A _____ is a form of Web conferencing that uses streaming media technologies to broadcast video and/or audio over the Internet from a single content source to many listeners or viewers simultaneously.

Answer:

You didn't specify the language so I did it in C#

Explanation:

Answer:

software

Explanation:

with out software the hardware cannot function

Answer:

Explanation:

The solution code is written in Java.

Firstly, create a Scanner object to get user input (Line 7). Next we use nextDouble method from Scanner object to get user first and second floating-point number (Line 9-15).

Next, display R and T and result of their summation, difference and product (Line 18-28).

Answer:

No, it can't be verified with a pseudocode.

Explanation:

We can not verify this with a pseudocode because the largest integer that we can store in 32-bit integer goes by the formula 2^32 - 1 = 4, 294, 967,295 and this means that it has 32 ones. Or it may be 2^31 - 1 = 2, 147, 483,647 which is a two complement signed integer.

Despite the fact that it can not be verified by using pseudocode, we can do the Verification by writting programs Through some programming language or in plain English code.

In a 32-bit CPU, the largest integer that we can store is 2147483647 because we can store integer as 2^31 and - (2^31 + 1).

Answer:

The methods is completed as follows

See attachment for .java source file

Comments are used to explain difficult lines

Program starts here

import java.util.*;

public class quiz1

{

public static int doubleOrNothing(int num)

{

 if(num<100)

 {

  num*=2;

 }

 else{

  num = 0;

 }

 System.out.println(num);

 return num;

}

public static String formatPercent(double percent)

{

 percent*=100;

 System.out.println(percent+"%");

 return percent+"%";

}

public static int everyOtherChar(String word)

{

 char first = word.charAt(0);

 char last = word.charAt(word.length() - 1);

 int ascii = (int)first + (int)last;

 System.out.print(ascii);

 return ascii;

}

public static void main(String [] args)

{

 //Testing doubleOrNothing method

 int num;

 Scanner input = new Scanner(System.in);

 System.out.print("Enter any integer number: ");

 num = input.nextInt();

 System.out.print("Result of doubleOrNothing method\n:");

 doubleOrNothing(num);

 //Testing formatPercent method

 double percent;

 System.out.print("Enter any number between 0 and 1: ");

 percent = input.nextDouble();

 System.out.print("Result of formatPercent method\n:");

 formatPercent(percent);

 //Testing everyOtherChar method

 String word;

 System.out.print("Enter any string: ");

 word = input.next();

 System.out.print("Result of everyOtherChar method\n:");

 everyOtherChar(word);

}

}

//See Attached file

Answer:

To answer this question, i prepared a pseudocode and a program written in python;

Pseudocode begins here:

1. Start

2. Input montlySales

3. If monthlySales < 100000

3.1. Display Nothing

4. Else

4.1 Display “You earned a $5000 bonus!”

4.2 If monthlySales > 1.25 * 90000

4.2.1 Display “All employees get one day off!”

5.     Stop

Python Program starts here (See attachment for proper view of the program):

#Prompt user for input

monthlySales = float(input("Monthly Sales: "))

#Check monthlySales

if monthlySales < 100000:

     print("")

else:

     print("You earned a $5,000 bonus")

     if monthlySales > 1.25 * 90000:

           print("All Employees get the day off")

Explanation:

To answer this question, a conditional if statement is needed.

The pseudocode (and the program) starts by prompting user for input;

Then, the user input is first compared with 100,000

If it's less than 100,000; then nothing is displayes

However, if it is at least 100,000

"You earned a $5,000 bonus" is displayed

It further checks if the user input is greater than 125% of 90,000

If yes, "All Employees get the day off" is displayed else, nothing is displayed.

The pseudocode (and the program) stops execution, afterwards

Answer:

Hope this helps...

Good luck on your assignment...

Answer:

RAM is the memory available for the operating system, programs and processes to use when the computer is running. ... When you power off your computer the data stored in RAM is deleted. ROM is a type of non- volatile memory. Data in ROM is permanently written and is not erased when you power off your computer.

Explanation:

Answer:

...............................................

Explanation:

............................................................

