If (-8,3) lies on the circle and its Center is (-4,3) then, the radius of the circle is 4.
We know that the center of the circle is (-4, 3). Let's call the radius of the circle "r".
The distance between the center of the circle and the point (-8, 3) on the circle is equal to the radius "r".
Using the distance formula, we can find the distance between these two points;
d =√[(x2 - x1)² + (y2 - y1)²]
d = √[(-8 - (-4))² + (3 - 3)²]
d = √[(-8 + 4)² + 0²]
d = √[4²]
d = 4
Since the distance between the center of the circle and the point on the circle is equal to the radius, we have;
r = d = 4
Therefore, the radius of the circle is 4.
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I also need help on finding the pvalue
The claim is: Testing if the time spent completing the obstacle course is improved by the energy drink
The null and the alternate hypotheses are added below
Stating the null and the alternate hypothesisFrom the question, we have the following parameters that can be used in our computation:
The table
Also, we have the following statistical question
Is there sufficient evidence at α = 0.05 to conclude that the students did better the second time?
This means that the null hypothesis are
H1: There is no significant difference in the time spent to complete the obstacle course before and after drinking the new energy drink.
The alternate hypothesis is the opposite of the null hypothesis
So, we have
H2: There is no significant difference in the time spent to complete the obstacle course before and after drinking the new energy drink.
Lastly, the claim is that
Testing if the time spent completing the obstacle course is improved by the energy drink
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need answer for this +explanation
______________________________
A = L × B × H = 2 × 2 × 5= 20in²______________________________
The following transactions are taken from the record of ABC
(a) Commenced business with cash of Rs. 1,00,000 and Machine of Rs. 50,000.
(b) Purchased goods for cash Rs. 30,000 and credit Rs. 10,000.
(c) Sold goods for cash Rs. 25,000 and credit Rs. 15,000.
(d)
Goods taken by the owner for private use Rs. 2,000.
Cash paid to creditors Rs 8,000.
(e)
(f) Cash received from debtors Rs. 14,500 in full settlement.
(g) Received a loan of Rs. 5,000 from Mr. Dipendra.
(h) He introduced additional capital Rs. 40,000.
Required: Accounting equation
Ans: A = Rs. 1,94,500, C= Rs. 1,87,500, L = Rs. 7,000
The accounting equation is:
Assets = Rs. 2,19,500
Liabilities = Rs. 1,000
Capital = Rs. 2,10,500
How to determine the accounting equationThe accounting equation is:
Assets = Liabilities + Capital
(a) Commenced business with cash of Rs. 1,00,000 and Machine of Rs. 50,000.
Assets = Cash + Machine = Rs. 1,00,000 + Rs. 50,000 = Rs. 1,50,000
(b) Purchased goods for cash Rs. 30,000 and credit Rs. 10,000.
Assets = Cash + Inventory = Rs. 1,30,000
Liabilities = Accounts Payable = Rs. 10,000
(c) Sold goods for cash Rs. 25,000 and credit Rs. 15,000.
Assets = Cash + Accounts Receivable + Inventory = Rs. 1,70,000
Liabilities = Accounts Payable = Rs. 10,000
(d) Goods taken by the owner for private use Rs. 2,000.
Assets = Cash + Accounts Receivable + Inventory - Drawings = Rs. 1,68,000
(e) Cash paid to creditors Rs 8,000.
Assets = Cash + Accounts Receivable + Inventory - Drawings = Rs. 1,60,000
Liabilities = Accounts Payable - Rs. 8,000 = Rs. 2,000
(f) Cash received from debtors Rs. 14,500 in full settlement.
Assets = Cash + Inventory - Drawings = Rs. 1,74,500
Liabilities = Accounts Payable - Rs. 8,000 = Rs. 2,000
Capital = Rs. 1,70,500
(g) Received a loan of Rs. 5,000 from Mr. Dipendra.
Assets = Cash + Inventory - Drawings = Rs. 1,79,500
Liabilities = Accounts Payable - Rs. 8,000 + Loan Payable Rs. 5,000 = Rs. 1,000
Capital = Rs. 1,74,500
(h) He introduced additional capital Rs. 40,000.
