1. (a) The life time of a certain brand of bulbs produced by a company is normally distributed, with mean 210 hours and standard deviation 56 hours. What is the probability that a bulb picked at random from this company’s products will have a life time of:
(i) (ii) (iii) at least 300 hours,
at most 100 hours, between 150 and 250 hours.
(b) In a contest, two friends, Kofi and Mensah were asked to solve a problem. The probability that Kofi will solve it correctly is and the probability that Mensah
will solve it correctly is . Find the probability that neither of them solved it correctly.
2. Suppose that the random variable, X, is a number on the biased die and the p.d.f. of X is as shown below;
X
1
2
3
4
5
6
P(X=x)
1/6
1/6
1/5
k
1/5
1/6
a) Find;
(i) (ii) (iii) (iv) (v) the value of k. E(X)
E(X2) Var(X) P(1 £X <5)
b) If events A and B are such that they are independent, and P(A) = 0.3 with P(B) = 0.5;
i. ii. Find P(A n B) and P(AUB)
Are A and B mutually exclusive? Explain.
c) In how many ways can the letters of the word STATISTICS be arranged?
Answers
Answer:
See explanation
Step-by-step explanation:
Q1)a
- Denote a random variable ( X ) as the life time of a brand of bulb produced.
- The given mean ( μ ) = 210 hrs and standard deviation ( σ ) = 56 hrs. The distribution is symbolized as follows:
X ~ Norm ( 210 , 56^2 )
i) The bulb picked to have a life time of at least 300 hours.
- We will first standardize the limiting value of the RV ( X ) and determine the corresponding Z-score value:
P ( X ≥ x ) = P ( Z ≥ ( x - μ ) / σ )
P ( X ≥ 300 ) = P ( Z ≥ ( 300 - 210 ) / 56 )
P ( X ≥ 300 ) = P ( Z ≥ 1.607 )
- Use the standard normal look-up table for limiting value of Z-score:
P ( X ≥ 300 ) = P ( Z ≥ 1.607 ) = 0.054 .. Answer
ii) The bulb picked to have a life time of at most 100 hours.
- We will first standardize the limiting value of the RV ( X ) and determine the corresponding Z-score value:
P ( X ≤ x ) = P ( Z ≤ ( x - μ ) / σ )
P ( X ≤ 100 ) = P ( Z ≤ ( 100 - 210 ) / 56 )
P ( X ≤ 100 ) = P ( Z ≤ -1.9643 )
- Use the standard normal look-up table for limiting value of Z-score:
P ( X ≤ 100 ) = P ( Z ≤ -1.9643 ) = 0.0247 .. Answer
iii) The bulb picked to have a life time of between 150 and 250 hours.
- We will first standardize the limiting value of the RV ( X ) and determine the corresponding Z-score value:
P ( x1 ≤ X ≤ x2 ) = P ( ( x1 - μ ) / σ ≤ Z ≤ ( x2 - μ ) / σ )
P ( 150 ≤ X ≤ 250 ) = P ( ( 150 - 210 ) / 56 ≤ Z ≤ ( 250 - 210 ) / 56 )
P ( 150 ≤ X ≤ 250 ) = P ( -1.0714 ≤ Z ≤ 0.71428 )
- Use the standard normal look-up table for limiting value of Z-score:
P ( 150 ≤ X ≤ 250 ) = P ( -1.0714 ≤ Z ≤ 0.71428 ) = 0.6205 .. Answer
Q1)b
- Denote event (A) : Kofi solves the problem correctly. Then the probability of him answering successfully is:
p ( A ) = 0.25
- Denote event (B) : Menesh solves the problem correctly. Then the probability of him answering successfully is:
p ( B ) = 0.4
- The probability that neither of them answer the question correctly is defined by a combination of both events ( A & B ). The two events are independent.
- So for independent events the required probability can be stated as:
p ( A' & B' ) = p ( A' ) * p ( B' )
p ( A' & B' ) = [ 1 - p ( A ) ] * [ 1 - p ( B ) ]
p ( A' & B' ) = [ 1 - 0.25 ] * [ 1 - 0.4 ]
p ( A' & B' ) = 0.45 ... Answer
Q2)a
- A discrete random variable X: defines the probability of getting each number on a biased die.
- From the law of total occurrences. The sum of probability of all possible outcomes is always equal to 1.
