yes the answer is( true).
Answer:
The answer is (True)
Step-by-step explanation:
7 days 8 hours 20 minutes
- 4 days 10 hours 30 minutes
F 2 days 21 hours
50 minutes
G 3 days 2 hours
10 minutes
H 7 days 8 hours
20 minutes
J 11 days 8 hours
50 minutes
K none of these
The height of a ball above the ground as a function of time is given by the function h(t)= -32t^2+8t+3 where h is the height of the ball in feet and t is the time in seconds. When is the ball at a maximum height
Answer:
The ball is at a maximum height when t = 0.125s.
Step-by-step explanation:
Vertex of a quadratic function:
Suppose we have a quadratic function in the following format:
[tex]f(x) = ax^{2} + bx + c[/tex]
It's vertex is the point [tex](x_{v}, f(x_{v})[/tex]
In which
[tex]x_{v} = -\frac{b}{2a}[/tex]
If a<0, the vertex is a maximum point, that is, the maximum value happens at [tex]x_{v}[/tex], and it's value is [tex]f(x_{v})[/tex]
In this question:
[tex]h(t) = -32t^{2} + 8t + 3[/tex]
So [tex]a = -32, b = 8[/tex]
When is the ball at a maximum height
[tex]t_{v} = -\frac{8}{2*(-32)} = 0.125[/tex]
The ball is at a maximum height when t = 0.125s.
From 1985 to 2003, the total attendance A (in thousands) at NCAA women’s basketball games can be modeled by =−1.95^3 +70.1x^2 −188+2150 where x is the number of years since 1985.
a. What is the initial value of this function (the attendance in 1985)?
b. Find the attendance for the year 1998.
Answer:
21507269Step-by-step explanation:
We assume your intended attendance equation is ...
A = -1.95x^3 +70.1x^2 -188x +2150
a. For x=0 (corresponding to 1985), the first three terms are 0, so we have ...
A = 2150 . . . . the initial value of the function
__
b. For x=13 (corresponding to 1985) we have ...
A = ((-1.95(13) +70.1)(13) -188)(13) +2150 = (44.75(13) -188)(13) +2150
= 393.75(13) +2150 = 7268.75
Attendance in the year 1998 is modeled to be about 7269.
Marts is solving the equation S=2nrh+2nr2 for h. Which should be the result?
Step-by-step explanation:
Hope you understand this
Solve for x: -3x-3=-3(x+1)
Answer:
x= -6 broo
Step-by-step explanation:
What’s the correct answer for this?
Answer:
x = 7
Step-by-step explanation:
<ACF = 90° (since AB is the diameter and it is perpendicular to EF)
But <ACF = 2(7x-4)
So
2(7x-4) = 90
14x-8 = 90
14x = 90+8
14x = 98
Dividing both sides by 14
x = 7
Solve the following quadratic equation using the quadratic formula. Separate multiple answers with a comma if necessary.
[tex]−yx^{2} +4y−6=0[/tex]
Answer:
[tex] y^2 -4y +6=0[/tex]
[tex] y =\frac{-b \pm \sqrt{b^2 -4ac}}{2a}[/tex]
Where [tex] a = 1, b= -4 ,c =6[/tex]
And replacing we got:
[tex] y = \frac{-(-4) \pm \sqrt{4^2 -4(1)(6)}}{2*1}[/tex]
And solving we got:
[tex] y = \frac{4 \pm \sqrt{-8}}{2} =2 \pm 2\sqrt{2} i[/tex]
Where [tex] i =\sqrt{-1}[/tex]
And the possible solutions are:
[tex] y_1=2 + 2\sqrt{2} i , y_2 = 2 - 2\sqrt{2} i [/tex]
Step-by-step explanation:
For this case we use the equation given by the image and we have:
[tex] -y^2 +4y -6=0[/tex]
We can rewrite the last expression like this if we multiply both sides of the equation by -1.
[tex] y^2 -4y +6=0[/tex]
Now we can use the quadratic formula given by:
[tex] y =\frac{-b \pm \sqrt{b^2 -4ac}}{2a}[/tex]
Where [tex] a = 1, b= -4 ,c =6[/tex]
And replacing we got:
[tex] y = \frac{-(-4) \pm \sqrt{4^2 -4(1)(6)}}{2*1}[/tex]
And solving we got:
[tex] y = \frac{4 \pm \sqrt{-8}}{2} =2 \pm 2\sqrt{2} i[/tex]
Where [tex] i =\sqrt{-1}[/tex]
And the possible solutions are:
[tex] y_1=2 + 2\sqrt{2} i , y_2 = 2 - 2\sqrt{2} i [/tex]
HELP ASAP PLS! A random number generator is used to create a real number between 0 and 1, equally likely to fall anywhere in this interval of values. (For the instance, 0.3794259832... is a possible outcome). a. Sketch a curve of the probability distribution of this random variable, which is the continuous version of the uniform distribution. b. What is the mean of this probability distribution?
