Write the cations and anions present in CrO2

Answers

Answer 1

The chemical molecule CrO2 is also known as chromium(IV) oxide or chromic acid. It has the molecular formula CrO2 and is an inorganic substance.

In the solid state, CrO2 exists as a solid with a layered structure, and it is considered a cationic compound. The cation present in CrO2 is chromium(IV) ion, denoted as Cr4+.

On the other hand, the anion present in CrO2 is oxide ion, denoted as O2-. The oxidation state of oxygen in this compound is -2.

So, the cations present in CrO2 are Cr 4+ ions, and the anions present are O2 -2 ions.

In CrO2, the cation present is Chromium (Cr) with a charge of +4, and the anion present is Oxygen (O) with a charge of -2.

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Related Questions

2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l)
If 538 mol
of octane combusts, what volume of carbon dioxide is produced at 31.0 ∘C
and 0.995 atm?

Answers

The volume of the carbon dioxide is produced at the 31.0 °C and the 0.995 atm is 119,786 L.

The number of moles of octane = 538 mol

The moles of carbon dioxide = 4888 mol

The temperature of the gas = 31.0 °C

The pressure of the gas = 0.995 atm

The volume of the gas = ?

The ideal gas equation is :

P V = n R T

Where,

The p is the pressure = 0.995 atm

The V is the volume = ?

The n is moles of gas = 4888 mol

The R is gas constant = 0.823 atm L / mol K

The T is temperature = 31 + 273 = 304 K

V = n R T / P

V = ( 4888 mol × 0.0823 × 304 ) / 0.995

V = 119,786 L

The volume is 119,786 L.

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Silver chloride, AgCl, is a sparingly soluble solid. Answer the following questions about a saturated solution prepared by placing solid silver chloride in a 2.45 10-5 M NaCl(aq) solution. At some temperature, the silver ion concentration, [Ag+], was found to be 5.36 10-6 M.
(a) What is the concentration of chloride ions, [Cl − ], in the resulting solution?

Answers

The solubility of silver chloride (AgCl) can be represented by the following equilibrium equation:

AgCl(s) ⇌ Ag+(aq) + Cl-(aq)

In a saturated solution of AgCl, the concentration of Ag+ ions is equal to the solubility product constant (Ksp) for AgCl at that temperature. Since the concentration of Ag+ ions in the solution is given as 5.36 x 10^-6 M, we can write:

[Ag+] = 5.36 x 10^-6 M

According to the stoichiometry of the equilibrium equation, the concentration of chloride ions ([Cl-]) is also equal to the concentration of Ag+ ions, as one mole of AgCl dissociates to yield one mole of Ag+ ions and one mole of Cl- ions. Therefore:

[Cl-] = 5.36 x 10^-6 M

So, the concentration of chloride ions in the resulting solution is 5.36 x 10^-6 M.

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A sample of gas is contained in a 245 mL flask at a temperature of 23.5°C. The gas pressure is 37.8 mm Hg. The gas is moved to a new flask, which is then immersed in ice water, and which has a volume of 54 mL. What is the pressure of the gas in the smaller flask at the new temperature?

Answers

We can use the combined gas law to solve this problem:

(P1V1/T1) = (P2V2/T2)

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

We are given that the initial pressure is P1 = 37.8 mm Hg and the initial volume is V1 = 245 mL. The initial temperature is T1 = 23.5°C, which we need to convert to Kelvin by adding 273.15:

T1 = 23.5°C + 273.15 = 296.65 K

We are also given that the final volume is V2 = 54 mL, and the final temperature is the temperature of the ice water, which is 0°C or 273.15 K.

Now we can solve for the final pressure, P2:

(P1V1/T1) = (P2V2/T2)

P2 = (P1V1T2) / (V2T1)

P2 = (37.8 mm Hg * 245 mL * 273.15 K) / (54 mL * 296.65 K)

P2 = 24.4 mm Hg

Therefore, the pressure of the gas in the smaller flask at the new temperature is 24.4 mm Hg.

