N
O O
What is the slope of the line represented by the equation y = --- 5x?
0-5
4 ~/m ~/m
+
O 5
O

Answer:

y = 4x

Step-by-step explanation:

Equation of line in point -y intercept form:

    [tex]\sf \boxed{\bf y-y_1=m(x- x_1)}[/tex]

[tex]\sf x_1 = 1 \ ; \ y_1=4 \ \& \ m = 4[/tex]

  y - 4 = 4(x -1)

  y - 4 = 4*x - 4*1

  y - 4 = 4x - 4

Add 4 to both sides

       y = 4x - 4 + 4

      y =4x

Answer:

1 and -2 (has a multiplicity of 2)

Step-by-step explanation:

so since x=-2 is a root then (x+2) is a factor of the polynomial. This means you can divide the polynomial by (x+2) by using synthetic or long division. So for this example I'll using synthetic division which is much more simple than long division

-2 | 1   3    0   -4

         -2   -2    4

     1    1    -2   0

(x+2)(x²+x-2)

Now you can factor the quadratic into

(x+2)(x-1)

x+2 = 0

x = - 2

x-1 =0

x = 1

Answer: 55[tex]m^{2}[/tex]

Step-by-step explanation:

First find the area of the trapezoid: [tex]\frac{b1 +b2}{2}[/tex](h) : (base 1 + base 2) ÷ 2 x height

base 1 is 5m and we know the other base is parallel to the base of the rectangle so base 2 is 9m.

Since the total height is 7 m and the height of the rectangle is 5 m, subtract to get the height of the trapezoid: 7m - 5m = 2m

put the three values into the equation and solve:

(5m + 9m) ÷ 2 x 2m

(14m) ÷ 2 x 2m

7m x 2m

14[tex]m^{2}[/tex]

Find area of the rectangle which is just base x height

Which is 9m x 5m = 45[tex]m^{2}[/tex]

To find the total area, add the area of the trapezoid and the area of the rectangle. 14[tex]m^{2}[/tex] + 45[tex]m^{2}[/tex] = 55[tex]m^{2}[/tex]

Hope this helps

Answer:

Ok ya sure I would love to. :)

Step-by-step explanation:

Oh wait….

*Crickets chirping*

Answer:

Step-by-step explanation:

The surface area of a hexagonal prism willl be 251.13844 cm².

The total land area of all the faces of a three-dimensional object is its surface area. When we wish to wrap something in real life, we employ the notion of surface areas of distinct things.

A=6ah+3√3a²

A=6×4×7+3√3×4²

A≈251.13844

Hence the surface area of a hexagonal prism willl be 251.13844 cm².

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Answer:

y

Factor:4x^3-7x^2-30/y+15:

⬇

4x^3y-7x^2y+15y-30

y

Answer:

[tex]\huge\boxed{\dfrac{6}{10}=0.6}[/tex]

Step-by-step explanation:

[tex]0.6=\dfrac{6}{10}[/tex]

one digit after the decimal point - one zero in the denominator

[tex]0.06=\dfrac{6}{100}[/tex]

two digits after the decimal point - two zeros in the denominator

[tex]6.0=6[/tex]

[tex]1.6=1\dfrac{6}{10}\ \text{or}\ 1.6=\dfrac{16}{10}[/tex]

Answer:

Maybe the answer will be C. P (A and B )

Ans: C

Explanation:

I think it is option c , P(A and B)

as this is the only option which has the value of 80, which we got from the table

The volume of the cylinder is in the cubic cm is 311017.67 and in litres is 311.017, and the number of bottle is 426.

In geometry, it is defined as the three-dimensional shape having two circular shapes at a distance called the height of the cylinder.

