Answer:
The Group 1 elements in the periodic table are known as the alkali metals. They include lithium, sodium and potassium, which all react vigorously with water to produce an alkaline solution.
Explanation:
Please help me . I attached a picture down below . I need a answer as soon as possible
Answer:
I can't see the picture.. Can you try attaching it again?
Explanation:
The Kp for the reaction A (g) = 2 B (g) is 0.0380. What is Kp for the reaction 4 B (g) = 2 A (g)?
Answer:
692.52
Explanation:
First Reaction;
A (g) = 2 B (g)
Kp is given as; (PB)² / (PA)
But Kp = 0.0380
So we have;
(PB)² / (PA) = 0.0380
Second Reaction;
4 B (g) = 2 A (g)
Kp is given as; (PA)² / (PB)⁴
The relationship between Kp expressions for both reactions is given as;
Second Reaction Kp = 1 / (First Reaction Kp)²
Second Reaction Kp = 1 / (0.0380)² = 1/0.001444
Second Reaction Kp = 692.52
How many moles are found in 10.5 g of Pb?
Answer:
Number of moles = 0.05 mol
Explanation:
Given data:
Mass of Pb = 10.5 g
Number of moles of Pb = ?
Solution:
Formula:
Number of moles = mass/molar mass
Molar mass of Pb is 207.2 g/mol.
Now we will put the values in formula.
Number of moles = 10.5 g/207.2 g/mol
Number of moles = 0.05 mol
If a substance has a density pf 2.5 g/cm³ how much mass will 50 cm³ of it have
Answer:
Density often has units of grams per cubic centimeter (g/cm3). Remember, grams is a mass and cubic centimeters is a volume (the same ... and minerals since the density of substances rarely changes significantly. For example, gold will always have a density of 19.3 g/cm3; if a mineral has a density
Explanation:
For example, a 1-litre soda bottle filled with air would feel much lighter than the same ... If 500 mL of a liquid has a density of 1.11 g/mL, what is its mass? ... The density of water at 4oC can be written as 1.000g/cm3 , 1.000g/mL ... In order to determine the density of a substance, you need to know its mass and its volume.
If a substance has a density of 2.5 grams/centimeters³ then the mass of the substance having a volume of 50 centimeters³ would be 75 grams.
What is density?It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.
As given in the problem If a substance has a density of 2.5 grams/centimeters³ then we have to find out the mass of the substance which has a volume of 50 centimeters³
the density of the substance = mass of the substance /volume of the substance
2.5 grams/centimeters³ = mass of the substance/50 centimeters³
mass of the substance = 2.5 ×50
= 75 grams
Thus, the mass of the substance would be 75 grams.
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Which graph best matches a person walking away at a constant speed
What is the name???????
Answer:
Carbon Hydrogen
Explanation:
I believe it means carbon (C) to one atom of hydrogen (H).
What happens to the particles in a berry sauce mixture as it boils?
Answer:
The particles garner more and more energy as the boiling continues and thus the energy particles would find a way to escape from it's surface and ultimately the sauce will get to a point where it will turn to gas.
Explanation:
When berry sauce is boiling, it's particles will garner more energy and therefore will move at an increasing faster rate which makes the sauce to continuously expand. Now, the hotter the boiling gets, the more the most energetic particles located at the surface of the sauce will escape from the surface of the sauce. This is because liquids usually evaporate faster when they undergo heating and more particles will have sufficient energy to break away.
As boiling continues, it will get to a point that even particles in the middle of the sauce will begin to form bubbles of gas and at this point, the sauce would have achieved sufficient heat that it will begin to turn to gas.
Need help on 6 and 7 or just one please help
ou are given a solution containing a pair of enantiomers (A and B). Careful measurements show that the solution contains 98% A and 2% B. What is the ee of this solution
Complete Question
You are given a solution containing a pair of enantiomers (A and B). Careful measurements show that the solution contains 98% A and 2% B. What is the enantiomeric excess?
Answer:
The value is [tex]k = 96 %[/tex]
Explanation:
From the question we are told that
The percentage of enantiomer A is A = 98%
The percentage of enantiomer B is B = 2%
Generally the enantiomeric excess is mathematically represented as
[tex]k = \frac{A -B}{A+B} * 100[/tex]
=> [tex]k = \frac{98 -2}{98+2} * 100[/tex]
=> [tex]k = 96 %[/tex]
Why does sodium chloride form a crystal lattice
Answer:
Ions of opposite charge strongly attract each other; those of like charges repel. As a result ions in an ionic compound are arranged in a particular manner.
