

1 day = 48 × (30 minutes)

Thus, there are 48, 30-minutes in a day. On Friday, however, we start counting at noon, which is half of the day. Moreover, on Monday, the mark is only up to 6 pm, which is three-fourths of the day.

Friday = 48 × [tex]\frac{1}{2}[/tex] = 24

Saturday = 48

Sunday = 48

Monday = 48 × [tex]\frac{3}{4}[/tex] = 36

TOTAL = 24 + 48 + 48 + 36 = 156

Therefore, the total number of 30-minutes that have passed is 156. There were 156, 30-minutes that passed during the time period.

Divide the number of total seconds late by the number of 30-minutes passed.

That is, the number of total seconds late= 468 seconds ÷ 156

= 3 seconds  

Therefore, the clock was skipping 3 seconds every 30 minutes from Friday noon to Monday 6 pm.

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Answer:

390/1000

This is the answer and hope it helps