A 85.0kg man and a 65, 0kg woman are riding a Ferris wheel with a radius of 20.0m. What is the Ferris wheels tangential velocity if the net centripetal force on the woman is 115N

Answers

Answer 1

Answer:

The Ferris wheel's tangential (linear) velocity if the net centripetal force on the woman is 115 N is 3.92 m/s.

Explanation:

Let's use Newton's 2nd Law to help solve this problem.

F = ma

The force acting on the Ferris wheel is the centripetal force, given in the problem: [tex]F_c=115 \ \text{N}[/tex].

The mass "m" is the sum of the man and woman's masses: [tex]85+65= 150 \ \text{kg}[/tex].

The acceleration is the centripetal acceleration of the Ferris wheel: [tex]a_c=\displaystyle \frac{v^2}{r}[/tex].

Let's write an equation and solve for "v", the tangential (linear) acceleration.

[tex]\displaystyle 115=m(\frac{v^2}{r} )[/tex][tex]\displaystyle 115 = (85+65)(\frac{v^2}{20})[/tex][tex]\displaystyle 115=150(\frac{v^2}{20} )[/tex][tex].766667=\displaystyle(\frac{v^2}{20} )[/tex][tex]15.\overline{3}=v^2[/tex][tex]v=3.9158[/tex]

The Ferris wheel's tangential velocity is 3.92 m/s.


Related Questions

AC 1. When a driver applies the brake of a light truck traveling a speed of 12 m/s it skids a distance of 3 m before stopping. How far will the truck skid if it is traveling at a speed of 24 is when the brakes are applied?​

Answers

vf²=vi²-2ad (vf = 0, stop)

12² = 2a.3

144 = 6a

a = 24 m/s²

24² = 2 x 24 x d

576 = 48d

d = 12 m

3- Which of the following represents a way through which thermal energy is transferred by direct contact?
a Conduction O
b. Radiation O
c. Convection O
d. Specific heat

Answers

Answer:

A. conduction

Explanation:

Conduction is the transfer of energy from one molecule to another by direct contact.

The crust is composed primarily of basalt and _____________.

Answers

Answer:

Granite

Explanation:

Trust me I learned this 2years ago

The displacement of a 500 g mass, undergoing simple harmonic motion, is defined by the function :
x=-3.5sin(π/2t+(5π)/4)

Find
a. maximum kinetic energy
b. maximum potential energy
c. maximum mechanical energy

Answers

The maximum kinetic energy, maximum potential energy and the maximum mechanical energy are equal to 7.56J.

What is simple harmonic motion?

Simple harmonic motion, in physics, repetitive movement back and forth through an equilibrium, or central, position, so that the maximum displacement on one side of this position is equal to the maximum displacement on the other side.

Simple Harmonic Motion

The given equation of the simple harmonic motion is

[tex]x=3.5 sin (\frac{\pi }{2t} + \frac{5\pi }{4} )[/tex]

Data;

ω = π/2

k = 1.254N/m

Solving this

[tex]\frac{dx}{dt} = -3.5 X \frac{\pi }{2} cos (\frac{x\pi t}{2}+\frac{5\pi }{4} )[/tex]

Let's calculate the maximum velocity.

[tex]V_{m} =\frac{3.5\pi }{2}[/tex]

This is only possible when cos θ = -1

The maximum kinetic energy is

[tex]K_m =\frac{1}{2} mv^2 = \frac{1}{2} X \frac{500}{1000} X \frac{7^2\pi ^2}^{4} ^2[/tex]

[tex]w^2 = \frac{k}{m} \\k = w^2m\\k = \frac{\pi ^2}{4} X \frac{500}{1000} \\k =1.254 N/m[/tex]

Using the value of spring constant, we can find the maximum potential energy.

[tex]P.E =\frac{1}{2} k x^2\\P.E =\frac{1}{2} X 1.234 X 3.5^2 \\P.E = 7.56 J[/tex]

The maximum potential energy is 7.56J

The maximum mechanical energy is equal to the sum of maximum potential energy and the maximum kinetic energy.

