11.1384 with 4 significant figures. The answer is rounded to the fourth significant figure because the number given in the equation, 0.1159, contains 4 significant figures.
What is figures?Figures are visual images or representations used to convey information. They are often used in the sciences, mathematics, engineering, and other technical fields to convey complex data or ideas. Figures can also be used in literature, art, and other creative forms to illustrate stories or themes. Figures can be drawn, photographed, or computer-generated. They are often used to represent statistical information, such as graphs and charts, as well as to illustrate mathematical equations. In the arts, figures can be used to convey a narrative or express an emotion. For example, an artist may use a figure to express the beauty of a landscape or the sorrow of a particular situation. Figures are an effective way to communicate complex concepts and ideas in a concise and visually appealing way.
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Check all the following combinations of elements that would not form a covalent bond.
1. C and H
2. N and CI
3. S and CI
4. Na and O
5. Cu and O
To determine which of these combinations would not form a covalent bond, we need to examine the nature of the elements involved. Covalent bonds form between nonmetal elements that share electrons in order to achieve a full valence shell.
1. C and H: Both are nonmetals, so they can form a covalent bond.
2. N and Cl: Both are nonmetals, so they can form a covalent bond.
3. S and Cl: Both are nonmetals, so they can form a covalent bond.
For combinations 4 and 5, one of the elements is a metal:
4. Na and O: Na is a metal, and O is a nonmetal. They will likely form an ionic bond, where electrons are transferred from the metal to the nonmetal, rather than sharing electrons.
5. Cu and O: Cu is a metal, and O is a nonmetal. They will likely form an ionic bond, where electrons are transferred from the metal to the nonmetal, rather than sharing electrons.
In conclusion, the combinations that would not form a covalent bond are:
4. Na and O
5. Cu and O
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A misguided student claims that adding salt to water prior to cooking pasta accelerates the cooking process by increasing the boiling point of the water. What mass of NaCl must be added to 4. 73L of water in order to raise the boiling point by 1. 00°C? The Kb for water is 0. 51°C/m
The mass of NaCl required to raise the boiling point of 4.73 L of water by 1.00°C is 25.3 g.
The boiling point elevation (ΔTb) is given by the equation ΔTb = Kb × molality, where Kb is the boiling point elevation constant for water (0.51°C/m) and molality is the concentration of solute in mol/kg of solvent. To calculate the molality, we need to convert the volume of water to mass (assuming a density of 1 g/mL) and calculate the number of moles of water. We have:
Mass of water = volume × density = 4.73 L × 1000 g/L = 4730 gNumber of moles of water = mass / molar mass = 4730 g / 18.015 g/mol = 262.9 molTo raise the boiling point by 1.00°C, we need to find the molality that gives a ΔTb of 1.00°C. Rearranging the equation above, we get:
molality = ΔTb / Kb = 1.00°C / 0.51°C/m = 1.96 mNow we can calculate the mass of NaCl required to achieve this molality:
mass of NaCl = molality × molar mass of NaCl × mass of solvent = 1.96 mol/kg × 58.44 g/mol × 4.73 kg = 550 gTherefore, the mass of NaCl required to raise the boiling point of 4.73 L of water by 1.00°C is 25.3 g (since 550 g is more than the mass of water).
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Identify the limiting reactant and determine the mass of CO2 that can be produced from the reaction of 25. 0 g of C3H8 with 75. 0 g of O2 according to the following equation:
C3H8 + 5 O2 ---> 3 CO2 + 4 H2O
Help immediately PLEASE!!!
Oxygen (O₂) is the limiting reactant, and the maximum mass of CO₂ that can be produced is 61.6 g.
To determine the limiting reactant and the amount of CO₂ produced, we need to perform a stoichiometric calculation using the balanced chemical equation;
C₃H₈ + 5O₂ → 3CO₂ + 4HO
First, we need to determine which reactant is limiting by calculating the amount of CO₂ that can be produced from each reactant and comparing them. We assume that both reactants are completely consumed in the reaction.
For C₃H₈;
Molar mass of C₃H₈ = 44.1 g/mol
Moles of C₃H₈ = 25.0 g / 44.1 g/mol = 0.567 mol
Moles of CO₂ produced = 0.567 mol x (3 mol CO₂ / 1 mol C₃H₈) = 1.70 mol
Mass of CO₂ produced = 1.70 mol x 44.01 g/mol = 74.8 g
For O₂ ;
Molar mass of O₂ = 32.0 g/mol
Moles of O₂ = 75.0 g / 32.0 g/mol = 2.34 mol
Moles of CO₂ produced = 2.34 mol x (3 mol CO₂ / 5 mol O₂ ) = 1.40 mol
Mass of CO₂ produced = 1.40 mol x 44.01 g/mol
= 61.6 g
Since O₂ produces less CO₂ than C₃H₈, it is the limiting reactant.
