Order these numbers from least to greatest.
8.461, 169/20, 8 6/11, 8.49
Hurry please

Reason:

The standard error of the mean has the formula [tex]\frac{\sigma}{\sqrt{n}}[/tex] where [tex]\sigma[/tex] (greek letter sigma) is the standard deviation and n is the sample size.

As n gets bigger, the standard error [tex]\frac{\sigma}{\sqrt{n}}[/tex] gets smaller, and vice versa. This assumes sigma is fixed. A larger sample indicates the error goes down to narrow in better on the population mean.

Based on what I mentioned, this tells us that sample A has the larger standard error since n = 350 is smaller than n = 500 for sample B.

Answer:

B.) As x → –∞, f(x) → ∞, and as x → ∞, f(x) → –∞.

Step-by-step explanation:

[tex]\lim_{x\rightarrow -\infty } f\left( x\right) =\lim_{x\rightarrow -\infty } -4\sqrt[3]{x} = (-4)\times(-\infty) = +\infty[/tex]

[tex]\lim_{x\rightarrow \infty } f\left( x\right) =\lim_{x\rightarrow \infty } -4\sqrt[3]{x} = (-4)\times(+\infty) = -\infty[/tex]

Answer:

5√6

Step-by-step explanation:

√25 x 6

√25 x√6

5√6

Volume is a three-dimensional scalar quantity. The number of boxes that can fit in the cargo hold of the truck is 54.

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

The volume of the box = Volume of the cube = a³ = (2.50)³ = 15.625 ft³

The volume of cargo hold = 7.50 × 7.50 × 15 = 843.75 ft³

Now, the number of boxes that can fit in the cargo hold of the truck will be,

Number of boxes = (Volume of truck container)/(Volume of box)

                              = 843.75/15.625

                              = 54

Hence, the number of boxes that can fit in the cargo hold of the truck is 54.

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What is volume of the box in diagram (in cubic ft.)

Volume of cube = a³

putting the value of a

Volume = (2.5ft.)³

Volume = 15.625 ft³

To find how many such boxes can be fit into the truck , we need to first find the volume of cargo hold of the truck and then divide it by the volume of 1 box

Volume of Cargo hold of truck =

= 15ft. × 7.5ft. × 7.5ft

= 843.75 ft³

No. of boxes that can be fit into the truck =

Volume of truck/ Volume of one box

= 843.75ft.3³/15.625ft.³

= 54 boxes

Answer:

1300 ppl

Step-by-step explanation:

35%  = .35 in decimal

.35 x =455

x = 455/.35 = 1300 ppl

Answer:

The GCF of 12 and 28 is 4

hope it helpsss

Answer: is 4 thats the answer

Step-by-step explanation: i have none im not good at explaining math welp have a good day

Step-by-step explanation:

divide equation by 2

subtract 6

-x

The velocity of the jogger will be 0.18 miles per minute.

Velocity is defined as the ratio of the distance moved by the object in a particular time. The velocity is a vector quantity so it needs both the magnitude and the direction.

Given that:-

The velocity will be calculated as:-

V   =   Distance  ÷   Time

V   =   8     ÷    45

V   =   0.18 miles per minute

Therefore the velocity of the jogger will be 0.18 miles per minute.

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Using the slope concept, it is found that the kite is 46.50 feet above the ground.

The slope is given by the vertical change divided by the horizontal change, and it's also the tangent of the angle of depression.

In this problem:

Hence:

tan(24º) = (3.5 + x)/105.

3.5 + x = 105tan(24º)

x = 105tan(24º) - 3.5

x = 43.25 ft.

Hence, the height of the kite is:

43.25 ft + 3.25 ft = 46.50 feet.

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Answer:

Step-by-step explanation:

�

105

105

x

​

sin

24

1

=

1

sin 24

​

=

�

105

105

x

​

105

sin

24

=

105 sin 24=

�

x

Cross multiply.

�

=

42.707347...

x=42.707347...

Type into calculator.

Add 3.25, the distance from the ground to his hand:

Add 3.25, the distance from the ground to his hand:

42.707347...

+

3.25

=

42.707347...+3.25=

45.957347...

