Acontinous random variable X has a pdf given by p(x) = (5x4 0≤x≤1 0, otherwise) Let Y=X3. Find the probability distribution function ​

The difference of two squares expression is (d) 25a^2-36b^6

The difference of two squares is represented as:

x^2 - y^2

Where x and y are perfect square expressions.

From the list of options, we have:

25a^2-36b^6

The terms of the above expression are perfect squares

i.e.

25a^2 = (5a)^2

36b^6 = (6b^3)^2

Hence, the difference of two squares expression is (d) 25a^2-36b^6

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Your answer is correct. The two "bases" of the trapezoid are the line segments (0, 0)-to-(y, 0) and (0, x)-to(z, x), with lengths y and z, respectively. Then the average of the bases is [tex]\frac{y+z}2[/tex]. (We know they're the bases because the line segments are parallel.)

We multiply this by the height, which is given by the length of the line segment (0, 0)-to-(0,x), or x.

Hence the area is

[tex]\dfrac{x(y+z)}2[/tex]

(which is identical to what you have).

Step-by-step explanation:

look at the attachment above

Answer:

[tex]\textsf{1)} \quad -\dfrac{1}{16}e^{-4x}\left(4x+1\right)+\text{C}[/tex]

[tex]\textsf{2)} \quad - \cos x+\dfrac{2}{3} \cos^3 x - \dfrac{1}{5} \cos^5 x +\text{C}[/tex]

Step-by-step explanation:

Question 1

[tex]\boxed{\begin{minipage}{5 cm}\underline{Integration by parts} \\\\$\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x=uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x$ \\ \end{minipage}}[/tex]

[tex]\boxed{\begin{minipage}{5 cm}\underline{Integration of $e^{ax}$} \\\\$\displaystyle \int e^{ax}\:\text{d}x=\dfrac{1}{a}e^{ax}+\text{C}$\\\\for $a\neq 0$\\\end{minipage}}[/tex]

Given integral:

  [tex]\displaystyle \int xe^{-4x}\:\text{d}x[/tex]

Using Integration by parts:

[tex]\textsf{Let }\:u=x \implies \dfrac{\text{d}u}{\text{d}x}=1[/tex]

[tex]\textsf{Let }\:\dfrac{\text{d}v}{\text{d}x}=e^{-4x} \implies v=-\dfrac{1}{4}e^{-4x}[/tex]

Therefore:

[tex]\begin{aligned}\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x & =uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x\\\\\implies \displaystyle \int xe^{-4x}\:\text{d}x & =-\dfrac{1}{4}xe^{-4x}-\int -\dfrac{1}{4}e^{-4x}\: \text{d}x\\\\& =-\dfrac{1}{4}xe^{-4x}+\int \dfrac{1}{4}e^{-4x}\: \text{d}x\\\\& =-\dfrac{1}{4}xe^{-4x}-\dfrac{1}{16}e^{-4x}+\text{C}\\\\& =-\dfrac{1}{16}e^{-4x}\left(4x+1\right)+\text{C}\end{aligned}[/tex]

Question 2

[tex]\boxed{\begin{minipage}{4 cm}\underline{Integrating $x^n$}\\\\$\displaystyle \int x^n\:\text{d}x=\dfrac{x^{n+1}}{n+1}+\text{C}$\\ \end{minipage}}[/tex]    

[tex]\boxed{\begin{minipage}{5 cm}\underline{Integrating a constant}\\\\$\displaystyle \int n\:\text{d}x=nx+\text{C}$\\(where $n$ is any constant value)\end{minipage}}[/tex]

Rewrite the given integral:

[tex]\begin{aligned}\displaystyle \int \sin^5 x \: \text{d}x & =\int (\sin x)^4 \cdot \sin x \: \text{d}x\\& =\int (\sin^2 x)^2 \cdot \sin x \: \text{d}x\end{aligned}[/tex]

Use the trig identity  [tex]\sin^2x+\cos^2x \equiv 1[/tex]  to rewrite  [tex]\sin^2x[/tex] :

[tex]\implies \displaystyle \int \sin^5 x \: \text{d}x = \int (1-\cos^2 x)^2 \cdot \sin x \: \text{d}x[/tex]