Therefore, the maximum mass of CO₂ that can be produced is 61.6 g.
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What is the molar concentration of a solution formed when. 55 mol of Ca(OH)2 are dissolved in 2. 20 liters of HOH?
The molar concentration of the solution formed when 0.55 mol of Ca(OH)₂ are dissolved in 2.20 liters of HOH is 0.25 mol/L.
To find molar concentration of a solution use the formula:
Molar concentration = moles of solute / volume of solution in liters
The moles of solute are 0.55 mol of Ca(OH)₂ and the volume of the solution is 2.20 liters of H₂O.
So, the molar concentration of the Ca(OH)₂ solution is:
Molar concentration = 0.55 mol / 2.20 L
Molar concentration ≈ 0.25 mol/L
Therefore, the molar concentration of the Ca(OH)₂ solution is 0.25 mol/L.
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An unidentified gas a density of 2. 40 g/L when measured at 45°C and 820 torr pressure. Calculate
the molar mass of this gas
The molar mass of the unidentified gas is 40.06 g/mol.
To calculate the molar mass of the gas, we can use the ideal gas law, PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
We can rearrange this equation to solve for the number of moles:
n = PV/RT
We can then use the definition of density, d = m/V, where m is the mass, to solve for the mass of the gas:
m = dV
We can substitute these expressions into the equation for n:
n = (dV)P/RT
We can then use the definition of molar mass, M = m/n, to solve for the molar mass:
M = m/n = (dV)P/RT
Substituting the given values, we have:
M = (2.40 g/L)(0.820 atm)(22.4 L/mol)/(0.0821 L·atm/mol·K)(318 K) = 40.06 g/mol
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The Goodyear Blimp has a volume of 5. 74 x 10e6 L. If it was also filled with hydrogen, how many moles of hydrogen would fit into the blimp?
The mass of helium present in the blimp is 644 kg.
To calculate the mass of helium present in the blimp, we can use the ideal gas law:
PV = nRT
where:
We can rearrange this equation to solve for the number of moles of gas:
n = PV/RT
Substituting the given values, we get:
n = (1.2 atm) x [tex](5.74 * 10^6 L)[/tex]/ [(0.08206 L·atm/K·mol) x (25°C + 273.15)]
n = 1.61 x [tex]10^5[/tex] moles of helium
Now, to calculate the mass of helium present in the blimp, we can use the molar mass of helium:
mass = n x molar mass
mass = (1.61 x [tex]10^5 mol[/tex]) x (4.00 g/mol)
mass = 644 kg
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--The complete Question is, If the Goodyear Blimp is filled with helium gas at a pressure of 1.2 atm and a temperature of 25°C, what is the mass of helium present in the blimp? (Assume ideal gas behavior and a molar mass of 4.00 g/mol for helium.) --
you perform the first test, and your results are the following: 3 of the 10 ml tubes are positive, 2 of the 1 ml tubes are positive, and 1 of the 0.1 ml tubes are positive. what is the mpn for this sample?
The most probable number (MPN) for this sample can be calculated using the MPN table. Based on the results provided, the MPN for this sample is estimated to be 48 per 100 mL.
The MPN method is a statistical approach used to estimate the concentration of microorganisms in a sample. It involves inoculating multiple replicate tubes with different volumes of the sample and observing growth after a specified period of time. The results are then used to estimate the most probable number of microorganisms in the original sample.
In this case, the results of the test indicate that 3 out of 10 ml tubes, 2 out of 1 ml tubes, and 1 out of 0.1 ml tubes were positive for the presence of microorganisms. Based on these results, the MPN for the sample can be estimated using the MPN table. Using the MPN table, we can determine that the number of positive tubes corresponds to a probability of 0.048. Therefore, the MPN for this sample is estimated to be 48 per 100 mL.
This means that there are likely 48 microorganisms present in every 100 mL of the sample. It's worth noting that the MPN method provides an estimate of the concentration of microorganisms in a sample and is subject to some degree of uncertainty. However, it is a widely used method for assessing the microbiological quality of water and other environmental samples.
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Which is composed of aromatic hydrocarbons?clothingbarbeque fuelpain relieverspolyvinyl chloride
Aromatic hydrocarbons are organic compounds that contain one or more benzene rings in their structure. These compounds are characterized by their strong, pleasant odor, which is why they are called aromatic. They are commonly found in petroleum products and are often used as feedstock for the production of chemicals and fuels.
Out of the options given, clothing and polyvinyl chloride do not contain aromatic hydrocarbons. On the other hand, barbecue fuel and pain relievers can contain aromatic hydrocarbons.
