The only value of x where f'(x) = 0 is x = 0.
Let's find all values of x where the derivative of f(x) = [tex]arcsin(e^(2x) – 2x)[/tex] is equal to 0.
Step 1: Find the derivative f'(x) using the chain rule.
For this, we'll need to differentiate [tex]arcsin(u)[/tex] with respect to u, which is [tex](1/√(1-u^2))[/tex], and then multiply by the derivative of u [tex](e^(2x) – 2x)[/tex]with respect to x. So, f'(x) = [tex](1/√(1-(e^(2x) – 2x)^2)) * d(e^(2x) – 2x)/dx[/tex]
Step 2: Find the derivative of e^(2x) – 2x with respect to x. Using the chain rule and the derivative of [tex]e^u: d(e^(2x) – 2x)/dx = 2e^(2x) – 2[/tex]
Step 3: Combine the derivatives. f'(x) =[tex](1/√(1-(e^(2x) – 2x)^2)) * (2e^(2x) – 2)[/tex]
Step 4: Set f'(x) equal to 0 and solve for x. [tex](1/√(1-(e^(2x) – 2x)^2)) * (2e^(2x) – 2) = 0[/tex]
Since the first part of the product [tex](1/√(1-(e^(2x) – 2x)^2))[/tex] is never 0, we can focus on the second part: [tex]2e^(2x) – 2 = 0[/tex]
Step 5: Solve for x. [tex]2e^(2x) = 2 e^(2x) = 1[/tex]
The only way this is true is when 2x = 0, since [tex]e^0 = 1: 2x = 0 x = 0[/tex]
So, the only value of x where f'(x) = 0 is x = 0.
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Use an integer to describe the situations.
6 meters above sea level ___
sea level ___
Answer:
An integer to describe 6 meters above the sea level would be meters.
As per the question statement, We are supposed to use an integer to describe the following situation "6 meters above sea level".
We assume that sea level is the datum line and anything above that would be positive and below that would be negative.
So 6 meters above the sea level can be described as .
Integers: Set of whole number containing both positive and negative values of it.
PLS MARK BRAINLIEST
Step-by-step explanation:
The following table gives the average monthly exchange rate between the us dollar and the australian dollar for 2018. it shows that 1 us dollar was equivalent to 1.256 australian dollars in january 2018. a. evaluate the components of time series of average monthly exchange rate b. smooth out the patterns that includes everything the model learned so far based on history record of the exchange rate. the forecast in the first month was 1.235. you are free to choose the suitable coefficient to conduct the model. explain the decision on the coefficient c. would you apply the method in part (b) to forecast the monthly exchange rate for 2020? please suggest and conduct all possible techniques that may apply to predict monthly foreign exchange rate in year 3. d. compare the forecasting results of different techniques applied in part (c). which ones yield more accurate results?
The average monthly exchange rate between the us dollar and the Australian dollar for 2018
A. The components of a time series of average monthly exchange rates include trend, seasonality, cyclical fluctuations, and random noise. The trend represents the long-term movement of the exchange rate, seasonality represents repeating patterns within a fixed period, cyclical fluctuations are changes due to economic cycles, and random noise consists of unpredictable fluctuations.
B. To smooth out the patterns that include everything the model learned, you can apply an exponential smoothing method with a chosen smoothing coefficient (alpha). A suitable coefficient could be 0.2, representing a balance between giving weight to recent data and considering the historical pattern. The decision on the coefficient depends on the specific characteristics of the data and the desired degree of smoothing.
C. To forecast the monthly exchange rate for 2020, you can apply various techniques, such as moving average, exponential smoothing, autoregressive integrated moving average (ARIMA), and machine learning-based methods. Each method has its advantages and limitations, and it's important to analyze the performance of each technique on historical data to choose the most appropriate method for forecasting.
D. Comparing the forecasting results of different techniques applied in part (C) requires measuring their accuracy using metrics like mean absolute error (MAE), root mean square error (RMSE), and mean absolute percentage error (MAPE). The technique with the lowest error values would be considered more accurate in predicting the monthly exchange rates. It is crucial to consider the data characteristics and the goals of the forecast when deciding on the most suitable technique.
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Huang buys 3 shirts that each cost the same amount a pair of pants that cost 12$ and pays with a 100$ bill which expressesion represents the amount of change huang receive
Answer: 64$
Step-by-step explanation:
A cylinder and a cone have the same volume. The cylinder has radius x
and height y
. The cone has radius 2x
. Find the height of the cone in terms of y
.
The height of the cone in terms of y is h = y / 4.
How to find the volume of a cone and a cylinder?The cylinder and the cone have the same volume. The cylinder has radius x and height y. The cone has radius 2x.
Therefore,
volume of a cylinder = πr²h
where
r = radiush = heightVolume of a cone = 1 / 3 πr²h
where
r = radiush = heightTherefore,
πr²h = 1 / 3 πr²h
πx²y = 1 / 3 π (2x)²h
πx²y = 1 / 3 π 4x² h
multiply both sides by 3
πx²y = π 4x² h
divide both sides by π 4x²
Hence,
h = πx²y / π 4x²
h = y / 4
Therefore, the height of the cone is h = y / 4.
