I need help with my homework please? I will give a lot of points and a brainlist.
Answers
Answer:
1. False
some metals are ferromagnetic
2.True
3. True
4. True
5. False
The strength of electromagnetic can be increased by increasing the number of wire around it
#1
FalseVery few like Fe,Ni ,Co are ferromagnetic.
Most are para magneticSome are dia magnetic#2
True
#3
True
#4
It's Orsterd experiment conclusion
True#5
FalseBecause
[tex]\sf B=\mu_o nI[/tex]
If you decrease no of turns magnetic force decreases
Related Questions
The left side of the armature in an electric motor is pushed down. when the current changes direction, how is the motion of the armature affected? it is pulled up on the left side. it is pulled up on the right side. it is pulled toward the commutator. it is pushed away from the commutator.
Answers
Answer:
It is pulled up on the left side. took the test
Explanation:
2. At the earth’s surface, a projectile is launched straight up at a speed of 10. 0 km/s. To what height will it rise? ignore air resist
Answers
Answer:
5.097 m
Explanation:
H = vo t - 1/2 a t^2
= 10t - 1/2 (9.81) t^2 max occurs at -b/2a = 10/9.81=1.0194 sec
sub in this 't' value to get H =5.097 m
Two beams of coherent light are shining on the same piece of white paper. with respect to the crests and troughs of such waves, darkness will occur on the paper where
Answers
Answer:
"where crests and troughs have their maxima at the same time"
Crests and troughs are 180 deg out of phase and when they have their maxima at the same time and place, their net contribution will be zero"
Which section from the article BEST explains why wavelength and frequency are dependent on each other? (A) "Amplitude And Height" (B) "Wavelength And Cycle" (C) "Frequency And Period" (D) "Speed"
Answers
You walk 6 meters east followed by 4 meters west in 4 seconds. What is your velocity
Answers
Answer:
16 velocity
Explanation:
For a bike that went a distance of 100 meters in 45 seconds
southeast to his friend's house. what would his velocity be?
Answers
Answer:
velocity = Displacement
Time
Velocity = 100m 45° SE
45s
= 2. 11m/s 45° SE
A radar transmits a signal towards an aeroplane. The velocity of the signal is 3.0 x 10^8 m/s. After 0.0036 s, the radar detects the reflected signal. What is the distance of the aeroplane from the radar?
Answers
The distance of the airplane from the radar will be 1.08×10⁶ m. Distance can refer to a physical length.
What is distance?Distance is a numerical representation of the distance between two objects or locations.
The distance of the airplane from the radar is found by the formula;
Distance = velocity × time
Distance = 3.0 x 10^8 m/s× 0.0036 s,
Distance = 1.08×10⁶ m.
Hence, the distance of the airplane from the radar will be 1.08×10⁶ m.
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Which of the following is a pure
substance?
A. Heterogenous mixture
B. Homogenous mixture
C. Solution
D. Element
Answers
Answer:
B. Homogenous mixture
Explanation:
........
A 1.5 x 105 kg train is accelerating. The force applied to the train is 7.0 x 104 N. What is the train’s acceleration?
Answers
Answer:
See below
Explanation:
F = ma
7 X 10^4 = 1.05 x 10^5 * a
a = .666 = 2/3 m/s^2
I need help with my homework please?
Answers
Answer:
i need the describtion like what i need to do
Explanation:
Answer:
it's easy bro once try yourself if you can't then l am here
help please!
will give brainliest to the correct answer.
question; the work one by friction force to stop a car of mass 1000 kg moves with velocity 72km/h is ..........
a) 72 x 10³ J
b) 2 x 10⁴ J
c) 2 x 10⁵ J
d) 4 x 10⁵ J
an explanation for future reference would be appreciated^^
Answers
Answer:
b)
Explanation:
The work done by friction is equal to the all of the initial Kinetic Energy lost when the vehicle comes to a complete stop
KE = 1/2 m v^2
72 km / hr = 20 m/s
KE = 1/2 * 1000 kg * (20 m/s)^2 = 200 000 J = 2 x 10^4 J
Identify the amplitude of the wave using the picture below.
Answers
Answer:
Line 2 is the amplitude
Explanation:
The amplitude is the distance from equilibrium to the top of the maximum or minimum of the wave.
How far away is the closest star?
Answers
Answer: Proxima Centauri is the closet star about 40,208,000,000,000 km away.
Explanation:
Answer:
The closest star is about 25,300,000,000,000 miles (39,900,000,000,000 kilometers) away
Explanation:
A surfacing whale in an aquarium produces water wave crests having an amplitude of 1.2 meters every 0.40 second. If the water wave travels at 4.5 meters per second, the wavelength of the wave is
Answers
The wavelength of the water wave having a amplitude of 1.2 meters every 0.4 seconds is 1.8 m .
