Answer:
Using 3 periods to get an accurate reading:
3T = (6.40 S - 0.90 s) = 5.50 S So, T = 1.83 s
m = 0.250 kg
Using algebra:
k= [tex]\frac{4\pi ^{2}m }{T^{2} }[/tex]=[tex]\frac{4\pi ^{2}0.250 }{1.90^{2} }[/tex]=2.95kg/sec
Kim is ice-skating going 4.6 m/s. What is her velocity after 10 seconds ?
This is a uniform rectilinear motion (MRU) exercise.
To start solving this exercise, we obtain the following data:
Data:v = 4.6 m/sd = ¿?t = 10 secTo calculate distance, speed is multiplied by time.
We apply the following formula: d = v * t.
We substitute the data in the formula: the speed is equal to 4.6 m/s, the time is equal to 10 s, which is left as follows:
[tex]\bf{d=4.6\dfrac{m}{\not{s}}*10\not{s} }[/tex]
[tex]\bf{d=46 \ m}[/tex]
Therefore, the speed at 10 seconds is 46 meters.
[tex]\huge \red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]
A satellite completes one revolution of a planet in almost exactly one hour. At the end of one hour, the satellite has traveled 2.0 × 107 meters and is only 10 meters away from its starting point. What is the numerical value of the satellite's average velocity after that one hour?
Answer:
shown below
Explanation:
2 x 10⁷ as a number is 20,000,000
20,000,000 - 10 = 19,999,990
It went 19,999,990 m/h
in km/h:
19,999,990 / 1000 = 19,999.99 km/h
in km/s
19,999,990 / 3,600,000 = ~5.56 km/s
in m/s
19,999,990 / 3600 = ~5555.56 m/s
Wavelength is determined by dividing a wave's speed by its frequency. If a wave has a frequency of 1 hertz and a speed of 20 m/s, what is its wavelength?
Select one:
a. 80 m
b. 5 m
c. 0.05 m
d. 20 m
Answer:
D. 20m
Explanation:
this answer is 20 m.
wavelength = velocity / frequency
Name the inertia in the following cases.
A passenger jumping out of a moving bus falls forward.
Answer:
inertia of motion
Explanation:
it's because when a passenger is jumping from a bus his/her body is in motion after falling in a road he/she remains or tends to remain in the state of motion that is the reason
state how the centripetal force is provided in a c held on a playground roundabout
The centripetal force is obtained by its formulas is,[tex]\rm F_C= \frac{mv^2}{r}[/tex]
What is centripetal acceleration?The acceleration needed to move a body in a curved way is understood as centripetal acceleration.
The direction of centripetal acceleration is always in the path of the center of the course. The total acceleration is the result of tangential and centripetal acceleration.
The formula for the centripetal force is ;
[tex]\rm F_C= \frac{mv^2}{r}[/tex]
Where,
r is the radius
v is the linear speed
m is the mass of an object
Hence, the centripetal force obtained by its formulas as,[tex]\rm F_C= \frac{mv^2}{r}[/tex]
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Which is the correct unit for electrical power?
Answer:
As electrical power is measured in Watts (W), therefore it must be also be measured in Joules per Second. So we can correctly say that: 1 watt = 1 joule per second (J/s).
Explanation:
Calculate the approximate number of atoms in a bacterium, assuming the average mass of an atom is ten times the mass of a hydrogen atom. The mass of a bacterium is 10−15 kg and the mass of a hydrogen atom is of the order of 10−27 kg.
atoms
10¹¹ is the approximate number of atoms in a bacterium.
What do you understand by mass of element?
The atomic mass of an element is the average mass of the atoms of an element measured in atomic mass unit (amu).
Given,
Mass of a bacterium atom = 10⁻¹⁵ kg.
Mass of a hydrogen atom = 10⁻²⁷ kg.
From the above observation ,
The average mass of an atom of the bacterium is ten times the mass of a hydrogen atom.
Atomic mass 1 bacterium atom = 10 x mass of hydrogen atom
= 10 x 10⁻²⁷ kg.
= 10⁻²⁶ kg.
Thus,
The number of atoms in a bacterium
= [tex]\frac{Total mass}{Atomicmass of 1 bacterium}[/tex]
= [tex]\frac{10^{-15} }{10^{-26} }[/tex]
= [tex]10^{11}[/tex]
The approximate number of atoms in a bacterium is [tex]10^{11}[/tex].
