Energy conversion in an electric circuit consisting of a battery and a load
is.............

A. Heat Energy→ Electrical Energy → Potential Energy

B. Potential Energ → Electrical Energy → Heat Energy

C. Electrical Energy → Potential Energy→ Chemical Energy

D. Potential Energy → Heat Energy→ Electrical Energy


please please please i need heeelp​

Answers

Answer 1

Answer:

[tex]option \: c. \: is \: correct[/tex]

Explanation:

[tex]C. \\ Electrical \: Energy → Potential \: Energy→ Chemical \: Energy[/tex]

♨Rage♨

Answer 2

Answer:

 B that is Potential Energy → Electrical Energy → Heat Energy because, the energy is always stored in the form of potential energy because it is not in static form, so in this case it is going to be in a form of CHEMICAL POTENTIAL ENERGY now when it is connected with the load, the energy stored in the battery will move in the form of electrical energy, now you should remember Electrical energy is a type of kinetic energy caused by moving electric charges, so if it says kinetic energy, you should it is talking about electrical energy. So finally the static electrical energy is converted in the form of heat energy. We could take the EXAMPLE of heater.

In the heater chemical potential energy is converted into Heat Energy.


Related Questions

A 100 kg mass, initially at rest, is blown apart into a 60 kg piece and a 40 kg piece. After the blast, the two masses are moving apart with a relative velocity of 60 m/s. The speed of the 60 kg mass is

Answers

Answer:

Explanation:

According to law of conservation of momentum

(m1+m2)v = m1u1+m2u2

Let m1 and m2 be the masses

u1 and u2 be their respective velocities

v is the velocity of combined objects

Given

m1 =60kg

m2 = 40kg

v =0 m/s

u2 -  u1 = 60 ............ 1

0 = 60u1 + 40u2 = 0 .......... 2

From 1: u2 = 60+u1

Substitute into 2:

60u1 + 40(60+u1) = 0

60u1 +2400 +40u1 = 0

100u1 = -2400

u1 = -2400/100

u1 = -24m/s

Hence the speed of the 60 kg mass is 24m/s (in the negative direction)

I NEED HELP ASAP! PLS! <3

Answers

Answer:

a = - 1 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f} = v_{o} +(a*t)[/tex]

where:

Vf = final velocity = 0 (velocity at 10 seconds)

Vo = initial velocity = 4 [m/s]

a = desacceleration [m/s²]

t = time = 4 [s]

From the graph, we can deduce that between the second 10 and the second 6 there are (10-6) = 4 seconds difference.

In the second 6, the velocity is 4 [m/s]

0 = 4 + (a*4)

4*a = -4

a = - 1 [m/s²]

Which type of muscle helps the body move?
a
Cardiac
b
Smooth
c
Skeletal
d
None of the Above

Answers

Answer:

Cccccccc GIVE BRAINLYEST PLEASE

Answer: It´s c-skeletal

Explanation:

An object is moving with an initial velocity of 20 m/s. If it is decelerating at 5 m/s2 how far does it travel before it stops

Answers

Answer:

The object travels a distance of 40 meters before it stops.

Explanation:

A body moves with constant acceleration motion or uniformly accelerated rectilinear motion (u.a.r.m) when the trajectory of the mobile is a straight line and its speed varies the same amount in each unit of time.

Torricelli's equation relates the speed to the space traveled by the body in u.a.r.m. To calculate the velocity of a body as a function of space, the expression is used:

[tex]v^{2} =v0^{2} +2*a*d[/tex]

Where :

v: final velocity (m/s) v0: initial velocity (m/s) a: acceleration (m/s²) d: space traveled by the body (m)

In this case:

v: 0 m/s because the object stopsv0: 20 m/sa: - 5 m/s²  because the object is deceleratingd: ?