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Can someone help me ASAP please? It’s due tomorrow. Show work please!! I will give brainliest if it’s correct and has work.
Answer:
Step-by-step explanation:
There are 12 possible cards you can choose.
There are 3 possible results for the spinner.
There are 2 possible results for the coin toss.
When doing all 3 events:
Total possibilities [tex]=12\times 3 \times 2=72.[/tex]
SOLUTION: 72
Let g(x.y)= 15x2 +2y2. Compute g(3,3), g(0,-2), and g(a,b). g(3,3)= _____
The function g(x, y) is defined as 15x^2 + 2y^2. To compute g(3,3), g(0,-2), and g(a,b), we substitute the given values into the function.
To find g(3,3), we substitute x = 3 and y = 3 into the function g(x, y) = 15x^2 + 2y^2:
g(3,3) = 15(3)^2 + 2(3)^2
g(3,3) = 135 + 18
g(3,3) = 153
To find g(0,-2), we substitute x = 0 and y = -2 into the function g(x, y) = 15x^2 + 2y^2:
g(0,-2) = 15(0)^2 + 2(-2)^2
g(0,-2) = 0 + 8
g(0,-2) = 8
To find g(a,b), we substitute x = a and y = b into the function g(x, y) = 15x^2 + 2y^2:
g(a,b) = 15a^2 + 2b^2
Note: The function g(a,b) cannot be simplified further without knowing the values of a and b.
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90. lim (In V 4x2 + 6 - In x) = A. In 2 B. 0 C. 2 D. - 91. The horizontal asymptote(s) of the function f(x) = 37€* is (are) = = e+ A. y = 0 B. y = e C. x = 0 D. none . = 0. 109. If a, n > 0, with a > 1, then lim 2+ Inc A. True B. False
For the first question, to get the limit of the function lim (In V 4x2 + 6 - In x), we can use the property of logarithms that says ln(a) - ln(b) = ln(a/b). Applying this property to the given function, we get ln[(4x^2 + 6)/x]. Now we can simplify the expression by dividing both the numerator and the denominator by x. So we get ln(4x + 6/x), which can be rewritten as ln(4 + 6/x). Now we can take the limit as x approaches infinity. As x gets larger and larger, the 6/x term becomes smaller and smaller and approaches zero. So ln(4 + 6/x) approaches ln(4), and the final answer is A. In 2.
For the second question, to get the horizontal asymptote(s) of the function f(x) = 37€*, we can take the limit as x approaches infinity. As x gets larger and larger, the exponential term €* becomes larger and larger, approaching infinity. So the function approaches 37 times infinity, which is infinity. Therefore, there is no horizontal asymptote and the answer is D. none.
For the third question, the statement is false. The limit as x approaches infinity of 2^(ln(a)/ln(x)) is equal to infinity if a > 1 and is equal to zero if 0 < a < 1.
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EXAMPLE 1 A spring with a mass of 6 kg has a natural length of 0.3 m. A force of 38.4 N is required to maintain it stretched to a length of 0.7 m. If the spring is stretched to a length of 0.7 m and then released with initial velocity 0, find the position of the mass at time t. SOLUTION From Hooke's Law, the force required to stretch the spring is k(0.4) = 38.4 so k = 38.4/0.4 = 96. Using this value of the spring constant k, together with m = 6, we have d²x 6 = 0. + dt2 As in the earlier general discussion, the solution of this equation is X(t) = ( cos(4t) + C2 sin(4t). We are given the initial condition that x(0) = 0.4. But, from the previous equation, x(0) = cz. Therefore cn = . Differentiating, we get x'(t) = -4c sin(4t) + 4c2 cos(4t). Since the initial velocity is given as x'(O) = 0, we have cz = 0 and so the solution is = x(t) =
The equation given in the solution is X(t) = (cos(4t) + C2sin(4t)). This equation represents the position of the mass at time t after the spring has been released with an initial velocity of 0. The terms "spring" and "stretch" indicate that Hooke's Law is being used to determine the spring constant k.
The term "velocity" is used to describe the initial velocity of the mass, which is given as 0. The position of the mass at time t is determined by the value of X(t), which is a function of time. Therefore, the position of the mass at any given time can be found by plugging in the value of t into the equation X(t) = (cos(4t) + C2sin(4t)).
