5.00 μF, 10.0 μF, and 50.0 μF capacitors are connected in series across a 12.0-V battery.
(a) How much charge is stored in the 5.00-μF capacitor?
(b) What is the potential difference across the 10.0-μF capacitor?

He would measure the speed of molecules as the temperature gets colder until the temperature is measured at which motion stops(option A).

The absolute zero refers to the temperature at which the gas seems to stop moving. Recall that temperature is the measure of the average kinetic energy of the molecules of a gas. We now have to consider the options and see the one that connects temperature and speed of molecules.

Hence, if Guillaume Amontons first took a stab at measuring absolute zero in 1702, he would measure the speed of molecules as the temperature gets colder until the temperature is measured at which motion stops.

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An object, which weighs 98 N on the surface of Earth, weigh on this point is 2.23 x 10²⁴ kg.

The force of attraction felt by a person at the center of a planet or Earth is called as the gravity.

Given, the Earth has the acceleration due to gravity, g =  9.81 m/s².

Force of gravity W = mass x acceleration due to gravity

98N = m x 9.8m/s²

m = 10 kg

The value of acceleration due to gravity (g) on a point 10,000 km above sea level is about 1.49 m/s².

The acceleration due to gravity and mass is related as

g = GM/R²

where G = gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg² and R is the distance between two masses.

Substituting the values, we get

1.49 m/s² =  6.67 x 10⁻¹¹ N.m²/kg² x M/ (10000 x 10³ m)²

M = 2.23 x 10²⁴ kg

Therefore, an object will weigh on this point is 2.23 x 10²⁴ kg

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The net force on the crate will be 99 N.Option B is correct.

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N). it is defined as the product of the coefficient of friction and normal reaction.

On resolving the given force and acceleration.Mathematically in the different components and balancing the equation gets.Components in the x-direction.

When all the forces get resolved the y-direction of forces are;

300 sin 10° +N = 445

N = 445-295.4

N = 392.9 N

The normal force is 392.9 N.

The net force on the crate is found by resolving the force in the x-direction;

F = 300 cos 10° - μN

F= 295.44-196.45

F= 98.99

F=99

Hence, the net force on the crate will be 99 N.Option B is correct.

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Answer:

54.0 x0.1=5.4 x0.03=0.162

kinetic force

If a contestant in a winter games event pushes a 54.0 kg block of ice across a frozen lake. The coefficient of static friction is 0.1 and the coefficient of kinetic friction is 0.03, then the minimum force F he must exert to get the block moving would be 5.2974 Nwrons.

Friction is a type of force that resists or prevents the relative motion of two physical objects when their surfaces come in contact.

As given in the problem, If a contestant in a winter games event pushes a 54.0 kg block of ice across a frozen lake. The coefficient of static friction is 0.1 and the coefficient of kinetic friction is 0.03,

The force required to get the block moving = μMg

                                                                          = 0.01×54×9.81

                                                                         = 5.2974 Newtons

Thus, the minimum force required to move the block would be 5.2974 Newtons.

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Answer:

enable us to take in a wide variety of information, and process it based on our past experience and values.

Explanation:

The true statement about the accuracy and precision of measuring tools is Tools cannot be both accurate and precise. The correct option is C.

When in an experiment, a value is measured 5 times, then if the values measured are same for most of the time or like three times out of five, it said to be accurate. The phenomenon is accuracy.

Precision is about comparing the values to each other then find them near to each other.

Accuracy compares the experimental value to the theoretical value.

So, when all the values are close to each other but not nearest to the theoretical value, then it is said to be precise but not accurate.

Thus, the correct option is C.

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The charge on each sphere is 742 n

In physics, Charge, also known as electric charge is a electrical charge, or electrostatic charge and symbolized q, is a characteristic of a unit of matter that expresses the extent to which it has more or fewer electrons than protons.

According to the question,

Distance = 15cm or 0.15m

Force =  0.22N

[tex]K=9*10^{9} kgm^2/c^2[/tex] ( this is a constant value of K)

By using the formula,

F = [tex]\frac{kQq}{d^{2} }[/tex]

0.220 N = 8.99

N·m²/C² * Q² / (0.15m)²

Q = 7.42e-7

C = 742 n

C is the charge of each sphere .

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Answer:

1. 92, 138, 92

2. 7, 7, 7

3. 17, 18, 17

4. 29, 34, 29

Explanation:

the number on the bottom is always going to be the atomic number, or the number of protons.

the number on the top is going to be the atomic mass number, which is the sum of the number of protons and neutrons.

there is always going to be the same number of electrons as protons, because that was the overall charge of each atom is 0.

for example, for the first one:

there are 92 protons

there are 230 - 92 = 138 neutrons

there are 92 electrons

The acceleration of this sled can be calculated by doing: option A, B, E and F.