Answer:
a. Attached.
b. Mean = 0.5
Step-by-step explanation:
This random number generator con be modeled with an uniform continous random variable X that has values within 0 and 1, each with the same constant probability within this range.
The probability for the values within the interval [a,b] in a continous uniform distribution can be calculated as:
[tex]f(x)=\dfrac{1}{b-a}\;\;\;x\in[0; 1][/tex]
In this case, b=1 and a=0, so f(x)=1.
The sketched curve of the probability distribution of this random variable is attached.
The mean of this distribution can be calculated as the mean for any uniform distribution:
[tex]E(X)=\dfrac{a+b}{2}=\dfrac{0+1}{2}=0.5[/tex]
A card is chosen from a standard deck of cards. The drawer is looking for clubs and face cards.
Club not a club
Face card 3 9
Not a face card 10 13
Find P(Club | Not a Face Card).
Question 13 options:
52/13
3/13
1/4
10/13
Answer:
[tex](C)\dfrac{1}{4}[/tex]
Step-by-step explanation:
In a standard deck,
Total Number of cards=52Number of face cards=12Number of Clubs =13The table below gives the distribution of the cards.
[tex]\left|\begin{array}{c|c|c|c}&$Club&$Not a club\\----&----&---&----\\$Face card&3&9&12\\$Not a face card&10&30&40\\----&----&---&----\\$Total&13&39&52\end{array}\right|[/tex]
[tex]P($Club$ | $Not a Face Card)$=\dfrac{10}{40}\\ =\dfrac{1}{4}[/tex]
The correct option is C.
The length of time for one individual to be served at a cafeteria is an exponential random variable with mean of 6 minutes. Assume a person has waited for at least 4 minutes to be served. What is the probability that the person will need to wait at least 9 minutes total
Answer:
43.46% probability that the person will need to wait at least 9 minutes total
Step-by-step explanation:
To solve this question, we need to understand conditional probability and the exponential distribution.
Conditional probability:
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
Expontial distribution:
The exponential probability distribution, with mean m, is described by the following equation:
[tex]f(x) = \mu e^{-\mu x}[/tex]
In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.
The probability that x is lower or equal to a is given by:
[tex]P(X \leq x) = \int\limits^a_0 {f(x)} \, dx[/tex]
Which has the following solution:
[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]
The probability of finding a value higher than x is:
[tex]P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}[/tex]
In this question:
Event A: Waited at least 4 minutes.
Event B: Waiting at least 9 minutes.
The length of time for one individual to be served at a cafeteria is an exponential random variable with mean of 6 minutes.
This means that [tex]m = 6, \mu = \frac{1}{6}[/tex]
Probability of waiting at least 4 minutes.
[tex]P(A) = P(X \geq 4) = P(X > 4)[/tex]
[tex]P(A) = P(X > 4) = e^{-\frac{4}{6}} = 0.5134[/tex]
Intersection:
The intersection between a waiting time of at least 4 minutes and a waiting time of at list 9 minutes is a waiting time of 9 minutes. So
[tex]P(A \cap B) = P(X > 9) = e^{-\frac{9}{6}} = 0.2231[/tex]
What is the probability that the person will need to wait at least 9 minutes total
[tex]P(B|A) = \frac{0.2231}{0.5134} = 0.4346[/tex]
43.46% probability that the person will need to wait at least 9 minutes total
Please someone help me !
Step-by-step explanation:
a. If x is the total numbers of students in school, 35%x = 140.
0.35x = 140
x = 140/0.35 = 400
b. Since there are 400 kids in the school, 15% of them take the bus which is 0.15 * 400 = 60 kids.
A Lake Tahoe Community College instructor is interested in the average number of days Lake Tahoe Community College math students are absent from class during a quarter that lasts 9 weeks. What is the population she is interested in
Answer:
All Lake Tahoe Community College math students
Step-by-step explanation:
From the question itself it is clear that the instructor is interested in the average number of days Lake Tahoe Community College math students are absent from class during a quarter that lasts 9 weeks, which clearly indicates that the teacher is interested in population of all Lake Tahoe Community College math students.
The time, T (seconds) it takes for a pot of water to boil is inversely proportional to the cooker setting, H , applied to the pot. When H = 7 , T = 150 . What must the cooker setting be if it takes 7 minutes to boil the water?
