The value of cos(A+B) is 36/325.
What is Trigonometry?The branch of mathematics concerned with specific functions of angles and their application to calculations.
Given:
cos(A)=−5/13
sin(B)=7/25
Now Using identity,
sin²A + cos² A= 1
sin A= √1 - cos² A
sin A = √1- 25/169
sin A= √144/169
sin A= 12/13
Again,
sin²B + cos² B= 1
cos B= √1 - sin² B
cos B = √1- 49/625
cos B= √576/625
cos B= -24/25
Now,
cos (A +B) = cos A cos B - sin A sin B.
= -5/13* (-24/25) - 12/13* 7/25
= 120/325 - 84/325
= 36/325
Hence, the value of cos (A + B) is 36/325.
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what is (x^2y^3)^1/3 / 3 sqrt x^2
Answer: y/(3x^1/3)
Step-by-step explanation:
Select The correct answer.
Segment AB Is tangent to the circle at point B. Which equation describes the relationship between the tangent and secant line segments?
B
D
OA
(AD)² = (AC) (AB)
OB. (AB)2 = (AC)(CD)
OC. (AB)2 = (AC)(AD)
OD. AB=(AC + AD)
According to the tangent-secant theorem, the relationship of the tangent and secant in the given circle is: C. AB² = (AC)(AD).
What is the Tangent-Secant Theorem?The secant tangent theorem defines the relationship between the lengths of the secant and the tangent line segments when they meet outside a circle.
Based on the tangent-secant theorem, using the image given, the equation that describes the relationship of the tangent and secant in the given circle is:
C. AB² = (AC)(AD)
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Answer: C
Step-by-step explanation:
got it right on my test!!
Follow the steps to find the area of the shaded region.
First use the formula below to find the area of the whole sector.
Sector Area= ( angle of sector/360). R2
Sector Area = ? Cm^2
Round to four decimal places.
14 cm
46°
14 cm
The area of the sector, to 4 decimal places, is 78.6794 cm².
We have given that,
Sector Area= ( angle of sector/360). R2
We have to determine the Sector Area
What is the Area of a Sector of a Circle?
Area of sector = ∅/360 × πr².
We have given the following:
∅ = 46°
Radius (r) = 14 cm
Area of sector = 46/360 × π(14²)
Area of sector ≈ 78.6794 cm²
The area of the sector is approximately 78.6794 cm².
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Word Problem 3 Priscilla works 43 hours a week for eight weeks. If she makes $14.73 per hour, how much money did she make in the eight weeks? Operation(s): Math sentence(s): Solution: Word Problem 3 Priscilla works 43 hours a week for eight weeks . If she makes $ 14.73 per hour , how much money did she make in the eight weeks ? Operation ( s ) : Math sentence ( s ) : Solution :
Answer:
$5067,12
Step-by-step explanation:
14,73*43*8
The required money Priscilla will earn in 8 weeks is $5067.12.
As mentioned in the question, Priscilla works 43 hours a week for eight weeks. If she makes $14.73 per hour,
What is simplification?The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.
Here,
Let the amount earned be x,
According to the condition,
x = 8 × 43 × 14.73
x = $5067.12.
Thus, the required money Priscilla will earn in 8 weeks is $5067.12.
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help pls i jusiot jiojfgnio43nfginfmowenfviowngognior3
Answer:
i dont know
Step-by-step explanation:
sorry please be a bit more clear on what help you would like
Please answer these questions!!!!
Answer:
BEC = C. 50
BCD = A. 120
Step-by-step explanation:
BEC
65 + 65 = 130
180 - 130 = 50
BCD = 180 - 60 = 120
BEC is 50
urgent help wanted/ needed
The equation in slope-intercept form is: y = -x + 5
The equation in point-slope form is: y - 3 = -1(x - 2)
How to Find the Equation of a Line in Point-Slope Form and Slope-intercept Form?Where (a, b) is a point on the line and m is the slope of the line, the equation in point-slope form for such line would be: y - b = m(x - a).Where b = y-intercept and m = slope, the slope-intercept form for the equation of the line is expressed as: y = mx + b.Slope (m) = rise/run = -(2/2) = -1
Y-intercept (b) = 5 (where the line intercepts the y-axis)
Using a point, (2, 3) = (a, b) and m = -1, the equation in point-slope form is:
y - 3 = -1(x - 2)
Rewrite in slope-intercept form:
y - 3 = -x + 2
y = -x + 2 + 3
y = -x + 5
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The following are scores for students in Ms. Kennedy's math class.What is the range of the scores?