Assets = Cash + Inventory - Drawings = Rs. 2,19,500
Liabilities = Accounts Payable - Rs. 8,000 + Loan Payable Rs. 5,000 = Rs. 1,000
Capital = Rs. 2,10,500
Therefore, the accounting equation is:
Assets = Rs. 2,19,500
Liabilities = Rs. 1,000
Capital = Rs. 2,10,500
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12,59,294,1469,7344 what is the pattern rule
Both equations give the correct terms, so we can conclude that the pattern rule is: [tex]an^2 - 131n + 80[/tex] , where [tex]a=63[/tex] .
What is the consecutive terms?To find the pattern rule for the given sequence 12, 59, 294, 1469, 7344, we need to observe the differences between consecutive terms. Let's find the differences between each pair of terms:
[tex]59 - 12 = 47[/tex]
[tex]294 - 59 = 235[/tex]
[tex]1469 - 294 = 1175[/tex]
[tex]7344 - 1469 = 5875[/tex]
The differences are not constant, so we need to find the differences between these differences:
[tex]235 - 47 = 188[/tex]
[tex]1175 - 235 = 940[/tex]
[tex]5875 - 1175 = 4700[/tex]
Now, the second differences are constant (equal to 940), which suggests that the pattern rule is a quadratic equation. Let's assume the pattern rule is of the form:
[tex]an^2 + bn + c[/tex]
where n is the term number (starting with n=1 for the first term).
To find the coefficients a, b, and c, we can use the first three terms of the sequence. Let's substitute n=1,2,3 into the equation and equate it to the corresponding terms:
[tex]a + b + c = 12 (for n=1)[/tex]
[tex]4a + 2b + c = 59 (for n=2)[/tex]
[tex]9a + 3b + c = 294 (for n=3)[/tex]
We can solve these equations simultaneously to get the values of a, b, and c:
[tex]a = 63[/tex]
[tex]b = -131[/tex]
[tex]c = 80[/tex]
Therefore, the pattern rule for the sequence is:
[tex]an^2 - 131n + 80[/tex]
where a=63.
To check if this pattern rule works for the other terms of the sequence, we can substitute n=4 and n=5:
[tex]a(4^2) - 131(4) + 80 = 1469[/tex]
[tex]a(5^2) - 131(5) + 80 = 7344[/tex]
Therefore, Both equations give the correct terms, so we can conclude that the pattern rule is:
[tex]an^2 - 131n + 80, where a=63.[/tex]
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P(JIK) = 0.35, P(KJ) = 0.95, P(K) = 0.3
What is P(J)?
O 0.1105
O 0.8143
O 0.8895
O 0.1857
The conditional value probability is solved and P ( J ) = 0.1105
Given data ,
P(JIK) = 0.35, P(KJ) = 0.95, P(K) = 0.3
We can use Bayes' theorem to find P(J):
P(J | K) = P(K | J) * P(J) / P(K)
0.35 = 0.95 * P(J) / 0.3
0.35 * 0.3 = 0.95 * P(J)
0.105 = 0.95 * P(J)
P(J) = 0.105 / 0.95
P(J) = 0.1105
Hence , the probability is P ( J ) = 0.1105
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what is the suface area of 11cm and 14cm
Answer:
429 i think
Step-by-step explanation:
Statistics Help, pls help me
A nationwide award for high school students is given to outstanding students who are sophomores, juniors, or seniors (freshmen are not eligible). Of the award-winners, 65 percent are SENIORS, 23 percent JUNIORS, and 12 percent are SOPHOMORES.
a) The probability of selecting exactly 3 award-winners before selecting a SENIOR is 0.078875
b)The probability of selecting more than 2 award-winners before selecting a JUNIOR is 0.135437
c)The probability of selecting 2 or fewer award-winners before selecting a SOPHOMORE is 0.252744
Define probabilityProbability is a measure of the likelihood or chance of an event occurring. It is a numerical value between 0 and 1, where 0 indicates that the event is impossible, and 1 indicates that the event is certain to occur.
(a) The probability of selecting a SENIOR is 0.65, and the probability of not selecting a SENIOR is 0.35.