Explanation:
Google is smart
Select the reagents you would use to synthesize the compounds below from benzene. Use the minimum number of steps. No more than three steps are required in any synthesis.
a. Br2, FeBr3
b. CH3COCi. AICl3
c. SO3, H2SO4
d. Cl2, FeCl3
e. KMnO4, H2O
f. HNO3, H2SO4
g. Fe, H3O then OH
h. CH3Cl, AICl3
m-chlorobenzenesulfonic acid:
2,4,6-tribromoaniline
Answer:
f and a. That is reagents f[HNO3, H2SO4] is used first then followed by reagent a[Br2, FeBr3]
Explanation:
So, in the production of m-bromonitrobenzene[3-Nitro-1-bromobenzene/1-Bromo-3-nitrobenzene] from benzene from the reagents provided by using the fastest reagents that is to say the reagent with the minimum number of steps, we are going to make use of reagents in option 'f' followed by reagents in option 'a'.
STEP ONE: The first step in the production of m-bromonitrobenzene[3-Nitro-1-bromobenzene/1-Bromo-3-nitrobenzene] from benzene to give the minimum number of steps from the reagents given is nitration by using the reagents in option 'f'' that is HNO3, H2SO4 to give nitrobenzene. The equation for the chemical reaction is given below as:
C₆H₆ + HNO₃, H₂SO₄ -------------------------------------------------------> C6H5NO2.
It is the N⁺O₂ that is been used in the reaction mechanism [from the reaction: HNO₃ + H₂SO₄ < -----------------> N⁺O₂ + HSO₄⁻ + H₂O].
STEP TWO: The next thing to do is to react the nitrobenzene got from the nitration of benzene in step one above with the reagents in option 'a'[Br2, FeBr3]. This step is known as the bromination of nitrobenzene.
C₆H₅NO₂ + Br₂, FeBr3 ------------------------------------------------> C₆H₄BrNO₂.
In the situations described below, what is the free energy change if 1 mole of Na+ is transported across a membrane from a region where the concentration is 267 μM to a region where it is 80 mM? (Assume T=37∘C.)
Answer:
ΔG = 19.5 kJ/mol
Explanation:
The free energy change for moving an ion is given by the following formula:
ΔG = RT㏑(C₂/C₁) + ΖЭψ
where R is molar gas constant = 8.315 J/mol;
T = 273 +37 = 310 K;
C₂ is concentration outside the cell = 267 μM = 0.000267 M;
C₁ is concentration inside the cell = 80 mM = 0.005 M;
Ζ is charge on ion = +1;
Э is Faraday's constant = 96500 J/V;
ψ is standard transmembrane potential = 0.05 V
ΔG = (8.315 J/mol * 310 K) ㏑(0.08/0.000267) + 1 *(96500 J/V * 0.05 V)
ΔG = (14692.60 + 4825)J/mol
ΔG = 19517.6 J/mol
ΔG = 19.5 kJ/mol
What is the pH of 0.166 M triethylammonium chloride, (C2H5)3NHCl. The Kb of triethylamine, (C2H5)3N, is 5.2 x 10-4.?
Answer:
5.7
Explanation:
(C₂H₅)₃NHCl dissociates according to the following equation.
(C₂H₅)₃NHCl ⇒ (C₂H₅)₃NH⁺ + Cl⁻
The molar ratio of (C₂H₅)₃NHCl to (C₂H₅)₃NH⁺ is 1:1. Then, the concentration of (C₂H₅)₃NH⁺ is Ca = 0.166 M.
(C₂H₅)₃NH⁺ is the conjugate acid of (C₂H₅)₃N. Given the Kb of (C₂H₅)₃N, we can calculate Ka for (C₂H₅)₃NH⁺ using the following expression.
Ka × Kb = Kw
Ka = Kw / Kb
Ka = 1.0 × 10⁻¹⁴ / 5.2 × 10⁻⁴
Ka = 1.9 × 10⁻¹¹
(C₂H₅)₃NH⁺ dissociates according to the following equation.
(C₂H₅)₃NH⁺ ⇄ (C₂H₅)₃N + H⁺
We can calculate [H⁺] using the following expression.
[H⁺] = √(Ca × Ka) = √(0.166 × 1.9 × 10⁻¹¹) = 1.8 × 10⁻⁶
The pH is:
pH = -log [H⁺] = -log 1.8 × 10⁻⁶ = 5.7
2.28 is the pH of 0.166 M triethylammonium chloride, [tex](C_2H_5)_3NHCl[/tex]. The Kb of triethylamine, [tex](C_2H_5)_3N[/tex], is [tex]5.2 \times 10^{-4}[/tex].