Replacing:

[tex](0\frac{m}{s} )^{2} =(20 \frac{m}{s} )^{2} +2*(-5\frac{m}{s^{2} }) *d[/tex]

Solving:

[tex]0\frac{m^{2} }{s^{2} } =400 \frac{m^{2} }{s^{2} } -10\frac{m}{s^{2} } *d[/tex]

[tex]0\frac{m^{2} }{s^{2} } -400 \frac{m^{2} }{s^{2} } = -10\frac{m}{s^{2} } *d[/tex]

[tex]-400 \frac{m^{2} }{s^{2} } = -10\frac{m}{s^{2} } *d[/tex]

[tex]\frac{ -400 \frac{m^{2} }{s^{2} }}{ -10\frac{m}{s^{2} }} = d[/tex]

40 m= d

The object travels a distance of 40 meters before it stops.

A hockey puck is sitting stationary on a frozen pond. A player slaps the puck, accelerating it from rest to 45 m/s in 0.03 s. What is the average force on the hockey puck while it is in contact with the stick

Answers

Answer:

F = 240 N

Explanation:

Let the mass of the puck, m = 160 g = 0.16 kg

Initial speed, u = 0 (at rest)

Final speed, v = 5 m/s

Time, t = 0.03 s

We need to find the average force on the hockey puck while it is in contact with the stick. Force is given by the formula as follows :

F = ma, a is acceleration

[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.16\times (45-0)}{0.03}\\\\F=240\ N[/tex]

So, the average force is 240 N.

If a coil stays at rest in a very large static magnetic field, no emf is induced in this coil. Group of answer choices True False

Answers

Answer:

True

Explanation:

Faraday's Law says that there is a emf induced in a conductor when the vector flux of the magnetic field across it changes in time.This can be true due to one of two facts, either the magnitude of the magnetic field changes in time, or the area through which the flux occurs changes due to the movement of the object.In this case, due to the magnetic field is constant, and the coil stays at rest, there is no possible change in flux, so emf induced is zero.

a 45 kg girl is bouncing on a trampoline. during a certain interval after she leaves t he surface of the trampoline, her kinetic energy decreases to 220 J from 420 J. how high does she rise during this interval neglect air resistance

Answers

Answer: Height = 0.45m

Explanation:

According to the conservation of energy, When there are no interactions outside a system ie  neglecting air resistance,The change in kinetic energy is equal to the change in potential energy in a closed system.

Therefore the kinetic energy decrease, the potential energy increases, and  decreases for increase in Kinetic energy

an is represented by the formulae

ΔKinetic energy + ΔPotential energy = 0

ΔKinetic energy = -ΔPotential energy ( where negative sign represent decrease as kinetic energy increases.

ΔK.E=ΔP.E

420J- 220J= mgh

mass = 45kg

g =gravitational acceleration =9.8 m/s^2

200J = 45 X 9.8 X h

h = 200/45 x 9.8 /= 0.45m

11.
A current of 67 amps runs through a resistor of 37 ohms, how much voltage is lost?

Answers

You divide them. 67/37 is 1.5 and so you subtract it with the 67 and multiple it by the coherent integer from the multiplication and you would get 20 volts lost roughly.

Answer: 20 volts

A dairy farmer notices that a circular water trough near the barn has become rusty and now has a hole near the base. The hole is 0.29 m below the level of the water that is in the tank. If the top of the trough is open to the atmosphere, what is the speed of the water as it leaves the hole

Answers

Answer:

2.385 m/s

Explanation:

Here there is a transformation of potential energy of the water at the top to Kinectic energy at the hole

This can be expressed as

Potential energy= Kinect energy

mgh= 1/2m v²

Where m= mass of water

h= Lenght below the level of the water that is in the tank.

v= the speed of the water as it leaves the hole

g= acceleration due to gravity= 9.81m/s

Here there is 'm' at both sides which can cancelled beach other out.