∑ p ( X = xi ) = 1
p ( X = 1 ) + p ( X = 2 ) + p ( X = 3 ) + p ( X = 4 ) + p ( X = 5 ) + p ( X = 6 )
1/6 + 1/6 + 1/5 + k + 1/5 + 1/6 = 1
k = 0.1 ... Answer
- The expected value E ( X ) or mean value for the discrete distribution is determined from the following formula:
E ( X ) = ∑ p ( X = xi ) . xi
E ( X ) = (1/6)*1 + (1/6)*2 + (1/5)*3 + (0.1)*4 + (1/5)*5 + (1/6)*6
E ( X ) = 3.5 .. Answer
- The expected-square value E ( X^2 ) or squared-mean value for the discrete distribution is determined from the following formula:
E ( X^2 ) = ∑ p ( X = xi ) . xi^2
E ( X^2 ) = (1/6)*1 + (1/6)*4 + (1/5)*9 + (0.1)*16 + (1/5)*25 + (1/6)*36
E ( X^2 ) = 15.233 .. Answer
- The variance of the discrete random distribution for the variable X can be determined from:
Var ( X ) = E ( X^2 ) - [ E ( X ) ] ^2
Var ( X ) = 15.2333 - [ 3.5 ] ^2
Var ( X ) = 2.9833 ... Answer
- The cumulative probability of getting any number between 1 and 5 can be determined from the sum:
P ( 1 < X < 5 ) = P ( X = 2 ) + P ( X = 3 ) + P ( X = 4 )
P ( 1 < X < 5 ) = 1/6 + 1/5 + 0.1
P ( 1 < X < 5 ) = 0.467 ... Answer
Q2)b
- Two independent events are defined by their probabilities as follows:
p ( A ) = 0.3 and p ( B ) = 0.5
- The occurrences of either event does not change alter or affect the occurrences of the other event; hence, independent.
- For the two events to occur simultaneously at the same time:
p ( A & B ) = p ( A )* p ( B )
p ( A & B ) = 0.3*0.5
p ( A & B ) = 0.15 ... Answer
- For either of the events to occur but not both. From the comparatively law of two independent events A and B we have:
p ( A U B ) = p ( A ) + p ( B ) - 2*p ( A & B )
p ( A U B ) = 0.3 + 0.5 - 2*0.15
p ( A U B ) = 0.5 ... Answer
- Two mutually exclusive events can-not occur simultaneously; hence, the two events are not mutually exclusive because:
p ( A & B ) = 0.15 ≠ 0
Q2)c
- The letters of the word given are to be arranged in number of different ways as follows:
STATISTICS
- Number of each letters:
S : 3
T : 3
A: 1
I: 2
C: 1
- 10 letters can be arranged in 10! ways.
- However, the letters ( S and T and I ) are repeated. So the number of permutations must be discounted by the number of each letter is repeated as follows:
[tex]\frac{10!}{3!3!2!} = \frac{3628800}{72} = 50,400[/tex]
- So the total number of ways the word " STATISTICS " can be re-arranged is 50,400 without repetitions.
Related Questions
A manufacturer of large appliances must decide which of two​ machines, A and​ B, they want to purchase to perform a specific task in the production process. The goal is to buy the machine that has smaller mean time required to perform the task. The plant supervisor selects 15 machine operators at​ random, and each operator performs the task on each of the two machines. The production times are paired for each worker. A paired​ t-test is to be performed to determine if there is evidence that the population mean time using machine A is less than the population mean time using machine B. The summary statistics for the differences in the times required for the task in minutes​ (machine A​ - machine​ B) for the 15 randomly selected workers are given below.
n=15; xÌ… = -10.9 and s=20.3
What must be true about the population of differences in the times required for the task between machine A and machine B for conclusions from the paired t-test to be valid for the population of differences among all workers?
a. Because of the small sample size of differences in times required between machine A and machine B, the distribution of sample means of the differences cannot be normal.
b. Because there were a total of 30 obervations (15 times from machine A and 15 times from machine B), the distribution of sample means of the differences will be approximately normal by the Central Limit Theorem.
c. Because the sample size is "large" enough, the distribution of differences for all workers will be normal.
d. Because of the small sample size of differences in times required between machine A and machine B, the distribution of differences for all workers must be normal.
Answers
Answer:
d. Because of the small sample size of differences in times required between machine A and machine B, the distribution of differences for all workers must be normal.
Step-by-step explanation:
A paired t- test conclusion is said to be valid if one of the assumptions that must be satisfied is that: the distribution of the differences must be normal in most cases for which the sample size is small.
From the given information:
the sample size n = 15 ;which is far less than 30
Therefore;we require the distribution of differences in times required between machine A and machine B for all workers to be normal.