We know the volume of the cylinder is given by:

[tex]\rm V = \pi r^2 h[/tex]

We have:

The radius of the cylindrical barrel r = 30 cm

Height of the cylindrical barrel h = 110 cm

Volume:

[tex]\rm V = \pi (30)^2 (110)[/tex]

V = 311017.67 cubic cm

The volume of litres:

V = 311.017 cubic ml  (1 liter = 1000 cubic cm)

Number of bottles = 311.017 /0.73= 426 bottles

Thus, the volume of the cylinder is in the cubic cm is 311017.67 and in litres is 311.017, and the number of bottle is 426.

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The answer is y=|x|-13.

Answer:

y=|x|-13

Step-by-step explanation:

The statement best describes Cheryl's computer is option C. Cheryl accelerated to 65 mph, drove at a constant speed for 5.5 minutes, and then decelerated to 45 mph.  

A graph contains data of which input maps to which output.

Analysis of this leads to the relations which were used to make it.

If we know that the function crosses the x-axis at some point, then for some polynomial functions, we have those as roots of the polynomial.

Let's assume the graph of Cheryl's commute was like the one below.

We can see that she started at 0 mph.  

One minute later, she was up to 65 mph, so she had accelerated (increased her speed).

At 6.5 min (5.5 min later) her speed was still 65 mph therefore, she was driving at a constant speed.

Over the next 2.5 min, her speed dropped to 45 mph, therefore she was decelerating.

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Answer:

[tex] {x}^{2} + {y}^{2} = 100[/tex]

The equation of the circle is x² + y² = 100.

Option A is the correct answer.

A circle is a two-dimensional figure with a radius and circumference of 2pir.

The area of a circle is πr².

We have,

The circle's equation is:

x² + y² = r²

where r is the length of the radius.

In this case, r = 10, so the equation becomes:

x² + y² = 10²

Simplifying:

x² + y² = 100

Therefore,

The equation of the circle is x² + y² = 100.

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The cost price of pawpaw is 40 and the cost if the basket of mangoes is 1250.

Based on the information given, the equations to solve the question will be:

30p + 100m = 2450 .... i

1.3 × 40p - 30 p + 1.3 × 100m = 855 ..... ii

30p + 100m = 2450

12p + 30m = 855

Solving simultaneously, the price of pawpaw is 40 and the price of mango is 12.5.

Therefore, the cost of 100 basket of mangoes will be:

= 12.5 × 100

= 1250

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Answer:

1/6

Step-by-step explanation:

the total carrot is 1/1 and fluffy ate 1/2 of it . this means half has been eaten and it is left with half so now 1/2 -1/3 ( carrot left in the morning - the carrot left now ) this will be 1/6

Answer:

Step-by-step explanation:

a. 4cm * 9cm * 2cm = 72 cm^3

b. 5m * 4m * 9m = 180 m^3

c. 10dm * 36 dm^2 (because the square could also be represented as 6cm * 6cm) =360 dm^3

d. (56mm)^3 =  175616 mm^3

e. 10 m * 1 m^2 (because of the square) = 10m^3

To tell which cubic unit of measure that should be used:

   ⇒ we should examine the unit of the side lengths

First question (a):

            ⇒ must use cm³ as cubic unit of measure

               ⇒ as all sides are centimeters

                  ⇒Answer: cubic centimeters or cm³

Second question(b):

            ⇒ must use m³ as cubic unit of measure

               ⇒ as all sides are meters

                  ⇒Answer: cubic meters or m³

Third question(c):

              ⇒must use dm³ as cubic unit of measure

                 ⇒ as all of the sides given are in decimeter

                     ⇒Answer: cubic decimeter or dm³

Fourth question(d):

              ⇒ must use mm³ as cubic unit of measure

                  ⇒ as all the given sides with side lengths are in millimeters

                      ⇒ Answer: cubic millimeters or mm³

Fifth question(e):

              ⇒ must use m³ as cubic unit of measure

                  ⇒ as all given sides with side lengths are in meter

                      ⇒Answer: cubic meter or m³

In general:

⇒ when faced with these problems

   ⇒ look to the unit of measure of the majority of the side lengths

   ⇒ look to the unit of measure that the problem wants for the answer

Hope that helps!