Then we have

gh= ¹/₂v²

making v² subject of the formular

v²=gh/(¹/₂)

v=√(2gh)

V=√2g h

V= √(2×9.81×0.29)

V=2.385 m/s

Therefore, the speed of the water as it leaves the hole is 2.385 m/s

Find the magnitude of the Sun's gravitational force on the Earth when the Earth is at perihelion and at aphelion. The perihelion and aphelion distances are 1.48 ✕ 1011 m and 1.52 ✕ 1011 m, respectively.

Answers

Answer:

Explanation:

Force F = GMm / R²

mass of the sun M = 1.99 x 10³⁰ kg

mass of the earth = 5.97 x 10²⁴ kg

value of G = 6.67 x 10⁻¹¹

for perihelion point R = 1.48 x 10¹¹ m

Force = 6.67 x 10⁻¹¹ x  1.99 x 10³⁰ x 5.97 x 10²⁴ / ( 1.48 x 10¹¹ )²

= 36.17 x 10²¹ N  

for aphelion point R = 1.52 x 10¹¹ m

Force = 6.67 x 10⁻¹¹ x  1.99 x 10³⁰ x 5.97 x 10²⁴ / ( 1.52 x 10¹¹ )²

= 34.29  x 10²¹ N  

A physicist is creating a computational model of a falling person before and after opening a parachute. What boundary conditions would be important here?
the air resistance encountered as the person falls

the speed at which the person falls

the change in kinetic and potential energy

the location where potential energy is zero

Answers

Answer:

Air resistance

Explanation:

Air resistance encountered as the person falls

Answer:

the location where potential energy is zero

Explanation:

What is an advantage of using nuclear power over natural gas to generate
electricity?
A. Nuclear power produces no waste.
B. Nuclear power does not contribute to climate change.
C. Nuclear power produces greenhouse gases.
D. Nuclear power is free.

Answers

Answer:b

Explanation:

I got the answer right

The main advantage of using nuclear power over natural gas to generate the electricity that nuclear power does not contribute to climate change, therefore the correct answer is option B.

What is a nuclear power plant ?

It is a particular kind of power plant where electricity is produced using a nuclear reactor that may use nuclear fusion or nuclear fission .

When a radioactive substance undergoes a nuclear reaction, a tremendous quantity of energy is produced .

As given in the problem , we have to find out what is an advantage of using nuclear power over natural gas to generate electricity .

Option B is the proper response , since employing nuclear power instead of natural gas to produce electricity has the advantage of not causing the climate change .

To learn more about Nuclear power plants here , refer to the link given below ;

brainly.com/question/4246037

#SPJ2

how much kinetic energy does a 2,000 kg car have when its traveling 5 m/s

Answers

Answer: 5000J

Explanation:

equation for kinetic energy is k=(mv^2)/2

plug in your mass and velocity

k = (2000*5^2)/2 = 5000J

A 10-kg object is hanging by a very light wire in an elevator that is traveling upward. The tension in the rope is measured to be 75 N. What are the magnitude and direction of the acceleration of the elevator

Answers

Answer:

2.31m/s² downwards

Explanation:

The sum of forces on the object is expressed as;

T-W

T is the tension on the rope

W is the weight

According yo Newton's second law:

T-W= ma

m is the mass

a is the acceleration

Given

T = 75N

W = mg = 10×9.81

W = 98.1N

Substitute

75-98.1 = 10a

-23.1 = 10a

a = -23.1/10

a = -2.31m/s²

The magnitude of the acceleration is 2.31m/s² and directions is downwards

Find relationship between‘ g’and ,‘G’​

Answers

Answer:

The acceleration on an object due to the gravity of any massive body is represented by g (small g). The force of attraction between any two unit masses separated by unit distance is called universal gravitational constant denoted by G(capital g). The relation between G and g is not proportional.

Explanation:

How far will a motorcycle that accelerates at 1.28 m/s2 travel as its velocity increases from 10.0 m/s to 20.0 m/s?

