A student must determine the relationship between the inertial mass of an object, the net force exerted on the object, and the object’s acceleration. The student uses the following procedure. The object is known to have an inertial mass of 1.0kg .
Step 1: Place the object on a horizontal surface such that frictional forces can be considered to be negligible.
Step 2: Attach a force probe to the object.
Step 3: Hang a motion detector above the object so that the front of the motion detector is pointed toward the object and is perpendicular to the direction that the object can travel along the surface.
Step 4: Use the force probe to pull the object across the horizontal surface with a constant force as the force probe measures force exerted on the object. At the same time, use the motion detector to record the velocity of the object as a function of time.
Step 5: Repeat the experiment so that the object is pulled with a different constant force.
Can the student determine the relationship using this experimental procedure?
Answer choices:
A) Yes, because Newton’s second law of motion must be used to determine the acceleration of the object.
B) Yes, because the net force exerted on the object and its change in velocity per unit of time are measured.
C) No, because the motion detector should be oriented so that the object moves parallel to the line along which the front of the motion detector is aimed.
D) No, because knowing the net force exerted on the object and its change in velocity per unit of time is not sufficient to determine the relationship.
Answers
Answer:
C
Explanation:
In order to obtain data about the object’s velocity as a function of time, the object must move either toward or away from the motion detector.
The student cannot determine the relationship using this experiment ; ( C ) Because the motion detector should be oriented so that the object moves parallel to the line along which the front of the motion detector is aimed
Given that the aim of the experiment is to determine the relationship between mass of inertia of object, net force exerted and acceleration of the object we have to first obtain the object's velocity (i.e. Distance travelled by object / time ). and
To obtain velocity of object with respect to time, the object must move in either direction ( back or front ) from its parallel position away from the position of the detector ( motion )
Hence we can conclude that The student cannot determine the relationship using this experimental procedures.Because the motion detector should be oriented so that the object moves parallel to the line along which the front of the motion detector is aimed
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Related Questions
A small box with mass 0.600 kg is placed against a compressed spring at the bottom of an incline that slopes upward at 37.0∘ above the horizontal. The other end of the spring is attached to a wall. The coefficient of kinetic friction between the box and the surface of the incline is μk=0.400. The spring is released and the box travels up the incline, leaving the spring behind.
What minimum elastic potential energy must be stored initially in the spring if the box is to travel 2.00 m from its initial position to the top of the incline?
Answers
Answer:
[tex]10.845\ \text{J}[/tex]
Explanation:
m = Mass of box = 0.6 kg
[tex]\theta[/tex] = Angle of incline = [tex]37^{\circ}[/tex]
[tex]\mu_k[/tex] = Coefficient of kinetic friction = 0.4
l = Distance the box travels = 2 m
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
The potential energy in the spring is given by
[tex]U=mgl\sin\theta+mg\mu_k\cos\theta l\\\Rightarrow U=mgl(\sin\theta+\mu_k\cos\theta)\\\Rightarrow U=0.6\times 9.81\times 2\times(\sin37^{\circ}+0.4\times\cos37^{\circ})\\\Rightarrow U=10.845\ \text{J}[/tex]
The minimum elastic potential energy required is [tex]10.845\ \text{J}[/tex].
The earth has a mass of, MEarth=6.4 X 1024 kg and a radius of REarth= 6.0 X 106meter and it has acceleration due to gravity, gE = 9.8 . One of Jupiter’s moon also has MJmoon = ½ * MEarth =3.2 x 1024 kg with a radius of, RJmoon = ½ * REarth =3.0 x 106 m and gJmoon value unknown. From the information, what is acceleration due to gravity of Jupiter’s moon, gjmoon, comparing to the earth’s acceleration due to gravity, gEarth?
