Based on the circle graph,how many pounds of milk and eggs does the average American consume each year?PLEASE EXPLAIN IMAGE IS PROVIDED
E.300
F.368
G.460
H.552

Based On The Circle Graph,how Many Pounds Of Milk And Eggs Does The Average American Consume Each Year?PLEASE

Answers

Answer 1

About 492 pounds of milk and egg were consumed each year

Pie charts and percentages

Given the following parameters from the chart

Total consumption = 1640 pounds per person

The percentage of milk and egg = 100 -(38 + 10 + 10 +8 + 4)

The percentage of milk and egg = 30%

Determine the amount consumed each year

Amount of milk and egg consumed = 30% of 1640

Amount of milk and egg consumed = 492 pounds

Hence about 492 pounds of milk and egg were consumed each year

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Related Questions

(3x + 5y = 7
{ 4x - y = 5

Answers

Answer:

Step-by-step explanation:

Solution by substitution method

3x+5y=7

and 4x-y=5

Suppose,

3x+5y=7→(1)

and 4x-y=5→(2)

Taking equation (2), we have

4x-y=5

⇒y=4x-5→(3)

Putting y=4x-5 in equation (1), we get

3x+5y=7

⇒3x+5(4x-5)=7

⇒3x+20x-25=7

⇒23x-25=7

⇒23x=7+25

⇒23x=32

⇒x=32/23

→(4)

Now, Putting x=32/23

in equation (3), we get

y=4x-5

⇒y=4(32/23)-5

⇒y=(128-115)/23

⇒y=13/23

∴y=13/23   and x=32/23

which of the following is most likely the next step in the series?

Answers

Answer:

errrrrr a not too sure but try

Step-by-step explanation:

i did the test got a 90

Hello, thank all of you that helped me fix my math problems you helped me to succeed and get a good grade !!!

Answers

Ik just gonna sneak this comment on here for some points :)

Given statements:
If a shape is a parallelogram, then opposite angles are congruent.
. A rhombus is a parallelogram.
Which is a logical conclusion from the given statements?
O A rhombus has opposite angles that are congruent.
O The opposite sides of a rhombus are congruent.
O The diagonals of a rhombus are congruent.
O A rhombus is a quadrilateral.

Answers

The logical conclusion from the statement is that

B. The opposite sides of a rhombus are congruent.

How to deduce the information?

From the information given, if shape is a parallelogram, then opposite angles are congruent.

In this case, since the rhombus is a parallelogram, then the opposite sides of a rhombus are congruent.

In conclusion, the correct option is B.

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Write the number five and a quarter million in figures.

Answers

Answer:

5 and a 250,000

Step-by-step explanation:

A quarter million = 1,000,000 · [tex]\frac{1}{4}[/tex] = 250,000

Answer:

It is: 5,250,000

What is an undefined term in geometry?
OA. A sentence that asserts a fact
OB. A term that has no formal definition, but is used to define other
terms
OC. A clause preceded by "if" in a conditional statement
OD. A statement in which the hypothesis and conclusion are switched

Answers

An undefined term in geometry is (b) A term that has no formal definition, but is used to define other terms

How to define the term?

In geometry, there are four undefined terms.

These terms are:

PointLinePlaneSet.

The above items do not have a specific or formal definition. However, they are used to define other terms in geometry

This is the reason they are referred to as undefined terms.

Hence, an undefined term in geometry is (b)

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What is the median of this data set?
22, 37, 49, 15, 72

Answers

Answer: 37

Steps:
Order the numbers from least to greatest.
15, 22, 37, 49, 72

The median value is the middle number.

37

Gabrielle is 10 years older than Mikhail. The sum of their ages is 84. What is Mikhail's age?

Answers

Answer:

Hence the age of Mikhail is 37 and the age of Grabrielle is 47

Answer:

Here;

Gabrielle age= 10yrs older that M..= 16 + 10= 26yrs old.

Sum of their age= 84

Now;

100 - 84

16,,

How to do this please?️​

Answers

Step-by-step explanation:

Using dimensional analysis, let convert km to cm.

[tex] \frac{4cm}{1km} \times \frac{km}{100000 \: cm} [/tex]

Cancel out the km

[tex] \frac{4cm}{100000 \: cm} [/tex]

[tex] \frac{1}{25000 } [/tex]

So n= 25000

iii.