The term "potential of hydrogen" (pH) refers to a solution's acidity or alkalinity. It is a scale from 0 to 14, with 7 representing neutrality. A pH value of 7 or higher suggests alkalinity, whereas one below 7 indicates acidity. Since the pH scale is logarithmic, each number corresponds to a tenfold increase or decrease in acidity or alkalinity. For instance, a pH of 3 solution is ten times more acidic than a pH 4 solution. Similar to this, a pH 10 solution is ten times more alkaline than a pH 9 solution.
[tex](C_2H_5)_3NH^+ (aq) + H_2O (l) \rightarrow (C_2H_5)_3N (aq) + H_3O^+ (aq)[/tex]
Kb = [triethylamine] [[tex]H_3O^+[/tex]] / [triethylammonium chloride]
5.2 x[tex]10^{-4}[/tex] = (x) (x) / (0.166 - x)
x ≈ 5.32 x [tex]10^{-3}[/tex] M.
pH= -log(x)
= -log(5.32 x [tex]10^{-3}[/tex]))
≈ 2.28
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Two fruit flies that are heterozygous for body color and eye color are crossed. Brown body color is dominant to black body color. Red eye color is dominant to brown eye color.
Determine the genotypes of offspring 1-8.
1
2
3
4
5
6
7
8
A 4-column table has 4 rows. The labels of the columns are Upper B Upper E, Upper B e, b Upper E, b e. The labels of the rows are Upper B Upper E, Upper B e, b Upper E, Upper B b Upper E e. The first column has entries 1, Upper B Upper B Upper E e, 4, Upper B b Upper E e. The second column has entries Upper B Upper B Upper E e, 3, Upper B b Upper E e, 7. The third column has entries Upper B b Upper E Upper E, Upper B b Upper E e, 5, b b Upper E e. The fourth column has entries 2,Upper B b e e, 6, 8.
Answer:
the answer is simple
Explanation:
jnnn B upper up of the eye color
Answer:
1. BBEE
2. BbEe
3. BBee
4. BbEE
5. bbEE
6. bbEe
7. Bbee
8.bbee
When you finish exercising, you are hot, tired, and sweating. After a bottle of juice, you feel a lot better. Which organ systems are working together in this scenario?
Answer:
Nervous and Excretory
Explanation:
The nervous system makes you thirsty. The integumentary system makes you sweat. the integumentary system is very similar to the Excretory system.
Nervous and Excretory systems are working together in this scenario.
The nervous system makes you thirsty. The integumentary system makes you sweat. the integumentary system is very similar to the Excretory system.
The blood flow increases, your brain is exposed to more oxygen and nutrients. Exercise also induces the release of beneficial proteins in the brain. Sweating cools the body when it becomes warm. When the body temperature rises, such as when exercising on a hot day, the dermal blood vessels dilate.The excretory system works with the endocrine system to help maintain homeostasis.Learn more:
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Sulfur trioxide, SO3 , is produced in enormous quantities each year for use in the synthesis of sulfuric acid.
S(s) + O2(g) -------> SO2(g)
2SO2(g) + O2(g) ---------> 2SO3(g)
What volume of O2(g) at 340.°С and a pressure of 4.75 atm is needed to completely convert 6.30 g sulfur to sulfur trioxide?
Volume =_____ L
Answer:
3.14 L of oxygen (O₂).
Explanation:
We'll begin by calculating the number of mole in 6.3 g of sulphur (S). This can be obtained as follow:
Molar mass of S = 32 g/mol
Mass of S = 6.3 g
Mole of S =.?
Mole = mass / molar mass
Mole of S = 6.3/32
Mole of S = 0.197 mole
Next, we shall write the overall equation of the reaction between sulphur (S) and oxygen (O₂) to produce sulphur trioxide (SO₃) .
This is illustrated below:
S (s) + O₂ (g) —> SO₂ (g)
SO₂ (g) + O₂ (g) —> 2SO₃ (s)
Overall reaction:
2S (s) + 3O₂ (g) —> 2SO₃ (g)
Next, we shall determine the number of mole of oxygen (O₂) needed to completely convert 6.30 g (i.e 0.197 mole) of sulfur.
This is illustrated below:
From the balanced equation above,
2 moles of sulphur (S) required 3 moles of oxygen (O₂) .
Therefore, 0.197 mole of sulphur (S) will require = (0.197 × 3)/2 = 0.296 mole of oxygen (O₂).
Therefore, 0.296 mole of oxygen (O₂) is needed.
