Answer:
12.4m/s²; 80.99m
Explanation:
Acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time. Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.
Mathematically, acceleration is given by the equation;
[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]
Given the following data;
Initial velocity = 19.5m/s
Final velocity = 50.1m/s
Time = 2.47 secs
Substituting into the equation;
[tex]a = \frac{50.1 - 19.5}{2.47}[/tex]
[tex]a = \frac{30.6}{2.47}[/tex]
Acceleration, a = 12.4m/s²
Solving for the distance covered;
[tex] S = ut + \frac {1}{2}at^{2}[/tex]
Substituting into the values into the equation;
[tex] S = 19.5(2.47) + \frac {1}{2}(12.4)(2.47)^{2}[/tex]
[tex] S = 48.165 + 6.2 *6.1009[/tex]
[tex] S = 48.165 + 32.8256[/tex]
S = 80.99m
How much would a 1000 gram soccer ball accelerate if I kicked it with a force of 15 N?
Answer:
15m/s2
Explanation:
Acceleration = Force / Mass
Acceleration = 15N / 1kg
Acceleration = 15m/s2
An automobile tire with a radius of 0.30 m starts at rest and accelerates at a constant angular acceleration of 2.0 rad/s2 for 5.0 s. What is the angular displacement of the tire?
Answer:
The value is [tex]\theta = 25 \ radian[/tex]
Explanation:
From the question we are told that
The radius is [tex]r = 0.30 \ m[/tex]
The acceleration is [tex]\alpha = 2.0 \ rad/s^2[/tex]
The time taken is [tex]t = 5.0[/tex]
Generally the angular displacement is mathematically represented as
[tex]\theta = \frac{s}{r}[/tex]
Here s is the linear distance covered by the tire which is mathematically represented as
[tex]s = u t + \frac{1}{2}a t^2[/tex]
Here u is 0 given that the car started from rest and
[tex]a = \alpha * r = 2.0 * 0.30= 0.6\ m/s^2[/tex]
So
[tex]s = 0 + \frac{1}{2}*0.6* 5^2[/tex]
[tex]s = 7.5 \ m[/tex]
So
[tex]\theta = \frac{7.5}{0.30}[/tex]
=> [tex]\theta = 25 \ radian[/tex]
The FITT principles of training include __________.
A.
fundamental, intensity, time, and type
B.
frequency, intensity, time, and type
C.
frequency, individual, time, and type
D.
frequency, intensity, tough, and time
Please select the best answer from the choices provided.
Answer:
IT Will be Answer choice B
Explanation:
frequency, intensity, time, and type
FITT (frequency, intensity, time, and type) is one way to remember the general guidelines for what should be included in a fitness plan.
Answer:
B. frequency, intensity, time, and type
Explanation:
^^^^
A motorcyclist started a race from START line and from rest, and accelerated with the acceleration of 2 m/s2 for 7 seconds. Then he increased the acceleration to 4 m/s2 and went with that acceleration for 8 seconds. What was the racer’s position from the START line after 7+8 seconds from the start of the race?
Answer:
289 m .
Explanation:
s = ut + 1/2 at² , u is initial velocity , t is time , a is acceleration and s is distance covered .
For t = 7 s
s = 0 + 1/2 x 2 x 7²
= 49 m
velocity after 7 s
= a x t = 2 x 7 = 14 m /s
for next 8 s , initial velocity u = 14 m /s
S = ut + 1/2 at²
= 14 x 8 + 1/2 x 4 x 8²
= 112 + 128
= 240 m
Total displacement in 7 + 8 s
= 49 + 240 = 289 m .
What is the mass of a 7500N car on earth?
Answer:
Weight of the car F = m*g ; Here, g = 9.81 N/kg ;
So, we can find from the formula mentioned above m = F/g ;
Mass m is equal about 764 kg.
Explanation:
The distance between pitcher and catcher on a baseball field is 18.4 m. If a pitcher releases a ball from a height of 1.5 m and the catcher catches the ball right at ground level, how fast did the pitcher throw the ball?