Dimensional Analysis

[tex] \frac{3 \: cm}{1 } \times \frac{km}{100000 \: cm} [/tex]

[tex] \frac{3 \: km}{100000} [/tex]

Or

[tex]0.00003 \: km[/tex]

Find the domain and range

Answers

Answer:

Domain: (-∞, ∞)
Range: [-2, ∞)

Step-by-step explanation:

The domain of any parabola is (-∞, ∞)
The range of this parabola is [-2, ∞) because the vertex is at (-2, -2).

Evaluate sin ( Cos^-1( -15/17)) enter your answer as a fraction using the slash bar (/)

Answers

Answer:

sin(cos^-1(-15/17))=8/17

Step-by-step explanation:

I apologize for the bad writing, I hope you can read it

please i need help so bad

Dilbert invests $2,000 at 6% simple interest for 1 year. How much is in the account at the end of the 1 year period?

Answers

Answer:

$2,120

Step-by-step explanation:

Simple interest formula

A = P(1 + rt)

where:

A = final amountP = principalr = interest rate (in decimal form)t = time (in years)

Given:

P = $2000r = 6% = 0.06t = 1 year

Substitute the given values into the formula and solve for A:

⇒ A = 2000(1 + 0.06(1))

⇒ A = 2000(1.06)

⇒ A = 2120

Therefore, there will be $2,120 in the account at the end of the 1 year period.

What is the length ?

Answers

Answer:

AC = 2x - 13 Cm

BC = 3x + 4 Cm

AB = 36 Cm

AB = AC + BC

BC = AB - AC

= 36 - (2x - 13)

= 36 - 2x + 13

= 49 - 2x

but, BC = 3x + 4

so equating both the equation we get

3x + 4 = 49 - 2x

3x + 2x = 49 + 4

5x = 53

x = 53/5

x = 10.6

BC = 49- 10.6*2

= 49- 21.2

= 27.8 CM

Answer:

BC = 31 cm

Step-by-step explanation:

from the diagram

AC + CB = AB ( substitute values )

2x - 13 + 3x + 4 = 36

5x - 9 = 36 ( add 9 to both sides )

5x = 45 ( divide both sides by 5 )

x = 9

then

BC = 3x + 4 = 3(9) + 4 = 27 + 4 = 31 cm

Help me with this question please!! :)

Answers

Answer: 20/63

Step-by-step explanation:

The probability that the first marble is red is 16/28.The probability that the second marble is red is 15/27.

Multiplying these probabilities, we get (16/28)(15/27) = 20/63

GIVING 100 POINTS: The graph shown here displays the distance, in miles. traveled by a jet in a certain number of hours. Based on the graph, which of the following equations indicates the correct variables, and in how many hours does the jet travel 12,000 miles if it travels at the same speed?

Graph titled Motion of a Jet shows Time in hours on x axis and Distance in miles on y axis. A straight line joins the ordered pairs 0, 0 and 2, 1200 and 4, 2400 and 6, 3600.

y = 600x, the jet travels 12,000 miles in 20 hours
x = 600y, the jet travels 12,000 miles in 20 hours
y = 600x, the jet travels 12,000 miles in 22 hours
x = 600y, the jet travels 12,000 miles in 22 hours

Answers

Answer:

A. y = 600x, the jet travels 12,000 miles in 20 hours

Explanation:

[tex]\sf slope: \dfrac{y_2 - y_1}{x_2- x_1} \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points[/tex]

Take two points: (2, 1200), (4, 2400)

[tex]\sf slope : \dfrac{2400-1200}{4-2 } = 600[/tex]

Equation:

y - 1200 = 600(x - 2)

y - 1200 = 600x - 1200

y = 600x

Miles the Jet travels at 20 hours:

y = 600(20) = 12000 miles

Miles the Jet travels at 22 hours:

y = 600(22) = 13200 miles

Answer:

y = 600x, the jet travels 12,000 miles in 20 hours

Step-by-step explanation:

Slope-intercept form of a linear equation:

[tex]y = mx + b[/tex]

where:

m = slopeb = y-intercept

To find the slope, define two points on the line and use the slope formula to find the slope:

[tex]\textsf{let}\:(x_1,y_1)=(0,0)[/tex][tex]\textsf{let}\:(x_2,y_2)=(2, 1200)[/tex]

[tex]\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{1200-0}{2-0}=600[/tex]

From inspection of the graph, the y-intercept (where the line crosses the y-axis) is at (0, 0).  Therefore, the equation of the line is:

y = 600x

y is defined as the distance (in miles).  Therefore, to find the number of hours it takes for the jet to travel 12,000 miles, substitute y = 12000 into the found equation and solve for x:

[tex]\sf \implies 600x=12000[/tex]

[tex]\sf \implies x=\dfrac{12000}{600}[/tex]

[tex]\sf \implies x=\dfrac{120}{6}[/tex]

[tex]\implies \sf x=20[/tex]

Therefore, it takes the jet 20 hours to travel 12,000 miles.

