A computer system is priced at $3200. A man buys
the computer system on hire purchase according
to the following terms: a down payment of $480
and the remaining to be paid in monthly
instalments over 2 years at a simple interest rate of
9.5% per annum.
(i) Find his monthly instalment.
(ii) Find the total amount the man pays for the
computer system.
(iii) How much more does he have to pay
for
buying the computer system on hire purchase?
dollar

This is about interpretation of graphs.

Option C is correct.

From the graph, we can see the 2 lines representing function f(x) and function g(x).

Now for us to find the value of x in g(x) = k⋅f(x), we need get a mutual x-coordinate where we can easily read their respective y-coordinate values.

We see that the best point for that is where x = -3.

For f(x), when x = -3, y = 1

For g(x), when x = -3, y = -3

we can rewrite them as;

x = -3, f(-3) = 1 and x = -3, g(-3) = -3

Let us plug in the relevant values into g(x) = k⋅f(x) to get;

-3 = k(1)

Thus; k = -1/3

The value of [tex]a_{5}[/tex] is 2500, when [tex]a_{1}=4[/tex] and [tex]5a_{n-1}[/tex].

Given that, [tex]a_{1}=4[/tex] and [tex]5a_{n-1}[/tex].

We need to find the value of [tex]a_{5}[/tex].

An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

Now, to find the value of [tex]a_{5}[/tex] :

[tex]a_{2} =5a_{2-1}=5a_{1}=5 \times4=20[/tex]

[tex]a_{3} =5a_{3-1}=5a_{2}=5 \times20=100[/tex]

[tex]a_{4} =5a_{4-1}=5a_{3}=5 \times100=500[/tex]

[tex]a_{5} =5a_{5-1}=5a_{4}=5 \times500=2500[/tex]

Therefore, the value of [tex]a_{5}[/tex] is 2500.

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Answer:

perpendicular

Step-by-step explanation:

Answer:

x = 12 half page advertisements

y = 8 full page advertisements

Step-by-step explanation:

42x + 86y = 1192

x + y = 20

y = 20 - x

Input (20-x) as y into the first equation

42x + 86(20-x)=1192

42x + 1720 - 86x = 1192

(42x - 86x) 1720 -1720= 1192-1720

-44x = -528

x = 12

12 + y = 20

y=8

a. 'x' represents half page advertisement and 'y' represents full page advertisement.

System of equation is given by 42x + 86y = 1192 , x + y =20.

b. Number of full page advertisement  Kathryn purchase is equals to 8.

c.  Number of half page advertisement  Kathryn purchase is equals to 12.

" System of equation is defined as the finite set of equations for which we find a common solution."

According to the question,

Cost of half page advertisement = $42

Cost of full page advertisement = $86

Number of advertisement Kathryn could purchase = 20

Total budget of Kathryn to purchase advertisement = $1192

'x' represents half page advertisement

'y' represents full page advertisement

As per the situation given system of equation we have,

42x + 86y = 1192                                 ______(1)

x + y = 20                        

x = 20 - y                                             _____(2)

Substitute the value of 'x' from  system of equation (2) in (1) we get,

[tex]42( 20 -y) +86y =1192\\\\\implies 840 - 42y +86y =1192\\\\\implies 44y = 1192-840\\\\\implies y = \frac{352}{44}\\ \\\implies y =8[/tex]

Substitute the value of y in (2) to get 'x' ,

[tex]x=20-8[/tex]

  = 12

Hence,

a. 'x' represents half page advertisement and 'y' represents full page advertisement.

System of equation is given by 42x + 86y = 1192 , x + y =20.

b. Number of full page advertisement  Kathryn purchase is equals to 8.

c.  Number of half page advertisement  Kathryn purchase is equals to 12.

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5.12 minutes ≈ 5 minutes 7.2 seconds

Distance. The length along a line or line segment between two points on the line or line segment.

Here, The flight path of the airplane is along the line ...

y = -125/135x = -25/27x

The perpendicular line through Mt. Rainier's location is ...

 y = 27/25(x -56) -40

In standard form, these two equations are ...

25x +27y = 0

27x -25y = 2512

The point of closest approach has the coordinates that are the solution to these two equations:

(x, y) = (33912/677, 31400/677)

The distance d from the origin to this point is given by the Pythagorean theorem (distance formula) as ...

d = 1256√(2/677) . . . . . km

This distance can be converted to time using the speed of the airplane:

1256√(2/677) X 60/800 =  94.2√(2/677) ≈ 5.120019 mins

Thus, 5.12 minutes after departing JBLM you will be closest to Mt. Rainier.

The attached graph shows the geometry of the problem.

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Step-by-step explanation:

the circumference of a whole circle is

2×pi×r

with r being the radius. which is in our case a.

so,

2×pi×a

the part arc of just a sector of the circle is just the angle/360 part (as the whole circle is 360°).

we therefore know

27×pi = 2×pi×a × 60/360 = 2×pi×a × 1/6 = pi×a × 1/3

3×27×pi = pi×a

81×pi = pi×a

a = 81

a)QM and PM

b)QMN and NMQ

c)M

Answer:

No, the solution is -3.