Answer:
150
Step-by-step explanation:
Given the following parameters;
Time, T = 150mins
Cooker setting, H = 7
Since the time for a pot of water to boil is inversely proportional to the cooker setting;
[tex]T * 1/H[/tex]
[tex]T = K/H[/tex] ........equation 1
Where, K is the constant of proportionality.
Substituting the parameters into the equation 1, we have;
150 = K/7
K = 150*7
K = 1050
To find the cooker setting at 7mins;
[tex]T = K/H[/tex]
H = K/T
H = 1050 ÷ 7
H = 150.
Hence, the cooker setting must be at 150.
These box plots show daily low temperatures for a sample of days in two different towns.
Town A. 10,15,20,30, and 55
Town B. 5,20,30,40, and 55
*The question is incomplete. Attached below is the diagram of the box plots being referred to followed by the complete question and options.
Answer:
D. The median for town A, 20 degrees, is less than the median of town B, 30 degrees
Step-by-step Explanation:
From the given diagram of the box plots showing the daily low temperatures for town A and B, the median of town A and B is shown on the box plots by the line that divides the box. Therefore, the median of town A is where the line that divides the box is. Median for town A is 20⁰. Same applies for town B. Town B median is 30⁰.
Therefore, option D is the most appropriate comparison of the centers. Median of town A is less than median of town B.
In October 2012, Apple introduced a much smaller variant of the Apple iPad, known as the iPad Mini. Weighing less than 11 ounces, it was about 50% lighter than the standard iPad. Battery tests for the iPad Mini showed a mean life of 10.25 hours (The Wall Street Journal, October 31, 2012). Assume that battery life of the iPad Mini is uniformly distributed between 8.5 and 12 hours.
a. What is the probability that the battery life for an iPad Mini will be 10 hours or less (to 4 decimals)?b. What is the probability that the battery life for an iPad Mini will be at least 11 hours (to 4 decimals)?c. What is the probability that the battery life for an iPad Mini will be between 9.5 and 11.5 hours (to 4 decimals)?d. In a shipment of 100 iPad Minis, how many should have a battery life of at least 9 hours (to nearest whole value)?
Answer:
a) 0.4286 = 42.86% probability that the battery life for an iPad Mini will be 10 hours or less
b) 0.2857 = 28.57% probability that the battery life for an iPad Mini will be at least 11 hours
c) 0.5714 = 57.14% probability that the battery life for an iPad Mini will be between 9.5 and 11.5 hours
d) 86 should have a battery life of at least 9 hours.
Step-by-step explanation:
An uniform probability is a case of probability in which each outcome is equally as likely.
For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.
The probability that we find a value X lower than x is given by the following formula.
[tex]P(X \leq x) = \frac{x - a}{b-a}[/tex]
The probability of being higher than x is:
[tex]P(X > x) = \frac{b - x}{b-a}[/tex]
The probability of being between c and d is:
[tex]P(c \leq X \leq d) = \frac{d-c}{b-a}[/tex]
Assume that battery life of the iPad Mini is uniformly distributed between 8.5 and 12 hours.
This means that [tex]a = 8.5, b = 12[/tex]
a. What is the probability that the battery life for an iPad Mini will be 10 hours or less (to 4 decimals)?
[tex]P(X \leq x) = \frac{x - a}{b-a}[/tex]
[tex]P(X \leq 10) = \frac{10 - 8.5}{12 - 8.5} = 0.4286[/tex]
0.4286 = 42.86% probability that the battery life for an iPad Mini will be 10 hours or less.
b. What is the probability that the battery life for an iPad Mini will be at least 11 hours (to 4 decimals)?
[tex]P(X > x) = \frac{b - x}{b-a}[/tex]
[tex]P(X > 11) = \frac{12 - 11}{12 - 8.5} = 0.2857[/tex]
0.2857 = 28.57% probability that the battery life for an iPad Mini will be at least 11 hours
c. What is the probability that the battery life for an iPad Mini will be between 9.5 and 11.5 hours (to 4 decimals)?
[tex]P(c \leq X \leq d) = \frac{d-c}{b-a}[/tex]
[tex]P(9.5 \leq X \leq 11.5) = \frac{11.5 - 9.5}{12 - 8.5} = 0.5714[/tex]
0.5714 = 57.14% probability that the battery life for an iPad Mini will be between 9.5 and 11.5 hours.
d. In a shipment of 100 iPad Minis, how many should have a battery life of at least 9 hours (to nearest whole value)?
Proportion of iPad Minis with a battery life of at least 9 hours.