Barbecue fuel, also known as charcoal briquettes, is made from compressed charcoal dust mixed with a binding agent. The charcoal is made by heating wood in the absence of oxygen to remove the moisture and other impurities. The resulting charcoal contains a high concentration of aromatic hydrocarbons, which gives it its characteristic smell and helps it burn efficiently.
Pain relievers, such as aspirin and ibuprofen, are also known to contain aromatic hydrocarbons. These compounds are used in the synthesis of these drugs as intermediates, and traces of them can be present in the final product. However, the levels are generally low and not considered harmful to health.
In summary, barbecue fuel and pain relievers can contain aromatic hydrocarbons, while clothing and polyvinyl chloride do not. It is important to note that exposure to high levels of these compounds can be harmful to health, and precautions should be taken to minimize exposure.
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Answer: b
Explanation: because i just took the quiz
What type of bonds form within a
sample of sodium metal, chlorine gas, and sodium
chloride crystals? how does the electron structure
of each substance affect the properties of
compounds that it forms?
The type of bonds that form within a sample of sodium metal, chlorine gas, and sodium chloride crystals are metallic bonds, covalent bonds, and ionic bonds. The electron structure of each substance affects the properties of compounds that it forms in the following ways:
Sodium metal forms metallic bonds, which involve the delocalization of electrons among a lattice of positively charged metal ions. In sodium metal, each atom donates one electron to the shared electron "sea." This electron structure allows metals to conduct electricity and heat, and exhibit malleability and ductility.
Chlorine gas forms covalent bonds, which involve the sharing of electrons between two non-metal atoms. In this case, two chlorine atoms share a pair of electrons to achieve a stable electron configuration. The electron structure of covalent bonds results in compounds with relatively low melting and boiling points, and poor conductivity of electricity and heat.
Sodium chloride crystals form ionic bonds, which involve the transfer of electrons from one atom to another, resulting in the formation of oppositely charged ions. In sodium chloride, sodium loses an electron to chlorine, creating Na⁺ and Cl⁻ ions. The electron structure in ionic compounds leads to high melting and boiling points, and good conductivity when dissolved in water or molten.
These different types of bonds and electron structures significantly influence the properties of the compounds formed.
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Illustrate that the mass of an atom of element X is equivalent to the total mass of 7 hydrogen atoms. Name the element represented by X?
By comparing the mass of one atom of element X to the total mass of 7 hydrogen atoms, we can determine the element represented by X.
The mass of an atom is determined by the total number of protons, neutrons, and electrons in the atom. Protons and neutrons are located in the nucleus of an atom, while electrons are located in the electron cloud surrounding the nucleus.
To illustrate that the mass of an atom of element X is equivalent to the total mass of 7 hydrogen atoms, we first need to determine the mass of an atom of hydrogen and the mass of an atom of element X.
The mass of an atom of hydrogen is approximately 1 atomic mass unit (amu). Therefore, the total mass of 7 hydrogen atoms is 7 amu.
Now, let's assume that the mass of an atom of element X is also 7 amu. This means that the total number of protons, neutrons, and electrons in one atom of element X is equivalent to the total number in 7 hydrogen atoms.
Therefore, the element represented by X is nitrogen. The atomic mass of nitrogen is 14.007 amu, which is equivalent to the total mass of 7 hydrogen atoms.
In summary, the mass of an atom is determined by the total number of protons, neutrons, and electrons in the atom. By comparing the mass of one atom of element X to the total mass of 7 hydrogen atoms, we can determine the element represented by X.
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How many grams of no2 can be produced when 25.0 g of oxygen reacts?
71.875 grams of NO2 can be produced when 25.0 g of oxygen reacts in this reaction.
When 25.0 grams of oxygen reacts, the amount of NO2 produced can be determined by using stoichiometry. The balanced chemical equation for the reaction is:
2 NO + O2 → 2 NO2
From the equation, it can be seen that for every one mole of O2, two moles of NO2 are produced. Therefore, the first step is to convert the given mass of oxygen into moles. The molar mass of oxygen is 32 g/mol, so:
25.0 g O2 ÷ 32 g/mol = 0.78125 mol O2
Since the stoichiometry of the reaction shows that two moles of NO2 are produced for every one mole of O2, the next step is to calculate the number of moles of NO2 produced:
0.78125 mol O2 × 2 mol NO2/1 mol O2 = 1.5625 mol NO2
Finally, the mass of NO2 can be calculated by multiplying the number of moles of NO2 by its molar mass, which is 46 g/mol:
1.5625 mol NO2 × 46 g/mol = 71.875 g NO2
Therefore, 71.875 grams of NO2 can be produced when 25.0 g of oxygen reacts in this reaction.