Finally, we shall determine the volume of oxygen (O₂) needed as follow:
Number of mole (n) of oxygen (O₂) = 0.296 mole
Temperature (T) = 340 °С = 340 °С + 273 = 613 K
Pressure (P) = 4.75 atm
Gas constant (R) = 0.0821 atm.L/Kmol
Volume (V) of oxygen (O₂) =.?
PV = nRT
4.75 × V = 0.296 × 0.0821 × 613
Divide both side by 4.75
V = (0.296 × 0.0821 × 613) / 4.75
V = 3.14 L
Therefore, 3.14 L of oxygen (O₂) is needed for the reaction.
Most animals can survive without food for a longer time than they can survive without water. Why is water so important to animals? Why can an animal survive without food for longer?
Answer:
Water is very important for animals because if the animal's cells don't get enough water they will shrivel up and die.
Explanation:
Answer:
1. Animals need fresh water for their bodies to function.
2. Animals can store energy as lipids and carbohydrates.
Explanation:
1. Water is very important for animals because if the animal's cells don't get enough water they will shrivel up and die. Water is also needed to carry out life processes.
2. Animals can store energy as lipids and carbohydrates which helps them survive for a longer time.
What type of wave does not need matter to carry energy?
The answer is Electromagnetic
Answer:
Electromagnetic
Explanation:
Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.
The half life of oxygen is 2 minutes. What fraction of a sample of 0.15 will remain after 5 half lives?
Answer:
3.13%.
Explanation:
The following data were obtained from the question:
Original amount (N₀) = 0.15
Half life (t½) = 2 mins
Number of half-life (n) = 5
Fraction of sample remaining =.?
Next, we shall determine the amount remaining (N) after 5 half-life. This can be obtained as follow:
Amount remaining (N) = 1/2ⁿ × original amount (N₀)
NOTE: n is the number of half-life.
N = 1/2ⁿ × N₀
N = 1/2⁵ × 0.15
N = 1/32 × 0.15
N = 0.15/32
N = 4.69×10¯³
Therefore, 4.69×10¯³ is remaining after 5 half-life.
Finally, we shall the fraction of the sample remaining after 5 half-life as follow:
Original amount (N₀) = 0.15
Amount remaining (N) = 4.69×10¯³
Fraction remaining = N/N₀ × 100
Fraction remaining = 4.69×10¯³/0.15 × 100
Fraction remaining = 3.13%
What are the factors affecting your limitations? How about possibilities?
Explanation:
My physiological make-up that governs the attributes I have and my climate, i.e. the conditions I have, are the variables influencing my limits. Biological make-up also regulates my prospects when they depend on my attributes, i.e. my ability and my environment , i.e. the conditions under which I am. This has been shown by experiments on twins, that our limits and opportunities are controlled by both genetics and environment.
A sample of methane gas is collected at 285 K and cooled to 245 K. At 245 K the volume of the gas is 75.0 L. Calculate the volume of the methane gas at 285 K. Assume constant pressure
Answer:
V₂ = 87.24 L
Explanation:
Charle's law states that at constant pressure, the volume of the gas is directly proportional to the temperature. Its mathematical form is given by :
[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]
We have, V₁ = 75, T₁ = 245 K, T₂ = 285, V₂ = ?
Putting all the values, we get :
[tex]V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{75\times 285}{245}\\\\V_2=87.24\ L[/tex]
So, the new volume is 87.24 L.
Air containing 20.0 mol% water vapor at an initial pressure of 1 atm absolute is cooled in a 1- liter sealed vessel from 200°C to 15°C. (a) What is the pressure in the vessel at the end of the process? (Hint: The partial pressure of air in the system can be determined from the expression pair = nairRT/V and P = pair + pH2O. You may neglect the volume of the liquid water condensed, but you must show that condensation occurs.) (b) What is the mole fraction of water in the gas phase at the end of the process? (c) How much water (grams) condenses?
Answer:
This solution is quite lengthy
Total system = nRT
n was solved to be 0.02575
nH20 = 0.2x0.02575
= 0.00515
Nair = 0.0206
PH20 = 0.19999
Pair = 1-0.19999
= 0.80001
At 15⁰c
Pair = 0.4786atm
I used antoine's equation to get pressure
The pressure = 0.50
2. Moles of water vapor = 0.0007084
Moles of condensed water = 0.0044416
Grams of condensed water = 0.07994
Please refer to attachment. All solution is in there.
i need soon this is due at 10:30 pm its curently 6:00 pm
What is parasitism?
Answer:
the practice of living as a parasite in or on another organism.
Hope this HELPS!!!
Explanation:
Sam washed his favorite pair of jeans. He hung the wet jeans on a clothesline outside. An hour later the jeans were dry.
