Karl, Serene and Pauline have 1281 stickers altogether. 08
Pauline had 3 times as many stickers as Serene.
Karl had 175 stickers fewer than Pauline.
How many stickers did Pauline have?

The subpopulations of mechanical and civil engineers are not earning different salaries.

If a study determines the difference in average salary for subpopulations of mechanical engineers and civil engineers is NOT significant.

This assertion simply means that average salaries of the  mechanical and civil engineers are not different.

Thus, the subpopulations of mechanical and civil engineers are not earning different salaries.

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The expression that represents this inequality must relate both temperatures, then it would look like this: -40°F < x < 140°F.

To express this situation in an inequality we must include the temperature values. Additionally, we must include the greater than (>) or less than (<) symbols to relate the values.

According to the above, the expression would look like this:

Note: This question is incomplete because some information is missing. Here is the information:

A truck driver is driving from Nome, Alaska to Death Valley, California. Because he is traveling between locations with extreme temperatures, he needs to check the weather continuously to make sure the gas in his truck remains in liquid form. The gas he uses freezes at −40° F and evaporates at 140° F.

Write an inequality to represent the temperatures at which the gas in the truck will remain in liquid form.

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Using the z-distribution, it is found that 3,007 passengers must be surveyed.

A confidence interval of proportions is given by:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which:

The margin of error is given by:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In this problem, we have a 90% confidence level, hence[tex]\alpha = 0.9[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.9}{2} = 0.95[/tex], so the critical value is z = 1.645.

In this problem, we desired a margin of error of M = 0.015, with no prior estimate, hence [tex]\pi = 0.5[/tex], then we solve for n to find the minimum sample size.

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.015 = 1.645\sqrt{\frac{0.5(0.5)}{n}}[/tex]

[tex]0.015\sqrt{n} = 1.645(0.5)[/tex]

[tex]\sqrt{n} = \frac{1.645(0.5)}{0.015}[/tex]

[tex](\sqrt{n})^2 = \left(\frac{1.645(0.5)}{0.015}\right)^2[/tex]

n = 3007.

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No. of pounds of seed it takes to plant an 8-acre field = 70 pounds.

No. of acres can be planted per pound of seed = 70/8

= 8.75.

thus, 8.75 acres can be planted per pound of seed.

A function assigns the values. The absolute magnitude of a star that has a period of 62 days is -6.3328.

A function assigns the value of each element of one set to the other specific element of another set.

The relationship between the brightness of a Cepheid star and its period, or length of its pulse, is given by

M = − 2.78 (log P) − 1.35,

Given the absolute magnitude of a star that has a period of 62 days is,

M = − 2.78 (log 62) − 1.35

M = -6.3328

Hence, the absolute magnitude of a star that has a period of 62 days is -6.3328.

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Between Steps 1 and 2, the student added 6x to the left hand side, but subtracted 6x from the right hand side.

Answer:

[tex] \boxed{ \rm(6x)²-(5)²}[/tex]

Step-by-step explanation:

Given expression/polynomial :

[tex]3 6{x}^{2} - 25[/tex]

Let's evaluate.

We can re-write the polynomial as

Further

Hence, the expression is equivalent to last Choice, (6x)²-(5)².

-Regards, Hannah :)

Answer:

2

Step-by-step explanation:

Rational exponents are beneficial in removing the root over or radicals

Let's check the rule

Take an example

The height of the tree is 249.5 feet

The given parameters are:

Let the height of the tree be x.

So, we have:

tan(80) = x/44

Multiply both sides by 44

x = 44 * tan(80)

Evaluate

x = 249.5

Hence, the height of the tree is 249.5 feet

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Answer:

[tex]1.3\cdot 10^3\text{ J}[/tex]

Step-by-step explanation:

Power is defined by work over time. In physics, work can be defined as the energy transferred over from an applied force over some distance. As a formula:

[tex]W=Fd[/tex], where F = force applied and d = distance that force is applied over.

*It is worth noting that F must be parallel to the distance travelled. If it is perpendicular, no work is done, and if it is at an angle, find the parallel component and use that for F.

In this case, the force applied must counter the force of gravity on Martha, which is given by [tex]F_g=mg[/tex], where m = Martha's mass and g = gravitational constant 9.8 m/s/s. Therefore, [tex]F_g=75\cdot 9.8=735\text{ N}[/tex]. Since she raises her body 4.0 meters, the work done must be [tex]W=Fd=735\cdot 4=2940\text{ J}[/tex].