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Answer:

Width is 46 meter

Length is 86 meter

Given:

Formula:

Trial and improvement:

1st try with w = 50

w(w + 40) = 4000

50(50 + 40) = 4000

4500 ≠ 4000

Value too high.

2nd try with w = 45

w(w + 40) = 4000

45(45 + 40) = 4000

3825 ≠ 4000

Value too small

3rd try with w = 46

w(w + 40) = 4000

46(46 + 40) = 4000

3956 ≠ 4000

This value is somewhat near to the area value.

It is found that width = 46 m then length = (w + 40) = (46 + 40) = 86 m

f(-2) = 2(-2)² - 8(-2) + 6 = 30

f(-1) = 2(-1)² - 8(-1) + 6 = 16

f(0) = 2(0)² - 8(0) + 6 = 6

f(1) = 2(1)² - 8(1) + 6 = 0

f(2) = 2(2)² - 8(2) + 6 = -2

Answer:

k = 4

Explanation:

[tex]\sf 10^{k-2}=100[/tex]

make bases similar

[tex]\sf 10^{k-2}=10^2[/tex]

cancel out the bases

[tex]\sf k-2=2[/tex]

add '2' on both sides

[tex]\sf k-2+2=2+ 2[/tex]

simplify the following

[tex]\sf k =4[/tex]

Answer:

[tex]\fbox {D. 10}[/tex]

Step-by-step explanation:

As the triangles are similar :

45/55 = (12x - 3)/143

9/11 = (12x - 3)/143

9 x 13 = 12x - 3

12x = 117 + 3

12x = 120

x = 10

Answer:

D. 10

Step-by-step explanation:

We can use similar triangles to solve this question. ΔRSE ≅ ΔFGE by SAS. We can set up this similarity equations: [tex]\frac{SE}{GE} = \frac{RE}{FE}[/tex] . Plugging in the numbers from the diagram, we get [tex]\frac{45}{12x-3} = \frac{55}{143}[/tex] . Using cross multiplication, we get the following equation:

[tex]45 * 143 = 55 *(12x-3)\\ 6435 = 660x - 165\\6600 = 660x\\x = 10[/tex]

Our final answer is D. 10

Answer:

C

Step-by-step explanation:

Answer:

Please review the question.  I don't see a diagram. And the "expressions" are just numbers.

Step-by-step explanation:

The expressions aren't really expressions.  There are no variables (x or y).

-6 - (-1)   is -5

-6 - 1      is -7

-5 - (-1)   is -4

-5 -1       is -6

We don't know if these are values of x or y, so the diagram could only be a series of dots on a number line.

Each step of the proof are:

The given parameter is:

Lines a and b are parallel.

This is represented as; a || b

Corresponding angles are equal.

∠1 and ∠5 are corresponding angles.

So, we have: ∠1 ≅ ∠5

Also, they are congruent.

So, we have ∠1 ≅ ∠5

Vertical angles are equal.

∠5 and ∠7 are vertical  angles.

So, we have: ∠5 ≅ ∠7

Also, they are congruent.

So, we have ∠5 ≅ ∠7

According to the transitive property;

If ∠1 ≅ ∠5 and ∠5 ≅ ∠7, then ∠1 ≅ ∠7

Hence, it has been proved that ∠1 ≅ ∠7

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Answer:

A = 42 cm²

Step-by-step explanation:

the area (A) of a parallelogram is calculated as

A = bh ( b is the base and h the perpendicular height )

here b = 6 and h = 7 , then

A = 6 × 7 = 42 cm²

The volume of the spherical ball will be  4 · π · 3² · 10⁶ cubic cm. Then the correct option is A.

The complete question is attached below.

Let r be the radius of the sphere.

Then the volume of the sphere will be

V = 4/3 πr³ cubic units

The radius of the sphere is 3·10² cm.

Then the volume of the spherical ball will be

V =  4/3 πr³

V =  4/3 π(3 x 10²)³

V =  4/3 · π · 3³ · 10⁶

V =  4 · π · 3² · 10⁶ cubic cm

Then the correct option is A.