From the first option; it is incorrect because even if the sample size is small; the distribution of sample means of the differences will be normal but in the first option ; it is stated that the differences cannot be normal. That makes the first option to be incorrect.
From the second option; is not correct because the sample size (for differences) is 15 and therefore that is a minimal sample which makes the Central Limit Theorem to be invalid and not applicable here.
From the third option; we all know that the sample size is small and not large since it is lesser than 30.
A soft drink machine outputs a mean of 24 ounces per cup. The machine's output is normally distributed with a standard deviation of 3 ounces. What is the probability of filling a cup between 21 and 28 ounces? Round your answer to four decimal places.
Answers
Answer:
[tex]P(21<X<28)=P(\frac{21-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{28-\mu}{\sigma})=P(\frac{21-24}{3}<Z<\frac{28-24}{3})=P(-1<z<1.33)[/tex]
And we can find the probability with this difference
[tex]P(-1<z<1.33)=P(z<1.33)-P(z<-1)[/tex]
And using the normal standard distribution or excel we got:
[tex]P(-1<z<1.33)=P(z<1.33)-P(z<-1)=0.908-0.159=0.749[/tex]
Step-by-step explanation:
Let X the random variable that represent the soft drink machine outputs of a population, and for this case we know the distribution for X is given by:
[tex]X \sim N(24,3)[/tex]
Where [tex]\mu=24[/tex] and [tex]\sigma=3[/tex]
We want to find this probability:
[tex]P(21<X<28)[/tex]
The z score is given by:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
Using this formula we got:
[tex]P(21<X<28)=P(\frac{21-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{28-\mu}{\sigma})=P(\frac{21-24}{3}<Z<\frac{28-24}{3})=P(-1<z<1.33)[/tex]
And we can find the probability with this difference
[tex]P(-1<z<1.33)=P(z<1.33)-P(z<-1)[/tex]
And using the normal standard distribution or excel we got:
[tex]P(-1<z<1.33)=P(z<1.33)-P(z<-1)=0.908-0.159=0.749[/tex]
What’s the correct answer for this?
Answers
9.4 units.
Because,
Formula for arc length is 2times pie times radius times angle divided by 360.
Answer:
The answer is option 2.
Step-by-step explanation:
You have to use length or arc formula, Arc = θ/360×2×π×r where θ represents degrees and r is radius. Then substitute the following values into the formula :
[tex]arc = \frac{θ}{360} \times 2 \times \pi \times r[/tex]
Let θ = 45,
Let r = 12,
[tex]arc = \frac{45}{360} \times 2 \times \pi \times 12[/tex]
[tex]arc = \frac{1}{8} \times 24\pi[/tex]
[tex]arc = 9.42 \: units \: (3s.f)[/tex]
The temperature at noon was 10 degrees. For the next 3 hours it dropped at a rate of 3 degrees an hour. Express this change in temperature as an integer.
Answers
Answer:
Change in temperature = -9 degrees
Step-by-step explanation:
Given
[tex]Start Temperature = 10 deg[/tex]
[tex]Change = 3 deg/hr[/tex]
[tex]Time= 3hr[/tex]
Required
Change in temperature;
First, the total change in 3 hours has to be solved for. This is done as follows:
[tex]Total Change = Change* Time[/tex]
[tex]Total Change = 3 deg/hr * 3 hr[/tex]
[tex]Total Change = 9 deg[/tex]
From the question, we understand that the temperature dropped.
So, we can conclude that the temperature changed by -9 degrees;
This means that at the end of the third hour is temperature is 1 degrees
samantha is making punch for a class picnic. there are 25 students in her class. Samantha uses 1 gallon 2 quarts of orange juice, 3 quarts of lemonade, and 1 gallon 3 quarts of sparkling water. How much punch did samantha make? will there be enough for each student to make two 1 cup servings of punch?
Answers
Answer:
4 gallonsyesStep-by-step explanation:
A quart is 1/4 gallon, so the total of liquid ingredients for the punch is ...
(1 2/4 gal) +(3/4 gal) +(1 3/4 gal) = 2 8/4 gal = 4 gal
Samantha made 4 gallons of punch.
__
1 cup is 1/16 gallon, so 2 cups each for 25 students requires ...
(1/16 gal)(2)(25) = 50/16 gal = 3 1/8 gal
Samantha made more punch than that, so there will be enough for 2 1-cup servings for each student.
