Answer: Wind current
Explanation:
The wind current is the main driving force along with the water currents when one reaches to the seashore. The wind currents above surface of water generates due to the evaporation of water.
The strong wind currents can pull any animal or human walking or running near the sea shore. These currents bring the animal or human towards the sea.
the number of electrons present in 4.2 gram of methane is
Answer:
Explanation:
One CH4 molecules = 10 electrons ( Carbon 6e + 4Hydrogen 4e)
A mole of any substance witll have = 6.023*10^23 atom/ molecuels,
One mole of any substnce is equal is nothing but its moalr mass
Molar mass of CH4 = 16.04
It mean,
16.04 g of CH4 has = 6.023*10^23 molecules of methane
but
4.2 gram of CH4 = 6.023*10^23 * 4.2 /16.04 = 1.58*10^23 molecuels of CH4
So one molecule has =10 electrons
1.58*10^23 molecuels will have = 1.58*10^23 * 10 = 1.58*10^24
Hope this help you
The reform reaction between steam and gaseous methane () produces "synthesis gas," a mixture of carbon monoxide gas and dihydrogen gas. Synthesis gas is one of the most widely used industrial chemicals, and is the major industrial source of hydrogen. Suppose a chemical engineer studying a new catalyst for the reform reaction finds that liters per second of methane are consumed when the reaction is run at and . Calculate the r
Answer:
The rate at which dihydrogen gas is being produced = 0.018 kg/s
Explanation:
Firstly, we write the balanced equation for the production of the synthesis gas
CH₄ + H₂O → CO + 3H₂
The rate of consumption of CH₄ is 159 litres per second. With the reaction ran at T = 294°C and a pressure of 0.86 atm
Using the ideal gas equation, we can convert the volumetric rate of consumption of methane to molar rate of consumption
PV = nRT
PV' = n'RT
P = pressure = 0.86 atm = 87,139.5 Pa
V' = 159 L/s = 0.159 m³/s
n' = ?
R = molar gas constant = 8.314 J/mol.K
T = absolute temperature in Kelvin = 294°C = 567.15 K
87,139.5 × 0.159 = n' × 8.314 × 567.15
n' = (87,139.5 × 0.159) ÷ (8.314 × 567.15)
n' = 2.9383547773 mol/s = 2.938 mol/s
From the stoichiometry of this reaction,
1 mole of methane gives 3 moles of dihydrogen gas
2.938 mol/s of methane will correspond to (3 × 2.938) mol/s of dihydrogen gas, that is, 8.815 mol/s.
Mass flowrate = (molar flowrate) × (molar mass)
Molar flowrate = 8.815 mol/s
Molar mass of dihydrogen gas = 2 g/mol = 0.002 kg/mol
Mass flowrate = 8.815 × 0.002 = 0.0176301287 kg/s = 0.018 kg/s to 2 s.f.
Hope this Helps!!!
Complete Question:
The reform reaction between steam and gaseous methane (CH4) produces "synthesis gas," a mixture of carbon monoxide gas and dihydrogen gas. Synthesis gas is one of the most widely used industrial chemicals, and is the major industrial source of hydrogen.
Suppose a chemical engineer studying a new catalyst for the reform reaction finds that 924. liters per second of methane are consumed when the reaction is run at 261.°C and 0.96atm. Calculate the rate at which dihydrogen is being produced. Give your answer in kilograms per second. Round your answer to 2 significant digits.
Answer:
Rate at which H₂ is produced = 0.12 kg/s
Explanation:
Volume of methane produced, V = 924 litres
Temperature, T = 261.°C = 261 + 273
T = 534 K
Pressure, P = 0.96 atm
Gas constant, R = 0.0821 L-atm/ K-mol
We will calculate the number of moles of methane used in the reaction.
[tex]n_{methane} = \frac{PV}{RT} \\n_{methane} = \frac{0.96 * 924}{0.0821 * 534} \\n_{methane} = \frac{887.04}{43.8414}\\n_{methane} = 20.23 moles[/tex]
Equation of reaction:
[tex]CH_{4} + H_{2} O \rightarrow CO + 3H_{2}[/tex]
From the reaction above :
1 mole of methane produced 3 moles of H₂
20.23 moles of methane will produce (20.23 * 3 ) moles of H₂
Number of moles of H₂, [tex]n_{H_{2} } = 60.69 moles[/tex]
That is 60.69 moles of hydrogen is produced per second.