Answer: provided in the explanation section

Explanation:

Network Merging and Acquisitions

Environment:

· 400 Windows Servers

· 8000 Windows client devices (laptops running Windows os)

· 40 Linux servers Active Directory Domain Services to provide DNS services to all the hosts, both Windows and Linux.

· Unix servers(Other environment to be merged)

· host resolution they use is BIND

A great challenge of managing a network at a growing company is that of acquisitions. That is, one of the ways a developing company grows is by acquiring other companies. When that acquisition happens, there is usually the require to connect the two networks together.

Connecting two networks environments together is one of those tasks that makes network engineers groan. As networks are not built to any type of agreed-upon norm, what the opposite network will hold is always unpredictable, most probably in a difficult-to-integrate way.

Quick & Dirty IPSEC Tunnel

When an acquisition deal happen, management needs the IT infrastructures connected. The proper way of bringing networks together involves a full audit of the remote network to insure compliance with regulatory obligations, inventorying IP address blocks both public and private and BGP ASNs in use, understanding IGP routing schemes, reviewing WAN provider contracts, itemizing hardware and software in use, purchasing needed equipment, staging infrastructure changes, scheduling maintenance windows, and so on.  

Main problems with quick and dirty IPSEC tunnels are

Maintaining network lists manually.

manual maintenance of route injection into the IGP.

Probable single points of failure.

Using SD-WAN As Acquisition Network Glue:

Thinking through SD-WAN technology, quick connectivity option that’s better than a quick and dirty IPSEC tunnel. SD-WAN offers

1. Easily managed redundant plumbing :

SD-WAN forms a mesh of tunnels on top of all available paths. That means that a local circuit outage neither takes down the ability to forward nor needs a network engineer to re-configure IP tunnel endpoints.

2. IGP integration:

When route injection is often available with IPSEC tunnels, it is found that route injection is not terribly reliable, depending on vendor, software version, and a host of other factors. I have not been keen to rely on routes being injected or withdrawn by an IPSEC VPN endpoint.

3. Segment isolation:

An SD-WAN function available from many of SD-WAN vendors is that of segment isolation. You can create virtual network segments that permit intra-segment communication while preventing inter-segment communication. In the case of an acquisition, that functionality seems really helpful.

Segment isolation can also help simplify routing. If you’re facing overlapping, this might help avoid a complex NAT scheme.

4. Service chaining:

Many SD-WAN products shows service chaining. That is, SD-WAN devices tunnel between each other. By seeing the tunnelling ability, it’s possible to drop traffic off when we need.

Drawbacks Of The SD-WAN Approach

A few drawbacks in using SD-WAN as a network merger tool come to mind.

Cost:

The cost of adding a new network segment to an SD-WAN deployment varies by licensing scheme, but is not at all free. Quick and dirty IPSEC tunnels often are free which requires no capital expense to stand up.

Remote hands:

In order to leverage SD-WAN at remote sites, there is a great chance you’ll need remote hands to pull off the device installation. That’s not anything else than deploying SD-WAN in your own network

Perhaps not quick and dirty enough:

The great problem facing around is the long time it takes to stand up dedicated WAN circuits. IPSEC tunnels are often the path of very less resistance to bringing up a private connection between two newly acquainted organizations.

To Conclude:

Using IPSEC tunnels to join networks together what will eventually be part of a unified IT whole isn’t a mature solution in the modern era. SD-WAN looks like a mature solution that do not need require private MPLS circuits to function.

If private MPLS circuits are eventually added to the SD-WAN mix, technology transition is not required. The SD-WAN option can stay in place as-is, using the MPLS circuit being added to the SD-WAN forwarding device as a newly available path. That means the temporary solution can transition into the permanent solution by grace.

SD-WAN can be opted as a way to onboard an acquired network permanently, at the same time retaining the fast time to connect that an IPSEC tunnel offers. For organizations who already have an SD-WAN solution in place, there is nothing to think about. Considering organizations who haven’t invested in SD-WAN so far, this might be an additional driver to do so.

Answer:

The programming language is not stated; However, I'll answer this question using two programming languages (Python and C++)

Comments are used to explain difficult lines

#Python Program starts here

#Prompt user for monthly pay

pay = float(input("Enter Monthly Pay: "))

#Prompt user for rent

rent = float(input("Enter Rent: "))

#Prompt user for utilities

utilities = float(input("Enter Utilities: "))

#Prompt user for groceries

groceries = float(input("Enter Groceries: "))

#Calculate discretionary

discretionary = pay - rent - utilities - groceries

#Print discretionary

print("Discretionary: ")

print(discretionary)

#Python Program ends here

//C++ Program starts here

#include<iostream>

using namespace std;

int main()

{

//Declare variables

float pay, rent, utilities, groceries, discretionary;

//Prompt user for input

cout<<"Enter Monthly Pay: ";

cin>>pay;

cout<<"Enter Rent: ";

cin>>rent;

cout<<"Enter Utilities: ";

cin>>utilities;

cout<<"Enter Groceries: ";

cin>>groceries;

//Calculate discretionary

discretionary = pay - rent - utilities - groceries;

//Print discretionary

cout<<"Discretionary: "<<discretionary;

return 0;

}

//C++ Program ends here

Answer: Yes but maybe yes

Explanation: reality does exist pinch yourself

Answer:

there should be

Explanation:

Contrary to Russell's suggestion, the distinction between appearance and reality is not simply the distinction "between what things seem to be and what they are," more precisely, the distinction between what things seem to be and what they are is not a simple distinction.

Appearance and Reality. Metaphysics is the science that seeks to define what is ultimately real as opposed to what is merely apparent. The contrast between appearance and reality, however, is by no means peculiar to metaphysics. ... Ultimate reality, whatever else it is, is genuine as opposed to sham.

Answer: provided in the explanation section

Explanation:

Given that:

Assume D(k) =║ true it is [1 : : : k] is valid sequence  words or false otherwise

now the sub problem s[1 : : : k] is a valid sequence of words IFF s[1 : : : 1] is a valid sequence of words and s[ 1 + 1 : : : k] is valid word.

So, from here we have that D(k) is given by the following recorance relation:

D(k) = ║ false maximum (d[l]∧DICT(s[1 + 1 : : : k]) otherwise

Algorithm:

Valid sentence (s,k)

D [1 : : : k]             ∦ array of boolean variable.

for a ← 1 to m

do ;

d(0) ← false

for b ← 0 to a - j

for b ← 0 to a - j

do;

if D[b] ∧ DICT s([b + 1 : : : a])

d (a) ← True

(b). Algorithm Output

      if D[k] = = True

stack = temp stack           ∦stack is used to print the strings in order

c = k

while C > 0

stack push (s [w(c)] : : : C] // w(p) is the position in s[1 : : : k] of the valid world at // position c

P = W (p) - 1

output stack

= 0 =

cheers i hope this helps !!!

Answer:

The header file in C++ is as follows

myFunction.h

void max(int a, int b)

{

if(a>b)

{

 std::cout<<a;

}

else

{

 std::cout<<b;

}

}

The Driver Program is as follows:

#include<iostream>

#include<myFunction.h>

using namespace std;  

int main()

{

int m,n;

cin>>m;

cin>>n;

max(m,n);

}

Explanation:

It should be noted that, for this program to work without errors, the header file (myFunction.h) has to be saved in the include directory of the C++ IDE software you are using.

For instance; To answer this question I used DevC++

So, the first thing I did after coding myFunction.h is to save this file in the following directory  ..\Dev-Cpp\MinGW64\x86_64-w64-mingw32\include\

Back to the code

myFunction.h

void max(int a, int b)  {

-> This prototype is intialized with integer variables a and b

if(a>b)  -> If the value of a is greater than b;

{

 std::cout<<a;  -> then the value of variable a will be printed

}

else

-> if otherwise,

{

 std::cout<<b;

-> The value of b will be printed

}

}

Driver File (The .cpp file)

#include<iostream>

#include<myFunction.h>  -> This line includes the uesr defined header

using namespace std;  

int main()

{

int m,n;  -> Two integer variables are declared

      cin>>m;  -> This line accepts first integer input

      cin>>n;  -> This line accepts second integer input

max(m,n);

-> This line calls user defined function to return the largest of the two integer variables

}

Answer:

The default location for local logon scripts is

next time m8 mmmmmdsaasd

Answer:

  1.55 dB

Explanation:

Attenuation to 1.4/2.0 = 0.7 of the previous power level is a gain of ...