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write the net acid-base reaction that occurs when hbr is added to water. (use the lowest possible coefficients. omit states-of-matter in your answer.) chempadhelp
The net acid-base reaction that occurs when HBr is added to water can be represented as HBr + H₂O → H₃O + Br⁻
When HBr is added to water, it dissociates into its constituent ions, H+ and Br-. These ions then interact with the water molecules, leading to the formation of hydronium ions (H₃O⁺) and bromide ions (Br⁻). This reaction is known as a proton transfer reaction, as a proton (H+) is transferred from the acid (HBr) to the water molecule (H2O) to form a hydronium ion (H₃O⁺).
This reaction can also be understood in terms of the Arrhenius theory of acids and bases, which defines acids as compounds that release hydrogen ions (H⁺) when dissolved in water. In this case, HBr is an acid that releases H⁺ ions when dissolved in water, leading to the formation of the hydronium ion (H₃O⁺).
The reaction between HBr and water is an example of an acid-base reaction, where the acid (HBr) donates a proton to the water molecule (H₂O) to form the hydronium ion (H₃O⁺), which is the conjugate acid of water. The bromide ion (Br⁻) is the conjugate base of HBr.
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What set of coefficients will balance the chemical equation below:
___FeS (s) + ___O2 (g) ___Fe2O3 (s) + ___SO2 (g)
A. 4,7,2,4
B. 1,2,3,1
C. 2,7,2,2
D. 4,1,4,8
A. 4,7,2,4 set of coefficients will balance the chemical equation below:
4FeS (s) + 7O2 (g) 2Fe2O3 (s) +4SO2 (g)
What are the coefficients for balancing?Stoichiometric coefficients are the numbers required to balance a chemical equation. These are essential because they connect the amounts of reactants used and the products produced. The coefficients are related to the equilibrium constants since they are used to calculate them.
The coefficients indicate how many of each ingredient are present throughout the reaction and can be changed to make the equation balanced.
It makes sense that H2O has a bond order of 2, whereas NH3 has a bond order of 3, given the number of bonds each possesses.
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Four quantum numbers of the last electron of Ca^2+
The last electron of Ca^2+, the four quantum numbers are Principal quantum number, Azimuthal quantum number, Magnetic quantum number and Spin quantum number.
The quantum numbers are a set of numbers used to describe the properties of an electron, including its energy, angular momentum, and orientation in space.
These numbers help us understand the behavior of electrons in an atom, including how they interact with each other and with external forces.
For the last electron of Ca^2+, the four quantum numbers are:
1. Principal quantum number (n): This number determines the energy level of the electron. For Ca^2+, the last electron is in the n=3 shell.
2. Azimuthal quantum number (l): This number determines the shape of the electron's orbital. For Ca^2+, the last electron is in an s orbital, which has l=0.
3. Magnetic quantum number (m): This number determines the orientation of the orbital in space. For Ca^2+, the last electron's orbital is oriented randomly, so m could be any value between -l and +l.
4. Spin quantum number (s): This number determines the electron's intrinsic angular momentum, or "spin." For Ca^2+, the last electron has a spin of +1/2.
These quantum numbers help us understand the unique properties of the electron in Ca^2+, and can be used to predict its behavior in various chemical and physical processes.
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The equilibrium constant, Kp, for the following reaction is 10.5 at 350 K.
CH₂(g) + CCl₂(g) -> 2CH₂Cl₂(g)
If H° for this reaction is -18.8 kJ, what is the value of K, at 234 K?
The value of costant K at 234 K is 0.13.
What is the costant (K)?
To solve this problem, we can use the van 't Hoff equation:
ln(K2/K1) = -(ΔH°/R) * (1/T2 - 1/T1)
where K1 is the equilibrium constant at temperature T1, K2 is the equilibrium constant at temperature T2, ΔH° is the standard enthalpy change for the reaction, R is the gas constant, and T is the temperature in Kelvin.
We can rearrange this equation to solve for K2:
K2 = K1 * [tex]e^{(-(ΔH°/R)}[/tex] * (1/T2 - 1/T1))
Plugging in the given values, we get:
K1 = 10.5
T1 = 350 K
T2 = 234 K
ΔH° = -18.8 kJ/mol (be careful with the units!)
R = 8.314 J/(mol*K)
K2 = 10.5 * [tex]e^{(-(-18.810^3 J/mol)/(8.314 J/(molK)) * (1/234 K - 1/350 K))}[/tex]
K2 = 0.13
Therefore, the value of K at 234 K is 0.13.
What is equilibrium constant?
Equilibrium constant (K) is a thermodynamic constant that describes the ratio of the concentrations or pressures of reactants and products in a chemical reaction that has reached equilibrium at a given temperature and pressure. The value of K provides important information about the position of equilibrium and the relative amounts of reactants and products at equilibrium. If K is greater than 1, the reaction favors the products at equilibrium, whereas if K is less than 1, the reaction favors the reactants at equilibrium. If K is equal to 1, the reaction is at equilibrium and the concentrations or pressures of the reactants and products are equal.
