fred buys a shipment of fruit that consists of only apples and oranges. for every 3 apples, there are 2 oranges. if there are 5 dozen pieces of fruit total, how many are oranges?

Answer:

Step-by-step explanation:

167.00 / 100 = $1.67

Answer:

33v - 48

Step-by-step explanation:

- 9v - 6(8 - 7v) ← multiply each term in the parenthesis by - 6

= - 9v - 48 + 42v ← collect like terms

= 33v - 48

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \: - 9v - 6(8 - 7v)[/tex]

[tex]\qquad \sf  \dashrightarrow \: - 9v - [(6 \times 8) - (6 \times 7v)][/tex]

[tex]\qquad \sf  \dashrightarrow \: - 9v - (48 - 42v)[/tex]

[tex]\qquad \sf  \dashrightarrow \: - 9v - 48 + 42v[/tex]

[tex]\qquad \sf  \dashrightarrow \:33v - 48[/tex]

Hope it helps ~

Answer:

cross multiplication

x

Answer:

0.9974

Step-by-step explanation:

[tex]arcsin( \frac{1}{7} ) = 0.1433 \\ cos( \frac{0.1433}{2} ) = 0.9974[/tex]

[tex]\csc \theta \tan \theta - \tan \theta \sin \theta \\\\\\=\dfrac 1{\sin \theta} \cdot \dfrac{\sin \theta }{\cos \theta }- \dfrac{\sin \theta }{\cos \theta} \cdot \sin \theta\\\\\\=\dfrac{1}{\cos \theta}-\dfrac{\sin^2 \theta}{\cos \theta}\\\\\\=\dfrac{1- \sin^2 \theta}{\cos \theta}\\\\\\=\dfrac{\cos^2 \theta}{\cos \theta}~~~~~~~~~~~~~~;[\sin^2 \theta + \cos^2 \theta =1 ]\\\\\\=\cos \theta[/tex]

Let's write out some trigonometric identities that we can use:

Now let's try solving them out:

  [tex]csc(x)tan(x)-tan(x)sin(x)=\frac{1}{sin(x)}tan(x)-sin(x)tan(x)\\\\ csc(x)tan(x)-tan(x)sin(x)=tan(x)(\frac{1}{sin(x)}-sin(x))\\\\ csc(x)tan(x)-tan(x)sin(x)=tan(x)(\frac{1}{sin(x)} -\frac{sin^2(x)}{sin(x)} )\\\\csc(x)tan(x)-tan(x)sin(x)=tan(x)*(\frac{1-sin^2(x)}{sin(x)} )\\\\csc(x)tan(x)-tan(x)sin(x)=\frac{sin(x)}{cos(x)}*\frac{cos^2(x)}{sin(x)} \\\\csc(x)tan(x)-tan(x)sin(x)=\frac{sin(x)}{sin(x)}*\frac{cos^2(x)}{cos(x)}\\\\csc(x)tan(x)-tan(x)sin(x)=1 * cos(x)\\\\ csc(x)tan(x)-tan(x)sin(x)=cos(x)[/tex]

  *I used a different variable, but that doesn't change the answer

Answer: cos(x)

Hope that helps!

Answer:

hope you understand......

Answer:

1/3

Step-by-step explanation:

Number of pizza=12

Number of students=4

Therefore,4/12=4/4

=1/3

If there is no picture for the spinner and we assume that it is completely fair, meaning that you have an equal chance of landing on any spot: You will expect to get a certain color every 3 spins because you have 3 different colors. In this case the answer would be 20 pupcakes.

Answer:

y intercept: 65

rate of change: $2.75

Step-by-step explanation:

Really quite simple lad. Your equation is y=2.75x+65. 65 is your y-intercept, and you have a rate of change of 2.75 per bouquet.

Answer:

W = 11340 J

Step-by-step explanation:

Given,

Force ( F ) = 567 N

Distance ( s ) = 20 N

To find : Work done ( W )

Formula : -

W = Fs

W = 567 x 20

W = 11340 J

Hence,

the amount of work done is 11340 J.

Answer:

mean is 2 brothers.

mean, means average

Answer:

√5

Step-by-step explanation:

Given:

[tex]\displaystyle \large{5\div \sqrt{5}}[/tex]

Which can be rewritten as:

[tex]\displaystyle \large{\dfrac{5}{\sqrt{5}}}[/tex]

To find:

To find simplified form of the expression, keep in mind that surds should not remain as denominators. Therefore, what we have to do is to multiply both numerator & denominator by the surd itself so the denominator will be cleared as rational number.

[tex]\displaystyle \large{\dfrac{5\cdot \sqrt{5}}{\sqrt{5}\cdot \sqrt{5}}}[/tex]

We know that if same surds multiply each other, the surd will be canceled and remains only the insides. To express it in math, it can be as:

[tex]\displaystyle \large{\sqrt{a}\cdot \sqrt{a} = \left(\sqrt{a}\right )^2 =a}[/tex]

Therefore:

[tex]\displaystyle \large{\dfrac{5\sqrt{5}}{5}}[/tex]

Cancel 5:

[tex]\displaystyle \large{\sqrt{5}}[/tex]

Henceforth, the simplified expression is √5

The best estimate and the degree of freedom when the t-distribution is used to find a confidence interval is 7 and 56 respectively.

