Answer:
a). Second order reaction.
b). [tex]$50.14\ Lmol^{-1}s^{-1}$[/tex]
c). [tex]$t_{1/2}=1994.41 \ h$[/tex]
Explanation:
a). The order of the reaction of ozone decomposition is second order reaction.
It will be second order because the plot between the Inverse of Concentration versus Time will be a straight line.
[tex]$\frac{1}{[A]}=\frac{1}{[A_0]}+kt$[/tex]
b). Calculating slope by
[tex]$y_0= 100000.000$[/tex]
[tex]$y_1= 952380.952$[/tex]
[tex]$\Delta y = 852380.9524$[/tex]
[tex]$x_0=0E+00$[/tex]
[tex]$x_1= 2E+04$[/tex]
[tex]$\Delta x = 2E+04$[/tex]
Slope, k = [tex]$\frac{\Delta y}{\Delta x}=50.14$[/tex]
Thus we see that the slope of the curve will be rate constant.
Therefore, rate constant = [tex]$50.14\ Lmol^{-1}s^{-1}$[/tex]
c). We know half life ,
[tex]$t_{1/2}=\frac{1}{k[A_0]}$[/tex]
[tex]$[A_0]=0.00001 \ mol/L$[/tex]
k = [tex]$50.14\ Lmol^{-1}s^{-1}$[/tex]
Putting the values, we get
[tex]$t_{1/2}=\frac{1}{50.14[0.00001]}$[/tex]
[tex]$t_{1/2}=1994.41 \ h$[/tex]
Which term describes a solution having a very well-known concentration of solute? Select one: Secondary standard Primary standard Standard solution Volumetric analysis
Answer:
Standard solution
Explanation:
The correct answer would be a standard solution.
By definition, a standard solution is a solution whose concentration is known and which is often used to determine the concentration of other substances in, for example, titration. The process of using a solution of known concentration to determine the concentration of another substance is known as standardization.
PLZZZ Help ME !!! Will give Brainiest!!!
Does the intensity of the laser affect the voltage across the photo tube?
Answer:
Yes, the intensity of the laser does affect the amount of current that flows through the photo tube. The more intense the light, the more electrons are expelled, and thus the higher the current.
Explanation: Hope this helps!
Yes, the intensity of the laser does affect the amount of current that flows through the photo tube.
What is laser light effect?Laser light is a form of electromagnetic radiation and should not be confused with ultrasound or other electromedical therapies.
Laser light is of an electrical and magnetic character. Laser light can change the chemical structure of cells and tissue, which visible light cannot.
Thus laser light differs significantly from visible light.
The intensity of a laser beam is the optical power per unit area, which is transmitted through the target surface to the spread direction.
The units of the optical intensity are W/m2 or more commonly W/cm2.
Therefore ,we can conclude that laser light does effect the amount of current that flows through phototube.
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The hydrolysis of sucrose (C12H22O11) into glucose and fructose in acidic water has a rate constant of 1.8×10−4s−1 at 25 ∘C. Assuming the reaction is first order in sucrose, determine the mass of sucrose that is hydrolyzed when 2.45 L of a 0.170 M sucrose solution is allowed to react for 195 min.
Answer:
Explanation:
k = 1.8 x 10⁻⁴ s⁻¹
no of moles initially = 2.45 x .17 = .4165 moles
initial moles a = .4165
k = (1 / t ) ln a / ( a - x )
a is initial moles , x is moles reacted .
a is initial moles , x is moles reacted .
time t = 195 min = 11700 s
1.8 x 10⁻⁴ = 1 / 11700 x ln .4165 /( .4165 - x )
2.106 = ln .4165 /( .4165 - x )
.4165 /( .4165 - x ) = e²°¹⁰⁶ = 8.215
.4165 = 3.42 - 8.215 x
8.215 x = 3.0035
x = .3656
moles of sucrose hydrolysed = .3656 moles.
How many grams of Cu(OH)2 will precipitate when excess KOH solution is added to 76.0 mL of 0.764 M Cu(NO3)2 solution
Answer:
5.66g of Cu(OH)2 can be produced
Explanation:
Cu(NO3)2 reacts with KOH, as follows:
Cu(NO3)2 + 2KOH → Cu(OH)2 + 2KNO3
76.0mL of 0.764M Cu(NO3)2 are, in moles:
0.0760L * (0.764mol / L) = 0.0581 moles Cu(NO3)2
As 1 mole of Cu(NO3)2 produce 1 mole of Cu(OH)2, the moles of Cu(OH)2 produced are 0.0581 moles Cu(OH)2.