Number of moles = Mass/ Molar mass
[tex]n_{H_{2} } = \frac{Mass_{H_{2} }}{Molar mass_{H_{2} }} \\Mass_{H_{2}} = n_{H_{2} } * Molar mass_{H_{2} }\\Mass_{H_{2}} = 60.69 * 2.016\\Mass_{H_{2}} = 122.35 g[/tex]
Rate at which H₂ is produced = 122.35 g/s = 0.12 kg/s
What inference can be drawn from the graph?
A + B C + D
A
The reaction between A and B is reactant favored.
B.
The amount of product is greater than the amount of reactant.
C. The reaction uses all its reactants to form products.
D
The reaction reaches equilibrium at 15 seconds
Determine the only possible 2 ion for which the following two conditions are both satisfied: The net ionic charge is one-tenth the nuclear charge. The number of neutrons is four more than the number of electrons. Express your answer as an ion and as an isotope separated by a comma.
Explanation:
The answer is the Calcium ion. It satisfies the conditions of the question.
Condition 1
The net ionic charge is one-tenth the nuclear charge.
In the Calcium ion, Ca²⁺. The nuclear charge in this ion is 20. The net ionic charge is 2.
2 / 20 = 1 / 10. So the net ionic charge is indeed one tenth of the nuclear charge.
Condition 2
The number of neutrons is four more than the number of electrons.
Mass Number of Ca²⁺ = 44
Atomic Number = 20
Neutrons = Mass Number - Atomic Number = 44 -20 = 24
Number of electrons = 20 - 2 = 18
Since Number of Neutrons = 22, Number of electrons = 18. This condition also holds.
As an ion and as an isotope = Ca²⁺, Ca - 42
. How many milliliters of 0.20 M HCl are needed to exactly neutralize 40. milliliters of 0.40 M KOH
Answer:
[tex]V_{HCl}=80mL[/tex]
Explanation:
Hello,
In this case, for the given reactants we identify the following chemical reaction:
[tex]KOH+HCl\rightarrow KCl+H_2O[/tex]
Thus, we evidence a 1:1 molar ratio between KOH and HCl, therefore, for the complete neutralization we have equal number of moles, that in terms of molarities and volumes become:
[tex]n_{HCl}=n_{KOH}\\\\M_{HCl}V_{HCl}=M_{KOH}V_{KOH}[/tex]
Hence, we compute the volume of HCl as shown below:
[tex]V_{HCl}=\frac{M_{KOH}V_{KOH}}{M_{HCl}} =\frac{0.40M*40mL}{0.20M} \\\\V_{HCl}=80mL[/tex]
Best regards.
Which hormones are secreted from the posterior pituitary gland?
Answer:
growth hormone is ur answer
Answer:
Explanation:
two hormones are secreted from posterior lobe i.e. oxytocin and vasopressin
2H2+O2->2H20 How many moles of water can be produced if 8 moles H2 are used
1. Which of the following choices demonstrates the law of constant composition? (Slides 2 ‒ 3: Laws on Matter) (a) Nitrogen and oxygen are both found in nature as diatomic molecules. (b) When 20.0 g of nitrogen and 32.0 g of oxygen are combined and allowed to react in two separate experiments, both times the product isolated from reaction contains 14.0 g of nitrogen and 32.0 g of oxygen. (c) Nitrogen and oxygen gases are mixed to produce a sample consisting of 20.0 g of nitrogen and 32.0 g of oxygen. (d) When 14.0 g of nitrogen and 32.0 g of oxygen are mixed and react, there is no measurable change in mass during the reaction. (e) Nitrogen and oxygen are gases found in air, nitrogen is approximately 79% of air and oxygen is approximately 21%.
Answer:
(b) When 20.0 g of nitrogen and 32.0 g of oxygen are combined and allowed to react in two separate experiments, both times the product isolated from reaction contains 14.0 g of nitrogen and 32.0 g of oxygen.
Explanation:
The law of definite proportion states that a gen chemical compound always contains its constituent elements in a fixed ratio by mass, independent on the method of preparation.
The molar mass of Nitrogen and Oxygen would always remain the same, allowing for exact reactant masses (or mole ratio) irrespective of the given amount of sample.
