Alicia made her aunt a garden. The width is 6 5/7 ft ft and the length is 7 3/5 ft. What is the area of the garden
Please answer!

Answers

Answer 1

Step-by-step explanation:

Area=Length×width

=6 5/7×7 3/5

change the improper fraction to proper

=47/7 ×38/5

=1786/35

=51.03ft²


Related Questions

Some contact lens wearers report problems with dryness in their eyes. A study was conducted to evaluate the effectiveness of a new eye-drop solution to relieve dryness for contact lens wearers. Twenty-five volunteers who wore contact lenses agreed to use the new solution for one month. At the end of the month, 36 percent of the volunteers reported that the new solution was effective in relieving dryness. The company that produced the new eye-drop solution concluded that using the new solution is more effective in relieving dryness than using no solution. Which of the following best explains why the study does not support such a conclusion.

(A) The sample size was too small.
(B) The study had no control group.
(C) The participants were volunteers.
(D) The participants self-reported the frequency with which they used the new solution.
(E) The participants self-reported the effectiveness of the new solution.

Answers

B is the correct answer

The preceding help understand why the study doesn't really support such a conclusion: the sample size was too small.

The assumption is approximate [tex]\hat{P}[/tex] by a normal distribution will be:

[tex]np \geq 10[/tex][tex]n (1-p) \geq 10[/tex][tex]n = 25[/tex]

→ [tex]np = 25\times 0.36[/tex]

       [tex]=9[/tex]

→ [tex]n (1-p) = 25\times (1-0.36)[/tex]

                [tex]= 25\times 0.64[/tex]

                [tex]= 16[/tex]

The above assumption is not satisfied. Thus the above answer i.e., "option A" is the appropriate one.

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The average marks of candidates in an aptituste test
was 128.5with a standard deviation of 8.2
Three scores extracted from the test are
148,102, 152, what is the average of the
extracted scores that are extreme values
fouthers (out the coutlier)

Answers

Answer:

102

Step-by-step explanation:

We must calculate the value of z for each value and then compare each one and thus manage to see what is an outlier, we know that z is equal to:

z = (x - m) / sd

where x is the value to evaluate, m the mean and sd the standard deviation. Now we have to:

For x = 148:

z = (148 - 128.5) /8.2

z = 2.37

For x = 102:

z = (102 - 128.5) /8.2

z = -3.23

For x = 152:

z = (152 - 128.5) /8.2

z = 2.86

The value of this is generally between -3.09 and 3.09, so when x is 102, it goes out of range of the value of z, which means that this is the outlier.

Eric’s average income for the first 4 months of the year is $1,450.25, what must be his
average income for the remaining 8 months so that his average income for the year is
$1,780.75?

Answers

Answer:

Average income of Eric for the remaining 8 months = [tex]\$1946[/tex]

Step-by-step explanation:

Given: Average income of Eric for the first 4 months of the year is equal to  $1,450.25

To find: average income for the remaining 8 months so that his average income for the year is  $1,780.75

Solution:

Average income = Total income for the year/Total number of months

Average income of Eric for the first 4 months = $1,450.25

So,

Total income of Eric for the first 4 months = 1,450.25 × 4 = 5801

Let x denotes total income of Eric for the remaining 8 months

Total income for the year = 5801 + x

Therefore,

Average income for the year = [tex]\frac{5801+x}{12}[/tex]

Also, average income for the year is  $1,780.75

[tex]1780.75=\frac{5801+x}{12}\\1780.75\times 12=5801+x\\21369=5801+x\\21369-5801=x\\15568=x[/tex]

Total income of Eric for the remaining 8 months = $15568

Average income of Eric for the remaining 8 months = [tex]\frac{15568}{8}=\$1946[/tex]

which expression is equivalent to -f-5(2f-3)

Answers

[tex]\text{One of the expressions can be the simplified version}\\\\\text{Simplify:}\\\\-f-5(2f-3)\\\\\text{Use the distributive property}\\\\-f-10f+15\\\\\text{Combine like terms}\\\\\boxed{-11f+15}\\\\\text{That expression is equivalent to the expression listed in the question}[/tex]

Answer:

11f+5

Step-by-step explanation:

khan

It is known that 25% of inhabitants of a community favour a political party A.
A random sample of 20 inhabitants was selected from the community and each person was asked he/she will vote for party A in an impending election. This follows a Binomial distribution, what is the probability that:
(i) exactly two persons will vote for party A?
(ii) at least three persons will vote for party A?
(iii) fewer than two persons will vote for party A?