Molar mass of Cu(OH)2 is 97.561g/mol. In 0.0581 moles there are:
0.0581 moles Cu(OH) * (97.561g / mol) =
5.66g of Cu(OH)2 can be producedFind the density of an object that has a volume of 2.3 x 10^2 and a mass of
3.5 x 10^3. *
Answer:
[tex]\frac{250}{23}[/tex]
Step-by-step explanation:
[tex]10^{2} = 100[/tex] 2.3 × 100 = 230[tex]10^{3} = 1000[/tex] 3.5 × 1000 = 3500[tex]D = \frac{m}{v}[/tex] [tex]D = \frac{3500}{230}[/tex] 3500 ÷ 230 = [tex]\frac{250}{23}[/tex]I hope this helps!
What do the blue and red lines indicate?
A cold front is moving to the north and west before a warm front moves through.
A cold front is moving to the south and east before a warm front moves through.
A warm front is moving to the north and east before a cold front moves through.
A warm front is moving to the south and west before a cold front moves through.
WILL GIVE BRAINLIEST!
Answer:
this the one i needed help on pleasee sb help meh out
Explanation:
Answer:
A cold front is moving to the north and west before a warm front moves through.
Explanation:
A gas occupies a volume of 25.0 mL at a pressure of 760.0 mmHg and 27.0oC. What is the volume of the gas when the pressure is changed to 500.0 mmHg and the temperature to 400 K
Answer:
V2 = 50.67mL or 50.67cm^3
Explanation:
using the general gas law formula
(P1V1)/T1 = (P2V2)/T2
Where P1=760.0mmHg
P2=500.0mmHg
V1=250.0mL
V2=?
T1=27.0°C = 273+27=300K Note: constant temperature unit must be in Kelvin
T2=400k
Appling the formula
(P1V1) /T1 = (P2V2) /T2
Cross multiply
P1V1T2 =P2V2T1
Divide through by P2T1
therefore: V2= (P1V1T2) /(P2T1)
Inserting the values
V2=(760×25.0×400) /(500×300)
V2=(7600000) /(150000)
V2=50.67mL
Note: 1mL = 1 cm^3 therefore: V2= 50.67mL or 50.67cm^3
WILL GIVE BRAINLIEST AND LOTS OF POINTS
I rlly need help its due tomorrow
Alma is planning on joining the track team this year. In preparation for the season, Alma decides she wants to start running on her own to get in shape.
The next day, Alma decides to work on short sprints instead of long-distance running. Explain how Alma’s body cells would obtain energy differently when she sprints than when she runs long distances. When would her body’s cells make energy more efficiently? Why?
Alma is using ATC-PC which is a quick fuel source. Which is the first energy used in short and quick uses of energy. While it gives the max energy at first, after about 10 seconds it runs out. Which then short term energy starts. Which uses carbs as energy. This gets to max energy after a little bit and after a few minutes, it starts to run out. Then long term energy kicks in. This uses oxygen to provide energy, while it lasts for a long time, it takes time to reach max energy. This can also fail if your respiratory system or cardiovascular system can't provide enough oxygen.
Calculate the percentage by mass of lead in Pb(NO3)2. Calculate the percentage by mass of lead in Pb(NO3)2. 65.3 62.6 44.5 71.2 38.6
Answer:
62.6 %
Explanation:
Pb(NO₃)₂ = 207 + 124 = 331 gram
331 gram of lead nitrate contains 207 grams of lead
100 gram of lead nitrate contains
207 x 100 / 331 = 62.6 %
It can be deduced that percentage by mass of lead in Pb(NO₃)₂ is B. 62.6%.
How to calculate the percentage?From the given information, Pb(NO₃)₂ = 207 + 124 = 331 grams.
Therefore, 331 gram of lead nitrate contains 207 grams of lead. It can be deduced that 100 gram of lead nitrate will contain:
= 207 x 100 / 331
= 62.6 %
In conclusion, the correct option is 62.6%.
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What would you expect to observe when you add flour to a glass of water
Answer: It will kind of make like a type of tough or soft dough
Explanation: If you add too much water it might be a dough that bearly tays together or is very soft, but if you add too little it will be hard to mold. The reason it forms a sort of consistency like this is because When water is added to flour and mixed, these proteins absorb water, otherwise known as hydrating. Gliadin and Glutenin then combine to form the protein called GLUTEN. ... When flour is mixed with water, the gluten swells to form a continuous network of fine strands.