Integration by substitution

[tex]\textsf{Let }\:u=\cos x \implies \dfrac{\text{d}u}{\text{d}x}=-\sin x \implies \text{d}x=-\dfrac{1}{\sin x}\: \text{d}u[/tex]

Therefore:

[tex]\begin{aligned}\implies \displaystyle \int \sin^5 x \: \text{d}x & = \int (1-u^2)^2 \cdot \sin x \cdot -\dfrac{1}{\sin x}\: \text{d}u\\& = \int -(1-u^2)^2 \: \text{d}u\\ & =\int -1+2u^2-u^4 \: \text{d}u\\& =-u+\dfrac{2}{3}u^3-\dfrac{1}{5}u^5+\text{C}\end{aligned}[/tex]

Finally, substitute  [tex]u = \cos x[/tex]  back in:

[tex]\implies \displaystyle \int \sin^5 x \: \text{d}x=- \cos x+\dfrac{2}{3} \cos^3 x - \dfrac{1}{5} \cos^5 x +\text{C}[/tex]

Answer:

I believe you forgot to add a picture

Answer:

a= 30

b=60

c=105

Step-by-step explanation:

A forms a vertical angle with another angle that measures 30 degrees, therefore,

a= 30 degrees.

Since a is 30 degrees and a and b are in the same triangle with a 90-degree angle and all interior angles in a triangle equal 180 degrees.

Then, 30+90+b=180

120+b=180

b=60

Angle c and an angle that equals 75 degrees are supplementary. meaning that they add up to 180 degrees.

180-75=c

105=c

Answer:

It doesn't say anything about "Length" and "Width".

Step-by-step explanation:

Brainlest . Just press the .

Answer: We can take 2 common we could also write this as 2 times X plus y.

Step-by-step explanation:

Answer:

[tex]4\sqrt{26}[/tex]

Step-by-step explanation:

The distance formula is [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex].

Thus we can plug the numbers in:

[tex]\sqrt{(-2-(-6))^2+(10-(-10))^2}[/tex]

[tex]\sqrt{(4)^2+(20)^2}[/tex]

[tex]\sqrt{16+400}[/tex]

[tex]\sqrt{416}[/tex]

[tex]4\sqrt{26}[/tex]

Answer:

Charles Babbage

Step-by-step explanation:

Answer: Hope this may help you

Charles Babbage, I think

Step-by-step explanation:

Charles Babbage is sometimes referred to as the father of computers.

Press the Linear Regression button to generate the regression line.

We have given that, regression line using a regression calculator

We have to determine how to graph a scatterplot and its regression line using a regression calculator.

Before entering data into the regression calculator, it is important to determine which variable should be associated with the x-axis and which with the y-axis.

Regression analysis is a set of statistical processes for estimating the relationships between a dependent variable and one or more independent variables.

Enter the data pairs.

Press the Linear Regression button to generate the regression line.

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i ) 3(2x - 3) = 4(2x + 4)

[tex]6x - 9 = 8x +1 6 \\ \\ 6x - 8x = 16 + 9 \\ \\ - 2x = 25 \\ \\ x = - \frac{25}{2} .[/tex]

ii )2(x + 2) + 5(x + 5) = 4(x-8) + 2(x - 2)

[tex]2x + 4 + 5x + 25 = 4x - 32 + 2x - 4 \\ \\ 7x + 29 = 6x - 36 \\ \\ 7x - 6x = - 36 - 29 \\ \\ x = - 65.[/tex]

2. 3x /4 - 7 /4 = 5x + 12

[tex] \frac{3x}{4} - \frac{7}{4} = 5x + 12 \\ \\ \frac{3x}{4} - 5x = 12 + \frac{7}{4} \\ \\ \frac{3x - 20x}{4} = \frac{48 + 7}{4} \\ \\ \frac{ - 17x}{4} = \frac{55}{4} [/tex]

cancel 4 from both sides

[tex] - 17x = 55 \\ \\ x = \frac{ - 17}{55} .[/tex]

3. x +7 - 8x/3 = 17/6 - 5x/8

[tex]x + 7 - \frac{8x}{3} = \frac{17}{6} - \frac{5x}{8} [/tex]

put x = 4

[tex]4 + 7 - \frac{ 8\times 4}{3} = \frac{17}{6} - \frac{5 \times 4}{8} \\ \\ 11 - \frac{32}{3} = \frac{17}{6} - \frac{20}{8} \\ \\ \frac{33 - 32}{3} = \frac{68 - 60}{24} \\ \\ \frac{1}{3} = \frac{8}{24} \\ \\ \frac{1}{3} = \frac{1}{3} .[/tex]

L.H.S. = R.H.S.