What is wavelength?Wavelength is the total distance traveled by a wave in one cycle.
To calculate the wavelength of the wave, we use the formula connecting
speed, wavelength, and Period.
Formula:
v = λ/T........... Equation 1Where:
v = Velocity of the waveλ = WavelengthT = PeriodMake λ the subject of the equation
λ = vT............ Equation 2From the question,
Given:
v = 4.5 m/sT = 0.40 sSubstitute these values into equation 2
λ = (4.5×0.4)λ = 1.8 mHence, The wavelength of the water wave having a amplitude of 1.2 meters every 0.4 seconds is 1.8 m .
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The primary coil of a transformer has 1,000 turns of wire, and its secondary coil has 2,000 turns of wire. The input voltage is 140 V. What is the output voltage of the transformer?
Answers
Answer:
Here is the solution hope it helps:)
Answer:
280v
Explanation:
During which season is the sun highest in the sky?.
Answers
Answer: summer
Explanation:
In June, when the Earth is tilted towards Sun and the Sun reaches its highest point in the sky, that is called the summer solsticeand is the longest day of the year.
A tube is open only at one end. A certain harmonic produced by the tube has a frequency of 475 hz. The next higher harmonic has a frequency of 1425 hz. The speed of sound in air is 343 m/s
Answers
The formula for the fundamental frequency for an open tube at one end is : F = nV/4L the integer n = 3 which describe the frequency 450 hertz and length of tube L = 0.6m approximately
What is frequency?Frequency of the object is defined as the number of cycles attend in a second .
Given that a tube is open only at one end. And a certain harmonic produced by the tube has a frequency of 450 Hz. The next higher harmonic has a frequency of 750 Hz. The formula for the fundamental frequency for an open tube at one end is :
[tex]F = \dfrac{V}{4L}[/tex]
That is, 1st harmonic
[tex]\dfrac{V}{4L} = F[/tex]
2nd harmonic =
[tex]\dfrac{3V}{4L} = 3F[/tex]
3rd harmonic =
[tex]\dfrac{5V}{4L} = 5F[/tex]
The general formula can therefore be [tex]F =\dfrac{ nV}{4L}[/tex]
For the first harmonic in the question,
[tex]450 = \dfrac{343n}{4L}[/tex]
make 4L the subject of the formula
[tex]4L = \dfrac{343n}{450}[/tex]
The next higher harmonic will be
[tex]750 = \dfrac{343(n + 2)}{4L}[/tex]
make 4L the subject of the formula
[tex]4L = \dfrac{343(n + 2)}{ 750}[/tex]
Equate the two 4L
[tex]\dfrac{343n}{450} = \dfrac{343( n + 2)}{750}[/tex]
cross multiply
[tex]257250n = 154350( n + 2 )[/tex]
[tex]257250n = 154350n + 308700[/tex]
collect the likes term
[tex]257250n - 154350n = 308700[/tex]
[tex]102900n = 308700[/tex]
[tex]n =\dfrac{ 308700}{102900}[/tex]
n = 3
Given that the speed of sound in air is 343 m/s, The length of the tube can be calculate by using the same formula.
[tex]F = \dfrac{nV}{4L}[/tex]
[tex]450 = \dfrac{3(343)}{4L}[/tex]
[tex]4L = \dfrac{1029}{450}[/tex]
4L = 2.28
[tex]L = \dfrac{2.28}{4}[/tex]
L = 0.57 m
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2. A box filled with books has a mass of 15.0 kg. It is pushed across the floor with a constant force of 60.0 N. If the frictional force by the floor on the box is 15.0 N, what is the acceleration of the box?
Answers
Answer:
[tex]3 m/s^{2}[/tex]
Explanation:
ΣF=ma
The two forces at play are the force applied and the force due to friction. As they are opposing forces set the direction being pushed as the positive in the x direction. the equation you come out with is 60 - 15=(15)A (we know mass to be 15kg). Solve for 3 m/s^2.
An astronaut lands on a new, recently discovered planet in a different star system. The astronaut measures the acceleration due to gravity on the planet to be 12m/s2, and the mass of the planet is measured to be 7. 5E23kg. What is the radius of the new planet?
Answers
Answer:
The radius of the new planet is ~2.04 * 10⁶ m, or 2,041,752 m.
Explanation:
We can use Newton's Law of Universal Gravitation:
[tex]\displaystyle F_g=G\frac{Mm}{r^2}[/tex]Let's look at Newton's 2nd Law:
[tex]F=ma[/tex]We can set these equations equal to each other:
[tex]\displaystyle G\frac{Mm}{r^2} =ma[/tex]The mass of the second mass (astronaut) cancels out. We are left with:
[tex]\displaystyle G\frac{M}{r^2} =a[/tex]We are solving for the radius of the new planet, so we can rearrange the equation:
[tex]\displaystyle r=\sqrt{\frac{GM}{a} }[/tex]Substitute in our known values given in the problem (G = 6.67 * 10⁻¹¹ ; M = 7.5 * 10²³ ; a = 12).
