Answer:
5628(288im you po ma'amdoes anyone live in the concord, NC area? I need to get out of this place TwT
that's tuff you live in NC
Identify the highlighted part of circle
O shown below.
The highlighted part is known as the center of the circle. Then the correct option is C.
What is a circle?It is a locus of a point drawn an equidistant from the center. The distance from the center to the circumference is called the radius of the circle.
Identify the highlighted part of circle O shown below.
The mid-point of the diameter is known as the center of the circle.
The highlighted part is known as the center of the circle.
Thus, the correct option is C.
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Determine the identity. Show all steps.
Step-by-step explanation:
[tex]\frac{1-\sin ^2\left(x\right)}{1+\sin \left(x\right)}=1-\frac{1}{\csc \left(x\right)}[/tex]
[tex]\frac{1-\sin ^2\left(x\right)}{1+\sin \left(x\right)}[/tex]
[tex]=1-\sin \left(x\right)[/tex]
⇒ [tex]\sin \left(x\right)=\frac{1}{\csc \left(x\right)}[/tex]
[tex]=1-\frac{1}{\csc \left(x\right)}[/tex]
least to greatest:
1.11, 1 1/10, the square root of 3, 1.73, 1 2/5
Answer:
least to greatest:
1 1/10, 1.11, 1 2/5, 1.73, the square root of 3
Step-by-step explanation:
1 1/10 = 1.10
1.11 = 1.11
1 2/5 = 1.4
1.73 = 1.73
the square root of 3 is approximately 1.732
Find the circumference and the area of a circle with diameter 2 km.
Write your answers in terms of it, and be sure to include the correct units in your answers.
(a) Circumference:
(b) Area:
Can you please help me with 12 please? I will give an brainlist
Answer:
[tex]x+(\frac{1}{2} x + 12) =[/tex] number of postcards Simone has now
Step-by-step explanation:
x = the number of postcards in Simone's collection
Simone bought 12 more than half the number of postcards in her collection.
So Simone bought half her collection ( [tex]\frac{1}{2} *x = \frac{1}{2} x[/tex] ) plus 12 more postcards.
[tex](\frac{1}{2}x +12)[/tex] = number of postcards Simone bought
Write an expression to show how many pstcards she has now.
[tex]x+(\frac{1}{2} x + 12) =[/tex] number of postcards Simone has now
Let she has p no of postcards before .
She bought 12 more than the half of p
p/2+12Currently she has
p+p/2+123p/2+12(3p+24)/2 postcardspls help me pls help me
Answer:
The Sum of supplementary angles is 180.
Therefore, <A + <B = 180
<A = 19<B
19<B + <B = 180
20<B = 180
<B = 9°
& <A = 19×9°
<A = 171°
whats the answer for this? 0.5x=24
The answer for the expression 0.5x=24 will be x=48
What is a linear equation?The linear equation is defined as the equation having a degree of one or the power of the variable will be one. Linear equation shows the staright line on the graph.
here the given equation is:-
0.5x=24
We can write 0.5 in fraction as 1/2
1/2x=24
x=48
Hence the answer for the expression 0.5x=24 will be x=48
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please help me solve this !
The equation of a function f(x) = x² -4x -12 in the vertex form is f(x) = (x -2)² -16 and the value of the a = 1, h = 2, and k = -16
What is a quadratic equation ?Any equation of the form [tex]\rm ax^2+bx+c=0[/tex] Where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.
We have a quadratic equation:
f(x) = x² -4x -12
f(x) = x² -4x -12 + 4 -4
f(x) = (x -2)² -16
Here a = 1, h = 2, and k = -16
Thus, the equation of a function f(x) = x² -4x -12 in the vertex form is f(x) = (x -2)² -16 and the value of the a = 1, h = 2, and k = -16
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A rectangular stained glass window is made up of identical triangular parts as pictured below. 24 triangles are connected to have a height of 36 inches and a width of 48 inches. every 2 triangles combine to form a rectangle. what is the area of the shaded triangular section? 18 square inches 36 square inches 72 square inches 144 square inches
The area of the shaded triangular section of the stained glass window is 72 square inches.
What is the area of the shaded triangular section?
The first step is to determine the dimensions of each rectangle that makes up the stained glass window.
Length of one rectangle = length of the window / number of rectangles along the length
36/4 = 9 inches
Width of one rectangle = width of the window / number of rectangles along the width
48/3 = 16 inches
Area of the shaded triangular section = 1/2 x area of one rectangle
1/2 ( length x width)
1/2 x (16 x 9) = 72 square inches.