In the following chapter, enzyme catalysis reactions will be extensively reviewed. The first step in these reactions involves the binding of a reactant molecule (referred to as a substrate) to a binding site on the enzyme. If this binding is extremely efficient (that is, equilibrium strongly favors the enzyme–substrate complex over separate enzyme and substrate) and the formation of product rapid, then the rate of catalysis could be diffusion limited. Estimate the expected rate constant for a diffusion controlled reaction using typical values for an enzyme ( and Å) and a small molecular substrate ( and Å).
Complete Question
The complete question is shown on the first uploaded image
Answer:
The rate constant is [tex]k_d = 3.44*10^{10} \ L \cdot mol^{-1} s^{-1}[/tex]
Explanation:
From the question we are told that
The values for an enzyme is given as
[tex]D_1 = 1.00 *10^{-7} \ cm^2 s^{-1}[/tex]
[tex]r_1 = 40.0 \r A = 40*10^{-8} cm[/tex]
The values of a small molecular substrate is
[tex]D_2 = 1.00 *10^{-5} \ cm^2 s^{-1}[/tex]
[tex]r_2 = 5.00 \r A = 5.00*10^{-8} \ cm[/tex]
The equation relating the rate constant is
[tex]k_d = 4 \pi N_A (D_1 +D_2) (r_1 +r_2)[/tex]
substituting values
[tex]k_d = 4 \pi (6.022 *10^{23})(1 *10^{-7} * 1*10^{-5} (40*10^{-8} + 5*10^{-8}))[/tex]
[tex]k_d = 3.44*10^{10} \ L \cdot mol^{-1} s^{-1}[/tex]
Which of the following processes is endothermic? Group of answer choices the reaction associated with the ionization energy of lithium. the formation of CO2 from its elements in their standard states. the reaction associated with the heat of formation of Sr S. the reaction associated with the lattice energy of Na Br.
Answer:
the reaction associated with the ionization energy of lithium
Explanation:
An endothermic process is any process which requires or absorbs energy from its surroundings, usually in the form of heat.
the reaction associated with the ionization energy of lithium:
Ionization energy is endothermic because it requires an energy input to occur, we need to supply energy to remove that outermost electron.
the formation of CO2 from its elements in their standard states:
This reaction is exothermic, heat is released per mole of CO2 formed.
the reaction associated with the heat of formation of Sr S:
Heat is giving off, so the process is an exothermic process.
the reaction associated with the lattice energy of Na Br:
Lattice energy is exothermic. Lattice energy is the energy released when gaseous cations and anions associate with each other to form a solid.
This increase in blood pHpH due to hyperventilation disrupts O2O2 transport by causing the deprotonation of various residues of the hemoglobin protein. With less O2O2 reaching the brain, an individual who is hyperventilating may faint. Because the brain needs O2O2 to produce ATP, the brain temporarily shuts down the one function that demands the most ATP—consciousness. Shutting down consciousness conserves energy and allows the brain to devote its resources to maintaining essential life support functions, such as breathing. When O2O2 transport regains its efficiency, the individual regains consciousness. How would rebreathing exhaled air from a paper bag prevent an individual who is hyperventilating from fainting?
The question is incomplete as it does not have the options which has been provided in the attachment.
Answer:
1. sudden decrease
2. Respiratory alkalosis
Explanation:
Hyperventilation is a condition caused by the excess removal of the CO₂ from the blood which leads to the decrease in the pCO₂ of the arteries.
This decrease can cause fainting and death of the individual due to the malfunctioning of the body parts, especially the brain.
The decrease in the CO₂ amount of the blood causes the formation of bicarbonate and H⁺ ions which leads to respiratory alkalosis.
Therefore the selected options are correct.
. In which reaction is nitric acid acting as an oxidising agent?
A. CuO + 2HNO3 → Cu(NO3)2 + H2O
B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2
C. Na2CO3 + 2HNO3 → 2NaNO3 + H2O + CO2
D. NaOH + HNO3 → NaNO3 + H2O. In which reaction is nitric acid acting as an oxidising agent?
A. CuO + 2HNO3 → Cu(NO3)2 + H2O
B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2
C. Na2CO3 + 2HNO3 → 2NaNO3 + H2O + CO2
D. NaOH + HNO3 → NaNO3 + H2O
Answer:
B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2
Explanation:
Hello,
In this case, we should understand oxidizing agents as those substances able to increase the oxidation state of another substance, therefore, in B. reaction we notice that copper oxidation state at the beginning is zero (no bonds are formed) and once it reacts with nitric acid, its oxidation states raises to +2 in copper (II) nitrate, thus, in B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2 nitritc acid is acting as the oxidizing agent.