If f(x)= 6x squared - 4 and g(x)= 2x + 2 find (f-g)(x)
Answers
Answer:
[tex]6x^2-2x-6[/tex]
Step-by-step explanation:
[tex]f(x)=6x^2-4 \\\\g(x)=2x+2 \\\\(f-g)(x)= (6x^2-4)-(2x+2)=6x^2-2x-6[/tex]
Hope this helps!
simplify (3a-2b)²-2(3a-2b)(a+2b)+(a+2)²
Answers
4a - 20ab + 12b. +4a + 4
A study of the amount of time it takes a mechanic to rebuild the transmission for a 1992 Chevrolet Cavalier shows that the mean is 8.4 hours and the standard deviation is 1.8 hours. If 40 mechanics are randomly selected, find the probability that their mean rebuild time exceeds 9.1 hours.
A ) 0.1046 B) 0.0069 C ) 0.1285 D ) 0.0046
Answers
Answer:
B) 0.0069
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question, we have that:
[tex]\mu = 8.4, \sigma = 1.8, n = 40, s = \frac{1.8}{\sqrt{40}} = 0.2846[/tex]
Find the probability that their mean rebuild time exceeds 9.1 hours.
This is 1 subtracted by the pvalue of Z when X = 9.1. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{9.1 - 8.4}{0.2846}[/tex]
[tex]Z = 2.46[/tex]
[tex]Z = 2.46[/tex] has a pvalue of 0.9931
1 - 0.9931 = 0.0069
So the answer is B.
If the Math Olympiad Club consists of 11 students, how many different teams of 3 students can be formed for competitions?
Answers
Answer:
165 different teams of 3 students can be formed for competitions
Step-by-step explanation:
Combinations of m elements taken from n in n (m≥n) are called all possible groupings that can be made with the m elements so that:
Not all items fitNo matter the order Elements are not repeatedThat is, a combination is an arrangement of elements where the place or position they occupy within the arrangement does not matter. In a combination it is interesting to form groups and their content.
To calculate the number of combinations, the following expression is applied:
[tex]C=\frac{m!}{n!*(m-n)!}[/tex]
It indicates the combinations of m objects taken from among n objects, where the term "n!" is called "factorial of n" and is the multiplication of all the numbers that go from "n" to 1.
In this case:
n: 3m: 11Replacing:
[tex]C=\frac{11!}{3!*(11-3)!}[/tex]
Solving:
[tex]C=\frac{11!}{3!*8!}[/tex]
being:
3!=3*2*1=68!=8*7*6*5*4*3*2*1=40,32011!=39,916,800So:
[tex]C=\frac{39,916,800}{6*40,320}[/tex]
C= 165
165 different teams of 3 students can be formed for competitions
Answer:
There will be 3 teams of 3 students, and one team of 2 students, so there will be 4 teams with one team one student short, but only 3 teams that can hold 3 students
A manufacturer produces both a deluxe and a standard model of an automatic sander designed for home use. Selling prices obtained from a sample of retail outlets follow. Model Price ($) Model Price ($) Retail Outlet Deluxe Standard Retail Outlet Deluxe Standard 1 39 27 5 40 30 2 39 29 6 39 35 3 46 35 7 35 29 4 38 31 The manufacturer's suggested retail prices for the two models show a $10 price differential. Use a .05 level of significance and test that the mean difference between the prices of the two models is $10. a.Calculate the value of the test statistic (to 2 decimals).
b.What is the 95% confidence interval for the difference between the mean prices of the two models (to 2 decimals)?
Answers
Answer:
Step-by-step explanation:
The data is incorrect. The correct data is:
Deluxe standard
39 27
39 28
45 35
38 30
40 30
39 34
35 29
Solution:
Deluxe standard difference
39 27 12
39 28 11
45 35 10
38 30 8
40 30 10
39 34 5
35 29 6
a) The mean difference between the selling prices of both models is
xd = (12 + 11 + 10 + 8 + 10 + 5 + 6)/7 = 8.86
Standard deviation = √(summation(x - mean)²/n
n = 7
Summation(x - mean)² = (12 - 8.86)^2 + (11 - 8.86)^2 + (10 - 8.86)^2 + (8 - 8.86)^2 + (10 - 8.86)^2 + (5 - 8.86)^2 + (6 - 8.86)^2 = 40.8572
Standard deviation = √(40.8572/7
sd = 2.42
For the null hypothesis
H0: μd = 10
For the alternative hypothesis
H1: μd ≠ 10
This is a two tailed test.