Answers

Answer:

i) [tex]P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669[/tex]

ii) [tex]P(X=0)=(20C0)(0.25)^0 (1-0.25)^{20-0}=0.00317[/tex]

[tex]P(X=1)=(20C1)(0.25)^1 (1-0.25)^{20-1}=0.0211[/tex]

[tex]P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669[/tex]

And replacing we got:

[tex] P(X \geq 3) = 1- [0.00317+0.0211+0.0669]= 0.90883[/tex]

iii) [tex]P(X <2)= 0.00317+ 0.0211= 0.02427[/tex]

Step-by-step explanation:

Let X the random variable of interest "number of inhabitants of a community favour a political party', on this case we now that:

[tex]X \sim Binom(n=20, p=0.25)[/tex]

The probability mass function for the Binomial distribution is given as:

[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]

Where (nCx) means combinatory and it's given by this formula:

[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]

Part i

We want this probability:

[tex]P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669[/tex]

Part ii

We want this probability:

[tex]P(X\geq 3)[/tex]

And we can use the complement rule and we have:

[tex]P(X\geq 3) = 1-P(X<3)= 1-P(X \leq 2) =1- [P(X=0) +P(X=1) +P(X=2)][/tex]

And if we find the individual probabilites we got:

[tex]P(X=0)=(20C0)(0.25)^0 (1-0.25)^{20-0}=0.00317[/tex]

[tex]P(X=1)=(20C1)(0.25)^1 (1-0.25)^{20-1}=0.0211[/tex]

[tex]P(X=2)=(20C2)(0.25)^2 (1-0.25)^{20-2}=0.0669[/tex]

And replacing we got:

[tex] P(X \geq 3) = 1- [0.00317+0.0211+0.0669]= 0.90883[/tex]

Part iii

We want this probability:

[tex] P(X <2)= P(X=0) +P(X=1)[/tex]

And replacing we got:

[tex]P(X <2)= 0.00317+ 0.0211= 0.02427[/tex]

On a coordinate plane, 4 lines are shown. Line L M goes through (negative 5, negative 3) and (0, 3). Line N O goes through (negative 6, negative 5) and (0, 0). Line J K goes through (negative 6, 1) and (0, negative 4). Line P Q goes through (negative 5, 4) and (0, negative 2). Which line is perpendicular to a line that has a slope of Negative five-sixths? line JK line LM line NO line PQ

Answers

Answer:

no pq

Step-by-step explanation:

Answer:

Line LM

Step-by-step explanation:

Got it right on Edge2020

Leah ran the track 8 times. She ran a total of 2,000 meters. How many meters equals 1 lap?

Answers

Answer:

250m

Step-by-step explanation:

2000m/ 8laps = 250m

The publishers of a business magazine are running sales promotions for the weekly magazine. The number of prospective customers a sales representative sees per day varies 1 to 40. If the sales representative is able to her 20% of the prospective customers to subscribe, the maximum expected number of subscriptions per week is .if the sales representative earns $3 per subscription in addition to daily wages, the minimum expected value of the extra income per week is .

Answers

Answer:

the maximum expected number of subscriptions per week is

34 subscriptions

the minimum expected value of the extra income per week is

$94.20

Step-by-step explanation:

number of sales visits per day 1 - 40

success rate in closing sales 20%

total visits per week:

week 1 = 20 + 22 + 27 + 17 + 31 + 12 + 39 = 168week 2 = 26 + 13 + 30 + 18 + 24 + 14 + 32 = 157week 3 = 21 + 12 + 22 + 37 + 30 + 23 + 18 = 163week 4 = 15 + 33 + 10 + 28 + 34 + 24 + 22 = 166week 5 = 11 + 33 + 21 + 32 + 26 + 19 + 22 = 164week 6 = 19 + 27 + 20 + 18 + 31 + 14 + 37 = 166week 7 = 29 + 22 + 27 + 30 + 16 + 9 + 36 = 159week 8 = 8 + 28 + 19 + 28 + 25 + 36 + 26 = 170