ASAP!!!!!!!!!!!!

PLEASE GIVE A STEP BY STEP EXPLANATION!!!


The linear functions f(x) and g(x) are represented on the graph, where g(x) is a transformation of f(x):

Part A: Describe two types of transformations that can be used to transform f(x) to g(x). (2 points)


Part B: Solve for k in each type of transformation. (4 points)


Part C: Write an equation for each type of transformation that can be used to transform f(x) to g(x). (4 points)

Answers

The two transformations for fx and gx would be to shift by 6 units and also go up by 18.

What is a transformation?

This is the term that is used in mathematics to describe the manipulation of a line or a shape.

a. The possible transformations that can be gotten here would be to shift to the left by 6 units from what we have in the graph and also shift to the top by 18.

b. How to solve for K in the transformation

g of x = f(x - k) then

g(x)= f(x) + k

C. The value of k should be based on the way it changes based on the given points.

Vertically, g(x)=f(x) +18

Horizontally , g(x)=f(x-6)

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The mean diastolic blood pressure for a random sample of 80 people was 100 millimeters of mercury. If the standard deviation of individual blood pressure readings is known to be 11 millimeters of mercury, find a 95% confidence interval for the true mean diastolic blood pressure of all people. Then give its lower limit and upper limit.

Answers

The confidence interval for the true mean diastolic blood pressure of all people is 100 ± 2.41 where the lower limit is 97.59 and the upper limit is 102.41

How to determine the confidence interval?

We have:

Mean = 100

Sample size = 80

Standard deviation = 11

At 95% confidence interval, the critical z value is:

z = 1.96

The confidence interval is then calculated as:

[tex]CI = \bar x \pm z \frac{\sigma}{\sqrt n}[/tex]

So, we have:

[tex]CI = 100 \pm 1.96 \frac{11}{\sqrt {80}}[/tex]

Evaluate the product

[tex]CI = 100 \pm \frac{21.56}{\sqrt {80}}[/tex]

Divide

[tex]CI = 100 \pm 2.41[/tex]

Split

CI  = (100 - 2.41,100 + 2.41)

Evaluate

CI  = (97.59,102.41)

Hence, the confidence interval for the true mean diastolic blood pressure of all people is 100 ± 2.41

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Question 2(Multiple Choice Worth 4 points)
If (89)P=818, what is the value of p?
02
09
10
18

Answers

Answer:

p = 2

Step-by-step explanation:

using the rule of exponents

[tex](a^{m}) ^{n}[/tex] = [tex]a^{mn}[/tex]

[tex](8^{9}) ^{2}[/tex] = [tex]8^{9(2)}[/tex] = [tex]8^{18}[/tex]

so value of p = 2


A. 6x 10y=9
B. 6x=9
C. -10y = 15
D. 2x= 15

Answers

Answer:

6x = 9

Step-by-step explanation:

4x-5y  = 12

2x+5y  = -3

Add the equations together

4x-5y  = 12

2x+5y  = -3

-------------------

6x + 0y = 9

6x = 9

Answer:

B. 6x = 9

Step-by-step explanation:

4x - 5y = 12

+ 2x + 5y = -3

____________

6x + 0 = 9

Hence, option B. 6x = 9 is the correct answer.

Which sequences are arithmetic sequences? Select all that apply.
a) 100, 95, 90, 85, ...
b) 10, 20, 40, 80, ...
c) 5, 17, 29, 41, 53, ...
d) -1, 1, -1, 1, -1, 1, ...
e) 42, 52, 62, 72, 82, ...


Answers

Answer:

state Avogadro's hypothesis and prove that molecular weight

The function f(x) = –x2 – 4x + 5 is shown on the graph. On a coordinate plane, a parabola opens down. It goes through (negative 5, 0), has a vertex at (negative 2, 9), and goes through (1, 0). Which statement about the function is true? The domain of the function is all real numbers less than or equal to −2. The domain of the function is all real numbers less than or equal to 9. The range of the function is all real numbers less than or equal to −2. The range of the function is all real numbers less than or equal to 9.