  10·log(0.7) = -1.549 dB

The signal is attenuated by 1.55 dB.

Answer:

Following are the statement in C++ Programming language

cout<<setw(4);// set the width

cout<<number; // print the number with the width of 4

Explanation:

The  setw() is setting  according to the width defined as the argument to the function .The setw()  is under the ios header library .It means its definition is under the ios header file .

Following are the syntax to defined the setw() function that are given below

 setw(int k)

For example

include <iomanip>   // header file

#include <ios>   // header file

#include <iostream>   // header file

using namespace std;   // namespace

int main()   // main function

{    

   int number = 60;// variable declaration  

   cout << "previous width:" << number; // print  

   cout << " After setting the width"<< setw(4);  

   cout << number;     // display number

   return 0;  

}

Answer:

The csharp program to compute square roots of numbers and write to a file is as follows.

class Program  

{  

static long max = 1000000;  

static void writeRoots()  

{  

StreamWriter writer1 = new StreamWriter("roots.txt");  

double root;  

for (int n=1; n<=max; n++)  

{  

root = Math.Sqrt(n);  

writer1.WriteLine(root);  

}  

}  

static void Main(string[] args)  

{  

writeRoots();  

}  

}

The program to compute squares of numbers and write to a file is as follows.

class Program  

{  

static long max = 1000000;  

static void writeSquares()  

{  

StreamWriter writer2 = new StreamWriter("squares.txt");  

long root;  

for (int n = 1; n <= max; n++)  

{  

root = n*n;  

writer2.WriteLine(root);  

}  

}  

static void Main(string[] args)  

{  

writeSquares();  

}  

}  

Explanation:

1. An integer variable, max, is declared to hold the maximum value to compute square root and square.

2. Inside writeRoots() method, an object of StreamWriter() class is created which takes the name of the file as parameter.

StreamWriter writer1 = new StreamWriter("roots.txt");

3. Inside a for loop, the square roots of numbers from 1 to the value of variable, max, is computed and written to the file, roots.txt.

4. Similarly, inside the method, writeSquares(), an object of StreamWriter() class is created which takes the name of the file as parameter.

StreamWriter writer2 = new StreamWriter("squares.txt");

5. Inside a for loop, the square of numbers from 1 to the value of the variables, max, is computed and written to the file, squares.txt.

6. Both the methods are declared static.

7. Inside main(), the method writeRoots() and writeSquares() are called in their respective programs.

8. Both the programs are written using csharp in visual studio. The program can be tested for any operation on the numbers.

9. If the file by the given name does not exists, StreamWriter creates a new file having the given name and then writes to the file using WriteLine() method.

10. The csharp language is purely object-oriented language and hence all the code is written inside a class.

Explanation:

Both perform almost the same function of storing data, performing numerical calculations, formating cells, and to generate reports.

However, when dealing with data that is short term (requiring less updating) Microsoft Excel is recommended as it provides easy spreadsheet functions. Access on the other hand is a more complex application for data analysis involving constantly changing data values that are long term based. Access allows for efficient data analysis using complex tools such as import module, automated queries etc.

Answer:

a = ['a', 'b', 'r', 'a', 'c', 'a', 'd', 'a', 'b', 'r', 'a']  

a = [x for x in a if x != 'a']

print(a)

Explanation:

The code is written in python

a = ['a', 'b', 'r', 'a', 'c', 'a', 'd', 'a', 'b', 'r', 'a']  

a = [x for x in a if x != 'a']

print(a)

a = ['a', 'b', 'r', 'a', 'c', 'a', 'd', 'a', 'b', 'r', 'a']  

I declared a variable a and stored the list of value.

a = [x for x in a if x != 'a']

I used list comprehension to loop through the array and find any value that is not 'a' .

print(a)

I printed every value that is not 'a' in the array.

Answer:

mylist = [] #Create an empty list

i = 0 # initialize counter to 0

b = int(input("Enter into list: ")) # prompt user for input

while not(b == 0): #test if input is not 0

mylist.append(b) #insert input into list if it's not 0

i = i + 1 #increment counter

b = int(input("Enter into list: ")) #prompt user for input

#save sorted list in a newlist

newlist = sorted(mylist)

#print element on separate lines

for ind in newlist:

print(ind)

#End of program

Explanation:

Line 1 of the program creates an empty list named mylist

Line 2, initializes a counter variable i to 0

Line 3 prompts user for input

Line 4 to 7 iterates until user input is 0

Line 9 sorts the list and saves the sorted list into a new list

Line 11 & 12 prints the each element of the list on separate lines

Answer:

(1).short term goal.