Answers

This is the answer hope you get it :)

Answer:

117

Explanation:

Which type of power plant uses the energy of moving water in nature to
generate electricity?
A. Radiant power
B. Natural gas
C. Coal
D. Hydroelectric

Answers

Answer:

D

Explanation:

Answer:

Hydroelectric power plants

Explanation:

This is because hydropower is a form of renewable energy that uses water stored in dams, rivers to create electricity

A ball is thrown straight downward with a speed of 0.50 meter per second from a height of 4.0 meters. What is the speed of the ball 0.70 second after it is released? [Neglect friction.]

Answers

Answer:

The speed of the ball is 7.36 m/s

Explanation:

Constant Acceleration Motion

It happens when the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

[tex]v_f=v_o+at[/tex]

Since the situation corresponds to a vertical motion, the acceleration is g=9.8 m/s^2.

The ball is thrown downward at vo=0.5 m/s. Its speed at t=0.7 seconds is

[tex]v_f=0.5+9.8\cdot 0.7[/tex]

[tex]v_f=7.36\ m/s[/tex]

The speed of the ball is 7.36 m/s

Note: There is no use of the height it was released from

A string under a tension of 53.9 N is used to whirl a rock in a horizontal circle of radius 2.59 m at a speed of 21.8 m/s. The string is pulled in and the speed of the rock increases. When the string is 1.23 m long and the speed of the rock is 54.8 m/s, the string breaks. What is the breaking strength (in newtons) of the string

Answers

Answer:

The breaking strength of the string is 717.19 N

Explanation:

Given;

initial tension on the string, T₁ = 53.9 N

initial radius of the string, r₁ = 2.59 m

initial speed of the rock, v₁ = 21.8 m/s

final radius of the string, r₂ = 1.23 m

final speed of the rock, v₂ = 54.8 m/s

the final tension on the string = breaking strength, T₂ = ?

Apply centripetal force equation due to inward motion;

[tex]T= \frac{mv^2}{r}\\\\Tr = mv^2\\\\m =\frac{Tr}{v^2}\\\\ \frac{T_1r_1}{v_1^2} = \frac{T_2r_2}{v_2^2}\\\\T_2 = \frac{T_1r_1v_2^2}{r_2v_1^2}\\\\ T_2 = \frac{(53.9)(2.59)(54.8)^2}{(1.23)(21.8)^2}\\\\ T_2 = 717.19 \ N[/tex]

Therefore, the breaking strength of the string is 717.19 N

Which atoms are deflected the most by the magnetic field?

Answers

Answer:

Different ions are deflected by the magnetic field by different amounts. The amount of deflection depends on: the mass of the ion. Lighter ions are deflected more than heavier ones.

Consider a car with a mass of 1250 kg moving at a constant speed of (22.0 A) m/s in a circular off ramp with a radius of (65.0 +B) m. What does the coefficient of static friction have to be for the car to just maintain its motion of ramp? Give your answer to 3 significant figures.
A=7
B=2

Answers

Answer:

Explanation:

weight of the car mg = m g

frictional force acting on the car = μ mg where μ is coefficient of friction

= m μ g

This force provides centripetal force , hence

m μ g  = m v² / R

μ = v² / rg

= 22 x 22 / 65 x 9.8

= .759  

The line segment joining the mid point of any side with the opssosite vertex is called? ​

Answers

a median:)
hope this helped!

In a single process, a system does 125 J of work on its surroundings while 75 J of heat is added to the system. What is the internal energy change for the system

Answers

Answer:

-50J

Explanation:

What is the first law of thermodynamics?

"The first law of thermodynamics state that energy is conserved"

the expression bellow is the  Change in internal energy of a system

Change in internal energy of a system

= heat put into the system - work done by the system on its surroundings,

or

ΔU = ΔQ - ΔW.

given data

Work done=125J

Heat= 75J

change=?