451
560
600
422
603
514
A 109
B 149
C 178
D181
Answer:
The answer will be D. 181
Step-by-step explanation:
603 - 422 = 181
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which of the following expresses the coordinates of the foci of the conic section shown below? (x-2)^2/4+(y+5)^2/9
Step-by-step explanation:
[tex] \frac{(x - 2) {}^{2} }{4} + \frac{(y + 5) {}^{2} }{9} = 1[/tex]
This is the equation of the ellipse. Since the denominator is greater for the y values, we have a vertical ellipse. Remember a>b, so a
The formula for the foci of the vertical ellipse is
(h,k+c) and (h,k-c).
where c is
Our center (h,k) is (2, -5)
[tex] {c}^{2} = {a}^{2} - {b}^{2} [/tex]
Here a^2 is 9, b^2 is 4.
[tex] {c}^{2} = 9 - 4[/tex]
[tex] {c}^{2} = 5[/tex]
[tex]c = \sqrt{5} [/tex]
So our foci is
[tex](2, - 5 + \sqrt{5} )[/tex]
and
[tex](2, - 5 - \sqrt{5} )[/tex]
Which statements are true? Select three options O The line x = O is perpendicular to the line y = -3 O All lines that are parallel to the y-axis are vertical lines. O All lines that are perpendicular to the x-axis have a slope of O. O The equation of the line parallel to the x-axis that passes through the point (2, -6) is x = 2. O The equation of the line perpendicular to the y-axis that passes through the point (-5, 1) is y = 1
The statements which are true among the answer choices are;
The line x = O is perpendicular to the line y = -3.All lines that are parallel to the y-axis are vertical lines. Which statements among the answer choices are true?In the concept of straight line graphs (linear graphs) the statements are evaluated as follows;
The line x = O is perpendicular to the line y = -3. - This is true because the former is a vertical line while the latter is horizontal.All lines that are parallel to the y-axis are vertical lines. - True, because the y-axis itself is a vertical line.All lines that are perpendicular to the x-axis have a slope of O. - False, because all lines perpendicular to the X axis are vertical lines and have do not have slope 0.The equation of the line parallel to the x-axis that passes through the point (2, -6) is x = 2. - False, because a line parallel to the x-axis is defined by y.The equation of the line perpendicular to the y-axis that passes through the point (-5, 1) is y = 1. - True.Read more on parallel and perpendicular lines;
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Finding the Domain and Range of a Graph
Determine the domain and range for the graph below. Write your answer in interval notation.
Answer:
Domain: [tex][-3, 1)[/tex]Range: [tex][-5, 4][/tex]Step-by-step explanation:
The domain is the set of x-values and the range is the set of y-values.
how do you simplify
−(12st3+34s3t+t2−1)
Answer:
-34s^3t - 12st^3 - t^2 + 1
Step-by-step explanation:
hope this helps
Christmas bulbs made of different colours are set to light after 8seconds,10 seconds and 14 seconds. How many times will they light simultaneously in one hour if they start together
Answer:
36 seconds will be the answer... by looking down here↓:
Step-by-step explanation:
6 secs x 6 cycles = 36 seconds
9 secs x 4 cycles = 36 secs
12 ses x 3 cycles = 36 secs
what are the intercepts of x^2 +8x+16
Answers:
x intercept = -4
y intercept = 16
The graph is shown below.
=======================================================
Explanation:
To determine the x intercept(s), we set the expression equal to zero and solve for x. In other words, we plug in y = 0 and solve for x.
y = x^2 +8x+16
0 = x^2 +8x+16
x^2 +8x+16 = 0
(x+4)^2 = 0
x+4 = 0
x = -4
There's only one x intercept. It's located at the vertex of the parabola.