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Answer:
144
Step-by-step explanation:
i took the test
Review the steps of the proof of the identity
At which step was an error made?
sin (A-3) - COSA.
= A.
step 1
step 2
3п
sin
step 3
step 4
Step 1: = sinAcos
3 п
2
-
COSAsin
n ()
Step 2: = (sinA)(0) + COSA( - 1)
Step 3: = (sinA)(0) + (1) (COSA)
Step 4: = 0 + COSA
Step 5: Cos A
Answer:
step 2
and then step 3 : the error neutralized the error of step 2
Step-by-step explanation:
sin(a + b) = sin(a)cos(b) + cos(a)sin(b)
and because
sin(-b) = -sin(b)
cos(-b) = cos(b)
we have
sin(a - b) = sin(a)cos(-b) + cos(a)sin(-b) =
= sin(a)cos(b) - cos(a)sin(b)
3pi/2 = 270° or -90°.
sin(3pi/2) = sin(270) = sin(-90) = -1
that means, it is the full radius straight down from the center of the circle.
cos(3pi/2) = cos(270) = cos(-90) = cos(90) = 0
so, step 1 is correct :
sin(A - 3pi/2) = sin(A)cos(3pi/2) - cos(A)sin(3pi/2) =
= sin(A)×0 - cos(A)×(-1) (correct step 2)
but as we see, the provided step 2 is incorrect.
it should have been the indicated
sin(A)×0 - cos(A)×(-1)
and NOT the provided
sin(A)×0 + cos(A)×(-1)
step 3 based on the erroneous step 2 should then have been
sin(A)×0 - (1)cos(A)
but instead another error with the sign was made that neutralized the error of step 2 and we got after this second mistake by pure chance the overall correct step 3
sin(A)×0 + (1)cos(A)
so, again, the first error was made in step 2.
but technically, there was also a consecutive error made in step 3 to bring everything back to the correct approach.
in 2009 a total of R36 000 was invested in two accounts. One account earned 7% annual interest and the other earned 9% .The total annual earned was R2 920 .How much was invested in each accounts?
a = amount invested at 7%
b = amount invested at 9%
we know the amount invested was ₹36000, thus we know that whatever "a" and "b" are, a + b = 36000. We can also say that
[tex]\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{7\% of a}}{\left( \cfrac{7}{100} \right)a}\implies 0.07a~\hfill \stackrel{\textit{9\% of b}}{\left( \cfrac{7}{100} \right)b}\implies 0.09b[/tex]
since we know the interest earned from the invested was ₹2920, then we say that 0.07a + 0.09b = 2920.
[tex]\begin{cases} a + b = 36000\\\\ 0.07a+0.09b=2920 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{using the 1st equation}}{a + b = 36000\implies \underline{b = 36000-a}}~\hfill \stackrel{\textit{substituting on the 2nd equation}}{0.07a~~ + ~~0.09(\underline{36000-a})~~ = ~~2920} \\\\\\ 0.07a+3240-0.09a=2920\implies 3240-0.02a=2920\implies -0.02a=-320 \\\\\\ a=\cfrac{-320}{-0.02}\implies \boxed{a=16000}~\hfill \boxed{\stackrel{36000~~ - ~~16000}{20000=b}}[/tex]
3. Prove that MNOP is a parallelogram given that its diagonals bisect each other. (MO and NP bisect each other at R)
Answer:
The student is incorrect and for parallelograms to be equal, included angles between them too should be equal.Explanation:When two quadrilaterals MNOP=TQRS, then not only all corresponding sides are equal, all corresponding angles too are equal.As MNOP and TQRS are parallelograms their diagonals bisect each other. And as MO=TR and NP=QS, it is apparent (see figure below) that MX=XO=TY=YR and NX=XP=SY=YQ. And hence two sides of all the four triangles (in each of the parallelogram) are equal.However, the angles included between the two diagonals can change (as is seen from the figure below),and hence MNOP≠TQRS
Step-by-step explanation:
In the figure above, the shaded triangle is bounded by the y-axis, the line y=6, and the line y=2/3x. What is the area, in square units, of the shaded triangle?
Answer:
84.9
Step-by-step explanation:
Samin can run 5 kilometers in 30 minutes. Assuming she keeps a constant pace, how many kilometers can she run in 45 minutes
Answer:
7.5 kilometres
Step-by-step explanation:
In 30 minutes she ran 5 kilometres.
We know that 30 + 15 = 45, so we can divide the minutes and kilometres by 2.