Answers

The true statement is:

"The range of the function is all real numbers less than or equal to 9."

Which statements are true?

Here we have the quadratic function:

[tex]f(x) = -x^2 - 4x + 5[/tex]

And we want to see which of the given statements are true.

The first one is:

"The domain is al real numbers less than or equal to -2"

This is false, for all quadratic functions the domain is the set of all real numbers (unless the domain is defined).

The second statement is:

" The domain of the function is all real numbers less than or equal to 9."

Also false

Third one:

" The range of the function is all real numbers less than or equal to −2"

The range of a quadratic function with a negative leading coefficient will be the set of all the values smaller than the y-value of the vertex.

In this case, the quadratic function is:

[tex]f(x) = -x^2 - 4x + 5[/tex]

So the vertex is at:

[tex]x = 4/(2*-1) = -2\\[/tex]

Then the y-value of the vertex is:

[tex]f(-2) = -(-2)^2 - 4*(-2) + 5 = -4 + 8 + 5 = 9[/tex]

So the range is the set of all real numbers less than or equal to 9.

So the above statement is false, and the final one:

"The range of the function is all real numbers less than or equal to 9."

Is the true statement.

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Samantha invests $11,000 at 6% simple interest for 25 years.
Round your answers to the nearest cent.

Answers

Answer:

$27,500.00

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 6%/100 = 0.06 per year.

Solving our equation:

A = 11000(1 + (0.06 × 25)) = 27500

A = $27,500.00

The total amount accrued, principal plus interest, from simple interest on a principal of $11,000.00 at a rate of 6% per year for 25 years is $27,500.00.

Somebody please assist me here

Answers

The base case of [tex]n=1[/tex] is trivially true, since

[tex]\displaystyle P\left(\bigcup_{i=1}^1 E_i\right) = P(E_1) = \sum_{i=1}^1 P(E_i)[/tex]

but I think the case of [tex]n=2[/tex] may be a bit more convincing in this role. We have by the inclusion/exclusion principle

[tex]\displaystyle P\left(\bigcup_{i=1}^2 E_i\right) = P(E_1 \cup E_2) \\\\ P\left(\bigcup_{i=1}^2 E_i\right) = P(E_1) + P(E_2) - P(E_1 \cap E_2) \\\\ P\left(\bigcup_{i=1}^2 E_i\right) \le P(E_1) + P(E_2) \\\\ P\left(\bigcup_{i=1}^2 E_i\right) \le \sum_{i=1}^2 P(E_i)[/tex]

with equality if [tex]E_1\cap E_2=\emptyset[/tex].

Now assume the case of [tex]n=k[/tex] is true, that

[tex]\displaystyle P\left(\bigcup_{i=1}^k E_i\right) \le \sum_{i=1}^k P(E_i)[/tex]

We want to use this to prove the claim for [tex]n=k+1[/tex], that

[tex]\displaystyle P\left(\bigcup_{i=1}^{k+1} E_i\right) \le \sum_{i=1}^{k+1} P(E_i)[/tex]

The I/EP tells us

[tex]\displaystyle P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) = P\left(\left(\bigcup\limits_{i=1}^k E_i\right) \cup E_{k+1}\right) \\\\ P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) = P\left(\bigcup\limits_{i=1}^k E_i\right) + P(E_{k+1}) - P\left(\left(\bigcup\limits_{i=1}^k E_i\right) \cap E_{k+1}\right)[/tex]

and by the same argument as in the [tex]n=2[/tex] case, this leads to

[tex]\displaystyle P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) = P\left(\bigcup\limits_{i=1}^k E_i\right) + P(E_{k+1}) - P\left(\left(\bigcup\limits_{i=1}^k E_i\right) \cap E_{k+1}\right) \\\\ P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) \le P\left(\bigcup\limits_{i=1}^k E_i\right) + P(E_{k+1})[/tex]

By the induction hypothesis, we have an upper bound for the probability of the union of the [tex]E_1[/tex] through [tex]E_k[/tex]. The result follows.

[tex]\displaystyle P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) \le P\left(\bigcup\limits_{i=1}^k E_i\right) + P(E_{k+1}) \\\\ P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) \le \sum_{i=1}^k P(E_i) + P(E_{k+1}) \\\\ P\left(\bigcup\limits_{i=1}^{k+1} E_i\right) \le \sum_{i=1}^{k+1} P(E_i)[/tex]

Hi can someone please help me with this geometry problem? Thanks!