A solution has [H+] = 1.39x10^-6 M. What is the pH?

Answers

Answer:

the pH of the solution is approximately 5.857.

Explanation:

The pH of a solution can be calculated using the formula:

pH = -log[H+]

where [H+] is the concentration of hydrogen ions in moles per liter (M).

In this case, [H+] = 1.39x10^-6 M, so:

pH = -log(1.39x10^-6)

= 5.857

Therefore, the pH of the solution is approximately 5.857.

The density of a test gas is to be determined experimentally at 289.2 K using an apparatus constructed of a 4.050 L glass bulb volume that is attached to a vacuum pump. The mass of the evacuated bulb is 22.513 g. After it is filled with the test gas to a pressure of 0.0250 atm, the mass increases to 22.651 g. Assume the gas behaves ideally.
What is the density of the gas? How many moles of gas are in the bulb? What is the apparent molar mass of the gas?

Answers

The density of the gas is  0.0340 g/L, moles of gas in the bulb is 0.00124 mol and apparent molar mass is 111.3 g/mol.

How to calculate density, moles and molar mass?

To determine the density of the gas, use the ideal gas law:

PV = nRT

where P = pressure, V = volume, n = number of moles, R = gas constant, and T = temperature.

Since the volume and temperature are constant:

(P/n) = constant

Therefore, the density (ρ) of the gas is given by:

ρ = (m-m₀)/V = (Δm)/V

where m = mass of the bulb filled with the gas, m₀ = mass of the evacuated bulb, and Δm = m - m₀ is the mass of the gas.

Substituting the given values:

Δm = 22.651 g - 22.513 g = 0.138 g

V = 4.050 L

ρ = 0.138 g / 4.050 L = 0.0340 g/L

To find the number of moles of gas in the bulb, use the equation:

n = PV/RT

Substituting the given values:

n = (0.0250 atm)(4.050 L) / (0.0821 L·atm/mol·K)(289.2 K) = 0.00124 mol

Finally, to find the apparent molar mass of the gas, use the equation:

M = m/n

where M = molar mass of the gas and m = mass of the gas.

Substituting the given values:

M = 0.138 g / 0.00124 mol = 111.3 g/mol

Therefore, the density of the gas is 0.0340 g/L, there are 0.00124 mol of gas in the bulb, and the apparent molar mass of the gas is 111.3 g/mol.

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Help!!!!!!!!!!!!!!!!!!!!!!!

Answers

All of the equation-related claims are not entirely true. The appropriate chemical formula should be:

Fe(OH)3 + 3NH4Cl = FeCl3 + 3NH4OH

Because the total mass of the reactants and products are equal, as well as the number of each type of atom in each of the reactants and products, mass is conserved in this balanced equation. Depending on the stoichiometric coefficients in the balanced equation, there may or may not be an equal amount of molecules in the reactants and products.

Iron(III) hydroxide (Fe(OH)3) and ammonium chloride (NH4Cl) are the products of the chemical reaction between iron(III) chloride (FeCl3) and ammonium hydroxide (NH4OH).

The coefficients (the numbers in front of the chemical formulae) must be changed to make sure that the number of each type of atom is the same on both sides of the equation in order to ensure that the equation is balanced. The coefficients in this instance are:

Fe(OH)3 + 3NH4Cl = FeCl3 + 3NH4OH

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Hellpppp with this question!!! THE ANSWER IS NOT 0.3 or 0.5

Answers

the answer is 2.5 according to me

help with questions 1-5 pls??

Answers

In comparison to towns located inland, cities close to water features like lakes or oceans typically experience cooler summer temperatures.

Why is a city not so hot in summer when the city is close to water?

Since water has a higher specific heat capacity than land, this is the case. The quantity of energy needed to raise a substance's temperature by a specific amount is known as its specific heat capacity. Compared to land, raising the temperature of water requires more energy because water has a higher specific heat capacity.