So 30 divided by 2= 15 minutes.
And 5 kilometres divided by 2= 2.5 kilometres.
Now we just add the two distances, as we know that the minutes make 45.
2.5 + 5 = 7.5.
I hope this helps, have a lovely day.
The speed is the distance covered by an object at a particular time. The distance covered by Saima in 45 minutes is 7.5 km.
What is speed?The speed is the distance covered by an object at a particular time. Therefore, it is the ratio of distance and time.
[tex]\rm{Speed = \dfrac{Distance}{Time}[/tex]
Given Samin can run 5 kilometres in 30 minutes. Therefore, the speed of Samin will be,
Speed = 5km/30min = 5/30 km per minute
The distance covered by Saima in 45 minutes will be equal to
Distance = 5/30 × 45 = 7.5 km
Hence, The distance covered by Saima in 45 minutes is 7.5 km.
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5,200,000×(8.3×10^2)−(3.1×10^8) in scientific notation, need it quick
Step-by-step explanation:
5,200,000 = 5.2 × 10⁶
so, we have
(5.2 × 10⁶) × (8.3 × 10²) - (3.1 × 10⁸)
(5.2 × 8.3 × 10⁸) - (3.1 × 10⁸)
(43.16 × 10⁸) - (3.1 × 10⁸) = 40.06 × 10⁸ = 4.006 × 10⁹
A scale drawing of a rectangular park had a scale of 1 cm = 100 m. What is the actual area of the park in meters squared?
Explanation:
5.1 cm on paper corresponds to 5.1*100 = 510 meters in real life due to the scale 1 cm = 100 m.
11.9 cm on paper corresponds to 11.9*100 = 1190 meters in real life.
The 5.1 cm by 11.9 cm rectangle on paper corresponds to the real life counterpart of 510 meters by 1190 meters.
The actual area of the real life park is length*width = 510*1190 = 606,900 square meters
4. Complete the table given below
To solve this formula, we can simply use the formula of half-life of a radioactive substance to calculate the decay rate.
The disintegration constant or decay rate is calculated as 0.385min^-1
Half-LifeThe half-life of a radioactive substance is defined as the time taken for the initial mass of the substance to reach half it's starting mass.
The formula is given as
[tex]T_\frac{1}{2} = \frac{\ln2}{\lambda}[/tex]
Let's substitute the value into the equation and solve through
[tex]T_\frac{1}{2} = \frac{\ln2}{\lambda} \\\lambda = \frac{\ln2}{T_\frac{1}{2} } \\\lambda = \frac{0.693}{1.8} \\\lambda = 0.385[/tex]
The disintegration constant or decay rate is calculated as 0.385min^-1
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Graph the two sides of the equation 2* – 2.5 = 2x +0.7. Zoom in a few times for added accuracy, and use the pointer tool to approximate the intersection. Then, find the value of x at the point (or points) of intersection.
By graphing both functions, we will see that there are two intersections at (-1.41, -2.12) and (3.28, 7.27).
How to solve the equation graphically?
Here we must solve:
[tex]2^x - 2.5 = 2x + 0.7[/tex]
To do it, we can graph the functions:
[tex]y = 2^x - 2.5\\\\y = 2x + 0.7[/tex]
And see where do the curves intersect.
The graph can be seen below, in there we can see two intersections.
One at (-1.41, -2.12) and (3.28, 7.27).
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solve the equation 3x^2-x-3=0 to the nearest tenth
Answer:
You use the quadartic foruala for this problem your fanial anwers is
x=1 + or - radical 37 / 6.
1+ radical 37 over 6 =1.180460422
To the nearest tenth =1.2
1-radical 37 over 6= -0.8471270884
To the nearest tenth=-0.8
Mamadou surveyed 500 of his students in his school about their favorite color students could choose between blue and red 390 students said their favorite color was red what percentage of the surveyed students said they favorite color was red
Answer:
78%
Step-by-step explanation:
a percentage is equivalent to a number over 100.
