The object has a redshift of 7.6 and the JWST observes the object at a wavelength of 2 microme-
tres (mid-infrared light).
(b) What is the wavelength of the light emitted by the object? (c) What type of radiation was originally emitted by the object?

a) 4.9 m

b) 38.3 m/s

c) 33.4 m

The three equations are,

v = u + at

v² = u² + 2as

s = ut + ½at²

According to the question,

Let hold the y-axis in the direction of gravity.

Initial velocity 0 = 0 /,

Initial height ℎ0 = 0 , and finish height ℎ = 75.0

gravitational acceleration = 9.8 /²

a) Determine the distance traveled during the first second.

By third equation of motion

[tex]S_{0} = v_{0} t +\frac{1}{2} gt^{2}[/tex]  where [tex]v_{0}[/tex] =0

then [tex]S_{0} = \frac{gt^{2}}{2} = \frac{9.8*1^{2} }{2} = 4.9 m[/tex]

b) Determine the final velocity at which the object hits the ground

let – velocity of object, when it falling to the ground

– moment falling to the ground, and obtain from condition:

ℎ = ℎ() = 75.0

[tex]v_{f} = v_{0} +gt = gt[/tex]

[tex]h (t_{f} ) = \frac{gt^{2} }{2} = 75.0 m\\t_{f} =\sqrt{\frac{2h_{f} }{g} } \\v_{f}= gt = g \sqrt{\frac{2h_{f} }{g} } =\sqrt{2hg_{f} }= =\sqrt{2*9.8*75.0} = 38.3 m/s[/tex]

c) Determine the distance traveled during the last second of motion before hitting the ground.

From the above equation we get,

[tex]\sqrt{2*75*9.8*1} - \frac{9.8*1^{2} }{2} = 38.3 -4.9 = 33.4 m[/tex]

Therefore,

a) 4.9 m is the distance traveled during the first second.

b) 38.3 m/s is the final velocity at which the object hits the ground

c) 33.4 is the distance traveled during the last second of motion before hitting the ground.

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The magnitude of the average acceleration of the ball during this time interval will be 1969.69 m/s².

The rate of velocity change concerning time is known as acceleration.

Given data;

Initial velocity, u= 27.5 m/s

Rebound velocity, v= 21.0 m/s

Time elapsed, t = 3.30 × 10⁻³ seconds.

To find ;

Average acceleration, a

The average acceleration when the change in velocity is observed by the formula as:

[tex]\rm a_{avg}= \frac{v-u}{t}[/tex]

Substitute the given values:

[tex]\rm a_{avg}= \frac{27.5-21.0}{3.30 \times 10^{-3}} \\\\ a_{avg}= 1969.69 \ m/s^2[/tex]

Hence, the magnitude of the average acceleration of the ball during this time interval will be 1969.69 m/s².

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If one year consists of 365 days, this is closest to x = 3.15 × 10⁷ seconds.

Given that;

Note that; there are 24 hours in a day, 1440 minutes in a day and 86400 seconds in a days.

1 day contains 86400 seconds

365 contains x seconds

x = 365 × 86400

x = 3.15 × 10⁷ seconds

Therefore, if one year consists of 365 days, this is closest to x = 3.15 × 10⁷ seconds.

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The maximum and minimum variation between the true and magnetic poles is 180 degrees and 0 degrees respectively.

The poles of the earth are the North and South poles.

The North is taken as the reference point.

The true north is a fixed point on the globe and gives the true North and South poles.

The Magnetic north is the direction that a compass needle points to as it aligns with the Earth's magnetic field and gives the magnetic North and South poles.

The maximum maximum and minimum variation between the true and magnetic poles is 180 degrees and 0 degrees respectively.

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The North America will not be able to view the eclipse because of its location on the earth caused by the tilting of the earth.

The tilt of the Earth is what causes seasons to occur. These are the seasons in relation to the Northern Hemisphere.

The tilting of the Earth causes the difference in the amount of sun reaching each region of the earth like in the North America continent.

Thus, the North America will not be able to view the eclipse because of its location on the earth caused by the tilting of the earth.

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Explanation:

Methane (CH4) is 30 times stronger than carbon dioxide as an absorber of infrared radiation.

Answer:

The main reasons why CH4 has a higher vapor pressure at a given temperature when compared to CH3Cl is that CH4.

And Is 30 Times Stronger than Carbon dioxide...

Explanation:

Hope It Helps!!!

Answer:

A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point.

Hope this helps:)

An example of an object moving in projectile motion is; A basketball being thrown into a net.

Projectile motion is the motion of an object thrown or projected into the air, subject to only the acceleration of gravity.

Now, an example of an object moving in a projectile motion is throwing a basketball into a basketball net in a game. This is because the ball is thrown into the air at an angle towards the net and as such is subject to only acceleration of gravity.

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Answer:

V = 26.95 cm³

Explanation:

Density is given by the formula :

ρ = m÷V

Density = mass ÷ Volume

Given both density and mass we rearrange, substitute and solve for Volume :

Rearranging the equation to make Volume the subject :

ρ = m÷V

ρV = m

V = m÷ ρ

Now substitute :

V = 45 ÷ 1.67

V = 26.9461077844

Take 2 decimal places as the density is 2 decimal places :

V = 26.95

Units will be cm³ as it is volume

Hope this helped and have a good day

Answer:

0.372779 cubic meters

Explanation:

Answer:

.3104 m^3

Explanation:

1 gal (US) = .00378541178 m^3

Matter falling into a black hole arranges itself in the shape of a disk that is thick at the outer edge, thin along the inner ring.

A black hole is a region of space time where gravity is so strong that nothing or  no particles or even electromagnetic radiation such as light can escape from it.