Correct Lewis structure for oxygen
Answer:
false
Explanation:
Explanation:
Lewis Dot Diagrams are represented by the element name in the middle, the same as in the periodic table, and is surrounded by dots that represent the elements valence electrons.
Calculate the energy of a photon of infrared light that has a
frequency of 2.40 x 10^12 Hz
Please Help!!!
Answer:
Option C. 1.60×10¯²¹ J
Explanation:
The following data were obtained from the question:
Frequency (f) = 2.40×10¹² Hz
Energy (E) =..?
We can obtain the energy of the photon of the infrared light by applying the following formula:
Energy (E) = Planck's constant (h) × frequency (f)
E = hf
Frequency (f) = 2.40×10¹² Hz
Planck's constant (h) = 6.63×10¯³⁴ Js
Energy (E) =..?
E = 6.63×10¯³⁴ × 2.40×10¹²
E = 1.60×10¯²¹ J
Thus, the energy of the photon of the infrared light which has a frequency of 2.40×10¹² Hz is 1.60×10¯²¹ J
According to the law of energy, it states that energy can never be created nor be destroyed. It can only transfer from one thing to another.
These are the various type of energy:-
Heat energyWind energyLight energyWater energyWe can obtain the energy of the photon of the infrared light by applying the following formula:
Energy (E) = Planck's constant (h) × frequency (f)
[tex]E = hf[/tex]
After putting the value:-
[tex]E = 6.63 * 10^3^4 * 2.40*10^1^2[/tex]
After solving the equation, the energy is:-
E = 1.60×10¯²¹ J
Thus, the energy of the photon of the infrared light which has a frequency of 2.40×10¹² Hz is 1.60×10¯²¹J
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A hypothetical element consists of two isotopes of masses 69.95 amu and 71.95 amu with abundances of 25.7% and 74.3%, respectively. What is the average atomic mass of this element?
a. 71.95 amu
b 71.4 amu
c. 69.95 amu
d. 70.95 amu
e. 70.5 amu
Answer:
Option B. 71.4 amu
Explanation:
From the question given above, the following data were obtained:
Isotope A:
Mass of A = 69.95 amu
Abundance (A%) = 25.7%
Isotope B:
Mass of B = 71.95 amu
Abundance (B%) = 74.3%
Average atomic mass =..?
The average atomic mass of the element can be obtained as shown below:
Average atomic mass = [(Mass of A × A%)/100)] + [(Mass of B × B%)/100)]
= [(69.95 × 25.7)/100] + [(71.95 × 74.3)/100]
= 17.977 + 53.459
= 71.436 ≈ 71.4 amu
Therefore, the average atomic mass of the element is 71.4 amu
If the analysis of carbon in a molecule indicates sp hybridization, what must be the shape around the carbon
Answer:
The shape around the carbon is linear . Sp hybridisation generally tends to be linear.
Explanation:
The hybridization procedure includes blending of the valence s orbital with one of the valence p orbitals to yield equal sp hybrid orbitals which can be orientated in a linear geometry. The p orbital is one orbital that could keep up to 2 electrons. The sp set is equal orbitals that factor 180° from every other.
Hence , the answer is linear shape around the carbon.
In his 1859 book On the Origin of Species, Charles Darwin stated
that modern organisms have evolved from common ancestors
through he process of
d
O adaptation
O evolution
diversification
O natural selection
pls help
natural selection
Explanation:
B. For the following questions, use the reaction SO3(g) SO2(g) + O2(g), with ΔH = 98.4 kJ/mol and ΔS = 0.09564 kJ/(mol·K). (8 points)
i. Draw a possible potential energy diagram of the reaction. Label the enthalpy of the reaction. (2 points)
(A picture from online will do I just need some sort of drawing)
THANK YOU VERY MUCH I REALLY NEED THIS!!
Answer:
A).
ΔH is positive, Therefore reaction is endothermic
B).
ΔG = ΔH - T∙ΔS
= 98.4 kJ/mol - 300K ∙ 0.09564 kJ/molK
= 69.7 kJ/mol
C).
ΔG is positive, Therefore reaction is non-spontaneous
Explanation:
look i know that its not a drawing but its the best that i can do with what i have. i hope this helps!