43% is 43/100
72% is 72/100
87% is 87/100
etc.
to find the percentage of students who said their favorite color is red, we need to set up a cross-multiplication equation
390/500 = ?/100
390 times 100 is 39000
39000/500 = 78
78% of the students said their favorite color is red
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Solve the following equation
Answer: [tex]\frac{- 1}{11}[/tex]
Step-by-step explanation:
Note: the "." symbol stands for multiplication
Given,
[tex]\frac{2x+4}{3} \\[/tex] - [tex]\frac{5x-7}{2}[/tex] = 5
First we the LCM = 6,
[tex]\frac{2(2x+4)}{2.3}[/tex] - [tex]\frac{3(5x-7)}{3.2}[/tex]= 5
Then, we join both sides, since they have same denominator
[tex]\frac{2(2x+4) - 3(5x-7)}{6}[/tex] = 5
Multiply again
[tex]\frac{4x+8 - 15x+21}{6}[/tex] = 5
Add the same numbers
[tex]\frac{-11x + 29}{6}[/tex] = 5
Transpose 6 to the other side
-11x + 29 = 5.6
-11x + 29 = 30
Transpose 29 to the other side
-11x = 30 -29
-11x = 1
Transpose 11 to the other side to get answer
x = [tex]\frac{-1}{11}[/tex]
Hope it helps! If you have any doubts, feel free to ask
if a shoelace drawer is 12.49 inches and a paperclip drawer is 4.579 inches about how many inches wider is the shoelace drawer than the paperclip drawer
The shoelace drawer is 7.911 inches wider than the paperclip drawer.
Measurement difference between two drawersThe height of shoelace drawer is = 12.49 inches
The height of paperclip drawer is = 4.579 inches
Therefore the measurement difference between the two drawer is = 12.49 inches - 4.579 inches
= 7.911 inches
Therefore, the shoelace drawer is 7.911 inches wider than the paperclip drawer.
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Based on probability and if it is appropriate for a decision to be left up to chance, choose every situation that is both statistically fair and morally fair.
The situations that are both statistically fair and morally fair are Situation 2, Situation 3 and Situation 5
How to categorize the situations?For a situation to be fair, the probability of every outcome must be equal.
Using the above definition, we can now analyze each option
Situation 1
Letters = 26
P(Vowel) = 5/26
P(Consonant) = 21/26
Both probabilities are not equal.
Hence, this situation is not fair
Situation 2
Participants = 4
P(Each) = 1/4
All probabilities are equal in the above scenario i.e. 1/4
Hence, this situation is fair
Situation 3
Cousins = 5
P(Each) = 1/5
All probabilities are equal in the above scenario i.e. 1/5
Hence, this situation is fair
Situation 4
Numbers = 5 i.e. 2 to 6
P(Prime) = 3/5
P(Composite) = 4/6
Both probabilities are not equal.
Hence, this situation is not fair
Situation 5
Roommates = 5
Cards = 5
Aces = 4
P(Each) = 1/5
All probabilities are equal in the above scenario i.e. 1/5
Hence, this situation is fair
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how much larger is 8 x 10^8 than 2 x 10^5
Answer:
799800000 larger
Step-by-step explanation:
8 × (10 × 8) = 8000000002 × (10 × 5) = 200000
So . . Subtract
800000000 - 200000 = 799800000
Answer: 799800000
Step-by-step explanation: For 8 x 10^8, do 10 x 10 x 10 10 x 10 x 10 10 x 10 to get 100,000,000 and x 8 is 800,000,000
For 2 x 10^5 do 10^5 ( 10 x 10 x 10 x 10 x 10) which is 100,000 and then x 2 is 200,000
Then subtract.
800,000,000 - 200,000 is 799800000
Question
Consider the diagram.
A triangle with interior angles labeled w degrees, x degrees, and y degrees. A ray extends to the left on the top side of the triangle to create an exterior angle labeled z degrees.
Which equations are true? Select all true equations.
Answer: 1, 2, 5
Step-by-step explanation:
The first equation is true because angles in a triangle add to 180 degrees.
The second equation is true because both sides equal 180 degrees (left hand side is a straight angle, right hand side is the sum of angles in a triangle)
The third equation is not true because z = 180 - y, and 180-y+w+z is not 180.
The fourth equation is not true because z=180-y, and 180-y=w+y is not always true.
The fifth equation is true by the exterior angle theorem.
Julianna is making a rectangular garden in her backyard. She has plotted three of the corners on the coordinate plane.
Geometry help I NEED ASAP ( see picture).
8π is the circumference
1/2 2/4 4/8 are mixed numbers
3. The length of a rectangular patio is
32 feet. Its area is 800 square feet.
What is the perimeter of the patio in
feet?
Answer:
114 feet
Step-by-step explanation:
To figure out the perimeter, we also need the width
The width can be found by dividing the area by the length
800/32 = 25
to find the perimeter, we use the equation 2L + 2W = P
L is the length
W is the width
2(32) + 2(25) = 64 + 50 = 114
114 feet is the perimeter
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