ME = K.E + P.E

ME = 7.56J

From the calculations above, the maximum kinetic energy, maximum potential energy and the maximum mechanical energy are equal to 7.56J.

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A particle q1 with the charge of 4.5x10-⁶C is fixed in the space from a distance of 3.7cm , a particle q2 of mass 6.9g and the charge of -3.10x10-⁶C is fired with the initial velocity of 60m/s toward the fixed charge. what is the velocity when it is 1cm away from the q1

Answers

The velocity of particle 2 when it is 1cm away from particle 1 is determined as 62.18 m/s.

Force between the charges

The electrostatic force between the two charges is calculated as follows;

F = (kq1q2)/(r²)

F = (9 x 10⁹ x 4.5 x 10⁻⁶ x 3.1 x 10⁻⁶)/(0.037)²

F = 91.71 N

Acceleration of the second particle

F = ma

a = F/m

a = (91.71 N)/(0.0069 kg)

a = 13,291.2 m/s²

Velocity of particle 2 at 1 cm from particle 1

v² = u² + 2as

v² = 60² + 2(13,291.2)(0.01)

v² = 3865.82

v = 62.18 m/s

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The drawing shows a crystalline slab (refractive index 2.043) with a rectangular cross section. A ray of light strikes the slab at an incident angle of θ1= 37.0°, enters the slab, and travels to point P. This slab is surrounded by a fluid with a refractive index n. What is the maximum value of n such that total internal reflection occurs at point P?

Answers

A drawing shows a crystalline slab (refractive index 2.043) with a rectangular cross-section, the maximum value of n   is mathematically given as

nm=1.627

What is the maximum value of n such that total internal reflection occurs at point P?

Generally, the equation for the snells law  is mathematically given as

[tex]n=\frac{sin \theta_1}{sin \theta_2}[/tex]

Therefore

[tex]\theta_2=sin-1(sin35/1.725)\\\\\theta_2=19.42[/tex]

From the image critical angle is

ic=90-19.42

ic=70.58

In conclusion, snells law for total internal reflection

[tex]gn=\frac{sinic}{sin90}[/tex]

sinic=nm/ng

nm=1.725*sin70.58

nm=1.627

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In sound, the wavelength of the sound
determines the __ of the sound.
A. Pitch
B. Volume
C.Length

Answers

Answer:

A) Pitch

Explanation:

Wavelength determines the pitch  ( or frequency which is 1/wavelength)

A contractor uses a paddle stirrer to mix a can of paint. The paddle turns at 27.6 rad/s and exerts a torque of 16.6 N•m on the paint, doing work on the paint at a rate of Power = 16.6 N•m × 27.6 rad/s = 458.2 W. An internal energy increase of 11.9 kJ causes the temperature of the paint to increase by 1.00K.

If there were no heat flow between the paint and surroundings, what would be the temperature change of the paint as it is stirred for 5.00 mins?​

Answers

P = W/t

t = W/P = 11.9 x 10³ : 458.2 = 25.971 s = 0.433 min

0.433 min = 1 K

so for 5 mins = 0.433 x 5 x 1 K = 2.165 K

“Jonny pulls his sister Jane (weight 28 lbs), who is sitting in a wagon, up an incline ramp (θ = 17°) with a steady speed. If the coefficient of kinetic friction is 0.18, the wagon has a mass of 14 kg, and the length of the ramp is 2.4 m, find: a) the work done by the frictional force. b) the work done by the gravitational force.“

Answers

(a) The work done by the frictional force is -33.1 J.

(b) The work done by the gravitational force is 175.58 J

Work done by frictional force

The work done by frictional force is calculated as follows;

W = -μmgsinθ x L

W = -μmgsinθ  x L

where;

m is mass of Jane and wagon

W = -0.18 x (12.7 + 14)9.8 x sin(17) x 2.4

W = -33.1 J

Work done by the gravitational force

W = mgh

W = mgcosθ  x h

W = mgcosθ  x Lsinθ

W = (26.7)(9.8)cos(17) x 2.4 x sin(17)

W = 175.58 J

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Which of the following is a disadvantage of renewable energy?
A. It creates large amounts of pollution
B. It could be costly to initially switch to.
C. It will not produce enough power to sustain us.
D. It will not run out.

