The value of a given that A = 63°, C = 49°, and c = 3 is 4 units
How to determine the value of a?The given parameters are:
A = 63°, C = 49°, and c = 3
Using the law of sines, we have:
a/sin(A) = c/sin(C)
So, we have:
a/sin(63) = 3/sin(49)
Multiply both sides by sin(63)
a = sin(63) * 3/sin(49)
Evaluate the product
a = 4
Hence, the value of a is 4 units
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Two runners are saving money to attend a marathon.
The first runner has $110 in savings, received a $45 gift
from a friend, and will save $25 each month. The
second runner has $50 in savings and will save $60
each month.
After how many months will both runners have the
same amount of money?
02
O 3
Answer:
3 months
Step-by-step explanation:
The first runner: $110 + $45 = $155 starting out, plus 25x for $25 each month.
The second runner: $50 starting out, plus 60x for $60 each month.
To find out when both runners have the same amount of money, we will set the expressions equal to each other and solve.
155 + 25x = 60x + 50
105 = 35x
x = 3
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Create and solve a linear equation that represents the model, where circles and a square are shown evenly balanced on a balance beam.
A linear equation that represents the model is: x + 6 = 10; x = 4
How to solve linear equations?Let us first define the variables based on the attached image of the ball balance:
Let x = number of balls that contains the square.
On the left side, we have; square + 6 balls
On the right side, we have; 10 balls
To balance this, we have;
x + 6 = 10
x = 10-6
x = 4
Thus, a linear equation that represents the model is:
x + 6 = 10; x = 4
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What are the solutions to the equations y= 4x^2+5x-6
Answer:
D. x = -2; x = 3/4
Step-by-step explanation:
Read the values of a, b, and c from the quadratic equation: a is the number in front of x^2, b is the number in front of x, c is the number at the end. In our case: a = 4,b = 5,c = −6 The formula for the roots is = [tex]\frac{-b +-\sqrt{b^{2}-4ac } }{2a\\}[/tex]One positive number is 8 times another number. Their difference is 70.
Which of the following equations could be used to find the numbers?
Answer:
X equals 10.
8x - x = 70
Step-by-step explanation:
8 x 10 = 80
80 - 10 = 70
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex] \texttt{ \:The absolute maxima of f is f(-8) = 6} [/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
Absolute maxima is the maximum possible value for a given x, of a function.
and here, the maximum value is at -8, and the maximum value is 6.
[tex]\qquad \tt \rightarrow \: maximum - \: \: f( - 8) = 6[/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
The Strikers soccer team has 20 members, and 8 of them play offense. What percent of the team members play offense?
Answer:
40%
Step-by-step explanation:
We already have our first value 20 and the second value 8. Let's assume the unknown value is Y which answer we will find out.
As we have all the required values we need, Now we can put them in a simple mathematical formula as below:
Step 1 ⇒ Y = 8/20
By multiplying both numerator and denominator by 100 we will get:
Step 2 ⇒ Y = 8/20 × 100/100 = 40/100
Step 3 ⇒ Y = 40
Finally, we have found the value of Y which is 40 and that is our answer.
what is the ratio of the radius of circle a to the radius of circle b?
Answer:
3:1
Step-by-step explanation:
Assuming that the edges of the circle are supposed to line up with the dotted lines of the graph, all you have to do is count how many lines are between the middle of the circle and the edge (either directly vertical or horizontal due to the graph we are using). We can see that the radius of circle A is approximately 3 units, while the radius of circle B is approximately 1 unit. So the ratio of the radius of circle A to the radius of circle B is 3:1.
Answer:
3:1
Step-by-step explanation:
because once count the radius of the big circle that is 3 unit and the radius of small circle is 1 unit
What are m and b in the linear equation y=16+6x
Answer: B=16 and m=6
Step-by-step explanation:
in y=mx+b the number next to x is always the m/slope and the number without a variable is always the b.