Substituting we have

ΔU = 75- 125

ΔU = -50J

"ΔQ is positive if heat flows into the system, negative if it flows out of the system.

ΔW is positive if the system does work on its surroundings and it is negative if work is done on the system. "

last question, PLEASE help
An athlete wants your shoe company to make his/her new basketball shoe. He is known for his speed down the court and doesn't want his shoes to have any pattern on the outsole, the bottom of the shoe, because he thinks it would slow him down. How would you convince this athlete that a pattern is needed because friction is important in his game?​

Answers

Answer:

my answer is in explanation below

Explanation:

You would convince him by saying the pattern adds elevation to the shoe therefore causing more friction.

(If it's wrong, I am sorry, I'm not in college)

(If it's right, can I get that brainliest?)

A hopper jumps straight up to a height of 0.45 m. With what velocity will it return to the table?

Answers

Answer:

3 m/s

Explanation:

We can solve with kinematics or with energy.

Using kinematics, and taking down to be positive, we're given:

Δy = 0.45 m

v₀ = 0 m/s

a = 10 m/s²

Find: v

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (10 m/s²) (0.45 m)

v = 3 m/s

Or, we can use energy.

PE = KE

mgh = ½ mv²

v = √(2gh)

v = √(2 × 10 m/s² × 0.45 m)

v = 3 m/s

An asteroid floating in space attracts a skyscraper on Earth’s with gravitational force of 12
newtons from a given distance. If the distance between the two objects is reduced to half, what is the
changed force of attraction between them?
a. 3 Newtons
b. 24 Newtons
c. 48 Newtons
d. 144 Newtons

Answers

Answer:

Explanation:

it is C

A 0.414 kg object is at rest at the origin of a coordinate system. A 2.08 N force in the positive x direction acts on the object for 1.57 s. What is the velocity at the end of this interval

Answers

Answer:

The value is [tex]v = 7.89 \ m/s[/tex]

Explanation:

From the question we are told that

  The mass  of the object is [tex]m = 0.414 \ kg[/tex]

   The force is [tex]F = 2.08 \ N[/tex]

  The time taken is  [tex]t = 1.57 \ s[/tex]

Generally the force acting on the object according to Newton's second law is

        [tex]F = \frac{ m (v -u )}{t}[/tex]

=>     [tex]v = \frac{F * t}{m} + u[/tex]

Here u is the initial velocity with value  0 m/s since the object was initially at rest

        [tex]v = \frac{2.08 * .57}{0.414 } + 0[/tex]

     [tex]v = 7.89 \ m/s[/tex]

Use the drop-down menus to identify the parts of the diagram labeled A, B, and C.

Label A

Label B

Label C

Answers

Answer:

b

Explanation:

bcuz I looked it up and it was on there

Answer:

the answers are:

- cool fluid sinks

- warm fluid rises

- convention current

Explanation:

Im late but mark me as brainliest for helping you out cause the one on top is clueless

Write the electric field strength EE in all three regions as a function of rr: for r>r2r>r2, r1

Answers

Answer:

Explanation:

See attachment

For a smooth sphere with a 11 cm diameter thrown through air (air density of 1.25 kg/m3, air viscosity 1.83*10-5 Pa-s), what is the speed (in cm/s) when the Reynolds number is 2,511

Answers

Answer:

u = 0.334 m/s

Explanation:

The formula for Reynold's number is given as follows:

Re = ρuL/μ

where,

Re = Reynold's Number = 2511

ρ = Density of air = 1.25 kg/m³

μ = Dynamic Viscosity of Air = 1.83 x 10⁻⁵ Pa.s

L = Characteristic Length = Diameter of Sphere = 11 cm = 0.11 m

u = Speed = ?

Therefore,

2511 = (1.25 kg/m³)(u)(0.11 m)/(1.83 x 10⁻⁵ Pa.s)

u = (2511)/(7513.66 s/m)

u = 0.334 m/s

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