The summer sun warms both land and water, but due to land's lower specific heat capacity, land warms up more quickly than water. As a result, communities farther from water bodies tend to be hotter than cities closer to water.

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please help show i need help​

Answers

The complete table for the phase changes would be as follows:

solid to liquid: melting, heating, IMF's breaking, energy absorbedliquid to gas: vaporization, heating, IMF's breaking, energy absorbedsolid to gas: sublimation, heating, IMF's breaking, energy absorbedliquid to solid: freezing, cooling, IMF's forming, energy releasedgas to solid: deposition, cooling, IMF's forming, energy releasedgas to liquid: condensation, cooling, IMF's forming, energy released

What are phase changes?

Phase changes occur when a substance changes from one phase to another. When a significant amount of energy is gained or lost, this process takes place.

Phase change also depends on elements like pressure and temperature.

There are six ways a substance can change between these three phases; melting, freezing, evaporating, condensing, sublimation, and deposition.

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Which of the following statements confirms the law of conservation of energy?

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Statement that shows that the total energy of a system remains constant and is conserved would confirm the law of conservation of energy.

What is law of conservation?

The law of conservation of energy states that energy cannot be created or destroyed, only transformed from one form to another. Therefore, any statement that shows that the total energy of a system remains constant and is conserved would confirm the law of conservation of energy.

Here are some examples of statements that confirm the law of conservation of energy:

The total energy of a closed system, such as a roller coaster, remains constant as the coaster moves from one point to another. Even though the potential energy of the coaster decreases as it goes downhill and the kinetic energy increases, the total energy of the coaster (potential plus kinetic) remains constant.

When a pendulum swings back and forth, the potential energy is converted into kinetic energy and back again, but the total energy of the pendulum remains constant.

In a chemical reaction, the total energy of the reactants is equal to the total energy of the products. Although energy can be released or absorbed during the reaction, the total energy of the system is conserved.

When a ball is thrown into the air, it gains potential energy as it rises and loses potential energy as it falls back down. However, the total energy of the ball (potential plus kinetic) remains constant, neglecting air resistance.

All of these statements confirm the law of conservation of energy by showing that the total energy of a system is conserved over time.

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Complete question is: "The total energy of a system remains constant and is conserved" statement would confirm the law of conservation of energy.

Perform the conversions between energy units.
6.61 x 10^6 J = ___kcal. My initial answer was 6610 but it was wrong can someone show me how to get the correct answer

Answers

After considering the given data and performing the evaluation regarding the convertion of energy units the answer derived is 6.61 x 10⁶ J = 1577.16 kcal.

In order to alter joules (J) to kilocalories (kcal), the below conversion can be applied.
1 kcal = 4.184 kJ.
We start by, converting J to kJ by dividing by 1000:
6.61 x 10⁶ J = 6.61 x 10³ kJ
Next step we convert kJ to kcal by dividing by 4.184:
= 6.61 x 10³ kJ ÷ 4.184
= 1577.16 kcal (rounded to five significant figures)


1 joule (J) is the amount of energy needed to apply a force of 1 newton (N) over a distance of 1 meter (m).
1 kilocalorie (kcal), on the other hand, is described as the amount of energy required to increase the temperature of 1 kilogram (kg) of water by 1 degree Celsius (°C), which is equal to 4184 joules (J).
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What is the difference between practical work inside a laboratory and outside a laboratory

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Answer:

The main difference between practical work inside and outside a laboratory is that the practical work inside the lab includes good equipment and chemicals which are very advanced and the practical outside a laboratory is more about the safety of life.

Explanation:

Practicals are set up at stations with lab equipment and chemicals, where students can learn, and researchers can experiment and find different new things.

Thus, the practical work inside the lab includes lab equipment and chemicals, and the practical outside a laboratory is more about conserving nature.  

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You want to make a 50 mL SATURATED solution of potassium chloride at 40 degrees Celsius. How many grams of potassium chloride do you need?

Answers

We need 21 grams of potassium chloride to make a 50 mL saturated solution at 40 degrees Celsius. It's important to note that if the temperature or volume of the solution were to change, the amount of solute needed to make a saturated solution would also change, as solubility is dependent on both temperature and volume.