estimated sales per week:

week 1 = 168 x 20% = 33.6week 2 = 157 x 20% = 31.4week 3 = 163 x 20% = 32.6week 4 = 166 x 20% = 33.2week 5 = 164 x 20% = 32.8week 6 = 166 x 20% = 33..2week 7 = 159 x 20% = 31.8week 8 = 170 x 20% = 34

extra income per week:

week 1 = 33.6 x $3 = $100.80week 2 = 31.4 x $3 = $94.20week 3 = 32.6 x $3 = $97.80week 4 = 33.2 x $3 = $99.60week 5 = 32.8 x $3 = $98.40week 6 = 33.2 x $3 = $99.60week 7 = 31.8 x $3 = $95.40week 8 = 34 x $3 = $102

Answer: subscriptions per week: 34

Extra income per week: $94.20

Step-by-step explanation: I got this right on Edmentum

Please answer this correctly

Answers

Answer:

volume = 75 cubic yards

Step-by-step explanation:

Base is 3×5 or 15 yd²

110-15-15=b×3×2+b×5×2

80=6b+10b

80=16b

Divide both sides by 16

b=5

The height of the rectangular prism is 5 yards

Now the volume is l×w×h

3×5×5=

75 yd³ or 75 cubic yards

Answer:

Volume = 75 yards³

Step-by-step explanation:

Surface Area = 110 yards²

But

Surface area = 2(wl+lb+bw) --(1)

Where w is the width , l is length and b is height

L = 5 yards, w = 3 yards

Putting in (1)

110 = 2{(3)(5)+(5)b+3b}

110 = 2(15+5b+3b)

110 = 2(15+8b)

110 = 30+16b

16b = 110-30

16b = 80

Dividing both sides by 18

b = 5

Now

Volume of rectangular prism = wlb

Where w is width, l is length and b is height

= (5)(3)(5)

= 75 yards³

The product of a number and 18 is -378. what does that mean or what's the equation

Answers

Answer:

Hope this helps you to solve it

A construction company finally completed a major project that paid $1,786,000. This company uses contract workers instead of employees. The money is to be divided in the ratio 4:2:3:3 among the company, The plumber, the electrician and the auxiliary workers. Calculate how much each of them receives.

Answers

Answer:

The company receives $595,333.333.

The plumber receives $297,666.667.

Each the electrician and the auxiliary workers receive $446,500.

Step-by-step explanation:

The total amount is $1,786,000.

Company:

The company receives [tex]\frac{4}{4 + 2 + 3 + 3} = \frac{4}{12} = \frac{1}{3}[/tex] of the total amount. So

[tex]\frac{1*1786000}{3} = 595333.333[/tex]

The company receives $595,333.333.

Plumber:

[tex]\frac{2}{4 + 2 + 3 + 3} = \frac{2}{12} = \frac{1}{6}[/tex] of the total amount. So

[tex]\frac{1*1786000}{6} = 297666.667[/tex]

The plumber receives $297,666.667.

Electrician and the auxiliary workers:

Each receives [tex]\frac{3}{4 + 2 + 3 + 3} = \frac{3}{12} = \frac{1}{4}[/tex] of the total amount. So

[tex]\frac{1*1786000}{4} = 446500[/tex]

Each the electrician and the auxiliary workers receive $446,500.

Twenty percent of what number is equal to five percent of 680

Answers

Answer:

170

Step-by-step explanation:

5/100 ×680

=34

20%=34what about 100%=?

(100×34)÷20

170

Twenty percent of 170 is equal to five percent of 680.

What is percentage?

The term ‘per cent’ means ‘out of a hundred’. In mathematics, percentages are used like fractions and decimals, as ways to describe parts of a whole.  When you are using percentages, the whole is considered to be made up of a hundred equal parts. The symbol % is used to show that a number is a percentage.

Let the number be x

According to question:

20% of x = 5%  of 680

[tex]\frac{20}{100}[/tex] x = [tex]\frac{5}{100}[/tex] × 680

20 x = 5 × 680

x = 170

Hence, Twenty percent of 170 is equal to five percent of 680.

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what is 9 1/2 x 1/4? i just need it for a math question on study island.