Answers

Answer:

B. It could be costly to initially switch to.

A body moves in the east with the velocity of 25 m/s. Another body B moves in the same direction with a velocity of 10 m/s. If both of them had started from the same point then find :

i) The velocity of w .r. t. B.

ii) The distance covered by each in 30
seconds...

iii) The distance between them after 1
minute...

Please help....ty !!!
[tex].....[/tex]

Answers

Answer:

See below

Explanation:

i)     Velocity of A  wrt B is  15 m/s east

ii)    A   30 * 25 = 750 m east      B   30 *10 = 300 m east

iii)    1 minute will be    15 m/s * 60 = 900 m  apart

a machine is 12% efficient if useful work done by it is 6 joules what will be the total energy consumed by it

Answers

Since work is the change in kinetic energy, the efficiency of a machine can be stated as the percentage of the output work divided by the input work minus the work lost from to friction and heat. Multiply Eff by 100% to get the efficiency percentage.

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3. The height of a wave crest is called
a. wavelength.
c. amplitude.
b. frequency
d. energy

Answers

Answer:

C. Amplitude

Explanation:

The height of a wave crest is called Amplitude

Nisha stands at the edge of an aquarium 3.0 m deep. She
shines a laser at a height of 1.7 m that hits the water of the pool
8.1 m from the edge. How far from the edge of the pool will the light hit bottom?

Answers

It's denoting to a right angle traingle

Perpendicular=P=3+1.7=4.7mBase=B=8.1m

Hypotenuse we need

Apply Pythagorean theorem

H²=P²+B²H²=4.7²+8.1²H²=87.7H=9.4m

Explanation:

The graph of y = √x is reflected in the y-axis, is horizontally stretched by a factor of 2, shifted 3 units up and 1 unit left. What is the equation of the transformed graph?

Original: y = √(x)

Reflected in the y-axis: y = √(-x)

Horizontally stretched by a factor of 2: y = √(-x/2)

Shifted 3 units up: y = 3 + √(-x/2)

And 1 unit left: y = 3 + √(-(x+1)/2)

1. The Falcon Heavy rocket takes off with a constant net vertical force of 6.27 x 10^5
N. How much work does it do if it moves a distance of 144 km?

Answers

Explanation:

The formula for work is

[tex]w = |f| |d| \cos(x) [/tex]

where x is the angle between the displacement and force.

F is the force that is currently being active.

D is the displacement.

We only want our force and displacement to be positve so we use the absolute value sign.

Since the rocket and the displacement is both upwards, the signs. between them is 0.

So since

[tex] \cos(0) = 1[/tex]

We can just use that

[tex]w = |f| |d| [/tex]

First, we covert km to m.

[tex]144 \: km \times \frac{1000 \: m}{1 \: km} = 144000 m[/tex]

Now, we can multiply.

[tex]w = 14400 \: km \: \times (6.27 \times 10 {}^{5} )[/tex]

[tex]w = (1.44 \times 10 {}^{5} ) \times (6.27 \times 10 {}^{5} )[/tex]

[tex]w = 9.0288 \times 10 {}^{10} [/tex]

N times Meters = J so our answer is

[tex]w = 9.0288 \times 10 {}^{10} \: j[/tex]

A force of 124 newtons pushed a 12kg object forward 13 meters. How much work is being done?

Answers

Answer:

Work = Force * Distance

Here,

force = 124 N

distance = 13m

Thus, Work = 124 * 13 = 1612 joules(J)

A student lifts a physical science book off the table and above their head. Is there work being done?

Answers

Answer: A force must cause a displacement in order for work to be done. A book falls off a table and free falls to the ground. Yes. This is an example of work.

Explanation:

A (-8.8×10-20 C) charge is moving at (9.6×106 m/s) perpendicular a magnetic field. It
experiences a force of to (-5.2×10-16 N). What is the magnetic field strength?

6.2×10 -4 T
5.4×10 -15 T
3.2 ×10 -27 T
4.4×10 -20 T

Answers

The magnetic field strength will be 6.1 x 10⁻⁴ T.