March 8, 2017, one U.S. dollar was worth 66.79 Indian rupees.
a) On that date, how many dollars was 110.66 rupees worth?
Round your answer to the nearest hundredth of a dollar. I need help with this question.
[tex] \huge \tt \underline {\green{Answer}}[/tex]
If on March 8, 2017 , one U.S. dollar worth 66.79 Indian rupees
ie. $1 = Rs 66.79
$ 1 = 66.79 × 1
$ ? = 110.66
$ = New / old
$ = 110.66 / 66.79
$ = 1.65683485552
or
$1.66 = 110.66
Question 10 of 10
Rewrite the following linear equation in slope-intercept form. Write your
answer with no spaces.
v+2=4(x-3)
Answer here
A woman passed gas silently. I said "it stinks", and she said "I apologize. Excuse me". Why did she say both of those things?
Answer:
one possible way was because she knew what she did and started playing innocent
Find an equation for the line that passes through the point P(-5,-3) and is parallel to the line
7x + 4y
10. Use exact values.
-------------------------------------------------------------------------------------------------------------
Answer: [tex]\textsf{y = -1.75x - 11.75}[/tex]
-------------------------------------------------------------------------------------------------------------
Given: [tex]\textsf{Goes through (-5, -3) and parallel to 7x + 4y = 10}[/tex]
Find: [tex]\textsf{The equation in slope-intercept form}[/tex]
Solution: We need to first solve for y in the equation that was provided so we can determine the slope. Then we plug in the values into the point-slope form, distribute, simplify, and solve for y to get our final equation.
Subtract 7x from both sides
[tex]\textsf{7x - 7x + 4y = 10 - 7x}[/tex][tex]\textsf{4y = 10 - 7x}[/tex]Divide both sides by 4
[tex]\textsf{4y/4 = (10 - 7x)/4}[/tex][tex]\textsf{y = (10 - 7x)/4}[/tex][tex]\textsf{y = 10/4 - 7x/4}[/tex][tex]\textsf{y = 2.5 - 1.75x}[/tex]Plug in the values
[tex]\textsf{y - y}_1\textsf{ = m(x - x}_1\textsf{)}[/tex][tex]\textsf{y - (-3) = -1.75(x - (-5))}[/tex]Simplify and distribute
[tex]\textsf{y + 3 = -1.75(x + 5)}[/tex][tex]\textsf{y + 3 = (-1.75 * x) + (-1.75 * 5)}[/tex][tex]\textsf{y + 3 = -1.75x - 8.75}[/tex]Subtract 3 from both sides
[tex]\textsf{y + 3 - 3 = -1.75x - 8.75 - 3}[/tex][tex]\textsf{y = -1.75x - 8.75 - 3}[/tex][tex]\textsf{y = -1.75x - 11.75}[/tex]Therefore, the final equation in slope-intercept form that follows the information that was provided is y = -1.75x - 11.75
find the slope of the line that passes through (3,10) and (1,17)
Answer:
[tex]m=- \frac{7}{2}[/tex]
Step-by-step explanation:
The slope of a line passing through the two points [tex]\displaystyle{\large{{P}={\left({x}_{{1}},{y}_{{1}}\right)}}}[/tex] and[tex]\displaystyle{\large{{Q}={\left({x}_{{2}},{y}_{{2}}\right)}}}[/tex] is given by [tex]\displaystyle{\large{{m}=\frac{{{y}_{{2}}-{y}_{{1}}}}{{{x}_{{2}}-{x}_{{1}}}}}}[/tex].
We have that [tex]x_1=3[/tex], [tex]y_1=10[/tex], [tex]x_2=1[/tex], [tex]y_2=17[/tex].
Plug the given values into the formula for slope: [tex]m=\frac{\left(17\right)-\left(10\right)}{\left(1\right)-\left(3\right)}=\frac{7}{-2}=- \frac{7}{2}[/tex]
Answer: the slope of the line is [tex]m=- \frac{7}{2}[/tex].