[tex]\displaystyle r =\sqrt{\frac{(6.67\times 10^{-11})(7.5 \times 10^{23}}{12} }[/tex][tex]r=2.04 \times 10^6[/tex]The radius of the new planet is ~2.04 * 10⁶ m.
An electron confined in a one-dimensional box is observed, at different times, to have energies of 12 ev, 27 ev, and 48 ev
Answers
Answer:
l=3.5 x 10^-10m
Explanation:
just toook the test got it right good luck!
Name one energy source that is used to make sure that we can provide energy consistently,even though demand varies during the day
Answers
Answer:
Water power, eg tidal and hydroelectricity , is reliable and predictable because of the Moon causing the tides and rainfall filling reservoirs. They can also be used to supply additional demand.
Explanation:
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A proton moves with a speed of 0. 985c. (a) calculate its rest energy
Answers
The rest energy of the proton will be 938 MeV. The rest energy is related to the rest mass of the proton.
What is rest energy?The rest energy is the rest mass times the square of the speed of light of a particle at rest in an inertial frame of reference.
The rest energy is found as;
[tex]\rm E_R= mC^2\\\\ E_R=(1.67 \times 10^{-27})\times 3 \times 10^8)^2\\\\ E_R= 9.375 \times 10^8 / eV[/tex]
Convert into the mega electron volt;
[tex]\rm E_R= 938 \ MeV[/tex]
Hence, the rest energy of the proton will be 938 MeV
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If I am driving on the highway and see a pig on the road and go from 60m/s to 20 m/s in 5 s. What is my acceleration?
Answers
Explanation:
Acceleration = final velocity - initial velocity
______________________
time taken
= 20 m/s - 60m/s
________________
5seconds
= -40 m/s
_______
5 seconds
= -8m/s^2
If air resistance acts on a falling object will all of its potential energy be converted into kinetic energy?
Answers
Answer:
No, some energy will be dissipated energy due to work of air resistance.
what particle collides with a fissionable nucleus in order to begin the fission process?
Answers
Answer:
neutrons
Explanation:
Neutrons are usually released when fission takes place. Fission of a nucleus may be spontaneous, that is, it may happen at random due to internal processes within the nucleus. Fission can also be induced by bombarding a nucleus with a neutron.
Place the elements c, n, and o in order of increasing ionization energy
Answers
The increasing order for the first ionization energy has been:
< C < N < O.
What is ionization energy?The first ionization energy has been the amount of energy required for removing the electron from the gaseous state. The molecules that have small structures and available valence electrons, the ionization energy has been decreased.
In the periodic table, on moving from left to right there has been an increase in the size of the atom, as well as the valence electrons. The increase in size results in more attraction by the nucleus resulting in increased first ionization energy.
The increasing order for the first ionization energy has been:
C < N < O.
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You throw a ball straight up into the air with velocity 40 ft/sec and catch it (at the same height) when it comes back down. What is the total distance traveled by the ball
Answers
The total distance traveled by the ball is determined as 49.68 ft.
Height travelled by the ball
The height travelled by the ball or the maximum height attained by the ball is calculated as follows;
v² = u² - 2gh
at maximum height, v = 00 = u² - 2gh
2gh = u²
h = u²/2g
h = (40²)/(2 x 32.2)
h = 24.84 ft
Total distance = 2 x 24.84 ft = 49.68 ft
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Two charges of +2.6 μC and –5.4 μC experience an attractive force of 6.5 mN. What is the separation between the charges?
Answers
Answer:
Explanation:
[tex]q_{1} =+2.6 X10^{_-6}C \\q_{2} =-5.4 X10^{_-6}C \\F=6.5mN\\F=\frac{Kq_{1}q_{2} }{d^{2} }[/tex]
2. FAt=p (remember p=mv). A 2.5Jg baseball moving at 8.5m/s to the left is slowed by a tipped
catch to 7.5m/s to the right in 0.25 seconds, what was the force of the tipped catch?
Answers
The force of the tripped catch exerted on the 2.5 Kg ball moving at 8.5 m/s to the Left is 160 N
Data obtained from the question Initial velocity (u) = 8.5 m/sFinal velocity (v) = 7.5 m/sTime (t) = 5 ms = 0.25 sMass (m) = 2.5 KgForce (F) = ?How to determine the forceThe force exerted on the ball can be obtained as follow:
F = m(v + u) / t
F = [2.5(7.5 + 8.5)]/ 0.25
F = 40 / 0.25
F = 160 N
Thus, the force exerted on the ball is 160 N
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