Find the range of f(x) = 3x + 2 for the domain = {1, 2, 3}.

Using tally marks make a table of the given subjects English (4), Urdu (3), Maths (4), Science (3) and Computer (2).

The given data are English, Maths, Urdu, Science, English, Urdu, Science, Maths, English, Computer, Maths, Urdu, Science, Maths, Computer, and English.

A table is an arrangement of information or data, typically in rows and columns, or possibly in a more complex structure. Tables are widely used in communication, research, and data analysis.

The data table for the given data is given below:

Thus, using tally marks make a table of the given subjects English (4), Urdu (3), Maths (4), Science (3) and Computer (2).

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Answer:

huh

Step-by-step explanation:

A person can immigrate to another country for educational purposes.

A person can emigrate to another country for work.

A person can emigrate to another country due to war in their own country.

Migration is when a person moves from one geographical location or another. Immigration and emigration are types of migration.

Immigration is when a person moves to a foreign country. For example, when a US citizen moved to Italy for work. Emigration is when a person lives his home country.

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Answer:

1

Step-by-step explanation:

the number of solutions corelatea with number of cross-points in the graphs, in our exame, 1 point, hence 1 solution

The function values are f(1) = -3, f(-2) = -12, f(x + 4) = 3x + 6

The problem is incomplete. The complete problem is

Find the function value, if possible. (If an answer is undefined, enter UNDEFINED.) f(x) = 3x − 6

(a) f(1)

(b) f(−2)

(c) f(x + 4)

We have

(a) f(1) = 3 (1) - 6 = 3 - 6 = -3

(b) f(-2) = 3(-2) - 6 = -12

(c) f(x + 4) = 3(x + 4) - 6 = 3x + 6

So, the evaluations are f(1) = -3, f(-2) = -12, f(x + 4) = 3x + 6

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Answer:

( 8x - 4 ) ( x - 2 )

Step-by-step explanation:

8x² - 12x - 8

8x² - 16x + 4x - 8

8x ( x - 2 ) - 4 ( x - 2 )

( 8x - 4 ) ( x - 2 )

Answer:

⇒ [tex]4(x-2)(2x+1)[/tex]

Step-by-step explanation:

1) Common factor

⇒ [tex]8x^2-12x-8\\[/tex]

⇒ [tex]4(2x^2-3x-2)[/tex]

2) Use the sum-product pattern

⇒ [tex]4(2x^2-3x-2)[/tex]

⇒ [tex]4(2x^2+x-4x-2)[/tex]

3) Common factor from the two pairs

⇒ [tex]4(2x^2+x-4x-2)[/tex]

⇒ [tex]4(x(2x+1)-2(2x+1))[/tex]

4) Rewrite in factored form

⇒ [tex]4(x(2x+1)-2(2x+1))[/tex]

⇒ [tex]4(x-2)(2x+1)[/tex]

The 40-year-old should have $76800 in capital. The 35-year-old should be saving $$10,320 for retirement.

The capital that a 40 year old has to have with an income of 32000 is

capital income at age 40 * income

= 2.4 * 32000

Capital = $76800

b. At 35 the savings income has to be

percentage of savings income * income

= 12% * $86000

= $10,320

c. There is no specified value for education earnings.

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Answer:

science type of food group : fibre

Answer:

C

Step-by-step explanation:

Comment

The square root of 48 is nowhere near 12. That means that A and D are wrong. On a test that's an important consideration because if you have to guess, you've just cut the possibilities down to 2.

So the answer must  be B or C. Furthermore, you don't have to go to the trouble of factoring 48 to show that it is 4 sqrt(3). There's no other choice.

So what about x^5. 5 is an odd number. That means that one of the xs is left underneath the square root sign. That makes B incorrect. Without doing a calculation, I know that C is the answer.

Note

x^5 = x * x * x * x * x

The rule is for ever 2 factors that are the same, 1 factor is put in front of the square root sign and the other 1 is thrown out.

√x^5 = √x * x * x * x * x  = x * x √x

Therefore the answer to the problem is 4 x * x√3 x = 4x^2√3x

Answer:

5/18

Step-by-step explanation:

The LCD of 9, 3, and 6 is 18.