According to the solubility table, the solubility of potassium chloride at 40 degrees Celsius is 42 grams per 100 mL of water. This means that we can dissolve 42 grams of potassium chloride in 100 mL of water at 40 degrees Celsius to make a saturated solution.


To make a 50 mL saturated solution, we can use the following formula:
mass of solute = (volume of solution x solubility)/100
mass of solute = (50 x 42)/100
mass of solute = 21 grams
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5. A sample of unknown metal has a mass of 135 grams. As the sample cools from 100.5 °C to 35.5 °C, it releases 7500 joules of energy. What is the specific heat of the sample?
please show work ​

Answers

The sample of the unknown metal has the mass of the 135 grams. The sample cools from the 100.5 °C to the 35.5 °C, and it releases the 7500 joules of the energy. The specific heat of the sample is 0.854 J/g °C.

Th mass of the metal = 135 g

The initial temperature = 100.5 °C

The final temperature = 35.5 °C

The heat energy releases = - 7500 J

The heat energy is expressed as :

Q = mc ΔT

Where,

The m is mass of the metal = 135 g

The c is the specific heat capacity = ?

The Q is heat energy releases = - 7500 J

The ΔT is the change in the temperature = final temperature - initial temperature.

The ΔT is the change in the temperature = 35.5 - 100.5

The ΔT is the change in the temperature =  - 65 °C

The specific heat capacity, c = Q / m ΔT

The specific heat capacity, c = - 7500 / 135 × - 65

The specific heat capacity, c = 0.854 J/g °C

The specific heat capacity of metal is 0.854 J/g °C.

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please help me pair pka values with displayed molecules

Answers

If we label the compounds ABCD from left to right;

A - 12.10

B - 15.90

C - 12.66

D - 12.35

What is the pKa?

A molecule or compound's acidity is quantified by the pKa, which is the negative logarithm (base 10) of the acid dissociation constant (Ka). The lower the pKa value, the stronger the acid; it reflects a compound's propensity to give a proton (H+) in a solution.

The compound that has the highest number of attachment of the most electronegative elements would have the greatest pKa.

The justification of the answer above is that, seeing that the compound labelled B has three highly electronegative atoms hence it would have the most or the highest pKa of about  15.90 among the other compounds. The other compounds A, C and D have fewer electronegative atoms attached and thus a lower pKa as shown

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After writing the correct formulas for the reactants and products, the equation is balanced by a. adjusting subscripts to the formula(s). b. adjusting coefficients to the smallest whole-number ratio. c. changing the products formed. d. making the number of reactants equal to the number of products.

Answers

After writing the correct formulas for the reactants and products, the equation is balanced by adjusting coefficients to the smallest whole-number ratio. The correct answer is option b.

Adjusting the coefficients to the smallest whole-number ratio is the process of balancing a chemical equation. Balancing the equation means that the number of atoms of each element on the reactant side must equal the number of atoms of each element on the product side.

The coefficients in front of the formulas of the reactants and products are used to balance the equation. By adjusting the coefficients, you can make sure that the number of atoms of each element is balanced on both sides of the equation. Therefore option b is correct

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Draw a model of the four types of nuclear decay and explain each. Pick the same element (Si-32) to start with.

Answers

Sure, I can explain the four types of nuclear decay and provide a model for each using Si-32 as an example.

Si-32 is a radioactive isotope of Silicon with 14 protons and 18 neutrons.

1. Alpha Decay:

In alpha decay, an unstable nucleus emits an alpha particle, which consists of two protons and two neutrons, reducing the atomic number by two and the mass number by four. This makes the resulting nucleus a different element.

Model: Si-32 → alpha particle + Mg-28

Explanation: Si-32 decays into an alpha particle (two protons and two neutrons) and becomes Mg-28.