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What is temperature?
A. A type of heat transfer
ANUN
B. The measure of an object's "hotness"
APATIN
HERRE
C. Electromagnetic waves
Digita
D. The energy transferred between objects
H
The term temperature has to do with the measure of an object's "hotness".
What is temperature?The term temperature has to do with how hot or cold a body is. In other words, the word temperature brings us to call to mind the degree of hotness or coldness of a body.
Succinctly put, the term temperature has to do with the measure of an object's "hotness".
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One endpoint of a line segment is (1, 2) and the midpoint of the line segment is
(−1, 4). What is the other endpoint?
It then can be stated:
[tex]\large\red\hookrightarrow \rm \large \: \:X_m \: = \: \frac{X_1 \: + \: \: X_2 }{2} \: \: \: \: \: \: \: \:... (1) \\ [/tex]
[tex]\large\red\hookrightarrow \rm \large \: \:Y_m \: = \: \frac{Y_1 \: + \: \: Y_2 }{2} \: \: \: \: \: \: \: \:... (2)\\ [/tex]
Since, Xm = -1 and X1 = 1 we can write equation (1) as
[tex]\large\purple\longrightarrow \rm \large \: \:-1 \: = \: \frac{1 \: + \: \: X_2 }{2} \: \: \: \: \: \: \: \:... (1) \\ [/tex]
[tex]\large\purple\longrightarrow \rm \large \: \:-2 \: = \:1 \: + \: X_2[/tex]
[tex]\large\purple\longrightarrow \rm \large \: \: - 2 \: - 1 \: = \: X_2[/tex]
[tex]\large\purple\longrightarrow \rm \large \: \: - 3 \: = \: X_2[/tex]
Since , Ym = 4 and Y1 = 2 we can write the equation (2) as
[tex]\large\purple\longrightarrow \rm \large \: \:4 \: = \: \frac{2 \: + \: \: Y_2 }{2} \: \: \: \: \: \: \: \:... (2)\\ [/tex]
[tex]\large\purple\longrightarrow \rm \large \: \:8 \: = \: 2 \: + \: Y_2[/tex]
[tex]\large\purple\longrightarrow \rm \large \: \:8 \: - \: 2 \: = \: Y_2[/tex]
[tex]\large\purple\longrightarrow \rm \large \: \:6 \: = \: Y_2[/tex]
Therefore the other endpoint of the line (X2, Y2) is (-3 , 6)
3
012 10.0 points
A car with mass 1060 kg crashes into a wall.
The car's velocity immediately before the col-
lision was 14.6 m/s and the bumper is com-
pressed like a spring with spring constant
1.14 × 107 N/m.
What is the maximum deformation of the
bumper for this collision?
Answer in units of m.
013 10
Hi there!
The maximum deformation of the bumper will occur when the car is temporarily at rest after the collision. We can use the work-energy theorem to solve.
Initially, we only have kinetic energy:
[tex]KE = \frac{1}{2}mv^2[/tex]
KE = Kinetic Energy (J)
m = mass (1060 kg)
v = velocity (14.6 m/s)
Once the car is at rest and the bumper is deformed to the maximum, we only have spring-potential energy:
[tex]U_s = \frac{1}{2}kx^2[/tex]
k = Spring Constant (1.14 × 10⁷ N/m)
x = compressed distance of bumper (? m)
Since energy is conserved:
[tex]E_I = E_f\\\\KE = U_s\\\\\frac{1}{2}mv^2 = \frac{1}{2}kx^2[/tex]
We can simplify and solve for 'x'.
[tex]mv^2 = kx^2\\\\x = \sqrt{\frac{mv^2}{k}}[/tex]
Plug in the givens and solve.
[tex]x = \sqrt{\frac{(1060)(14.6^2)}{(1.14*10^7)}} = \boxed{0.0198 m}[/tex]
when energy is transferred from one part of a system to another, some of the energy is lost during the transfer and cannot be used as it was intended. Which two sentences describes examples of this?
Sentences A and D describe examples of energy transformation.Heat is produced when a car's tires rub against the pavement and as electricity passes across power wires, they become hotter.