1 - 2/9 - 1/3 - 1/6 =

= 18/18 - 4/18 - 6/18 - 3/18

= 5/18

Answer: 5/18

Step-by-step explanation:

1/1 - 2/9 - 1/3 - 1/6

18 - 4 - 6 - 3/18

5/18

1≥2x and 6x≥3+8x-4 are correct representations of the inequality 6x ≥ 3 + 4(2x – 1).Option A,B and C are correct.

Inequality is a sort of equation in which the equal sign is missing. As we will see, inequality is defined as a statement regarding the relative magnitude of two claims.

The solution to the given inequality is;

6x≥3+4(2x-1)

6x≥3+8x-4

2x≤1

x≤(1/2)

The correct options are;

A)1 ≥ 2x

B)6x ≥ 3 + 8x – 4

C)A number line from negative 1.5 to 1.5 in increments of 0.5. A point is at 0.5 and a bold line starts at 0.5 and is pointing to the left.

1≥2x and 6x≥3+8x-4 are correct representations of the inequality 6x ≥ 3 + 4(2x – 1).

Hence, options A, B, and C are correct.

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Answer:

A, B, C

Step-by-step explanation:

Observe the diagram below with indexes on the shapes.

The transformations are:

Answer:

[tex]\fbox {D. ray}[/tex]

Step-by-step explanation:

A part of a line that starts at one endpoint and extends forever in one direction is a ray.

Answer: D. Ray

Step-by-step explanation:

Let's do the process of elimination.

It's not A because there is only one line.

It is not B because a point is only a dot.

It is not C because a line extends forever from BOTH ends.

The correct answer is D because a ray starts on one endpoint and extends forever in one direction.

I hope this helps!! Pls mark brainliest!! :)

Teniendo en cuenta la regla de tres simple, el cartero reparte 64.200 cartas en un semestre.

La regla de tres es una forma de resolver problemas de proporcionalidad entre tres valores conocidos y un valor desconocido, estableciendo una relación de proporcionalidad entre todos ellos.

Es decir, lo que se pretende con ella es encontrar el cuarto término de una proporción conociendo los otros tres.

Si la relación entre las magnitudes es directa, es decir, cuando una magnitud aumenta, la otra también (o cuando una magnitud disminuye, la otra también), se debe aplicar la regla de tres directa.

Para resolver una regla de tres directa se debe seguir la siguiente fórmula, siendo a, b y c datos conocidos y x la variable a calcular:

a ⇒ b

c ⇒ x

Entonces: [tex]x=\frac{cxb}{a}[/tex]

En este caso, se puede aplicar la regla de tres de la siguiente manera: Entonces, si el cartero en un mes reparte 10.700 cartas, ¿en 6 meses (un semestre) reparte cuántas cartas?

1 mes ⇒ 10.700 cartas

6 meses ⇒ ×

Entonces: [tex]cantidad de cartas=\frac{6 mesesx10.700 cartas}{1 mes}[/tex]

Resolviendo:

cantidad de cartas= 64.200 cartas

En resumen, el cartero reparte 64.200 cartas en un semestre.

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Answer:

(0,-2)

Step-by-step explanation:

y intercept is that line that intercepts with the y axis

when x is 0 then y value.

hello hello hello

Step-by-step explanation:

hi hi hi

Step-by-step explanation:

First she will start by mutiplying the two numbers.

Answer:

see below

Step-by-step explanation:

The graph is shifted to the RIGHT so it will be a   ' x-1'

and it is shifted UP 3 units  so:

Looks like    log3 (x-1) + 3

   at x = 4 the value of the graph is 4

            log3 (4-1) + 3 = 4    CHECK !

Answer:

h = 17.5 m

Step-by-step explanation:

We have 2 similar right triangles as models of the situation

one has legs with George's height and shadow

the other is the height h of the tree and length of it's shadow

the corresponding sides of the 2 triangles are in proportion, that is

[tex]\frac{6.25}{h}[/tex] = [tex]\frac{10}{28}[/tex] ( cross- multiply )

10h = 175 ( divide both sides by 10 )

h = 17.5 m

Answer:

See below

Step-by-step explanation:

3 and 5     have a LCM of 15    which is  3 * 5

[tex]\boxed{\sf x = \dfrac{c}{b} \quad or \quad \dfrac{-b}{a}}[/tex]

Explanation:

Given expression: (ab)x^2 + (b^2 - ac)x + (-bc) = 0

Here given:

Apply quadratic formula:

[tex]\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \quad when \ ax^2 + bx + c = 0[/tex]

Insert values:

[tex]\sf x = \dfrac{-(b^2 - ac) \pm \sqrt{(b^2 -ac)^2-4(ab)(-bc)} }{2(ab)}[/tex]

[tex]\sf x = \dfrac{-b^2 + ac \pm \sqrt{\left(b^2-ac\right)^2+4abbc} }{2ab}[/tex]

[tex]\sf x = \dfrac{-b^2 + ac \pm \sqrt{b^4+2b^2ac+a^2c^2} }{2ab}[/tex]

[tex]\sf x = \dfrac{-b^2 + ac \pm \sqrt{\left(b^2+ac\right)^2} }{2ab}[/tex]

[tex]\sf x = \dfrac{-b^2 + ac \pm( b^2+ac )}{2ab}[/tex]

[tex]\sf x = \dfrac{-b^2 + ac +( b^2+ac )}{2ab} \quad or \quad \dfrac{-b^2 + ac -( b^2+ac )}{2ab}[/tex]

[tex]\sf x = \dfrac{2ac}{2ab} \quad or \quad \dfrac{-2b^2}{2ab}[/tex]

[tex]\sf x = \dfrac{c}{b} \quad or \quad \dfrac{-b}{a}[/tex]

Apply quadratic formula:

[tex]\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a} [/tex]

[tex]\\ \sf\Rrightarrow x = \dfrac{-(b^2 - ac) \pm \sqrt{(b^2 -ac)^2-4(ab)(-bc)} }{2(ab)}[/tex]

[tex]\\ \sf\Rrightarrow x= \dfrac{-b^2 + ac \pm \sqrt{\left(b^2-ac\right)^2+4abbc} }{2ab}[/tex]

[tex]\\ \sf\Rrightarrow x = \dfrac{-b^2 + ac \pm \sqrt{b^4+2b^2ac+a^2c^2} }{2ab}[/tex]

[tex]\\ \sf\Rrightarrow x = \dfrac{-b^2 + ac \pm \sqrt{\left(b^2+ac\right)^2} }{2ab}[/tex]

[tex]\\ \sf\Rrightarrow x = \dfrac{-b^2 + ac \pm( b^2+ac )}{2ab}[/tex]

[tex]\\ \sf\Rrightarrow x = \dfrac{-b^2 + ac +( b^2+ac )}{2ab} \quad or \quad \dfrac{-b^2 + ac -( b^2+ac )}{2ab}[/tex]

[tex]\\ \sf\Rrightarrow x = \dfrac{2ac}{2ab} \quad or \quad \dfrac{-2b^2}{2ab}[/tex]

[tex]\\ \sf\Rrightarrow x = \dfrac{c}{b} \quad or \quad \dfrac{-b}{a}[/tex]

Answer:

5/6

Step-by-step explanation:

cuz there's 6 sides and there are 5 more sides than the 1

The correct answer is :  [tex]\frac{5}{6}[/tex]

Step-by-step explanation:

a die has 6 sides.

each side has a number 1-6

The chance of it rolling a number greater than one is 5 chances per 6 options or 5/6

The correct option for the given vector is the third one:

If the initial point is (0, 0), then the component form of the vector is just equal to the terminal point of the vector.

Then we have:

u = (5, -8)

For a vector w = (x, y) the magnitude is:

[tex]||w|| = \sqrt{x^2 + y^2}[/tex]

In this case, the magnitude will be:

[tex]||u|| = \sqrt{5^2 + (-8)^2} = \sqrt{89}[/tex]

Then the correct option is the third one.

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Answer:

A. [tex]\frac{5}{9}[/tex]

Step-by-step explanation:

To find f(-2) in f(x)=5*3^x, plug in -2 into all the x values.

f(-2)=5*3^-2, you can use calculator to calculate 3^-2 which equals 0.1, forever 1's.

f(-2)=5*0.1=0.5  Forever 5's.

f(-2)=0.5 or [tex]\frac{5}{9}[/tex]

Hope this helps!

If not, I am sorry.