Hi! Based on the information provided, you have a spring with a mass of 6 kg and a natural length of 0.3 m. A force of 38.4 N is required to stretch it to 0.7 m. The spring constant, k, is determined to be 96. The spring is then stretched to 0.7 m and released with an initial velocity of 0. To find the position of the mass at time t, you can use the equation:
x(t) = C1 * cos(4t) + C2 * sin(4t)
Given the initial condition x(0) = 0.4, we find that C1 = 0.4. The initial velocity x'(0) is 0, leading to the conclusion that C2 = 0. Therefore, the equation for the position of the mass at time t is:
x(t) = 0.4 * cos(4t)
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There are 90 children in year 6 at woodland junior school
they are split into three classes
class
number n class
27
6m
6p
33
6t
30
each child chose football or netball or hockey.
in 6m, 13 children chose hockey.
the rest of the class were split equally between football and netball.
in 6p, 9 children chose netball
twice as many children chose football as chose hockey
in 6t the ratio of children who chose
football to netball to hockey was 1:2:3
complete this table
class
number in class
football
netball
hockey
6м
27
13
6p
33
6t
30
In Year 6 at Woodland Junior School, there are 90 children split into three classes of 14, 24, and 12 on the basis of there selection of sports. In 6M, 14 not chose hockey, and the rest of the class was split equally between football and netball. In 6P, 24 not chose netball, 16 chose football, and 8 choose hockey In 6T, the ratio of football to netball to hockey was 1:2:3. The completed table is shown.
To complete the table, we need to distribute the remaining children who did not choose their sport in each class. Here's how we can calculate it
In 6M, the number of children who did not choose hockey is 27 - 13 = 14.
Since the rest of the class was split equally between football and netball, each of these two sports will have 14/2 = 7 children.
In 6P, the number of children who did not choose netball is 33 - 9 = 24.
Since twice as many children chose football as chose hockey, we can write the number of footballers as 2x, and the number of hockey players as x. Then we have 2x + x + 9 = 33, which gives x = 8. Therefore, we have 16 children who chose football, and 8 children who chose hockey. The number of children who did not choose any of these two sports is 33 - 16 - 8 - 9 = 0.
In 6T, the ratio of children who chose football to netball to hockey was 1:2:3. Let's call the number of children who chose netball as 2x, and the number of children who chose hockey as 3x. Then we have x + 2x + 3x = 30, which gives x = 6. Therefore, we have 6 children who chose football, 12 children who chose netball, and 18 children who chose hockey.
Thus, the completed table is shown.
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A brick wall be shaped like a rectangular prism.the wall needs to be 3 feet tall, and the builder have enough bricks for the wall to have a volumn of 330 cubic feet.
we need to find two numbers whose product is 110. Possible combinations include L = 10 feet and W = 11 feet or L = 11 feet and W = 10 feet. Therefore, the dimensions of the brick wall can be either 10 feet by 11 feet or 11 feet by 10 feet.
A brick wall can be shaped like a rectangular prism, and in this case, the wall needs to be 3 feet tall. With the builder having enough bricks for the wall to have a volume of 330 cubic feet, we can calculate the area of the base of the wall.
To find the base area, we can use the formula for the volume of a rectangular prism: Volume = Base Area × Height. In this situation, we know the volume (330 cubic feet) and the height (3 feet), so we can solve for the base area.
330 cubic feet = Base Area × 3 feet
Dividing both sides of the equation by 3, we get:
Base Area = 110 square feet
So, the base area of the brick wall that is shaped like a rectangular prism with a height of 3 feet and a volume of 330 cubic feet will be 110 square feet.
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A plane leaves Singapore airport at 07:45 to fly to Sydney. The plane flies at an average speed of 757.2 km/h. The distance from Singapore to Sydney is 6310 km. The time in Sydney is 2 hours ahead of Singapore time. Calculate the local time when the plane arrives in Sydney. Give your answer in the form hours:minutes using the 24-hour clock.
The local time in Sydney when the plane arrives will be 18:58, or 6:58 PM on a 24-hour clock.
How to find arrival time for the plane?The time difference between Speed and Sydney is 2 hours, and the plane will take some time to fly from Singapore to Sydney at an Speed of 757.2 km/h over a distance of 6310 km.
The time it takes the plane to fly from Speed to Sydney can be calculated as:
time = distance / Speed= 6310 km / 757.2 km/h = 8.33Speed
So the plane will take 8.33 hours to fly from Singapore toSpeed
Now we need to add the 2-hour time difference between Singapore and Sydney to determine the local time in Sydney when the plane arrives.
07:45 (Singapore time) + 8.33 hours (flight time) + 2 hours (time difference) = 18:58
Therefore, the local time in Sydney when the plane arrives will be 18:58, or 6:58 PM on a 24-hour clock.
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Find the area of the regular polygon with the given apothem a and side length s.
pentagon, a = 10. 4 cm, s = 15. 1 cm
The area of the regular pentagon is approximately 392.2 square centimeters.
The area of a regular polygon can be calculated using the formula:
A = (1/2) * apothem * perimeter
where perimeter = number of sides * side length.
For a pentagon with side length s = 15.1 cm, the perimeter is:
perimeter = 5 * 15.1 = 75.5 cm
The apothem is a = 10.4 cm.
Using the formula, we get:
A = (1/2) * 10.4 * 75.5
A = 392.2 cm^2
Therefore, the area of the regular pentagon is approximately 392.2 square centimeters.