Answers

Answer:

[tex]2 \frac{3}{8} [/tex]

Step-by-step explanation:

[tex]9 \frac{1}{2} \times \frac{1}{4} \\ \frac{19}{2} \times \frac{1}{4} \\ = \frac{19}{8} \\ = 2 \frac{3}{8} [/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

Answer:

2 3/8

Hope this helps :)

a bucket that holds 5 1/4 gallons of water is being used to fill a tub that can hold 34 1/8 gallons. How many buckets will be needed to fill the tub?

Answers

The answer is 6 1/2 buckets.

What is did was turn the fractions into decimals to make it easier.  

So the ratio is 5.25 gallons per bucket. I divided 34 1/8 by 5 1/4 in decimal form (34.125/5.25) and got 6.5

So therefore, the answer is 6 1/2 buckets of water is needed ti fill up the tub.


Explain how to find the relationship between two quantities, x and y, in a table. How can you use the relationship to calculate the missing values in the table?

Answers

Explanation:

In general, for arbitrary (x, y) pairs, the problem is called an "interpolation" problem. There are a variety of methods of creating interpolation polynomials, or using other functions (not polynomials) to fit a function to a set of points. Much has been written on this subject. We suspect this general case is not what you're interested in.

__

For the usual sorts of tables we see in algebra problems, the relationships are usually polynomial of low degree (linear, quadratic, cubic), or exponential. There may be scale factors and/or translation involved relative to some parent function. Often, the values of x are evenly spaced, which makes the problem simpler.

Polynomial relations

If the x-values are evenly-spaced. then you can determine the nature of the relationship (of those listed in the previous paragraph) by looking at the differences of y-values.

"First differences" are the differences of y-values corresponding to adjacent sequential x-values. For x = 1, 2, 3, 4 and corresponding y = 3, 6, 11, 18 the "first differences" would be 6-3=3, 11-6=5, and 18-11=7. These first differences are not constant. If they were, they would indicate the relation is linear and could be described by a polynomial of first degree.

"Second differences" are the differences of the first differences. In our example, they are 5-3=2 and 7-5=2. These second differences are constant, indicating the relation can be described by a second-degree polynomial, a quadratic.

In general, if the the N-th differences are constant, the relation can be described by a polynomial of N-th degree.

You can always find the polynomial by using the given values to find its coefficients. In our example, we know the polynomial is a quadratic, so we can write it as ...

  y = ax^2 +bx +c

and we can fill in values of x and y to get three equations in a, b, c:

  3 = a(1^2) +b(1) +c

  6 = a(2^2) +b(2) +c

  11 = a(3^2) +b(3) +c

These can be solved by any of the usual methods to find (a, b, c) = (1, 0, 2), so the relation is ...

   y = x^2 +2

__

Exponential relations

If the first differences have a common ratio, that is an indication the relation is exponential. Again, you can write a general form equation for the relation, then fill in x- and y-values to find the specific coefficients. A form that may work for this is ...

  y = a·b^x +c

"c" will represent the horizontal asymptote of the function. Then the initial value (for x=0) will be a+c. If the y-values have a common ratio, then c=0.

__

Finding missing table values

Once you have found the relation, you use it to find missing table values (or any other values of interest). You do this by filling in the information that you know, then solve for the values you don't know.

Using the above example, if we want to find the y-value that corresponds to x=6, we can put 6 where x is:

  y = x^2 +2

  y = 6^2 +2 = 36 +2 = 38 . . . . (6, 38) is the (x, y) pair

If we want to find the x-value that corresponds to y=27, we can put 27 where y is:

  27 = x^2 +2

  25 = x^2 . . . . subtract 2

  5 = x . . . . . . . take the square root*

_____

* In this example, x = -5 also corresponds to y = 27. In this example, our table uses positive values for x. In other cases, the domain of the relation may include negative values of x. You need to evaluate how the table is constructed to see if that suggests one solution or the other. In this example problem, we have the table ...

  (x, y) = (1, 3), (2, 6), (3, 11), (4, 18), (__, 27), (6, __)

so it seems likely that the first blank (x) will be between 4 and 6, and the second blank (y) will be more than 27.