The acceleration of this sled can be calculated by using Newton's Second law of motion. Mathematically, the acceleration of an object is given by this formula:

Net force = Mass × acceleration

Deductively, the acceleration of this sled can be calculated by doing the following:

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Complete Question:

A sled is moving down a steep hill. The mass of the sled is 50 kg and the net force acting on it is 20 n. What must be done to find the acceleration of the sled? check all that apply.

A. The force of gravity must be broken into its parallel and perpendicular components.

B. Acceleration can be found by dividing the net force by mass.

C. Acceleration can be found by multiplying the net force by mass.

D. The magnitude of the force components must be multiplied by gravity.

E. Trigonometry can be used to solve for the magnitude of the force components.

F. Net force must be found before acceleration can be found.

Answer:

To find the acceleration, you do 20N/50kg = 0.4 m/s^2

Explanation:

example: a = F/m = 10/2 = 5 m/s2

(a) The acceleration of the two block is determined as 0.93 m/s².

(b) The tension in the string is 5.78 N.

The net force on the aluminum block is calculated as follows;

[tex]T - \mu_a m_a g = m_a a \ --- \ (1)[/tex]

The net force on the copper block is calculated as follows;

[tex]m_cg sin(30) - T -\mu _cm_c gcos(30) = m_c a --- (2)[/tex]

where;

Solve for T using (1) and (2)

[tex]a = g(\frac{m_c sin30\ - \ \mu _c m_c cos30 \ - \mu_ a m_a}{ma_a + m_c} )\\\\a = 9.8(\frac{6 sin30\ - \ 0.2 (6) cos30 \ - 0.2 (6)}{2 +6} )\\\\a = 0.93 \ m/s^2[/tex]

From equation (1);

T = μm_ag + m_aa

T = 0.2(2)(9.8) + 2(0.93)

T = 5.78 N

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there is no pic or whatever to show

Answer:

D. 3 cm

Wavelength is the distance between two crests or two troughs.

In the given picture, the distance between two adjacent crests is 3 cm.

Hence, the wavelength is 3 cm.

(a) The time spent in the air by the ball is 1.5 seconds.

(b) The horizontal distance of the ball is 9.83 m.

(c) The impact speed of the ball is 20.37 m/s.

(2) The magnitude of the force is 253.5 N in horizontal direction.

The time of motion of the ball is calculated as follows;

h = vt + ¹/₂gt²

18 = 8sin(35)t + (0.5)(9.8)t²

18 = 4.589t + 4.9t²

4.9t² + 4.589t - 18 = 0

solve the quadratic equation using formula method,

t = 1.5 s

X = vcosθ(t)

X = 8cos(35) x 1.5

X = 9.83 m

vyf = vyi + gt

vyf = 8sin(35) + 9.8(1.5)

vyf = 19.289 m/s

vxf = vxi

vxf = 8 x cos(35)

vxf = 6.55 m/s

Resultant speed = √(19.289² + 6.55²) = 20.37 m/s

F = ma

F = 65 x 3.9

F = 253.5 N

Since the motion is horizontal, the angle of the motion is zero.

Fx = 253.5cos(0) = 253.5 N

Fy = 253.5sin(0) = 0 N

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Gravity and normal forces act on the toy car.

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The distance from the rounded tip of the plate to the center of mass is 1.87 m.

The center of mass is a point inside or outside the mass where all of the mass is concentrated.

The y-coordinate of the centroid is given by the ratio of two definite integrals;

Yc = ∫ydm/∫dm,

where dm is a density function

For the uniform plate, δ does not change with position in the plate.

Yc = ∫yδdA/∫δdA

Yc = ∫ydA/∫dA.

dA is a horizontal slice of the plate with dimensions xdy.

Solving the parabola for x,

y = 0.5x²

x = ± √(y/0.50), where the negative value corresponds to the left half of the parabola and the positive to the right half.

dA = (√(y/0.50)

     = √(y/0.50))dy

     = 2(√(y/0.50))dy

The limits of integration are from zero to 1.870, the top of the plate.

∫ydA = ∫2y√(y/0.50)dy = 7.232 m³

∫dA = ∫2√(y/0.50)dy = 3.868 m²

∫ydA/∫dA =  7.232 m³/3.868 m²

∫ydA/∫dA =  1.869700 m

∫ydA/∫dA =   1.87 m

Thus, the distance from the rounded tip of the plate to the center of mass is 1.87 m.

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The car's acceleration will be 0.575 m/s².The unit of acceleration is m/sec².

The rate of velocity change concerning time is known as acceleration.

Given data;

Initial velocity, u= 0 m/s

Final velocity, v= 4.2 m/s

Time elapsed, t = 7.3 seconds.

To find ;

Acceleration, a

The acceleration when the change in velocity is observed by the formula as:

a= (v-u)/(t)

Substitute the given values:

a= (4.2-0)/(7.3)

a=(4.2)/(7.3)

a= 0.575 m/s²

Hence, the car's acceleration will be 0.575 m/s².

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Hence, the time required is approximately equal to 4 minutes and 39 seconds.