Answers

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry.

What is a triangle?

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The sum of all the angles of a triangle is always equal to 180°.

The triangles ΔEST and ΔEFD are similar triangles, therefore, we can write,

[tex]\dfrac{ES}{EF} = \dfrac{ET}{ED} = \dfrac{ST}{FD}[/tex]

Since S and T are midpoints of EF and ED, the lines will be divided into two equal parts. Therefore,

[tex]\dfrac{ES}{EF} = \dfrac{ET}{ED} = \dfrac{ST}{FD}= \dfrac12[/tex]

Therefore, we can write it as,

[tex]FD = 2 (ST)[/tex]

In ΔEST and ΔTDR

∠T ≅ ∠T {Vertical angles}

ET ≅ TD {T is the midpoint of ED}

∠SET ≅ ∠TDR {Alternate interior angles}

Therefore,  ΔEST ≅ ΔTDR.

Since the two triangles are equal we can write,

ST ≅ TR

Further, it can be written as,

FD = 2(ST)

FD = ST + ST

FD = ST + TR

FD = SR

Hence, FD≅SR.

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Find the GCF of 12a and 18a²

Answers

The GCF of those two numbers is 6a

Answer:

6

Step-by-step explanation:

the blue factors are all the factors 12 and 18 have in common.

The stock of Company A lost 2% today to $73.50. What was the opening price of the stock in the beginning of the day?

Answers

The opening price of the stock in the beginning of the day will be $75.

What is the percentage?

The quantity of anything is stated as though it were a fraction of a hundred.

The stock of Company A lost 2% today to $73.50.

Let x be the opening price of the stock in the beginning of the day.

Then the opening price of the stock in the beginning of the day will be

0.98 · x = 73.5

         x = 73.5 / 0.98

         x = $75

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Which ordered pair is a solution of the equation?
y=4x−7

Answers

Answer:

Unknown

Step-by-step explanation:

Hi! so you didn't add the ordered pair options but I will do my best :) so if you see the ordered pair (0.7) that could definitely be a solution because using the slope intercept form equation you gave I know that's our y Intercept. the slope is 4/1 so moving up 4 and to the right 1 or down 4 and to the left 1 on a graph could show you more points! If you don't want to draw it you could use Desmos and just put this equation in or give me the ordered pairs and I will give you your answer!

hope this helps :)

I need help pls help

Answers

Answer:

550g

Step-by-step explanation:

total g in 1 kg is 1000

so 1000 - 550 =450

given that √5 = 2.24 and √50= 7.07 , find
√500 and √0.5

Answers

Answer:

see explanation

Step-by-step explanation:

using the rules of radicals

[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex]

[tex]\sqrt{\frac{a}{b} }[/tex] ⇔ [tex]\frac{\sqrt{a} }{\sqrt{b} }[/tex]

then

[tex]\sqrt{500}[/tex]

= [tex]\sqrt{100(5)}[/tex]

= [tex]\sqrt{100}[/tex] × [tex]\sqrt{5}[/tex]

= 10 × 2.24

= 22.4

-------------------------------

[tex]\sqrt{0.5}[/tex]

= [tex]\sqrt{\frac{50}{100} }[/tex]

= [tex]\frac{\sqrt{50} }{\sqrt{100} }[/tex]

= [tex]\frac{\sqrt{50} }{10}[/tex]

= [tex]\frac{7.07}{10}[/tex]

= 0.707

what is the answer to the question?

Answers

Using logic concepts, the correct statement is given by:

[tex](p \vee \neg p) \wedge \neg q[/tex]. FALSE.

What are the events in this problem?

The events are:

Event P: Henry is wearing a red shirt.Event Q: Henry is wearing khaki shirts.

The statement is:

Henri is wearing a red or blue shirt today with jeans.

A red or blue shirt can be represent by p or not p, that is:

[tex](p \vee \neg p)[/tex]

Jeans is not khaki, hence the second part is:

[tex]\neg q[/tex]

Combining the statements, we have that the expression is:

[tex](p \vee \neg p) \wedge \neg q[/tex]

Since p and q are true, [tex]\neg q[/tex] is false, and the entire statement is false. Hence the correct option is:

[tex](p \vee \neg p) \wedge \neg q[/tex]. FALSE.

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