The distribution is a students t. Therefore, degree of freedom, df = n - 1 = 7 - 1 = 6
2) The formula for determining the test statistic is
t = (xd - μd)/(sd/√n)
t = (8.86 - 10)/(2.42/√7)
t = - 1.25
We would determine the probability value by using the t test calculator.
p = 0.26
Since alpha, 0.05 < than the p value, 0.26, then we would fail to reject the null hypothesis.
b) Confidence interval is expressed as
Mean difference ± margin of error
Mean difference = 8.86
Margin of error = z × s/√n
z is the test score for the 95% confidence level and it is determined from the t distribution table.
df = 7 - 1 = 6
From the table, test score = 2.447
Margin of error = 2.447 × 2.42/√7 = 2.24
Confidence interval is 8.86 ± 2.24
A man claims that his lot is triangular, with one side 450 m long and the adjacent side 200 m long. The
angle opposite one side is 28º. Determine the other side length of this lot to the nearest metre.
Answers
Given information:
Side a = 450 m (opposite angle A)Side b = 200 m (opposite angle B)Angle A = 28°We can use the Law of Sines to find angle B:
[tex]$\frac{a}{\sin{A}} = \frac{b}{\sin{B}}[/tex]Substitute the given values:
[tex]$\frac{450}{\sin{28^\circ}} = \frac{200}{\sin{B}}[/tex]Now, solve for angle B:
[tex]$\sin{B} = \frac{200 \times \sin{28^\circ}}{450}[/tex][tex]$\sin{B} \approx 0.208654[/tex][tex]$B \approx \arcsin{0.208654} \approx 12.0435^\circ[/tex]Now that we have angle B, we can find angle C using the fact that the sum of the interior angles in a triangle is always 180°:
Angle C = 180° - 28° - 12.0435° Angle C = 139.9565°Now, we can use the Law of Sines again to find the length of the other side (side c) opposite angle C:
[tex]$\frac{a}{\sin{A}} = \frac{c}{\sin{C}}[/tex]Substitute the given values:
[tex]$\frac{450}{\sin{28^\circ}} = \frac{c}{\sin{139.9565^\circ}}[/tex]Now, solve for side c:
[tex]$c = \frac{450 \times \sin{139.9565^\circ}}{\sin{28^\circ}}[/tex][tex]$c \approx 616.685[/tex]To the nearest meter, the other side length of the triangular lot is approximately 617 m. But, since there is not an option for the answer, the closest option is C. 616 m.
________________________________________________________
Full QuestionAnswer:
289 m or 617 m
Step-by-step explanation:
You want the third side length of a triangle with side lengths 450 m and 200 m, with an angle of 28°.
Solution 1The man's claim does not say which side the given angle is opposite. There are two possibilities. (1) It is opposite the unknown side; (2) it is opposite the side of length 450 m. (No triangle is possible having an angle of 28° opposite the shorter given side.)
If the angle is opposite the unknown side, the law of cosines can be used to find the third side length:
c² = a² + b² - 2ab·cos(C)
c² = 450² +200² -2·450·200·cos(28°) ≈ 83569.43
c ≈ √83569.43 ≈ 289 . . . . meters
The other side length could be 289 meters.
Solution 2The third side could also be figured using the law of sines.
a/sin(A) = b/sin(B) = c/sin(C)
450/sin(28°) = 200/sin(B)
B = arcsin(200/450·sin(28°)) ≈ 12.043°
Then angle C is ...
C = 180° -28° -12.043° = 139.957°
and side 'c' is ...
c = 450·sin(139.957°)/sin(28°) ≈ 617 . . . . meters
The other side length could be 617 meters.
__
Additional comment
The problem tells us "one side" is 450 m, and it tells us the angle opposite "one side" is 28°. If both of the descriptors "one side" are referring to the same side, then Solution 2 is the intended one.
The description can be written in a less ambiguous way. As is, we are not sure that the second use of "one side" is referring to any side in particular. Hence the two possibilities.
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An engineering school reports that 52% of its students are male (M), 33% of its students are between the ages of 18 and 20 (A), and that 27% are both male and between the ages of 18 and 20. What is the probability of a random student being chosen who is a female and is not between the ages of 18 and 20?
Answers
Answer:
42%
Step-by-step explanation:
Given: P(M) = 0.52, P(A) = 0.33, and P(M and A) = 0.27.
Find: P(not M and not A).