4. Let 3 consecutive integers : x , x+1 , x+2

As per the question : 2x + 3(x+1) + 4(x+2) = 56

9x + 11 = 56

Transpose 11 to RHS

9x = 45

Divide both sides by 9

x = 5 ,

x + 1 = 5 + 1 = 6

x + 2 = 5 + 2 = 7

Numbers are 5 , 6 and 7 .

5. Let the age of Jane’s younger sister is x.

Age of Jane will be x + 6

As per the question, after 10 years the sum of their ages will be 50.

After 10 years,

age of Jane = x + 16

age of her younger sister = x + 10

Therefore,

x + 16 + x +10 = 50

2x + 26 = 50

2x = 24

x = 12

Thus, the present age of Jane’s younger sister is 12 years.

And of Jane’s is 12 + 6 = 18 years.

6. Let the breadth of rectangular swimming pool be x metres.

Then, its length = (2x + 2) metres.

We know that the Perimeter of a rectangle

= 2(Length + Breadth)

= 2(2x + 2 + x) = 6x + 4

According to the given condition, we have

6x + 4 = 154

6x = 154 − 4

6x = 150

[Dividing both sides by 6]

x = 25

Thus, breadth = 25 m and

length = 25 × 2 + 2 = 52 m .

7. Let the digit in ten's .

Place be x and the digit in the one's place be y.

x − y = 5 ⟶ (i)

Two digit number = 10x + y

Two digit after reversing the digits = 10y + x

According to question ,

10x + y + 10y + x = 99

11x + 11y = 99

x + y = 9 ⟶ (ii)

On adding (i) and (ii),

2x = 14

x = 7

Putting the value of x in equation (i)

x − y = 5

y = 2

Number = 10x + y

=72 .

8. Let the speed of the steamer in still water be x km/h.

Then , the speed downstream = (x+2) km/h

and the speed upstream = (x−2) km/h

Given , distance covered in 4 hours downstream = distance covered in 5 hours upstream

4(x + 2) = 5(x − 2)

4x + 8 = 5x − 10

4x − 5x = − 10 − 8

[Transposing 5x to LHS and 8 to RHS]

−x = −18 or x = 18 km/h .

9. Let the number of notes of different denomination be x.

∴ Numbers of Rs 100 notes , 50 notes and Rs 10 notes will be 2x , 3x and 5x respectively.

Amount of 100 Rs notes ⇒Rs 100 × 2x = 200x

Amount of 50 Rs notes ⇒Rs 50 × 3x = 150x

Amount of 10 Rs notes ⇒Rs 10 × 5x = 50x

As per the question

Total amount = 400000

200x + 150x + 50x = 400000

400x = 400000 , x = 1000

No of Rs 100 notes = 2x = 2 × 1000 = 2000

No of Rs 50 notes = 3x = 3 × 1000 = 3000

No of Rs 10 notes = 5x = 5 × 1000 = 5000 .

10. Let the age of the man be x

Then age of his son becomes (x − 24)

2 years later from now,

Age of man will be = x + 2

and age of his son will be = (x − 24 + 2) = x − 22

According to question,

2(x − 22) = x + 2

i.e., 2x − 44 = x + 2

i.e., x = 46

Therefore ,

Present age of man = 46 years

And present age of his son = 46 − 24 = 22 years .

[tex]\huge\underline\red{Answer -}[/tex]

[tex]\bold{8 \frac{2}{5} }\: \\\\ \implies \: \frac{5 × 8 + 2}{5} \: \\ \\ \implies \: \frac{ 40 + 2}{5} \\\\ \implies \frac{42}{5} \\\\ \rightarrow \:\boxed {reciprocal \: = \frac{5}{42} } \\ \\[/tex]

hope helpful ~

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{8 \dfrac{2}{5}}\\\\\mathsf{= \dfrac{8\times5+2}{5}}\\\\\mathsf{= \dfrac{40 + 2}{5}}\\\\\mathsf{= \dfrac{42}{5}}\\\\\mathsf{=\dfrac{5}{42}}\\\\\huge\text{Therefore, the answer should be: \boxed{\mathsf{\dfrac{5}{42}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

y - 5 = -2(x + 3)

Step-by-step explanation:

When you write an equation in point-slope form, you only need two things: a point and a slope.