[tex]P(X > 11) = \frac{12 - 9}{12 - 8.5} = 0.8571[/tex]
Out of 100:
0.8571*100 = 85.71
To the nearest whole number
86 should have a battery life of at least 9 hours.
I need help not good at graphs
Answer:
a, b
Step-by-step explanation:
a and b cause all the data are not in a form of a line
Matthew can jog 3 and ⅖ miles in ⅞ of an hour. Find his average speed in miles per hour.
Answer:
3 [tex]\frac{31}{35}[/tex] mph ≈ 3.8857 mph
Step-by-step explanation:
Speed = distance/time
1) Plug the numbers in.
Speed = 3 ⅖ / ⅞
2) Convert the numbers to decimals.
Speed = 3.4 / 0.875
3) Solve.
Speed ≈ 3.8857 mph = [tex]\frac{136}{35}[/tex] mph = 3 [tex]\frac{31}{35}[/tex] mph
ANOTHER WAY TO SOLVE
Speed = distance/time
1) Plug the numbers in.
Speed = 3 ⅖ / ⅞
2) Convert into improper fractions
Speed = [tex]\frac{17}{5}[/tex] / [tex]\frac{7}{8}[/tex]
3) Multiply by the reciprocal
Speed = [tex]\frac{17}{5}[/tex] × [tex]\frac{8}{7}[/tex] = [tex]\frac{136}{35}[/tex] mph = 3 [tex]\frac{31}{35}[/tex] mph
A line passes through the point (3,-8) and has a slope of 3. Write an equation in point-slope form for this line.
Answer:
y+8 = 3(x-3)
Step-by-step explanation:
The point slope form of the equation for a line is
y-y1 = m(x-x1)
y- -8 = 3(x -3)
y+8 = 3(x-3)
Some parts of California are particularly earthquake-prone. Suppose that in one metropolitan area, 33% of all homeowners are insured against earthquake damage. Four homeowners are to be selected at random. Let X denote the number among the four who have earthquake insurance. A) Find the probability distribution of X.B) What is the most likely value for X?
C) What is the probability that at least two of the four selected have earthquake insurance?
Answer:
(a) The probability mass function of X is:
[tex]P(X=x)={4\choose x}\ (0.33)^{x}\ (1-0.33)^{4-x};\ x=0,1,2,3...[/tex]
(b) The most likely value for X is 1.32.
(c) The probability that at least two of the four selected have earthquake insurance is 0.4015.
Step-by-step explanation:
The random variable X is defined as the number among the four homeowners who have earthquake insurance.
The probability that a homeowner has earthquake insurance is, p = 0.33.
The random sample of homeowners selected is, n = 4.
The event of a homeowner having an earthquake insurance is independent of the other three homeowners.
(a)
All the statements above clearly indicate that the random variable X follows a Binomial distribution with parameters n = 4 and p = 0.33.
The probability mass function of X is:
[tex]P(X=x)={4\choose x}\ (0.33)^{x}\ (1-0.33)^{4-x};\ x=0,1,2,3...[/tex]
(b)
The most likely value of a random variable is the expected value.
The expected value of a Binomial random variable is:
[tex]E(X)=np[/tex]
Compute the expected value of X as follows:
[tex]E(X)=np[/tex]
[tex]=4\times 0.33\\=1.32[/tex]
Thus, the most likely value for X is 1.32.
(c)
Compute the probability that at least two of the four selected have earthquake insurance as follows:
P (X ≥ 2) = 1 - P (X < 2)
= 1 - P (X = 0) - P (X = 1)
[tex]=1-{4\choose 0}\ (0.33)^{0}\ (1-0.33)^{4-0}-{4\choose 1}\ (0.33)^{1}\ (1-0.33)^{4-1}\\\\=1-0.20151121-0.39700716\\\\=0.40148163\\\\\approx 0.4015[/tex]
Thus, the probability that at least two of the four selected have earthquake insurance is 0.4015.
The range of which function includes -4?
A y=-x-5
B y=√x+5
C y=√x+5
D y=-{X-5
Range of the given function y=-x-5 includes -4
What is function?
A relation between a collection of inputs and outputs is known as a function. A function is, to put it simply, a relationship between inputs in which each input is connected to precisely one output.
For the given function,
y = -x-5
Wen we put x = -1
we get y = -4
Also,
The range of this function is (-∞, ∞)
Hence,
The function y = -x-5 includes the -4.