Answer:
33.26 m/s
Explanation:
The initial velocity of the ball can be determined by;
R = v[tex]\sqrt{\frac{2H}{g} }[/tex]
Where R is the range (distance between pitcher and catcher), H is the height covered, v is the initial velocity and g is the acceleration due gravity (9.8 m/[tex]s^{2}[/tex]).
So that;
18.4 = v[tex]\sqrt{\frac{2*1.5}{9.8} }[/tex]
= v [tex]\sqrt{\frac{3}{9.8} }[/tex]
= v [tex]\sqrt{0.3061}[/tex]
= 0.5533v
⇒ v = [tex]\frac{18.4}{0.5533}[/tex]
= 33.2550
The initial velocity of the ball is 33.26 m/s.This is the velocity with which the pitcher threw the ball.
Which two phrases describe the nature of an electromagnetic force?
A. Not a fundamental force of nature
B. Produced by interactions between magnetic objects
C. Acts only when objects tough each other
D. Produced by interactions between electrically charged objects
Answer:
I think its C and D
Explanation:
What is the acceleration of a car that moves in a straight line and decreases its speed from 80km/hr to 15km/hr in exactly 5.0 seconds
Answer:
-3.6 m/s
Explanation:
first go from km/hr to m/s
so 80km/hr⇒ 22.2222 m/s
15km/hr ⇒4.16667 m/s
now use the equation for acceleration
[tex]\frac{v-v0}{t}[/tex]
(4.16667-22.2222)/5 = 18.05553/ 5 = -3.611106 m/s
with sig figs
-3.6 m/s
which equation states Newton's second law
Newton's second law of motion is expressed by the equation F = m × a. where F is the force and m is the mass of the object.
Where:
F represents the net force acting on an object,
m denotes the mass of the object, and
a represents the acceleration produced by the net force.
According to Newton's second law, the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.
This equation (F = m × a) is Newton's second law equation.
To know more about Newton's second law:
https://brainly.com/question/15280051
#SPJ4
Why is visible light between infrared and ultraviolet
Answer:
The infrared has longer wavelengths (700 nm to 1 mm) than those of visible lights (390 nm to 700 nm). Note though that visible light is the only radiation that can be seen by the human eye. The ultraviolet is much more intense and has a shorter wavelength (400 nm to 10 nm) compared to visible light.
Explanation:
GREETINGS!
Visible light is in between UV and IR region because visible light has a wavelength ranging from 400nm to 700nm, and below 400nm is the region of UV and above 700 is the region of IR, So visible lights is in between UV and IR
To understand things more clearly you could see the electromagnetic spectrum to see which ray lies lies in what region.
HOPE THIS HELPS YOU
what is the average speed of a person who swims 105m in 70s ?
Answer:
v = 1.5 [m/s]
Explanation:
This problem can be solved using the definition of velocity which is the relationship between space and time.
v = x/t
where:
v = speed [m/s]
x = distance = 105 [m]
t = time = 70 [s]
v = 105/70
v = 1.5 [m/s]
Answer:time.
v = x/t
where:
v = speed [m/s]
x = distance = 105 [m]
t = time = 70 [s]
v = 105/70
v = 1.5 [m/s]
Explanation:time.
v = x/t
where:
v = speed [m/s]
x = distance = 105 [m]
t = time = 70 [s]
v = 105/70
v = 1.5 [m/s]
A 25-kg mass is suspended 4 meters above the ground. Find its potential energy. Show your work, and use the
rules of significant figures when giving your answer
Acids and bases are compounds with very different properties. Which of the following is a property of an acid?
Answer:
reacts to mos metlal
Explanation:
The power in an electrical circuit is given by the equation P = I2R, where I is the current flowing through the circuit and R is the resistance of the circuit. What is the power in a circuit that has a current of 0.1 amps and a resistance of 18 ohms?
Answer:
0.18 watt
Explanation:
The following data were obtained from the question:
Current (I) = 0.1 A
Resistance (R) = 18 ohms
Power (P) =.?
P = I²R
Where
P is the power.
I is the current in the circuit.
R is the resistance.