Which answer best describes that happened to the water that was in the wet jeans an hour later?
State your answer and provide an explanation for your answer
A It soaked into the ground.
B It disappeared and no longer exists.
C It is in the air in an invisible form.
D It moved up to the clouds.
E It chemically changed into a new substance.
F It went up to the Sun.
G It broke down into atoms of hydrogen and oxygen.
Please help D:
Answer:
THe sun evapored the water and the wind helped dry it to.
Explanation:
Literally struggling with this concept.(problem set included below)
Identify the correct equation for the equilibrium constant Kc for the reaction given. C u ( s ) + 2 A g N O 3 ( a q ) − ⇀ ↽ − C u ( N O 3 ) 2 ( a q ) + 2 A g ( s ) Cu(s)+2AgNOX3(aq)↽−−⇀Cu(NOX3)X2(aq)+2Ag(s) Select one: K c = [ Cu ( NO 3 ) 2 ] [ Ag ] 2 [ AgNO 3 ] 2 [ Cu ] Kc=[Cu(NO3)2][Ag]2[AgNO3]2[Cu] K c = [ Cu ( NO 3 ) 2 ] 2 [ Ag ] [ AgNO 3 ] [ Cu ] 2 Kc=[Cu(NO3)2]2[Ag][AgNO3][Cu]2 K c = [ Cu ( NO 3 ) 2 ] [ AgNO 3 ] 2 Kc=[Cu(NO3)2][AgNO3]2 K c = [ Cu ( NO 3 ) 2 ] [ AgNO 3 ] Kc=[Cu(NO3)2][AgNO3]
Answer:
Kc = [Cu(NO₃)₂]/[2 AgNO₃]²
Explanation:
Let's consider the following balanced redox equation.
Cu(s) + 2 AgNO₃(aq) ⇄ Cu(NO₃)₂(aq) + 2 Ag(s)
The concentration equilibrium constant (Kc) is equal to the product of the concentration of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients. It only includes gases and aqueous species.
The concentration equilibrium constant for this reaction is:
Kc = [Cu(NO₃)₂]/[2 AgNO₃]²
Which of the following is an example of chemical weathering?
A . Rock grinded away by other rocks in a stream bed
B. Ice freezing and thawing in cracks
C. Waves beating on the shoreline
D. Dissolving of rock due to acid rain
Answer:
D. Dissolving of rock due to acid rain.
A helium filled blimp will rise just so high into the atmosphere and then stop. Why? Will a smaller blimp rise higher than a larger one, if both are filled to the same pressure?
Answer:
See explanation
Explanation:
When a helium blimp rises in the atmosphere, a point eventually comes when the buoyancy of the blimp compared to the air it displaces is no longer greater than gravity's pull on the blimp hence it stops rising.
A smaller blimp will rise more than a larger blimp at the same pressure because the weight of the blimp determines the altitude to which it will rise.
The discrete group of atoms that are held together by sharing valence electrons
Answer:
Molecule
Explanation:
Molecule is defined as the discrete group of atoms that are held together by sharing valence electrons.
This is because two or more atoms is known as a molecule and for electron sharing to occur then there must be a minimum of two atoms which is also known as a molecule present in the sharing process.
Hydrogen sulfide decomposes according to the following reaction, for which Kc=9.30E-8 at 700 degrees Celsius. 2 H2S(g) --> 2 H2(g) + S2(g) If 0.29 moles of H2S is placed in a 3.0-L container, What is the equilibrium concentration of H2(g) at 700 degrees Celsius?
Answer: The equilibrium concentration of [tex]H_2(g)[/tex] at 700 degrees Celsius is 0.0012 M
Explanation:
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as [tex]K_c [/tex]
Moles of [tex]H_2S[/tex] = 0.29 mole
Volume of solution = 3.0 L
Initial concentration of [tex]H_2S[/tex] = [tex]\frac{0.29mol}{3.0L}=0.097M[/tex]
The given balanced equilibrium reaction is,
[tex]2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)[/tex]
Initial conc. 0.097 M 0M 0M
At eqm. conc. (0.097-2x) M (2x) M (x) M
The expression for [tex]K_c[/tex] is written as:
[tex]K_c=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}[/tex]
[tex]K_c=\frac{(2x)^2\times x}{(0.097-2x)^2}[/tex]
[tex]9.30\times 10^{-8}=\frac{(2x)^2\times x}{(0.097-2x)^2}[/tex]
[tex]x=0.00060[/tex]
Equilibrium concentration of [tex][H_2][/tex]= 2x= [tex]2\times 0.00060=0.0012M[/tex]