Moreover, in the other reactions, copper (A.), sodium (C. and D.) remain with the same initial oxidation state, +2 and +1 respectively.
Regards.
Answer:
B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2
Explanation:
A substance is acting as oxidising agent when is reducing its chemical state in the reaction.
In HNO3, Nitrogen has an oxidation state of +5 (Each oxygen is -2, 3 oxygens, -6, 1 hydrogen, +1). Thus, if the oxidation state of the nitrogen in the products is < +5, the nitrogen is reducing its oxidation state acting as oxidising agent.
In the reactions:
A. CuO + 2HNO3 → Cu(NO3)2 + H2O . In Cu(NO₃)₂, Nitrogen has an oxidation state of +5. Thus, nitric acid is not acting as oxidising agent.
B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2 . Also, oxidation state in Cu(NO₃)₂ does not have any change but there is another product, NO₂, where nitrogen has an oxidation state of +4. That means nitric acid is acting as oxidising agent.
C. Na2CO3 + 2HNO3 → 2NaNO3 + H2O + CO2 . Here, in NaNO₃, oxidation state of nitrogen is +5 (Na: +1, 3 O: -6). Thus, nitrogen is not changing is oxidation state and nitric acid is not acting as oxidising agent.
D. NaOH + HNO3 → NaNO3 + H2O. Here, also, the product is NaNO₃. That means nitric acid is not acting as oxidising agent.
what is the relative atomic mass of a hypothetical element that consists of the following isotopes in the indicated natural abundances?? pls help
Answer:
87.3
Explanation:
To calculate the relative atomic mass
((84.9*15)+(86.9*12.9)+(87.9*72.1))/15+12.9+72.1
(1273.5 + 1121.01 + 6337.59) / 100
8732.1/100
87.321 = 87.3
What would be the volume of a balloon containing 64g of oxygen gas at STP (standard temperature and pressure)? You should be able to obtain this answer by calculation or by using logical reasoning.
Answer: 44.8 L
Explanation:
To find the volume, we would need to use the ideal gas law.
Ideal Gas Law: PV=nRT
We take the given information and plug it into the equation, but first, we have to manipulate the equation so that we are finding volume.
[tex]V=\frac{nRT}{P}[/tex]
P= 1.00 atm (STP)
T= 273.15 K (STP)
R= 0.08206 Latm/Kmol
n= [tex]64g*\frac{1mol}{31.998 g O_{2} }=2 mol[/tex]
[tex]V=\frac{(2 mol)(0.08206Latm/Kmol)(273.15 K)}{1.00atm} =44.8 L[/tex]
What is economic racism?
OA. Something that causes financial inequality for certain ethnic groups
OB. A stock market crash
OC. Laws and policies that go against a particular race
OD. All of the above
Please
Answer:
A
Explanation:
Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a tank with of ammonia gas, and when the mixture has come to equilibrium measures the amount of nitrogen gas to be . Calculate the concentration equilibrium constant for the decomposition of ammonia at the final temperature of the mixture. Round your answer to significant digits.
Answer:
Kc = 15.25
Explanation:
In this case, As I say in the comments, you are missing the following data of moles and volume which are:
Initial moles of ammonia = 29 mol
Final moles of nitrogen = 13 mol
Volume tank = 75 L
Now, if your data is different, just replace the values and follow the same procedure written here to get the accurate result.
With these data, let's write the equilibrium reaction that is taking place here:
2NH₃ <---------> N₂ + 3H₂ Kc = ?
To get the Kc, we need to use the following expression:
Kc = [N₂] [H₂]³ / [NH₃]²
This expression is only usable when we reach the equilibrium. But we don't have the concentrations in equilibrium of any species, so, we need to get those values. To get that, we need to do an ICE chart, write the initial and final concentrations given, and then, replace the values.