Step-by-step explanation:

3y+10=-5y-14

We move all terms to the left:

3y+10-(-5y-14)=0

We get rid of parentheses

3y+5y+14+10=0

We add all the numbers together, and all the variables

8y+24=0

We move all terms containing y to the left, all other terms to the right

8y=-24

y=-24/8

y=-3

Answer:

y = - 3

Step-by-step explanation:

3y + 10 = - 5y - 14 ( add 5y to both sides )

8y + 10 = - 14 ( subtract 10 from both sides )

8y = - 24 ( divide both sides by 8 )

y = - 3

The expression -4 (-11 + 4n) – 3(- 2n + 9) is equivalent to the expression 17 — 10n.

The equivalent is the expressions that are in different forms but are equal to the same value.

The expression is given below.

⇒ -4 (-11 + 4n) – 3(- 2n + 9)

On simplifying, we have

⇒ 44 – 16n + 6n – 27

⇒ 17 — 10n

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The IQR for male data is 10, the estimated difference between medians is 2, the box plot for males is symmetric and for females, the box plot is left side skewed.

A box and whisker plot is a method of abstracting a set of data that is approximated using an interval scale. It's also known as a box plot. These are primarily used to interpret data.

From the box plot:

Part A:

IQR for males data:

IQR = Q3 - Q1

The estimated value of Q3 is 15 (between 10 and 20)

The estimated value of Q1 is 5 (between 0 and 10)

IQR = 15 -5 = 10

Part B:

= Median(male) - Median(femal)

= 10 - 8

= 2

Part C:

The box plot for males is symmetric and for females, the box plot is left side skewed.

Part D:

There can be holidays for the outliers

Thus, the IQR for male data is 10, estimated difference between medians is 2, the box plot for males is symmetric and for females, the box plot is left side skewed.

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Answer:

D.All of the choice

Step-by-step explanation:

D.All of the choice

Answer: 3

Step-by-step explanation:

Answer:

equate two simultaneous equations for r and solve

Answer: y = 0.75x + 80

Step-by-step explanation:

let x = 1 mile

y = 0.75x + 80

The function would become an exponential decay function.

For every meter there are 3.281 feet. The perimeter of the yard is 188ft. Divide 188 by 3.281 and you get 57.3 (rounded to 1dp). Round that up to the nearest meter and you get 58. So, Mr Smith needs 58 meters of fencing for his yard.

Step-by-step explanation:

multiply 2×3 to get 6 and then multiply 6×4

or

multiply 3×4 to get 12 and then multiply 12×2

The coordinates of the midpoint of the segment whose endpoints are W (-3,-7) and X (-8,4) will be (-11/2, -3/2). Then the correct option is D.

The complete options are given below.

1. (-11/2) -(11/2)

2.(-5/2)-(3/2)

3.(-5/2-(11/2)

4. (-11/2) -(-3/2)

Let C be the mid-point of the line segment AB.

A = (x₁, y₁)

B = (x₂, y₂)

C = (x, y)

Then the midpoint will be

x = (x₁ + x₂) / 2

y = (y₁ + y₂) / 2

The end points are given below.

(-3, -7) and (-8, 4)

We have

(x₁, y₁) = (-3, -7)

(x₂, y₂) = (-8, 4)

Then the mid-point will be

x = (- 3 - 8) / 2

x = -11 / 2

y = (-7 + 4) / 2

y = -3/2

Then the coordinates of the midpoint of the segment whose endpoints are W (-3,-7) and X (-8,4) will be (-11/2, -3/2).

Then the correct option is D.

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Answer:

i think 345 if not sorry

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

Although you did not give me the answer choices, I believe that the only possible answer is 1 because the only y value the graph is on is 1.

Answer:

 [tex]\frac{18}{5}[/tex] (11)

Step-by-step explanation:

If it varies directly, you need to find k, the constant of proportionality.

This is done by plugging the values in for x & y that are known.

y = kx

18 = k(5)

[tex]\frac{18}{5}[/tex] = k

Now solve for y  when x is 11.

y = [tex]\frac{18}{5}[/tex] (11)

y = 39.6

The distributive property of multiplication over addition for rational numbers is (a) -3/4 × {2/3 + (-5/6)} = [-3/4 × 2/3] + [-3/4 × (-5/6)]

Which of the following is an example of distributive property of multiplication over addition for rational numbers

(a) -3/4 × {2/3 + (-5/6)} = [-3/4 × 2/3] + [-3/4 × (-5/6)]

(b) -3/4 × {2/3 + (-5/6)} = [3/4 × 2/3] - (-5/6)

(c) -3/4 × {2/3 + (-5/6)} = 2/3 + (-3/4) × -5/6

(d) -3/4 × {2/3 + (-5/6)} = {2/3 + (-5/6)} - 3/4

The distributive property of multiplication states that:

a * (b + c) = (a * b) + (a * c)

From the given question, we have:

-3/4 × {2/3 + (-5/6)}

This means that:

a = -3/4

b = 2/3

c = -5/6

Recall that a * (b + c) = (a * b) + (a * c)

So, we have:

-3/4 × {2/3 + (-5/6)} = [-3/4 × 2/3] + [-3/4 × (-5/6)]

Hence, the distributive property of multiplication over addition for rational numbers is (a) -3/4 × {2/3 + (-5/6)} = [-3/4 × 2/3] + [-3/4 × (-5/6)]

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Answer:

The answer should be 3.3/4

Step-by-step explanation:

The result follows from the fundamental theorem of calculus. Since [tex]f''(x)[/tex] is the derivative of [tex]f'(x)[/tex], we have

[tex]\displaystyle \int_0^c f''(x) \, dx = \boxed{f'(c) - f'(0)}[/tex]

(E)