Since we are selecting award-winners until we select a SENIOR, the first two selections must not be SENIORS, and the third selection must be a SENIOR.
the probability of selecting exactly 3 award-winners before selecting a SENIOR is:
P(not SENIOR) x P(not SENIOR) x P(SENIOR) = 0.35 x 0.35 x 0.65 = 0.078875
(b)Therefore, the probability of selecting more than 2 award-winners before selecting a JUNIOR is:
P(not JUNIOR) x P(not JUNIOR) x P(JUNIOR) = 0.77 x 0.77 x 0.23 = 0.135437
To find the probability of selecting more than 2 award-winners, we can subtract this value from 1, since the only other possibility is selecting exactly 2 award-winners before selecting a JUNIOR:
P(more than 2) = 1 - P(exactly 2) = 1 - (P(not JUNIOR) x P(JUNIOR) x P(not JUNIOR)) = 1 - (0.77 x 0.23 x 0.77) = 0.567911
(c) The probability of selecting a SOPHOMORE is 0.12, and the probability of not selecting a SOPHOMORE is 0.88.
Since we are selecting award-winners until we select a SOPHOMORE, we can keep selecting SENIORS and JUNIORS until we select a SOPHOMORE.
Therefore, the probability of selecting 2 or fewer award-winners before selecting a SOPHOMORE is:
P(SOPHOMORE) + P(not SOPHOMORE) x P(JUNIOR) x P(SOPHOMORE) + P(not SOPHOMORE) x P(not JUNIOR) x P(JUNIOR) x P(SOPHOMORE) = 0.12 + (0.88 x 0.23 x 0.12) + (0.88 x 0.77 x 0.23 x 0.12) = 0.252744
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In ΔFGH, g = 910 cm,
m∠G=98° and
m∠H=51°. Find the length of h, to the nearest 10th of a centimeter.
In ΔFGH, the length of h is 714.2 cm
Let us assume that in ΔFGH, f represents the opposite side to angle F, g represents the opposite side to angle G, and h represents the opposite side to angle H.
Consider the following figure.
Using sine rule for triangle FGH,
sin F/f = sin G/g = sin H/h
Consider equation sin G/g = sin H/h
sin(98°) / 910 = sin(51°) / h
We solve this equation for h.
h = (sin(51°) × 910)/ sin(98°)
h = (0.777 × 910)/ 0.99
h = 714.21
h = 714.2 cm
This is the required length of h.
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Pre calculus trigonometry
The result of the division of the two complex numbers is equal to z₁ / z₂ = (8 / 9) · [cos (π / 10 - π / 12) + i sin (π / 10 - π / 12)].
How to find the division of two complex numbers
In this problem we find two complex numbers in rectangular form, whose division must be found. This can done by easily by means of complex numbers in polar form and definition of division:
Complex number (rectangular form)
z = r · (cos θ + i sin θ)
Complex number (polar form)
[tex]z = r\cdot e^{i\cdot \theta}[/tex]
Where:
r - Normθ - DirectionDivision between two complex numbers in polar form:
[tex]\frac {z_{1}}{z_{2}} = \left(\frac{r_{1}}{r_{2}}\right)\cdot e^{i\cdot (\theta_{1}-\theta_{2})}[/tex]
This number is equivalent to the following expression in rectangular form:
z₁ / z₂ = (r₁ / r₂) · [cos (θ₁ - θ₂) + i sin (θ₁ - θ₂)]
If we know that r₁ = 8, r₂ = 9, θ₁ = π / 10 and θ₂ = π / 12, then the division of the two complex numbers is:
z₁ / z₂ = (8 / 9) · [cos (π / 10 - π / 12) + i sin (π / 10 - π / 12)]
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Seven days a year, Tiger Stadium becomes the fifth largest city in the state of Louisiana. Over 92,000 fans pack the stadium to watch the Tigers play. After the game, if the fans leave at a rate of 10% per minute, how long will it take before the stadium is half empty?
1. Find the data using at least 10 numbers in the x column.
2. Create a scatter plot. Label the graph and show increments.
3. Write an exponential equation.
4. Interpret the meaning of the "a" and "b" in your function y=ab^x including the units.
5. Find out how long it will take before the stadium is half empty and all the way empty.
Find relative extrema (x, y) of a function h(x) = x^3 + 3x^2 − 2 using
(a) the first derivative test
(b) the second derivative test
Which test is easiest?
a) Based on the first derivative test, h(x) has a relative minimum at x = -2 and a relative maximum at x = 0.
b) For x = -2: h''(-2) = 6(-2) + 6 = -6 < 0, so h(x) has a relative maximum at x = -2.
For x = 0: h''(0) = 6(0) + 6 = 6 > 0, so h(x) has a relative minimum at x = 0.