To learn more about function visit:
https://brainly.com/question/8892191
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Which expression represents the composition [g o f o h](x) for the functions below?
f(x) = 5x – 4
g(x) = 5x3
h(x) = 3x
Answer: 16875x³-13500x²+3600x-320
Step-by-step explanation:
[gοfοh](x) means g(f(h(x))). So you plug in h(x) into f(x) and that into g(x).
f(3x)=5(3x)-4=15x-4
g(f(3x))=5(15x-4)³
g(f(3x))=5(3375x³-2700x²+720x-64)
g(f(3x))=16875x³-13500x²+3600x-320
Answer:
A
Step-by-step explanation:
Are these calculated correctly?
14. Was the perimeter calculated correctly?
Length = 4 yards Breadth = 1 *2/5 yards = 7/5 yardsWe know that,
Perimeter of rectangle = 2 ( l + b )
= 2 ( 4 + 7 / 5 )
= 2 ( 20 + 7 / 5 )
= 2 × 27/5
= 54 / 5
= 1 * 4/5
No ...
Calculate the derivative indicated.
dy
1
where
y=51
+ 4x2
dx2
x=6
73
Answer:
8 5/648
Step-by-step explanation:
y = 5x ^ -3 + 4x^2
dy /dx = 5 * -3 x^ -4 + 4 * 2x ^ 1
= -15 x ^ -4 + 8x
Now take the second derivative
dy^2/ dx^2 = -15 * -4 x^-5 +8
= 60 x^ -5 +8
= 60 /x^5 +8
Evaluate at x = 6
= 60 / 6^5 +8
60/7776 +8
5/648 + 8
8 5/648
A ball thrown into the air from a roof 15 feet above the ground with an initial vertical velocity of 30 ft/sec can be modeled by the equation: . How long will the ball be in the air? What is it’s maximum height?
Answer:
Total time of flight= 6.3 s
Total Max height= 60.87ft
Step-by-step explanation:
Height above ground = 15ft
Velocity=30ft/sec
Angle = 90°
Max height traveled= U²Sin²tita/2g
Max height traveled= ( 30²*1²)/(2*9.81)
Max height traveled= 900/19.62
Max height traveled= 45.87 ft
Total Max height= 15+45.87= 60.87ft
Time travel to Max height
=( usin90)/g
Time travel to initial position
= (30*sin90)/9.81
= 3.1 s
Time to travel to the ground from Max height
H = 1/2gt²
60.87= 1/2 * 9.81*t²
(60.87*2)/9.81= t²
3.5 = t
Total time of flight = 3.5+3.1
Total time of flight= 6.3 s
These two figures are the image and pre-image of a
dilation.
Find the value of x.
4 m
6 m
8 m
9 m
Answer:
D.) 9m
Step-by-step explanation:
Answer:
its d
Step-by-step explanation:
i just did the question
What’s the correct answer for this?
Answer:
1/2
Step-by-step explanation:
The formula that relates two independent events is provided as below:
P(A) x P(B) = P(A⋂B)
=> P(A) x (1/3) = 1/6
=> P(A) = (1/6) x 3
=> P(A) = 3/6 = 1/2
=> Option D is correct
Hope this helps!
Triangles R S T and V U T are connected at point T. Angles R S T and V U T are right angles. The length of side R S is 12 and the length of side S T is 16. The length of side T U is 8 and the length of U V is 6. Which statements can be concluded from the diagram and used to prove that the triangles are similar by the SAS similarity theorem? StartFraction R S Over V U EndFraction = StartFraction S T Over U T EndFraction and angle S is-congruent-to angle U StartFraction R S Over V U EndFraction = StartFraction S T Over U T EndFraction = StartFraction R T Over V T EndFraction StartFraction R S Over V U EndFraction = StartFraction T U Over T S EndFraction and angle S is-congruent-to angle U StartFraction R S Over V U EndFraction = StartFraction T U Over T S EndFraction = StartFraction R T Over V T EndFraction
Answer:
StartFraction R S Over V U EndFraction = StartFraction S T Over U T EndFraction and angle S is-congruent-to angle U
Step-by-step explanation:
The expression below means RS/VU = ST/UT
See the attachment for better explanation.
Answer:
A
Step-by-step explanation:
I took the test
Classify the triangle based on its angles and sides
Answer:
Options (c) and (f)
Step-by-step explanation:
In the given triangle,
Measure of one angle is 90°.
Therefore, it's a right angle triangle.
Since two angles of the given triangle are equal, opposite sides of this triangle will be equal.
Therefore, the given right triangle is an isosceles triangle.
Options (c) and (f) will be the answer.
Express as a ratio: the speed of 1 km/min to
the speed of 10 m/s.
Answer:
10 : 6
Step-by-step explanation:
1km / min = 1000m / 60 sec = 100/6 m/s
Ratio :
100/6 : 10
10/6 : 1
10 : 6
An athlete eats 85 grams of protein per day while training. How much is this in milligrams ?