Since power is equal to work over time and t = 2.3 seconds, we have:

[tex]\displaystyle P=\frac{W}{t}=\frac{2940}{2.3}=\boxed{1278\text{ J}}\approx \boxed{1.3\cdot 10^3\text{ J}}[/tex] (to two significant figures)

Answer:

w= 2v/3 plus 5

2v+15=3w.forw

Swap sides so that all variable terms are on the left hand side.

3w=2v+15

Divide both sides by 3.

3

3w

​

=

3

2v+15

​

Dividing by 3 undoes the multiplication by 3.

w=

3

2v+15

​

Divide 2v+15 by 3.

w=

3

2v

​

+5

Step-by-step explanation:

2v+15=3w.forw

Swap sides so that all variable terms are on the left hand side.

3w=2v+15

Divide both sides by 3.

3

3w

​

=

3

2v+15

​

Dividing by 3 undoes the multiplication by 3.

w=

3

2v+15

​

Divide 2v+15 by 3.

w=

3

2v

​

+5

Step-by-step explanation:

2v+15=3w.forw

Swap sides so that all variable terms are on the left hand side.

3w=2v+15

Divide both sides by 3.

3

3w

​

=

3

2v+15

​

Dividing by 3 undoes the multiplication by 3.

w=

3

2v+15

​

Divide 2v+15 by 3.

w=

3

2v

​

+5

Step-by-step explanation:

2v+15=3w.forw

Swap sides so that all variable terms are on the left hand side.

3w=2v+15

Divide both sides by 3.

3

3w

​

=

3

2v+15

​

Dividing by 3 undoes the multiplication by 3.

w=

3

2v+15

​

Divide 2v+15 by 3.

w=

3

2v

​

+5

Step-by-step explanation:

1

Step-by-step explanation:

when we put 1 in the equation the nominator becomes zero and it becomes undefined

Hii!

___________________________________________________________

[tex]\stackrel\star\rightsquigarrow\circ\boldsymbol{\underbrace{Answer:}}}\circ\leftharpoonup[/tex]

The value of x should be 5! ^^

[tex]\stackrel\star{\rightsquigarrow\circ\boldsymbol{\underbrace{Explanation:}}}\circ\leftharpoonup[/tex]

[tex]\boxed{\\\begin{minipage}{7cm} For\,an\,expression \\ \boldsymbol{to\,be\,und efined,} \\ \,its\,denominator\,should\,be\,zero \end{minipage}}}[/tex]

Remember this! ^^

Now let's consider this:

Which value of x will make the denominator equal to 0?

Is it 1? If we stick 1 in, we will not obtain 0.

[tex]\twoheadrightarrow\sf y=\cfrac{3\cdot1-3}{1-5}[/tex]

[tex]\bullet[/tex] Simplify this

[tex]\twoheadrightarrow\sf y=\cfrac{3-3}{-4}[/tex]

---

We will obtain 0 in the numerator, but not in the denominator; if the numerator is 0, then the fraction, or fractional expression, is 0.

Let's try 5. 5-5 is equal to 0, so this sounds promising! ^^

[tex]\twoheadrightarrow\sf y=\cfrac{3\cdot5-3}{5-5}[/tex]

[tex]\bullet[/tex] Look what we obtain when we simplify

Don't we obtain 15-3/0?

Like I said above, if an expression has 0 as its denominator, it's undefined.

--

Hope that this helped! Best wishes.

[tex]\textsl{Reach far. Aim high. Dream big.}[/tex]

--

Answer:

b

Step-by-step explanation:

just took it

Answer:

B. m∠JXY = m∠NXY

Step-by-step explanation:

I got the answer correct

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{6x = 54}\\\\\large\textbf{DIVIDE 6 to BOTH SIDES}\\\\\mathsf{\dfrac{6x}{6} = \dfrac{54}{6}}\\\\\textbf{SIMPLIFY IT!}\\\\\mathsf{x = 9}\\\\\huge\text{Therefore, your answer should be: \boxed{\mathsf{x = 9}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

Answer:

[tex]\left[\begin{array}{cccc}-1\\1\\1\\0\end{array}\right][/tex], [tex]\left[\begin{array}{cccc}0\\2\\0\\1\end{array}\right][/tex] Are two vectors which are basis of null space of A

Step-by-step explanation:

Basis of a null space is a vector matrix which when multiplied by the reduced echelon form of the matrix gives null matrix or 0 matrix

So, to find the reduced echelon form we apply the row operations :

R₁ = R₁/2

[tex]\left[\begin{array}{cccc}1&-2&3&4\\2&-1&3&2\\4&-5&9&10\\0&-1&1&2\end{array}\right][/tex]