What is the calculus?Calculus is a branch of mathematics that deals with the study of rates of change, accumulation, and the properties and behavior of functions.
(a) First derivative test:
The first derivative test involves finding the critical points of the function, where the first derivative is equal to zero or undefined, and then checking the sign of the first derivative in the intervals between the critical points to determine whether the function has relative extrema at those points.
Find the first derivative of h(x):
h'(x) = 3x² + 6x
Set h'(x) = 0 and solve for x to find the critical points:
3x² + 6x = 0
x(x + 2) = 0
x = 0 or x = -2
Test the intervals between the critical points using the sign of the first derivative:
For x < -2: Choose x = -3, h'(-3) = 27 + (-18) = 9 > 0, so h(x) is increasing.
For -2 < x < 0: Choose x = -1, h'(-1) = 3 - 6 = -3 < 0, so h(x) is decreasing.
For x > 0: Choose x = 1, h'(1) = 3 + 6 = 9 > 0, so h(x) is increasing.
Based on the first derivative test, h(x) has a relative minimum at x = -2 and a relative maximum at x = 0.
(b) Second derivative test:
The second derivative test involves finding the critical points of the function using the first derivative, and then checking the sign of the second derivative at those points to determine whether the function has relative extrema at those points.
Find the second derivative of h(x):
h''(x) = 6x + 6
Evaluate the second derivative at the critical points found in step 2 of the first derivative test:
For x = -2: h''(-2) = 6(-2) + 6 = -6 < 0, so h(x) has a relative maximum at x = -2.
For x = 0: h''(0) = 6(0) + 6 = 6 > 0, so h(x) has a relative minimum at x = 0.
Hence, the ease of a test may vary for different individuals and their familiarity with calculus concepts.
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What is the equation through the points: (-7, -3), (1, 2)
ASAP please
The equation of the line passing through the points (-7, -3) and (1, 2) is [tex]y = \frac{5}{8}x + \frac{11}{8}[/tex].
What is the equation of the line?The formula for equation of line is expressed as;
y = mx + b
Where m is slope and b is y-intercept.
First, we determine the slope of the line.
Given the two points are (-7, -3) and (1, 2)
We can find the slope of the line by using the slope formula:
m = ( y₂ - y₁ ) / ( x₂ - x₁ )
Substituting the values, we get:
m = (2 - (-3)) / (1 - (-7))
m = 5/8
Using the point-slope form, plug in one of the given points and slope m = 5/8 to find the equation of the line.
Let's use the point (-7, -3:
y - y₁ = m(x - x₁)
[tex]y - (-3) = \frac{5}{8}( x - (-7) ) \\\\y + 3 = \frac{5}{8}(x + 7 )\\\\y + 3 = \frac{5}{8}x + \frac{35}{8} \\ \\y = \frac{5}{8}x + \frac{35}{8} - 3\\\\y = \frac{5}{8}x + \frac{11}{8}[/tex]
Therefore, the equation of the line is [tex]y = \frac{5}{8}x + \frac{11}{8}[/tex].
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Given (x – 7)2 = 36, select the values of x. x = 13 x = 1 x = –29 x = 42
The solution for x in the equation (x – 7)^2 = 36 are x = 13 and x = 1
Solving for x in the equationWe can solve for x by taking the square root of both sides of the equation:
(x – 7)^2 = 36
Taking the square root of both sides:
x - 7 = ±6
Adding 7 to both sides:
x = 7 ± 6
Therefore, the values of x are:
x = 7 + 6 = 13
x = 7 - 6 = 1
So the correct answers are x = 13 and x = 1. The values x = -29 and x = 42 are not solutions to the equation.
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The amount of money in a saving account increases bu D. 2% every month
Write a function for the amount of money in the accounts, after t months with an initial deposit of tr $ 100
By what' factor does the amount in the account increases ever meant every year?
The exponential function giving the balance of the account after t months is:
[tex]y = 100(1.02)^t[/tex]
The yearly growth factor is given as follows:
26.82%.
How to define an exponential function?An exponential function has the definition presented as follows:
[tex]y = ab^x[/tex]
In which the parameters are given as follows:
a is the value of y when x = 0.b is the rate of change.The parameter values for this problem are given as follows:
a = 100 -> initial deposit.b = 1.02 -> increase of 2% every month -> 1 + 0.02 = 1.02.Hence the function is:
[tex]y = 100(1.02)^t[/tex]
The yearly growth factor can be obtained as follows:
[tex](1.02)^{12} = 1.2682[/tex]
Increase of 26.82% each year, which is composed by 12 months.
