Write the balanced equation for the reaction between HCl and NaOH. Then, calculate the molarity of the NaOH.

Answer:

C. 7.4 kJ

Explanation:

Let assume that Mercury is at room temperature (25 °C). The energy required to boil the sample of mercury is the sum of sensible and latent heats. Mercury has a fussion and boiling points of -38.83 °C and 356.7 °C, respectively, and a specific heat of [tex]138\,\frac{J}{kg\cdot ^{\circ}C}[/tex]. Then:

[tex]Q = (25\,g)\cdot \left[\left(0.138\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (356.7^{\circ}C - 25^{\circ}C) + 296\,\frac{J}{g} \right][/tex]

[tex]Q = 8544.365\,J[/tex]

The option that offers the best approximation to the result is C.

Answer:

the valency of oxygen is -2

Answer:

-2

Explanation:

The valency of oxygen is -2. This means oxygen needs to gain or share two electrons for stability.

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Answer:

Heat energy required (Q) = 10.736 KJ

Explanation:

Given:

Specific heat of ethanol (C) = 2.44 J/g °C

Mass of ethanol (M) = 50 gram

Initial temperature (T1) = -20°C

Final temperature (T1) = 68°C

Find:

Heat energy required (Q) = ?

Computation:

Change in temperature (ΔT) = 68°C - (-20°C)

Change in temperature (ΔT) = 88°C

Heat energy required (Q) = mC(ΔT)

Heat energy required (Q) = (50)(2.44)(88)

Heat energy required (Q) = 10,736 J

Heat energy required (Q) = 10.736 KJ

Answer:

A

-1440J

Explanation:

Hello,

This question requires us to calculate the work done on a object to move it from point A to point B

Data

Mass = 60kg

Initial velocity (V1) = 8.0m/s

Final velocity (V2) = 4.0m/s

Workdone on an object is equal to force applied on the object to move it through a particular distance.

Work done = force × distance

Force (F) = mass × acceleration

Distance = s

F = Ma

Work done = M× a × s

But a = velocity (v) / time (t)

Work done = mvs / t

But velocity = distance/ time

Work done = mv × v/

Work done = mv²

Work done = ½mv²

Workdone = ½M(V2² - V1²)

Workdone = ½ × 60 (4² - 8²)

Work done = 30 × (16 - 64)

Workdone = 30 × (-48)

Work done = -1440J

Work done = -1.44kJ

The workdone on the object is equal to -1.44kJ

Answer:

–1,440 J

Explanation:

a on edge 2021

Metals are solids, non metals are gasses and metalloids are in between metals and non metals. Also, metals have there atoms all close and packed, non metals have there atoms far apart, and metalloids have there atoms either close or far apart. Metals are separated form the non metals in the periodic table.