Given:

point: (-3, 5)

slope (m): -2

The standard point-slope equation is

y - y₁ = m(x - x₁)

Plug in what you know.

y - (5) = -2(x - (-3))

Simplify.

y - 5 = -2(x + 3)

This is your equation.

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Answer:

yes

Step-by-step explanation:

because bank

Answer:

f'(x) = 7x^4 (5 ln(x) + 1) + x^2

Explanation:

[tex]\sf Let \ f(x)=7x^5 ln(x) + \dfrac{1}{3} x^3[/tex]

Properties used while differentiating:

[tex]i) \quad \sf \dfrac{d}{dx} (ln(x)) = \dfrac{1}{x}[/tex]

[tex]ii) \quad \sf \dfrac{d}{dx} (x^n) = n(x)^{n-1}[/tex]

[tex]iii) \quad \sf \dfrac{d}{dx}(uv)=u \dfrac{dv}{dx}+v \dfrac{du}{dx}[/tex]

Begin solving:

f'(x) =

[tex]\Longrightarrow \sf \dfrac{d}{dx}\:\left(7x^5\:ln\left(x\right)\:+\:\dfrac{1}{3}\:\:x^3\right)[/tex]

[tex]\Longrightarrow \sf \dfrac{d}{dx}\:\left(7x^5\:ln\left(x\right)\right) + \dfrac{d}{dx}\left(\dfrac{1}{3}x^3\right)[/tex]

[tex]\Longrightarrow \sf \dfrac{d}{dx}(7x^5)\:\ \times ln\left(x\right) + \dfrac{d}{dx}(ln(x)) \times \ 7x^5 + \left(3\:\times \dfrac{1}{3}x^{3-1}\right)[/tex]

[tex]\Longrightarrow \sf 5(7x^{5-1})\:\times\ ln(x) + \dfrac{1}{x} \:\times\ 7x^5 \ + x^2[/tex]

[tex]\Longrightarrow \sf 35x^{4} ln(x) + \ 7x^4 \ + x^2[/tex]

[tex]\Longrightarrow \sf 7x^4(5 ln(x) + 1) \ + x^2[/tex]

Answer: [tex]x=5\sqrt{3}[/tex]

Step-by-step explanation:

As the triangle is equilateral, we know that all sides have a length of 10. Thus, if we consider either of the right triangles, we know they have legs of lengths 5 and x (since an altitude of an equilateral triangle bisects the side it is drawn to), and a hypotenuse of 10.

Thus, by the Pythagorean theorem,

[tex]5^{2}+x^{2}=10^{2}\\\\25+x^{2}=100\\\\x^{2}=75\\\\\boxed{x=5\sqrt{3}}[/tex]

The ordering-quantity that should be recommended will be 117 units.

The following can be deduced from the information given:

Demand = 679

Ordering cost = 7

Holding cost = 10%

Ordering quantity will be:

= ✓(2 × Demand × Ordering cost / Holding cost)

= ✓(2 × 679 × 7/0.1)

= ✓13580

= 116.53

= 117

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(a) [tex]\frac{6-8}{-4-4}=\frac{-2}{-8}=\boxed{1/4}[/tex]

(b) Using the point (4,8), we get [tex]\boxed{y-8=\frac{1}{4}(x-4)}[/tex]

(c) Rearranging into slope-intercept form,

[tex]y-8=\frac{1}{4}(x-4)\\\\y-8=\frac{1}{4}x-1\\\\\boxed{y=\frac{1}{4}x+7}[/tex]

Answer:  A B C

Step-by-step explanation:

A whole number is like 1,500 and a nonwhole number is like 33.2 or like 55/100.  

And have a good day.

The correct statement compares the means of the data in the dot plots is option C; the mode is greater for Mrs. Ramos’s class.

Median represents the middle value of the given data when arranged in a particular order.

Mode is that number that appears most frequently in the given set of data.