Answers
Answer:
gjmoon = 19.6 m/s2
Explanation:
Applying the Universal Law of Gravitation, the force exerted by the Earth on a mass m, can be written as follows:[tex]F_{gE} = m* \frac{G*M_{E} }{R_{E} ^{2} } = m*g_{E}[/tex]
In the same way, the force due to gravity of Jupiter's moon, can be written as follows:[tex]F_{gjmoon} = m* \frac{G*M_{Jmoon} }{R_{Jmoon} ^{2} } = m*g_{jmoon} (1)[/tex]
Now, we know the following:[tex]M_{Jmoon} = \frac{M_{E} }{2} (2)[/tex]
[tex]R_{Jmoon} = \frac{R_{E} }{2} (3)[/tex]
Replacing (2) and (3) in (1), we get:[tex]F_{gjmoon} = m* \frac{G*M_{E} }{2*\frac{R_{E} ^{2}}{4} } = m*g_{jmoon} (1) = m* 2* \frac{G*M_{E} }{R_{E} ^{2}} = 2* m*g_{E}[/tex]
⇒ [tex]g_{jmoon} = 2* g_{E}[/tex]
gjmoon = 19.6 m/s2 (in magnitude).
What is the net work, in joules, required to stop a crate of mass 64.5 kg that is moving at a speed of 1.26 m/s
Answers
Answer:
51.2Joules
Explanation:
Work done = Force × distance
Force = mg = 64.5×9.81
Force = 632.745N
Next is to get the distance using the equation of motion
v² = u²+2gS
1.26² = 0+2(9.81)S
1.5876 = 19.62S
S = 1.5876/19.62
S = 0.0809m
Get the work done:
Work done = F×S
Work done = 632.745×0.0809
Work done = 51.2Joules
Hence the net work done in Joules is 51.2Joules
The net work done required to stop a crate will be "51.2 Joules".
Force and MassAccording to the question,
Mass, m = 64.5 kg
Speed, v = 1.26 m/s
Acceleration due to gravity, g = 9.8
We know,
The force, F = mg
By substituting the values,
= 64.5 × 9.8
= 632.745 N
By using Equation of motion,
→ v² = u² + 2gS
(1.26)² = 0 + 2(9.81) S
1.5876 = 19.62 S
S = [tex]\frac{1.5876}{19.62}[/tex]
= 0.0809 m
hence,
The work done (W) will be:
= F × S
= 632.745 × 0.0809
= 51.2 Joules
Thus the above response above is correct.
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Find the distance along an arc on the surface of the earth that subtends a central angle of 1 minutes (1 minute = 1/60 degree). The radius of the earth is 3960 miles. Round to the thousandths. (3 decimal places)
Answers
Answer:
1.152 miles
Explanation:
Given: central angle = 1 minute = [tex](\frac{1}{60}) ^{o}[/tex]
radius of the earth = 3960 miles
The length of an arc = [tex]\frac{\alpha }{360^{o} }[/tex] 2[tex]\pi[/tex]r
where: [tex]\alpha[/tex] is the central angle, and r is the radius.
Thus,
Distance along the arc = [tex]\frac{\alpha }{360^{o} }[/tex] 2[tex]\pi[/tex]r
Distance along the arc = [tex]\frac{(\frac{1}{60}) ^{o} }{360^{o} }[/tex] x 2 x [tex]\frac{22}{7}[/tex] x 3960
= [tex]\frac{(\frac{1}{60}) ^{o} }{360^{o} }[/tex] x 24891.4286
= 1.1524
The required distance along an arc is 1.152 miles.
An ion has unequal numbers of which two particles?
Answers
A small child weighs 60 N. If mommy left him sitting on top of the stairs, which are 12 m high, how much energy does the child have!