R₂ = R₂ - 2R₁

[tex]\left[\begin{array}{cccc}1&-2&3&4\\0&3&-3&-6\\4&-5&9&10\\0&-1&1&2\end{array}\right][/tex]

R₃ = R₃ - 4R₁

[tex]\left[\begin{array}{cccc}1&-2&3&4\\0&3&-3&-6\\0&3&-3&-6\\0&-1&1&2\end{array}\right][/tex]

R₂ = R₂/3

[tex]\left[\begin{array}{cccc}1&-2&3&4\\0&1&-1&-2\\0&3&-3&-6\\0&-1&1&2\end{array}\right][/tex]

R₁ = R₁ + 2R₂

[tex]\left[\begin{array}{cccc}1&0&1&0\\0&1&-1&-2\\0&3&-3&-6\\0&-1&1&2\end{array}\right][/tex]

R₃ = R₃ - 3R₂

[tex]\left[\begin{array}{cccc}1&0&1&0\\0&1&-1&-2\\0&0&0&0\\0&-1&1&2\end{array}\right][/tex]

R₄ = R₄  + R₂

[tex]\left[\begin{array}{cccc}1&0&1&0\\0&1&-1&-2\\0&0&0&0\\0&0&0&0\end{array}\right][/tex]

which is a reduced echelon form of the matrix A

now ,

[tex]\left[\begin{array}{cccc}1&0&1&0\\0&1&-1&-2\\0&0&0&0\\0&0&0&0\end{array}\right][/tex]    [tex]\left[\begin{array}{cccc}x1\\x2\\x3\\x4\end{array}\right][/tex]  [tex]=\left[\begin{array}{cccc}0\\0\\0\\0\end{array}\right][/tex]

therefore,

x₁ + x₃ = 0

x₁  = -x₃

x₂ - x₃ - 2x₄ = 0

x₂ = x₃ + 2x₄

so now replacing values of x₁ , x₂ in the vector matrix

[tex]\left[\begin{array}{cccc}-x3\\x3 + 2x4\\x3\\x4\end{array}\right][/tex]

we can write the above matrix as,

[tex]x3\left[\begin{array}{cccc}-1\\1\\1\\0\end{array}\right][/tex] [tex]+ x4\left[\begin{array}{cccc}0\\2\\0\\1\end{array}\right][/tex]

therefore we can say that above mentioned vector matrices are the basis of the null space of matrix A

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Answer + Step-by-step explanation:

The packet should be dropped  3636.55 horizontal meters before the target in order to hit the target

Trajectory is the path followed by a moving object when it is falling under gravitational force.

x = 90 t

y = -4.9 t²2 + 4500

t ≥ 0

y = 0

-4.9t² + 4500 = 0

4.9t²2 = 4500

[tex]\rm t = \sqrt {\dfrac{4500}{4.9}}[/tex]

t = 30.30 seconds

substituting the value to determine the horizontal distance

x = 120 * 30.30

x = 3636.55 meters

Therefore the packet should be dropped  3636.55 horizontal meters before the target in order to hit the target

The complete question is

a drone traveling horizontally at 120m s over a flat ground at an elevation of 4500 meters must drop an emergency package on a target on the ground the trajectory of the package is given by x 120t y 4.9t 2 4500 where the origin is the point on the ground directly beneath the drone at the moment of release. How many horizontal meters before the target should the package be released in order to hit the target? Round to the nearest meter.

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H0: µ1 = µ2; The exercise program do not have significant effect on physical fitness, H1: µ1 =/ µ2; the exercise program had a significant effect on physical fitness and the  Estimated Cohen's d is 0.82.

A. Significant effect

H0: µ1 = µ2

Based on the above hypothesis the exercise program does not have significant effect on physical fitness

H1: µ1 =/ µ2

Based on the above hypothesis the exercise program had a significant effect on physical fitness

Pooled variance: sp2 = (190 + 120.5/(15-1) + (10-1)

Pooled variance: sp2 = 310.5/23

Pooled variance: sp2 =13.5

Estimated standard error ( sM1-M2):

sM1-M2 =√13.5/15 +13.5/10

sM1-M2 =√2.25

sM1-M2 = 1.5

Tailed test (t)

t = (15.5 - 12)/1.5

t=3.5/1.5

t= 2.33

B. Estimated Cohen's d:

Estimated Cohen's d  = 3/√13.5

Estimated Cohen's d = 3/3.67

Estimated Cohen's d= 0.817

Estimated Cohen's d= 0.82 (Approximately); this is a large effect.