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Need help with this question. Been stuck on this for 20 mins.
Answer:
see below
Step-by-step explanation:
The Reason for #1 is literally GIVEN to you.
Statement #2: Since the Base Angles of an isosceles triangle are congruent, this statement should be ∠CAB≅∠CBA.
Reason #3: Notice that the statement repeats itself (AB=AB). This demonstrates the REFLEXIVE property.
Reason #4: (Clue) Note which items have been Given or Proven congruent and use it as the triangle congruence property. It helps to actually mark them. Your choices are SSS, SAS, ASA, and AAS.
Reason #5: (Clue) Since the triangles of which AM and BN are of part are now proven congruent, these Corresponding Parts are Congruent as well.
The formula v= √√2gh gives the velocity v, in feet per second, of an object after it falls h feet accelerated by gravity g, in feet
per second squared. If g is approximately 32 feet per second squared, find how far an object has fallen if its velocity is 96 feet
per second.
We can rearrange the formula to solve for h:
v = √√2gh
Squaring both sides: v^2 = 2gh
Dividing both sides by 2g: h = v^2 / 2g
Substituting v = 96 ft/s and g = 32 ft/s^2, we get:
h = (96 ft/s)^2 / (2 × 32 ft/s^2)
h = 288 ft
Therefore, the object has fallen 288 feet.
A line passes through the points (8,8) and (5,2). What is its equation in slope-intercept form?
Step-by-step explanation:
m=y1-y2/x1-x2
m=2-8/5-8
m=-6/-3
m=2
y=m(x-x1)+y1
y=m(x-8)+8
y=2x-16+8
y=2x-22
Answer: Y=mx+c
Step-by-step explanation:
The Slope-Intercept Form can be written in the form: y = mx + c Where “m” is the slope of the line “c” is the y-intercept of the equation of the line
where should the linear inequality y ≤ 3/2x + 3 be shaded?
Answer:
Step-by-step explanation:
it should be shaded at the 76
Can someone help me I dont understand this :(
Check the picture below.
solve for x, neg x over 4 = 12 A 48 or B -3 or C 3 or D -48?
The solution for x is -48, the answer is D) -48.
What is Algebraic expression ?
An algebraic expression is a mathematical phrase that contains variables, constants, and mathematical operations such as addition, subtraction, multiplication, and division. It represents a value that can change based on the values assigned to the variables.
Starting with:
x:4 = 12
Multiplying both sides by -1 gives:
(-x÷4) = -12
Simplifying the left side:
x÷4 = -12
Multiplying both sides by 4 gives:
x = -48
Therefore, the solution for x is -48, the answer is D) -48.
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Solve for w.
w − 5
4
= 2
The value of the variable w is 56
What are algebraic expressions?Algebraic expressions are described as expressions that are composed of terms, variables, factors, coefficients and constants.
Also, algebraic expressions are made up of mathematical or arithmetic operations, such as;
AdditionBracketSubtractionParenthesesMultiplicationDivisionFrom the information given, we have the algebraic equation as;
w - 54 = 2
To determine the value of the variable, we take the steps;
collect the like terms
w = 2 + 54
Now, add the values
w = 56
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Evaluate the determinant
1
03
03
0)2
w2
1 , where w is a cube root
co
2 1 o
of unity.
In this case, the cube root is = 0
Why is this so?We can use the rule Sarrus to evaluate the determinant
1 w w²
w w² 1
w² 1 w
Starting with the first column, we can wrte out the terms for the diagonal products and
then sum the terms for the products of the diagonal elements that wrap around
(1 x w² x w) +(w x 1 x w²) + (w² x w x w) - (w ² x w x 1) - (w x w² x w) - (1 x w x w ²)
Simplifying each term:
w³ + w³ + w³ - w³ -w³ - w³
We can see that all the terms cancel out, leaving us with a determinant of 0. So it is clear that
|1 w w²|
|w w² 1 |
|w² 1 w | = 0
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Full Question:
Although part of your question is missing, you might be referring to this full question:
Evaluate the determinant 1 w w2 , w w2 1, w2 1 w. where w is a cube root of unity.