2. Beta Decay:

In beta decay, a neutron is converted into a proton and an electron. The proton stays in the nucleus, and the electron is emitted as a beta particle. This increases the atomic number by one while keeping the mass number the same.

Model: Si-32 → beta particle + P-32

Explanation: Si-32 decays into a beta particle (an electron) and becomes P-32.

3. Gamma Decay:

Gamma decay occurs when an unstable nucleus emits high-energy photons called gamma rays. Unlike alpha and beta decay, gamma decay does not change the atomic number or mass number of the nucleus.

Model: Si-32 → Si-32 + gamma ray

Explanation: Si-32 emits a gamma ray but remains Si-32.

4. Electron Capture:

In electron capture, an unstable nucleus absorbs an electron from an inner shell, converting a proton into a neutron. This reduces the atomic number by one while keeping the mass number the same.

Model: Si-32 + electron → Al-32

Explanation: Si-32 captures an electron and becomes Al-32.

These four types of nuclear decay can occur in radioactive isotopes, and they result in a change in the atomic number and/or mass number of the nucleus.

What do not have true leaves or roots

Answers

Answer: Moss

Explanation: It's a flowerless plant

Н
HOH
14
Н-С-С-С-Н
I
ННН
List the number of each atom in the formulas above:
H
НН Н
Н-С-С-С-О-Н
LI
НН Н
DONE
Н Н
H
Н-С-С-О-С-Н
II
Н Н
H

Answers

Answer:

Explanation:

It seems like you’re trying to count the number of atoms in some chemical formulas. Here’s the list of the number of each atom in the formulas you provided:

Formula 1: Н - 1 Formula 2: H - 1, O - 1 Formula 3: Н - 14 Formula 4: Н - 2, C - 3 Formula 5: I - 1 Formula 6: Н - 3 Formula 7: H - 2 Formula 8: Н - 2, C - 3, O - 1 Formula 9: Li - 1 Formula 10: Н - 2 Formula 11: Н - 2 Formula 12: H - 1 Formula 13: Н - 2, C - 2, O - 1 Formula 14: II

A sample of air occupies 0.75 L at standard conditions. What is the pressure in atm if the volume is 100.0 mL at 25oC?

P1 = 760 mmHg P2 = ?
V1 = 0.750 L V2 = 100.0 mL
T1 = 273 K T2 = 25oC

Answers

According to the ideal gas law, a gas's pressure is inversely related to its volume and directly proportionate to its temperature. So, if a gas sample's volume is reduced, the gas sample's pressure must also increase.

As a result, in order to determine the pressure of the gas sample under the specified circumstances, we must first determine the ratio of the two volumes before multiplying the starting pressure of the sample by that ratio.

We may get the ratio of the two volumes using the ideal gas law as follows: V2/V1 = (100.0 mL/0.75 L) x (273 K/25oC) = 8.02 As a result, the gas sample's pressure at 25 oC with a volume of 100.0 mL is 8.02 times higher than the sample's original pressure.

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Which solution would you choose to supress the dissolution of MgCO3?

A. 0.200 M NaCl
B. 0.200 HCl
C. 0.200 M NaNO3
D. 0.200 M Na2CO3

Answers

The best solution to suppress the dissolution of MgCO3 is option D 0.200 M Na2CO3

To suppress the dissolution of MgCO3

We need to add an ion or compound that will react with MgCO3 and form a precipitate, thus removing Mg2+ and CO32- ions from the solution.

Therefore, Option D, 0.200 M Na2CO3, contains CO32- ions that can react with Mg2+ ions to form MgCO3 precipitate. This would effectively suppress the dissolution of MgCO3 by removing Mg2+ and CO32- ions from the solution.

Therefore, option D is the best solution to suppress the dissolution of MgCO3.

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What is the equilibrium constant, K? 3 A(g) + 3 B(g) <-> 5 C(g) + 2 D(g)

Answers

The equilibrium constant is written as;

Keq = [tex][D]^2 [C]^5/[A] [B]^3[/tex]

What is the equilibrium constant?

The equilibrium constant's value is influenced by the reaction's chemical make-up and temperature.