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The value of x in the equation [tex]\frac{4x}{x - 1} - \frac{5x}{x -2} = \frac{2}{x^2 - 3x + 2}[/tex] is x = -1 or x = -2

The equation is given as:

[tex]\frac{4x}{x - 1} - \frac{5x}{x -2} = \frac{2}{x^2 - 3x + 2}[/tex]

Start by taking the LCM

[tex]\frac{4x(x - 2) - 5x(x - 1)}{(x - 1)(x -2)} = \frac{2}{x^2 - 3x + 2}[/tex]

Expand the denominator

[tex]\frac{4x(x - 2) - 5x(x - 1)}{x^2 -3x +2} = \frac{2}{x^2 - 3x + 2}[/tex]

Cancel out the common factor

4x(x - 2) - 5x(x - 1)= 2

Expand

[tex]4x^2 - 8x - 5x^2 + 5x = 2[/tex]

Evaluate the like terms

[tex]-x^2 - 3x = 2[/tex]

Rewrite as:

[tex]x^2 + 3x + 2 = 0\\[/tex]

Expand

[tex]x^2 + 2x + x + 2 = 0[/tex]

Factorize

x(x + 2) + 1(x + 2) = 0

Factor out x + 2

(x + 1)(x + 2) = 0

Solve for x

x = -1 or x = -2

Hence, the value of x in the equation [tex]\frac{4x}{x - 1} - \frac{5x}{x -2} = \frac{2}{x^2 - 3x + 2}[/tex] is x = -1 or x = -2

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Answer:

3/216

Step-by-step explanation:

The sample space for this experiment is 6^3 which is 216

there are three prime numbers on  die

namely 2 , 3 and 5

so the probability of getting a prime number on all three roles would be

(3/6)^3

Answer:

49(17 + 3)

Step-by-step explanation:

The Distributive Law says [tex]a(b+c)=ab+ac[/tex].  But it can be used in the other direction,  [tex]ab+ac=a(b+c)[/tex].  That way, you look at ab and ac to find the common factor a.  What's playing the role of  a  in the expression 49 x 17 + 49 x 3?  It's 49, the factor that shows up twice.  That's the factor that can be taken outside the parentheses.

49 x 17 + 49 x 3 = 49(17 + 3)

Answer:

Step-by-step explanation:

Solution

This (after combining the top 2 fractions, is a 4 tier fraction.

1/4*3/4 = 3/16

So the question now becomes 3/16 ÷ 10/3

The rule for such a question is invert (turn up side down) the second fraction and multiply.

3/16 * 3/10                   Combine

(3*3)/(16* 10)          

9 / 160

0.05625

[tex]\bf{\dfrac{1}{4}\times\dfrac{3}{4}\div\dfrac{10}{3} }[/tex]

Multiply 1/4 by 3/4 (to do this, multiply the numerator by the numerator and the denominator by the denominator).

[tex]\bf{\dfrac{1\times3}{4\times4}\div\dfrac{10}{3} \ \ \to \ \ \ Multiply.}[/tex]

Do the multiplications in the fraction 1 × 3 / 4 × 4.

[tex]\bf{\dfrac{3}{16}\div\dfrac{10}{3} }[/tex]

Divide 3/16 by 10/3 by multiplying 3/16 by the reciprocal of 10/3.

[tex]\bf{\dfrac{3}{16}\times\left(\dfrac{3}{10}\right) }[/tex]

Multiply 3/16 by 3/10 (to do this, multiply the numerator by the numerator and the denominator by the denominator).

[tex]\bf{\dfrac{3\times3}{16\times10 } \ \ \to \ \ \ Multiply }[/tex]

Do the multiplications in the fraction 3 × 3 / 16 × 10

[tex]\bf{\dfrac{9}{160} \ \ \to \ \ Answer }[/tex]

[tex]\huge \red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]