Please help ASAP
Answers
Answer:
6000 joules
Explanation:
I jus learned dis
Answer:6000j
Explanation:
Hope that helps
The latent heat of fusion of mercury is 11.8 J/g. The amount of energy, rounded to the nearest tenth, needed to change 8.00 grams of mercury to a liquid is
Answers
Answer:
94.4
Explanation:
it is
Answer:
94.4 i took the test and got it right :)
hope that helps
You and some friends visit the Florida State Fair and decide to play a game. To play the game you must slide a metal hockey-type puck up a wooden ramp so that it drops through a hole at the top of the ramp. Your prize, if you win, is a large, stuffed gorilla. You realize the secret to winning is giving the puck just enough velocity at the bottom of the ramp to make it to the hole. You estimate the distance from the bottom of the ramp to the hole at about 3 m, and the ramp appears to be inclined with an angle of 10o from the horizontal. You just got out of physics class and recall the coefficient of static friction between steel and wood is 0.1 and the coefficient of kinetic friction between steel and wood is 0.08. The mass of the puck is about 1 kg. You decide to impress your friends by sliding the puck at the precise speed on the first try so as to land it in the hole. You slide the puck at 2.0 m/sec. Do you win the stuffed poodle? Let g = 10 m/s2. Note: A slightly too hard throw will win since your aim is so good the puck would drop in the hole.
Answers
Answer:
No you didn't win the stuffed poodle
Explanation:
From the question we are told that
The distance of the ramp to the hole is d = 3 m \
The angle of inclination is [tex]\theta = 10^o[/tex]
The coefficient of static friction is [tex]\mu_s = 0.1[/tex]
The coefficient of kinetic friction is [tex]\mu_k = 0.08[/tex]
The mass of the puck is m = 1 kg
The velocity of the first slide is [tex]v_1 = 2.0 m/s[/tex]
Generally the kinetic energy at the bottom of the ramp is equal the energy loss due to friction and this can be mathematically represented as
[tex]\frac{1}{2} m * v^ 2 = \mu_k * [m * g] * cos (theta ) * d[/tex]
=> [tex]\frac{1}{2} * v^ 2 = 0.08 * 9.8 * cos (10 ) * 3[/tex]
=> [tex] v= 2.17 \ m/s [/tex]
Comparing the relative velocity obtained and the velocity of your first throw we can see that you didn't win the stuffed animal
Which simple machines are used in the tool or device
Answers
Answer:
Explanation:
What are simple machines?
Simple machines reduce effort or extend the ability to perform tasks beyond their abilities.
Why do we use simple machines?
Simple machines are used widely as they help humans and save time.
Simple Machine Examples:
MachineScrewWheel and axle - wheeled carry-on luggageLever - see sawPulley - flag polesInclined planeWedge - knifeWhich property of a substance can be determined using a pH indicator.
Answers
Answer:
Acidity
Explanation:
A pH indicator measures how acidic or basic a substance is.
Hope this helped :)
Suppose you are given two clay balls of equal size and shape. The two clay balls also weigh the same. One ball is flattened into a pancake-shaped piece. Which of these statements is correct and why?
Answers
A squirrel drops an acorn from a tree. Starting from rest, it reaches the ground 22.0 meters
below. What is the acorn's velocity as it hits the ground?
Answers
my mom is dum and anoying asl, what should i do?
Answers
Answer:
stop being an annoying child and appreciate everything your mother does for you because she cares for you
Explanation:
its the right thing to do
Be thankful for everything your mom does bc one day she wont be here any more! Love her while you can
If you borrow your mom's car to drive 128 m to the store, but you go cruising
instead and drive a total distance of 1256 m in 3600s. What was your speed during the
trip? Round answer to 2 significant figures.
Answers
Answer:
v = 0.349 m/s
Explanation:
If you borrow your mom's car to drive 128 m to the store, but you go cruising instead and drive a total distance of 1256 m in 3600s.
We need to find your speed during the trip. It is equal to the total distance divided by time taken.
He has done cruising instead and drive a total distance of 1256 m.
So,
[tex]v=\dfrac{d}{t}\\\\v=\dfrac{1256\ m}{3600\ s}\\\\v=0.349\ m/s[/tex]
So, the speed of the person during the trip is 0.349 m/s.
What happens to the energy in a closed system?