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Clue 1: The R stamps total 24 cents. R1 + R2 + R3 = 24 Clue 2: The R stamps with animals total 16 cents. R1 + R2 = 16 Combining this with Clue 1, we know R3 = 8 Clue 3: The stamps with animals total 20 cents. R1+ Combining this with Clue 2, we know S2 = 4 Clue 4: The stamps with two animals total 13 cents. S2 + R2 = Combining this with what we learned from Clue 3, we know R2 = +72 = 22 Clue 5: The two stamps with a person total 22 cents. Combing this with what we learned from Clue 2, we know I? Clue 6: The triangle stamps total 24 cents. I+ Combining this with what we learned from Clue 5, we know +52 = 20 Clue 7: The stamps with mechanical devices total 20 cents. 71+ R3 51 Combining this with what we learned from Clue 2 and Clue 6. we know Sl SA The S stamps total 11 cents. S1 + $2+ Combining this with what we learned from Clue 3 and Clue 7, we know 5
Using the combine clues method:
[tex]R_1=7\\\\R_2=9\\\\R_3=8\\\\S_1=2\\\\S_2=4\\\\S_3=5\\\\T_1=10\\\\T_2=14[/tex]
How to combine clues?Certain items that must be worn, used, or accessed in order to access particular clues. The maximum skill level needed to solve each master clue is shown.
Clue 1: [tex]R_1 + R_2 + R_3 = 24[/tex]
Clue 2: [tex]R_1 + R_2 =16[/tex]
Since, [tex]R_1 + R_2 + R_3 = 24[/tex] (from clue 1)
[tex]R_1 + R_2 + R_3 = 24\\\\16 + R_3 = 24[/tex]
Subtract both the sides by 16,
[tex]R_3=8[/tex]
Clue 3:
We need to find the blank [tex]R_1 +[/tex] __ [tex]+S_2=20[/tex] and [tex]S_2=4[/tex]
Since, [tex]R_1 + R_2 = 16[/tex] (from clue 2)
So,
[tex]R_1 + R_2 + S_2 = 20\\\\16 + S_2 = 20[/tex]
Subtract 16 from both sides.
[tex]16 + S_2 - 16 = 20 -16\\\\S_2 = 4[/tex]
So,
[tex]R_1 + R_2 + S_2 = 20[/tex]
Clue 4:
We need to find the blank [tex]R_2[/tex] = __
[tex]S_2 + R_2 = 13[/tex]
Since, [tex]S_2 = 4[/tex]
[tex]S_2 + R_2 = 13\\\\4 + R_2 = 13[/tex]
Subtract 4 from both sides.
[tex]R_2 = 9[/tex]
So, [tex]R_2 = 9[/tex]
Clue 5:
We need to find the blank ___ [tex]+ T_2 = 22[/tex] and [tex]T_2=[/tex] ___
[tex]R_3 + T_2 = 22[/tex]
Since, [tex]R_3 =8[/tex] (from the Clue 2)
[tex]R_3 + T_2 = 22[/tex]
[tex]8 + T_2 = 22[/tex]
Subtract both the sides by 8,
[tex]T_2 = 14[/tex]
So, [tex]R_3 + T_2 = 22[/tex]
Clue 6:
We need to find the blank [tex]T_1 +[/tex] ___ = 24 and ___ = 10
Since, [tex]T_1 + T_2 = 24[/tex] (from the Clue 5)
[tex]T_1 + 14 = 24[/tex]
Subtract both the sides by 14,
[tex]T_1 = 10[/tex]
Clue 7:
We need to find the value of [tex]S_1[/tex],
Given [tex]T_1 + R_3 + S_1 =20[/tex]
Since, [tex]T_1=10[/tex] and [tex]R_3=8[/tex]
[tex]10+ 8 + S_1 = 20\\\\18 + S_1 = 20[/tex]
Subtract both the sides by 18,
so, [tex]S_1=2[/tex]
Combining this with what we learned from Clue 2 and Clue 6, we know
[tex]S_1=2[/tex]
Now, we need to find the blank, [tex]S_1 + S_2 +[/tex] ___ = 11
Combining this with what we learned from Clue 3 and Clue 7, we know:
___ = 5
[tex]S_1 + S_2 + S_3 = 11\\\\2 + 4 + S_3 = 11\\\\6 + S_3 = 11[/tex]
Subtract both the sides by 6,
[tex]S_3 = 5[/tex]
For [tex]R_1[/tex]
Since,
[tex]R_1 + R_2 + R_3 = 24\\\\R_1 + 9 + 8 = 24\\\\R_1 + 17 = 24[/tex]
Subtract both the sides by 17,
[tex]R_1 = 17[/tex]
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On the first day it was posted online, a music video got 1880 views. The number of views that the video got each day increased by 25% per day. How many total views did the video get over the course of the first 16 days, to the nearest whole number?
Answer:
The answer to your problem is, 259,644
Step-by-step explanation:
an = 1880 ( it 25% [tex])^{t}[/tex]
= 1880 x (1.25[tex])^{t}[/tex]
ai = 1880, r will equal 1.25
Sn = [tex]\frac{aill-r^{4} }{l = r}[/tex]
[tex]S_{16}[/tex] = [tex]\frac{1880(l-1.25^{16}) }{l - 1.25}[/tex]
= 259,644
Thus the answer to your problem is, 259,644
The first steps in writing f(x) = 4x2 48x 10 in vertex form are shown. f(x) = 4(x2 12x) 10 (twelve-halves) squared = 36 what is the function written in vertex form? f(x) = 4(x 6)2 10 f(x) = 4(x 6)2 – 26 f(x) = 4(x 6)2 – 134 f(x) = 4(x 6)2 154
The function in vertex form is f(x) = 4(x - 6)² - 26.
How to write f(x) in vertex form?The function in vertex form is f(x) = 4(x - 6)² - 26.
To get to this form, the first step is to factor out the coefficient of x², which is 4:
f(x) = 4(x² - 12x) + 10
Next, complete the square by adding and subtracting (12/2)² = 36 inside the parenthesis:
f(x) = 4(x² - 12x + 36 - 36) + 10
Simplify the expression inside the parenthesis and combine like terms:
f(x) = 4((x - 6)² - 36) + 10
f(x) = 4(x - 6)² - 134
Therefore, the function in vertex form is f(x) = 4(x - 6)² - 26.
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Use the pythagorean Theorem to find the length of a right triangles hypotenuse. The longer sides are 9 cm and 12 cm long
The length of the hypotenuse of the right triangle is 15 cm.
The Pythagorean Theorem states that in a right triangle, the sum of the squares of the two shorter sides is equal to the square of the hypotenuse. Using this formula, we can calculate the length of the hypotenuse of a right triangle.
Given that the longer sides of the right triangle are 9 cm and 12 cm long, we can assume that one of these sides is the shorter side and the other is the longer side. Let's assume that the shorter side is 9 cm long and the longer side is 12 cm long.
Using the Pythagorean Theorem, we can calculate the length of the hypotenuse as follows:
Hypotenuse² = Shorter side² + Longer side²
Hypotenuse² = 9² + 12²
Hypotenuse² = 81 + 144
Hypotenuse² = 225
Taking the square root of both sides, we get:
Hypotenuse = √225
Hypotenuse = 15
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If Juan does not read any books before day 4 and he starts reading at the same
rate as Patti for the rest of the month, how many books will he have read by
day 12?
A. 5
B. 10
C. 15
D. 20
If Juan does not read any books before day 4 and he starts reading at the same rate as Patti for the rest of the month, he would have read 6 books by day 12. The correct option is A.
If Juan does not read any books before day 4, it means he has missed out on the opportunity to read for the first three days. Assuming Patti and Juan have been reading at the same rate since day 4, we can calculate the total number of books they would have read by day 12.
Patti reads one book per day, so by day 12, she would have read a total of 9 books (from day 4 to day 12). If Juan starts reading at the same rate as Patti from day 4, he would also have read 9 books by day 12.
However, we have to account for the fact that Juan did not read any books before day 4. This means that he missed out on the opportunity to read 3 books (one book per day for the first three days). Therefore, by day 12, Juan would have read a total of 6 books (3 books missed + 3 books read from day 4 to day 12).
Therefore, the answer is A. Juan would have read 5 books less than Patti by day 12, since Patti would have read a total of 9 books and Juan would have only read 6.
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The value of the integral ∫ dx/√(1-2x^2) is
So the value of the integral ∫ dx/√(1-2x^2) over the interval [-1/√2, 1/√2] is (1/√2)π.
The value of the integral ∫ dx/√(1-2x^2) is given by:
∫ (1/√(1-2x^2)) dx = (1/2) * arcsin(√2 * x) + C
where C is the constant of integration.
The value of the integral ∫ dx/√(1-2x^2) is equal to the integral of the function 1/√(1-2x^2) with respect to x. This is an example of an integral that requires a trigonometric substitution to evaluate. Specifically, we can let x = sin(θ)/√2 and dx = cos(θ)/√2 dθ. Substituting these expressions into the integral yields:
∫ dx/√(1-2x^2) = ∫ (cos(θ)/√2) / √(1-2(sin(θ)/√2)^2) dθ
Simplifying the denominator gives:
√(1-2(sin(θ)/√2)^2) = √(1 - sin^2(θ)) = cos(θ)
Substituting this expression into the integral gives:
∫ dx/√(1-2x^2) = ∫ (cos(θ)/√2) / cos(θ) dθ = ∫ dθ/√2 = (1/√2)θ + C
To find the value of the integral, we need to substitute back in for x and evaluate at the limits of integration. If we are integrating over the interval [-1/√2, 1/√2], then:
(1/√2)θ evaluated from -π/4 to π/4 gives:
(1/√2)(π/4 + π/4) - (1/√2)(-π/4 - π/4) = (1/√2)π
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Translate each problem into a mathematical equation.
1. The price of 32'' LED television is P15,500 less than twice the price of the
old model. If it cost P29,078. 00 to buy a new 32'' LED television, what is
the price of the old model?
2. The perimeter of the rectangle is 96 when the length of a rectangle is
twice the width. What are the dimensions of therectangle?
The price of the old model is given by $22.289 and dimensions of the rectangle by 16units and 32 units.
Two dimensions make up a rectangle: the length and, perpendicular to that, the breadth. A triangle's or an oval's interior likewise has two dimensions. Despite the fact that we don't consider them to have "length" or "height," they do span a territory that is expansive in more than one way.
