WILL MARK BRAINLIST!! The image depicts the composition of air. Use the image to explain why this statement is correct: “Mixtures are composed of different proportions of pure substances.”

Synthesis reaction

It is a reaction in which 2 or more reactants combine with each other to form one product .

Check option C

Sulphate and water are combining to form sulfuric acid .

Hence option C is correct

Answer:

SO3 + H2O => H2SO4

Explanation:

I took the test :)

Answer: When this atom loses an electron, the result is a positive ion.

Explanation:

Answer:

Las Vegas is expected to recieve less precipitation

Ionization reaction gives the ionization state of the chemical species. Its ionization will result in a conjugate base of the formic acid and release a hydrogen ion.

The acid dissociation constant is the concentration of the acid that has been dissociated into its constituents ions in the solution.

The ionization equation of the formic acid is:

[tex]\rm HCOOH \rightleftharpoons HCOO^{-} + H^{+}[/tex]

The acid dissociation constant (Ka) for formic acid is given as,

[tex]\rm Ka = \rm \dfrac {[H^{+}][HCOO^{-}]}{[HCOOH]}[/tex]

Anions are negatively charged ions and formate ions generated in the dissociation of the formic acid.

Therefore, the formate ion is an anion.

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The Delta G for the autoionization of water can be calculated as [tex]\Delta G=-RTlnK[/tex].

The autoionization of water is given as the reaction of the two water molecules, resulting in the formation of the ions of hydronium and hydroxide ion.

It can be expressed as:

[tex]\rm 2\;H_2O\;\leftrightharpoons\;H_3O^+\;+\;OH^-[/tex]

The[tex]\Delta G[/tex] of the autoionization of water can be given as;

[tex]\Delta G=-RTlnK[/tex]

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The molar solubility of AuCl₃ in 0.010M MgCl₂ is 4 ×10⁻²⁰M.

The solubility product constant, Ksp, is the equilibrium constant for a solid substance dissolving in an aqueous solution. And for the AuCl₃ Ksp will be written as: Ksp = [Au³⁺][Cl⁻]³

AuCl₃(aq) ⇄ Au³⁺(aq) + 3Cl⁻(aq)

Let the solubility of the AuCl₃ in 0.013m solution of magnesium chloride is x, of Au³⁺ is x and of Cl⁻ is 3x. But we know that MgCl₂ is a strong electrolyte and it completely dissociates into its ion and will produce 2 moles of chloride ions. For this solution let we consider the volume is 1 litre then the concentration of chloride ions in MgCl₂ is 2(0.010) = 0.020M.

So, in MgCl₂ solution concentration of Cl⁻ becomes = 3x + 0.020.

Value of Ksp for AuCl₃ = 3.2 × 10⁻²⁵

On putting all values on the Ksp equation, we get

Ksp = (x)(3x + 0.020)³

Value of 3x is negligible as compared to the 0.020, so the equation becomes

3.2 × 10⁻²⁵ = (x)(0.020)³

x = 3.2×10⁻²⁵ / (0.020)³

x = 4 ×10⁻²⁰M

Hence the molar solubility of AuCl₃ in 0.010M MgCl₂ is 4 ×10⁻²⁰M.

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The concentration of the 2.22 mL perchloric acid that was neutralized with barium hydroxide is 3.1 M.

The neutralization is given as the reaction of the acid and the base forming salt. The reaction of 1 mole of barium hydroxide requires 2 moles of perchloric acid to neutralize completely.

The volume of barium hydroxide given was 15.1 mL. The moles of barium hydroxide has been:

[tex]\rm 1000\;mL\; Ba(OH)_2 = 0.2288 \;mol Ba(OH)_2\\\\15.1\;mL\;Ba(OH)_2=0.0034\;mol[/tex]

The moles of perchloric neutralized by 0.0034 mol barium hydroxide will be:

[tex]\rm 1\;mol\;Ba(OH)_2=2\;mol\;HClO_4\\\\\rm 0.0034\;mol\;Ba(OH)_4=0.0069\;mol\;HClO_4[/tex]

The volume of perchloric has been 2.22 mL. The concentration of the acid is given as:

[tex]\rm Concentration=moles\;\times\dfrac{1000}{volume(mL)}\\\\Concentration=0.0069\;mol\;\times\dfrac{1000}{2.22}\\\\Concentration=3.1\;M[/tex]

The concentration of the perchloric acid aliquot is 3.1 M.

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The total pressure of the gas is calculated as 849 mmHg.

The term partial pressure is the pressure that is exerted by an individual gas in a mixture of gases.

In this case, the partial pressures of hydrogen and water are 789 mmHg and  60 mmHg respectively.

Thus, the total pressure of the gas =  60 mmHg +  789 mmHg = 849 mmHg.

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Answer:

T = (Z x 10) + 50

Explanation:

Answer:

It means there are 6 O2 molecules

Explanation:

If there are equal moles of each gas, what is the partial pressure of H₂ is 0.362.

The pressure that one of the gases in a mixture would exert if it were in the same volume on its own.

According to the Dalton's law of partial pressure

The Partial pressure of a gas = (Total pressure × mole fraction of the particular gas)

Partial pressure of H₂ is

[tex]\dfrac{1.81}{5.00} = 0.362[/tex]

Thus, the partial pressure of H₂ is 0.362.

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The mass of the formed precipitate of AgCl in the reaction is 1.29 grams.

Moles (n) of any substance from molarity (M) will be calculated by using the below equation:
M = n/V, where

V = volume in L

Given chemical reaction is:
2AgNO₃(aq) + CaCl₂(aq) → 2AgCl(s) + Ca(NO₃)₂(aq)

From the stoichiometry of the reaction, mole ratio of AgNO₃ to CaCl₂ is 2:1.