45.957347...

≈

≈

46

46

Round to the nearest tenth.

The kite is 46 feet above the ground.

The kite is 46 feet above the ground.

Volume is a three-dimensional scalar quantity. The height of the cuboid is 7 cm.

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

Given the volume of the cuboid is 385cm³, the length of the cuboid is 10cm, while the width of the cuboid is 5.5 cm, therefore, the height of the cuboid is,

385cm³ = 10cm × 5.5cm × H

H = 385cm³/(10cm×5.5cm)

H = 7cm

Hence, the height of the cuboid is 7 cm.

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Answer:

$20.90

Step-by-step explanation:

If we want to find Aiden's hourly rate, and we know how long he worked, and how much money he made, then we can simply divide his profit by how long he worked. This will give us the precise amount of money he made per hour.

So,

$334.40 / 16 hours = 20.9

This means Aiden earned approximately $20.90 per hour.

Hope this helped!

Answer:

Step-by-step explanation:

Remark

If the figures are similar then this is a proportion question. A proportion is 2 equation ratios. The ratios can have at most 1 unknown.

Givens

DC = 7

ML = 4.9

AB = 4

JK = x

Equation

DC/ML = AB/x                  Substitute values into equation and solve

Solution

7/4.9 = 4/x                        Cross Multiply

7x = 4 * 4.9                       Combine the right.

7x = 19.6                           Divide by 7

7x/7 = 19.6/7

x = 2.8

Answer

x = 2.8

7¹⁴÷7²

= 7¹⁴-²

=7¹²

hope this helps:)

Answer:

12 feet and 6inches ..................

Answer:

12 feet and 6 inches

Step-by-step explanation:

Answer:

Step-by-step explanation:

Solve each equation and compare the solutions

1.

2.

Both a and b have same value

Answer:

Yes, a and b have the same value in the given equations.

Step-by-step explanation:

Equation 1

      [tex]2(a-1.1)=5.8[/tex]

[tex]\implies 2a-2.2=5.8[/tex]

[tex]\implies 2a-2.2+2.2=5.8+2.2[/tex]

[tex]\implies 2a=8[/tex]

[tex]\implies \dfrac{2a}{2}=\dfrac{8}{2}[/tex]

[tex]\implies a=4[/tex]

Equation 2

    [tex]\dfrac{5}{2}b-2\frac{3}{4}=7 \frac{1}{4}[/tex]

[tex]\implies \dfrac{5}{2}b-\dfrac{2 \times 4+3}{4}=\dfrac{7 \times 4+1}{4}[/tex]

[tex]\implies \dfrac{5}{2}b-\dfrac{11}{4}=\dfrac{29}{4}[/tex]

[tex]\implies \dfrac{5}{2}b-\dfrac{11}{4}+\dfrac{11}{4}=\dfrac{29}{4}+\dfrac{11}{4}[/tex]

[tex]\implies \dfrac{5}{2}b=\dfrac{40}{4}[/tex]

[tex]\implies \dfrac{5}{2}b=10[/tex]

[tex]\implies 2 \cdot \dfrac{5}{2}b=2 \cdot 10[/tex]

[tex]\implies 5b=20[/tex]

[tex]\implies \dfrac{5b}{5}=\dfrac{20}{5}[/tex]

[tex]\implies b=4[/tex]

Conclusion

As  a = 4  and  b = 4, the two variables have the same value in the given equations.

Answer:

Plug into desmos, the exact equation, and put in what point comes out.

Step-by-step explanation:

Answer:

Once fully solved, x is equal to 0, so it means that there is only one solution

Step-by-step explanation:

When you combine like terms (without adding variables to either side), the equation is equal to:

2x + 5 = 8x + 5

Then, the next step is:

5 = 8x + 5 - 2x

Finally, the last one is:

0 = 6x, which is x = 0.