With the above formula, we can obtain the power in the circuit as follow:
P = 0.1² × 18
P = 0.01 × 18
P = 0.18 watt
Therefore, the power in the circuit is 0.18 watt
A motorcyclist started a race from START line and from rest, and accelerated with the acceleration of 2 m/s2 for 7 seconds. Then he increased the acceleration to 4 m/s2 and went with that acceleration for 8 seconds. What was the racer’s position from the START line after 7+8 seconds from the start of the race?
Answer:
.
Explanation:
A car slams on its brakes creating an acceleration of -3.2 m/s². It comes to rest after traveling a distance of 210 m. What was its velocity before it began to accelerate?
Answer: 36.66m/s
Explanation:
Listing everything is gives you:
Vf = 0
a = -3.2
Δx = 210
Vi = ?
Pick one of the kinematic equations to find the missing variable
I used this one: [tex]Vf^2=Vi^2 + 2a[/tex]Δx
When you plug everything in, you get
0 = [tex]Vi^2 -1344[/tex]
add 1344 to both sides and square root to get Vi = 36.66
Which equation correctly represents the gravitational potential energy of a
system?
Answer:
I don't really understand what you are asking but... i can try to help
The formula for potential energy depends on the force acting on the two objects. For the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters.
Hope this helps sorry I couldn't answer it☺️
a dog with mass of 14kg has a kinetic energy of 135.5j. what is the speed of the dog
Answer:
v = 4.39968 m/s
v = 9.8418038654259 mi/h
v = 14.434645669291 ft/s
v = 15.838846732892 km/h
Explanation:
v=KE/1/2m
Which of the following shows levels of organization in living things, from smallest to largest?
A)organ - cell - organ system - tissue
B)organ system - tissue - cell - organ
C)cell - tissue - organ - organ system
D)organ system - organ - tissue - cell.
A person travels by car from one city to another with different constant speeds between pairs of cities. She drive 60.0 min at 100.0km/h, 5.0 min at 90.0 km/h, and 40.0 min at 60.0km/h and soends 30.0 min eating lunch and buying gas. (A) determine the average speed for the trip. (B) determine the distance between the intial and final cities alkng the route
Answer:
The average speed for the trip is 65.56 [tex]\frac{km}{h}[/tex] and the distance between the intial and final cities along the route is 147.5 km
Explanation:
You know:
t1= 60.0 min= 1 h v1= 100.0km/ht2= 5.0 min= 1/12 hv2= 90.0 km/ht3= 40.0 min= 2/3 hv3= 60.0km/h t4=30.0 min= 0.5 h= 1/2 hv4= 0 because she stops to eat lunch and buy gas.Speed is a quantity that reflects the space traveled by a body in a unit of time. That is, the average velocity relates the change in position with the time taken to effect said change.
[tex]speed=\frac{change in position}{time}[/tex]
To calculate the average speed of the trip you must calculate the total distance traveled and the total time used.
The total time used for the trip is:
t= t1 + t2 + t3 + t4= 60 min + 5 min + 40 min + 30 min= 135 min= 2.25 h
The distance traveled in each stage of the trip is calculated knowing the speed in that stage and the time used by the expression:
distance= speed*time
Then:
distance1= v1*t1 = 100 km/h * 1 h= 100 kmdistance2= v2*t2 = 90 km/h * 1/12 h= 7.5 kmdistance3= v3*t3 = 60 km/h * 2/3 h= 40 kmdistance4= v4*t4 = 0 km/h * 1/2 h= 0 kmSo, the total distance traveled is calculated as:
d= 100 km + 7.5 km + 40 km + 0 km= 147.5 km
Then, the average speed for the trip is:
[tex]average speed=\frac{total distance}{total time}[/tex]
[tex]average speed=\frac{147.5 km}{2.25 h}[/tex]
average speed= 65.56 [tex]\frac{km}{h}[/tex]
The average speed for the trip is 65.56 [tex]\frac{km}{h}[/tex] and the distance between the intial and final cities along the route is 147.5 km
A child pushes a toy car with a force of 5 N which causes it to accelerate at a rate of 2.0 m/s2. What force would be required to accelerate the toy car at 3.0 m/s2?
Answer:
7.5 N
Explanation:
For is given by :
F = ma
Where
m is mass of an object and is its acceleration
When force is 5 N, its acceleration is 2 m/s². We need to find the force required to to accelerate the toy car at 3.0 m/s².