What is the law of conservation of energy?According to the law of conservation of energy, the energy of an isolated system stays unchanged throughout time.it is said to be conserved.
Energy cannot be created nor destroyed and can be transferred from one form to the other form.
The complete question is
"When energy is moved from one component of a system to another, some of the energy is lost and cannot be used as planned.
Which two statements provide examples?
A. Friction between a car's tires and the road produces heat.
B. Sunlight strikes a solar panel, generating electricity.
c. Stereo speakers emit a sound when powered by electrical energy,
D. Wind moves a turbine, generating electricity.
I E. Power lines heat up as electricity flows through them."
Some of the energy wasted during the movement of energy from one section of a system to another is heat is produced by friction between a car's tires and the road and as electricity passes via power lines, they heat up.
Hence, sentences A and D describe examples of energy transformation.
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A small mass m slides with negligible friction down an incline at an angle of 25.76° with respect to the horizontal. It then drops down to a horizontal surface and bounces elastically back up as shown.
The picture is to scale. It shows the position of the mass at equal time intervals starting from rest at T. The height of the mass at X is the same as at V. Click here to view the motion of the mass m.
(options are: less than, greater than, equal to)
• The speed change between T and S is (blank) between S and R.
• The speed of m at X is (blank) that at Q.
• The size of the total force on m at P is (blank) at U.
• The mechanical energy of m at P is (blank) that at V.
• The size of the total force on m at S is (blank) at P.
• The velocity of m at X is (blank) that at V.
• The speed change between T and S is greater between S and R.
• The speed of m at X is greater that at Q.
• The size of the total force on m at P is less at U.
• The mechanical energy of m at P is equal to that at V.
• The size of the total force on m at S is greater at P.
• The velocity of m at X is equal to that at V.
What is mechanical energy?The mechanical energy is the sum of kinetic energy and the potential energy of an object at any instant of time.
M.E = KE +PE
Given is a small mass m slides with negligible friction down an incline at an angle of 25.76° with respect to the horizontal. It then drops down to a horizontal surface and bounces elastically back up as shown.
The picture shows the position of the mass at equal time intervals starting from rest at T. The height of the mass at X is the same as at V.
Between T to S and S to R, the mass is under constant acceleration. Time taken to move from T to S is greater than S to R. Thus, the speed change between T and S is greater than between S and R.
At Q, there is only a horizontal velocity component, but at X. the speed will be greater and has both vertical and horizontal component. Thus, the speed of m at X is greater than that at Q.
Force is given as the rate of change of momentum with time. At U, change in momentum is large compared to P. Thus, the size of the total force on m at P is less at U.
There is no friction acting on the system. So the energy remains conserved. Mechanical energy at P = V.
The force on mass m at S is only the gravity force. The remaining forces are cancelled by the normal force. Thus, size of the total force on m at S is greater at P.
The energy is conserved at each point of motion of mass. If X and V are at same height, they have same potential energy and so their kinetic energy. Thus, velocity of m at X is equal to that at V.
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An elevator is moving in an upwards direction. The free body diagram for the forces acting on the elevator during this time is: The motion of the elevator can best be described as:
The motion of the elevator can best be described as motion against gravity with negative acceleration.
What is motion?Motion refers to a change in position of an object when it moves from one point another along a reference frame.
An object moving in a downward direction is moving in a positive direction and its velocity increases relative to the earth since gravity acts downwards.
An object moving in a upward direction is moving in a negative direction and its velocity decreases relative to the earth since gravity acts downwards.
Therefore, the motion of the elevator can best be described as motion against gravity with negative acceleration.
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Lesson 1, What is Physical Science.
Write an expository essay explain the difference between scientific knowledge and other kinds of science, include ideas regarding:
1) the scientific method.
2) true science versus false science.
3) examples of what scientists study and do not study.
4) what is required for a scientist to consider an idea to be true.
Physical science explains the physical world and not supernatural events and an idea is considered true by science if it can be observed, explained and reproduced by others.
What is physical science?
Physical science is a systematic study of the of the physical world and phenomena based on observation and experiments.
The scientific method involves:
observation and questionshypothesisexperimentsresults and further experimentstheories and lawsScience explains the physical world and not supernatural events.
Science studies physical phenomena such as the stars, the planets, living things, etc.