The location of the x intercept is the point (-4,0)
------------
To find the y intercept, we plug in x = 0 and compute like so:
y = x^2 +8x+16
y = (0)^2 +8(0)+16
y = 16
The y intercept is 16 which is located at (0,16)
Check out the graph below. It was made using the free app Desmos.
Which of the following terms best describes a vertical line that the graph of a function approaches but never intersects
Answer: an asymptote is, essentially, a line that a graph approaches , but does not intersect.
Step-by-step explanation:
for example , in the following graph of y =1x y=1x the line approaches the x- axis (y=0) but never touches it
Tan + Cos / 1 + Sin = Sec
[tex]\tan x+\frac{\cos x}{1+\sin x}\\\\ =\frac{\sin x}{\cos x}+\frac{\cos x}{1+\sin x}\\\\=\frac{\sin x(1+\sin x)+\cos^{2} x}{\cos x(1+\sin x)}\\\\=\frac{\sin^{2} x+\cos^{2} x+\sin x}{\cos x(1+\sin x)}\\\\=\frac{1+\sin x}{\cos x(1+\sin x)}\\\\=\frac{1}{\cos x}\\\\=\sec x[/tex]
Another day, another math problem 3
Answer:
[tex]2\sqrt{x+1}-3\\domain:[-1, \infty)[/tex]
Step-by-step explanation:
[tex]g(h(x)) = 2(\sqrt{x+1})-3\\g(h(x)) = 2\sqrt{x+1} - 3\\[/tex]
the function is only defined when (x+1) >= 0 (since square root) so the domain is when x >= -1
A 13 -ft ladder is leaning against a house when its base starts to slide away. By the time the base is 12 ft from the house, the base is moving away at the rate of 15 ft/sec.
a. What is the rate of change of the height of the top of the ladder?
b. At what rate is the area of the triangle formed by the ladder, wall, and ground changing then?
c. At what rate is the angle between the ladder and the ground changing then?
indicate whether the statement is true of false.
please provide a explanation
A linear system with three variables and three equations has a unique solution.
The statement is false, as the system can have no solutions or infinite solutions.
Is the statement true or false?
The statement says that a system of linear equations with 3 variables and 3 equations has one solution.
If the variables are x, y, and z, then the system can be written as:
[tex]a_1*x + b_1*y + c_1*z = d_1\\\\a_2*x + b_2*y + c_2*z = d_2\\\\a_3*x + b_3*y + c_3*z = d_3[/tex]
Now, the statement is clearly false. Suppose that we have:
[tex]a_1 = a_2 = a_3\\b_1 = b_2 = b_3\\c_1 = c_2 = c_3\\\\d_1 \neq d_2 \neq d_3[/tex]
Then we have 3 parallel equations. Parallel equations never do intercept, then this system has no solutions.
Then there are systems of 3 variables with 3 equations where there are no solutions, so the statement is false.
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If y=4 when x=12, find y when x=-24
The value of y is -8 if the x -24 and y varies directly with x, and If y = 4 when x = 12.
What is a proportional relationship?It is defined as the relationship between two variables when the first variable increases, the second variable also increases according to the constant factor.
The question is incomplete.
The complete question is:
If y varies directly with x, and If y = 4 when x = 12, how do you find y when x = -24?
y ∝ x (given)
y = kx
k is the constant of proportionality.
4 = 12k (y = 4, and x = 12)
k = 1/3
y = x/3
Plug x = -24
y = -24/3
y = -8
Thus, the value of y is -8 if the x -24 and y varies directly with x, and If y = 4 when x = 12.
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1. The perimeter of the square is f(x) = 4x, where x is the side of the square. Find the domain of the function.
A. Set of rational numbers
B. Set of whole numbers
C. Set of integers
D. All of the choices
2. Find the domain of the function y = 3x + 8(3 - x).
A. Set of real numbers
B. Set of integers
C. Set of whole numbers
D. Set of natural numbers
Question 1
B. Set of whole numbers
Eliminate A and C because negative integers are in those sets.Question 2
A. Set of real numbers
The equation represents a line, which has a domain of all real numbers.If the perimeter of the square is 4x then the domain of the function will be set of rational numbers and the domain of the function y=3x+8(3-x) is set of real numbers.
Given The perimeter of the square is f(x)=4x and the function is y=3x+8(3-x)
We will first solve the first part in which we have been given that the perimeter of the square is 4x and we have to find the domain of the function.
First option is set of rational numbers which is right for the function.
Second option is set of whole numbers which is not right as whole number involves 0 also and the side of the square is not equal to 0.
Third option is set of integers which is not right as integers involve negative number also and side of square cannot be negative.
Hence the domain is set of rational numbers.
Now we will solve the second part of the question
f(x)=3x+8(3-x)
we have not told about the range of the function so we can put any value in the function and most appropriate option will be set of real numbers as real number involve positive , negative and decimal values also.
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Analyze the diagram below and complete the instructions. Find the value of x and the value of y
The value of the variable x and y will be 15 and 5√3. Then the correct option is D.
The complete question is attached below.
What is trigonometry?The connection between the lengths and angles of a triangular shape is the subject of trigonometry.
The right triangle is shown.
Then the value of x will be
x = 10√3 × sin 60°
x = 15
Then the value of y will be
y = 10√3 × cos 60°
y = 5√3
Then the correct option is D.
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f(x) = -3 +3
Which graph represents the inverse of function ?
-3
N
-1
4
3-
2-
1-
-2+
-3-
-4+
-5+
W.
Y
54
-1-
4-
3-
2
-4
-2
N
-3
-5+
X.
Y
4-
3-
2-
-1-
3
X
e
Answer: Y
Step-by-step explanation:
Since f(x) passes through (0,3), its inverse should pass through (3,0).
This eliminates X and Z.Also, since f(x) has a negative slope, so its inverse should also have a negative slope.
This eliminates W.The graph of the inverse of function is shown in figure.
We have to given that,
Function is defined as,
f (x) = - 3x + 3
Hence, The inverse of function f (x) is,
f (x) = - 3x + 3
y = - 3x + 3
Solve for x,
3x = y + 3
Divide by 3;
x = (y + 3) / 3
Hence,
f⁻¹ (x) = (x + 3) / 3
f⁻¹ (x) = x/3 + 1
Therefore, The graph of the inverse of function is shown in figure.
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The equation for the pH of a substance is pH = -log[H*], where H+ is the concentration of hydrogen ions. A basic
solution has a pH of 11.2. An acidic solution has a pH of 2.4. What is the approximate difference in the concentratic
of hydrogen ions between the two solutions?
1.6x10-9
O4.0x10-3
O 6.7x10-1
O 1.6x10¹11
The approximate difference in the concentration of hydrogen ions between the two solutions is 4.0×10⁻³
What is pH value?The pH of a solution is a measurement of the concentration of hydrogen ions in the solution, as well as its acidity or alkalinity. Normally, the pH scale ranges from 0 to 14.
pH value for basic solution = 11.2
pH value for acidic solution = 2.4
Concentration for a basic solution:
[tex]\rm = 10^{-11.2}[/tex]
[tex]= 6.309\times10^{-12}[/tex]
Concentration for an acidic solution:
[tex]\rm = 10^{-2.4}[/tex]
[tex]= 3.981\times10^{-3}[/tex]
Difference between the concentration:
[tex]= 3.981\times10^{-3}- 6.309\times10^{-12}[/tex]
[tex]= 3.98\times10^{-3}[/tex]
[tex]= 4\times10^{-3}[/tex]
Thus, the approximate difference in the concentration of hydrogen ions between the two solutions is 4.0×10⁻³
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The statement “a > 2 and a < 5” is true when a is equal to
A. 5
B. 3
C. 10
D. 2
Answer:
B
Step-by-step explanation:
because > means greater than or more than
and < means less than
the answer is B because 3 is more than 2 and the same time less than 5
Simplify
[tex]\left(\frac{123}{321}\right)\left(\frac{456}{654}\right)\left(\frac{789}{987}\right) \left(\frac{123}{321}\right)^{-1}\left(\frac{456}{654}\right)^{-1}\left(\frac{789}{987}\right)^{-1}[/tex]
Answer:
1
Step-by-step explanation:
using the rule of exponents
[tex](\frac{a}{b}) ^{-1}[/tex] = [tex]\frac{b}{a}[/tex] , then
[tex]\frac{123}{321}[/tex] × [tex]\frac{456}{654}[/tex] × [tex]\frac{789}{987}[/tex] × [tex]\frac{321}{123}[/tex] × [tex]\frac{654}{456}[/tex] × [tex]\frac{987}{789}[/tex]
[ [tex]\frac{123}{321}[/tex] × [tex]\frac{321}{123}[/tex] = 1 , [tex]\frac{456}{654}[/tex] × [tex]\frac{654}{456}[/tex] = 1 , [tex]\frac{789}{987}[/tex] × [tex]\frac{987}{789}[/tex] = 1 ]
= 1 × 1 × 1
= 1
Where does billy bob johns
Answer:
in ur moms house
Step-by-step explanation:
Answer:
he doesn't
Step-by-step explanation:
what is the answer please??
Answer:
See below
Step-by-step explanation:
Area of a circle = pi * r^2
for this circle : Area = 3.142 * 10 * 10 = 314.2 cm^2
The formula for area of a circle is [tex]\pi r^{2}[/tex]
So using pi as 3.142, we can do 3.142 • 100 which is 314.2 when moving place values.
Even though you did not ask, the circumference formula is 2[tex]\pi[/tex]r.
If we were given the same information, where the radius is 10, and we were solving circumference, then we would do 3.14 • 20 = 62.8.
Brainliest if helpful.
Describe the change in the graph of the parabola f(x) when it transforms into g(x) =
The parabola g(x) will open in the opposite direction of f(x), and the parabola will be narrower than f(x).
The parabola g(x) will open in the same direction of f(x), and the parabola will be narrower than f(x).
The parabola g(x) will open in the opposite direction of f(x), and the parabola will be wider than f(x).
The parabola g(x) will open in the same direction of f(x), and the parabola will be wider than f(x).
Answer:
(d) The parabola g(x) will open in the same direction of f(x), and the parabola will be wider than f(x).
Step-by-step explanation:
We assume you intend ...
f(x) = equation of a parabola
g(x) = 2/3·f(x)
Multiplying a function by a factor of 2/3 will cause it to be compressed vertically to 2/3 of its original height. When the function is a parabola, this has the effect of making it appear wider than before the compression.
__
The compression factor is positive, so points on the graph remain on the same side of the x-axis. The direction in which the graph opens is not changed.
The attachment shows parabolas that open upward and downward, along with the transformed version.
Answer:
D.) The parabola g(x) will open in the same direction of f(x), and the parabola will be wider than f(x).
Step-by-step explanation:
I got it right on the test :)
stay hydrated.
Which expression is equivalent to One-fifth (150 x minus 80 y + 50 minus 50 x minus 25 y + 20)?
20 x minus 21 y + 14
20 x + 11 y + 14
20 x minus 11 y + 6
20 x + 21 y + 6
Answer:
150 x - 80 y + 50 - 50 x - 25 y + 20
Arranging like terms
150 x - 50 x -25 y - 80y + 50 + 20
100x - 105 y + 70
5 ( 20x - 21y + 14)Answer:
20x - 21y + 14
Explanation:
[tex]\rightarrow \sf \dfrac{1}{5} (150x - 80y + 50 - 50x - 25y + 20)[/tex]
collect like terms
[tex]\rightarrow \sf \dfrac{1}{5} (150x-50x - 80y -25y + 50 + 20)[/tex]
add/subtract like terms
[tex]\rightarrow \sf \dfrac{1}{5} (100x - 105y+70)[/tex]
distribute inside parenthesis
[tex]\rightarrow \sf \dfrac{1}{5} (100x) + \dfrac{1}{5}( - 105y) + \dfrac{1}{5}(70)[/tex]
simplify the following
[tex]\rightarrow \sf 20x -21y + 14[/tex]