[tex]\dfrac{F_1}{F_2}=\dfrac{a_1}{a_2}[/tex]
Solving for F₂.
[tex]F_2=\dfrac{F_1a_2}{a_1}\\\\F_2=\dfrac{5\times 3}{2}\\\\F_2=7.5\ N[/tex]
So, it would require 7.5 N of force to accelerate the toy car at 3.0 m/s².
3. Elizabeth tested how high five different brands of new tennis balls would bounce when dropped from the same height of 2 meters. She dropped the balls so that they hit the same floor tile each time. In this consumer testing she did not have a control experiment but took factual information from the manufacturers on how well their product bounced (resiliency). She tested 100 balls of each brand. She measured the bounces in centimeters. what is the controlled variable and the Independant variable and the dependent variable
Answer:
Controlled variable: the height from which the ball is dropped and the floor tile on which the ball hits
Independent variable: different tennis ball brands
Dependent variable: height of bounce in centimeters
Explanation:
Scientific experiments have three major kinds of variables:
Independent variable: This is the variable that is subject to the manipulation of the experimenter. The values of this variable are determined by the experimenter. In this example, Elizabeth determines the brand of tennis ball to be tested, hence the tennis ball brand is the independent variable
Dependent variable: This variable has values which are a result of the effect of the manipulation of the independent variable. The values of the dependent variable are not under the direct control of the experimenter. They are simply the results of the experiment. Here, the height to which the ball bounces is not predetermined, hence it is the outcome or dependent variable.
Control variables; These are variables that can affect the outcome of the results of the experiment but are kept constant throughout the experiment, to rule out biases when testing the effect of the independent variable.
just answer this plzz
C, i know this trust me
Increased globalization has been caused by all of the following except
A improved technology
B. increased transportation speeds
C. improved communication speeds
D. decreased distances between nations
Please select the best answer from the choices provided.
Answer: D. decreased distances between nations
just did test on edge
i really need brainliest plz
Which of the following is not a word to describe a part of a wave?
Amplitude
Crest
Wavelength
Color
Answer:
Color, as far as I'm aware.
If a student leaves home at 7:30 AM to walk to his school 2 km away, stops at a neighbor's house for 15 min, then arrives at school at 8:00 AM, what is the student's average speed for the trip to school?
Answer:
The student's average speed for the trip to school is 4 [tex]\frac{km}{h}[/tex]
Explanation:
Speed is a quantity that relates the displacement that an object makes in a given unit of time. In other words, speed is a physical quantity that expresses the relationship between the space traveled by an object, the time used for it and its direction.
Since the average speed relates the change in position to the time taken to effect said change, then:
[tex]speed=\frac{change in position}{time}[/tex]
In this case, the student travels a total distance of 2 km between his home and school and the total time spent on the trip is 30 minutes, then:
change in position= 2 kmtime= 30 minutes= 0.5 hours (being 60 minutes = 60 hours)Replacing:
[tex]speed=\frac{2 km}{0.5 hours}[/tex]
Solving:
speed= 4[tex]\frac{km}{hours}[/tex]
The student's average speed for the trip to school is 4 [tex]\frac{km}{h}[/tex]
20. A hurricane in the Gulf of Mexico travels 360 km in 15 h. What is the average speed of this hurricane?
Answer:
The average speed of this hurricane is 24 kph.
Explanation:
let me know if this helps
3. What is the shortest possible time in which a bacterium could travel a distance of 84. cm across a Petri dish
at a constant speed of 3.5 mm/s? *(answer in cm/s)
whats the answer in cm/s
Answer:
240 s
Explanation:
distance = 84 cm
speed = 3.5 mm/s (0.35cm/s)
but speed = distance/time
hence the shortest time taken = distance/speed
= 84/0.35 = 240s
Assume a freely falling object were somehow equipped with a speedometer on a planet where the acceleration due to gravity is 20 meters per square second.
By how much would its speed reading in- crease each second?
a. 10 m/s
b. 40 m/s
c. A value dependent on its initial speed 4. 30 m/s
d. 5 m/s
e. 20 m/s
Help number 3 ASAP !!!