Answers
Answer:
can exchange energy with its surroundings through heat and work transfer. In other words, work and heat are the forms that energy can be transferred across the system boundary.
If the experimenter knows who is in the experimental and control groups and treats them accordingly, she runs the risk of ________.
Answers
Answer:
Experimenter bias
Explanation:
If the experimenter knows who is in the experimental and control groups and treats them accordingly, she runs the risk of Experimenter bias.
Definitions of Experimenter bias
1) Research bias, also called experimenter bias, is a process where the scientists performing the research influence the results, in order to portray a certain outcome.
2) Observer bias (also called experimenter bias or research bias) is the tendency to see what we expect to see, or what we want to see. When a researcher studies a certain group, they usually come to an experiment with prior knowledge and subjective feelings about the group being studied.
Shoot the cannon velocity of 25 m/s and observe the velocity vector on the simulator and make a statement about your observation . In other words what is happening to the projectile as it travel its parabolic trajectory ?
Answers
Answer:
Its speed remains the same but its velocity keeps chaging (in direction)
Explanation:
The public is not yet able to purchase cars powered by hydrogen fuel cells because engineers have to determin
how the cars perform based on which scenario?
on racetracks
Answers
Answer:
The options are
A.on racetracks
B.in real-world conditions
C.in flooded environments
D.on closed courses
The answer is B. In real world conditions
The public is not yet able to purchase cars powered by hydrogen fuel cells because engineers have to determin
how the cars perform based on real world conditions.
This will ensure they encounter the real and first hand experiences about the challenges and also the advantages associated with using this type of fuel.
Vertical acceleration of the stone thrown upwards at the top of the trajectory (where its velocity vanishes) is equal to
A. g
B. g/2
C. 0
D. nine of the above
Answers
Answer:
A. g
Explanation:
An airline employee tosses two suitcases in rapid succession with a horizontal velocity of 7.2 ft/s onto a 50-lb baggage carrier which is initially at rest. Problem 14.003.a Conservation of momentum: two colliding suitcases Knowing that the final velocity of the baggage carrier is 4.8 ft/s and that the first suitcase the employee tosses onto the carrier has a weight of 30 lb, determine the weight of the other suitcase. (You must provide an answer before moving on to the next part.) The weight of the other suitcase is lb.
Answers
Answer:
m₁ = 70 lb
Explanation:
Here we will use the law of conservation of momentum:
m₁u₁ + m₂u₂ + m₃u₃ = m₁v₁ + m₂v₂ + m₃v₃
where,
m₁ = mass of first suitcase = ?
m₂ = mass of second suitcase = 30 lb
m₃ = mass of baggage carrier = 50 lb
u₁ = initial speed of first suitcase = 7.2 ft/s
u₂ = initial speed of second suitcase = 7.2 ft/s
u₃ = initial speed of baggage carrier = 0 ft/s
v₁ = Final speed of first suitcase = 4.8 ft/s
v₂ = Final speed of second suitcase = 4.8 ft/s
v₃ = Final speed of baggage carrier = 4.8 ft/s
because after collision all three will have same speed
Therefore,
(m₁)(7.2 ft/s) + (30 lb)(7.2 ft/s) + (50 lb)(0 ft/s) = (m₁)(4.8 ft/s) + (30 lb)(4.8 ft/s) + (50 lb)(4.8 ft/s)
(m₁)(7.2 ft/s) + (216 lb ft/s) + (0 lb ft/s) = (m₁)(4.8 ft/s) + (144 lb ft/s) + (240 lb ft/s)
(m₁)(7.2 ft/s) - (m₁)(4.8 ft/s) = 168 lb ft/s
m₁ = (168 lb ft/s)/(2.4 ft/s)
m₁ = 70 lb
Please help which one is correct
Answers
Answer:
option (i) is correct