=>complete the studies : next 4 months(time frame); certifcate in the course(reward or incentive).

=> getting a job : next six months(time frame); financial stability (reward or incentive).

(2). Long term goal.

=> learn about Business Analytics : 1 year(time frame); good pay for the position (reward/incentive).

=> Build my career: 2nd year (time frame);

Explanation:

At a particular period of time we all need mentors and this mentorships are what that we build us. When we are already built, we also become mentors and in turn we mentor others so as to build them too.

For the question, we should have something like this from a mentee

(1).short term goal.

=>complete the studies : next 4 months(time frame); certifcate in the course(reward or incentive).

=> getting a job : next six months(time frame); financial stability (reward or incentive).

(2). Long term goal.

=> learn about Business Analytics : 1 year(time frame); good pay for the position (reward/incentive).

=> Build my career: 2nd year (time frame);

Answer:

Option(a) is the correct answer to the given question .

Explanation:

The Biba Model in the database management system ensure the data integrity and define the state transaction in the data security policy .Following are the Features of the Biba Model.

Answer:

Explanation:

Following are the Semaphores:

Customers: Counts waiting customers;

Barbers: Number of idle barbers (0 or 1)

mutex: Used for mutual exclusion.

Cutting: Ensures that the barber won’t cut another customer’s hair before the previous customer leaves

Shared data variable:

count_cust: Counts waiting customers. ------------copy of customers. As value of semaphores can’t access directly.

// shared data

semaphore customers = 0; semaphore barbers = 0; semaphore cutting = 0; semaphore mutex = 1;

int count_cust= 0;

void barber() {

while(true) { //shop is always open

wait(customers); //sleep when there are no waiting customers

wait(mutex); //mutex for accessing customers1

count_cust= count_cust-1; //customer left

signal(barbers);

signal(mutex);

cut_hair();

}

}

void customer() {

wait(mutex); //mutex for accessing count_cust

if (count_cust< n) {

count_cust= count_cust+1; //new customer

signal(customers); signal(mutex);

wait(barbers); //wait for available barbers get_haircut();

}

else { //do nothing (leave) when all chairs are used. signal(mutex);

}

}

cut_hair(){ waiting(cutting);

}

get_haircut(){

get hair cut for some time; signal(cutting);

}

Answer:

Explanation:

Code:-

using System;

using System.Linq;

using System.Collections;

using System.Collections.Generic;

public class Test{

public static int no_drawer(){

Console.WriteLine("Enter the number of drawers : ");

return Int32.Parse(Console.ReadLine());

}

public static char wood_type(){

Console.WriteLine("Enter the type of woods('m' for mahogany, 'o' for oak, or 'p' for pine) : ");

return Console.ReadLine()[0];

}

public static double final_cost(int d,char ch){

double cost = 0.0;

if (ch == 'p') cost += d*100;

else if (ch == 'o') cost += d*140;

else cost += d*180;

cost += d*30;

return cost;

}

public static void display(int d,char ch,double p){

Console.WriteLine("Number of drawers : "+d);

if (ch == 'p')

Console.WriteLine("Type of Wood Chosen : pine");

else if (ch == '0')

Console.WriteLine("Type of Wood Chosen : oak");

else if (ch == 'm')

Console.WriteLine("Type of Wood Chosen : mahogany");

else

Console.WriteLine("Type of Wood Chosen : other");

Console.WriteLine("Total Cost is : "+p);

}

public static void Main(){

int drawers = no_drawer();

char ch_wood = wood_type();

double res = final_cost(drawers,ch_wood);

display(drawers, ch_wood,res);

}

}

cheers i hope this helped !!!

Answer:

Wireshark is used to find anomalies in network traffic as well as to troubleshoot application performance issues.

Explanation:

Wireshark is a computer software that was Initially released in the year 1998. The software was written in language (programming language) such as the C++ and the C programming language.