Here is your answer     |  To determine the relationship between quantities, you must determine what to do to the x-values to make them into y-values. The correct operation must turn every x-value into the corresponding y- value in the table. Once you know the relationship, you can use the same operation on all of the x-values that have unknown y-values.

29 POINTS AND BRAINLIEST !!! Jim likes to rock climb in his spare time. Recently, he climbed down from the top of a cliff to the bottom. At the top, where Jim started, he was 2500 ft above the ground. He moved down the cliff at a speed of 20 ft/min.
a) Write an equation to represent the height h, in feet, that Jim was above the ground after t minutes.
b) Make a table of values for Jim's height above the ground for values of t from 0 to 4.
c) What was Jim's height above the ground after 40 minutes?
d) How many minutes did it take to reach the ground?

Answers

Answer:

Step-by-step explanation:

A) y = -20x + 2500

The above equation is written in slope intercept form - y=mx+b - the y int. is 2500, while the rate of change, aka the slope, is -20 feet per minute.

B) (0,2500)    (1,2480)    (2,2460)    (3,2440)    (4,2420)

For this question just plug in the x values 0 to 4 into the equation above. For example -20(0) +2500 = 2500

C) 1700 feet above the ground

Plug the number 40 into the equation above. -20(40) + 2500 = 1700

D) 125 minutes

The y-int. represents the time it takes him to reach the ground, this means you can set the equation equal to zero and solve to find the answer.

0 = -20x + 2500

subtract 2500 from both sides

-2500 = -20x

divide -20 from both sides

125 = x

Answer:50m

Step-by-step explanation: the highest

A recipe uses cup of brown sugar to make 18 cookies. How many cups of brown sugar are needed to make 45 cookies? ASAP

Answers

Answer:

2.5

Step-by-step explanation:

it takes 1 cup to make 18 cookies so you divide 45 by 18 to get your answer

The function f(x) = –StartRoot x EndRoot is represented by the graph. What is the range of the given function? {y | all real numbers} {y | y ≤ 0} {y | y ≥ 0}

Answers

Answer:

  {y | y ≤ 0}

Step-by-step explanation:

The vertical extent of the graph is all values of y less than or equal to zero:

  {y | y ≤ 0}

Answer: {y | y ≤ 0}

Step-by-step explanation: It is the correct answer <3 have an amazing day.

A ball is thrown straight up from a cliff. The function f(x) = –4.9t2 + 17t + 19 describes the height of the ball, in meters, as a function of time, t, in seconds. What is the maximum height of the ball? At what time is that height reached? Round your answers to 1 decimal place.


Maximum height:

__ meters


Time:

__ seconds

Answers

Answer:

Maximum height: 33.7 meters

Time: 1.7 seconds

Step-by-step explanation:

Suppose we have a quadratic equation in the following format:

[tex]f(t) = at^{2} + bt + c[/tex]

In a is negative, the maximum point of the function happens at the time of

[tex]t_{v} = -\frac{b}{2a}[/tex]

And it's value is: [tex]f(t_{v})[/tex]

In this question:

[tex]f(t) = -4.9t^{2} + 17t + 19[/tex]

So [tex]a = -4.9, b = 17, c = 19[/tex]

The time of the maximum height is:

[tex]t_{v} = -\frac{b}{2a} = -\frac{17}{2*(-4.9)} = 1.7[/tex]

The maximum height is:

[tex]f(1.7) = -4.9*(1.7)^{2} + 17*1.7 + 19 = 33.7[/tex]

A rancher has a roll of fencing to enclose a rectangular area. The table shows how the area that the rancher can enclose with the fencing depends on the width of the rectangle. Which quadratic equation gives the area A of the rectangle in square feet given its width in w feet? ✔ A(w) = -w² + 100w The rancher decides to make the width of the rectangle 40 ft. What is the area of the rectangle? PLEASE HURRY

Answers

Answer:

A(w) = -w^2 + 100w

Step-by-step explanation:

just took the assignment

Finding the numeric value of the function, it is found that the area of the rectangle is of 2400 square feet.

---------------------------

The area of a rectangle of width w is given by:

[tex]A(w) = -w^2 + 100w[/tex]

In this question, we have a width of 40 ft, thus [tex]w = 40[/tex], and the area is of:

[tex]A(40) = -40^2 + 100(40) = -1600 + 4000 = 2400[/tex]

The area is of 2400 square feet.