First, the concentrations of the species are:
[NH₃] = 29 / 75 = 0.3867 M
[N₂] = 13 / 75 = 0.1733 M
Now that we have these values, we will replace them in the ICE chart, and then, rewrite the Kc expression to get that value so:
2NH₃ <---------> N₂ + 3H₂ Kc = ?
i) 0.3867 0 0
c) -2x +x +3x
e) 0.3867-2x x 3x
However, as we already have the value for concentration of nitrogen, this will be the value of "x", therefore, our final values in equilibrium would be:
[NH₃] = 0.3867 - 2(0.1733) = 0.0401 M
[H₂] = 3(0.1733) = 0.5199 M
Now with these values, we can replace them in the Kc expression to get that value so:
Kc = (0.5199)³ * (0.1733) / (0.0401)²
Kc = 0.0244 / 0.0016
Kc = 15.25
And this is the value of Kc for this reaction.
How cholestrol transport fatty acids in body ?
In order to use the energy stored in fat, the body breaks dow triglycerides into fatty acids, which individual cells burn for energy
Calculate the free energy change for the reaction:
2 NO(g) + O2(g) → 2 NO2(g)
(A) - 9.3 kcal
(B) + 24.9 kcal
(C) + 9.3 kcal
(D) - 16.6 kcal
(E) + 16.6 kcal
Answer:
(D) - 16.6 kcal
Explanation:
Hello,
In this case, the Gibbs free energy for the given reaction is computed in terms of the Gibbs free energy of formation of each species involved in the chemical reaction:
[tex]\Delta _rG=2\Delta _fG_{NO_2}-2\Delta _fG_{NO}-\Delta _fG_{O_2}[/tex]
Thus, it is found for nitrogen monoxide, oxygen and nitrogen dioxide the following Gibbs free energies of formation: 87.6, 0 and 51.3 kJ/mol respectively, therefore we compute:
[tex]\Delta _rG=2(51.3kJ/mol)-2(87.6kJ/mol)=-72.6kJ*\frac{1kcal}{4.184kJ} \\\\\Delta _rG=-17.35kcal[/tex]
The closest result is (D) - 16.6 kcal, as such difference is noticed when different sources for thermochemical data are used, in this case, the NIST data were used.
Best regards.
Explain in terms of bonding why the hydrocarbon 2-methylpropane is saturated
Answer:
because no 2 or 3 bond so it is saturated
Examine the reaction equation. CH4 + O2 →H2O + CO2 What coefficients will balance the equation? A) 2, 3, 2, 2 B) 1, 3, 2, 1 C) 1, 2, 2, 1 D) 1, 1, 1, 1
Answer:
B
Explanation:
CH4 + O2 →H2O + CO2
Left side
C = 1
H = 4
O = 2
Right side
C = 1
H = 2
O = 3
So find common denominator in this case would be 6 O
CH4 + 3O2 →2H2O + CO2
Left side
C = 1
H = 4
O = 6
Right side
C = 1
H = 4
O = 6
Answer:
[tex]\huge \boxed{\mathrm{C) \ 1, 2,2,1}}[/tex]
[tex]\rule[225]{225}{2}[/tex]
Explanation:
[tex]\sf CH_4+ O_2 \Rightarrow CO_2 + H_2O[/tex]
Balancing the Hydrogen atoms on the right side,
[tex]\sf CH_4+ O_2 \Rightarrow CO_2 +2 H_2O[/tex]
Balancing the Oxygen atoms on the left side,
[tex]\sf CH_4+ 2O_2 \Rightarrow CO_2 +2 H_2O[/tex]
[tex]\rule[225]{225}{2}[/tex]
Suppose a current of flows through a copper wire for seconds. Calculate how many moles of electrons travel through the wire. Be sure your answer has the correct unit symbol and round your answer to significant digits.
Answer:
1.20 × 10⁻³ mol e⁻
Explanation:
There is some info missing. I think this is the original question.
Suppose a current of 0.880 A flows through a copper wire for 132 seconds. Calculate how many moles of electrons travel through the wire. Be sure your answer has the correct unit symbol and round your answer to significant digits.
Step 1: Given data
Intensity of the current (I): 0.880 A (= 0.880 C/s)Time elapsed (t): 132 sStep 2: Calculate the charge, in Coulomb, that travel through the wire
We will find the circulating charge (q) using the following expression.