I need help ASAP please .................. You have a mixture of water, alcohol, and iron. Tell me, how would you separate them from each other?
Calculate the formula mass for HFO2
Answer:
The molar mass is 210.49 g/mol
Explanation:
A-Bohr's model
B-J.J. Thomson's plum pudding model
C-Dalton's atomic theory
D-Rutherford's gold foil experiment
The development of current atomic theory has changed over time as result of different proposed models and experiments. Place
these in chronological order.
Answer:
C, B, D, A
Explanation:
Dalton's model - 1803
J.J Thomson's model - 1904
Rutherford's model - 1911
Bohr's model - 1913
What do you guys think egg packaging should be made out of? Like what Materials? Best answer gets Brianly or whatever you call it lol
Also this is for a Science project so be smart heehee
Answer:
Well to start, as fragile as the eggs are, there should be a more durable material you feel me? Like maybe try something such as a rubbery product but one that isn't so tough on outside but not too soft on the inside. Basically a cushion but where is accessible for the eggs. We also dont want a material that is way to hard because it leaves no room for the eggs and its a very difficult workspace.
Explanation:
Hope this helps and good luck on your project :)
Which of the following sets of quantum numbers (n, l, m, ms) is possible for a 5f electron?
0 4,3,0,-
O 5,3,0,-
O 5, 3, +4,- 42
O 5, 2, 0, - 42
O 5,3,0,0
The possible quantum numbers for 5f are :
n = 5l =f = 3ml = -3,-2,-1,0,1,2,3ms = +1/2 or -1/2 Further explanationEach orbital in an atom consists of 4 quantum numbers
n is the principal quantum number ---> describes the size of the orbitals
l is the angular momentum / azimuthal quantum number -> describes the shape of the orbitals.
ml, the magnetic quantum number -> describes the orientation of orbitals in space
ms, the electron-spin quantum number ---> describes the spin of electrons
Value of n: positive integer
value of l: s = 0, p = 1, d = 2, f = 3, ... (n-1)
ml value: between -l to + l
ms value: +1/2 or -1/2
So the possible quantum numbers for 5f are :
n = 5l =f = 3ml = -3,-2,-1,0,1,2,3ms = +1/2 or -1/2Because the answer choices are not very clear, please see the composition I have described above
1. How are chemical bonds formed? *
Answer: Bonds form when atoms share or transfer valence electrons. Valence electrons are the electrons in the outer energy level of an atom that may be involved in chemical interactions. Valence electrons are the basis of all chemical bonds.
Explanation: Due to atoms and science ;)
Answer:
throught transferring or sharing an electron
Explanation:
a p e x :)))
PLEASE HELP!!!
Students combine several chemicals and record the observations in their science notebooks. A list of the observed results is given here. • Production of a gas (bubbles) • Phase change (solid to liquid) • A precipitate forms • Change in shape • Crystals dissolving • Heat produced How many of the observations are evidence that a new substance was formed? *
1 point
3
4
5
6
Answer:
3
Explanation:
I have indeed already took the quizzes my friend
20 points PLS HURRY
What will most likely occur if communities around the world increase the amount of wood they burn for heat?
A CO2 in the atmosphere will increase.
В CO2 in the atmosphere will decrease.
C Dissolved oxygen in the water will increase.
D Dissolved oxygen in the water will decrease.
Answer:
the answer is a shh /..\ yall smell that
Explanation:
) Chromate/Dichromate Equilibrium. Yellow chromate ion reacts with hydrogen ion to form (by condensation and loss of H2O) the orange dichromate ion:
Answer:
Explanation:
The Chromite ore is used for the production of Chromate/dichromate formation.
[tex]4FeCr2O4 + 8Na2CrO4+7O2 \\[/tex] →[tex]8NaCrO4 +2Fe2O3 +8CO2\\yellow[/tex]
so[tex]Na2CrO4[/tex] is called Chromite ore which is of yellow color.
[tex]Na2CrO4 +2H^+[/tex] → [tex]Na2CrO4 +2Na^+ +H2O[/tex]
[tex]Orange[/tex]
so when sodium chromate is reacted with hydrogen ion it forms sodium dichromate which is of orange color
Now
[tex]Na2Cr2O7+2KCl[/tex]→[tex]K2Cr2O7 + NaCl[/tex]
The chromate and dichromate are interconvertible in aqueous solution depending upon the PH of solution
Acid medium: [tex]Cr2O4^2-[/tex] [tex]2H^+[/tex]→[tex]Cr2O7^2-[/tex][tex]+H2O[/tex]
Base:[tex]Cr2O7^2- +2OH^-[/tex]→ [tex]CrO4^2- +H2O[/tex]
Hence Chromate and dichromate are interconvertible and hold and equilibrium.