A circle can be measured in any direction. Why do we just consider it to be two dimensional? Because only one direction—the direction perpendicular to the first measurement—can be used to make a second measurement, for a total of two directions.
Let us assume that, price of the old model is Px .
so,
→ Price of 32" LED television = P(2x - 15.500)
A/q,
→ (2x - 15.500) = 29.078
→ 2x = 29.078 + 15.500
→ 2x = 44.578
→ x = $22.289
Therefore, price of the old model is $22.289.
Let us assume that, width of the rectangle is x unit.
so,
→ Length = twice of width = 2x = 2x unit .
then,
→ Perimeter = 2(Length + width)
A/q,
→ 2(2x + x) = 96
→ 3x = 48
→ x = 16 unit .
therefore,
Width of rectangle = x = 16 units .
Length of rectangle = 2x = 32 units.
Hence, the dimensions of the rectangle are 16units and 32 units.
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The price of the old televison is P22,289
The dimensions of the rectangle are 16 and 32
Translating word problems to equationsWe have to read the problem carefully so as to be able to know how to translate the problem effectively and that is what we are going to do below.
We know that;
Let the price of the old 32'' LED television be x
Now;
29,078. 00 = 2x - 15,500
29,078. 00 + 15,500 = 2x
x = 29,078. 00 + 15,500 /2
x = P22,289
ii) Given that;
l = 2w
Perimeter = 2(l +w)
P = 2(2w + w)
P = 2(3w)
P = 6w
w = 96/6
w = 16
Then l = 2(w) = 32
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100 points
i can't think of a good question, someone give me one about sports or something interesting
Answer:
Who is the current world number one in men’s tennis?
What is the name of the sport that combines skiing and shooting?
How many countries are in the European Union?
What is the largest animal that ever lived on Earth?
What is the most spoken language in the world?
Step-by-step explanation:
is that ok?
write your own word problem that can be solved using equivalent ratios.
solve your problem
Word problem: The ratio of the number of people that attended Michael party to the number of people that attended Joshua's party is 5: 25
How to determine the expressionFirst, we need to know that equivalent ratios are those ratios that can usually be simplified to a similar value.
Also, algebraic expressions are defined as expressions that are composed of terms, variables, coefficients, terms, constants and factors.
These expressions are also made up of arithmetic operations such as addition, multiplication, subtraction, bracket, parentheses, etc
From the information given,
The word problem is;
The ratio of the number of people that attended Michael party to the number of people that attended Joshua's party is 5: 25
This is represented as;
5/25
Divide the values
1/5
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This diagram shows an equilateral triangle and three lines, p, q, and r, that meet at the
triangle's center, T.
Select all of the transformations that map the triangle onto itself.
reflection across line q followed by 90° clockwise rotation about point T
reflection across line p followed by 240 clockwise rotation about point T
reflection across liner
270 clockwise rotation about point T
120 counterclockwise rotation about point 7
180 counterclockwise rotation about point 7 followed by reflection across
sine q
Answer:
-Reflection across line p followed by 240 clockwise rotation about point T.
-Reflection across line r.
-120 counterclockwise rotation about point T.
Step-by-step explanation:
All these transformations map the triangle onto itself.
The diameter of a sphere measures 10. 4 inches. What is the surface area of the sphere?
The Surface Area of the sphere is approximately 339.79 square inches.
The surface area of a sphere is given by the formula:
surface area= [tex]4\pi r^{2}[/tex]
where r is the radius of the sphere.
The diameter of the sphere measures 10.4 inches, hence the radius can be calculated as:
r=10.4/2=5.2inches
Hence, the surface area can be calculated as by substituting r=5.2 inches
Therefore, surface area of the sphere is:
Surface Area = [tex]4\pi (5.2)^{2}[/tex]=[tex]4\pi (27.04)[/tex]= 108.16[tex]\pi[/tex] square inches.
So, the Surface Area of the sphere is approximately 339.79 square inches(if we use [tex]\pi[/tex]=3.14 as an approximation)
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The areas of two triangles are 50 cm2 and 98 cm2. what is the ratio of their perimeters?
a ) 25/49
b ) 50/98
c ) 625/2401
d ) 5/7
e ) 2500/9604
The ratio of the perimeters is 14/5, which simplifies to 70/25, which reduces to 14/5. So the answer is (d) 5/7.