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what number is to be multiplied with 1/3 to get 1/21

Answers

Answer:

1/7

Step-by-step explanation:

Since we do not know the number let us use the alphabet A to represent the unknown number

A × 1/3= 1/21

A/3= 1/21

Cross multiply both sides

A×21= 3×1

21A= 3

Divide both sides by the coefficient of A which is 21

21A/21=3/21

A=1/7

Hence the unknown number is 1/7

Answer:

The number to multiply with 1/3 to get 1/21 is 1/7.

Step-by-step explanation:

The question wants us to find the number you can multiply with 1/3 to get 1/21. The number is unknown but when you multiply that unknown number by 1/3 your answer should be 1/21.

Let

the number to be multiplied with = a

Therefore,

1/3 × a = 1/21

a/3 = 1/21

cross multiply

21a = 3

divide both sides by 21

a = 3/21

a = 1/7

The number to multiply with 1/3 to get 1/21 is 1/7.

Nathan spins 2 different spinners at the same time. There are a total of 10 possible
outcomes. Which pair of spinners did Nathan spin?
A
B
A
B
1
2
E
2
E
5
3
D
4
A
B
2
A
B
E
c
COM
3
D
с​

Answers

Answer:

Since the spinners have been spun simultaneously, every side on each of the spinner carries equal probability of landing. In order for there to be only 10 possible outcomes, no more no less, the spinners cannot be identical. One of the spinner in two sided while the other spinner must then be a five sided spinner. Choosing this particular pair of spinners gives Nathan 10 possibilities of combinations.

Hope that answers the question, have a great day!

Answer:

The spinners he spins are the ones that together add up to ten numbers.

Step-by-step explanation:

Please help !!! Ill give you brainliest!!!

Answers

Answer:

72

Step-by-step explanation:

s=9

t=8

therefore , st

9×8

= 72

Answer:

st

Putting the value of s and t in above equation

=> 9 × 8

=> 72

if you work make 15 an hour for 8 hour shift how much is that

Answers

Answer:

120

Step-by-step explanation:

15*8=120

120 , multiply 15 by 8

9(5r-2) and 14r-7 yes or no to tell if this expression is equivalent or not

Answers

Answer:

No instead of doing multiplication u did division

Step-by-step explanation:

This equation is called distributive property where u multiply the answer from the outside by the inside number

In an experiment to study the effect of temperature (x) on the yield of a chemical reaction (y), 30 experimental runs were conducted. The level of temperature was carefully controlled at each of five levels, coded as x = -2, -1, 0, 1, 2. Two catalysts were used. For each catalyst three runs were taken at each level of temperature, and the yield was measured. The model y = beta_0 + beta_1x + beta_2x^2 + beta_3z + epsilon, epsilon ~ N(0, sigma^2) was considered, where z = 0 for catalyst 1 and z = 1 for catalyst 2. a. Carefully interpret the parameter beta_3 in this model. b. The model was fit to the data and the output is summarized below. The residual sum of squares is 25.05, and Is there any evidence of a difference in the two catalysts? Find a 95% confidence interval for beta_2. c. We also know that (X'X)^-1 = [0.114 0 -0.023 -0.067 0 0.017 0 0 -0.023 0 0.012 0 -0.067 0 0 0.133] i. Explain why ^beta_1and ^beta_3 are independent random variables. ii. Find a 95% confidence interval for the expected yield when the standard temperature (x = 0) and catalyst 2 are used. iii. Find a 95% prediction interval for the yield of a new experiment run under standard temperature (x = 0) and with catalyst 2.

Answers

Answer:

=5

Step-by-step explanation:

Given that an experimenter is studying the effects of temperture, pressure, and type of catalyst on yield from a certain chemical reaction. Three different temperatures, four different pressures, and five different catalysts are under consideration.

a) Experimental runs possible if use of single temperature, pressure and catalyst is there = no of temperatures x no of pressures x no of catalysts

= b) Here pressure and temperature have no choice as lowest is selected.

no of methods = no of catalysts x 1 x1

= 5

5) Horatio Reyes earns 3.625% interest on his account. If his principal is

$6000 and he deposits $150 into the account every 6 days, how much total

interest will Horatio earn after 30 days? *

Answers

Answer:

$20.11

Step-by-step explanation:

Solution:-

- We will define the interest rate ( R ) earned on his deposits in the account per annum ( 365 days ).