Answer:
slope = - [tex]\frac{7}{2}[/tex]
Step-by-step explanation:
calculate the slope m using the slope formula
m = [tex]\frac{x_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (3, 10 ) and (x₂, y₂ ) = (1, 17 )
m = [tex]\frac{17-10}{1-3}[/tex] = [tex]\frac{7}{-2}[/tex] = - [tex]\frac{7}{2}[/tex]
A sells an article to B at profit of 20% and B sells it to C at a profit of 25%. If C buys it for Rs.225, what did A pay for it?
Answer:
A pay 120 for itLet the cost price be X
A Sells to B
profit = 20%
= cost price + 20%
= X + 20/100 of X
= 6x/ 5
B sells to C
profit = 25%
= Cost price + + 25%
= cost price + 25%
= 6x/5 + 25/100*6x/5
= 6x/5.+ 3x/10.
= 3x/2
3x/2 = 225.
3x = 450
x = 150.
sp = C. p + profit
S. p - profit = C. p
X - X/5
4x/5
4(150)/5.
120
can someone help me asap :)
Answer:
Option 2 - TU is perpendicular to MN and MN is parallel to PQangle M = angle P ( 90°)
so MN is parallel to pq
MN makes 90° with UT so it is perpendicular
Find the area of the trapezoid. TOP 11ft, RIGHT4√3ft , BOTTOM 15ft ,LEFT 8ft
Answer:
[tex]52\sqrt{3} ft^{2}[/tex]
Step-by-step explanation:
Please refer to the attached picture.
First we will find the area of rectangle BCDE.
Area of Rectangle = Length x Breadth = DE x CD
= 11 x [tex]4\sqrt{3}[/tex]
[tex]=44\sqrt{3} ft^{2}[/tex]
Next we will find Area of Triangle ABE.
Area of Triangle = 0.5 x Base x Height
[tex]0.5*4*4\sqrt{3} \\=8\sqrt{3} ft^{2}[/tex]
Area of Trapezoid = Area of Rectangle + Area of Triangle
[tex]=44\sqrt{3} +8\sqrt{3} \\=52\sqrt{3} ft^{2}[/tex]
Answer:
A = 52[tex]\sqrt{3}[/tex] ft² ≈ 90.1 ft²
Step-by-step explanation:
the area (A) of a trapezoid is calculated as
A = [tex]\frac{1}{2}[/tex] h (b₁ + b₂ )
where h is the perpendicular height and b₁ , b₂ the parallel bases
here h = 4[tex]\sqrt{3}[/tex] , b₁ = 15 , b₂ = 11 , then
A = [tex]\frac{1}{2}[/tex] × 4[tex]\sqrt{3}[/tex] × (15 + 11)
= 2[tex]\sqrt{3}[/tex] × 26
= 52[tex]\sqrt{3}[/tex] ft²
≈ 90.1 ft² ( to the nearest tenth )
It has been estimated that only about 40% of California residents have adequate earthquake supplies suppose you randomly survey 22 California residents we are interested in the number who have adequate earth quake supplies
The answers are as follows:
a) X denotes the number of the california residents that have adequate earthquake insurance
b) x = 1 ,2 ,3 ......
c) P( X=x ) = 0.3(1-0.3) ^ (x-1)
d) P( X=1) + P( X=2) + P( X=3) + P( X=4)
e) 0.49
f)0.42
g)0.33
What is probability?It is a branch of mathematics that deals with the occurrence of a random event.