[tex]q = I \times t = \frac{0.880C}{s} \times 132s = 116C[/tex]
Step 3: Calculate the moles of electrons with a charge of 116 C
We will use the relationship 1 mole of electrons = 96,486 C (Faraday's constant)
[tex]116C \times \frac{1mol\ e^{-} }{96,486 C} =1.20 \times 10^{-3} mol\ e^{-}[/tex]
Based on the activity series provided which reactants will form products? F>Cl>Br>l
Answer:
CuI₂ + Br₂
Explanation:
Answer:
CuI₂ + Br₂
Explanation:
1) The activity series F > Cl > Br > I means that F is the most active and I is the least active of those four elements (the halogens, group 17 in the periodic table).
The activity is a measure of how eager is an element to react compared to other elements in the series in a single replacement reaction.
2) Choice 1: CuI₂ + Br₂
Since the activity of Br is higher than that of I, Br will react with CuI₂, displacing I, which will be left alone, as per this chemical equation:
CuI₂ + Br₂ → CuBr₂ + I₂
Being I less active than Br, it cannot displace Br in CuBr₂.
3) Choice 2: Cl₂ + AlF₃
Being Cl less active than F, the former will not displace the latter, and the reaction will not proceed.
4) Choice 3: Br₂ + NaCl
Again, being Br less active than Cl, the former will not displace the latter, and the reaction will not proceed.
5) Choice 4: CuF₂ + I₂
Once more, being I less active than F, the former will not displace the latter, and the reaction will not proceed.
hope this helped!
How many moles are in 42.9 g of Fe2O4
Answer:
0.24375moles
Explanation:
Moles=mass/moler mass
Fe-56
O-16
(56×2)+(16×4)
=176
42.9÷176=0.24375moles
1. Potassium (K) has an atomic mass of 39.0983 amu and only two naturally-occurring isotopes. The K-41 isotope (40.9618 amu) has a natural abundance of 6.7302%. What is the mass (in amu) of the other isotope
Answer:
38.96383282 amu
Explanation:
39.0983 = (40.9618 [tex]\times[/tex] 0.067302) + ( ? [tex]\times[/tex] (1-0.067302)
39.0983 = 2.756811064 + ( ? [tex]\times[/tex] 0.932698)
subtract 2.756811064 from both sides
36.34148894 = ( ? [tex]\times[/tex] 0.932698)
divide both sides by 0.932698
? = 38.96383282 amu
Answer:
38.96383282 amu
Explanation:
39.0983 = (40.9618 0.067302) + ( ? (1-0.067302)
39.0983 = 2.756811064 + ( ? 0.932698)
subtract 2.756811064 from both sides
36.34148894 = ( ? 0.932698)
divide both sides by 0.932698
? = 38.96383282 amu
A 50.0 mL solution of 0.141 M KOH is titrated with 0.282 M HCl . Calculate the pH of the solution after the addition of each of the given amounts of HCl .
Answer:
pH =1 2.84
Explanation:
First we have to start with the reaction between HCl and KOH:
[tex]HCl~+~KOH->~H_2O~+~KCl[/tex]
Now for example, we can use a volume of 10 mL of HCl. So, we can calculate the moles using the molarity equation:
[tex]M=\frac{mol}{L}[/tex]
We know that [tex]10mL=0.01L [/tex] and we have the concentration of the HCl [tex]0.282M[/tex], when we plug the values into the equation we got:
[tex]0.282M=\frac{mol}{0.01L}[/tex]
[tex]mol=0.282*0.01 [/tex]
[tex]mol=0.00282[/tex]
We can do the same for the KOH values ([tex]50mL=0.05L[/tex] and [tex]0.141M[/tex]).
[tex]0.141M=\frac{mol}{0.05L}[/tex]
[tex]mol=0.141*0.05 [/tex]
[tex]mol=0.00705[/tex]
So, we have so far 0.00282 mol of HCl and 0.00705 mol of KOH. If we check the reaction we have a molar ratio 1:1, therefore if we have 0.00282 mol of HCl we will need 0.00282 mol of KOH, so we will have an excess of KOH. This excess can be calculated if we substract the amount of moles:
[tex]0.00705-0.00282=0.00423mol~of~KOH[/tex]
Now, if we want to calculate the pH value we will need a concentration, in this case KOH is in excess, so we have to calculate the concentration of KOH. For this, we already have the moles of KOH that remains left, now we need the total volume:
[tex]Total~volume=50mL+10mL=60mL[/tex]
[tex]60mL=0.06L[/tex]
Now we can calculate the concentration:
[tex]M=\frac{0.00423mol}{0.06L}[/tex]
[tex]M=0.0705[/tex]
Now, we can calculate the pOH (to calculate the pH), so:
[tex]pOH=-Log(0.0705)[/tex]
[tex]pOH=1.15[/tex]
Now we can calculate the pH value:
[tex]14=~pH~+~pOH[/tex]
[tex]pH=14-1.15=12.84[/tex]
Which of the following shows the proper configuration of a straight chain isomer of nonane? A B C
Answer:
C
Explanation:
The correct option is C and the anming is 2-ethyl-3-methylhexane.