Thus, matter falling into a black hole arranges itself in the shape of a disk that is thick at the outer edge, thin along the inner ring.

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Plant trees on places where forests have been chopped down to restore damaged ecosystems. Encourage individuals to live in a way that is environmentally friendly. Create parks to conserve the rainforests and animals. Companies that operate in environmentally friendly methods should be supported.

Answer:

Weaker, stronger

Explanation:

hope this helped!

Answer:

[tex]\fbox {weaker, stronger}[/tex]

Explanation:

The farther you bring charged objects from each other, the weaker the electrical force between them, and the bigger the charges on the objects, the stronger the electrical force between them.

Proving

Here we need the formula for Coulomb's Law, which is :

[tex]\boxed {F = \frac{1}{4\pi\epsilon_{0}}\times\frac{q_{1}q_{2}}{r^{2}}}[/tex]

As we can see, when the distance increases, the overall force will decrease as they are inversely proportional.

Similarly, as the product of charges is directly proportional to the electrical force produced, as the charges increase, the force increases.

The  direction the BASEBALL which is traveling in projectile motion is going is called a parabola.

Projectile motion is the motion of an object launched into the air at an angle to the horizontal and allowed to fall freely under the effect of gravity.

The  object is known as a projectile, and the path of motion is a curved path called a parabola.

Therefore, the direction the BASEBALL which is traveling in projectile motion is going is called a parabola.

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The liquid A is present lower in the container as compared to liquid B due to more weight.

If two liquids A and B of relative densities 0.7 and 0.4 respectively then the lower density liquid remain at the top and higher density solution which is liquid A remains lower in the container because higher density solution has more weight.

So we can conclude that the liquid A is present lower in the container as compared to liquid B due to more weight.

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Answer:Because if the shape gets changed it will move faster without to much weight

Explanation:

Answer:

um d. but I am guessing this ans

Answer:

750

Explanation:

The kinetic formula is 1 over 2 *mass * velocity Square

Answer:

designing a solution

Explanation:

after knowing & identifying a problem we start putting a solution

Answer:

because the side walk is at high temperature

A virtual and erect image is formed by concave mirror.

The focal length of the mirror is the distance between the lens and the image sensor.

It is also defined as the distance from a lens or mirror to the focal point.

It is also stated by the formula

[tex]\frac{1}{y} +\frac{1}{u} = \frac{1}{f}[/tex]

u = -50 cm and f = 0.50 m (50cm)

[tex]\frac{1}{v} +\frac{1}{-50} =\frac{1}{50}[/tex]

v= -50 cm

where - sign shows that image is virtual.

Magnification  m= [tex]\frac{v}{u}[/tex]

m = -50/50

m = 0

hence, virtual and erect image will be formed.

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Answer:

[tex]\fbox {D. Isobaric}[/tex]

Explanation:

The process during which pressure remains constant is called an isobaric process.

Answer:

The value of index of refraction(n₂) is 1.26

Explanation:

look at the attachment above

Answer:

It has greater accuracy than other nondestructive methods in determining the depth of internal flaws and the thickness of parts with parallel surfaces.

Explanation:

Hope this helps you!

Difference in air pressure helps us by contraction and relaxation of lungs  which forces air in and out of the lungs.

The pressure is the amount of force applied per unit area. It is represented as

Pressure p = Force/Area

The atmospheric pressure is constant. The flow of air is determined by how much above or below atmospheric pressure. The pressure inside the lungs rises or falls. The diaphragm in the lung contracts and relaxes  which forces air in and out of the lungs.

Hence, the person uses diaphragm of lungs to breathe.

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The a barrier to the correct interpretation of what you hear can occur due to different frame of reference.

A frame of reference is a particular set of beliefs or ideas on which you base your judgment of things.

A barrier in the correct interpretation of information can occur when two observers are in different frames of reference.

Thus, the a barrier to the correct interpretation of what you hear can occur due to different frame of reference.

The complete question is below:

Which is a barrier to the correct interpretation of what you​ hear?

-Different frame of reference

-Dissimilar vocabulary

-Differing accent

-Jargon usage

-Poor explanation

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Answer:

E = K Q / R^2

E1 = K Q1 / R1^2 = K * (-6.39 E-9) / .4^2 = -K 39.9 E-9

E2 = K Q2 / R2^2 = K * 3.22 E-9 / .25^2 = K 51.5 E-9

Field will point to right of P since E2 (positive) stronger

E = K (E2 - E1) = 9.0 E9 * (51.5 - 39.9) E-9 = 104 N/C

The electric field at point P is 104.6 N/C.

Every place in space where a charge exists in any form has an electric attribute that can be defined as the electric field.

Here,

q₁ = -6.39 x 10⁻⁹C

q₂ = 3.22 x 10⁻⁹C

Distance from q₁ to P, d₁ = 0.4 m

Distance from q₂ to P, d₂ = 0.25 m

Electric field at P due to q₁, E₁ = k x -6.39 x 10⁻⁹/(0.4)²

E₁ = -39.9 x 10⁻⁹k N/C

Electric field at P due to q₂, E₂ = k x 3.22 x 10⁻⁹/(0.25)²

E₂ =51.52 x 10⁻⁹k N/C

Therefore, total electric field at P,

E = E₂ - E₁

E = (51.52 - 39.9) x 10⁻⁹k

E = 104.6 N/C

Hence,

The electric field at point P is 104.6 N/C.

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Answer:

ohms

Explanation:

because it deal with circuit

Electric resistance is measured in Ohms.

A electric resistance can be defined as the opposition to current flow in a conductor.

From ohms law, an electric resistance can be determined using the formula below.

Formula:

Where:

Also,

Hence, Electric resistance is measured in Ohms.

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