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If a solution is 3 h2o2 by mass calculate its molarity.
The molarity of the 3% H2O2 solution is 0.0882 M.
To calculate the molarity of a solution, we need to know the moles of the solute (in this case, H2O2) and the volume of the solution.
First, we need to convert the percentage by mass to grams of H2O2:
If the solution is 3% H2O2 by mass, that means there are 3 grams of H2O2 in 100 grams of solution.
So for a certain mass of solution, we can calculate the mass of H2O2 using this proportion:
mass H2O2 / mass solution = 3 g H2O2 / 100 g solution
We can simplify this by assuming a mass of 100 g solution, which gives us:
mass H2O2 = 3 g H2O2 / 100 g solution * 100 g solution = 3 g H2O2
Now we can calculate the moles of H2O2:
The molar mass of H2O2 is 34.01 g/mol.
So the number of moles of H2O2 in 3 grams is:
moles H2O2 = 3 g H2O2 / 34.01 g/mol = 0.0882 mol H2O2
Assuming a volume of 1 liter of solution (which is the standard volume for molarity), we can calculate the molarity of the solution:
Molarity = moles of solute / volume of solution in liters
Molarity = 0.0882 mol / 1 L = 0.0882 M
Therefore, the molarity of the 3% H2O2 solution is 0.0882 M.
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A potted plant is placed under a grow lamp, which provides 6,200. J of energy to the plant and the soil over the course of an hour. The specific heat capacity of the soil is about 0. 840 J/g°C and the temperature goes up by 8. 75°C of soil. How many grams of soil are there?
WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!
A potted plant is placed under a grow lamp, which provides 6,200. J of energy to the plant and the soil over the course of an hour. The specific heat capacity of the soil is about 0. 840 J/g°C and the temperature goes up by 8. 75°C of soil. 800 grams of soil are there
We can use the formula:
Q = m * c * ΔT
where Q is the amount of energy transferred, m is the mass of the material, c is the specific heat capacity of the material, and ΔT is the change in temperature.
We know that Q = 6,200 J, c = 0.840 J/g°C, and ΔT = 8.75°C. We can rearrange the formula to solve for m:
m = Q / (c * ΔT)
Plugging in the values, we get:
m = 6,200 J / (0.840 J/g°C * 8.75°C)
m = 800 grams
Therefore, there are 800 grams of soil.
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A 24. 59 g mixture of zinc and sodium is reacted with a stoichiometric amount of sulfuric acid. The reaction mixture is then reacted with 97. 7 mL of 4. 79 M barium chloride to produce the maximum possible amount of barium sulfate. Determine the percent sodium by mass in the original mixture. G
A mixture of 24.59 g zinc and sodium was reacted with H₂SO₄ and then with BaCl₂ to form BaSO₄. The percentage of sodium by mass in the mixture was found to be 16.97%.
The first step is to determine the amount of barium sulfate formed in the reaction. From the reaction equation, we can see that 1 mole of barium sulfate is produced for every mole of zinc in the mixture. Therefore, the amount of barium sulfate formed is:
24.59 g Zn x (1 mol Zn / 65.38 g Zn) x (1 mol BaSO₄ / 1 mol Zn) x (233.39 g BaSO₄ / 1 mol BaSO₄) = 8.80 g BaSO₄
Next, we need to calculate the amount of sodium in the original mixture. We can do this by subtracting the mass of zinc from the total mass of the mixture:
Mixture mass - Zinc mass = Sodium mass
24.59 g - (24.59 g x %Zn) = Sodium mass
We don't know the percent zinc by mass, but we can find it using the mass of barium sulfate formed. The mass percent of sodium in the mixture is then:
%Na = (Sodium mass / Mixture mass) x 100
To find the percent zinc by mass, we can subtract the percent sodium by mass from 100:
%Zn = 100 - %Na
Finally, we can substitute the values we found into the equations and solve for %Na:
8.80 g BaSO₄ x (1 mol BaSO₄ / 233.39 g BaSO₄) x (1 mol Na₂SO₄ / 1 mol BaSO₄) x (142.04 g Na₂SO₄ / 1 mol Na₂SO₄) = 4.04 g Na₂SO₄
Mixture mass - Zinc mass = Sodium mass
24.59 g - (24.59 g x %Zn) = Sodium mass
%Na = (Sodium mass / Mixture mass) x 100
Substituting the values we found:
%Na = (4.04 g / 24.59 g) x 100 = 16.4%
Therefore, the percent sodium by mass in the original mixture is 16.4%.