Originally, the main author of the Wireshark software is a man named Gerald Combs.

Wireshark is used in analyzing network protocols and software troubleshooting

Infomation such as antennae signal strengths can also be gotten by using Wireshark.

Hence, "Wireshark is used to find anomalies in network traffic as well as to troubleshoot application performance issues." Is the correct Option.

Answer: Provided in the explanation section

Explanation:

CODE USED :

//weight class

public class Weight

{

  //defining private variables pound, ounces and number of ounces in pound which is 16

  private int pounds;

  private double ounces;

  private int numberOfOuncesInPound=16;

  //constructor which initializes the weight variable with the coming input

  public Weight(int p, double o)

  {

      this.pounds=p;

      this.ounces=o;

  }

  //checks if the incoming weight object is less than the current object weight

  public boolean lessThan(Weight w)

  {

      //first comparison between pounds of the objects, if current object is less, then return true

      if(this.pounds<w.pounds)

          return true;

      //else if it is less then return false

      else if(this.pounds>w.pounds)

          return false;

      //else if both are equal then we compare the ounces

      else

      {

          //if current object ounces is less than we return true else false

          if(this.ounces<w.ounces)

              return true;

          else

              return false;

      }

  }

  //adds incoming weight to the current weight object and then normalize it

  public void addTo(Weight w)

  {

      this.pounds+=w.pounds;

      this.ounces+=w.ounces;

      normalize();

  }

  //divide the current weight with factor x which is a parameter of the function

  public void divide(int x)

  {

      this.ounces=toOunces();

      this.ounces/=x;

      this.pounds=0;

      normalize();

  }

  //returns a string which contains the data in a Particular Format

  public String toString()

  {

      return this.pounds+" lbs "+this.ounces+" oz";

  }

  //returns weight converted into ounces

  private double toOunces()

  {

      return this.pounds*this.numberOfOuncesInPound+this.ounces;

  }

  //this function checks if number of ounces is greater than 16 then it normalizes it by converting into pounds

  private void normalize()

  {

      while(this.ounces>this.numberOfOuncesInPound)

      {

          this.ounces-=this.numberOfOuncesInPound;

          this.pounds++;

      }

  }

}

cheers i hope this helped !!

Answer:

The correct answer is option (A) Create a sandbox on the machine

Explanation:

Solution

From the example given, the first step the security professional should take is to create a sandbox on the machine.

Sandbox: It  refers to as a remote testing environment that allows users to run programs or implement files without distorting the application, system or platform on which they run.

In areas of computer security a sandbox is a security technique used for separating running programs, normally in an effort to reduce system failures or software vulnerabilities from moving further.

Answer:

501.

Explanation:

In Transmission Control Protocol (TCP), sending and receiving of data is done as byte. These bytes are eventually grouped into packets referred to as segment.

The sequence number of the segment if all data is sent in only one segment is the same as the first byte of that segment.

In this scenario, a user datagram connection is sending 500 bytes to a client and the first byte is numbered 501. Thus, if all data is sent in only one segment, the sequence number of the segment is 501. The 501 represents the initial segment number (ISN).

However, assuming the same data was sent in five (5) segments. The sequence number would be;

First segment (1st) = 501.

Second segment (2nd) = 1501.

Third segment (3rd) = 2501.

Fourth segment (4th) = 3501.

Fifth segment (5th) = 4501.

Answer:

D. Screen Clipping

Explanation:

Screen clipping is a feature or application integrated into operating systems to grab or capture a snapshot of the current open window on the desktop. It could be an inbuilt feature like "Snipping Tool" which is seen in the Windows operating system by default (from Windows 7 and upward); this feature is however not restricted to only Windows operating systems. It could also be a third party app to capture onscreen processes.

Smart Art is a visual representation of data and information which is made by choosing a layout that best suits the information you are projecting.

Online Pictures

are ready resources (photographs) which are already available online; they have to be downloaded to be used.  

3D Models is the process of creating and developing a mathematical representation of data and information in three dimensions using specialized software. This help bring the data and information to life  

All these options (A - D) are good ways of enhancing a presentation. However, to get a snapshot of an onscreen process from the desktop, Option D (Screen Clipping) is the correct answer