The complete question is
It has been estimated that only about 30% of California residents have adequate earthquake supplies. Suppose we are interested in the number of California residents we must survey until we find a resident who does not have adequate earthquake supplies. a. In words, define the random variable X. b. List the values that Xmay take on. c. Give the distribution of X.X~ _____(_____,_____) d. WhatistheprobabilitythatwemustsurveyjustoneortworesidentsuntilwefindaCaliforniaresidentwhodoes not have adequate earthquake supplies? e. What is the probability that we must survey at least three California residents until we find a California resident who does not have adequate earthquake supplies? f. HowmanyCaliforniaresidentsdoyouexpecttoneedtosurveyuntilyoufindaCaliforniaresidentwhodoesnot have adequate earthquake supplies? g. How many California residents do you expect to need to survey until you find a California resident who does have adequate earthquake supplies?
given that 30% of California residents have adequate earthquake supplies.
a) variable X denotes the number of the california residents that have adequate earthquake insurance
b) x = 1 ,2 ,3 ......
c) p=0.3
P( X=x ) = 0.3(1-0.3) ^ (x-1)
d) P( X=1) + P( X=2) + P( X=3) + P( X=4)
= 0.3(1-0.3) ^ 0 + 0.3(1-0.3) ^1 + 0.3(1-0.3)^ 2 +...
e) P( X≥ 3) = 1- P(X<3)
= 1- (P(X=1) + (X=2))
= 1- 0.051
= 0.49.
f) E(X)= 1/P
p is the resident who does not have adequate earthquake supplies
p= 1-0.3
p = 0.7
E(X) = 1/0.7
= 0.42
g) E(X) = 1/q
= 1/0.3
= 3.333
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A hyperbola centered at (7, 0) has a focus at (7, 5) and vertex at (7, 4). Which is the equation of the hyperbola in standard form?
quantity x minus 7 end quantity squared over 16 minus y squared over 9 equals 1
quantity x minus 7 end quantity squared over 25 minus y squared over 16 equals 1
y squared over 16 minus quantity x minus 7 end quantity squared over 9 equals 1
y squared over 25 minus quantity x minus 7 end quantity squared over 16 equals 1
Based on the calculations, the equation of this hyperbola in standard form is: A. [tex]\frac{x\;-\;7}{16} + \frac{y}{9} = 1[/tex].
How to determine the equation of a hyperbola?Mathematically, the equation of a hyperbola in standard form is given by:
[tex]\frac{x\;-\;h}{a^2} + \frac{x\;-\;k}{b^2} = 1[/tex]
Given the following data:
Center (h, k) = (7, 0)
Vertex (h+a, k) = (7, 4)
Focus = (h+c, k) = (7, 5)
Also, we can deduce that the value of a and c are 4 and 5 respectively.
For the value of b, we would apply Pythagorean's theorem:
c² = a² + b²
b² = c² - a²
b² = 5² - 4²
b² = 9.
Substituting the parameters into the standard equation, we have:
[tex]\frac{x\;-\;7}{4^2} + \frac{y\;-\;0}{3^2} = 1\\\\\frac{x\;-\;7}{16} + \frac{y}{9} = 1[/tex]
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I need help ASAP please
Which statement is true about whether Z and B are independent events?
A: Z and B are independent events because P(Z | B) =P(Z).
B: Z and B are independent events because P(Z | B) = P(B).
C: Z and B are not independent events because P(Z | B) ≠ P(Z).
D: Z and B are not independent events because P(Z | B) ≠ P(B).