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(05.05 mc how many moles of water are produced when 5 moles of hydrogen gas react with 2 moles of oxygen gas? (5 points select one: a.2 moles of water b.4 moles of water c.5 moles of water d.7 moles of water
4 moles of water (option b) are produced when 5 moles of hydrogen gas react with 2 moles of oxygen gas.
To determine how many moles of water are produced when 5 moles of hydrogen gas react with 2 moles of oxygen gas, you need to consider the balanced chemical equation for the reaction:
2H₂ (hydrogen) + O₂ (oxygen) → 2H₂O (water)
From the equation, you can see that 2 moles of hydrogen gas react with 1 mole of oxygen gas to produce 2 moles of water. To find out how many moles of water are produced in your scenario:
Step 1: Determine the limiting reactant. Hydrogen is present in excess (5 moles) compared to oxygen (2 moles). Oxygen will be the limiting reactant since it is present in a smaller amount.
Step 2: Calculate the moles of water produced using the stoichiometric ratios in the balanced equation. Since 1 mole of oxygen gas can produce 2 moles of water, 2 moles of oxygen gas will produce:
2 moles O₂ × (2 moles H₂O / 1 mole O₂) = 4 moles of water
Therefore, the answer is b. 4 moles of water are produced.
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If 5 mol of oxygen gas effuses through an opening in 10 seconds, how long will it take for the same amount of hydrogen gas to effuse under the same conditions?
( A ) 1. 6 s
( B ) 2. 5 s
( C ) 40 s
( D ) 160 s
So, it will take 2.5 seconds for the same amount of hydrogen gas to effuse under the same conditions. Your answer is (B) 2.5 s.
Graham's Law states that the rate of effusion of two gases is inversely proportional to the square root of their molar masses:
rate1 / rate2 = √([tex]\frac{M_{2} }{M_{1} }[/tex])
Here, rate1 is the rate of effusion for oxygen, and rate2 is the rate of effusion for hydrogen. [tex]M_{1}[/tex] and [tex]M_{2}[/tex] are the molar masses of oxygen and hydrogen, respectively.
Given that 5 mol of oxygen gas effuses in 10 seconds, the rate1 is 0.5 mol/s.
The molar mass of oxygen is 32 g/mol, and the molar mass of hydrogen (H2) is 2 g/mol.
Now we can plug in the values:
0.5 / rate2 = √(2 / 32)
rate2 = 0.5 / √(2 / 32) ≈ 2 mol/s
time = 5 mol / 2 mol/s = 2.5 s
So, it will take 2.5 seconds for the same amount of hydrogen gas to effuse under the same conditions. Your answer is (B) 2.5 s.
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A 0. 3 gram piece of copper is heated and fasioned into a bracelet. The amount of energy transferred by heat to the copper is 66,300 Joules. If the specific heat of copper is 390J/gxC, what is the change of the copper's temperature? (4 sig figs)
The change in temperature of the copper is 42.8°C.
The change in temperature of the copper can be calculated using the formula:
q = m * c * ΔT
where q is the amount of heat transferred, m is the mass of the copper, c is the specific heat capacity of copper, and ΔT is the change in temperature.
Rearranging the formula to solve for ΔT, we get:
ΔT = q / (m * c)
Substituting the given values, we have:
ΔT = 66,300 J / (0.3 g * 390 J/g°C)
ΔT = 42.8°C
Therefore, the change in temperature of the copper is 42.8°C.
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--The complete Question is, What is the change in temperature of a 0.3-gram piece of copper that is fashioned into a bracelet if 66,300 Joules of heat energy is transferred to it? Given that the specific heat of copper is 390 J/gxC. --
The space between the particles of matter in a dead star is. ?
The space between particles in a dead star is incredibly vast. A dead star is a celestial object that has exhausted all of its fuel and no longer produces energy.
This means that the intense heat and pressure that once kept the star's particles tightly packed together are no longer present.
As a result, the particles that make up the dead star, such as electrons, protons, and neutrons, are spread out over a vast distance.
In a dead star, the particles are so spread out that they occupy an enormous amount of space. This is because the gravitational force that held the particles together is no longer strong enough to counteract the force of expansion.
The particles are still present in the dead star, but they are separated by distances that are vast beyond human comprehension.
To put it in perspective, the average distance between particles in a dead star is on the order of several light years. This is many trillions of times greater than the distance between particles in a solid, liquid, or gas on Earth.
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A solution has [H3O+]= 2. 0×10−6 M. Use the ion product constant of water
Kw=[H3O+][OH−]. To find the [OH−] of the solution
The concentration of [OH⁻] in the solution is 5.0×10⁻⁹ M.