Conclusion demonstrating how the outcome of the hypothesis test would tend to appear in a research report is:  (Reject H0). Because the  group exercise program tend to have a significant effect on the physical fitness of elderly adults, t = 2.33, p <.05, d = 0.82.

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The margin of error will be 20 and 10 respectively.

The margin of error for Robert will be:

= 1.96 × 50/✓25

= 1.96 × (50/5)

= 1.96 × 10

= 20 approximately

The margin of error for Val will be:

= 1.96 × 50/✓100

= 1.96 × 50/10

= 1.96 × 5

= 10 approximately

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The length of the infinite zigzag path is 1

Note that the infinite zigzag path is embedded in an isosceles triangle

Using angle π/4, we have that

Tan π/4 = opposite/ adjacent

[tex]tan \frac{3. 412}{4} = \frac{x}{1}[/tex]

[tex]tan 0. 7855 = x[/tex]

[tex]x = 0. 014[/tex]

To find the longer part 'y',  use the Pythagorean theorem

[tex]y^{2} = (0.014)^2 + (1)^2[/tex]

[tex]y^2 = 1.879 * 10^-4 + 1[/tex]
[tex]y^2 = 1. 00[/tex]

[tex]y = \sqrt{1. 000}[/tex]

[tex]y = 1. 000[/tex]

The length of the infinite zigzag path is the same as the length of the longer part of the triangle which equals 1.

Thus, the length of the infinite zigzag path is 1

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Step-by-step explanation:

hope you can understand

We conclude that the interval in which the function decreases is (1.5, 3]

The ball is decreasing when the graph, reading from left to right, is going downwards.

Particularly, in this parabola that opens downwards, the graph will decrease after the vertex.

And we can see that the vertex is at x = 1.5

And we also see that the graph of the function ends at x = 3.

Then we conclude that the interval in which the function decreases is (1.5, 3]

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Answer:

depends upon the degree of the angle

Step-by-step explanation:

vertically opposite angles are always equal like

80 = 80 sum is equal to 160 degrees not equal to 90

45 = 45 , sums equal to 90 degrees ,equal to 90

30 = 30 sum is equal to 60 degrees, not equal to 90

so we can say it depends what is the no of degrees if it is  45 only we can say  the vertically opposite angles are  complementary angle

Answer:

54

Step-by-step explanation:

⇒ 1 + 3 = 4

⇒ 4 * 13 = 52

⇒ 52 + 2 = 54 (Basic Operation)

Answer:

  (a)  9, 8, 7, 6, 5, ...

Step-by-step explanation:

The solution to the inequality can be done a couple of ways. The solution is similar to that for a one-step linear equation.

__

We know that multiplying numbers by a negative value reverses their order. For example, 1 < 2, but -1 > -2. That is, multiplying by -1 requires a change in the comparison operator if it is to remain true.

For our inequality, we want to solve it by multiplying both sides by -1/4:

  -4y > -40

  (-1/4)(-4y) < (-1/4)(-40) . . . . . multiply both sides by -1/4 (reverses order)

  y < 10 . . . . . . . . . . . simplify

The first few decreasing integer values that are part of this solution are ...

  {9, 8, 7, 6, 5, ...}

__

We can add 4y+40 to both sides of the inequality. The result will be an inequality with positive coefficients. This can be solved in one step.

  -4y > -40 . . . . . given

  (-4y) +(4y +40) > (-40) +(4y +40) . . . . . . add 4y+40 to both sides

  40 > 4y . . . . . . . . . . . . . . . simplify

  10 > y . . . . . . . . . . . . divide by 10 (order is unchanged)

  y < 10 . . . . . . . . . rearrange to put y on the left

Integer solutions to this inequality are ...

  {9, 8, 7, 6, 5, ...}

Probability helps us to know the chances of an event occurring. The probability of tossing heads and rolling a number less than 3 is 1/6.

Probability helps us to know the chances of an event occurring.

[tex]\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]

The number of cases where coins land on heads and a number less than 3 are rolled is 2, which are H1 and H2.

The probability of tossing heads and rolling a number less than 3 is,

Probability = (Outcomes where coins land on heads and a number less than 3 are rolled)/(Total number of cases)

Probability = 2/12 = 1/6

Hence, the probability of tossing heads and rolling a number less than 3 is 1/6.

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Answer: [tex]y-3=-4(x+3)[/tex]

Step-by-step explanation:

The slope is

[tex]\frac{-1-3}{-2-(-3)}=\frac{-4}{1}=-4[/tex]

So, using the point (-3, 3) to substitute into point-slope form, the equation is [tex]\boxed{y-3=-4(x+3)}[/tex]