|4x + 7| − 4 = 20
Can anyone help me with this
Answer:
x = -31/4 or x = 17/4
Step-by-step explanation:
|4x + 7| − 4 = 20
⇔ |4x + 7| − 4 + 4 = 20 + 4
⇔ |4x + 7| = 24
⇔ 4x + 7 = 24 or 4x + 7 = -24
⇔ 4x = 24 - 7 or 4x = -24 - 7
⇔ 4x = 17 or 4x = -31
⇔ x = 17/4 or x = -31/4
Answer:
x = [tex]\frac{17}{4}[/tex] (17/4 = 4.25)
or x = [tex]-\frac{31}{4}[/tex] (-31/4 = -7.75)
Step-by-step explanation:
| | is notation for absolute value
absolute value - the distance that a number is from 0
> essentially, you can think of absolute value as the "positive version" of whatever is inside of the | |
if we have | x | = 20, we could really have (without the | | ) two versions of x
either | x | = 20 ; or | -x | = 20 {because a negative x inside of the | | has the same value as positive x}
we set this up as two equations:
x = 20 or -x = 20
^ {multiply by -1}
x = 20 or x = -20
now, let's plug our understanding into the equation
|4x + 7| - 4 = 20
first, we should simplify our equation to:
|4x + 7| - 4 = 20
+ 4 + 4
|4x + 7| = 24
now, let's separate this absolute value equation into two separate equations:
4x + 7 = 24:
- 7 - 7 {subtract 7 from both sides to isolate x}
4x = 17
÷4 ÷4 {divide both sides by 4 to get 1x}
x= [tex]\frac{17}{4}[/tex]
or,
4x + 7 = -24:
- 7 -7 {subtract 7 from both sides to isolate x}
4x = -31
÷4 ÷4 {divide both sides by 4 to get 1x}
x = [tex]-\frac{31}{4}[/tex]
so, we know that
x = [tex]\frac{17}{4}[/tex] (17/4 = 4.25)
or x = [tex]-\frac{31}{4}[/tex] (-31/4 = -7.75)
hope this helps!!
To purchase 13700 worth of restaurant equipment for her business Maria made a down payment of 1500 and took out a business loan for the rest after 3 years of paying monthly payments of 371.16 she finally paid off the loan
What was the total amount Maria ended up paying for the equipment
How much internet did Maria pay on the loan
The total amount Maria ended up paying for the equipment will be $14,861.76. And The interest of Maria on the loan will be 8.48%.
What is Algebra?The analysis of mathematical representations is algebra, and the handling of those symbols is logic.
To purchase 13700 worth of restaurant equipment for her business.
Maria made a down payment of 1500 and took out a business loan for the rest, after 3 years of paying monthly payments of 371.16 she finally paid off the loan.
The total amount Maria ended up paying for the equipment will be
Total amount = 371.16 × 3 × 12 + 1500
Total amount = $14,861.76
The interest of Maria on the loan will be
Interset = [(14861.76 – 13700) / 13700] x 100
Interset = 8.48%
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How many pounds of candy that sells for $0.82 per lb must be mixed with candy that sells for $1.36 per lb to obtain 9 lb of a mixture that should sell for $0.91 per lb?
7.5 pounds of the $0.82 per lb candy must be used in the mixture.
How many pounds of each candy should we use?First, let's define the variables:
x = pounds of the $0.82 candy used.y = pounds of the $1.36 candy used.We want to make 9 lb of mixture, then:
x + y = 9.
And the price of these 9 pounds must be $0.91, then we can write:
x*$0.82 + y*$1.36 = 9*$0.91 = $8.19
Then we have a system of equations:
x + y = 9.
x*$0.82 + y*$1.36 = $8.19
We can isolate y on the first equation so we get:
y = 9 - x
Now we can replace that on the other equation:
x*$0.82 + (9 - x)*$1.36 = $8.19
And now we can solve this for x.
x*($0.82 - $1.36) = $8.19 - 9*$1.36
-x*$0.54 = -$4.05
x = (4.05/0.54) = 7.5
So 7.5 pounds of the $0.82 per lb candy must be used in the mixture.
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four big water bottles can hold 8 gallaons how much can 10 big water gallons hold
Which of the following terms best fits this definition?
The angle between two sides of a triangle.
Select one:
AAS Theorem
SAS Postulate
Included Side
ASA Postulate
HL Congruence Theorem
Included Angle
SSS Postulate
Step-by-step explanation:
hope you can understand
(7 + 7i)(2 − 2i)
(a) Write the trigonometric forms of the complex numbers. (Let
0 ≤ < 2.)