Let's use the fact that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding side lengths. If we let the corresponding side lengths be a and b, then we have:
(area of first triangle)/(area of second triangle) = (a^2)/(b^2)
We are given that the areas of the two triangles are 50 cm^2 and 98 cm^2, respectively. Let's call the side lengths of the first triangle a1, a2, and a3, and the side lengths of the second triangle b1, b2, and b3. Then we have:
(50)/(98) = (a1a2)/(b1b2)
We don't know the actual values of a1, a2, b1, and b2, but we can find the ratio of their perimeters by adding up the side lengths of each triangle. Let's call the perimeters of the first and second triangles P1 and P2, respectively. Then we have:
P1 = a1 + a2 + a3
P2 = b1 + b2 + b3
Dividing P1 by P2, we get:
P1/P2 = (a1 + a2 + a3)/(b1 + b2 + b3)
We can rewrite the ratios of the side lengths using the equation we found earlier:
P1/P2 = [(a1a2)/(b1b2)]*[(a1 + a2 + a3)/(a1 + a2 + a3)]
P1/P2 = [(a1a2)/(b1b2)]*1
P1/P2 = (a1a2)/(b1b2)
We still don't know the values of a1, a2, b1, and b2, but we can eliminate them by using the equation we found earlier:
(50)/(98) = (a1a2)/(b1b2)
Simplifying this expression, we get:
(a1/a2) = sqrt((98/50)*(b1/b2))
We can use this to substitute for one of the ratios of side lengths in the equation for P1/P2:
P1/P2 = [(a1a2)/(b1b2)]*[(a1 + a2 + a3)/(a1 + a2 + a3)]
P1/P2 = [sqrt((98/50)(b1/b2))][(a1 + a2 + a3)/(a1 + a2 + a3)]
P1/P2 = sqrt((98/50)*(b1/b2))
Now we can substitute the given values to get:
P1/P2 = sqrt((98/50)(b1/b2)) = sqrt((98/50)(2/1)) = sqrt(196/50) = 14/5
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(a) if f(4) = 6, what is f-|(6)? f-'(6) = (b) Suppose a function can be described by y = f(x). The function and its inverse intersect when y = (c) Consider a linear function f (x) = ax + b where a 70. Is the inverse of this linear function always a linear function? (No answer given) If f(x) = ax + b and a € 0, then f-'(x) =
To find f-1(6), we need to find the value of x that gives f(x) = 6. However, we don't have enough information about the function f to do this. We need to know whether f is a linear function or not.
When the function and its inverse intersect, we have f(x) = f-1(x). Substituting y for both f(x) and f-1(x), we get y = f(y). To find the value of y when this is true, we need to solve for y:
y = f(y)
y = f-1(y)
Substituting y = f(x), we get:
f(x) = f-1(f(x))
f(x) = x
So the function and its inverse intersect when y = x.
If a = 0, then the linear function is f(x) = b, which is a constant function. Constant functions do not have inverses, so the inverse of f(x) = b does not exist.
If a ≠ 0, then the inverse of f(x) = ax + b is given by:
f-'(x) = (x - b) / a
This is also a linear function, so the inverse of a linear function is always a linear function when a ≠ 0.
(a) To find the inverse of a linear function, you need to swap the x and y values. Given that f(4) = 6, the inverse function f^(-1)(6) would yield the value of x when y = 6. Since we know that f(4) = 6, it implies that f^(-1)(6) = 4.
A function and its inverse intersect when the input value (x) is equal to the output value (y). In other words, they intersect when y = x.
(c) Yes, the inverse of a linear function is always a linear function. If f(x) = ax + b, where a ≠ 0, then the inverse function, f^(-1)(x), can be found by swapping x and y values and solving for y. In this case, x = ay + b. Solving for y, we get y = (x - b) / a, which is also a linear function.
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The student council at Newberg High School is making T-shirts to sell for a fundraiser, at a price of $12 apiece. The costs, meanwhile, are $7 per shirt, plus a setup fee of $65. Selling a certain number of shirts will allow the student council to cover their costs. How many shirts must be sold? What will the costs be?
Let's assume that the number of shirts that must be sold to cover the costs is x.
The revenue from selling x shirts is 12x dollars, and the total cost is the sum of the setup fee and the cost per shirt multiplied by the number of shirts, which is 65 + 7x dollars.
To break even, the revenue must be equal to the cost:
12x = 65 + 7x
Subtracting 7x from both sides:
5x = 65
Dividing both sides by 5:
x = 13
Therefore, the student council must sell 13 shirts to break even.
To find the total costs, we can substitute x = 13 into the expression for the total cost:
65 + 7x = 65 + 7(13) = 156
So the total costs will be $156.
Answer:
The student council's costs will be $146 and they need to sell 13 shirts to cover their costs.
Step-by-step explanation:
Let's call the number of shirts sold "x".
The revenue from selling x shirts at $12 each is:
Revenue = 12xThe total cost of making x shirts is:
Total Cost = 7x + 65In order to break even (i.e. cover their costs), the revenue must equal the total cost:
[tex]\sf:\implies 12x = 7x + 65[/tex]
Solving for x:
[tex]\sf:\implies 5x = 65[/tex]
[tex]\sf:\implies \boxed{\bold{\:\:x = 13\:\:}}\:\:\:\green{\checkmark} [/tex]
Therefore, the student council must sell 13 shirts to break even.
To find the total costs, we can substitute x = 13 into the total cost equation:
[tex]\sf:\implies Total\: Cost = 7(13) + 65 = \boxed{\bold{\:\:\$146\:\:}}\:\:\:\green{\checkmark} [/tex]
So the student council's costs will be $146 and they need to sell 13 shirts to cover their costs.
Answer all the questions RIGHT and i will give you a brainly
1)The landscaper uses 4 bags of topsoil to cover 3/8 of the garden. How many bags of topsoil will he need to buy to cover the whole garden?