Given;

The Number of pets in Mr. McIntyre’s class ;

0,0,0,0,0,1, 1, 1, 1, 1, 4, 4, 4, 4, 1,

Median = 1

Mode = 0 and 1

The Number of pets in Mrs. Ramos’s Class;

0, 1, 1, 2, 2, 3, 3, 3, 3, 4, 4, 4, 3, 3, 3

Median = 3

Mode = 4 and 5

Hence, C; The mode is greater for Mrs. Ramos’s class.

The remaining part of the question is

"Which statement correctly compares the measures of center of the data in the dot plots?

The median is greater for Mr. McIntyre’s class.

The median is the same for both classes.

The mode is greater for Mrs. Ramos’s class.

The mode is the same for both classes."

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Answer:

C = 2√(πA) units

Step-by-step explanation:

If m VB = 60°  and m BS = 30°, then m ∠3 =15°.

A tangent is a line passing by touching the perimeter of the circle, perpendicular to the line joining the center and touch point.

Given, PB tangents PV, PU secants

If m VB = 60°  and m BS = 30°, then m ∠3 =

The measurement of the external angles is the semi difference of the arcs it consists.

∠3 = 1/2 (60 - 30)

∠3 = 15°

Thus, If m VB = 60°  and m BS = 30°, then m ∠3 =15°.

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Answer:

So, the answer is 20

Step-by-step explanation:

[tex]f(x) = \frac{1}{2} x + 10 = = = > \\ f(x) - 10 = \frac{1}{2} x = = = > \\ 2f(x) - 20 = x = = = > \\ {f}^{ - 1} (y) = 2y - 20 = = = > {f}^{ - 1} (x) = 2x - 20[/tex]

The missing value of the inverse function is 20.

Option D is the correct answer.

A function has an input and an output.

A function can be one-to-one or onto-one.

It simply indicated the relationships between the input and the output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

To find the inverse of a function, we usually replace f(x) with y, then solve for x in terms of y, and finally replace y with the inverse function notation h(x).

So let's do that with the given function:

f(x) = (1/2)x + 10

y = (1/2)x + 10

2y = x + 20 (multiply both sides by 2 to isolate x)

x = 2y - 20 (subtract 20 from both sides)

Now we can replace x with h(x) and y with x to get the inverse function:

h(x) = 2x - 20

Thus,

The missing value is 20.

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Using the Empirical Rule, it is found that:

It states that, for a normally distributed random variable:

Considering the mean of 88% and the standard deviation of 4%, the scores that are within 2 standard deviations of the mean are:

68% are within 1 standard deviation of the mean, hence, out of 100:

0.68 x 100% = 68 scores.

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Answer:

5,208,469

Step-by-step explanation:

5,000,000 + 200,000+ 8,000 + 400+60+9

5,000,000

  200,000

    00,000

       8,000

          400

            60

              9

5,208,469

Answer: 10

Step-by-step explanation:

[tex]\frac{5}{x+5} (2x-5(2))\\\frac{5}{x+5} (2x-10)\\\frac{10x-50}{x+5}\\\frac{10(x+5)}{x+5} \\\frac{10}{1} \\10[/tex]

Answer:

43

Step-by-step explanation:

because if you add it up thats how you get that

Answer:

3x* 2x^2 +3x*5 -2 * 2x^2  -2 *5

Step-by-step explanation:

(3x-2)(2x^2+5)

We can FOIL to find the expansion

First 3x* 2x^2 = 6x^3

Outer 3x*5 = 15x

Inner -2 * 2x^2 = -4x^2

Last -2 *5 = -10

Add all the terms together

3x* 2x^2 +3x*5 -2 * 2x^2  -2 *5

Answer:

3x • 2x^2 + 3x • 5 + (–2) • 2x^2 + (–2) • 5

Step-by-step explanation:

other answer was right

Answer: 8

Step-by-step explanation:

As corresponding sides of similar triangles are proportional,

[tex]\frac{RX}{RB}=\frac{XE}{BO}\\\\\frac{6}{15}=\frac{a}{20}\\\\a=20\left(\frac{6}{15} \right)=\boxed{8}[/tex]

Answer:

80 students are female

Step-by-step explanation:

21 are male meaning 19 are female

9 are female in French

12 are female in Spanish

total = 40

2x + 40 = 120

2x = 80

x = 40

females'  = 80

total = 80