Science do not study about angels or demons or supernatural events.
An idea is considered true by science if it can be observed, explained and reproduced by others.
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A squirrel sitting on the ground starts to run with an acceleration of 5.1 m/s².
How fast is the squirrel going after 0.25 seconds?
O A. 20.4m/s
OB. 0.49 m/s
OC. 3.1 m/s
OD. 1.28 m/s
Answer:
0.159
Explanation:
the formula to find its is 1÷2*gt^2
Answer:
D
Explanation:
v= a t
= 5.1 * .25 = 1.275 m/s
If the frequency of a FM wave is 8.85 × 107 hertz, what is the period of the FM wave?
Answer:
1.1299 x 10^-8 second
Explanation:
Period = 1 / f = 1 / (8.85 * 10^7) = 1.1299 x 01^-8 sec
The half-life of Iodine-131 is 8.0252 days. If 14.2 grams of I-131 is released in Japan and takes 31.8 days to travel across the Pacific, how much I-131 will be left by the time it reaches California?
Answer:
Explanation:
Half-life problems are modeled as exponential equations. The half-life formula is [tex]P=P_o\left (\dfrac{1}{2} \right)^{\frac{t}{k}}[/tex] where [tex]P_o[/tex] is the initial amount, [tex]k[/tex] is the length of the half-life, [tex]t[/tex] is the amount of time that has elapsed since the initial measurement was taken, and [tex]P[/tex] is the amount that remains at time [tex]t[/tex].
[tex]P=14.2\left (\dfrac{1}{2} \right)^{\frac{t}{8.0252}}[/tex]
Deriving the half-life formula
If one forgets the half-life formula, one can derive an equivalent equation by recalling the basic an exponential equation, [tex]y=a b^{t}[/tex], where [tex]t[/tex] is still the amount of time, and [tex]y[/tex] is the amount remaining at time [tex]t[/tex]. The constants a and b can be solved for as follows:
Knowing that amount initially is 14.2g, we let this be time zero:
[tex]y=a b^{t}[/tex]
[tex](14.2)=ab^{(0)}[/tex]
[tex]14.2=a *1[/tex]
[tex]14.2=a[/tex]
So, [tex]a=14.2[/tex], which represents out initial amount of the substance, and our equation becomes: [tex]y=14.2 b^{t}[/tex]
Knowing that the "half-life" is 8.0252 days (note that the unit here is "days", so times for all future uses of this equation must be in "days"), we know that the amount remaining after that time will be one-half of what we started with:
[tex]\left(\frac{1}{2} *14.2 \right)=14.2 b^{(8.0252)}[/tex]
[tex]\dfrac{7.1}{14.2}=\dfrac{14.2 b^{8.0252}}{14.2}[/tex]
[tex]0.5=b^{8.0252}[/tex]
[tex]\sqrt[8.0252]{\frac{1}{2}}=\sqrt[8.0252]{b^{8.0252}}[/tex]
[tex]\sqrt[8.0252]{\frac{1}{2}}=b[/tex]
Recalling exponent properties, one could find that [tex]\left ( \frac{1}{2} \right )^{\frac{1}{8.0252}}=b[/tex], which will give the equation identical to the half-life formula. However, recalling this trivia about exponent properties is not necessary to solve this problem. One can just evaluate the radical in a calculator:
[tex]b=0.9172535661...[/tex]
Using this decimal approximation has advantages (don't have to remember the half-life formula & don't have to remember as many exponent properties), but one minor disadvantage (need to keep more decimal places to reduce rounding error).
So, our general equation derived from the basic exponential function is:
[tex]y=14.2* (0.9172535661)^t[/tex] or [tex]y=14.2*(0.5)^{\frac{t}{8.0252}}[/tex] where y represents the amount remaining at time t.
Solving for the amount remaining
With the equation set up, substitute the amount of time it takes to cross the Pacific to solve for the amount remaining:
[tex]y=14.2* (0.9172535661)^{(31.8)}[/tex] [tex]y=14.2*(0.5)^{\frac{(31.8)}{8.0252}}[/tex]
[tex]y=14.2* 0.0641450581[/tex] [tex]y=14.2*(0.5)^{3.962518068}[/tex]
[tex]y=0.9108598257[/tex] [tex]y=14.2* 0.0641450581[/tex]
[tex]y=0.9108598257[/tex]
Since both the initial amount of Iodine, and the amount of time were given to 3 significant figures, the amount remaining after 31.8days is 0.911g.