P(not M and not A) = 1 − P(M or A)
P(not M and not A) = 1 − (P(M) + P(A) − P(M and A))
P(not M and not A) = 1 − (0.52 + 0.33 − 0.27)
P(not M and not A) = 1 − 0.58
P(not M and not A) = 0.42
Treating these probabilities as Venn probabilities, it is found that there is a 0.42 = 42% probability of a random student being chosen who is a female and is not between the ages of 18 and 20.
-------------------------
The events are:
Event A: Female.Event B: Not between the ages of 18 and 20.-------------------------
52% of the students are male, thus, 48% are female, and [tex]P(A) = 0.48[/tex].33% are between the ages of 18 and 20, thus, 67% are not between these ages, which means that [tex]P(B) = 0.67[/tex]27% are both male and between these ages, which means that 73% are either female or not between these ages, thus [tex]P(A \cup B) = 0.73[/tex].-------------------------
The probability of a random student being chosen who is a female and is not between the ages of 18 and 20 is given by:
[tex]P(A \cap B) = P(A) + P(B) - P(A \cup B)[/tex]
Inserting the probabilities we found:
[tex]P(A \cap B) = 0.48 + 0.67 - 0.73 = 0.42[/tex]
0.42 = 42% probability of a random student being chosen who is a female and is not between the ages of 18 and 20.
A similar problem is given at https://brainly.com/question/21421475
In a given year, 94 cities in the world had populations of 1 million or more. Fifty years later, 530 cities had populations of 1 million or more. What was the percent increase?
Answers
Answer:
The percent increase was of 464%.
Step-by-step explanation:
To find the percent increase, first we find how much the current amount is of the original amount. Then, we subtract the current amount from the original amount.
Percentage of current amount:
We solve this using a rule of three.
The original amount(94 cities), was 100% = 1.
The current amount(530 cities) is x. So
94 cities - 1
530 cities - x
94x = 530
x = 530/94
x = 5.64
5.64 = 564% of the original amount
What was the percent increase?
The current amount is 564%
The original amount is 100%
564 - 100 = 464
The percent increase was of 464%.
An account with a $250 balance accrues 2% annually.
Answers
A production line operation is designed to fill cartons with laundry detergent to a mean weight of 32 ounces. A sample of cartons is periodically selected and weighed to determine whether underfilling or overfilling is occurring. If the sample data lead to a conclusion of underfilling or overfilling, the production line will be shut down and adjusted to obtain proper filling. (a) Choose the null and alternative hypotheses that will help in deciding whether to shut down and adjust the production line. H0: - Select your answer - Ha: - Select your answer - (b) Comment on the conclusion and the decision when H0 cannot be rejected. The input in the box below will not be graded, but may be reviewed and considered by your instructor. (c) Comment on the conclusion and the decision when H0 can
Answers
Answer:
See explanation below
Step-by-step explanation:
Given a mean of 32. The claim here is that the mean is 32.
Therefore, the null hypothesis and alternative hypothesis, would be:
H0 : u = 32
Ha: u ≠ 32
b) When we fail to reject null hypothesis, H0. This means that the mean weight, u = 32
Conclusion: There is not enough evidence to conclude that there is overfilling or underfilling.
c) When null hypothesis, H0 is rejected. This means the mean weight, u ≠ 32.
Conclusion: There is enough evidence to conclude that overfilling or underfilling exists
The null hypothesis in the sampling is u = 32 and the alternative is that u isn't equal to 32.
How is the null hypothesis depicted?It should be noted that based on the information, when the null hypothesis is rejected, it implies that the weight is 32.
Also, there's no enough evidence to conclude that there's either overfilling or underfilling. When the null hypothesis is rejected, it means that the mean weight is not equal to 32.
Learn more about sampling on:
https://brainly.com/question/17831271
pls help i give brainliest
you buy a bag of crisps in an airport.After take off you take the crisps out of your ruck sack why has the bag expanded
Answers
Answer:
Step-by-step explanation:
there is a pressure difference between inside and outside the container and if the — bag, bottle, whatever — is flexible enough it will either expand as the ambient air pressure decreases when climbing or collapse when the aircraft is descending and the pressure is increasing.......
this is ur answer ....
The owner of a senior living facility examines data on the age of the residents at the facility. She finds that the distribution of ages of residents is approximately normal with a mean of 73.5 years and a standard deviation of 6.5 years. Which interval below estimates the middle 99.7% of ages of residents living at the facility?
a. (52,95)
b. (54,93)
c. (60.5, 86,5)
d. (67,80)
Answers
The interval of the data if, The mean of 73.5 years and the standard deviation of 6.5 years, is (67,80) so, option D is correct.