(7 + 7i) =
(2 − 2i) =
(b) Perform the indicated operation using the trigonometric forms. (Let
0 ≤ < 2.)
(c) Perform the indicated operation using the standard forms, and check your result with that of part (b).
The complex number -7i into trigonometric form is 7 (cos (90) + sin (90) i) and 3 + 3i in trigonometric form is 4.2426 (cos (45) + sin (45) i)
What is a complex number?It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.
We have a complex number shown in the picture:
-7i(3 + 3i)
= -7i
In trigonometric form:
z = 7 (cos (90) + sin (90) i)
= 3 + 3i
z = 4.2426 (cos (45) + sin (45) i)
[tex]\rm 7\:\left(cos\:\left(90\right)\:+\:sin\:\left(90\right)\:i\right)4.2426\:\left(cos\:\left(45\right)\:+\:sin\:\left(45\right)\:i\right)[/tex]
[tex]\rm =7\left(\cos \left(\dfrac{\pi }{2}\right)+\sin \left(\dfrac{\pi }{2}\right)i\right)\cdot \:4.2426\left(\cos \left(\dfrac{\pi }{4}\right)+\sin \left(\dfrac{\pi }{4}\right)i\right)[/tex]
[tex]\rm 7\cdot \dfrac{21213}{5000}e^{i\dfrac{\pi }{2}}e^{i\dfrac{\pi }{4}}[/tex]
[tex]\rm =\dfrac{148491\left(-1\right)^{\dfrac{3}{4}}}{5000}[/tex]
=21-21i
After converting into the exponential form:
[tex]\rm =\dfrac{148491\left(-1\right)^{\dfrac{3}{4}}}{5000}[/tex]
From part (b) and part (c) both results are the same.
Thus, the complex number -7i into trigonometric form is 7 (cos (90) + sin (90) i) and 3 + 3i in trigonometric form is 4.2426 (cos (45) + sin (45) i)
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A number is equal to the sum of half a second number and 3. The first number is also equal to the sum of one- quarter of the second number and 5. The situation can be represented by using the graph below, where x represents the second number. 16 NO 8 K 3₂ 5 2 4 st 6 8 10 12 14 16 Which equations represent the situation? Hurry
Need help with the following question
A woman passed gas silently. I said "it stinks", and she said "I apologize. Excuse me". Why did she say both of those things?
A rectangular parking lot has a perimeter of 820 ft. The area of the parking lot measures 42,000 ft2. What is a dimension of the parking lot?
By solving a system of equations, we will see that the parking lot is 210ft by 200ft.
How to get the dimensions of the parking lot?For a rectangle of length L and width W, the perimeter is:
P = 2*(L + W)
And the area is:
A = L*W
Here we know that the perimeter is 820 ft and the area is 42,000 ft²
Then we can write the two equations (ignoring units).
820 = 2*(L + W)
42,000 = L*W
We can isolate L in the first equation to get:
820/2 = L + W
410 - W = L
Now we can replace that in the other equation:
42,000 = (410 - W)*W = 410*W - W^2
Now we want to solve the quadratic equation:
-W^2 + 410*W - 42,000 = 0
The solutions are given by:
[tex]W = \frac{-410 \pm \sqrt{410^2 - 4*(-1)*(-42000)} }{-2} \\\\W = \frac{-410 \pm 10 }{-2}[/tex]
Then the solutions are:
W = (-410 + 10)/(-2) = 200
W = (-410 - 10)/2 = 210
If we take W = 200, then:
L = 410 - W = 410 - 200 = 210
So we can conclude that the parking lot is 200ft by 210ft.
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Answer: C, 210 ft
Step-by-step explanation: edge :)
Select the correct answer from each drop-down menu.
Consider the function Ax) = 3x+ 1 and the graph of the function g(x) shown below.
Answer:
write three methods of writing set. Give one example of each methods.