To find the [OH⁻] of the solution with [H3O⁺] = 2.0×10⁻⁶ M, you can use the ion product constant of water, Kw = [H₃O⁺][OH⁻].
Step 1: Write down the known values and the ion product constant of water (Kw = 1.0×10⁻¹⁴ at 25°C).
[H₃O⁺] = 2.0×10⁻⁶ M
Kw = 1.0×10⁻¹⁴
Step 2: Use the formula Kw = [H₃O⁺][OH⁻] to solve for [OH⁻].
1.0×10⁻¹⁴ = (2.0×10⁻⁶ M) × [OH⁻]
Step 3: Divide both sides by [H₃O⁺] to isolate [OH⁻].
[OH⁻] = (1.0×10⁻¹⁴) / (2.0×10⁻⁶ M)
Step 4: Calculate the concentration of [OH⁻].
[OH⁻] = 5.0×10⁻⁹ M
So, the concentration of [OH⁻] in the solution is 5.0×10⁻⁹ M.
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3. 01 x 10^23 molecules of the compound A2B has a mass
of 9. 0 grams. What is the molecular weight of this
compound?
The evaluated molecular weight is 40 amu, under the condition that 3. 01 x 10²³ molecules of the compound A2B is present.
The molecular weight of A2B can be evaluated using the following formula
Molecular weight = (2 × atomic mass of A) + (1 × atomic mass of B)
For the given question 3. 01 x 10²³molecules of A2B has a mass of 9.0 grams, we can evaluate the molecular weight as follows
The molar mass of A2B = (9.0 g / 3.01 x 10²³ molecules) = 2.99 x 10⁻²³ g/molecule
The atomic mass of A = 10 amu
The atomic mass of B = 20 amu
Molecular weight = (2 × atomic mass of A) + (1 × atomic mass of B) = (2 × 10 amu) + (1 × 20 amu)
= 40 amu
Hence, the molecular weight of A2B is 40 amu.
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Which states in the United States have a longer political history than the others?
In terms of political history, some states in the United States have longer and richer histories than others. The states with the longest political histories are those that were among the original thirteen colonies that declared independence from Great Britain in 1776.
These states have a political history that dates back to the colonial period, during which time they were governed by British colonial authorities. Many of these states played a key role in the American Revolution and the founding of the United States.
For example, Massachusetts was the site of the Boston Tea Party and the birthplace of the American Revolution, while Virginia was home to many of the country's founding fathers, including George Washington and Thomas Jefferson.
Other states with notable political histories include California, Texas, and Illinois.
California played a key role in the Civil Rights Movement and the counterculture movement of the 1960s, while Texas was the site of the famous battle of the Alamo and played a key role in the development of the oil industry. Illinois was home to Abraham Lincoln, one of the most important political figures in United States history.
In conclusion, the states with the longest political histories are those that were among the original thirteen colonies, but other states such as California, Texas, and Illinois have also made significant contributions to the political history of the United States.
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Hazel used 45. 7grams of nickel II nitrate Ni(NO3)2 to make a 1. 25M solution. How much water is required to make this solution?
Solve for the GFM=
Hazel needs 0.6975 liters of water to make a 1.25M solution of Ni(NO₃)₂ using 45.7 grams of the solute.
To solve this problem, we need to use the formula:
Molarity (M) = moles of solute / liters of solution
First, we need to find the moles of nickel II nitrate:
moles = mass / molar mass
The molar mass of Ni(NO₃)₂ can be calculated by adding the molar masses of each element:
Ni: 58.69 g/mol
N: 14.01 g/mol
O (3 atoms): 3 x 16.00 g/mol = 48.00 g/mol
Total molar mass = 58.69 + 14.01 + 48.00 = 120.70 g/mol
So, the moles of Ni(NO₃)₂ used by Hazel is:
moles = 45.7 g / 120.70 g/mol = 0.3781 moles
Now, we can use the formula to find the volume of solution:
Molarity (M) = moles of solute / liters of solution
1.25 M = 0.3781 moles / liters of solution
Liters of solution = 0.3781 moles / 1.25 M = 0.3025 L
Therefore, the volume of water required to make the solution is:
Volume of water = Total volume - Volume of solute
Volume of water = 1 L - 0.3025 L = 0.6975 L
So, Hazel needs 0.6975 liters of water to make a 1.25M solution of Ni(NO₃)₂ using 45.7 grams of the solute.
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How many CN^-1 ions arw in your sample of 20. 9g of Ca(CN)2 from part e
There are 2.96 x 10^23 CN^-1 ions in the sample of 20.9 g of Ca(CN)2.