The product of the product concentrations, each raised to the power of their stoichiometric coefficient, divided by the product of the reactant concentrations, each raised to the power of their stoichiometric coefficient, is known as the equilibrium constant.

The equilibrium constant is Keq = [tex][D]^2 [C]^5/[A] [B]^3.[/tex]

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The enthalpy combustion of ethanol is -1430 kJ/mol. Determine heat given off from the combustion of 1 dm³ of ethanol. Given density of ethanol is 0.79 gcm³. (molar mass ethanol = 46 g/mol)​

Answers

Answer:

The enthalpy of combustion of ethanol is -1430 kJ/mol, which means that for every mole of ethanol that is burned, 1430 kJ of heat is released.

To determine the amount of heat given off from the combustion of 1 dm³ of ethanol, we need to first calculate the number of moles of ethanol in 1 dm³.

1 dm³ is equivalent to 1000 cm³. Since the density of ethanol is 0.79 g/cm³, the mass of 1 dm³ of ethanol can be calculated as:

mass = density x volume

mass = 0.79 g/cm³ x 1000 cm³

mass = 790 g

To convert this mass to moles, we need to divide by the molar mass of ethanol:

moles = mass / molar mass

moles = 790 g / 46 g/mol

moles = 17.17 mol

Therefore, 1 dm³ of ethanol contains 17.17 moles of ethanol.

To calculate the heat given off from the combustion of 1 dm³ of ethanol, we can use the following equation:

heat = enthalpy of combustion x moles of ethanol

heat = -1430 kJ/mol x 17.17 mol

heat = -24,551 kJ

Therefore, the heat given off from the combustion of 1 dm³ of ethanol is -24,551 kJ, or approximately 24,551 kJ of heat is released.

An argon ion laser emits visible radiation with photons of energy 4.071 x 10-19 J. What is the
wavelength of the radiation?

Answers

The wavelength of the radiation emitted by the argon ion laser is [tex]4.854 * 10^-7 m[/tex].

Wavelength is a property of any type of wave that refers to the distance between two adjacent points on the wave that is in phase, i.e., at the same point in their respective cycles. It is usually denoted by the Greek letter lambda (λ) and is measured in units of length, such as meters or nanometers.

The energy carried by the photon (E) is related to the wavelength ([tex]\lambda[/tex]) through the following equation:

[tex]E=hc/\lambda[/tex]; where 'h' is the Plank's Constant and 'c' is the speed of light which is [tex]3* 10^{-7} m/s[/tex].

We can say that

[tex]\lambda - hc/E[/tex]

Now after substituting the given values, we get:

[tex]\lambda = (6.626 * 10^{-34} J.s * 3.00 * 10^8 m/s) / (4.071 * 10^{-19} J)\\\lambda = 4.854 * 10^-7 m[/tex]

Therefore the wavelength of the radiation emitted by the argon ion laser is [tex]4.854 * 10^-7 m[/tex].

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What mass (grams) of silver oxide would you need to decompose in order to produce 120.6 grams of silver?

Ag2O --> Ag + O2

Answers

The mass of silver oxide needed to decompose in order to produce 120.6 grams of silver is 494.5 grams.

The balanced chemical equation for silver oxide breakdown is:

[tex]Ag_2O[/tex] → [tex]2 Ag[/tex] + [tex]1/2 O_2[/tex]

The equation shows that for every mole of silver oxide that decomposes, two moles of silver are created, and the molar mass of [tex]Ag_2O[/tex] is 231.74 g/mol.

Hence, using stoichiometry, we can calculate the quantity of silver oxide necessary to generate 120.6 grams of silver:

120.6 g Ag × (1 mol Ag / 107.87 g Ag) × (1 mol [tex]Ag_2O[/tex]/ 2 mol Ag) × (231.74 g [tex]Ag_2O[/tex] / 1 mol [tex]Ag_2O[/tex] )

= 494.5 g [tex]Ag_2O[/tex]

As a result, 494.5 grams of silver oxide is needed to decompose in order to produce 120.6 grams of silver.