What is magnetic field?

The magnetic field is the region of space where a charged object experiences magnetic force when it is moving.

The magnetic field strength is the magnitude of magnetic field in Tesla. It is related to velocity, magnitude of charge and force by the relation,

Magnetic force F = qVB

Given is the charge q = -8.8×10⁻²⁰ C, Force F = -5.2×10⁻¹⁶ N and the velocity v = 9.6×10⁶ m/s, then the magnetic field strength will be

B =  -5.2×10⁻¹⁶/-8.8×10⁻²⁰ x9.6×10⁶

B = 6.1 x 10⁻⁴ T

Thus, the magnetic field strength will be 6.1 x 10⁻⁴ T.

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A lamp has a voltage of 120 V across it and uses a current of 0.5A. What is the power used by the lamp?

Answers

Given the voltage of the lamp and the amount of current use, the power used by the lamp is 60Watts.

What is the power used by the lamp?

Power is the quantity of energy transferred per unit time. It can be expressed as;

P = v × I

Where v is voltage and I is current.

Given that;

Voltage v = 120VCurrent I = 0.5APower P = ?

P = v × I

P = 120V × 0.5A

P = 60Watts

Therefore, given the voltage of the lamp and the amount of current use, the power used by the lamp is 60Watts.

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Skater 1 has a mass of 80.0 kg and a velocity of 10.0 m/s to the right. He
collides with Skater 2, who has a mass 50.0 kg and a velocity of 5.0 m/s to
the left. After they collide, Skater 2 has a velocity of 15.0 m/s to the right
What is the final velocity of Skater 1?
O A. 16.3 m/s to the right
O B. 15.0 m/s to the left
O C. 2.5 m/s to the left
D. 2.5 m/s to the right
SUBMIT

Answers

The answer is c. 2.5 m/s to the left

a man weights 800n at the earth's surface. What will be the weight of the same person when he is orbiting the earth at double the high of the earth's center

Answers

Answer:

200 N

Explanation:

F = G m1 m2 / r^2      G  m1  and m2  are constant for this scenario

             so this becomes

F is proprtional to  1/r^2    

f = 1/r^2

800 = 1/r^2     now change  r  to 2r

  F = 1/(2r)^2 = 1/4 * 1/r^2    <======shows force will be 1/4 of original , or 200N

Alchemists searched for ways to change lead into gold. Which type of change
must occur for this conversion to happen?

Answers

Answer:

It's had to be a Nuclear change since by nuclear fusion we can convert lead to Gold.

Therefore Option B. Nuclear Change is Answer.

By : Modern Einstein

Nuclear, chemical relates to compounds and other things, physical is phase changes or mixing, nuclear is right because for lead to become cold the nucleus of the atom would have to change the amount of protons present

what is 7 times 7 times 7 plus 3

Answers

7 x 7 x 7 + 3 = 346

7 x 7 = 49 ; 49 x 7 = 343 ; 343 + 3 = 346

- A particular light source gives off light waves with a measured wavelength of
2.0 X 10-7m. What is the frequency of the light source?

Answers

Answer:

f = 1.5 x 10¹⁵ Hz

Explanation:

Light is an electromagnetic wave and we know that the speed of light is a constant which is 

3 x 10⁸ m/s.

Knowing this; v = λ x f

λ = wavelength

f= frequency of light

v = seed of light

f = v/λ

f =  3 x 10⁸m/s / 2.0 x 10-⁷ m

f = 1.5 x 10¹⁵ Hz

When two surfaces interact, some mechanical energy leaves the system as thermal energy due to ________.

Answers

Answer:

Friction

Explanation:

Friction is wasted energy in the form of heat and or destruction.....this is why combustion engines have oil lubriction ====>  reduce friction and wear

Velocity can be negative, but kinetic energy cannot. Why?