A sports car can move 100.0 m in the first 3.8 s of constant acceleration. What is the car's acceleration?
m/s²
The distance covered by an accelerating object starting from rest is
D = (1/2 of acceleration) x (time²).
In this question,
D = 100 m
time = 3.8 s
100 = (1/2 acceleration) x (3.8s²)
100 = (1/2 a) x (14.44)
100/14.44 = 1/2 a
200/14.44 = a
a = 13.85 m/s²
In the image below, a worker is pushing a crate with a mass of 10 kg up a
ramp at a constant rate. Ignoring friction, how much force must the worker
apply so that the crate continues to move at the same speed? (Recall that g =
9.8 m/s²)
A. 25.6 N
B. 67.5 N
C. 16.2 N
D. 49.0 N
Answer:
D. 49N
Explanation:
Because there is no acceleration the sum of the forces in the x-direction is zero. Your weight force is mass x gravity which is 98N. The x-component of which is sin(30). 98sin30 = 49N in the negative x-direction. -49N + The force applied by the worker must equal zero. So, the force applied by the worker must be 49N.
If have a custom made telescope with these specifications then what's the focal length of my telescope? (refractor telescope only please)
_Specifications:_
*Objective diameter*: 90mm
*Distance between lenses*: 230mm
*Eyepiece focal length*: 4mm
*Eyepiece size*: 31.7mm
Please respond fast. Also please give a simplified answer for a brainliest answer tag. Thanks!
Answer:
i don't know sorry
i know a good website that may help you
it's called https://skyandtelescope.org/observing/telescope-calculator/
Explanation:
Put the steps of the scientific method in order.
A. Question -> Research -> Hypothesis -> Experiment -> Analysis -> Conclusion
B. Research -> Hypothesis -> Experiment ->Question -> Conclusion -> Analysis
C. Research -> Question -> Hypothesis -> Experiment -> Analysis -> Conclusion
D. Hypothesis -> Experiment -> Conclusion -> Question -> Research -> Analysis
Answer:
c
Explanation:
Answer:
c
Explanation:
im smart
A skater starts from rest v1=0, from the top of an h=6m hill and travels d=20m until it gets to the bottom of the hill where its speed is v2=1.2m/s. If the skater has m=50kg, what is the friction force?
The friction force is 1.5N
skater's initial velocity v1=0height of the hill=20mskater's final velocity=1.2m/sMass of the skater=50kg
Now, using the third equation of motion-
[tex]v^{2}= u^{2} +2as[/tex]
v=final velocity
u=initial velocity
a=acceleration
s=distance
substitute the values in the above equation
1.2=0+ 2a×20
a=1.2/40
a=0.03
friction force=mass ×acceleration
=50×0.03
=1.5N
hence, The friction force is 1.5N
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If two balls have the same mass, but ball P is twice as large as ball Q, which one will have the greater density?
a. Ball P
b. ball Q
c. Their densities are equal
a. Ball P
What is density.Density is define as mass per unit volume or the quantity per unit volume, unit area, or unit length.
If [tex]m_{1}[/tex] is mass , [tex]V_{1}[/tex] is volume and [tex]D_{1}[/tex] is density of ball P
[tex]m_{2}[/tex] is mass , [tex]V_{2}[/tex] is volume and [tex]D_{2}[/tex] is density of ball Q
It is given that ,
[tex]V_{1}[/tex] = [tex]V_{2}[/tex];
But [tex]m_{1}[/tex]= [tex]2m_{2}[/tex]
Based on above equation we have:
[tex]\frac{D_{1} }{D_{2} } = (\frac{m_{1} }{V_{1} } )* (\frac{m_{2} }{V_{2} } )\\ \\= (\frac{2m_{2} }{V_{2} })*(\frac{V_{2} }{m_{2} }) \\\\= 2[/tex]
Thus, density of ball P is twice that of Q.
Therefore ,
Ball P will have a greater density than Q
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When passing in a medium for a distance of 1.5 cm intensity
of the light decreased by 3 times. What will the distance x equal to when the intensity of the light decreases by 9 times?
