You are conducting an experiment inside an elevator that can move in a vertical shaft. A load is hung vertically from the ceiling on a string, and is stationary with respect to you. The tension in the string is measured to be exactly equal to the force due to gravity on the load. No other forces are acting on the load. Which of the following statements about the elevator are correct?
A. The elevator is an inertial frame of reference.
B. The elevator is not an inertial frame of reference.
C. The elevator may be at rest for the duration of the entire experiment.
D. The elevator may be moving at a constant velocity upward.
E. The elevator may be moving at a constant velocity downward.
F. The elevator must be accelerating

Explanation:

I have a lot to say it was very nice to meet my parents are u doing well I dont want too its been so much I love you so I was like u know I am not a man but you are the auditions I have been in a long long long life is a triangle and a chair for me and my parents think about the way I

Answer:

zero

Explanation:

The computation of the normal force is shown below:

As we know that

F_c = mg - N

F_c = mv^2 ÷ r

N = mg - mv^2 ÷ r

N = m(g - v^2 ÷ r)

Assume that

The mass of the car is 1200 kg

And, r = 10 m

So,

= 1200 (9.8 - 15^2 ÷ 10)

= -15240 N

Since it comes in negative so the normal force would be zero

at least two charged interacting parts

Answer:

120 W lightbulb

Explanation:

Let the two lightbulb be A and B respectively.

Given the following data;

Power A = 120W

Power B = 90W

Voltage = 120V

To find the current flowing through each lightbulb;

a. For lightbulb A

Power = current * voltage

120 = current * 120

Current = 120/120

Current = 1 Ampere.

b. For lightbulb B

Current = power/voltage

Current = 90/120

Current = 0.75 Amperes

Therefore, the lightbulb that carries more current is A with 1 Ampere.

The  bulb that  carries more current is :

- A with 1 Ampere.

Let the two lightbulb be A and B respectively.

To find the current flowing through each lightbulb;

Thus, the lightbulb that carries more current is A with 1 Ampere.

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Answer:

D.

Explanation:

Answer:

The answer is "Choice C ".

Explanation:

The relationship between the E and V can be defined as follows:

[tex]\to E= -\Delta V[/tex]

Let,

[tex]\to E= \frac{\delta V}{\delta x}[/tex]

When E=0

[tex]\to \frac{\delta V}{\delta x}=0[/tex]

v is a constant value

Therefore, In the electric potential in a region is a constant value then the electric-field must be into zero that is everywhere in the given region, that's why in this question the "choice c" is correct.

Answer:

The horizontal and vertical distances are x = 210 m and y = -240.35 m, respectively.

Explanation:

Using the equation of the displacement in the x-direction, we have:

(let's recall we have a constant velocity in this direction)

[tex]x=v_{ix}t[/tex]

Where:

[tex]x=30(7)[/tex]    

[tex]x=210\: m[/tex]    

Now, we need to use the equation of the displacement in the y-direction to find the vertical distance. Here we have an acceleration (g)

[tex]y=v_{iy}t-\frac{1}{2}gt^2[/tex]

Where:

Then, the vertical position at 7 s is:

[tex]y=-\frac{1}{2}(9.81)(7)^2[/tex]

[tex]y=-240.35\: m[/tex]

Therefore, the horizontal and vertical distances are x = 210 m and y = -240.35 m, respectively. The minus sign means the negative value in the y-direction.

I hope it helps you!

Answer:

No.

Explanation:

Velocity is a vector quantity which means that it has a certain direction so things that move in different directions DO NOT have the same velocity.

Answer:

It develops natural resources.

It works to eliminate poverty through development.

Answer:

P₂ = 4098.96 Pa

Explanation:

For this exercise let's use Bernoulli's equation

Let's use the subscript 1 for the point of the liquid surface and the subscript 2 for the ends (point A)

         P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

the velocity at the end of the tank

        v₂ = w r₂

the velocity at the surface of the liquid is

        v₁ - w r₁

where r₂ = 1.5 m and r₁ = 1 m

the tank pressure is P₁ = P₀ = 0.1 10³ Pa

         P₂ = P₁ + ½ ρ [w² (r₁² - r₂²)] + ρ g (y₁ -y₂)

We must remember that the pressure measurements the distances are measured from the lowest part to the surface that has zero height

let's reduce the magnitudes to the SI system

         w = 3 rev / min (2π rad / 1rev) (1 min / 60 s) = 0.314159 rad / s

let's calculate

        P₂ = 0.1 10³ + ½ 800 0.314159² |(1² -1.5²)| + 800 9.8 |(1-1.5)|

        P₂ = 0.1 103 +78.96 + 3920

        P₂ = 4098.96 Pa

Answer:

1.93×10²⁸ s

Explanation:

From the question given above, the following data were obtained:

Number of electron (e) = 2×10²⁴

Current (I) = 10 A

Time (t) =?

Next, we shall determine the quantity of electricity flowing through pasing through the point. This can be obtained as follow:

1 e = 96500 C

Therefore,

2×10²⁴ e = 2×10²⁴ e × 96500 / 1 e

2×10²⁴ e = 1.93×10²⁹ C

Thus, 1.93×10²⁹ C of electricity is passing through the point.

Finally, we shall determine the time. This can be obtained as follow:

Current (I) = 10 A

Quantity of electricity = 1.93×10²⁹ C

Time (t) =?

Q = it

1.93×10²⁹ = 10 × t

Divide both side by 10

t = 1.93×10²⁹ / 10

t = 1.93×10²⁸ s

Thus, it took 1.93×10²⁸ s for 2×10²⁴ electrons to pass through the point

Answer:

Nucleus

Explanation:

Answer: Nucleolus

Explanation: The nucleolus is like the cells brain. It controls all the other organelles (cell parts).

                                                 Hope I helped!

Answer: Throughout the scientific world where measurements are nearly always made in SI units, thermodynamic temperature is measured in kelvins (symbol: K). The Rankine scale uses the degree Rankine (symbol: °R) as its unit, which is the same magnitude as the degree Fahrenheit (symbol: °F).

Explanation:

Please mark me as the Brainiest if I got it right

what's the dimension symbol for thermodynamic temperature

Answer:

°R

Answer:

A) r = 20.0 m

B) T = 41.6 s

C) = 6.1 m/s²

Explanation:

A)

        [tex]a_{c} =\frac{v^{2}}{r} = \frac{(10.0m/s)^{2}}{r} = 5.00 m/s2 (1)[/tex]

       [tex]r = \frac{v^{2}}{a_{c} } = \frac{(10.0m/s)^{2}}{5.00m/s2} = 20.0 m (2)[/tex]

B)

        [tex]v = \frac{\Delta s}{\Delta t} = \frac{2*\pi*r}{T} (3)[/tex]

       [tex]T = \frac{\Delta s}{v} = \frac{2*\pi*r}{v} = \frac{2*\pi*265m}{40.0m/s} =41.6 s (4)[/tex]

C)

        [tex]a_{c} =\frac{v^{2}}{r} = \frac{(40.0m/s)^{2}}{265m} = 6.1 m/s2 (5)[/tex]

Answer:

the answers, the correct one is D,   Rb₂ = 29.97 ohm

Explanation:

For this exercise we use ohm's law and the equivalent resistance ratio for series and parallel circuits.

Serial circuit

         (Ra + Rb) is = V

         (Ra + Rb) 0.111 = 10

         (Ra + Rb) = 10 / 0.111 = 90.09

parallel circuit

         [tex]\frac{1}{R} = \frac{1}{Ra} + \frac{1}{Rb}[/tex]

           R = [tex]\frac{Ra \ Rb}{Ra + Rb}[/tex]

          \frac{Ra \ Rb}{Ra + Rb} i_p = V

         \frac{Ra \ Rb}{Ra + Rb} 0.5 = 10

         \frac{Ra \ Rb}{Ra + Rb} = 10 / 0.5 = 20

we write and solve our system of equations

         Ra + Rb = 90.09

         \frac{Ra \ Rb}{Ra + Rb} = 20

we solve for Ra in the first equation

          Ra = 90.09 - Rb

           RaRb = 20 (Ra + Rb)

we substitute Ra in the second equation

           (90.09-Rb) Rb = 20 [(90.09-Rb) + Rb]

            90.09 Rb - Rb² = 20 90.09

            Rb² - 90.09 Rb + 1801.8 = 0

we solve the quadratic equation

            Rb = [90.09 ±[tex]\sqrt{90.09^2 - 4 \ 1801.8}[/tex] ] / 2

            Rb = [90.09 ± 30.15] / 2

            Rb₁ = 60.12 ohm

            Rb₂ = 29.97 ohm

the smallest value is Rb = 30 ohm

When checking the answers, the correct one is D

Answer:

The answer would be 180 meters.

Explanation:

Answer:

a)  v₀ₓ = 9.9 m / s, b)  x_woman = 32.7 m

Explanation:

A) In this exercise, the movement of the bagels is parabolic, we find the time it takes to reach the floor.

          y = y₀ + v_{oy} t - ½ g t²

          0 = y₀ + 0 - ½ gt²

          t = [tex]\sqrt{2y_o/g}[/tex]

let's calculate

          t = [tex]\sqrt{2 \ 52.9/9.8}[/tex]

          t = 3,286 s

Now we can analyze how long Henrieta has walked, she has a walking time before the bagel movement begins (t₀ = 4.50 s)

          t_woman = t₀ + t

           t_woman = 4.50 + 3.286

           t_woman = 7.786 s

The distance traveled in this time is

           x_{woman} = v_woman t_woman

            x_{woman} = 4.20 7.786

          x_{woman} = 32.7 m

For her to grab the bagel, the two of them must be at this point

          x_bagel = x_woman

          x_bael = vox t

          v₀ₓ = x_bagel / t

          v₀ₓ = 32.7 / 3,286

           v₀ₓ = 9.9 m / s

b) when catching the bagels this point x_woman = 32.7 m

Answer:

the speed of the wave =1m/s

Answer:

a. Workdone = 44100 Joules

b. Power = 8820 Watts.

Explanation:

Given the following data:

Mass = 225kg

Distance = 20m

Time = 5 seconds

To find the workdone;

Workdone = force * distance

But force = mg

We know that acceleration due to gravity is equal to 9.8m/s²

Force = 225*9.8 = 2205N

Substituting the values into the equation, we have;

Workdone = 2205 * 20

Workdone = 44100 Joules

b. To find the power;

Power = workdone/time

Power = 44100/5

Power = 8820 Watts.

Answer:

the law of conservation of energy

Answer:

the current is 16 amphere

Explanation:

The computation of Current is shown below:

As we know that

1 ms = 0.001s

So for 35 ms = 0.035

Now the current is

= 0.56 ÷ 0.035

= 16 AMphere

Hence, the current is 16 amphere

Answer:

a)  y₁ = ½ a, b) y₂ = 4 y₁, c)  y₃ = 9 y₁

Explanation:

For this exercise we can use the accelerated motion relationships.

Let's set a reference system where the x axis is parallel to the plane and its positive side is going down the plane.

          y = y₀ + v₀ t + ½ a t²

in that case where we throw the marble is the zero point, y₀ = 0, as part of rest its initial velocity is zero v₀ = 0 and a  is the acceleration along the inclined plane

           y = ½ a t²

a) in the first second t = 1

            y₁ = ½ a

b) in the next second of movement

           t = 2 s

           y₂ = ½ a 2²

           y₂ = 4 ½ a

           y₂ = 4 y₁

c) for the next second

            t = 3 s

            y₃ = ½ a 3²

            y₃ = 9 ½ a

            y₃ = 9 y₁

Answer:

The car skids in a distance of 61.275 meters.

Explanation:

Since the only force exerted on the car is the kinetic friction between the car and the horizontal road, deceleration of the vehicle ([tex]a[/tex]), measured in meters per square second, is determined by the following expression:

[tex]a = \mu_{k}\cdot g[/tex] (1)

Where:

[tex]\mu_{k}[/tex] - Coefficient of kinetic friction, no unit.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

If we know that [tex]\mu_{k} = 0.52[/tex] and [tex]g = -9.807\,\frac{m}{s^{2}}[/tex], then the net deceleration of the vehicle is:

[tex]a = 0.52\cdot \left(-9.807\,\frac{m}{s^{2}} \right)[/tex]

[tex]a = -5.1\,\frac{m}{s^{2}}[/tex]

The distance covered by the car is finally calculated by this kinematic expression:

[tex]\Delta s = \frac{v^{2}-v_{o}^{2}}{2\cdot a}[/tex] (2)

Where:

[tex]v_{o}[/tex], [tex]v[/tex] - Initial and final speed, measured in meters per second.

[tex]a[/tex] - Net deceleration, measured in meters per square second.

If we know that [tex]v_{o} = 25\,\frac{m}{s}[/tex], [tex]v = 0\,\frac{m}{s}[/tex] and [tex]a = -5.1\,\frac{m}{s^{2}}[/tex], then the distance covered by the car is:

[tex]\Delta s = \frac{\left(0\,\frac{m}{s} \right)^{2}-\left(25\,\frac{m}{s} \right)^{2}}{2\cdot \left(-5.1\,\frac{m}{s^{2}} \right)}[/tex]

[tex]\Delta s = 61.275\,m[/tex]

The car skids in a distance of 61.275 meters.

Answer:

a. True

Explanation:

Electric field is a region of space where the effect of electric field lines or lines of forces are felt.

The electric field lines creates electric field and these field lines help to visualize the electric field.

Therefore,  electric field lines are tool used to visualize electric fields.

a. True

Answer:

    q = 2 10⁻⁸ C

Explanation:

For this exercise we use the translational equilibrium equation

                    F_e -A =

                    F_e = W

the electric force is given by Coulomb's law

                    F_e = [tex]k \frac{q_1q_2}{r^2}[/tex]

in this case they indicate that the loads on the tapes are equal

                    F_e = k q² / r²

we substitute

                    k q² / r² = m g

                    q = [tex]\sqrt{ \frac{mg r^2}{k} }[/tex]

calculate  

                     q = [tex]\sqrt { \frac{ 12 \ 10^{-3} \ 9.8 (0.55 \ 10^{-2})^2 }{9 \ 10^9} }[/tex]    

                     q = [tex]\sqrt{ 3.9526 \ 10^{-16}[/tex]

                     q = 1,999 10⁻⁸ C

                     q = 2 10⁻⁸ C

Answer:

D.) Sensory adaptation

Explanation:

Assuming you are talking about the cloth and metal monkey experiment performed in the field of psychology (not physics), the monkey formed an attachment to the cloth mother because it felt closer to it, as it was more appealing to its senses.

Answer:

1.32

Explanation:

Index of refraction of the glass = 1.52

Thickness = 104 nm

Length = 550 nm

 Using formula of index

n = L/4t

Where, L = length

t = thickness

Substituting the values into the formula we get

n = 500/(4×104)

n= 1.32

Hence, The index of refraction of the coating  is 1.32.

I would use a resistor rated for 1 W or more. Not less.

The power rating of a resistor that would be used in application that requires 0.6 W must be greater than 0.6 W.

The electrical power of an appliance shows the rating of the appliance, in terms of energy consumed at a given period of time.

Electrical power is calculated as follows;

P = IV

where;

[tex]P = (\frac{V}{R} )V\\\\P = \frac{V^2}{R}[/tex]

Thus, the power rating of a resistor that would be used in application that requires 0.6 W must be greater than 0.6 W.

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Answer:

.50 M

Explanation:

5*.50=2.5 + 2*.25=.5 = 3n

6*.50= 3N

Final answer is .50M