0.0015 moles of AgNO₃ = reacts with 1/2×0.0045 = 0.00075 moles of CaCl₂

Here CaCl₂ is the limiting reagent, and formation of precipitate depends on this only.

Again from the stoichiometry of the reaction:

0.0045 moles of CaCl₂ = produces 2(0.0045) = 0.009 moles of AgCl

Mass of 0.009 moles AgCl will be calculated as:

n = W/M, where

W = (0.009)(143.45) = 1.29g

Hence required mass of precipitate is 1.29 grams.

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Between A and B

The highest probability is that A and B are solids and they are forming liquid or gases.

Between A and C

Highest probability is that A and C are gases and they are turning into liquid or solid

The concentration required to begin to precipitate PbCl2 for PbCl2 is 0.0216 M.

Molarity is the measure of the concentration of any solute in per unit volume of the solution.

The reaction is [tex]\rm Pb^2^+(aq) + 2Cl^-(aq) \rightarrow PbCl_2(s).[/tex]

The molarity of lead is 0.025 M

The ksp is given 17×10⁻⁵

Now, calculating the concentration

[tex][Pb^2^+] = 0.025 M.\\Ksp = 1.17 \times 10^-^5\\Ksp = [Pb^2^+] \times [Cl^-]^2\\[Cl^-] = \dfrac{\sqrt{ Ksp}}{[Pb^2^+]} \\\\[Cl^-] = \dfrac{\sqrt{ 0.0000117}}{0.025} \\[Cl^-] = 2.16 \times 10^-^2M.[/tex]

Thus, the concentration required to begin to precipitate PbCl2 for PbCl2 is 0.0216 M.

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Answer:

A

Explanation:

Banana ripening in air is an example of oxidation reaction.

The number of particles of 285 grams of   aluminum oxide  (Al2O3) is  1.68 x 10²⁴ particles.

The number of moles of the given aluminum oxide is calculated as follows;

Al2O3 = 101.96 g/mol

moles = 285/101.96

moles = 2.795 moles

1 mole = 6.02 x 10²³ particles

2.795 moles = ?

= 2.795  x  6.02 x 10²³ particles

= 1.68 x 10²⁴ particles.

Thus, the number of particles of 285 grams of   aluminum oxide  (Al2O3) is  1.68 x 10²⁴ particles.

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The SN₁ substitution reaction, in which the halogen is released from the haloalkane, and the nucleophile attacks the carbon's positive charge. SN₂ in which the nucleophile attacks the halogen's carbon, causing the halogen to be replaced in which nucleophile attack.

Substitution reactions are those reactions in which one functional group is replaced by another functional group.

Two types of substitution reactions can occur in haloalkanes: SN1  and SN2.

Thus, the SN₁ substitution reaction, in which the halogen is released from the haloalkane, and the nucleophile attacks the carbon's positive charge. SN₂ in which the nucleophile attacks the halogen's carbon, causing the halogen to be replaced in which nucleophile attack.

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Geometric progression is a sequence that can be found by multiplying the same value by the preceding number. The next term in the sequence is 8 / 81.

A geometric progression is a sequence of numbers other than 0 and can be estimated by multiplying a specific digit by the prior number. It is given as,

an = a₁rⁿ⁻¹

Where r is the common ratio or the number.

For the given sequence the common ratio (r) is 2/3.

Substituting values:

an = (1/2) ×  (2/3)ⁿ⁻¹

Applying r:

an=2ⁿ⁻¹ / 2 × 3ⁿ⁻¹

Substitute n to find the nth term as:

a₅=2⁽⁵⁾⁻²/ 3⁽⁵⁾⁻¹

a₅=8/ 3⁽⁵⁾⁻¹

a₅ = 8/ 81

Therefore, the next number on the sequence is 8/81.

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Answer:

0.371

Explanation:

number of moles = mass / Ar

= 23.8g / 32.1 + (16.0 × 2)

= 0.37129485179 = 0.371 (3 s.f).

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The oxidation number of chromium (Cr) in CrO₂, Cr₂O₇²⁻ and Cr₂(SO₄)₃³⁻ is +4, +6 and +1.5 respectively.

Oxidation number of any compound gives idea about the number of exchangeable electrons from the outer most shell of an atom.

Let the oxidation state of chromium is x and charge on the whole molecule is zero, so it will be calculated as:

x + 2(-2) = 0

x - 4 = 0

x = +4

Let the oxidation state of chromium is x and charge on the whole molecule is -2, so it will be calculated as:

2x + 7(-2) = -2

2x - 14 = -2

2x = 12

x = +6

Let the oxidation state of chromium is x and charge on the whole molecule is -3, so it will be calculated as:

2x + 3(-2) = -3

2x - 6 = -3

2x = 3

x = +1.5 (which is impossible)

Hence oxidation state of chromium atom in CrO₂, Cr₂O₇²⁻ and Cr₂(SO₄)₃³⁻ is +4, +6 and +1.5 respectively.

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Answer:

yesss

Explanation:

hehhehehhehe

We can tell which acid which have the highest percent ionization on the basis of pH value.

The % ionized indicates how much of the original chemical has ionized. As a result, we compare the ion concentration in solution to the neutral species' original concentration.

If any acid have a high pH value then they must show high percent ionization because they are strong in nature and show full dissociation.

Hence acids with high pH value will show highest percent ionization.

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Answer:

V=10 l H2O

VM=22.4 l/mole

n=V/Vm=0.446 moles H2O

the ratio 1:2

x:0.446

x=0.223 moles O2

Answer:

Here is the solution....hope it helps :)