The distance x equal to 0.87 cm when the intensity of the light decreases by 9 times.
Intensity of light
The intensity of light is given as power emitted by the light by unit area.
I = P/A
I = P/L²
I₁L₁² = I₂L₂²
L₂² = I₁L₁²/I₂
L₂² = (3 x 1.5²)/(9)
L₂² = 0.75
L₂ = 0.87 cm
Thus, the distance x equal to 0.87 cm when the intensity of the light decreases by 9 times.
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Estimate the gravitational force of attraction between two people sitting side by side on a park bench. How does this force compare with the gravitational force exerted on each of them by the Earth
Weight is compared with the gravitational force exerted on each of them by the Earth.
What is Newton's law of gravitation?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
When mass increases and distance reduces, gravity rises. Gravity also lowers when the distance between two points grows and the mass decreases.
The gravitational force is balanced by weight;
[tex]\rm F = W \\\\ G\frac{mM}{r^2} =mg[/tex]
Hence, weight is compared with the gravitational force exerted on each of them by the Earth.
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Angel hits a ball with a ball. The action is the ball . What what is reaction force?
When Angel hits a ball with the ball. As the action is a ball as it is hitted. The reaction force is the force exerted on another ball.
Newton’s third law of motion describes the two forces, action and reaction forces. This states that for every action force, there is an equal and opposite reaction force.
As Angel hits a ball with another ball, the action is the ball as it is hit. The ball exerts a force on the ball. This is the action force. The ball exerts an equal and opposite force on the bat, which is known as the reaction force.
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A 50 g bullet moving horizontally at a velocity of 400 m/s collides and embeds itself in a 25 kg block that rests on a rough horizontal surface and is attached to a spring with a spring constant of 180 N/m. The impact causes a compression of 12 cm in the spring. What is the coefficient of friction between the block and the surface?
The coefficient of friction between the block and the surface is determines as 0.1.
Final velocity of the block and the bulletApply the principle of conservation of linear momentum;
0.05(400) = v(0.05 + 25)
20 = 25.05v
v = 0.8 m/s
Coefficient of frictionApply the principle of conservation of energy
P.E - K.E = Ux
μmgx - ¹/₂mv² = ¹/₂kx²
μ(25.05)(9.8)(0.12) - 0.5(25.05)(0.8)² = 0.5(180)(0.12)
29.459μ - 8.016 = 10.8
29.459μ = 2.784
μ = 0.1
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(The question and setup are below)
The gauge pressure at bottom of vaccine solution will be 16 kPa
Positive pressure is another name for gauge pressure. When a system's internal pressure exceeds that of its surroundings, it is said to be under positive pressure. Any leak that develops in the positively pressured system will therefore escape into the outside world. In contrast, a negative pressure chamber draws air into it.
Given As seen in the illustration, a syringe is held vertically. The container carries a 3 cm tall column of vaccine solution and has an open inner diameter of 1 cm. The needle contains a 2 cm column of vaccine solution and has an open inner diameter of 0.5 mm. At the needle's open end, the solution is exposed to the air. The vaccination solution has a density of 1200 kg/m3.
We have to find the gauge pressure at bottom of vaccine solution
Since the 5N force is applied to vaccine solution the pressure exerted will be much more
Hence the gauge pressure at bottom of vaccine solution will be 16 kPa
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1. List some environmental challenges identified by the Brundtland Commission's overview, as well as a key strategy for addressing them. Identify urgencies that the Commission sees as necessary for an optimistic environmental future.
The Brundtland Commission spotted as a matter of urgency, the interconnection between natural resource use and the economy.
What is the Brundtland Commission?The Brundtland Commission was set up with the intention to achieve sustainable development. The tenure of the commission lasted from 1984 to 1987.
The commission identified the pillars of sustainable growth as economic growth, environmental protection, and social equality. The committee opined that environmental problem emanates from poverty in the southern region and reckless consumption of resources in the northern region.
The Brundtland Commission spotted as a matter of urgency, the interconnection between natural resource use and the economy.
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yhisriyftt
carzy and want one g come 6x 10-1'coulomb or one unit. The ratio, mass for each of the particle is 9.58 x 10" per gram. Hence, the mass