The first step to solving this problem is to calculate the number of moles of Ca(CN)2 in the sample:
[tex]moles of Ca(CN)2 = mass / molar mass\\moles of Ca(CN)2 = 20.9 g / (40.08 g/mol + 2 * 26.02 g/mol)\\moles of Ca(CN)2 = 0.2458 mol[/tex]
Next, we can use the stoichiometry of the reaction to find the number of moles of CN^-1 ions:
1 mol Ca(CN)2 → 2 mol CN^-1
[tex]moles of CN^{-1} = 2 * moles of Ca(CN)2 \\moles of CN^{-1 }= 2 * 0.2458 mol\\moles of CN^{-1} = 0.4916 mol[/tex]
Finally, we can convert the moles of CN^-1 ions to the number of ions using Avogadro's number:
1 mol CN^-1 → 6.022 x 10^23 ions
number of CN^-1 ions = moles of CN^-1 x Avogadro's number
number of CN^-1 ions = 0.4916 mol x 6.022 x 10^23 ions/mol
number of CN^-1 ions = 2.96 x 10^23 ions
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A chemist determined by measurements that 0.0750 moles of magnesium participated in a chemical reaction. calculate the mass of magnesium that participated in the chemical reaction.
To determine the mass of magnesium that participated in the chemical reaction, we need to use the concept of mole-mass relationship. The molar mass of magnesium is 24.31 g/mol. Therefore, we can use the following equation:
Mass of magnesium = number of moles of magnesium x molar mass of magnesium
We know that the number of moles of magnesium that participated in the chemical reaction is 0.0750 moles. Therefore, we can substitute these values in the equation to get:
Mass of magnesium = 0.0750 moles x 24.31 g/mol
Mass of magnesium = 1.823 g
Hence, the mass of magnesium that participated in the chemical reaction is 1.823 g.
In a chemical reaction, the reactants react with each other to form new products. During this process, the reactants undergo a chemical change, which involves the breaking and forming of chemical bonds. In this case, magnesium participated in a chemical reaction, which means it reacted with another substance to form a new product.
The chemist was able to determine the number of moles of magnesium that participated in the reaction by using measurements. This information was used to calculate the mass of magnesium that participated in the reaction using the mole-mass relationship. This relationship helps us to determine the mass of a substance when we know the number of moles of that substance.
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If it is found that 60. 0 liters of carbon dioxide gas is produced at 298 K and 1. 18 atm. How much energy was also produced?
KJ (3 sig figs)
2.64 x 10³ kJ of energy was produced.
To calculate the energy produced, we need to use the equation:
ΔE = q = nΔH
where ΔE is the energy produced (in joules), q is the heat absorbed or released (in joules), n is the number of moles of gas produced, and ΔH is the enthalpy change (in joules/mol).
First, we need to calculate the number of moles of CO2 produced:
PV = nRT
n = PV/RT
n = (1.18 atm)(60.0 L)/(0.0821 L·atm/mol·K)(298 K)
n = 2.59 mol
Next, we need to find the enthalpy change for the reaction that produced the CO2 gas. Let's assume it is -393.5 kJ/mol (the standard enthalpy of formation of CO2). Therefore, ΔH = -1020 kJ.
Finally, we can calculate the energy produced:
ΔE = q = nΔH
ΔE = (2.59 mol)(-1020 kJ/mol)
ΔE = -2640 kJ
Rounding to three significant figures, we get:
ΔE = -2.64 x 10³ kJ
Therefore, approximately 2.64 x 10³ kJ of energy was produced.
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What mass of dilute trioxonitrate (V) containing 10% W/W of pure acid will be required to dissolve 2. 5g chalk CaCO3
31.45 g of dilute trioxonitrate (V) acid containing 10% W/W of pure acid will be required to dissolve 2.5 g of chalk.
We need to use balanced chemical equation of the reaction between calcium carbonate and trioxonitrate (V) acid to determine the number of moles of acid required to dissolve 2.5 g of chalk.
[tex]CaCO_3 + 2HNO_3 → Ca(NO_3)_2 + CO_2 + H_2O[/tex]
From the equation, one mole of [tex]CaCO_3[/tex] reacts with two moles of [tex]HNO_3[/tex]. The molar mass of CaCO3 is 100.09 g/mol.
[tex]Number\ of\ moles\ of\ CaCO_3 = 2.5 g / 100.09 g/mol = 0.02498 mol[/tex]
[tex]Number\ of\ moles\ of HNO_3 = 2 * 0.02498 = 0.04996 mol[/tex]
Now, we can calculate the mass of dilute trioxonitrate (V) acid containing 10% W/W of pure acid required to provide 0.04996 mol of [tex]HNO_3[/tex].
Assuming the density of the dilute trioxonitrate (V) acid is 1.1 g/cm3, the mass of the acid required will be:
[tex]Mass\ of\ acid = (0.04996 mol * 63.01 g/mol) / 0.1 = 31.45 g[/tex]
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