Answer:

61 + 142 + 44 = 247˚

Step-by-step explanation:

Just add haha

the person above is right

Answer:

? ≈ 6.5 yd

Step-by-step explanation:

the area (A) of a triangle is calculated as

A = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the perpendicular height )

here A = 13.3 and h = 4.1 , then

[tex]\frac{1}{2}[/tex] × 4.1b = 13.3 ( multiply both sides by 2 to clear the fraction )

4.1b = 26.6 ( divide both sides by 4.1 )

b = ? ≈ 6.5 yd ( to the nearest tenth )

Answer: the slope is y=-1/2

Step-by-step explanation:

because the line is moving from left to right, it is a negative slope

A. True. We see this by taking the highest order term in each factor:

[tex]f(x) = -3x(x-5)^3(x+2)^2 = -3x (x^3 + \cdots) (x^2 + \cdots) = -3x^{\boxed{6}} + \cdots[/tex]

B. True. Again we look at the leading term's degree and coefficient. f(x) behaves like -3x⁶ when x gets large. The degree is even, so as x goes to either ± ∞, x⁶ will make it positive, but multiplying by -3 will make it negative. So on both sides f(x) approaches -∞.

C. False. f(x) = 0 only for x=0, x = 5, and x = -2.

D. False. Part of this we know from the end behavior discussed in part B. On any closed interval, every polynomial is bounded, so that for any x in [-2, 5], f(x) cannot attain every positive real number.

E. True. x = 0 is a root, so f(0) = 0 and the graph of f(x) passes through (0, 0).

F. False. (0, 2) corresponds to x = 0 and f(x) = 2. But f(0) = 0 ≠ 2.

Answer:

5x-7y+35=0.

Step-by-step explanation:

1) according to the condition it is possible to make up the required equation:

[tex]\frac{x}{-7} =\frac{y}{5} =1;[/tex]

note, the numbers -7 and 5 are from the given coordinates;

2) if to re-write the equation into common form, then

5x-7y+35=0.

Answer:

x=√15 or x = -5 or x=3

Step-by-step explanation:

Possibility one:

x=x^2+x-15

x-x^2=x^2+x-15-x^2 (subtract x^2 from both sides)

-x^2+x=x-15

-x^2+x-x=x-15-x (subtract x from both sides)

-x^2=-15

-x^2/-1=-15/-1 (divide both sides by -1)

x^2=15

square root both sides

x=√15 or x=-√15

Possibility two:

x=(-x^2+x-15)

x=-x^2-x+15 (simplify)

x-(-x^2-x+15)=-x^2-x+15-(-x^2-x+15) (subtract both sides by -x^2-x+15)

x^2+2x-15=0

(x-3)(x+5)=0 (factor left side of equation)

x-3=0 or x+5=0 (set factors equal to 0)

x=3 or x=-5

Answer:

20 cm²

Step-by-step explanation:

If the given shape has been enlarged by scale factor 2, then each of the side lengths will be increased from 1 cm to 2 cm, as 1 × 2 = 2

Area of the given shape is 5 cm².

As we are working with area, we cannot simply multiply the area of the given shape by the scale factor.  Area is measured in square units, therefore we need to multiply the area of the given shape by the square of the scale factor.

⇒ area of the enlarged shape = area of given shape × sf²

                                                  = 5 cm² × 2²

                                                  = 5 cm² × 4

                                                  = 20 cm²

(see attached image for proof)

Answer:

[tex]\huge \orange{b = \boxed{ 6} \sqrt{ \boxed{3}} }[/tex]

Step-by-step explanation:

[tex]a = 12 \sin 30 \degree \\ \\ \implies \: a = 12 \times \frac{1}{2} \\ \\ \implies \: \huge \red{ a = 6} \\ \\ b = 12 \cos 30 \degree \\ \\ \implies \: b = 12 \times \frac{ \sqrt{3} }{2} \\ \\ \implies \: b = 6 \times \sqrt{3} \\ \\ \implies \: \huge \orange{b = \boxed{ 6} \sqrt{ \boxed{3}} }[/tex]

Answer:  [tex]\frac{219}{100}[/tex]

======================================================

Explanation:

Think of [tex]2.19[/tex] as [tex]\frac{2.19}{1}[/tex] or [tex]\frac{2.19}{1.00}[/tex]

This works because dividing anything over 1 does not change the original number.

Then we can move the decimal point two spots to the right for each number

Therefore, [tex]2.19 = \frac{219}{100}[/tex]