Isomers are compounds that have the same molecular formula but different structural formula; that s the way in which the atoms are arranged.
The Molecular formula of nonane is C9H20.
Answer:
C
Explanation:
Which equation represents the reaction of a weak acid with water
Answer:
Which equation represents the reaction of a weak acid with water? the equation is : HCl + H2O H3O+ + Cl- HCO3– + H2O H2CO3 + OH– H2O H + + OH- HCOOH + H2O H3O+ + HCOO
Explanation:
hope it helps : )
Answer:
Hey mate, here is your answer. Hope it helps you.
HCOOH + H2O ↔ H3O+ + HCOO-
Explanation:-
A strong acid is one which completely dissociates into its corresponding ions in aqueous medium.
In contrast, a weak will only partially dissociate such that there is an equilibrium between the dissociated ions and the undissociated acid.
In the given examples:
HCl, HCO3- and H2CO3 are all strong acids. However, HCOOH i.e. formic acid is a weak acid which dissociates in water to form H3O+ and formate ion, HCOO-
HCOOH + H2O ↔ H3O+ + HCOO-
A person has a height of 65 inches
You want to find out the height of
that person in centimeters. Which
unit conversion would you use?
Answer:
1 inch = 2.54 centimeters
Explanation:
A conversion factor or unit conversion is used to change the units only without affecting the value.
1 inch = 2.54 centimeters
Given, height = 65 inches
So, the height of that person in centimeters = 65 x 2.54
= 165.1 cm
Hence, the person's height in centimeters will be 165.1 cm.
Two types of alcohols namely as methylcyclohexanol and 2-methyl-2-hexanol were subjected to dehydration reaction and yield a mixture of two isomeric alkenes. Proposed a chemical reaction of both alcohols and determine which one is the major product. Justify your answer.
Answer:
a) Methylcyclohexanol = 1-methylcyclohex-1-ene and methylenecyclohexane
b) 2-methyl-2-hexanol = 2-methylhex-1-ene and 2-methylhex-2-ene
Explanation:
We have to remember that the dehydration of alcohols follows the Zaitsev rule. So, the most substituted alkene would be the major product for both molecules
In the case of methylcyclohexanol we have several options to put the double bond. Inside of the cyclic structure (1-methylcyclohex-1-ene) or between the cyclic structure and the methyl group (methylenecyclohexane). The most substituted one is 1-methylcyclohex-1-ene, so this is our major product.
In the case of 2-methyl-2-hexanol we have again several options for the double bond. Between the tertiary carbon (the carbon that holds the "OH" group) and the carbon in the left (2-methylhex-2-ene). The other option is to put the double between the tertiary carbon the carbon in the right (2-methylhex-1-ene). The most substituted one is 2-methylhex-2-ene, so this is our major product.
See figure 1
I hope it helps!
• When a mechanism has been investigated in detail, it can be understood on many levels of differing detail. • An additional detail about addition of hydrogen halides to alkenes in non-polar solvents is that additional molecules of hydrogen halide assist the rate-determining proton transfer by hydrogen-bond solvation of the halide ion. • What kinetic order is HI (the value of "x" in the equation below) would HI addition to propene exhibit according to the mechanism above? The predicted kinetic order in HI is . (an integer)
Complete Question
The complete question is shown on the first uploaded image
Answer:
The kinetic order in HI is x= 2
Explanation:
Generally the slow step in a reaction mechanism is the rate determining step
Now with this knowledge at the back of our minds we can see that the number of moles of HI i s 2 which implies that the order of HI is 2m
So we can represent the rate law as
[tex]Rate = k [CH_3 CHCH_2][HI]^2[/tex]
hence
x = 2