From the power rules, the matching of  each expression with its result is:

[tex](8.6*10^7)(9.1*10^{-8})=7.8[/tex]

[tex](6.9*10^5)(4.8*10^{-3})=3.3*10^3[/tex]

[tex]\frac{(3.7*10^2)*(4.6*10^{-3})}{(1.4*10^{-6})*(5.7*10^{8})} =2.1*10^{-3}[/tex]

[tex]\frac{(3.1*10^5)*(5.3*10^{-9})}{(7.3*10^{2})*(6.1*10^{-7})}=3.7[/tex]

There are different power rules, see some them:

1. Multiplication with the same base: you should repeat the base and  add the exponents.

2. Division with the same base: you should repeat the base and  subctract the exponents.

3.Power. For this rule, you should repeat the base and multiply the exponents.

4. Zero Exponent. When you have an exponent equals to zero, the result must be 1.

From this for your question, you have:

[tex]\frac{(3.7*10^2)*(4.6*10^{-3})}{(1.4*10^{-6})*(5.7*10^{8})} =\frac{(3.7*4.6)*(10^2*10^{-3})}{(1.4*5.7)*(10^{-6}*10^{8})} =\frac{17.02*10^{-1}}{7.98*10^2} =2.13*10^{-3}=2.1*10^{-3}[/tex]

[tex]\frac{(3.1*10^5)*(5.3*10^{-9})}{(7.3*10^{2})*(6.1*10^{-7})}=\frac{(3.1*5.3)*(10^{5}*10^{-9})}{(7.3*6.1)*(10^{2}*10^{-7})} =\frac{16.43*10^{-4}}{44.53*10^{-5}}=0.36896*10^1=3.7[/tex]

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Answer:138,336

Step-by-step explanation:Because one mile=5280 so that takes out a and d but then just multiply 26.2 and 5280 equals 138,336 hope this helps

138,336 feet is equivalent to 26.2 miles.

Hence, Option C is correct.

Given that,

Length of standard marathon = 26.2 miles

We have to calculate the length of it into feet

Since we know that,

A measurement unit is a standard quality used to express a physical quantity. Also it refers to the comparison between the unknown quantity with the known quantity.

Since we know that

1 miles = 5280

Now to find the length of standard marathon in feet,

Multiply 5280 with 26.2.

Hence the length of marathon in feet,

= 5280 x 26.2

= 138,336 feet.

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It has been proved that point A is equidistant from the sides of angle PQR.

Any line or point that divides an angle or a side in equal parts is called a Bisector.

It is given that

Point A is the bisector of Angle PQR

Referring to the image

1. QA is the bisector of angle PQR : Given

2.Angle PQA = Angle RQA : Definition of Bisector

3.Angle QXA = Angle QYA : Definitions of Perpendicular

4. Angle QXA = Angle QYA : All right angles are congruent.

5. QA ≅QA :  Reflexive Property of Congruence

6. ΔPQA ≅ΔRQA : AAS Congruence Postulate

7. AX ≅AY  Corresponding parts of Congruent Triangles

8. Point A is equidistant from the sides of Angle PQR : Definition of equidistant.

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Answer:

[tex]2y - 8x = 3[/tex]

Step-by-step explanation:

[tex]y - 4x = 9[/tex]

[tex]2y - 8x = 18[/tex]

So 2y - 8x = 3 is parallel to y - 4x = 9.

Answer:

A

Step-by-step explanation:

Angles 1 and 3 are congruent since they are vertical angles.

Angle 7 is congruent to angle 3 since they are corresponding angles.

Angle 5 is congruent to angle 1 since they are corresponding angles.

Answer: A

The perimeter of the triangle is 21.4 units

The points are given as:

A(−2,2), B(5,−3), and C(−4,−1)

Calculate the side lengths using:

[tex]d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2[/tex]

So, we have:

[tex]AB = \sqrt{(-2 -5)^2 + (2 + 3)^2} = 8.6[/tex]

[tex]AC = \sqrt{(-2 +4)^2 + (2 + 1)^2} = 3.6[/tex]

[tex]BC = \sqrt{(5+4)^2 + (-3 + 1)^2} = 9.2[/tex]

The perimeter is then calculated as:

P = AB + AC + BC

This gives

P = 8.6 + 3.6 + 9.2

Evaluate

P = 21.4

Hence, the perimeter of the triangle is 21.4 units

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