Explanation:
as there is no air resistance, no force is acting on the object horizontally, but gravitational acceleration will obviously act, regardless of the air resistance... option (i) is correct
PLEASE HELP WILL MARK BRAINLIEST
Answers
Answer:
also choose D and E i belive those are also correct
Lab report on motion 6th grade
Answers
Answer:
I'm in 10th grade
Explanation:
Forces are expressed in ________. (newtons or mass)
Answers
Mass isn’t even a unit of measurement
What determines the path that an object in projectile motion follows? (Ignore air resistance)
gravity only
inertia only
gravity and inertia
neither gravity or inertia
Answers
Answer:
C
gravity and inertia
Explanation:
Answer:
c :)
Explanation:
A 1000-turn solenoid is 50 cm long and has a radius of 2.0 cm. It carries a current of 18.0 A. What is the magnetic field inside the solenoid near its center
Answers
Answer:
The value is [tex]B = 0.0452 \ T [/tex]
Explanation:
From the question we are told that
The number of turns is N = 1000
The length is L = 50 cm = 0.50 m
The radius is r = 2.0 cm = 0.02 m
The current is I = 18.0 A
Generally the magnetic field is mathematically represented as
[tex]B = \mu_o * \frac{N }{L} * I[/tex]
Here [tex]\mu_o[/tex] is the permeability of free space with value
[tex]\mu_o = 4\pi * 10^{-7} N/A^2[/tex]
So
[tex]B = 4\pi * 10^{-7} * \frac{1000}{0.50} * 18.0[/tex]
=> [tex]B = 0.0452 \ T [/tex]
Streams compensate for changes in their systems by adjusting other factors in order to return to _______
Answers
Answer:
Equilibrium.
Explanation:
Streams compensate for changes in their systems by adjusting other factors in order to return to equilibrium because so as to maintain their watershed. When the surface runoff move downslope, it also cause a concentration in small areas and create small channels of streams. These channels normally allow the flow of water during rainfall.
Briefly explain why arterial injuries are more dangerous than damage to veins
or capillaries. Explanation should address structure and function of the
blood vessels.
IF YOU SEE THIS PLZ ANSWER RN
Answers
Answer:
Injury to a vein increases the risk of forming a blood clot.
Explanation:
hoped this helped
Gibbons, small Asian apes, move by brachiation, swinging below a handhold to move forward to the next handhold. A 9.0 kg gibbon has an arm length (hand to shoulder) of 0.60 m. We can model its motion as that of a point mass swinging at the end of a 0.60-m-long, massless rod. At the lowest point of its swing, the gibbon is moving at 3.5 m/s. What upward force must a branch provide to support the swinging gibbon
Answers
Answer:
The correct solution will be "271.95 N".
Explanation:
The given values are:
velocity
v = 3.5 m/s
mass
m = 9.0 kg
r = 0.6 m
According to the question:
⇒ [tex]F_{branch}=F_{gravity}+F_{centrifugal}[/tex]
⇒ [tex]=mg+\frac{mv^2}{r}[/tex]
On substituting the values, we get
⇒ [tex]=9\times 9.8+\frac{9\times (3.5)^2}{0.6}[/tex]
⇒ [tex]=88.2+\frac{110.35}{0.6}[/tex]
⇒ [tex]=271.95 \ N[/tex]
for an emitted wavelength of 500 nanometers and a redshift of 0.4 what will be the observed wavelength g
Answers
Answer:
The observed wavelength is [tex] \lambda = 700nm[/tex] (color - Red)
Explanation:
From the question we are told that
The wavelength of the emitter is [tex]\lambda_ e = 500 nm = 500 *10^{-9} \ m[/tex]
The redshift is R = 0.4
Generally red shift is mathematically represented as
[tex]R = \frac{ \lambda - \lambda_e }{\lambda_e}[/tex]
=> [tex]0.4 = \frac{ \lambda - 500 *10^{-9} }{500 *10^{-9} }[/tex]
=> [tex] \lambda - 500*10^{-9} = 200*10^{-9} [/tex]
=> [tex] \lambda = 700 *10^{-9}[/tex]
=> [tex] \lambda = 700nm[/tex]