If 86
is added to a number, the result is 44
less than three times the number. Find the number.
Answer:
x = 65
Step-by-step explanation:
let the number be 'x'.
If 86 is added to a number, the result is 44 less than three times the number. Therefore the equation will be,
=> 86 + x = 3x - 44
Rearranging,
=> x - 3x = -44 - 86
=> -2x = -130
=> x = 130/2
=> x = 65
Two mechanics worked on a car. The first mechanic worked for 20 hours, and the second mechanic worked for 15 hours. Together they charged a total of $2600. What was the rate charged per hour by each mechanic if the sum of the two rates was $155
per hour?
the first mechanic charged $55 per hour and the second mechanic charged $100 per hour. we solve this by forming equation by by given data.
what is equation ?
An equation is a mathematical statement that shows that two expressions are equal. It typically consists of two sides separated by an equal sign (=). The expressions on each side of the equal sign can contain variables,
In the given question,
Let's assume that the first mechanic charged x dollars per hour and the second mechanic charged y dollars per hour.
From the problem, we know that:
The first mechanic worked for 20 hours, so he charged 20x dollars.
The second mechanic worked for 15 hours, so he charged 15y dollars.
Together, they charged a total of $2600, so we have:
20x + 15y = 2600
The sum of the two rates was $155 per hour, so we have:
x + y = 155
We can use these two equations to solve for x and y. First, we can rewrite the second equation as:
y = 155 - x
Then, we can substitute this expression for y into the first equation:
20x + 15(155 - x) = 2600
Simplifying and solving for x, we get:
20x + 2325 - 15x = 2600
5x = 275
x = 55
Now that we know x, we can use the second equation to find y:
y = 155 - x = 155 - 55 = 100
Therefore, the first mechanic charged $55 per hour and the second mechanic charged $100 per hour.
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Function f is an exponential function. It predicts the value of a famous painting, in thousands of dollars, as a function of the number of years since it was last purchased.
What equation models this function?
ANSWER: 8(1.25)x just took the test
Answer:
[tex]f(t) = 8e^{0.223144t}[/tex]
if you help I would be so thankful
Answer:
I put the answer on the attachment please look
‼️‼️‼️‼️WILL MARK BRAINLIEST‼️‼️‼️‼️
Answer:
S = 2π(14^2) + 2π(14)(154)
= 2π(196) + 2π(2,156)
= 4,704π = 14,778.1 ft^2
Using 3.14 for π:
S = 4,704(3.14) = 14,770.6 ft^2
the set of five number each of which is divisible by 3
Answer:
{3, 6, 9, 12, 15}
Each of these numbers is divisible by 3
Step-by-step explanation:
Consider the graph of the function f(x)=(1/4)^x
Which statements describe key features of function f?
The horizontal asymptotes of the function is y = 0 and the y-intercepts is (0, 1).
What is graph of exponential functionAn exponential graph is a curve that represents an exponential function. An exponential graph is a curve that has a horizontal asymptote and it either has an increasing slope or a decreasing slope. i.e., it starts as a horizontal line and then it first increases/decreases slowly and then the growth/decay becomes rapid.
In this problem, the graph of the function f(x) = (1/4)ˣ is attached below the question and the characteristics of the graph are;
1. The domain of the function is {x|x ∈ R}
2. The range of the function is {y|y > 0}
3. The horizontal asymptotes is y = 0
4. The x-intercepts does not exists
5. The y-intercepts are (0, 1)
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Question 7(Multiple Choice Worth 1 points)
(07.04 HC)
Right triangle ABC is located at A (-1, -2), B (-1, 1), and C (-5, 1) on a coordinate plan
O (x + 1)2 + (y + 2)² = 9
O (x + 5)² + (1)² = 16
O(x + 1)2 + (y + 2)² = 25
O(x + 5)² + (y-1)² = 25
Answer:
O (x + 1)2 + (y + 2)² = 9
Step-by-step explanation:
This is because the distance between points A and B is 3 units, and the distance between points B and C is 4 units, making the triangle a 3-4-5 right triangle. Point B is located at (-1, 1), which is 3 units away from point A (-1, -2) and 4 units away from point C (-5, 1). Therefore, the circle with center (-1, -2) and radius 3 would pass through point B, and its equation would be:
(x + 1)2 + (y + 2)² = 3²
(x + 1)2 + (y + 2)² = 9