Why are Group 1B elements more stable than Group 1A elements even though they seem to have the same outer electron configuration, ns1, where n is the principal quantum number of the outermost shell?
Answer:
Explanation:
The elements in Group 1A elements are Lithium, Sodium, Potassium, Rubidium, Caesium, and Francium(radioactive). The valence shells of the members have the electronic configuration of ns¹ where n =2,3,4,5,6,7. They are known as alkali earth metals. Their chemistry is dominated by the only electron in the outer shell of their atoms. Thus, they are powerful reducing agents because of their ability to lose this outer shell electron readily.
Thus ns' electrons in Group 1A require lesser energy for ionization in the case of elements of Group 1A; this explains why Group 1A elements are more reactive.
On the other hand, the Group 1B elements outer ns' electrons are less effectively shielded by the inner d electrons; therefore, the outer electrons in case of Group 1B feel more nuclear pull (due to positively charged protons in the nucleus) as compared to the nuclear pull in Group 1A elements. Thus electrons require more energy for ionization in the case of elements of Group 1B. This explains why Group 1B elements are less reactive than elements of Group 1A.
What question might a scientist ask about a cuttlefish?
A. Why are cuttlefish so ugly?
B. Do cuttlefish taste good?
C. Is it wrong to eat cuttlefish?
D. What do cuttlefish have in common?
Answer:
D. What do cuttlefish have in common?
Explanation:
A P E X 2021 :)
The question that a scientist might ask about cuttlefish is, "What do cuttlefish have in common that is present in Option D?" as the cuttlefish is an invertebrate and a member of the phylum Mollusca.
What are the general characteristics of the phylum Mollusca?The phylum Mollusca includes the octopus, cuttlefish, and other aquatic animals with soft bodies that can easily blend in with the background in order to capture prey or avoid the predator, and they have other adaptations too, such as the digestive system and other organs, as they are organ-level organisms. They have the outer hard shell that is present in the snail, and they can reproduce sexually and show larval forms of development.
Hence, the question that a scientist might ask about cuttlefish is, "What do cuttlefish have in common that is present in Option D?" as the cuttlefish is an invertebrate and a member of the phylum Mollusca.
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For the reaction of Zn (s) with Cu(NO3)3 (aq), write the molecular, complete ionic and net ionic equations.
Answer:
Explanation:
Molecular reaction
Zn + Cu( NO₃ )₂ = Zn( NO₃ )₂ + Cu
Complete reaction
Zn + Cu⁺² + 2 NO₃⁻ = 2 Zn⁺² + 2 NO₃⁻ + Cu
net ionic reaction
Zn + Cu⁺² = Zn⁺² + Cu
Plzzzzzz help good answer gets brainly
Aqueous hydrochloric acid will react with solid sodium hydroxide to produce aqueous sodium chloride and liquid water . Suppose 30.3 g of hydrochloric acid is mixed with 25. g of sodium hydroxide. Calculate the minimum mass of hydrochloric acid that could be left over by the chemical reaction. Be sure your answer has the correct number of significant digits.
Answer:
[tex]m_{HCl}^{leftover}=7.50g[/tex]
Explanation:
Hello.
In this case, since the undergoing chemical reaction is:
[tex]HCl+NaOH\rightarrow NaCl+H_2O[/tex]
In order to identify the limiting reactant, we compute the available moles of sodium hydroxide (molar mass = 40 g/mol) and the moles of hydrochloric acid consumed by those moles via their 1:1 mole ratio considering the chemical reaction:
[tex]n_{HCl}=25.0gNaOH*\frac{1molNaOH}{40gNaOH} *\frac{1molHCl}{1molNaOH} =0.625molHCl[/tex]
Next, since the molar mass of hydrochloric acid is 36.46 g/mol, we compute the mass of that reactant that is actually consumed:
[tex]m_{HCl}=0.625molHCl*\frac{36.46gHCl}{1molHCl}=22.8gHCl[/tex]
In such a way, the leftover of HCl is:
[tex]m_{HCl}^{leftover}=30.3g-22.8g\\\\m_{HCl}^{leftover}=7.50g[/tex]
Best regards!