The best estimate from the information given in the research will be:

= X1 - X2

= 53.5 - 46.5

= 7

The degree of freedom will be:

= 38 + 20 - 2

= 56

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Answer:

x=120°

Step-by-step explanation:

sum of all angles in a triangle is equal to 180

let the unknown angle be

[tex] \alpha [/tex]

[tex]60 + 60 + \alpha = 180 \\ \alpha = 180 - 60 - 60 \\ \alpha = 60 \\ [/tex]

[tex] \alpha + x = 180 \\ x = 180 - \alpha \\ x = 180 - 60 \\ x = 120[/tex]

Answer:

See below ~

Step-by-step explanation:

Details of Graph

Answer:

y = 3x + 3

Step-by-step explanation:

when you check, only that equation delivers the correct x and y pairs.

x = 0, => y = 3×0 + 3 = 3

x = 1, y = 3×1 + 3 = 3+3 = 6

x = 2, y = 3×2 + 3 = 6 + 3 = 9

x = 3, y = 3×3 + 3 = 9 + 3 = 12

it all fits.

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

[tex]-2x+4y=8\implies 4y=2x+8\implies y=\cfrac{2x+8}{4} \\\\\\ y=\cfrac{2x}{4}+\cfrac{8}{4}\implies y=\stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{2}}x+2\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]

since we know that's its slope, then

[tex]\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{1}{2}} ~\hfill \stackrel{reciprocal}{\cfrac{2}{1}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{2}{1}\implies -2}}[/tex]

so then we're really looking for the equation of a line whose slope is -2 and passes through (2 , 1)

[tex](\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad \qquad \stackrel{slope}{m}\implies -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{-2}(x-\stackrel{x_1}{2}) \\\\\\ y-1=-2x-4\implies y=-2x-3[/tex]

The limit of the expressions [tex]3^{2n} + 1[/tex] and [tex]4^{n + 2} - 3[/tex] for n to infinity is infinity

The expressions are given as:

[tex]3^{2n} + 1[/tex]

[tex]4^{n + 2} - 3[/tex]

The limits of the expressions as they approach infinity are represented as:

[tex]\lim_{n \to \infty} 3^{2n} + 1[/tex] and [tex]\lim_{n \to \infty} 4^{n + 2} - 3[/tex]

Substitute [tex]\infty[/tex] for n in both expressions

[tex]\lim_{n \to \infty} 3^{2 * \infty} + 1[/tex] and [tex]\lim_{n \to \infty} 4^{\infty + 2} - 3[/tex]

Solve both expressions independently;

[tex]\lim_{n \to \infty} 3^{2n} + 1 = 3^{2 * \infty} + 1[/tex]

Evaluate the product

[tex]\lim_{n \to \infty} 3^{2n} + 1 = 3^{\infty} + 1[/tex]

Evaluate the exponent

[tex]\lim_{n \to \infty} 3^{2n} + 1 = \infty + 1[/tex]

Evaluate the sum

[tex]\lim_{n \to \infty} 3^{2n} + 1 = \infty[/tex]

Also, we have:

[tex]\lim_{n \to \infty} 4^{n + 2} - 3 = 4^{\infty + 2} - 3[/tex]

Evaluate the sum

[tex]\lim_{n \to \infty} 4^{n + 2} - 3 = 4^{\infty} - 3[/tex]

Evaluate the exponent

[tex]\lim_{n \to \infty} 4^{n + 2} - 3 =\infty - 3[/tex]

Evaluate the difference

[tex]\lim_{n \to \infty} 4^{n + 2} - 3 =\infty[/tex]

Hence, the limit of the expressions for n to infinity is infinity

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Answer:

scale

Step-by-step explanation:

it would be used to measure

Answer:

129060

Step-by-step explanation:

135 000 - .044(135000) = 129 060

Answer:

y=3x-27

Step-by-step explanation:

[tex]\rule{300}{1}\\\dashrightarrow\large\blue\textsf{\textbf{\underline{Given question:-}}}[/tex]

               Write an equation of the line passing through (6, -9) and has a slope of -3.

[tex]\dashrightarrow\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}[/tex]

First, we need to write the equation in point-slope form:-

[tex]\hookrightarrow\sf{y-y_1=m(x-x_1)}[/tex]

[tex]\hookrightarrow\sf{y-(-9)=3(x-6)}[/tex]

[tex]\bigstar[/tex] On simplification,

[tex]\hookrightarrow\sf{y+9=3(x-6)}[/tex]

[tex]\bigstar[/tex] On further simplification,

[tex]\hookrightarrow\sf{y+9=3x-18}[/tex]

[tex]\star[/tex] Subtract 9 from both sides, which results in:-

[tex]\hookrightarrow\sf{y=3x-27}[/tex]

So we conclude that Option B is correct.

[tex]\rule{300}{1}[/tex]

Answer:

A. -2

Step-by-step explanation: