write the slope intercept 5x+7y=21

Answer:

$3

Step-by-step explanation:

Flipping two fair coins :

Sample space :

{TH, HT, TT, HH}

Atleast one head = 12

If not = - 24

Probability of atleast one head = 3/4

If not ; probability of 2 tails = 1/4

Hence,

X ______12 ______ -24

P(x) ___0.75 ______0.25

Expected value for of gamble E(x) :

Σx * p(x) = (12 * 0.75) + (-24 * 0.25)

E(x) = 9 - 6

E(x) = 3

Expected value of gamble = $3

Answer:

x = 56 degrees, y = 32 degrees

Step-by-step explanation:

The Isosceles Triangle Theorem (ITT) tells us that if there are two sides of a triangle that are congruent, then the base angles of this triangle are congruent (angles opposite the congruent sides).

Let's focus on Triangle PQS first. We have the acute angle 68° and want to find x. Due to the ITT, we know that the other missing angle must also equal x.

Therefore, we can create an equation where the interior angles of Triangle PQS will add up to 180, because all interior angle measures of a triangle add up to 180 degrees.

Combine like terms.

Subtract 68 from both sides of the equation.

Divide both sides the equation by 2.

We have found that x = 56 degrees, and now we need to find y. We can do so by using the information we have already found. Since we have found the two angles x of Triangle PQS, we can find ∠QSR in Triangle QSR by using the idea that angles that make up a straight line must add up to 180 degrees.

Therefore:

We have found that ∠PSQ = 56, so substitute this value into the equation.

Subtract 56 from both sides of the equation.

Now we can use the fact that all interior angle measurements of a triangle add up to 180 degrees, and since we have 2 angle measures of Triangle QSR, we can create an equation to solve for y.

Combine like terms.

Subtract 148 from both sides of the equation.

We have found x = 56 degrees and y = 32 degrees.

Answer:

Answer:

I am a student. Jake should receive 8.15 dollars in change. Please pick me brainliest! I am new to this website and I wanna help.

Step-by-step explanation:

Answer:

[tex]f = \log_{4}\left(\sqrt{\frac{m\cdot n}{19}}\right)[/tex] is equivalent to  [tex]f = 0.5\cdot \log_{4} m + 0.5\cdot \log_{4}n -0.5\cdot \log_{4}19[/tex].

Step-by-step explanation:

Let be [tex]f = \log_{4}\left(\sqrt{\frac{m\cdot n}{19}}\right)[/tex], we transform this into an equivalent expression with sums and differences of logarithms by applying logarithm properties:

1) [tex]\log_{4}\left(\sqrt{\frac{m\cdot n}{19}}\right)[/tex] Given.

2) [tex]\log_{4}\left[\left(\frac{m\cdot n}{19} \right)^{0.5}\right][/tex] Definition of square root.

3) [tex]0.5\cdot \log_{4}\left(\frac{m\cdot n}{19} \right)[/tex]   [tex]\log_{a} b^{c} = c\cdot \log_{a} b[/tex]

4) [tex]0.5\cdot (\log_{4}m\cdot n -\log_{4} 19)[/tex]   [tex]\log_{a} \frac{b}{c} = \log_{a} b - \log_{a} c[/tex]

5) [tex]0.5\cdot \log_{4} m\cdot n -0.5\cdot \log_{4} 19[/tex] Distributive property.

6) [tex]0.5\cdot (\log_{4}m + \log_{4}n)-0.5\cdot \log_{4}19[/tex]   [tex]\log_{a} b\cdot c = \log_{a}b +\log_{a} c[/tex]

7) [tex]0.5\cdot \log_{4} m + 0.5\cdot \log_{4}n -0.5\cdot \log_{4}19[/tex] Distributive property/Result.

[tex]f = \log_{4}\left(\sqrt{\frac{m\cdot n}{19}}\right)[/tex] is equivalent to  [tex]f = 0.5\cdot \log_{4} m + 0.5\cdot \log_{4}n -0.5\cdot \log_{4}19[/tex].

Answer:

85

Step-by-step explanation:

Answer:

D.)51.837, B.)51.836, A.)51.835, C.)51.736

Step-by-step explanation:

its decreasing in this order

Answer:

51.837 > 51.836 > 51.835 > 51.736

Answer:

because you have to distrubute the 2 to the letters inside the () or else youll get a diff answer thats wrong

Step-by-step explanation:

Answer:

143 i think

Step-by-step explanation:

45+ 106= 151

151 - 8 = 143

Answer:

$143

Step-by-step explanation:

106+45= 151

151-8=143

Answer:

i need help too

Step-by-step explanation:

...

Answer:

Rewrite tan(w + Pi) using the tangent sum identity. Then simplify the resulting expression using tan(Pi) = 0

Step-by-step explanation:

According to tangent sub identity

Tan(A+B) = TanA+TanB/1-tanAtanB

Applying this in question

Tan(w+Pi) = tan(w)+tan(pi)/1-tan(w)tan(pi)

According to trig identity, tan(pi) = 0

Substitute

Tan(w+Pi) = tan(w)+0/1-tan(w)(0)

Tan(w+Pi) = tan(w)/1

Tan(w+Pi) = tan(w) (proved!)

Hence the correct option is

Rewrite tan(w + Pi) using the tangent sum identity. Then simplify the resulting expression using tan(Pi) = 0

The given expression can be prove by using tangent sub-identity. In the solution we will use [tex]\tan (A+B)[/tex] sub-identity.

The correct option is Rewrite tan(w + Pi) using the tangent sum identity. Then simplify the resulting expression using tan(Pi) = 0.

Given:

The given expression is as follows,

[tex]\tan(w+\pi)=\tan(w)[/tex]

Write the tangent sub-identity.

[tex]\tan(A+B)=\dfrac{\tan A+\tan B}{1-\tan A\tan B}[/tex]

Now replace [tex]A[/tex] with [tex]w[/tex] and [tex]B[/tex] with [tex]\pi[/tex].

[tex]\tan(w+\pi)=\dfrac{\tan w+\tan \pi}{1-\tan w\tan \pi}[/tex]

Substitute 0 for  [tex]\tan \pi[/tex].

[tex]\tan(w+\pi)=\dfrac{\tan w+0}{1-\tan w\times 0}\\\tan(w+\pi)=\tan w[/tex]

Thus, the correct option is Rewrite tan(w + Pi) using the tangent sum identity. Then simplify the resulting expression using tan(Pi) = 0.

Learn more about tangent sub-identity here:

https://brainly.com/question/1561928

Answer:

(a) Hypergeometric distribution

(b) 0.785384...

Step-by-step explanation:

(a) looking at the question, we see that [tex]X = \in \{0, ... , 10 \}[/tex], suppose Evans studied s key terms, this implies that he has not studied 100 - s key terms. Suppose [tex]k = \in \{0, ... , 10 \}[/tex] if X = k, then k out of the s key terms he had studied appeared. But 10 - k out of 100 - s key terms he hasn't studied appeared. Thus X is an Hypergeometric distribution, X~HGeom(s, 100 - s, 10) with PMF:

[tex]P_{x}(k) = P(X = k)[/tex]

Answer:

[tex]\left(x-1+3y\right)\left(x-1-3y\right)[/tex]

Step-by-step explanation:

[tex]x^2-2x+1-9y^2\\\\factor(skip for time)\\\\\left(x-1\right)^2-9y^2\\\\[/tex]

A little algebra process later...

you got the answer

Hoped this helped ya

<3

Answer:

(x-1-3y) x (x-1+3y)

Step-by-step explanation:

x^2-2x+1-9y^2

Using a^2 - 2ab + b^2 = (a-b)^2 (factor the expression) = (x-1)^2 - 9y^2

(x-1)^2 - 9y^2 = (x-1-3y) x (x-1+3y)  should be the answer :)

Answer:

A = 7

B = 5

C = 2

Step-by-step explanation:

We are given;

A8 × 3B = C730

Now, by inspection, in multiplication of the above, the product of 8 and B must produce a number whose unit digit is 0.

Thus,the only two single digit numbers that can fit this description for B is either 5 or 0 since if they would yield a unit digit of 0 when multiplied by8.

Now, let's test 0.

If B is 0, it means the unit digit of C730 is 0 as wanted while the remaining product of A8 and 3 should yield C73. Now product of A8 and 3 would produce a number with a last digit of 4. But our last digit there in C73 is 3. Thus, it means B cannot be 0 but is 5.

Thus, it means 3B is 35.

Now, we are told that A, B and C could be any single digit number.

from 0 - 9.

Thus, the maximum value of A is 9.

Let's try to put 9 for A and multiply by 35.

If A is 9,then 98 × 35 = 3430

It means that the maximum value of C is 3.

Thus, C can either be 3 or less than 3. So, C is either 1, 2, or 3

Now, if C = 1, it means the C730 is now 1730.

Thus,A8 will be: 1730/35 = 49.43

This is a decimal and thus, it means C ≠ 1.

Now,if C = 2, it means the C730 is now 2730.

Thus,A8 will be: 2730/35 = 78

This is a whole number and thus, it means C = 2

Now,if C = 3, it means the C730 is now 3730.

Thus,A8 will be: 3730/35 = 106.57

This is a decimal and thus, it means C ≠ 3

Thus; A8 is 78 when C = 2

So, A = 7

Answer:

12

Step-by-step explanation:

if 4x4 is 16 and we want to know what is 3/4 of that then we can easily just subtract 4 from it

Answer:

The guy above me is right.

Step-by-step explanation:

Answer:

1/2

Step-by-step explanation:

Answer:

Top left

Step-by-step explanation:

If an x value (domain) leads to more than one y-value (range), it is not a function. In other words, if each input value leads to only one output value, it is a function. It's still a function if the y-value leads to multiple x-values.

Answer:

0.72 or 0.72866953788  0.7  0.72866953788

Answer:

about  22 percent

Step-by-step explanation:

Answer:

The wood was cut approximately 8679 years ago.

Step-by-step explanation:

At first we assume that examination occured in 2020. The decay of radioactive isotopes are represented by the following ordinary differential equation:

[tex]\frac{dm}{dt} = -\frac{m}{\tau}[/tex] (Eq. 1)

Where:

[tex]\frac{dm}{dt}[/tex] - First derivative of mass in time, measured in miligrams per year.

[tex]\tau[/tex] - Time constant, measured in years.

[tex]m[/tex] - Mass of the radioactive isotope, measured in miligrams.

Now we obtain the solution of this differential equation:

[tex]\int {\frac{dm}{m} } = -\frac{1}{\tau}\int dt[/tex]

[tex]\ln m = -\frac{1}{\tau} + C[/tex]

[tex]m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }[/tex] (Eq. 2)

Where:

[tex]m_{o}[/tex] - Initial mass of isotope, measured in miligrams.

[tex]t[/tex] - Time, measured in years.

And time is cleared within the equation:

[tex]t = -\tau \cdot \ln \left[\frac{m(t)}{m_{o}} \right][/tex]

Then, time constant can be found as a function of half-life:

[tex]\tau = \frac{t_{1/2}}{\ln 2}[/tex] (Eq. 3)

If we know that [tex]t_{1/2} = 5730\,yr[/tex] and [tex]\frac{m(t)}{m_{o}} = 0.35[/tex], then:

[tex]\tau = \frac{5730\,yr}{\ln 2}[/tex]

[tex]\tau \approx 8266.643\,yr[/tex]

[tex]t = -(8266.643\,yr)\cdot \ln 0.35[/tex]

[tex]t \approx 8678.505\,yr[/tex]

The wood was cut approximately 8679 years ago.

Answer: 31 milligrams

Step-by-step explanation: As you can see on the chart you attached, 48 hrs equals 31 mg. One day is 24 hours, so that would mean two days in 48 hrs.

Answer: so the answer is A

Step-by-step explanation: -3/2

if you ever have a question like that again go to Math-way it is every helpful and easy.

Answer:

7(y+3)=5y+8

y= -3/2  One solution

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

you just divide 8 by 4 love:)

Answer:

It would be a triangular prism.

Step-by-step explanation:

We know this because of the two triangles at the top and bottom of this net and the rectangle connecting them. Then, if you imagine folding the second rectangle up, it would be one of the triangle's sides. Lastly for the third rectangle, it would be folded over the two triangles to finish the shape.

I hope this helps!!

Answer:

It would be a triangular prism

Step-by-step explanation:

If they ask how you got that say since the triangles at the top and bottom are both parell and to be a prim you need to have parell sides

Answer: -2 and -1

You have the correct answer.

Answer:

C

Step-by-step explanation:

I hope this helps!

Answer:

c

Step-by-step explanation:

Answer:

The following classification is found:

[tex](0.2, 6)[/tex] - Absolute minimum

[tex](-0.2, 10)[/tex] - Absolute maximum

Step-by-step explanation:

Let be [tex]f(x) = 125\cdot x^{3}-15\cdot x + 8[/tex], we need to find first and second derivatives of this expression at first:

First derivative

[tex]f'(x) = 375\cdot x^{2}-15[/tex] (Eq. 1)

Second derivative

[tex]f''(x) = 750\cdot x[/tex] (Eq. 2)

Critical points are points that equals first derivative to zero and that may be maxima or minima. That is:

[tex]375\cdot x^{2} -15 = 0[/tex]

[tex]x = \pm \sqrt{\frac{15}{375} }[/tex]

Which leads to the following critical points:

[tex]x_{1}\approx 0.2[/tex] and [tex]x_{2} \approx -0.2[/tex]

Now we evaluate each result in second derivative expression:

[tex]f''(x_{1}) = 750\cdot (0.2)[/tex]

[tex]f''(x_{1})=150[/tex] (Absolute minimum)

[tex]f''(x_{2})= 750\cdot (-0.2)[/tex]

[tex]f''(x_{2}) = -150[/tex] (Absolute maximum)

Lastly we evaluate the function at each critical point:

[tex]f(x_{1})= 125\cdot (0.2)^{3}-15\cdot (0.2)+8[/tex]

[tex]f(x_{1})= 6[/tex]

[tex]f(x_{2})= 125\cdot (-0.2)^{3}-15\cdot (-0.2)+8[/tex]

[tex]f(x_{2}) = 10[/tex]

And the following classification is found:

[tex](0.2, 6)[/tex] - Absolute minimum

[tex](-0.2, 10)[/tex] - Absolute maximum