- He deposits a principal amount of ( P ) = $6,000 once at the start of the accounting period.

- After the principal amount is deposited he deposits $ 150 in the account after every 6 days.

- We will first determine the amount in his account at the end of 30 days.

- We need to see how many additional deposits of $150 were made in these 30 days.

- The ( n ) number of additional deposits can be determined from the ratio of time-span of each deposition and the total accounting period:

                     [tex]n = \frac{30}{6} = 5[/tex]

- Horatio Reyes makes ( n = 5 ) additional deposits after the principal amount till the end of 30th day.

- Now we can calculate the total amount accumulated ( A ) in his account at the end of 30 days time period. It comprises of the initial principal amount and the 5 series of $150 deposits:

                   [tex]A = P + $150*n[/tex]

- Plug in the respective amounts ( P and n ):

                   [tex]A = 6000 + 150*5\\\\A = 6000 + 750\\\\A = 6750[/tex]

- At the end of 30th day Horatio Reyes has $6,750 in his account.

- The interest rate ( r ) applied at the end of the 30-day time period is sub-part of the total interest rate ( R ) applied per annum.

- So the interest rate applied at the end of 30-day tim period is determined from simple proportional ratios of time-period:

                      Rate(%)                     Time(days)

               R:   3.625                             365        

               r:       x                                   30

     ========================================

                      x = 30*3.625 / 365 = 0.29795%

     ========================================

- Now we will apply the rate ( r ) on the accumulated amount ( A ) by the end of 30-day time period in the account to determine the interest earned ( I ):

             

                        [tex]I= \frac{r*A}{100} \\\\I = \frac{0.29795*6750}{100} \\\\I = 20.111[/tex]

- The amount of interest earned ( I ) is $20.11 after 30 days.

           

                                     

f(x)=log2(x-3) find the domain of x

Answers

Domain and range should be (-&,-&)

A volleyball is an example of a____a0.

Answers

Answer:

sphere

Step-by-step explanation:

A volleyball is a three dimensional object

It is a three dimensional circle which is called a sphere

Answer:

sphere

Step-by-step explanation:

hope this helps:]

Overeating for just four weeks can increase fat mass and weight over two years later, a Swedish study shows.Researchers recruited 18 healthy and normal-weight people with an average age of 26. For a four-week period, participants increased calorie intake by (mostly by eating fast food) and limited daily activity to a maximum of 5000 steps per day (considered sedentary). Not surprisingly, weight and body fat of the participants went up significantly during the study and then decreased after the study ended. Participants are believed to have returned to the diet and lifestyle they had before the experiment. However, two and a half years after the experiment, the mean weight gain for participants was 6.8 lbs with a standard error of 1.2 lbs. A control group that did not binge had no change in weight.

Required:
a. Give a 95% confidence interval for parameter.
b. Give the margin of error.

Answers

Answer:

a) [tex] 6.8 -2.110*1.2 =4.268[/tex]

[tex] 6.8 +2.110*1.2 =9.332[/tex]

b) [tex] ME = t_{\alpha/2} SE= 2.110*1.2= 2.532[/tex]

Step-by-step explanation:

For this case we have the following info given:

[tex] \bar X= 6.8[/tex] represent the sample mean

[tex] Se= 1.2[/tex] represent the standard error

[tex] n =18[/tex] the sample size

Part a

For this case the confidence interval for the mean is given by:

[tex] \bar X \pm t_{\alpha/2} SE[/tex]

The degrees of freedom are given by:

[tex] df =n-1=18-1=17[/tex]

And the critical value for a confidence interval of 95% is given by:

[tex] t_{\alpha/2}=2.110[/tex]

And the confidence interval would be:

[tex] 6.8 -2.110*1.2 =4.268[/tex]

[tex] 6.8 +2.110*1.2 =9.332[/tex]

Part b

The margin of error is given by:

[tex] ME = t_{\alpha/2} SE= 2.110*1.2= 2.532[/tex]

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