Answers

Because of the formula

Let's see

how

KE=1/2mv²

m is mass

v is velocity

as it's v²

Its must be greater than or equal to 0 ,

So kinetic energy can't be negative

Please just give me an answer, thanks.
1. task
The resistance of the light bulb is 0.4 kΩ. To what voltage is it connected if a current of 33 mA flows through it? The answer is rounded to the nearest whole number!
2. task
The length of the cable is 69 m, its cross-sectional area is 0.4 mm2. What material is the wire made of if its resistance is 86.3 Ω? Just give me the result of numbers, i'll find myself what material corresponds to those numbers
3. task
Calculate the resistance of the galvanometer if a current of 6 μA flows through it and the voltage is 7 mV! Round to the nearest whole number!

Answers

#1

[tex]\\ \rm\dashrightarrow P=VI\implies V=\dfrac{P}{I}[/tex]

[tex]\\ \rm\dashrightarrow V=\dfrac{0.4\times 10^3}{33\times 10^{-3}}[/tex]

[tex]\\ \rm\dashrightarrow V=0.012\times 10^{-6}[/tex]

[tex]\\ \rm\dashrightarrow V=12mV[/tex]

#2

[tex]\\ \rm\dashrightarrow R=\rho \dfrac{\ell}{A}[/tex]

[tex]\\ \rm\dashrightarrow \rho =\dfrac{RA}{\ell}[/tex]

[tex]\\ \rm\dashrightarrow \rho=\dfrac{86.3(0.4\times 10^6)}{69}[/tex]

[tex]\\ \rm\dashrightarrow \rho=0.5\times 10^{6}[/tex]

It should be silicon

#3

Ohms law

[tex]\\ \rm\dashrightarrow R=\dfrac{V}{I}[/tex]

[tex]\\ \rm\dashrightarrow R=\dfrac{7(10^3)}{6(10^{-6})}[/tex]

[tex]\\ \rm\dashrightarrow R=1.167\times 10^9\Omega[/tex]

During which weeks of the moon cycle does the moon appear to be getting smaller

Answers

Answer:

Since the illuminated side of the moon appears to be getting smaller in size (after the full moon), the moon is said to be in the "erosion phase". For the next 7 days, the moon will remain in an “eroded gibbous stage”.

Explanation:

If ⃗ is the vector sum of ⃗ and ⃗⃗, ⃗ = ⃗ + ⃗⃗, what must be true about the directions and magnitudes of ⃗ and ⃗⃗ if = + ? What must be true about the directions and magnitudes of ⃗ and ⃗⃗ if = 0?

Answers

The magnitude of the vector sum of 2x and 3y is determined as 3.6 units and the direction is 56.3⁰.

Magnitude of the vector

The magnitude of two vectors is determined using the following formula;

[tex]|V| = \sqrt{V_x^2 + V_y^2}[/tex]

Let the sum of the vector = 2x + 3y

The magnitude of the vectors is calculated as follows;

[tex]|V| = \sqrt{2^2 + 3^2} \\\\|V| = 3.6 \ units[/tex]

Direction of the vectors

The direction of the vectors is calculated as follows;

[tex]tan(\theta) = \frac{V_y}{V_x} \\\\tan(\theta) = \frac{3}{2} \\\\tan(\theta) = 1.5\\\\\theta = tan^{-1} (1.5)\\\\\theta = 56.3 \ ^0[/tex]

Thus, the magnitude of the vector sum of 2x and 3y is determined as 3.6 units and the direction is 56.3⁰.

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6) If the mass of an object is 28kg and the gravitational force is 18G, what is the gravitational force of an object
that has half the mass?
a. 14kg
b. 56kg
C. 9G
d. 36G

Answers

Answer:

The gravitational force of an object that has half the mass is C) 9G.

Explanation:

Newton's Law of Gravitation:

[tex]\displaystyle F_g=G\frac{Mm}{r^2}[/tex]

We can see that the gravitational force, [tex]F_g[/tex], and mass (let's combine M * m into just "m"), [tex]m[/tex], are directly proportional to each other.

This means that if [tex]F_g[/tex] increases, [tex]m[/tex] also increases.

Therefore, if the mass is halved, that means that the gravitational force is also going to be halved.

The answer is 18G / 2 = 9G, which corresponds to answer C) 9G.

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