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N
01H
H
The property of water shown allows it to-
A freeze faster than it boils due to sharing metallic bonds
B. support floating objects due to forces between covalent bonds
C remain stable due to electrons forming ionic bonds
D. be both cohesive and adhesive due to hydrogen bonds

Answers

Answer:

D

Explanation:

The special property of water is that it is able to be cohesive and adhesive due to their hydrogen bonds

What happens to the particles of a gad when the gas is compressed

Answers

Answer:

When the gas is compressed, its molecules come closer and internal energy of gas is increased and the number of collisions will also increase. As the gas is compressed, the work done on it shows up as increased internal energy, which must be transferred to the surroundings to keep the temperature constant.

Write the net chemical equation for the production of manganese from manganese (II) carbonate, oxygen and aluminum. Be sure your equation is balanced.

Answers

Answer:

Explanation:

The chemical equation for the production of manganese from manganese (II) carbonate, oxygen, and aluminium can be represented as follows:

3MnCO3(s) + 3O2(g) + 4Al(s) → 3Mn(s) + 3CO2(g) + 2Al2O3(s)

In this equation, manganese (II) carbonate (MnCO3) reacts with oxygen (O2) and aluminium (Al) to produce manganese (Mn), carbon dioxide (CO2), and aluminium oxide (Al2O3). The equation is balanced with three molecules of manganese carbonate, three molecules of oxygen, and four molecules of aluminium reacting to produce three molecules of manganese, three molecules of carbon dioxide, and two molecules of aluminium oxide.

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For the Li2 molecule, rank order the following orbitals from lowest to highest energy: 1s, 2s, σ2s, σ*2s

Answers

The order of the energy levels for the Li2 molecule is:

1s < σ2s < 2s < σ*2s

The 1s orbital is the lowest in energy because it is closest to the nucleus and has the highest electron density. The σ2s orbital is next in energy because it is a bonding orbital that is formed by the overlap of two atomic 2s orbitals. The 2s orbital is higher in energy than the σ2s orbital because it is an atomic orbital that has not participated in bonding. The σ*2s orbital is the highest in energy because it is an antibonding orbital that weakens the bond between the two Li atoms.

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Based on the solubility rules, which one of these phosphate compounds is insoluble in water?
A) Li2CO3
B) Na3PO4
C) Ba(OH)2
D) (NH4)3PO4

Answers

(NH4)3PO4 is insoluble in water. The correct option is D

What is solubility rules ?

According to their chemical formula and ionic charges, ionic compounds generally follow a set of solubility laws that define their solubility patterns in water. These guidelines aid in determining whether an ionic compound will dissolve in water or not as well as if it will precipitate when combined with other ionic compounds.

Therefore, (NH4)3PO4 is the compound that is expected to be insoluble in water based on the solubility rules.