Given, Power, P = 300 W= 300J/s

Power= Energy per second

Mass, m= 0.25 kg

Initial Temperature= 20.0°C

Final Temperature= 100.0°C

Temperature difference, T =( 100-20)°C= 80.0°C

Specific heat of water, S= 4184 J/kg°C

Energy can be represented as

E=mST

where E is the energy, m is the mass, S is the specific heat of water and T is the temperature difference.

As Energy can be written as the product of time and power, E=Pt

Pt=mST

So,

t=(msT)/P

t=(0.25×4184×80)/300

Time, t = 278.934 seconds= 4 minutes and 39 seconds.

Hence, 4 minutes and 39 seconds will be required for a 300.0 W immersion heater to heat 0.25 kg of water from 20.0°C to 100.0°C.

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The minimum stopping distance when the car is moving at 32.0 m/s is 348.3 m.

The acceleration of the car before stopping at the given distance is calculated as follows;

v² = u² + 2as

when the car stops, v = 0

0 = u² + 2as

0 = 15² + 2(76.5)a

0 = 225 + 153a

-a = 225/153

a = - 1.47 m/s²

If the same force is applied, then acceleration is constant.

v² = u² + 2as

0 = 32² + 2(-1.47)s

2.94s = 1024

s = 348.3 m

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C. The Densities are equal.

Density is mass per unit volume or mass of a unit volume of a material substance.

If m1, V1 and D1 = mass, volume  and density respectively of ball C

m2, V2 and D2 = mass, volume and density respectively of ball D

According to the Question ,

[tex]V_{1} = 3V_{2} , m_{2} = \frac{1}{3} (m_{1} ) \\ \\= m_{1} = 3m_{2}[/tex]

Therefore,

[tex]\frac{D_{1} }{D_{2} } = (\frac{m_{1} }{V_{1} } )* (\frac{m_{2} }{V_{2} } )\\ \\= (\frac{3m_{2} }{3V_{2} })*(\frac{V_{2} }{m_{2} }) \\\\= 1[/tex]

Hence, D1 = D2

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The time for which the baseball remains in the air will be 9.37 sec. Option C is correct.

It is the height achieved by the body when a body is thrown at the same angle and the body is attaining the projectile motion.

From Newton's first equation of motion;

[tex]\rm v_y= u_y+gt \\\\ 0 = usin \theta - gt \\\\ t = \frac{u sin\theta }{g}\\\\t = 4.68 \ sec[/tex]

The time the baseball remains in the air will be twice the time he travels for one side motion;

T' = 2t

T'=2 × 4.68 sec

T'= 9.37 sec

Hence for 9.37 sec, the baseball willl remains in the air. Option C is correct.

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The total time required is 1 minute and 0.3 seconds.

Assumption: The distance between the people is 1 m and the stadium is a circle with a radius of 100m.

Here, the time taken by the person is 0.1 seconds.

Total distance covered by the wave = Circumference of the circle

So, total distance = 2 πr = 2 × 3.14 × 100 = 618 m

As the distance between each of the people is 1 m.

So, the number of personal interactions is 618.

Time taken by each person is 0.1 seconds.

So, total time, t = 0.1 × 618 = 61.8 seconds.

So, the order of the magnitude of the time required is 1 minute and 0.3 seconds for such a pulse to make one circuit around BC Place Stadium in Vancouver.

Hence, the total time required is 1 minute and 0.3 seconds.

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The Total assets based on the given table is $88,800.

An asset refers to a resource owned by an individual or company which has tangible value and whose value is expected to rise in the future.

The Total assets based on the table = Cash + Supplies + Prepaid rent + Equipment

Total assets = 13,100 + 6,000 + 3,800 + 65,900

Total assets = $88,800

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By using an electric field, it is feasible to differentiate between these different forms of radiation.

A source that emits radiation like gamma, beta, and alpha rays is said to be radioactive. Using an electric field, we can discriminate between these different forms of radiation.

The field does not deflate the gamma rays, but it does deflate the alpha and beta rays, with the alpha being deflated to the field's negative portion and the beta to its positive part.

Hence, by using an electric field, it is feasible to differentiate between these different forms of radiation.

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Answer:

the answer to the question is a reflector

[tex]\textsf {C. Force}[/tex]

[tex]\textsf {The quantity which is represented by a unit called Newton (N)}\\\textsf {is Force.}[/tex]

Answer:equal mass

Explanation:the mass of both is 5kg

Answer:

Explanation:

Hope I give all correct answer please mark as brainlest answer

Answer:

A 2kg block is moved a long a level floor by a horizontal force of 20N if the coefficient of sliding friction is 0.4

what is the acceleration of the blove

To deliver more power or voltage in the circuit use a battery with more current rating which is 1000 mAh.

The power generated in a circuit is directly proportional to the current flowing in the circuit.

P = IV

where;

Voltage in the circuit also increases with increase in the current flowing in the circuit.

Thus, to deliver more power or voltage in the circuit use a battery with more current rating which is 1000 mAh.

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Explanation:

this is the answer 276 volts