2)The road crew was laying down asphalt at a rate of 1 2/3 yards per 1 7/9 minutes. How many yards of asphalt can they lay per minute? (Put your answer in decimal form)
3)Maleah turned on the water in the kitchen. For every 1 3/4 minute, 1 2/3 gallons of water went into the sink. How many gallons of water filled the sink per minute?
4)James earned $26. 00 last week from mowing lawns for 2 hours. This week he mowed lawns for 4 hours and earned $52. 0. Is the amount of money he earns proportional to the number of hours he works? Yes or No
The landscaper needs to buy approximately 85.33 bags of topsoil to cover the whole garden.
The landscaper uses 4 bags of topsoil to cover 3/8 of the garden. To cover the whole garden, he would need:
First, we need to find how many bags of topsoil he needs per 1/8 of the garden:
4 bags / 3/8 of the garden = 32/3 bags of topsoil per 1 garden
Then, we can find the number of bags he needs for the whole garden:
32/3 bags * 8 = 256/3 bags or 85.33 bags (rounded to two decimal places)
Therefore, the landscaper needs to buy approximately 85.33 bags of topsoil to cover the whole garden.
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In the diagram below, DE is parallel to AB. If CE = 2,
AC = 3.6, AB = 4.2, and DC = 2.4, find the length of CB.
Figures are not necessarily drawn to scale.
The length of CB is 3 unit.
In the given figure ;
By SAS property of similar of triangles,
ΔCED and ΔCAB are similar.
Therefore,
CE/CB = DE/AB = DC/AC
⇒ CE/CB = DC/AC
⇒ 2/CB = 2.4/3.6
⇒ CB = (3.6/2.4)X2 = 3
Hence CB = 3
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The null and alternate hypotheses are:
H0 : μd ≤ 0
H1 : μd > 0
The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of 4 days last month.
Day: 1, 2, 3, 4
Day Shift: 12, 16, 20, 24
Afternoon Shift: 12, 10, 16, 18
At the 0. 05 significance level, is there a difference in the mean number of citations given by the two shifts?
a. What is the p-value?
Note that where the above statistics are give, the p-value is 0.04.
What is the explanation for the above ?1st , we calculate the differences between the number of citations given in the day shift and afternoon shift for each day
Differences - 0, 6, 4, 6
The mean difference is (m) = (0 + 6 + 4 + 6) / 4 = 4
The sample standard deviation of the differences is s = √ ([((0-4)² + (6-4)² + (4-4)² + (6-4)²)/3]) = 2.31
The standard error of the mean difference is SE(m) = s / √(n) = 2.31 / √(4) = 1.155
The t-statistic is t = (m - 0) / SE(m) = 4 / 1.155 = 3.4632034632
The paired t-test has n-1=3 degrees of freedom. We calcu0late the p-value associated with a t-statistic of 3.46 using a t-table or a t-distribution calculator with three degrees of freedom.
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A. Directions:translate each problem into algebraic expression or equation and identify the variable/s.
1. Julie weighs c kilogram. After going to gym for six months, she lost 2. 5 kilograms. Express her weight algebraically.
2. Peter is m centimeter tall. Jhon's height is 5 more than twice the height of Peter. How tall is Jhon?
3. Ador is thrice older than Emy. If Emy is d years old less than 9,how old is ador?
4. Jupiter is n years old now. How old is Jupiter 7 years from now?
5. Anna's sister is p years old. Anna is 4 years older than thrice the age of her sister. How old is Anna?
guys please help me please
lets assume.
Algebraic expression: c - 2.5. The variable is c, which represents Julie's initial weight in kilograms.
Algebraic equation: Jhon's height = 2m + 5. The variables are m, which represents Peter's height in centimeters, and the height of Jhon, which is represented by the equation.
Algebraic equation: Ador's age = 3(Emy's age - d). The variables are Ador's age and Emy's age, which is d years less than 9.
Algebraic expression: n + 7. The variable is n, which represents Jupiter's current age in years.
Algebraic equation: Anna's age = 3p + 4. The variables are p, which represents Anna's sister's age in years, and Anna's age, which is represented by the equation.
SO ANNA current age is P=3+4
and p=7
Anna's age = 3p + 4, where p is the age of Anna's sister in years, and Anna is 4 years older than thrice the age of her sister.
If Anna's sister is 10 years old, how old is Anna according to the equation?Algebraic expression: c - 2.5, where c is the weight of Julie in kilograms, and 2.5 is the weight she lost after six months of going to the gym.Algebraic equation: Jhon's height = 2m + 5, where m is the height of Peter in centimeters, and Jhon's height is 5 more than twice the height of Peter.Algebraic equation: Ador's age = 3(Emy's age - d), where Emy is d years less than 9, and Ador is thrice older than Emy.Algebraic equation: Jupiter's age 7 years from now = n + 7, where n is Jupiter's current age in years.Algebraic equation: Anna's age = 3p + 4, where p is the age of Anna's sister in years, and Anna is 4 years older than thrice the age of her sister.Learn more about Anna age
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