What is mean?Mean is a measurement of a probability distribution's central tendency along the median and mode. It also goes by the name "anticipated value."
Given:
The mean of 73.5 years and the standard deviation of 6.5 years,
the middle 99.7% of ages of residents living at the facility,
Calculate the interval as shown below,
The coordinates of x in the interval = Mean - Standard deviation
The coordinates of x in the interval = 73.5 - 6.5
The coordinates of x in the interval = 67
The coordinates of y in the interval = Mean + Standard deviation
The coordinates of y in the interval = 73.5 + 6.5
The coordinates of y in the interval = 80
Thus, the interval will be (67, 80).
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Five times the sum of 8u and eight gives one hundred sixty
Answers
Answer:
u=3
Step-by-step explanation:
(8u + 8)5 = 160
40u + 40 = 160
40u = 120
u = 3
Create a word problem on Algebraic Expressions and Measurement (grade 10)
Answers
Frank can build a fence in twice the time it would take Sandy. Working together, they can build it in 7 hours. How long will it take each of them to do it alone?
Answer
If Frank and Sandy can build the fence in 7 hours, they must be building
1
7
of the fence every hour.
Now, let the amount of time it takes Sandy be
x
hours so that Frank takes
2
x
hours. Sandy can build
1
x
of the fence every hour and Frank can build
1
2
x
of the fence every hour.
We now have the following equation to solve.
1
x
+
1
2
x
=
1
7
2
+
1
2
x
=
1
7
21
=
2
x
x
=
21
2
=
10.50
Thus, Sandy takes
10.50
hours and Frank takes
21
hours.
What should the rule be for the table?
On a recent test, you were given the table displayed and
asked to write the rule that models it.
Subtract 6 from the x value to get the y value.
Multiply the x value by 1/2 to get the y value.
Multiply the x value by 1/4 to get the y value.
Add 6 to the x value to get the y value.
8
12
12
6
16
10
(look at picture) pls help
Answers
Answer: it’s A
Step-by-step explanation:
Answer:
I check the answer was a or Subtract 6 from the x value to get the y value
Hal has 24 video games 6 if his games are sports related and the rest are role playing games which ratio represent the number of his role playing games
Answers
Answer:
It would be 18;24 or simplified it would be 3;4
Step-by-step explanation:
24-6=18 so there are 18 role playing games. So the ratio could be 18;24 but if it needs to be simplified you can divide both numbers by 6. 18/6=3 and 24/6=4
Simplify: 19w5+ (-3075)
Enter the original expression if it cannot be
simplified.
Enter the correct answer.
ODA
DONE
Answers
A walk-in medical clinic believes that arrivals are uniformly distributed over weekdays (Monday through Friday). It has collected the following data based on a random sample of 100 days. Frequency Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100 Assuming that a goodness-of-fit test is to be conducted using a 0.10 level of significance, the critical value is:
Answers
Answer:
The degrees of freedom are given by;
[tex] df =n-1= 5-1=4[/tex]
The significance level is 0.1 so then the critical value would be given by:
[tex] F_{cric}= 7.779[/tex]
If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays
Step-by-step explanation:
For this case we have the following observed values:
Mon 25 Tue 22 Wed 19 Thu 18 Fri 16 Total 100
For this case the expected values for each day are assumed:
[tex] E_i = \frac{100}{5}= 20[/tex]
The statsitic would be given by:
[tex] \chi^2 = \sum_{i=1}^n \frac{(O_i-E_i)^2}{E_i}[/tex]
Where O represent the observed values and E the expected values
The degrees of freedom are given by;
[tex] df =n-1= 5-1=4[/tex]
The significance level is 0.1 so then the critical value would be given by:
[tex] F_{cric}= 7.779[/tex]
If the calculated value is higher than this value we can reject the null hypothesis that the arrivals are uniformly distributed over weekdays
Students are designing a new town as part of a social studies project on urban planning. ey want to place the town’s high school at point A and the middle school at point B. they also plan to build roads that run directly from point A to the mall and from point B to the mall. the average cost to build a road in this area is $550,000 per mile. a. Find the measure of each acute angle of the right triangle shown. b. Find the length of the hypotenuse. Also nd the length of each of the three congruent segments forming the hypotenuse.
Answers
Answer:
The downtown angle measures about 22.62° and the town pool angle measures about 67.38°.
The hypotenuse measures 13 miles. Each third measures 4 1/3 miles.
Step-by-step explanation:
Use trigonometric ratios to solve this problem.
a. Find the measure of each acute angle of the right triangle shown.