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An aqueous solution of sodium acetate, nach3coo, is made by dissolving 13.8 grams of sodium acetate in sufficient water in a 300. ml volumetric flask, and then adding enough water to fill the flask to the mark. what is the weight/volume percentage of sodium acetate in the solution? in the spirit of ubuntu, how would you promote social cohesion and interdependence in your inclusive classroom Find the line of tangency to the circle defined by (x-3)^2 + (y-7)^2 = 169 at the point (15,2). help please ill give brainliest Europeans generally believed all of the following about Indians EXCEPT that:A. Indians lacked genuine religion. B. Indians had enormous potential to assimilate European ways. C. Indian males were weak and mistreated women. D. Indians did not use the land and thus had no claim to it. The author makes several references to goldilocks throughout the article. To whom or what does the author compare goldilocks? How does these comparisons contribute to the development of the article as a whole. Article's here:file:///C:/Users/shirl/Downloads/Ready+Unit+3+Interim+Assessment+Student%20(1). Pdf A tunnel is shaped in the form of a semi-ellipse. The width of the tunnel is 20 feet and the height of the tunnel is 12 feet. A train is 10 feet wide and centered in the tunnel. Determine whether a 10-foot high train would have clearance to pass through. If so, by how much? If not, by how much? (Nearest inch.) Gladstone company tracks the number of units purchased and sold throughout each accounting period but applies its inventory costing method at the end of each period, as if it uses a periodic inventory system. assume its accounting records provided the following information at the end of the annual accounting period, december 31. transactions units unit cost beginning inventory, january 1 1,800 $ 50 transactions during the year: a. purchase, january 30 2,500 62 b. sale, march 14 ($100 each) (1,450) c. purchase, may 1 1,200 80 d. sale, august 31 ($100 each) (1,900) assuming that for specific identification method (item 1d) the march 14 sale was selected two-fifths from the beginning inventory and three-fifths from the purchase of january 30. required: compute the amount of goods available for sale, ending inventory, and cost of goods sold at december 31 under each of the following inventory costing methods: a. last-in, first-out. b. weighted average cost. c. first-in, first-out. d. specific identification, assuming that the march 14 sale was selected two-fifths from the beginning inventory and three-fifths from the purchase of january 30. assume that the sale of august 31 was selected from the remainder of the beginning inventory, with the balance from the purchase of may 1. 2-a. of the four methods, which will result in the highest gross profit Please help with the 2nd one What is 2 + 2? I thought it was 4 but I don't know. This is making people drop grades when they are caught cheating, I would love it if you made changes, or at least make it so people can't cheat. Please take this to consideration. edictions)1. So far, Macbeth has been wavering in the plan to make the predictions come to fruition,while Lady Macbeth has been stalwart. Going forward, how do you think these roles willevolve?Type Here A survey was taken by students in 6th, 7th, and 8th grade to determine how many first cousins they have. The results are shown in the box plots below. Use these box plots to answer the questions. Show that the two straight lines through the origin which make an angle 45 with the line px + qy + r = 0 are given by the equation (p-q)(x - y) + 4pqxy = 0. I Need help with this math problem HELP!! Which statements describe the end behavior of f(x)?f(x)?Select two answers. the following selected data were taken from the books of the owens o-rings company. the company uses job costing to account for manufacturing costs. the data relate to april operations. (1) materials and supplies were requisitioned from the stores clerk as follows: job 405, material x, $7,000. job 406, material x, $3,000; material y, $6,000. job 407, material x, $7,000; material y, $3,200. for general factory use: materials a, b, and c, $2,300. (2) time tickets for the month were chargeable as follows: job 405$11,0003,000hours job 406 14,0003,600hours job 407 8,0001,900hours indirect labor 3,700 (3) other information: factory paychecks for $36,700 were issued during the month. various factory overhead charges of $19,400 were incurred on account. depreciation of factory equipment for the month was $5,400. factory overhead was applied to jobs at the rate of $3.50 per direct labor hour. job orders completed during the month: job 405 and job 406. selling and administrative costs were $2,100. factory overhead is closed out only at the end of the year. the end of the month work-in-process inventory balance would be: Kyle is buying gifts for Megan's birthday and needs to stay in budgetCake = half his money + 36.50Decorations = half of what he had left + 36.50Sweets = half of what he had left + 18.25Now he is out of money, what did he start with? Ten sixth-grade students reported the hours of sleep they get on nightsbefore a school day. Their responses are recorded in the dot plot. Lookingat the dot plot, Lin estimated the mean number of hours of sleep to be 8. 5hours. Noah's estimate was 7. 5 hours. Diego's estimate was 6. 5hours. Which estimate do you think is best? Solve for the mean to figure outwho was closer. *LinNoahDiego Solve x3 < 5 Question 12 options: A) x < 15 B) x 15 C) x 15 D) x > 15 Consider the initial value problem for function y, y (0) = 4. y" + y' - 2 y = 0, y(0) = -5, Find the Laplace Transform of the solution, Y(5) = 4 [y(t)] Y(s) = M Note: You do not need to solve for y(t)