Let's start with the acute angle that's marked near downtown. We can use the trigonometric ratio tangent to find the measure of this angle. (Remember, tangent = opposite/adjacent!)
We can divide the opposite side from the angle by the adjacent side to find the tangent:
5/12
= 0.4166666...
Now, we do the inverse tangent to find the measure of the angle:
≈ 22.62°
Now, we can find the angle near the town pool. This time, we can use tangent again, but the 12 mi side is the opposite and the 5 mi side is the adjacent:
12/5
= 2.4
Now, calculate the inverse tangent:
≈ 67.38°
b. Find the length of the hypotenuse. Also find the length of each of the three congruent segments forming the hypotenuse.
We can use the Pythagorean theorem to find the length of the hypotenuse. Remember, given legs a and b and hypotenuse c, the Pythagorean theorem states:
a² + b² = c²
Plug the values in this triangle into this equation:
5² + 12² = c²
25 + 144 = c²
169 = c²
13 = c
The hypotenuse measures 13 miles.
Now, we find the length of the three congruent segments that form the hypotenuse. (to be honest, I'm not sure that there are three congruent segments, but oh well, I'll just go with what it says there).
Since all the segments are the same length, we can just divide 13 by 3 to find the length of each of them:
13/3 = 4 1/3.
Each of the segments measures 4 1/3 miles.
Sophie Ruth is eating a 50-gram chocolate bar which contains 30 percent cocoa.
How many grams of cocoa are in the chocolate bar?
grams
Answers
hope it helps :] !!!!!!
Answer:
15 grams hope this helps
can anyone please explain me this,would be appreciated
Brian, a scientist, is writing a research paper on projectile motion. during one of his experiments, he throws a ball from a point marked as point a, with a certain velocity in the horizontal direction. the ball travels a horizontal distance of 0.6 meter in the 1st second, 1.2 meters in the 2nd second, 1.8 meters in the 3rd second, and so on. it hits the ground on the 8th second. brian marks the point where the ball landed as point b. calculate the distance between point a and point b.
Answers
Answer:
21.6m
Step-by-step explanation:
Brian throws a ball from point 'a'
The ball travels a distance of:
0.6m in the 1^st second1.2m in the 2^nd second1.8m in the 3^rd second2.4m in the 4^th second3.0m in the 5^th second3.6m in the 6^th second4.2m in the 7^th second4.8m in the 8^th secondThe ball travels a total distance of 0.6m + 1.2m + 1.8m + 2.4m + 3.0m + 3.6m + 4.2m + 4.8m = 21.6m from point 'a' to point 'b'.
A paper company produces 4,675 notebooks in 5 days. How many notebooks can it produce in 13 days?
OA. 12,155
OB. 2,431
OC. 4,473
OD. 12,100
Answers
Answer:
OA. 12,155
Step-by-step explanation:
A paper company produces 4,675 notebooks in 5 days. How many notebooks can it produce in 13 days?
--------
in 5 days= 4675
in 13 days= 4675/5*13= 12155
Answer
A OR D
Step-by-step explanation:
Assume that the random variable X is normally distributed, with mean muequals45 and standard deviation sigmaequals10. Compute the probability P(57 > than X less than or = 69).
Answers
Answer:
0.1069 = 10.69%
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:
[tex]\mu = 45, \sigma = 10[/tex]
Between 57 and 69
This is the pvalue of Z when X = 69 subtracted by the pvalue of Z when X = 57. So
X = 69
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{69 - 45}{10}[/tex]
[tex]Z = 2.4[/tex]
[tex]Z = 2.4[/tex] has a pvalue of 0.9918
X = 57
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{57 - 45}{10}[/tex]
[tex]Z = 1.2[/tex]
[tex]Z = 1.2[/tex] has a pvalue of 0.8849
0.9918 - 0.8849 = 0.1069 = 10.69%
Please answer this correctly
Answers
Answer:
x = 48
Step-by-step explanation:
Since it's given that these two shapes are similar, you can set up a proportion to solve for x, like so:
[tex]\frac{27}{18} =\frac{72}{x}[/tex]
Cross multiply:
[tex]\frac{27x}{1296}[/tex]
Divide 1296 by 27:
x = 48
A bag of trail mix shrugged 1.625 pounds round 1.625 to the nearest tenth.use the number line for help
Answers
Answer:
1.625 when convert it to 1.6 pounds
Step-by-step explanation:
The given bag of mill shrugged 1. 625 pounds.
1.625 ≈ 1.6 poundest to the nearest tenth.